Communication satellite use__sent by a transmitting station to transmit signals over long distances A microwaves B polar waves C light D radio waves

Hello,

Let's consider the temperature in any scale be "x".

Then,

• Temperature in Celsius = x °C

• Temperature in Kelvin scale = x K

The object changes its position as a result of the force applied to it. This change in position is known as acceleration.

The magnitude of the acceleration of the object depends on the magnitude of the force applied and the mass of the object. Based on the Second Law of Motion, the acceleration of an object is directly proportional to the force applied and inversely proportional to the mass of the object. This relationship can be expressed mathematically as:

a = F/m

where a is the acceleration of the object, F is the force applied, and m is the mass of the object.

So in this case, if a force of F is applied to the 5kg object, it will experience an acceleration of a = F/5. For example, if a force of 10N is applied to the object, it will accelerate at a rate of 2 m/s^2 (a = 10N/5kg = 2 m/s^2).

Therefore, the correct answer is as given above

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Answer:

439.6 THz

Explanation:

The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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Answer:

A

Explanation:

a pex

Answer:

P.S My answer may not render so let me know if it doesn't

Explanation:

As thermal energy is added to a sample of water, the potential energy of its molecules increases, and then the kinetic energy of its molecules increases.

The sections of the heating curve illustrate this process  is B followed by D

Therefore option A is correct.

Thermal energy (also called heat energy) is described as being produced when a rise in temperature causes atoms and molecules to move faster and collide with each other.

some factors of thermal energy include:

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The work done by the gaseous system if the volume is increased to 0.12 cubic meters is given as 21,600 joules

To find the work done by the gas, we can use the formula:

W = PΔV

where W is the work done, P is the pressure of the gas, and ΔV is the change in volume.

At the initial state, the pressure is P = 2.7 × 10^5 Pa and the volume is V1 = 0.04 m^3. At the final state, the volume is V2 = 0.12 m^3.

The change in volume is ΔV = V2 - V1 = 0.12 m^3 - 0.04 m^3 = 0.08 m^3.

Substituting these values into the formula, we get:

W = PΔV = (2.7 × 10^5 Pa) × (0.08 m^3) = 21,600 J

Therefore, the work done by the gaseous system is 21,600 joules (J).

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Answer:

4.6x10^4 joules

Explanation:

Answer:

It would be 90

Explanation:looked it up

The intensity of the sound wave that reaches the observer's ear is 0.17 W/m²

The intensity of a sound wave is the measure of power of the sound transmitted over a given area.

The intensity of sound is inversely proportional to the square of the distance between the sound source and the observer.

I ∝ 1/r²

I₁ r₁² = I₂ r₂²

where;

I₁ r₁² = I₂ r₂²

I₂ = I₁ r₁² / r₂²

Substitute the given parameters and solve for the intensity of the sound that reaches the observer.

I₂ = ( 100 W/m²   x  (5 m)² ) / (120 m)²

I₂ = 0.17 W/m²

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The velocity of the object between 5 s and 9 s is 20 m/s.

The velocity of an object is the rate of change of displacement of the object with time.

Mathematically, the formula for velocity of an object is given as;

v = Δx/Δt

where;

v = (xf - xi) / (t₂ - t₁)

where;

From the given graph, we can infer the following;

xf, the final displacement of the object = 180 m

xi, the initial displacement of the object = 100 m

t₂, the final time of motion of the object = 9 seconds

t₁, the initial time of motion of the object = 5 seconds

v = (180 m - 100 m) / (9 s - 5 s)

v = (80 m) / (4 s)

v = 20 m/s

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\(\sf{\underline{\underline{\qquad \clubsuit \: Given :\clubsuit\qquad}}} \\ \)

\(\sf{\underline{\underline{\qquad \clubsuit \: To \:Find :\clubsuit\qquad}}} \\ \)

\(\sf{\underline{\underline{\qquad \clubsuit \: Solution :\clubsuit\qquad}}} \\ \)

\(:\implies\sf Pressure = \dfrac{Force}{Area} \\ \\ \\ \)

\(:\implies\sf Pressure = \dfrac{50}{5} \\ \\ \\ \)

\(:\implies \underline{ \boxed{\sf Pressure = 10 \:pascal }}\\ \\ \\ \)

