Answer:
Volume of carbon dioxide is 428.23 L.
Explanation:
Below is the chemical reaction or chemical equation for the combustion of hydrocarbons such as undecane into carbon dioxide.
\(C_{11}H_{24}(l) + 17O_{2}(g) \to 11CO_{2} (g) + 12H_2O(g)\)
Here, undecane is in liquid form that reacts with gaseous oxygen (combustion) and produces carbon dioxide and water as a product in the gaseous form.
The molar mass of undecane = \(156.31 g/mol.\)
\(\text{Number of moles} = \frac{260g}{156.31g/mol} = 1.66 \ mol.\)
From the equation, it can be seen that 1 mole of undecane produces 11 moles of carbon dioxide. Therefore, 1.66 mol will produce 18.26 mol of carbon dioxide.
Now find the volume of 18.26 mol of carbon dioxide when the temperature is 13 degrees Celsius and pressure is 1 atm.
\(V = \frac{nRT}{P} \\\)
\(V = \frac{18.26 \times 0.082 \times 286 \ K}{1atm} \\\)
\(V = 428.23 \ L\)
2K + Se → K2Se oxidation numbers
Atoms can assume positive, negative or zero values of oxidation numbers depending on their state of combination. Oxidation numbers can also be a fraction in some cases. 'F' has -1 oxidation in all its compounds.
The oxidation number of an element can be defined as the charge which an atom of the element has or appears to have when present in the combined state in a compound. Oxidation number is actually the charge assigned to an atom according to certain rules.
The oxidation number of an element in the free or elementary state is always zero. The oxidation number of an element in monoatomic ion is equal to the charge on the ion.
Here 'K'and 'Se' have 0 oxidation state, In K₂Se, 'K' has +1 oxidation state and 'Se' has -2 oxidation state.
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Bacteria reproduce by invading a host cell. *
Is it true or false
Answer:
i think its true but nevermind its true✌
In a single displacement reaction between Al2S3 and Li, what products will form and why?
A
Li₂S3 and Al because metals replace metals
B
Li3Al and S because metals replace nonmetals
C Li2Al3 and S because metals replace nonmetals
D Li₂S and Al because metals replace metals
Answer: D
Explanation: Cause im always right
The product of the single displacement reaction between Al₂S₃ and Li are Li₂S₃ and Al because metals replaces metals.
What is displacement reaction?Displacement reactions are those, in which one or two species are displaced from a reactant by the reagent. There are two types of displacement reactions namely single displacement and double displacement.
In single displacement reactions, one atom or group from a reactant is replaced by other group. In double displacement, two group of different reactants are exchanged each other.
The reaction between Al₂S₃ and Li is written below:
\(\rm Li + Al_{2}S_{3} \rightarrow Li_{2}S_{3} + 2 Al\)
Here, metal Li replaces metal Al. Thus, option A is correct.
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What is the mass of a rectangular piece of copper 24.4cm x 11.4 cm x 7.9 cm? The density of copper is 8.92g/cm3.
The mass of the rectangular piece of copper is 18,869 g (approx).In conclusion, the mass of a rectangular piece of copper with dimensions 24.4cm x 11.4 cm x 7.9 cm and a density of 8.92 g/cm³ is 18,869 g (approx.).
The given dimensions of the rectangular piece of copper are:Length = 24.4 cmWidth = 11.4 cmHeight = 7.9 cmThe formula to calculate the mass of an object is given by;
Mass = Density x Volume
Here, the density of copper is given as 8.92 g/cm³.
Therefore, the first step is to calculate the volume of the rectangular piece of copper.The formula to calculate the volume of a rectangular object is given by:
Volume = Length x Width x Height
So,Volume = 24.4 cm x 11.4 cm x 7.9 cm= 2115.432 cm³Now we will use the mass formula:
Mass = Density x Volume= 8.92 g/cm³ x 2115.432 cm³= 18,869.27824 g= 18,869 g (approx.)
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Give two industrial uses of water
Answer:
Explanation:
i) in keeping industrial machine cool
ii) in textile inustries for dying clothes
The mass of an atom of element x is equivalent to the total mass of 7 hydrogen atoms
To condition the buret, add a small volume of ____________ to the buret and rotate the barrel ____________ so that the liquid makes contact with the full inner surface of the barrel. Complete this action _________ and discard each volume in a designated waste container.
