Chuse the correct ERGY s temperature B. M Molecules the 1 and bland 19. What is at 25°C for the followers COCO.(a) a. 21 b. 45.9 217 B_20. Choose the incorrea statement Gases have less entropy than their solids Solutions have more entropy than the solids dissolved. c. Gases have more entropy than the liquids d. Liquids have more entropy than there solids. Entropy of a substance increases as its temperature increases. 21. Which of the following statements is true? Spontaneous processes proceed without outside intervention b. A spontaneous reaction is a fast reaction. c. Only exothermic processes are spontaneous. d. All the statements are true. B 22. Which of the following processes is non-spontaneous? a. Salt dissolves in water b. Photosynthesis occurs C. Ice cream melts on a hot summer day d. Hot soup gets cold before it's served 23. The change in free energy for a reaction: a. predicts speed c. equals heat b. equals AH-TAS d. depends on the standard state chosen 24. In a sealed container, the rate of dissolving is equal to the rate of crystallization would expect: d. N a. AS=0 b. AGO C. AG = 0 25. A reaction is spontaneous if 1) AG is a negative value. 11) Both enthalpy and entropy increase. III) AH is negative and AS is positive. IV) Both enthalpy and entropy decrease. V) AH is positive AS is negative. a. III and IV b. I and 111 c.land 11

Answer:

A, D, F

Explanation:

took on edge.

Answer:

The answer is A,D,F

A:observing and interpreting readings on gauges, meters, and charts

D:testing boiler water quality or arranging for testing

F:operating or tending stationary engines, boilers, and auxiliary equipment

Explanation:

I got all right on edge.

An engine starting system must crank or spin the engine until fuel ignites forces the pistons down and the engine begins to operate on its own power.

Engine is a machine that converts energy into mechanical work. It is a device that takes an energy source, such as electricity, fuel, or solar power, and converts it into a form of energy that can be used to drive a machine, such as a car, truck, boat, or generator. Engines are used in almost all forms of transportation, from cars and trucks to boats and planes. They are also used in many industrial and commercial applications, such as manufacturing, power generation, and construction. Engines are composed of a number of components, including cylinders, pistons, valves, and a crankshaft. The pistons in the cylinders move up and down, creating energy that is then converted into movement that drives the crankshaft and ultimately powers the machine. Engines are usually powered by gasoline, diesel, or other fuels, although some can use electricity or solar power. They come in many different sizes and configurations, and are found in a variety of vehicles, from cars and motorcycles to boats and plane.

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An engine starting system must crank or spin the engine until fuel Combustion forces the pistons down and the engine begins to operate on its own power.

Combustion is a chemical reaction in which a substance reacts quickly with oxygen and produces heat. The original substance is referred to as the fuel, and the source of oxygen is referred to as the oxidizer. The fuel can be solid, liquid, or gas, but it is usually a liquid for aeroplane propulsion. Similarly, the oxidizer could be a solid, liquid, or gas, but for aeroplanes, it is usually a gas (air). A solid fuel and oxidizer are used in model rockets.

New chemical substances are formed during combustion from the fuel and the oxidizer. These substances are referred to as exhaust. The majority of the exhaust is caused by chemical reactions between the fuel and oxygen.

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Answer:

B

Explanation:

Here is the ER diagram for the Cruise Business Case:

+-------------+          +-------------+

|   Employee  |          |    Ships    |

+-------------+          +-------------+

| EmployeeID  |          |   ShipID    |

| LastName    |          | ShipName    |

| FirstName   |          | Description |

| Type        |          +-------------+

| ParrotID    |<---------|     Crew    |

+-------------+          +-------------+

                         |   Captain   |

                         |  ParrotID   |

                         +-------------+

+--------------+         +--------------+

|   Parrot     |         |  Dependents  |

+--------------+         +--------------+

| ParrotID     |<--------|  DependentID |

| ParrotName   |         |  FirstName   |

| Color        |         |  EmployeeID  |

+--------------+         +--------------+

+--------------+         +-------------+

|   Missions   |         | MissionShip |

+--------------+         +-------------+

| MissionID    |         | MissionID   |

| MissionName  |         | ShipID      |

| ScheduledDate|         +-------------+

| QuotedPrice  |

+--------------+

The tables and their relationships are as follows:

