Clear liquid is on top of the green liquid,green liquid is on top of the red liquid.What is the order of density of the liquids, from highest to lowest​

Answer:

A copper cup with a mass of 100.0 g contains 96.0 g of water. Both. the cup and the water are at 13.0OC. If 70.0 g of a substance at 84.0OC is added to the cup, the temperature increases to 20.0OC. If the specific heat capacities of copper and water are exactly 390 and 4180 respectively, find the specific heat capacity of the substance.

Explanation:

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a) There are electrons of parallel spins in the same orbital

b) The electron spins should be converted to antiparallel in the orbital

c) The element belongs to group six.

We know that the orbital diagram is the diagram that can be used to show how electrons are arranged in the orbitals of an element. As such, the segment of the orbital diagram that is shown would have to correspond to a give orbital and preferable part of the outermost orbital configuration of the elements that is in question.

The orbital diagram is incorrect because two electrons in the same orbital can be seen to have parallel spins and this against the postulate of the Pauli exclusion rule. We can correct this making one of the electron to have anti parallel spin.

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A methane molecule (CH4) is considered symmetrical because it possesses a symmetric structure and exhibits symmetry operations.

Symmetry refers to a balanced arrangement of elements that can be divided into equal parts by a plane, axis, or center. In the case of methane, it exhibits several symmetrical characteristics.

Firstly, methane has a tetrahedral molecular geometry, with the carbon atom at the center and four hydrogen atoms positioned around it. This geometry ensures that the molecule is symmetrical in terms of its spatial arrangement.

Each hydrogen atom is located at one of the vertices of the tetrahedron, forming equal angles and distances with respect to the central carbon atom. This symmetry is maintained regardless of the orientation of the molecule.

Additionally, methane possesses rotational symmetry. It can be rotated around any of the carbon-hydrogen bonds, and the molecule will retain its overall appearance.

The symmetry of methane arises from its molecular structure and the equal distribution of electron density around the central carbon atom. The four hydrogen atoms are bonded to the carbon through sigma bonds, which have a cylindrical symmetry. This balanced arrangement of the atoms contributes to the overall symmetry of the molecule.

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Apply Henry's law to calculate the molecular absorption of helium at 1.5 atm, 25 °C, and 1.5 atm of pressure. Helium in water obeys Henry's law without exception.

Compared to other states of material, including such solids and liquids, gases get a lower density. Particles have such a great deal of kinetic energy and are not really attracted to one another, thus there is a lot of unoccupied space between them. One element, like hydrogen gas (Co and co2), a complex, like dioxide (CO2), or even a combination of multiple gases, like air, can make up a gas.

Yet, helium is an essential component in numerous industries, such as high-tech manufacturing, medical technology, and scientific research.

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The concentration of iron used in the titration : 0.009 M

Given

Reaction

Cr₂O₇²⁻ + 6Fe²⁺ + 14H⁺ ⇒ 2Cr³⁺ + 6Fe³⁺ + 7H₂O

0.0093 mol/L potassium  dichromate

200 cm³ of dilute acid, 25cm³   was used in the titration.

Required

the concentration of iron

Solution

Titration formula

C₁V₁n₁=C₂V₂n₂⇒ From equation : n₁=6n₂(1=Cr₂O₇, 2=Fe)

titration average : 33+32.05+32.15+32.1 / 4 = 32.325 cm³(ml)

25 cm³ of iron solution used in titration :

\(\tt V_1=32.325~ml\\\\V_2=25~ml\\\\C_1=0.0093~M\\\\\\\\C_1.V_1.n_2=C_2.V_2.n_1\\\\0.0093\times 32.325\times 6=C_2\times 25\times 1\\\\C_2=0.07215~M\)

Dilution(25 ml from 200 ml iron solution)

\(\tt C_2.V_2=C_1.V_1\\\\0.007215\times 25=C_1\times 200\\\\C_1=0.009~M\)

Answer: 2.53

P = Pressure of the ideal gas,

V = Volume of the ideal gas,

n =  Total amount of ideal gas that is measured in terms of moles,

R = Gas constant, and

T =  Temperature

By rearranging the ideal gas equation we get,

P = 380 kPa

V = 6 L

n = 3 moles

T = 27+273 = 300 K

Put the value given in this equation:

R = 380 kPa . 6L / 3 mol . 300 K

R =  2.53

The major product from the above organic reaction is I

In this reaction, methoxy ethane undergoes addition reaction with hydrogen bromide, Markownikoff's rule being involved in the reaction.

