Clouds in our atmosphere cause us to see the different phases of the moon.

True

False

Answer:

false

Explanation:

The period of a wave that has a frequency of 57Hz is 0.018s.

A wave in physics is a moving disturbance in the energy level of a field.

Period refers to length of time and is denoted by T. The period of a wave can be calculated by finding the inverse of the frequency as follows;

T = 1/f

Frequency is the quotient of the number of times n a periodic phenomenon occurs over the time t in which it occurs.

T = 1/57

T = 0.018s

Therefore, 0.018s is the period of the wave.

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Communications: Laura develops programs that flag suspicious network activity.

Communication involves the transfer of information from one person (sender) to another (recipient), especially through the use of semiotics, symbols, signs and network devices.

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When a certain shade of blue has a frequency of 7.33×10¹⁴ Hz. So, the energy will be 4.86×10⁻¹⁹ J,

To calculate the energy of one photon of a certain shade of blue light with a frequency of 7.33×10¹⁴ Hz, we can use the formula: E = hf, where E is the energy of one photon, h is Planck's constant, and f is the frequency of the light.

Using Planck's constant ℎ=6.626×10⁻³⁴ J⋅s, we can calculate the energy of one photon of the blue light as follows:

E = hf = (6.626×10⁻³⁴ J⋅s)(7.33×10¹⁴ Hz) = 4.86×10⁻¹⁹ J

Therefore, the energy of exactly one photon of this light is 4.86×10⁻¹⁹ J.

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We can't tell what they're pouring glue on, but I would go for B since homogenous means of the same, and none of them are mixing things that are the same.

There are 1,048,576 possible outcomes (microstates) when flipping 20 fair coins. The probability of getting the sequence "HTHHTTTHTHHHTHHHHTHT" in exactly that order is approximately 9.5367e-07.

a) There are 2 possible outcomes (heads or tails) for each coin flip, and since there are 20 coin flips, the total number of possible outcomes, or microstates, is given by 2²⁰

Answer: 2²⁰= 1,048,576 possible outcomes.

b) To calculate the probability of getting the sequence "HTHHTTTHTHHHTHHHHTHT" in exactly that order, we need to determine the probability of obtaining each individual outcome (head or tail) and multiply them together.

Since each coin flip is independent and has a 1/2 chance of resulting in either heads or tails (assuming the coins are fair), the probability of obtaining the desired sequence is (1/2)²⁰

Answer: (1/2)²⁰≈ 9.5367e-07

c) To calculate the probability of getting exactly 12 heads and 8 tails in any order, we need to determine the number of ways to arrange 12 heads and 8 tails within the 20 coin flips.

This can be calculated using the binomial coefficient, also known as "n choose k." The formula for the binomial coefficient is:

C(n, k) = n! / (k! * (n-k)!)

Where n is the total number of coin flips and k is the number of heads.

Using this formula, the probability can be calculated as follows:

P(12 heads and 8 tails) = C(20, 12) * (1/2)^20

Calculating C(20, 12):

C(20, 12) = 20! / (12! * (20-12)!)

          = 20! / (12! * 8!)

          = (20 * 19 * 18 * 17 * 16 * 15 * 14 * 13) / (8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)

          = 125,970

P(12 heads and 8 tails) = 125,970 * (1/2)^20

Answer: P(12 heads and 8 tails) ≈ 0.12013435364 (approximately)

a) There are 1,048,576 possible outcomes (microstates) when flipping 20 fair coins.

b) The probability of getting the sequence "HTHHTTTHTHHHTHHHHTHT" in exactly that order is approximately 9.5367e-07.

c) The probability of getting exactly 12 heads and 8 tails in any order is approximately 0.12013435364.

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Answer:

Motion is mathematically described in terms of displacement, distance, velocity, acceleration, speed, and time.

The law can be expressed this way: In a collision, an object experiences a force for a specific amount of time that results in a change in momentum.

Explanation:

Hope this helps

Motion can be defined as the displacement, distance, or velocity of an object. Objects in a collision can have different changes in motion of the object.