\(\therefore{\underline{\textsf{The pressure exerted by the fluid is \textbf{10 pascal}}}}. \\ \)

Answer:c

Explanation:

F = ma

If you increase the mass but hold the acceleration constant you will increase the force and thus the spring scale will read higher

Answer:

5156.37 ft

Explanation:

Given data:

weight ( W ) = 243,000 Ib

Motion of shuttle ; from 189 mi/hr to 101 mi/hr

dv/dt = -0.0002 V^2

I/v * dv/dt = -0.0002 ds

Convert mi/hr to ft/s ( 1 mi/hr = 1.467 ft/s)

189 mi/hr = 277.263 ft/s

101 mi/hr = 148.167 ft/s

After Integrating

In ( 148.167 / 277.263 ) = -0.0002 ( S1 - S2 )

S1 - S2 = -0.627 / -0.0002

S1 - S2 = 3135 ft/s

Now from 101 mi/hr to 35 mi/hr

dv/dt = ( - 0.0002 V^2 + 3.5 )

ds =  V*dv / ( -0.0002 v^2 - 3.5 )

given :  35 mi/hr = 51.345 ft/s

             101 mi/hr = 148.167 ft/s

Integrate

S3 - S2 = - In( 0.0002 v^2 + 3.5 ) / 0.0002 * 2 ]

            = 1644.75 ft/s

S4 - S3 = 376.62 ft/s

attached below is the remaining part of the solution

Total distance travelled = 3135 + 1644.75 + 376.62 = 5156.37 ft

Answer:

(a)\(-0.75\mu\) Coulomb

(b) \(3.1 \mu\) Coulomb

Explanation:

Let \(q_1\) be the positive charge, in Coulumb, on the one sphere and \(q_2\) be the negative charge, in Coulumb, on the other sphere, where \(q_{1} > q_2\).

The center-to-center distance between the spheres is,

\(d=48.5 cm=0.485 m\).

From Coulomb's law, the magnitude of the force, \(F\), between two point charges having magnitudes \(q_1 \& q_2\), separated by distance,\(d\), is

\(F=\frac {1}{4\pi\epsilon_0}\frac{q_1q_2}{d^2}\;\cdots(i)\)

where, \(\epsilon_0\) is the permittivity of free space and

\(\frac {1}{4\pi\epsilon_0}=9\times 10^9\) in SI units.

So, using equation (i), the attractive force between both the spheres is

\(9\times 10^9\frac{q_1q_2}{(0.485)^2}=0.09\)

\(\Rightarrow q_1q_2=2.35225\times 10^{-12}\)

\(\Rightarrow q_1q_2= 2.35225 \mu^2\) [as \(\mu=10^{-6\)]

\(\Rightarrow q_2=\frac{\mu^2 2.35225}{q_1}\;\cdots (ii)\)

When both the sphere is connected by a thin conducting wire, then redistribution of charge take place and net charge , on combining both the spheres, is \(q_1-q_2\) ( as \(q_1>q_2\)).

Finally, the charge density on both the sphere will be the same.

Given that, both the sphere are identical, so, the quantity of charges on of charged on both the conducting spheres, after removing the conduction wire, will be the same.

So, the net charge on the individual sphere is

\(\frac {q_1-q_2}{2}\) which is positive in nature.

From equation (i), the repulsive force between the spheres is

\(9\times 10^9\times \frac{(q_1-q_2)(q_1-q_2)}{4\times 0.485^2}=0.0528\)

\(\Rightarrow (q_1-q_2)^2=5.52\mu^2\) [ as \(\mu=10^{-6}\)]

\(\Rightarrow q_1-q_2=2.35\mu\;\cdots(iii)\)

\(\Rightarrow q_1 - \frac{\mu^2 2.35225}{q_1}= 2.35\mu\) [using equation (ii)]

\(\Rightarrow q_1^2- 2.35\mu q_1- 2.35225\mu^2=0\)

\(\Rightarrow q_1=3.1 \mu\) or \(-0.76 \mu\)

Taking positive sign as \(q_1\) is the magnitude of charge.