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Answer: hello your question lacks the required diagram attached below is the diagram

answer :  29528.1  N/m^2

Explanation:

Given data :

dimensions of tank :

Length = 5-m

Width = 4-m

Depth = 2.5-m

acceleration of tank = 2m/s^2

Determine the maximum gage pressure in the tank

Pa ( pressure at point A )  = s*g*h1

    = 10^3 * 9.81 * 3.01

    = 29528.1  N/m^2

attached below is the remaining part of the solution

The relative humidity of atmospheric air for the given case is 23.16%.

The atmospheric air is at 25°C and 100 kPa. The products contain 9.57 kmol of water vapor per kmol of fuel burned. We are to determine the relative humidity of atmospheric air for the given case. Solution: Relative humidity is the ratio of the partial pressure of water vapor in the air to the equilibrium vapor pressure of water at a given temperature.

The equilibrium vapor pressure is determined from the Clausius - Clapeyron equation. The partial pressure of water vapor in the air can be determined from the amount of water vapor present in the products. Let us first determine the equilibrium vapor pressure of water at 25°C. The following equation gives the equilibrium vapor pressure of water at any temperature T in degrees Celsius:log10Pv = A − B / (T + C)Where, Pv is the equilibrium vapor pressure of water in kPa, A = 8.07131,B = 1730.63, and C = 233.426.

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The products are found to contain 9.57 kmol of water vapor per kmol of fuel burned is 80.97%.

Given that :

the temperature of atmospheric air, T1 = 25°C

Pressure of atmospheric air, P1 = 100 kPa

Volume of atmospheric air, V1 = 1 kmol

The number of moles of water vapor in the product is n2 = 9.57 kmol of water vapor

The number of moles of fuel burned = 1 kmol of fuel burned

Assuming that all the water vapor comes from the combustion of the fuel, the number of moles of dry air will be equal

to the number of moles of atmospheric air minus the number of moles of water vapor present in the product: n1 - n2 = 1 - 9.57 = -8.57 kmol of dry air

Since 1 kmol of dry air occupies a volume of 24.045 m3 at standard temperature and pressure (STP) conditions, i.e., at 0°C and 101.325 kPa, the volume of the dry air can be calculated as:V1 - V2 = (1 kmol dry air) x (24.045 m3/kmol) = 24.045 m3

We can use the ideal gas law to determine the volume of the mixture of dry air and water vapor at the initial conditions:

PV = nRTV = (nRT)/PP = P1 = 100 kPaT = T1 = 25 + 273.15 = 298.15 KR = 8.314 J/(mol·K)

Therefore, the volume of the mixture of dry air and water vapor can be calculated as follows:V = (n1 + n2)RT/P = [(1 kmol dry air) + (9.57 kmol water vapor)] x (8.314 J/(mol·K)) x (298.15 K)/(100 kPa) = 29.786 m3

We can now use the definition of relative humidity to calculate the relative humidity of the atmospheric air:RH = (n2 x P1)/(P2 - n2 x P1) x 100%P2 = P1 + PwPw = n2RT/V = (9.57 kmol) x (8.314 J/(mol·K)) x (298.15 K)/(29.786 m3) = 78.697 kPaP2 = 100 + 78.697 = 178.697 kPa

Therefore, the relative humidity of atmospheric air is:RH = (9.57 kmol x 100 kPa)/(178.697 kPa - 9.57 kmol x 100 kPa) x 100%≈ 80.97 %

Hence, the relative humidity of atmospheric air for the case where the atmospheric air is at 25 °C and 100 kPa and the products are found to contain 9.57 kmol of water vapor per kmol of fuel burned is approximately 80.97%.