Answer:
Acid, Horizontally, Drain off the acid by opening the stopcock
Explanation:
A buret is a calibrated glass appratus used to measure and deliver accurate volume of liquid, usually acids, in acid-base titrations.
Before usually the buret to carry out your titration reaction, it is advised to condition or prepare your buret for use.
To condition the buret, add a small volume of the acid to the buret and rotate the barrel horizontally to ensure that the liquid ( acid) makes contact with the inner surface of the barrel o the buret.
This procedure is done to wash off any previous acid or liquid that the buret had been used for in previous titrations.
Complete this action by opening the stopcock of the buret to drain off the acid and discarding each volume in a designated waste container.
Note that acids could be corrosive and dangerous to the skin and so should be handled with great care
3. A balloon is filled with a mystery fluid that has a mass of 1000 kg and a volume of
of |
500 mL.
A. What is the density of the fluid?
B. Will the balloon sink or float in water?
(Helpppp ppls)
What does the Law of Conservation of Mass state? (1 point)
O Matter cannot be rearranged during a chemical reaction.
O The total mass of all of the reactants prior to a chemical reaction must equal the total mass of all the products after the reaction.
O Matter is neither created or destroyed in a chemical reaction, only rearranged.
O The total mass of reactants prior to a chemical reaction is greater than the mass of the product due to the release of energy
Answer:
(Question) What does the Law of Conservation of Mass state?
(Answer) The total mass of all of the reactants prior to a chemical reaction must equal the total mass of all the products after the reaction.
(Question) If the mass of elements before a chemical reaction is 30 grams, after the chemical reaction, the mass will be __.
(Answer) 30 grams
(Question) 78 g of potassium (K) react with 71 g of chlorine (Cl) to produce potassium chloride. According to the Law of Conservation of Mass, what is the mass of the product (2KCl)?
(Answer) 149 g
(Question) 2 grams of potassium (K) reacts with 5 grams of Oxygen (O). According to the Law of Conservation of Mass, how many grams of potassium oxide (K2O) will be produced?
(Answer) 7
(Question) Which of the following equations demonstrates the Law of Conservation of Mass?
(Answer) CH4+O2→C+2H2O
Explanation:
just finished the quick check. enjoy
The correct statements are statement 2 and statement 3 about conservation of mass.
To understand this, let us first understand the Law of Conservation of Mass.
The Law of Conservation of Mass was given by Antoine Lavoisier in 1789.
It states, "a mass in an isolated system can neither be created nor destroyed by chemical or physical transformations. It can only change its form. Also, in a chemical reaction, the mass of reactants is equal to the mass of products."
Now that we know the Law of Conservation of Mass, let us understand the statements given in the question.
Statement 1 is a wrong statement because in a chemical reaction, mass cannot be created or destroyed, but it can be re arranged. We can use the reactants of any mass and can be rearranged. The mass of the reactants will be the mass of the products. Rearranging the mass of the reactants won't create new mass or destroy the mass present.
Statement 2 is correct because we have mentioned above that the law states that in a chemical or physical reaction mass of reactant is equal to mass of products. The total mass which we use remains the same, it doesn't change, hence, making no changes in the total mass of the products. Taking a very simple example of an eraser, we can prove it. If we take an eraser and cut it into small pieces, then, the eraser (reactant) will not change its mass when cut into pieces (product) but only will change its form (shape). Thus, we can see that the total mass of product is equal to the total mass of the reactant.
Statement 3 is also correct. Mass can neither be created nor destroyed, only rearranged. We can know this by a simple example of NaCl (Sodium Chloride). If we take 2 g of Na and 3 g of Cl then the product will have the same mass as 5 g of NaCl. In this reaction, we can rearrange the mass by either adding the reactant's mass or by interchanging the mass of reactants. But in any case, the total mass of product will be equal to total mass of reactants.