Organic compounds are the compounds which contains carbon and hydrogen.

Generally, organic compounds are characterized by the following:

Below are some classes of organic compounds:

So therefore, the major product from the the above organic reaction is IV

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Answer:

Capacity is the amount of liquid a container can hold. Mass is how much space an object takes up.

Explanation:

All the others are incorrect.

In A option1 is correct

What is Acid ?

In chemistry, an "acid" is a substance that donates hydrogen ions (H+) to another substance, or accepts electrons from another substance. Acids are typically characterized by a sour taste, the ability to dissolve some metals, and a pH value of less than 7 in aqueous solutions. They are often used as reagents in chemical reactions, and are important in many biological processes. Common examples of acids include hydrochloric acid (HCl), sulfuric acid (H2SO4), and acetic acid (CH3COOH). Acids can be classified as either strong or weak, depending on the extent to which they dissociate in water, and can react with bases to form salts and water in a process called neutralization.

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Answer:

nah

Explanation:

l though Most Salt are soluble in water (Properties of Ionic Compound) , Not all are soluble ,which means mixing a salt and water can produce either a Solution (homogeneous mixture) or a Suspension (heterogeneous mixture).

Answer:

Solution

Explanation:

The solved dissolves on the solute, creating a homogeneous substance

Complete Question:

Check the file attached to get the complete question

Answer:

In the film Ice word Revenge, vehicle 2 did not fall of the cliff because,  but in Claire's test, vehicle 2 off the cliff because

Explanation:

In Claire's test, the weight of vehicle 1 is either equal to or greater than the weight of vehicle 2, so it was sufficient to push it down the cliff.  In the film Ice word revenge, the weight of vehicle 1 is less than the weight of vehicle 2, it is not sufficient to make it fall off the cliff ( Note: Looking exactly the same in the movie, as Claire claimed, does not mean they have the same mass). Therefore if Claire wants a collision that will not make the vehicle 2 fall off the cliff, he should collide it with a vehicle of lesser mass/weight.

The answer is 100.431 °C.

we know that we can find the boiling point using the following equation:

ΔT=kb×m

where
ΔT=boiling point elevation

kb=molal boiling point elevation constant (0.51 °C/m for water)

m=molality of the solution

To calculate the molality of the given solution

The molar mass of FeBr3:

Fe:1×55.85g/mol =55.85g/mol

Br:3×79.90 g/mol=239.7 g/mol

Total:295.55 g/mol

number of moles present in 50g is:

n=mass/molar mass=50.0g/295.55g/mol

                                =0.169mol

mass of water=200.0g

molality=moles of solute/kg of solvent

molality=0.169mol/0.200kg=0.845mol/kg

Finally, we can calculate the boiling point elevation

ΔT=kb×m

ΔT=0.51 °C/m×0.845mol/kg=0.431 °C.

boiling point at standard pressure=100.0 °C.

boiling point of solution=100.0 °C +0.431 °C=100.431 °C

So the answer is 100.431 °C

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Answer:

Explanation:

Here, we want to get the net ionic equation of the given reaction

In reality, the given reaction produces silver chloride precipitate

Thus, the net reaction equation we would be writing is one that would give the silver chloride

We have this as:

Answer:

B

Explanation:

Unless the question asks for a different amount of digits (sig figs) then round to 3 sig figs, for example, instead of 34.3492012 it would be 34.4, because the 9 would round the 4 up to a 5 and the 5 would round up the 3 to a 4

Answer: Percent recovery is 47.34 %

Explanation:

Percent yield is defined as the ratio of experimental yiled to theoretical yield in terms of percentage.

\({\text{ percent yield}}=\frac{\text{amount recovered}}{\text{total amount}}\times 100\)

Putting in the values we get:

\({\text{ percent yield}}=\frac{0.732}{1.546}\times 100=47.34\%\)

Therefore, the percent recovery is 47.34 %

Answer:

MoleculeExplanation:

Answer:

Rubidium Cyanide and Water

Explanation:

The properties of hard and soft materials refer to their physical characteristics and behaviors.