So, for \(q1=3.1 \mu\)

\(q_2=3.1- \mu- 2.35\mu=0.75 \mu\) [from equation (iii)]

Hence,

(a) Negative charge on one of the spheres is,

\(q_2=-0.75 \mu\) Coulomb.

(b) Positive charge on the other sphere is,

\(q_1=3.1 \mu\) Coulomb.

Answer:

Convection heat transfer is the physical movement of a warm gas or liquid to a colder location.

Explanation:

hope it helped

Answer:

46.5 N

Explanation:

attached is explanation

Answer:

\(\boxed {\boxed {\sf 5 \ meters/second}}\)

Explanation:

Speed is equal to distance over time.

\(s=\frac{d}{t}\)

The distance is 100 meters and the time is 20 seconds.

\(d= 100 \ m \\t= 20 \ s\)

Substitute the values into the formula.

\(s=\frac{100 \ m }{20 \ s}\)

Divide.

\(s= 5 \ m/s\)

Aman's speed is 5 meters per second.

Answer: b

Explanation:

Answer /The wave with frequency 100 will have its crests farther apart as its wavelength Will be more or elevated.

Explanation:

For sound waves, the velocity ‘v’ is equal to the product of wavelength (λ) and frequency (f) i.e. (v = n × λ or v/n = λ). Therefore, frequency is indirectly proportional to the wavelength.

The sound wave with frequency 100 will have its crests farther apart from each other as frequency is indirectly proportional to the wavelength. The speed of a wave is uninfluenced by variation in the frequency. Therefore, the less frequency wave will have more wavelength.

The wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.

Frequency is the number of cycles of a periodic waveform that occur per unit of time. It is measured in Hertz (Hz).

We can use the equation λ=2L/n, where λ is the wavelength, L is the length of the string, and n is the harmonic number. Since the string has fixed ends, the harmonics must be odd-numbered, so we have n=1 for the fundamental frequency, n=3 for the second harmonic (315 Hz), and n=5 for the third harmonic (420 Hz).

Using n=1 and λ=2L/n, we get:

λ = 2L/1

λ = 2L

Using n=3 and λ=2L/n, we get:

λ = 2L/3

Using n=5 and λ=2L/n, we get:

λ = 2L/5

We can use the formula f=v/λ to relate the wave speed v, wavelength λ, and frequency f. For the two consecutive harmonics, we can write:

v/λ1 = f1

v/λ2 = f2

Since the two harmonics are consecutive, we can assume that they correspond to adjacent values of n, so we have:

λ1 = 2L/1 = 2L

λ2 = 2L/3

Substituting these values into the above equations and solving for v, we get:

v = f1λ1 = f2λ2 = (420 Hz)(2L) / (2L) = (315 Hz)(2L)/(2L/3) = 840 cm/s

To find the fundamental frequency, we use the formula f=v/λ1:

f = v/λ1 = 840 cm/s / 2L = (840 cm/s) / (0.75 m) = 1120 Hz

Therefore, the wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.

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The most likely reason parents and their children have similar physical traits is that (b) they have similar genetic structures.

Physical traits are largely determined by genes, which are segments of DNA passed down from parents to their offspring. Genetic information contains instructions for the development of various physical characteristics, such as eye color, height, and facial features. Therefore, children inherit genetic variations from their parents that contribute to the similarities in their physical traits.

Genes are responsible for the transmission of hereditary traits, and variations in these genes can result in different physical appearances. Children receive half of their genetic material from their biological mother and the other half from their biological father, leading to a combination of genetic traits from both parents. This genetic inheritance process explains why children often share physical characteristics with their parents, such as hair color or body structure.

While living in the same home and being born in similar environments can influence certain aspects of physical traits, such as lifestyle choices or exposure to certain factors, these factors do not have as direct and significant an impact as genetic inheritance. They may contribute to some environmental influences, but genetic factors are the primary drivers of physical trait similarities between parents and their children.

The similarity in blood types between parents and children is a result of genetic inheritance as well. Blood type is determined by specific genes, and children inherit their blood type alleles from their parents. However, blood type alone does not account for the full range of physical traits shared between parents and children, as it is just one characteristic among many that are determined by genetics.

In summary, while living in the same home and being born in similar environments can have some influence, the primary reason parents and their children have similar physical traits is due to their shared genetic structures. Genetic inheritance is the key factor that determines the passing down of physical characteristics from one generation to the next.