Statement 4 is wrong because the chemical reactions are energy releasing. Sometimes the physical reactions are also energy releasing but energy is not mass. Mass and energy are two different terms. The Law of Conservation of Mass states about mass particularly. We might even provide energy or energy might release but that won't affect mass. For example, if we have taken 10 mL of water and after providing energy, the atoms are brought together to make it into ice then ice will also have 10 mL of water. Even if we melt ice then it will again change back to water which is 10 mL. Hence, a wrong statement.
Thus, we can conclude that statement 2 and 3 are correct statements about the Law of Conservation of Mass.
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What was earth’s surface like? Landmasses? First land plants
Answer:
During the early Paleozoic Era, the Earth's surface was very different from what it is today. The continents were arranged differently, forming one large supercontinent called Pangea. This landmass was surrounded by a single large ocean called Panthalassa. The climate was much warmer and wetter than it is today, with no ice caps at the poles.
The first land plants, known as bryophytes, appeared during the early Silurian Period, around 430 million years ago. These plants were small and simple, lacking roots and vascular tissue. They grew in damp environments, such as along the edges of lakes and streams. They were important in the development of soils and in the colonization of land by other organisms, such as insects and other arthropods.
When zinc reacts with copper sulfate solution, zinc sulfate solution and copper are formed.(i) An experiment was carried out to measure the temperature change when zinc powder reactswith copper sulfate solution.initial temperature of copper sulfate solution = 20 °Cfinal temperature of mixture after the reaction = 46 °CExplain what the temperature readings show about the type of heat change that occurs duringthis reaction.
The temperature increase from 20 °C to 46 °C indicates that the reaction between zinc and copper sulfate solution is exothermic, with heat being released into the surroundings.
In the given reaction between zinc and copper sulfate solution, the temperature change can provide insights into the type of heat change occurring during the reaction. Based on the provided information, the initial temperature of the copper sulfate solution was 20 °C, and the final temperature of the mixture after the reaction was 46 °C.
The temperature increase observed in this reaction indicates an exothermic heat change. An exothermic reaction releases heat energy into the surroundings, resulting in a temperature rise. In this case, the reaction between zinc and copper sulfate solution is exothermic because the final temperature is higher than the initial temperature.
During the reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper metal. This displacement reaction is known as a single displacement or redox reaction. Zinc is more reactive than copper and therefore replaces copper in the compound.
The formation of new chemical bonds during the reaction releases energy in the form of heat. This energy is transferred to the surroundings, leading to an increase in temperature. The heat released is greater than the heat absorbed, resulting in a net increase in temperature.
The exothermic nature of this reaction can be explained by the difference in bond energies between the reactants and products. The breaking of bonds in the reactants requires energy input, while the formation of new bonds in the products releases energy.
In this case, the energy released during the formation of zinc sulfate and copper metal is greater than the energy required to break the bonds in copper sulfate and zinc.
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Explain how these results show that chlorine is more reactive than bromine and
lodine.
Chlorine is more reactive than bromine because it replaces both bromine and iodine.
How chlorine is more reactive than bromine?Fluorine is the most sensitive while on the other hand, the astatine is the least reactive as compared to other elements. The chlorine displaces both bromine and iodine, and bromine displaces iodine because of its high reactivity. The element that replaces other atom is considered as more reactive.
The order of reactivity is that the chlorine is more reactive than bromine, which indicates that chlorine is more reactive than iodine.
So we can conclude that chlorine is more reactive than bromine due to high reactivity.
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Report the following measurement using the correct number of significant figures.
Based on the information, we can infer that the red line is about 3.9 cm.
How to identify the measure of the red line?To identify the measure of the red line we must look at the metric rule at the bottom. As we can see, this demarcates the centimeters and the millimeters. Based on the information, we can infer that the answer is 3.9 cm since the line extends to the line that delimits this value.
Based on the above, we can infer that the red line measures about 3.9 cm, taking the ruler as a reference.
Note: This question is incomplete. Here is the complete information:
Attached image
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A 1.362 g sample of an iron ore that contained Fe3O4 was dissolved in acid with all of the iron being reduced to iron (II). The solution was acidified with sulfuric acid and titrated with 39.42 mL of 0.0281 M KMnO4, which oxidized the iron (II) to iron (III) while reducing the permanganate to manganese (II). Generate the balanced net ionic equation for the reaction. What is the mass percent of iron in this iron ore sample?