Motion can be described in terms of the displacement, distance, velocity, acceleration, speed, and time taken by an object. The law can be expressed this way in which a collision occur, an object which experiences a force for a specific amount of time that results in a change in momentum.

Force is responsible for the motion of objects. When two objects collide with each other, a force is exerted on each of the object. The two forces are in opposite directions however they are of the same strength. Even though the force on each of the object in a collision is the same strength, the objects will have different velocity changes on the basis of force and their masses are different.

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Answer:

velocity- the speed of something in a given direction.

Explanation:

acceleration- increase in the rate or speed of something.

The hippo's center of gravity is located 3.2 meters from its tail.

To determine the distance of the hippo's center of gravity from its tail, we need to consider the weight distribution between its front and rear feet. Given that the hippo carries 80% of its weight on its front foot, we can assume that 80% of the hippo's total weight acts at the front. Let's denote the distance from the tail to the center of gravity as "x."

Since the rear foot is located at the tail, the remaining 20% of the weight acts at the rear foot. Using the principle of moments, we can set up the equation: (80% of the weight) * (distance from front foot to center of gravity) = (20% of the weight) * (distance from rear foot to center of gravity). Plugging in the given values, we have (0.8) * (4.0 - x) = (0.2) * x. Solving this equation, we find x = 3.2 meters. Therefore, the hippo's center of gravity is located 3.2 meters from its tail.

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The efficiency of the engine is 1.57%.

Efficiency is a measure of how well a system converts input energy into useful output energy. It is calculated as the ratio of useful output energy to the total input energy.

To find the efficiency of the engine, we need to calculate the work done by the engine and the heat absorbed from the reservoirs during the cycle.

Step 1: Isothermal expansion at 325 K from 16.1 L to 31.5 L

Since this is an isothermal process, the temperature remains constant at 325 K. The work done by the engine during this process is given by:

W1 = nRT ln(V2/V1)

where n is the number of moles of the gas, R is the universal gas constant, and T is the temperature in kelvin.

n = 1 mol

R = 8.314 J/mol/K

T = 325 K

V1 = 16.1 L

V2 = 31.5 L

W1 = (1 mol)(8.314 J/mol/K)(325 K) ln(31.5 L/16.1 L)

W1 = 4527.6 J

The heat absorbed from the reservoir during this process is given by:

Q1 = W1 = 4527.6 J

Step 2: Cooling at constant volume to 163 K

Since this is a constant volume process, no work is done by the engine. The heat absorbed from the reservoir during this process is given by:

Q2 = nCvΔT

where Cv is the heat capacity at constant volume and ΔT is the change in temperature.

n = 1 mol

Cv = 21 J/K

ΔT = 163 K - 325 K = -162 K

Q2 = (1 mol)(21 J/K)(-162 K)

Q2 = -3402 J

Step 3: Isothermal compression to its original volume of 16.1 L

Since this is an isothermal process, the temperature remains constant at 163 K. The work done on the engine during this process is given by:

W3 = -nRT ln(V2/V1)

where V1 = 31.5 L and V2 = 16.1 L.

n = 1 mol

R = 8.314 J/mol/K

T = 163 K

V1 = 31.5 L

V2 = 16.1 L

W3 = -(1 mol)(8.314 J/mol/K)(163 K) ln(16.1 L/31.5 L)

W3 = -4456.5 J

The heat released to the reservoir during this process is given by:

Q3 = -W3 = 4456.5 J

Step 4: Heating at constant volume to its original temperature of 325 K

Since this is a constant volume process, no work is done by the engine. The heat released to the reservoir during this process is given by:

Q4 = nCvΔT

where Cv is the heat capacity at constant volume and ΔT is the change in temperature.

n = 1 mol

Cv = 21 J/K

ΔT = 325 K - 163 K = 162 K

Q4 = (1 mol)(21 J/K)(162 K)

Q4 = 3402 J

The net work done by the engine is given by the sum of the work done during steps 1 and 3:

Wnet = W1 + W3 = 4527.6 J - 4456.5 J = 71.1 J

The net heat absorbed from the reservoirs is given by the sum of the heat absorbed during steps 1 and 2, and the sum of the heat released during steps 3 and 4:

Qnet = Q1 + Q2 + Q3 +Q4 = 4527.6 J - 3402 J + 4456.5 J - 3402 J = 2179.1 J

The efficiency of the engine is given by:

η = Wnet/Q1 = 71.1 J/4527.6 J = 0.0157 or 1.57%

Therefore, the efficiency of the engine is 1.57%.