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\(f = force\)

\(m = mass \: of \: an \: object\)

\(a = acceleration\)

Newton's second law is one of the most important in all of physics. For a body whose mass m is constant, it can be written in the form F = ma, where F (force) and a (acceleration) are both vector quantities. If a body has a net force acting on it, it is accelerated in accordance with the equation

Bondtite Wood Adhesives is the best glue for pasting Acrylic Sheet to any wooden surface like Plywood , MDF, or WPC.

1. Make sure both surfaces are clear of dirt and other impurities (Oil, grease, dust, etc.).

2. Using a spreader, evenly apply Bondtite Acrylicfix on the plywood (base surface). Let the surface 8 to 10 minutes to dry.

3. Use a wet cloth to rub the acrylic sheet's backside on the second surface. Make sure there are no water droplets on the area that the adhesive will be sticking to. Avoid rubbing with wet towel during the rainy season.

4. To ensure a strong binding, bring the two surfaces together and apply uniform pressure using a roller, press machine, or dry cloth.

5. Use clamps, nails, tape, etc. to firmly hold the bonded surface together. Handling Strength can be attained in two to four hours.

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For an NPN , the base current is primarily made up .

The potential difference between the collector and the base is always less than 0.4 V, and the base current and collector current are directly proportional to one another.

Based on the types of the three main terminals, can be divided into NPN and PNP types. An NPN transistor is made up of two semiconductor junctions with a thin p-anode region, and a PNP transistor is made up of two semiconductor junctions with a thin n- cathode region.

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When encapsulation is not available under class I conditions, the contractor or installer must use alternative methods to control asbestos exposure. may include isolation, enclosure, or removal of the asbestos-containing material.

The choice of method depends on the specific circumstances and conditions of the site. It is important to note that these methods may not be as effective as encapsulation in preventing the release of asbestos fibers into the air. Therefore, it is crucial that the contractor or installer takes appropriate measures to ensure the safety of workers and occupants during the process. This may include using personal protective equipment, implementing proper ventilation systems, and following established asbestos handling procedures.

Overall, it is important for contractors and installers to be knowledgeable about the risks and regulations associated with asbestos to ensure the safe and proper handling of this hazardous material.It has been demonstrated that isolation fosters divergent evolution that results in unique phenotypes. It is regularly found that populations with different morphologies can reproduce with one another, and the presence of reproductive isolation within morphologically recognised species suggests the existence of cryptic species.

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Answer: hello the diagram related to your question is missing please the third image is the missing part of the question

Fx = 977.76 Ib/ft

Explanation:

Estimate the force that water exerts on the pier

V = 12 ft/s

D( diameter ) = 6 ft

first express the force  on the first half of the cylinder  as

Fx1 =  - \(-2\int\limits^\pi _\frac{\pi }{2} {Ps*cos\beta *a} \, d\beta\)   ---------------- ( 1 )

where ; Fy = 0

Ps = Po + 1/2 Pv^2 ( 1 - 4 sin^2β )  ------------- ( 2 )

Input equation (2)  into equation ( 1 )         (note :  assuming Po = 0 )

attached below is the remaining part of the solution

Answer:

The answer is "\(\bold{9.09\times 10^6 \frac{kg}{hour}}\)".

Explanation:

For the reference table we get:

\(h1 = 2410 \frac{kJ}{kg} \ , at \ \ \\\\ \ P = 0.08 \ bar \ and \ \ quality = 0.932\)

Through steam tables, they get:

\(\ h2 = 173.9 \frac{kJ}{kg} \ on\\\\ \ P = 0.08 \ bars \ \ \ but \ quality = 0 (sat.liquid),\)

Water power transfer = \(\ 3.4 \times 10 ^ 5 \times (2410-173.9)\\\)

It should be comparable to the water enthalpy:

\(m_{water}\times Cp\times (T2-T1)\\\\For \ eg:\\\\ = 3.4 \times 10 ^ 5\times (2410-173.9) \\\\ = m_{water}\times4.18\times(35-15)\\\)  

\(m_{water}=9.09\times 10^6 \frac{kg}{hour}\)

1. We can see here that three phase refers to a type of electrical power transmission that uses three alternating current (AC) waveforms that are 120 degrees out of phase with each other. This is different from single-phase power transmission, which uses only one AC waveform.