Answer:
a. MnO₄⁻ + 8H⁺ + 5Fe²⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O
b. 18.17% of Fe in the sample
Explanation:
a. In the reaction, Fe²⁺ is oxidized to Fe³⁺ and permanganate, MnO₄⁺ reduced to Mn²⁺, thus:
Fe²⁺ → Fe³⁺ + 1e⁻
MnO₄⁻ + 5e⁻ + 8H⁺ → Mn²⁺ + 4H₂O
5 times the iron and suming the manganese reaction:
MnO₄⁻ + 5e⁻ + 8H⁺ + 5Fe²⁺ → 5Fe³⁺ + 5e⁻ + Mn²⁺ + 4H₂O
MnO₄⁻ + 8H⁺ + 5Fe²⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂Ob. Moles of permanganate in the titration are:
0.03942L × (0.0281 moles / L) = 1.108x10⁻³ moles of MnO₄⁻
Based on the reaction, 1 mole of permanganate reacts with 5 moles of iron, if 1.108x10⁻³ moles of MnO₄⁻ reacts, moles of iron are:
1.108x10⁻³ moles of MnO₄⁻ × (5 moles Fe²⁺ / 1 mole MnO₄⁻) =
4.431x10⁻³ moles of Fe²⁺. Molar mass of Fe is 55.845g/mol. 4.431x10⁻³ moles of Fe²⁺ are:
4.431x10⁻³ moles of Fe²⁺ ₓ (55.845g / mol) =
0.2474g of Fe you have in your sample.Percent mass is:
0.2474g Fe / 1.362g sample ₓ 100 =
18.17% of Fe in the sampleThe mass percent of iron in the sample is 22.6%.
The net ionic equation of the reaction is;
5Fe^2+(aq) + 8H^+(aq) + MnO4^- -----> 5Fe^3+(aq) + Mn^2+(aq) + 4H2O(l)
Number of moles of MnO4^- = 39.42/1000 L × 0.0281 M = 0.0011 moles
If 5 moles of Fe^2+ reacts with 1 mole of MnO4^-
x moles of Fe^2+ reacts with 0.0011 moles
x = 5 moles × 0.0011 moles/1 mole
x = 0.0055 moles
Mass of Fe^2+ = 0.0055 moles × 56 g/mol = 0.308 g
Mass percent of iron = 0.308 g/ 1.362 g × 100/1
= 22.6%
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A certain metal M forms a soluble nitrate salt M NO Suppose the left half cell of a galvanic cell apparatus is filled with a 3.00 mM solution of M(NO) and the right half cell with a 3.00 M solution of the same substance. Electrodes made of M are dipped into both solutions and a voltmeter is connected between them. The temperature of the apparatus is held constant at 20.0 °C.
1. Which electrode will be positive? What voltage will the voltmeter show?
a. left
b. right
2. Assume its positive lead is connected to the positive electrode. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
Answer:
Explanation:
From the information given:
left half-cell = 3.00 mM M(NO)
right half-cell = 3.00 M M(NO)
Since the electrode are the same in both cells, then the concentration for the cell are also the same.
Negative electrode = Anode = lower concentration = 3.00 mM
Positive electrode = cathode = higher concentration = 3.00 M
Thus, right half cell will be postive electrode.
To determine the concentration cell:
\(Ecell =\Big( \dfrac{2.303\times R\times T}{nF} \Big)log\Big(\dfrac{[cathode]}{[anode]}\Big)\)
SInce [Cathode] > [anode],
\(R = 8.314 J/K/mol, \\ \\ T = 273+20 = 293 K \\ \\ Faraday's constant (F)= 96500 C/mol\)
n = 3
\(Ecell ={ \dfrac{2.303\times 8.314\times 293 }{(3\times 96500)}} log\dfrac{3}{0.003}\)
\(\mathbf{E_{cell} = 0.0582 V } \\ \\ \mathbf{E_{cell} = 0.06 V}\)
Question 1(Multiple Choice Worth 50 points)
(01.06 LC)
Which technology removes carbon dioxide from the air by binding to it?
