Colored lights are called additive colors. Why do you think this is so?

Answer:

The motion of the object between 0 and 8 seconds, as represented by the graph above, can be broken down into four segments:

For the first 4 seconds, the object experiences an increased velocity. This means that the object is accelerating downwards due to the force of gravity. During this time, the velocity increases at a constant rate of 9.8 m/s^2.

Between 4 and 6 seconds, the object experiences a constant velocity. This means that the object continues to fall with a steady speed, without any further increase in its velocity.

Between 6 and 7 seconds, the object again experiences a constant velocity. This means that the object continues to fall with the same steady speed as before.

Finally, between 7 and 8 seconds, the object experiences a decreased velocity. This means that the object is decelerating, or slowing down, as it approaches the ground. This could be due to air resistance or other factors.

So, to summarize, the motion of the object between 0 and 8 seconds is characterized by an initial increase in velocity for 4 seconds, followed by two periods of constant velocity for 2 seconds and 1 second respectively, and finally a decrease in velocity for 1 second.

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Answer:

A TURNING CAR WITH CONSTANT SPEED......NON-EX OF INERTIA

Explanation:

Granite will heat up the quickest among dry soil, granite, water, and wet soil due to its lower specific heat capacity.

To determine which substance will heat up the quickest among dry soil, granite, water, and wet soil, we need to consider their specific heat capacities. The substance with the lowest specific heat capacity will heat up the quickest.

Specific heat capacity is defined as the amount of heat energy required to raise the temperature of a substance by a certain amount. Different substances have different specific heat capacities due to variations in their molecular structure and composition.

Water has a relatively high specific heat capacity of about 4.18 J/g°C, meaning it requires a significant amount of heat energy to raise its temperature. Dry soil and granite, on the other hand, have lower specific heat capacities compared to water.

Wet soil is a mixture of dry soil and water, and its specific heat capacity will lie between the values of dry soil and water. Since water has a higher specific heat capacity than dry soil, wet soil is expected to have a higher specific heat capacity than dry soil as well.

Therefore, based on the comparison of specific heat capacities, the substance that will heat up the quickest is granite. Granite has a lower specific heat capacity than water and wet soil, making it more susceptible to temperature changes. Dry soil and wet soil, including water, will heat up at a slower rate compared to granite.

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SeaWorld is a chain of theme parks and oceanariums that showcase marine life through educational exhibits, live shows, and thrilling rides. While it has faced criticism for its treatment of animals, SeaWorld has made changes to prioritize conservation and phased out its orca breeding program.

SeaWorld is a chain of theme parks and oceanariums that primarily focuses on marine life and entertainment. The company operates various parks across the United States, including SeaWorld parks in Orlando, San Diego, and San Antonio, as well as Busch Gardens parks in Tampa and Williamsburg. SeaWorld offers a combination of educational exhibits, live shows, and thrilling rides, with a special emphasis on marine animals such as dolphins, whales, sea lions, penguins, and sharks.

SeaWorld parks provide visitors with opportunities to observe and interact with marine creatures up close, while also offering educational programs that aim to raise awareness about marine conservation and preservation. The parks feature captivating shows featuring trained animals, where they perform impressive behaviors and stunts, showcasing their intelligence and natural abilities.

Over the years, SeaWorld has faced criticism from animal rights activists and environmentalists, who argue that the captivity and use of marine animals for entertainment purposes is unethical and harmful to the animals' well-being. These concerns have led to significant changes in the company's practices, including the phasing out of its orca breeding program and the introduction of more educational and conservation-focused initiatives.

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Answer:

the work done by the net external force acting on the skier is 3046.12 J.

Explanation:

Given;

initial speed of the water skier, u = 6.3 m/s

final speed of the water skier, v = 10.9 m/s

mass of the water skier, m = 77 kg

The work done by the net external force is calculated as;

W = ΔK.E

\(W = \frac{1}{2} m(v^2 - u^2)\\\\W = \frac{1}{2} \times \ 77.0(10.9^2 - 6.3^2)\\\\ W= 3046.12 \ J\)

Therefore, the work done by the net external force acting on the skier is 3046.12 J.

Energy is a fundamental concept in physics that represents the ability or capacity of a system to do work.

It is a scalar quantity, meaning it has magnitude but no specific direction. Energy exists in various forms and can be converted from one form to another. The characteristics of energy include:

1. Forms of Energy: Energy can exist in different forms such as kinetic energy (energy of motion), potential energy (stored energy), thermal energy (heat), chemical energy, electrical energy, and many more.

2. Conservation of Energy: The law of conservation of energy states that energy cannot be created or destroyed; it can only be transformed from one form to another. The total amount of energy in a closed system remains constant.

3. Transfer and Conversion: Energy can be transferred from one object to another or converted from one form to another. For example, electrical energy can be converted into light energy in a light bulb.

4. Units of Measurement: Energy is typically measured in joules (J) in the International System of Units (SI). Other common units include kilowatt-hours (kWh) for larger quantities of energy and calories (cal) for thermal energy.