These properties are related to factors such as the arrangement of molecules, bonding strength, and response to external forces. Here, we will discuss the general properties of hard and soft materials.

Hard materials:

Rigidity: Hard materials exhibit high stiffness and resist deformation under applied forces. They tend to maintain their shape and structure.

High strength: Hard materials have strong intermolecular or intramolecular forces, allowing them to withstand high stress and pressure without breaking or deforming.

High melting and boiling points: Hard materials often have high melting and boiling points due to the strong bonds between their atoms or molecules.

Brittle: Hard materials are often brittle, meaning they have low tolerance to tensile or bending forces and are prone to fracturing or shattering instead of deforming.

Low compressibility: Hard materials have low compressibility, meaning they do not easily compress or change volume under pressure.

Soft materials:

Flexibility: Soft materials are pliable and easily deformable under applied forces. They can be bent, stretched, or compressed without breaking.

Low strength: Soft materials have weak intermolecular or intramolecular forces, making them more susceptible to deformation or damage under stress.

Low melting and boiling points: Soft materials generally have lower melting and boiling points compared to hard materials.

Ductile: Soft materials are often ductile, meaning they can be drawn into thin wires or stretched into thin sheets without fracturing.

High compressibility: Soft materials can be easily compressed or change volume under pressure due to their loosely packed molecular structures.

It's important to note that these properties are generalizations, and there can be variations within each category. Some materials may exhibit properties that fall between hard and soft, or they may have unique combinations of properties. Materials' properties play a crucial role in various applications, as they determine their suitability for specific uses such as construction, manufacturing, and design.

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To prepare a 0.12 M solution of FeCl₃, the amount of solid FeCl₃ to be dissolved in a given volume of solvent will be 9.72 grams.

Given,

Molarity of FeCl₃ (M)= 0.12 M

The molecular weight (m) of FeCl₃ is  = 162 gm

The volume of the solution (V) to be prepared is =500 ml

The amount of FeCl₃ to be dissolved to make a 0.12 M solution is= x

So,

MV= x ÷ m × 1000

0.12× 500 = x ÷ 162 × 1000

x = 60 × 162 ÷ 1000

x= 9.72 gm

So 9.72 grams of FeCl₃ is dissolved to make 500 ml of 0.12 M solution.

For preparing 0.4 M HCl from 4M HCL:

If we need to make 500 ml of solution with 0.4M of HCL, then we use the formula:

M₁V₁= M₂V₂

0.4 × 500= 4 × x

x= 50 ml

So 50 ml of 4M HCL is taken to make 0.4 M HCL.

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1. a) As impurity is non- polar than the solute, the impurities would be more soluble in the non-polar solvent, Q. The solute being much less soluble in the non-polar solvent, would tend to separate out from the solvent quickly to crystallize out. But impurities would be soluble in the solvent and hence would be removed easily from the solute.

b) Crystallisation process involves a solute which is very sparingly soluble in a particular solvent. The solute is dissolved in the solvent in hot condition and when the mixture is cooled, the solute crystallizes out due to low solubility. So, here it is advantageous to use a non- polar solvent like Q to crystallise a polar solute.

2. Incomplete drying would lead to draining some solute with solvents and it results in poor recovery yield.

3. Crystallisation process is a slow process where the solidification of solute happens when the solution is settled. If you disturb the process by shaking or bumping, the crystallization does not procced. Rather the solute starts to precipitate out.

4. We choose a solvent in which the solute is very less soluble for the purpose of crystallization. Initially , to dissolve the solute in the solvent, the solution needs to be heated strongly

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Answer:  determine how they break

Explanation:

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Answer: 2  

Explanation:

Answer:

no but oxygen

Explanation:

no but oxygen

Answer:

they release energy by using photosynthesis

Explanation:

First, we need to write out the balanced chemical equation for the reaction: 4 KO2 + 2 CO2 → 2 K2CO3 + 3 O2

From the equation, we can see that 4 moles of KO2 react with 2 moles of CO2 to produce 3 moles of O2. Therefore, we need to convert the given masses of KO2 and CO2 into moles:

moles of KO2 = 2.61 g / molar mass of KO2 = 2.61 g / 71.10 g/mol = 0.0367 mol
moles of CO2 = 4.46 g / molar mass of CO2 = 4.46 g / 44.01 g/mol = 0.1013 mol

Next, we need to determine the limiting reagent (the reactant that will be completely consumed in the reaction) by comparing the mole ratios of KO2 and CO2 in the balanced equation. The ratio of moles of KO2 to moles of CO2 is:
0.0367 mol KO2 / 4 mol KO2 per 2 mol CO2 = 0.0184 mol CO2

Since this ratio is less than the actual number of moles of CO2 we have (0.1013 mol), CO2 is in excess and KO2 is the limiting reagent.