Answers-
O Pyrolization
O Direct-air capture
() Engineered molecules
O Carbon ground injection
Answer:
Direct-air capture
Explanation:
To understand the technology I'm about to explain, I'll model it to something familiar. As you know, the process of photosynthesis is where trees and plants use sunlight, water, and carbon dioxide to create energy for themselves, and release oxygen as a byproduct. Direct- air capture is exactly like this. Its pulls in air and then through a range of similiar chemical reactions, it extracts the carbon dioxide from it while returning the rest of the air to the surrounding environment. Except, the Direct-air capture does this at a much faster rate than nature does. The direct-air capture uses a ginormous fan that pulls air in which then passes over plastic surfaces that have potassium hydroxide solutions covered over them. The potassium hydroxide solution chemically binds with the carbon dioxide molecules, removing them from the air and trapping them in the liquid solution as a carbonate salt. The carbon dioxide is then contained where it is compressed and purified and then stored for later use.
Deduce the structure of a compound of molecular formula C4H9Br which exhibits the following 1H NMR spectrum.
The structure C₄H₉Br that is 2-bromo-2-methylpropane , exhibits the ¹H NMR is as follows :
CH₃
|
CH₃ - CH - CH₃
|
Br
In the 2-bromo-2-methylpropnae molecule, all the 9 protons has the same chemical environment and there no splitting of the ¹H NMR resonance. All the protons are chemically equivalent, and they will have the same resonance frequency in the NMR.
In the molecule , 9 protons of the 2-bromo-2-methylpropane, as all the hydrogen atoms are having the same chemical environment. In the the Chemical shift (a) of the 1.80 ppm on the ¹H NMR spectrum for the 2-bromo-2-methylpropane is present.
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The reaction HCl(1) + H₂O(1)→ H30(aq) + Cl(aq) can be abbreviated as HCI → H+ + CI™.
How is this apparently important omission justified?
A)
It's understood that H+ doesn't exist on its own in water, and H30(aq) + Cl(aq)
are both aqueous.
B) It's generally understood that H3O+ is a hypothetical intermediary.
OC) Because water isn't important to the reaction
D) It isn't justified, and the abbreviation is an error.
Reaction - It's understood that H+ doesn't exist on its own in water, and H₃O⁺(aq)⁺Cl⁻(aq) are both aqueous.
What is Reaction?
An act that changes one group of chemical constituents chemically into another is known as a chemical reaction. Chemical reactions typically involve changes that only influence the positions of electrons in the formation and dissolution of chemical bonds between atoms, with no change to the nuclei. Chemical processes are commonly described by a chemical equation (no change to the elements present). The study of chemical processes involving unstable and radioactive elements—where both electronic and nuclear changes may take place—is known as nuclear chemistry.
When Acid HCl react with water it dissociates as H⁺ + Cl⁻ ion. H⁺ is a proton (Hydrogen ion is a proton with the charge on it) but this single unit of the charge is very small as compared to it value of the solution is water and acid. The resulting extraordinary high change desity of the proton strongly atom or molecule in ehich there exist an excess of the
⁻ve charge. In the case of water, the lone pair (e⁻) on oxygen attract the proton and form a co-ordinate bond with it creating a hydronium ion (H₃O⁺)
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Answer:
It's understood that H+ doesn't exist on its own in water, and H30(aq) + Cl(aq) are both aqueous.
Explanation:
took quiz
Which sound frequency with a human ear be able to detect? Select ALL correct answers.
100 Hertz
1,000 Hertz
10,000 Hertz
100, 000 Hertz
The answers are 100, 1,000, 10,000 if your are with K12
Answer:
100 HZ 1,000 HZ 10,000 HZ there you go :)
Answer:
100 hertz, 1,000 hertz, and 10,000 hertz
Explanation:
I took the k12 test :)
A gas is heated from 246 K to 289 K while its volume is increased from 22.0 L to 30.5 L by moving a large piston within a cylinder. If the original pressure was 0.98 atm, what would be the final pressure?
You have a container of 5L with a Molarity of 0.750. What would be the new volume if you diluted the solution to have a concentration of 9.71M?
Answer:
=64.73..