Voltage, also known as electric potential difference, is a measure of the electrical potential energy per unit of charge in an electrical circuit. It is defined as the amount of work required to move a unit of electric charge between two points in a circuit, typically measured in volts (V).

Three-phase power is needed because it allows for more power to be transmitted over a given amount of wire or cable. With three-phase power, the power is delivered in a more consistent manner, which means that there is less voltage drop over long distances.

2. In order for a three-phase system to be balanced, the three phases must have the same amplitude and be 120 degrees out of phase with each other. The voltage equation of a balanced three-phase voltage source is given by:

Vph = Vline / √3

where Vph is the phase voltage and Vline is the line voltage. The phasor diagram for a balanced three-phase system shows three sinusoidal waveforms that are displaced by 120 degrees from each other.

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Answer:

Rocks

Explanation:

I am not sure tho bc they are made out of coal and I think coal is a kind of rock

Answer:

I'm taking a guess for ya I shall say Metal or and Minerals

Explanation:

Good luck

Answer:

Option B

Explanation:

An evaporator along with  cold low pressure refrigerant absorbs heat from the air within the passenger compartment thereby supplying cool air for the occupants.

Hence, option B is correct

Answer:

a) Density of the road segment

i) Before bus strike = 23.02 pc/mi/In

ii) after bus strike = 25.76 pc/mi/In

b) Volume to capacity ratio

i) Before bus strike = 0.69

ii) After bus strike = 0.78

C) level of service of the upgrade segment

i) Before bus strike = LOS C

ii) after bus strike = LOS D

Explanation:

a) Density of the road segment

i) before bus strike ( D1 )

 D1 = 1662 / 72.18  = 23.02 pc/mi/In

ii) After bus strike ( D2 )

D1 = 1859 / 72.18 = 25.76 pc/mi/In

b) Volume to capacity ratio

i) Before bus strike ( v 1 )

V1 = 1662 / 2400 = 0.69

ii) After bus strike ( V2 )

V2 = 1859 / 2400 = 0.78

C) level of service of the upgrade segment  ( Gotten from " LOS Criteria for basic freeway segments " )

i) Before bus strike =  ( LOS C )

ii) After bus strike  = LOS D

Attached below is the detailed solution to the question above

The value of the site is $10,472,000.

The total construction costs are:

$6,000/m2 * 10,000m2 + $400,000 = $64,000,000

The professional fees are:

$64,000,000 * 0.13 = $8,320,000

The total development costs are:

$64,000,000 + $8,320,000 = $72,320,000

The developer's return for risk and profit is:

$72,320,000 * 0.20 = $14,464,000

The total cost of the development is:

$72,320,000 + $14,464,000 = $86,784,000

The expected rent is:

$3,000/m2 * 8,000m2 * 12 months = $28,800,000

The initial yield is:

$28,800,000 * 0.07 = $2,016,000

The value of the site is:

$86,784,000 - $2,016,000 = $10,472,000

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As the temperature of the material increases, the potential energy of the molecules increases. Thermal expansion occurs due to changes in temperature, and interatomic distances increase as potential energy increases.

Thermal expansion is used in a variety of applications such as rail buckling, engine coolant, mercury thermometers, joint expansion, and others.

It is to be noted that an application of the concept of liquid expansion in everyday life concerns liquid thermometers. As the heat rises, the mercury or alcohol in the thermometer tube moves in only one direction. As the heat decreases, the liquid moves back smoothly.

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Answer:

A motion sensor uses one or multiple technologies to detect movement in an area. When a sensor detects motion, it sends a signal to your security systems control panel, which connects to your monitoring panel system. This alerts you and the monitoring center to a potential threat in your home.

Hope It Helps You................

In order to determine the height of the tower, we would apply the second equation of motion and assume that the downward motion is negative.