5. Energy and Work: Energy is closely related to the concept of work. When work is done on an object, energy is transferred to it or from it, resulting in a change in its energy state.

Understanding the nature and characteristics of energy is crucial in various fields, including physics, engineering, and environmental science, as it plays a central role in explaining and analyzing various phenomena and processes.

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Chauffeur: car: pilot: cockpit, flower: stem: tree: trunk, bottom: top: basement: attic, mend: repair:: break: fix December: winter; September: fall; fade: maid: graceful: awkward; late: early; true: false; milk: liquid; broccoli: vegetable; canine: puppy; child: adult

You need to choose a word that appropriately completes the second pair in order to resolve the analogy. The words in an analogy may appear to be unrelated to one another at first look, but they are always logically connected. The link between the first and second word pairs is comparable.

In the testing analogies, only the first set of words is provided. Therefore, you must first determine how these two words are related. To complete the analogy, you must select a word or words that have an analogous relationship to the pair.

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The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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Answer:

B. Convection

D. Conduction

Explanation:

Conduction and convection are the two most prominent processes that helps transfer energy outward to the earth's crust.

Answer:

B and D

Explanation:

I just did it on a p e x. In case your not sure

Answer:   Relative Atomic Mass

Explanation:   The closer the element is to the bottom-right corner, the higher the relative atomic mass. Hydrogen has the lowest relative atomic number at 1, whereas Lawrencium has the highest relative atomic mass at 262.

When displaying sections of data, bar charts is used. As long as the number of categories to compare, vertical bar charts can be useful for comparing several category discrete data, like ages, classes, schools.

Charts and graphs are useful visual aids because they make information accessible and quick to understand. So, it is not unexpected that both print and digital media frequently use graphs. When data is displayed as a graph rather than a table, it can often be easier to understand because the graph might show a pattern or comparison.

Visual representations of data, such as tables and graphs, are used to arrange information and reveal patterns and correlations. To present the results of their research, scientists and researchers frequently employ tables and graphs.

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The final volume of the gas, when the pressure changes from 80.8 kPa to 101.3 kPa at constant temperature, is approximately 652.9 cm³.

To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Boyle's Law can be represented by the equation: P₁V₁ = P₂V₂

Where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.

Given:

Initial volume, V₁ = 817 cm³

Initial pressure, P₁ = 80.8 kPa

Final pressure, P₂ = 101.3 kPa

We need to find the final volume, V₂.

Using Boyle's Law equation, we can rearrange it to solve for V₂:

V₂ = (P₁V₁) / P₂

Plugging in the given values:

V₂ = (80.8 kPa * 817 cm³) / 101.3 kPa

Simplifying the expression:

V₂ ≈ 652.9 cm³

Therefore, the final volume of the gas, when the pressure changes from 80.8 kPa to 101.3 kPa at constant temperature, is approximately 652.9 cm³.

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If the rodent oscillates at a frequency of 0.950 kg/s, the motion will be critically dampened at a value of 1.732 kg/s for constant b. to highlight how different from angular frequency ordinary frequency is.

The frequency of an event is its repetitions per unit of time. When contrasting it with spatial frequency, it is also sometimes referred to as temporal frequency.

given damping force: mass = 0.3 kg, k = 2.5 N/m Fx=-bvx+b = 0.950 kg/s

This oscillator is underdamped since the equation of motion for it is mx" + bx' + kx = 0, which results in b2 - 4mk = 0. W = square root(k/m - b2/4m2) yields the angular frequency of oscillation.

For critically damped motion, b2 = 4mk b = 1.732 kg/s, where w = 2.41379 rad/s.

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The net force on q1 is 9.94 N.

From Coulomb's Law, the force between two point charges is given by:

where;

All the charges have the same charge and magnitude and are separated by the same distance.

The force between q1 and q2 is:

F12 = (9 * 10⁹ N * m²/C²) * (-2.35 x 10⁻⁶ C)² / (0.100 m)²

F12 = 4.97 N

The positive sign indicates that the force is repulsive

Similarly, the force between q2 and q3 is:

(9 * 10⁹ N * m²/C²) * (-2.35 x 10⁻⁶ C)² / (0.100 m)²

F12 = 4.97 N

The positive sign indicates that the force is repulsive

The net force on q1 will be:

Fnet = F12 + F23

Fnet = 4.97 N + (4.97)

Fnet = 9.94 N

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An exothermic reaction that is spontaneous at any temperature meets the following criteria. ∆H < 0 , ∆S > 0 , ∆G < 0

This is because G = H - T S, and since -T S is always negative, if H is negative and S is positive, then G will always be negative.

Exothermic reactions (H0) characterize combustion. Due to the additional rise in the amount of gaseous species (net gain of one mole of gas, S > 0), this specific reaction entails an increase in entropy. As a result, the reaction is spontaneous (G0) at all temperatures. The sign of G will always be negative when H is negative and S is positive, and the reaction will always be spontaneous at all temperatures.