Explanation:
0.750=5L
9.71=x
0.750*x÷0.750=5L*9.71÷0.750
x=48.55÷0.750
x=64.73..
assume a certain element has a density of 10.5 g/ml. you have a bag containing 81.50 g of pellets of this element. what is the volume in ml of the pellets in your bag? use density as a conversion factor to solve this problem.
The volume in mL of the pellets in your bag is 7.76mL.
How to calculate volume?Density is the measure of the mass of matter contained by a unit volume.
The density of a substance can be calculated using the following formula:
Density = mass ÷ volume
According to this question, a certain element has a density of 10.5 g/ml. one has a bag containing 81.50 g of pellets of this element. The density of the element is as follows:
10.5g/mL = 81.50g ÷ volume
volume = 81.50g ÷ 10.5g/mL
Volume = 7.76mL
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A balloon contains 0.76 mol O2, 0.18 mol Ne, 0.031 mol Xe and 0.026 mol CO2 at 749 mm Hg. What is the partial pressure of Ne
Answer:
ans given below
Explanation:
To keep simplicity, let's assume these gases behave ideally so we can use the equations for ideal gas. One of these equation is the Raoult's Law written below.
P* = xP
This is another form of the Raoult's Law where x is the mole fraction. Let's find x for O2.
x = 0.18/(0.76+0.18+0.031+0.026) = 0.1805
Partial Pressure = (0.1805)(749 mmHg) = 135.23 mmHg
In an experiment, a student dissolved 11.75 g of NaNO3 is an unknown mass of water initially at a temperature of 18.6 oC. After all the NaNO3 dissolved, the temperature of the solution was measured to be 12.5 oC. From this data, calculate the mass, in g, of water originally in the container before the NaNO3 was added.
111 was incorrect for me.
The mass of water initially present in the container is 11.16 g.
We are given the following:mass of NaNO3 = 11.75 ginitial temperature of water = 18.6 oC.final temperature of solution = 12.5 oCWe need to determine the mass of water initially present in the container. The key formula to use in this problem is the heat absorbed or lost formula, which is expressed as follows:q = m·c·ΔTwhere:q is the heat absorbed or lost in Joules (J)m is the mass of the substancec is the specific heat capacity of the substanceΔT is the change in temperature of the substance, expressed in degrees Celsius (oC)Firstly, let us determine the heat lost by the water. This heat is equal to the heat absorbed by the NaNO3, which can be expressed as follows:q NaNO3 = -q waterwhere the negative sign indicates that the water lost heat.q NaNO3 can be expressed as follows:q NaNO3 = m NaNO3 · c NaNO3 · ΔTwhere:m NaNO3 is the mass of NaNO3c NaNO3 is the specific heat capacity of NaNO3, which is 3.75 J/g·KΔT is the change in temperature of the solution, which is equal to (12.5 - 18.6) oC = -6.1 oC.Substituting the given values gives:q NaNO3 = (11.75 g) · (3.75 J/g·K) · (-6.1 oC)q NaNO3 = -257.49 J.Now we can determine the mass of water that was initially present in the container. The heat lost by the water is equal to the heat gained by NaNO3.
This can be expressed as follows:q water = -q NaNO3.Rearranging and substituting the given values gives:m water · c water · ΔT = -q NaNO3m water = (-q NaNO3) / (c water · ΔT) where:c water is the specific heat capacity of water, which is 4.184 J/g·KΔT is the change in temperature of the water, which is equal to (12.5 - 18.6) oC = -6.1 oC.Substituting the given values gives:m water = (-257.49 J) / [(4.184 J/g·K) · (-6.1 oC)]m water = 11.16 g.
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After mixing for three hours, the product is extracted into dichloromethane and the solvent is removed to give 245 mg of an oil. Using the moles of our protected aldehyde calculated earlier (2.96) and the molecular weight of the product (102 g/mol) predict the theoretical 100% yield of the product in milligrams. Round to the tenths place.