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Answer: Liquid 2, if it's 3 g/mL and liquid 2 has 6gs and 2 mLs than it's 3g/mL

To calculate the average air resistance acting on the winner of the race, we need to use the formula:

Work = Force * Distance

In this case, the work done against air resistance is given as 3,360,000 J. However, we do not have the distance traveled or the time taken to complete the race.

Without knowing the distance or time, it is not possible to calculate the average air resistance. Additional information, such as the speed or any other relevant data, would be required to determine the average air resistance.

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Your question is incomplete, but your full question can be:

During the race competitors work against air resistance. The work done against air resistance by the winner of the race was 3,360,000 J. Calculate the average air resistance acting on the winner of the race.

The total rotational kinetic energy of the system can be found by evaluating the above expression using the given values of m, r, and ω \(KE = 1/2 * (m1 * r1^2 + m2 * r2^2 + m3 * r3^2) * (2.00 rad/s)^2\)

The total rotational kinetic energy of a system can be found by evaluating the expression 1/2 Iω^2, where I is the moment of inertia of the system and ω is its angular velocity. In this case, the moment of inertia of the system can be found by adding the moments of inertia of each particle and the connecting rods.

Since the rods have negligible mass, their moment of inertia is also negligible and can be ignored. The moment of inertia of each particle is given by the formula:

I = mr^2

where m is the mass of the particle and r is its distance from the axis of rotation.

Assuming the particles have masses m1, m2, and m3 and distances from the axis of rotation r1, r2, and r3, respectively, the total moment of inertia is:

\(I = m1 * r1^2 + m2 * r2^2 + m3 * r3^2\)

Substituting the given values, we find:

I = (m1 * r1^2 + m2 * r2^2 + m3 * r3^2)

Finally, substituting the moment of inertia and angular velocity into the expression for rotational kinetic energy, we find:

KE = 1/2 * I * ω^2

\(KE = 1/2 * (m1 * r1^2 + m2 * r2^2 + m3 * r3^2) * (2.00 rad/s)^2\)

So, the total rotational kinetic energy of the system can be found by evaluating the above expression using the given values of m, r, and ω.

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Astronauts on the Apollo 11 Moon mission had to place a device on the Moon that would bounce the laser light back to Earth. The answer is option (b).

The device placed on the Moon by the astronauts of the Apollo 11 mission was a retroreflector, which reflects incoming light back in the direction from which it came. The retroreflector works by using a series of mirrored surfaces that bounce the light back towards its source, in this case, Earth-based telescopes.

When a high-powered laser beam is aimed at the retroreflector on the Moon, the light reflects off the mirrors and returns to Earth. The time it takes for the laser light to travel to the Moon and back is measured, and the distance is calculated using the speed of light.

This method allows scientists to accurately determine the distance from the Earth to the Moon, with a precision of a few centimeters. The use of retroreflectors on the Moon is an important tool for studying the Moon's orbit, geology, and for testing theories of gravity.

The answer is option (b).

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Complete question is:

The distance from Earth to the Moon can be accurately calculated by pointing high-powered lasers onto the Moon’s surface. The time it takes for the light to return is used to find the distance. To make this possible, astronauts on the Apollo 11 Moon mission had to place a device on the Moon that would ?

a) store the laser light for future use.

b) bounce the laser light back to Earth.

c) allow the laser light to pass through.

d) change the frequency of the laser light.

Answer:

To verify that they're polarized, he could hold the two lenses perpendicular (90 degrees) to each other, one lens in front of the other, and point it at a light source. If no light passes through then the lenses are polarized

The test of Polarization of pair of sunglasses is , hold the two lenses perpendicular to each other, one lens in front of the other, and point it towards a light source. If no light passes through then the lenses are polarized.

For example, when fishing on a sunny day, you wouldn't see through the water. You would only see a reflection of the sun hitting the water.

To verify that  pair of sunglasses are  polarized, he could hold the two lenses perpendicular  to each other, one lens in front of the other, and point it towards a light source. If no light passes through then the lenses are polarized.

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Answer:

this stuff hard no cap

Explanation:stop cheating cuhhh