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The height of the cannon where the objects are launched from is 18 feet.

The canons of page construction are historical reconstructions, based on careful measurement of extant books and what is known of the mathematics and engineering methods of the time, of manuscript-framework methods that may have been used in Medieval- or Renaissance-era book design to divide a page into pleasing proportions. Since their popularization in the 20th century, these canons have influenced modern-day book design in the ways that page proportions, margins and type areas (print spaces) of books are constructed.

To determine the height of the cannon where the objects are launched from, we need to find the value of "h" when "t" is equal to zero.

Given the equation: h = (-1/5)×t^2 + 5×(t) + 18

Substituting t = 0 into the equation, we have:

h = (-1/5)×(0)^2 + 5(0) + 18

= 0 + 0 + 18

= 18

Therefore, the height of the cannon where the objects are launched from is 18 feet.

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Answer:

dC = 72m < dA = 80m < dB = 90m

Explanation:

In order to calculate the distance traveled by each mobile, you use the following formula:

\(d=vt\)          (1)

d: distance traveled

v: speed of the car

t: time of the motion

You replace the values of v and t for each mobile:

mobile A:

\(d_A=v_At_A=(16m/s)(5s)=80m\)

mobile B:

\(d_B=v_Bt_B=(15m/s)(6s)=90m\)

mobile C:

\(d_C=v_Ct_C=(24m/s)(3s)=72m\)

Then, you obtain that he distances traveled by the mobiles show:

dC = 72m < dA = 80m < dB = 90m

Holding a vibrating fork in front of the unit causes the display to register a speed corresponding to the vibration frequency. A tuning fork is labeled "50 mph." The frequency of the tuning fork f = 0.066  Hz

To determine the frequency of the tuning fork, we can use the information provided that the tuning fork is labeled "50 mph."

The frequency of the tuning fork can be directly related to the speed it represents. In this case, the tuning fork is labeled with a speed of 50 mph. We know that the police radar display registers a speed corresponding to the vibration frequency of the tuning fork.

To convert from mph (miles per hour) to frequency, we can use the formula:

f = (speed in mph) / (speed of sound) × (wavelength)

The speed of sound is approximately 343 meters per second (m/s), and we can convert 50 mph to meters per second by multiplying it by 0.44704 (1 mph = 0.44704 m/s).

Calculating the frequency using the formula:

f = (50 mph × 0.44704 m/s) / (343 m/s) = 0.0657 Hz

However, we need to consider that the frequency should be expressed to two significant figures. Therefore, rounding the frequency to two significant figures, we get:

f = 0.0657 Hz ≈ 0.066 Hz

Thus, the frequency of the tuning fork is approximately 0.066 Hz.

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Answer:

wen I was in the car toing home from school after a bad day n si si I have crazzyyy

Answer:-

1. I feel  the most passionate and alive when I watch BTS, because they inspir me to do many things such as Loveing Myself and doning what I love in life and chase my dream. I also feel alive when playing soccer, dancing, playing piano, or singing/rapping, because these things are what I love to do and always loved to do.

2. Yes, I feel like I live everyday the same day, some little things change but the things I do every day are the same, never changes. Wake up, eat, homework, clean, eat, tv, eat, and sleep.

Answer:

B

Explanation:

Answer is B because the ball passes at 10 to 30

Use the work formula:

W = Fd

Replacing we have:

W = 1 N * 1 m

Resolving operation:

W = 1 J

The work efectuated is 1 Joule.

Answer:

What she can do to collect the data is;

B. Gather a few oranges and see how many seeds are in each

Explanation:

The quantity Katie wants to find out is the number of seeds contained in each orange

Therefore, the required population = The number of seeds in a given orange

The method of estimation of the number of seeds per orange is sampling method, whereby the number of seeds in each of the orange in the sample is used to as an hypothesis as to the number of seeds expected in each orange of the entire population.