Answer:
the theoretical 100% yield of the product in milligrams is 302920 mg
Explanation:
Given the data in the question;
245 mg of an oil
Using the moles of our protected aldehyde calculated earlier (2.96)
the molecular weight of the product (102 g/mol) = 102000 mg/mol
so, the mass of aldehyde produced (100% yield) will be;
⇒ number of moles × molar mass
⇒ 2.96 mol × 102000 mg/mol
⇒ 302920 mol.mg / mol
⇒ 302920 mg
Therefore, the theoretical 100% yield of the product in milligrams is 302920 mg
How many formula units are in 14.5 moles of H₂SO4?
There are 8.73 × 10²⁴ formula units in 14.5 moles of sulfuric acid.
How to calculate formula units?Formula units is an empirical formula of an ionic compound (that does not possess individual molecules) for use in stoichiometric calculations.
The formula unit can be calculated by multiplying the number of moles in a substance by Avogadro's number (6.02 × 10²³).
According to this question, there are 14.5 moles in sulfuric acid. The formula unit can be calculated as follows:
Formula units of sulfuric acid = 14.5 × 6.02 × 10²³
Formula units = 8.73 × 10²⁴ formula units
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How many grams of CO are needed to react with an excess of Fe2O3 to produce 209.7 g Fe? Equation Fe2O2(g) + 3CO(g) -> 3CO2(g) + 2Fe(g)
Answer: 157.3 g CO
Explanation:
Fe2O3 + 3CO —> 3CO2 + 2Fe [1 mol + 3 mol —> 3 mol + 2 mol]
3 mol CO —> 2 mol Fe
3*28g —> 2*56g
amt CO 3*28*209.7/(2*56) = 157.3g
Which choice is not an example of a molecule? Responses H2S uppercase H subscript 2 end subscript uppercase S, O3 uppercase O subscript 3, KOH uppercase K O H, Mn uppercase M lowercase n,
From the given choice of substances, the one that is not a molecule is Mn.
What are molecules?Molecules are defined as the smallest unit of a substance that can exist and still retain the properties of that substance.
Molecules of substance are usually formed from the atom of the substances when two or more atoms of the same elements or different elements combine.
Molecules of substances are capable of existing alone but atoms of an element must combine to form molecules.
Considering the given substance to determine whether they are molecules or not:
H₂S is a molecule because it contains more than one atom of elements.
O₃ is a molecule because it contains more than one atom of elements.
KOH is a molecule because it contains more than one atom of elements.
Mn is a not molecule because it contains only one atom of elements.
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HELP!
The law of conservation of energy states:
A. Energy increases exponentially with times
B. Total energy decreases due to energy output.
C. Energy cannot be created or destroyed.
D. Energy always remains in the same form.
Answer:
C
Explanation:
energy cannot be created or destroyed like solar energy for instance. it is already energy because it comes from the sun and for other reason.
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A chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solution. He has a 0.1463 M
standard sodium hydroxide solution. He takes a 25.00 mL
sample of the original acid solution and dilutes it to 250.0 mL.
Then, he takes a 10.00 mL
sample of the dilute acid solution and titrates it with the standard solution. The endpoint was reached after the addition of 18.47 mL
of the standard solution. What is the concentration of the original sulfuric acid solution?
The concentration of the original sulfuric acid solution is 0.05398M
In order to determine the concentration of the original sulfuric acid solution, we use the volume of the standard sodium hydroxide solution used in the titration along with the concept of stoichiometry.
Let us check the number of moles of sodium hydroxide (NaOH) used in the titration,
Moles of NaOH = Molarity of NaOH x Volume of NaOH
=0.1463M x 18.47 mL
= 0.002699 Moles
As the balanced chemical equation between Sulfuric acid (\(H_SO_4\)) and sodium hydroxide is 1:2, then we can deduct that 1 mole of sulfuric acid can react with 2 moles of sodium hydroxide.
In that case, the number of moles of sulfuric acid in the 10.00 mL sample is;
Moles of \(H_2SO_4\) = 0.002699 Moles x (1/2)
= 0.0013495 Moles
Now we can calculate the concentration of the original sulfuric acid solution:
That is, the concentration of \(H_2SO_4\) = Moles of \(H_2SO_4\) / Volume of original acid solution
=0.0013495 Moles / 0.02500L
=0.05398 M
Therefore, the concentration of the original sulfuric acid solution is approximately 0.05398 M.
To learn more about sulfuric acid,
https://brainly.com/question/10220770