Using the mole ratio from the balanced equation, we can calculate the number of moles of O2 produced:

moles of O2 = 3 mol O2 per 4 mol KO2 × 0.0367 mol KO2 = 0.0275 mol O2

Finally, we can convert the moles of O2 to grams:

mass of O2 = moles of O2 × molar mass of O2 = 0.0275 mol × 32.00 g/mol = 0.88 g
Therefore, 2.61 g of KO2 and 4.46 g of CO2 would produce 0.88 g of O2.

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Answer:

The partial pressure of helium gas in a gaseous mixture of helium and hydrogen is the pressure that the helium would exert in the absence of the hydrogen. equal to the total pressure divided by helium's molar mass. O equal to the total pressure divided by the number of helium atoms present.

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Answer:

D

Explanation:

Answer:

D

Explanation:

Answer:

C6H12O6

Explanation:

C6H12O6

Answer

CuSO₄ (aq) + Na₂CO₃ (aq) → CuCO₃ (s) + Na₂SO₄ (aq)

The reaction will occur.

Explanation

The given incomplete equation is: CuSO₄ + Na₂CO₃

The reaction will occur because Na will displace Cu from its salt because Na is more electropositive and higher in the activity series.

The complete equation for the reaction is:

CuSO₄ (aq) + Na₂CO₃ (aq) → CuCO₃ (s) + Na₂SO₄ (aq)

The reaction is a double replacement reaction.

The arbitrary assignment of the reduction of Zn2+(aq) to Zn(s) as E = 0 V serves as a reference point for determining the relative reduction potentials of other redox reactions. This assignment is based on the convention that the standard reduction potential

In the case of the Zn2+(aq) to Zn(s) reduction, the reaction involves the gain of two electrons by Zn2+ ions, leading to the formation of solid zinc metal. The assigned reduction potential of 0 V indicates that, under standard conditions (1 M concentration, 25°C, and 1 atm pressure), the Zn2+ ions have a tendency to accept electrons and be reduced to Zn metal.

Any reduction potential above 0 V suggests a greater tendency for reduction, while a negative reduction potential indicates a lower tendency for reduction compared to the Zn2+(aq) to Zn(s) reaction.

This reference potential allows us to compare the reactivity of other redox systems and predict the feasibility of different reactions. The more positive the reduction potential, the greater the tendency for reduction to occur. Therefore, if we encounter a reduction potential of +0.34 V for another reaction, we can infer that it is more likely to occur spontaneously compared to the Zn2+(aq) to Zn(s) reduction. Conversely, if we encounter a reduction potential of -0.50 V, we can conclude that the reverse reaction (oxidation) is more favorable than the reduction of Zn2+(aq) to Zn(s).

Overall, the assignment of E = 0 V for the reduction of Zn2+(aq) to Zn(s) provides a benchmark for understanding the electrochemical behavior of other redox reactions and allows us to make predictions based on the relative reduction potentials.

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The sample of air should be heated to 252 Kelvin (K) to increase its volume by 25%.

It is possible to determine the temperature to which the sample of air should be heated by using the concept of the ideal gas law. PV = nRT is the ideal gas law, and it relates the pressure (P), volume (V), number of moles (n), temperature (T), and gas constant (R). we can focus on the relationship between volume and temperature since the number of moles and pressure are assumed to be constant.

By showing the increase in volume as a percentage (25%), we can make the equation (V+0.25V)/T = V/T, where V represents the initial volume of the air.

On making the equation simple, we find  Tfinal / Tinitial = 1.25.

To solve for Tfianal, the final temperature,

Tfinal = Tinitail / 1.25

On substituting the initial temperature value of 315K into the equation, we will be getting;

Tfinal = 315K / 1.25

Tfinal = 252K

Hence, the sample of air should be heated to 252 Kelvin (K) in order to increase its volume by 25%.

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