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complete question: Which of the following sets of conditions is true for an exothermic reaction that is spontaneous at all temperatures?

(a)∆H < 0 , ∆S < 0 , ∆G < 0

(b)∆H > 0 , ∆S < 0 , ∆G < 0

(c)∆H < 0 , ∆S < 0 , ∆G > 0

(d)∆H > 0 , ∆S < 0 , ∆G < 0

(e)∆H < 0 , ∆S > 0 , ∆G < 0

convex lenses.

eyeglasses with convex lenses increase refraction, and accordingly reduce the focal lenght

Answer:

a) the body  is changing direction,

b)the body must go to the left and the acceleration to the right

c) the movement has not started.

d) all points of the motion

Explanation:

In this exercise you are asked to find in which position you have the following characteristics of the movement

a) The velocity is zero and the acceleration is negative

This is when the body reaches the end of the travel and turns around, in this case the speed is zero and the acceleration has the opposite direction to the movement.

In this case the body moves to the right and the acceleration is to the left, therefore the speed decreases

b) The velocity is zero, but the acceleration is positive

This occurs at the points where the speed is changing direction, specifically for this case the body must go to the left and the acceleration to the right

c) Both are zero

This only occurs where the body is stopped and the movement has not started.

d) both the velocity and the relation are nonzero.

This is at all points of the motion since the velocity is constantly changing as long as there is an acceleration

Answer: T=153minutes

Explanation:

For time period of revolution , the expression is as follows .

T² =  4π² R³ /GM , M is mass of the earth.

Putting the values

T² =  4π² (9480 x 10³)³ /(6.67 x 10⁻¹¹ )( 5.97 x 10²⁴ )

T² = 8.436 x 10⁷ s

T = 9.184x 10³ s

= 9184 s

= 153minutes .

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At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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The East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).

Isaac's force:

Magnitude: 255 N

Angle: 13 degrees North of East

x-component: 255*cos(13) = 245.1 N (Eastward)

y-component: 255*sin(13) = 58.1 N (Northward)

Newton's force:

Magnitude: 156 N

Angle: 34 degrees South of East

x-component: 156*cos(34) = 129.4 N (Westward)

y-component: 156*sin(34) = 86.5 N (Southward)

Now we can add the x- and y-components of the forces to find the net force:

Net force:

x-component: 245.1 N - 129.4 N = 115.7 N (Eastward)

y-component: 58.1 N - 86.5 N = -28.4 N (Southward)

The net force has an Eastward component of 115.7 N. Therefore, the East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).

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Answer:

There are many factors that are causing change in habitats. But, the main one would be deforestation. Deforestation is where, people go and chop down a whole bunch of trees in a specific area to create more land, and for wood. But, this isn't always good, because it destroys animal's homes that are living either in the tree, or on top of the tree, etc.

Explanation:

Answer:

these changes can happen for different reasons. Some of the changes happen because something that people do or because of weather patterns or a natural disaster. Animals and plants in habits are affected by any change that happens to an environment

Answer:

Its A. Walking on the beach

Answer:

walking on a bench is the answer

Answer:

The half-life is \( t_{1/2} = 1.005 h\)

Explanation:

Using the decay equation we have:

\(A=A_{0}e^{-\lambda t}\)

Where:

We know the activity decrease by a factor of two in a one hour period (t = 1 h), it means that \(A = \frac{A_{0}}{2}\)

\(\frac{A_{0}}{2}=A_{0}e^{-\lambda*1 h}\)

\(0.5=e^{-\lambda*1 h}\)

Taking the natural logarithm on each side we have:

\(ln(0.5)=-\lambda\)

\(\lambda=0.69 h^{-1}\)

Now, the relationship between the decay constant λ and the half-life t(1/2) is:

\(\lambda = \frac{ln(2)}{t_{1/2}}\)

\( t_{1/2} = \frac{ln(2)}{\lambda}\)

\( t_{1/2} = \frac{ln(2)}{0.69}\)

\( t_{1/2} = 1.005 h\)

I hope it helps you!

Answer:

Explanation:

F = k * q * lambda * R * π * (1 - √2/2)

Substituting the given values of q, lambda, R, and k, we get:

F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)

F ≈ 8.58 x 10^-4 N

Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.

The elastic potential energy stored in the spring is 0.375 J.

The formula for elastic potential energy is:

E = 1/2 * k * x^2

where:

* E is the elastic potential energy in Joules

* k is the spring constant in N/m

* x is the distance the spring is stretched or compressed from its equilibrium position in meters

In this problem, we have:

* k = 3 N/m

* x = 0.5 m (50 cm)

Substituting these values into the formula, we get:

E = 1/2 * 3 * 0.5^2 = 0.375 J

Therefore, the elastic potential energy stored in the spring is 0.375 J.

Explanation:

We know that,

Hence, the needed force is 100N.

Explanation:

We know that,

F=ma

F=20×5

F=100 N