Mathematically, the second equation of motion is given by this formula:

S = ut + ½gt²

Where:

Substituting the given parameters into the formula, we have;

S = S₀ + ut - ½gt²

0 = S₀ + (0)4.0 - ½ × (9.8) × 4.0²

0 = S₀ - 4.9 × 16.0

Height, S₀ = 78.4 meters.

In order to calculate the bearing's impact velocity, we would apply the first equation of motion:

V = u - at

V = 0 - 9.8(4.0)

Impact velocity, V = 39.2 m/s.

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Complete Question:

Ball bearings can be made by letting spherical drops of molten metal fall inside a tall tower, called a shot tower, and solidify as they fall.

a. If a bearing needs 4.0 s to solidify enough for impact, how high must the tower be?

b. What is the bearing's impact velocity?

The maximum peak output voltage and current if the supply voltages are changed to +15 V and --1V will be 15V and 0.1A.

From the information given, the supply voltages are +15V and -15V. The maximum peak output voltage will be 15V.

The maximum peak current will be:

= 15/150

= 0.1A

In conclusion, the maximum peak output voltage and current will be 15V and 0.1A.

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Answer:

0.981

Explanation:

velocity  of cars ( v1 , v2 )  = 55 mi/h

coefficient of adhesion ( u ) = 0.75

Reaction time of driver of car 1 = 2.3 -s

Reaction time of driver of car 2 = 1.9 -s

breaking efficiency of car 2 ( n2 ) = 0.80

Determine the braking efficiency of car 1

First determine the distance travelled during reaction time ( dr )

dr = v * tr ------- ( 1 )

tr ( reaction time )

v = velocity

note : 1 mile = 1609 m ,  I hour = 60 * 60 secs

back to equation 1

for car 1

dr1 =( 55 * 2.3 * 1609 ) / ( 60 * 60 )

    = 56.53 m

for car 2

dr2 = ( 55 * 1.9 * 1609 ) / ( 60 * 60 )

   = 46.70 m

next we calculate the stopping distances  ( d ) using the relation below

ds = d + dr

 d = distance travelled during break

 dr = distance travelled during reaction time

where : d = \(\frac{v^2intial}{2ugn}\)

for car 1

d1 = \(\frac{(55)^2}{2*0.75*9.81* n1} * (\frac{1609}{3600} )^2\)

∴ d1 = \(\frac{41.10}{n1}\)

for car 2

d2 = \(\frac{(55)^2}{2*0.75*9.8*0.8} * (\frac{1609}{3600} )^2\)

∴ d2 = 51.38

since the stopping distance for both cars are the same

d1 + dr1 = d2 + dr2

( 41.10 /n1 ) + 56.53 = 51.38 + 46.70

solve for n1

hence n1 = 0.981 ( braking efficiency of car 1 )

Answer:

yes.

Explanation:

Visual lead time on the highway is important as it helps a driver avoid collisions and makes safe driving possible. A visual lead time of 15 seconds is usually recommended for highway driving. This means that you should be able to see about 15 seconds ahead of your current position while driving.

A visual lead time of 15 seconds allows you to have enough time to react to any potential hazards or changes in traffic flow. This lead time can vary depending on road conditions, speed, and weather. If you are driving at high speed or in poor weather conditions such as heavy rain or fog, your visual lead time should be longer than 15 seconds to ensure safety.

In addition to visual lead time, it's also important to maintain a safe distance between your vehicle and the vehicle in front of you. The general rule of thumb is to stay at least one car length behind for every 10 mph you are driving. This means if you are driving at 60 mph, you should maintain a distance of at least six car lengths from the vehicle in front of you.

In conclusion, maintaining a visual lead time of 15 seconds while driving on the highway and maintaining a safe distance between your vehicle and other vehicles is crucial for safe driving.

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Answer:

c Many transportation industries were deregulated.

Explanation:

correct on edge 2022

Answer:

An algotherum is a finite set of sequential instructions to accomplish a task where instructions are written in a simple English language