Therefore, in order to collect the data, she can gather a few oranges and see how many seeds are in each.

Answer:

10,000 m/s per 100 seconds

The impulse was greater in the first experiment because the egg broke.

The term impulse is defined a the product of the force and time. We know that the impulse is high when a large force acts for a short time.

From the experiment if the students, we can conclude that  the impulse was greater in the first experiment because the egg broke.

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Answer:

The impulse was the same in both experiments because the egg came to a stop.

Explanation:

test

Answer:

865.08 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 243 m/s

Height (h) of the cliff = 62 m

Horizontal distance (s) =?

Next, we shall determine the time taken for the cannon to get to the ground. This can be obtained as follow:

Height (h) of the cliff = 62 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

62 = ½ × 9.8 × t²

62 = 4.9 × t²

Divide both side by 4.9

t² = 62/4.9

Take the square root of both side.

t = √(62/4.9)

t = 3.56 s

Finally, we shall determine the horizontal distance travelled by the cannon ball as shown below:

Initial velocity (u) = 243 m/s

Time (t) = 3.56 s

Horizontal distance (s) =?

s = ut

s = 243 × 3.56 s

s = 865.08 m

Thus, the cannon ball will impact the ground 865.08 m from the base of the cliff.

After the use the content of the unused flash bulb does not change although the contents are changed to magnesium oxide. This observation can be explained by the law of conservation of mass.

The chemical equation of the reaction of magnesium and oxygen to give magnesium oxide as product is,

2Mg + O₂ → 2MgO

As we can see from the above reaction, the total number of atoms on the product side are equal to the total number of atom on the react inside.

This observation can be explained by the law of conservation of mass because the mass on both side of the reaction are equal to each other.

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The time at which the energy stored in the capacitor will reduce to half of its initial value is 0.00693 s.

The time at which the energy stored in the capacitor will reduce to half of its initial value is calculated as follows;

\(Q = Q_o e^{-\frac{t}{RC} }\)

\(\frac{Q_0}{2} = Q_0 e^{-\frac{t}{RC} }\\\\\frac{Q_0}{2Q_0} = e^{-\frac{t}{RC} }\\\\\frac{1}{2} = e^{-\frac{t}{RC} }\\\\ln(\frac{1}{2} ) = -\frac{t}{RC} \\\\ln(\frac{1}{2} ) = - \frac{t}{0.01} \\\\-0.693 = - \frac{t}{0.01}\\\\t = 0.00693 \ s\)

Thus, the time at which the energy stored in the capacitor will reduce to half of its initial value is 0.00693 s.

"Your question is not complete, it seems to be missing the following information;"

"The capacitor in an RC circuit is discharged with a time constant of 10.0ms. At what time after the discharge begins is the charge on the capacitor reduced to half its initial value."

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Answer:

Ns/Np=1/4

Vs=?

Vp=220V

Ns/Np=Vs/Vp

Vs=Ns/NpxVp=1/4x220=55V

Explanation:

Answer:

Explanation:

14.9m

The altitude when the airplane flies a distance of 34 m is equal to 14.9 m.

The distance of an object can be demonstrated as the total length traveled by an object. The distance can be defined as a scalar parameter as it has magnitude, not direction. The distance by an object is always positive (+ve), it can never be zero.

Given, the airplane traveled the distance, BC = 34m as shown in the attached diagram, below:

The angle of the path with horizontal, θ = 26°

From the right angle triangle ΔCBA, we can calculate the BC:

Sin θ = BC/AC

Sin 26° = x/34

x = sin 26° ×34

x = 0.438 × 34

x = 14.9 m

Therefore, the altitude when an airplane has flown this distance is 14.9 m.

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Answer:

I need your answer choices to answer this man, you didn't give any.

Explanation:

Hi there "Princess "

Here is ur answer

Answer:

answer that in your parents

Answer:

If a tree falls over a river, the current will move it further downstream until it gets deposited in some areas, such as deltas and floodplains. Eventually, it would be broken down into sediments.

Explanation: