Chemical combination of two or more atoms that form a specific chemical compound is called: ____________

Answer:

The uniqueness of the plasma state is due to the importance of electric and magnetic forces that act on a plasma in addition to such forces as gravity that affect all forms of matter.

Explanation:

Answer:

C.) They both have equal charges.

Explanation:

Ignoring the signs, both a proton and electron have a charge of 1.

A proton has a greater magnitude of charge than an electron.

Both protons and electrons have charges, but the magnitudes of their charges are different. A proton carries a positive charge of +1 elementary charge, while an electron carries a negative charge of -1 elementary charge. The elementary charge is the fundamental unit of electric charge. Despite the opposite signs of their charges, the magnitudes are equal, and both charges have the same strength.

Therefore, when ignoring the sign of the charges and considering only their magnitudes, a proton has a greater magnitude of charge compared to an electron. The magnitude of the proton's charge is equal to that of the electron's charge. This is a fundamental property in the realm of electric charges, and it plays a critical role in various physical and chemical interactions, including the behavior of atoms, molecules, and electromagnetic forces.

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The Fermi energy of body-centred cubic Na and face-centred cubic Al can be calculated using the free electron model.

The Fermi energy (Ef) can be calculated using the formula:
Ef = (h^2 / (8 * m_e)) * (3 * N * π^2 / V)^(2/3)
where h is the Planck's constant (6.626 x 10^-34 J s), m_e is the electron mass (9.109 x 10^-31 kg), N is the number of free electrons per unit cell, V is the volume of the unit cell, and π is pi (approximately 3.14159).
For body-centred cubic Na (dimensions 0.43 nm), there is 1 free electron per unit cell (Na has 1 valence electron).

The volume V = a^3 = (0.43 x 10^-9)^3 m^3. Plug in these values into the formula to calculate Ef for Na.
For face-centred cubic Al (dimensions 0.40 nm), there are 3 free electrons per unit cell (Al has 3 valence electrons). The volume V = a^3 = (0.40 x 10^-9)^3 m^3. Plug in these values into the formula to calculate Ef for Al.

Summary: By applying the free electron model and using the given dimensions of the cubic unit cells, we can calculate the Fermi energy for body-centred cubic Na and face-centred cubic Al using the formula provided in the explanation.

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Answer: Salt

Explanation:

Answer:

IT îs said that the cell separarea water into its constituent elemente hidrogen and oxigen . Turn the hidrogen will ne burned ți obtain energy nu restoring the water molecules.

Water does  not stick to the leaves of the plant  owing to the fact that the leaves has a waterproof cuticle.

We know that the leaves are the parts of the plant that are involved in photosynthesis. Photosynthesis is the process by which green plants produce their own food in the presence of sunlight and chlorophyll. We know that the leave has an outer protective covering.

The tissue that plays this outer covering of a plant for is the  epidermis and its waxy cuticle. It prevents damage to the plant.

Water does  not stick to the leaves of the plant  owing to the fact that the leaves has a waterproof cuticle.

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The distance between point E(3, 7) and point (6, 5) is √13.

The distance between two points on a coordinate plane can be found using the distance formula. To determine which distance formula to use, we need to identify the coordinates of the two points.

Given the coordinates of point E as (3, 7) and the coordinates of another point as (6, 5), we can use the distance formula to find the distance between them.

The distance formula is √((x₂ - x₁)² + (y₂ - y₁)²), where (x₁, y₁) and (x₂, y₂) represent the coordinates of the two points.

Using the given points, we can substitute the values into the distance formula:

Distance = √((6 - 3)² + (5 - 7)²)

Simplifying further:

Distance = √(3² + (-2)²)

Distance = √(9 + 4)

Distance = √13

Therefore, the distance between point E(3, 7) and point (6, 5) is √13.

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There are various type of chemical reactions in chemistry like combination reaction, displacement reaction. One of these is the decomposition reaction. The product will remain same as 2H₂ ,  0₂ on addition of more water in the electrolysis.

Decomposition reaction is the one in which molecules breaks down in its constituent in presence of energy. Energy can be in any form, it can be light energy , heat energy.

Decomposition of water is done by providing electricity and the reaction is called electrolysis. Lysis means to break. To give decomposition reaction molecule must have more than one element. The product of electrolysis is independent of amount of water.

Therefore, the product of electrolysis will remain same.

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Before a phase change, thermal energy is absorbed by the water, causing its temperature to increase.

Thermal energy is absorbed by water when heat is transferred from a hotter object to a cooler object, causing the temperature of the cooler object to increase. This can happen through several mechanisms, including conduction, convection, and radiation.

Conduction occurs when heat is transferred through direct contact between the hotter and cooler objects. For example, if you put a pot of water on a hot stove, heat will be transferred from the stove to the pot through direct contact.

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The maximum number of grams of PbI2 precipitated upon mixing 25.0 mL of 0.150 M KI with 15.0 mL of 0.175 M Pb(NO3)2 is 1.211 g.

To determine the maximum number of grams of PbI2 precipitated, we need to first calculate the limiting reagent in the reaction between KI and Pb(NO3)2.

The balanced chemical equation for the reaction is:

2KI + Pb(NO3)2 → 2KNO3 + PbI2

The reaction ratio between KI and Pb(NO3)2 is 2:1, which means that we need twice as many moles of KI as Pb(NO3)2 to ensure that all the Pb(NO3)2 is reacted.

First, we need to calculate the number of moles of KI and Pb(NO3)2:

n(KI) = 0.150 mol/L x 0.0250 L = 0.00375 mol

n(Pb(NO3)2) = 0.175 mol/L x 0.0150 L = 0.002625 mol

Since the reaction ratio is 2:1, we need twice as many moles of KI as Pb(NO3)2:

n(KI) needed = 2 x 0.002625 mol = 0.00525 mol

Since we have an excess of KI, only 0.002625 mol of Pb(NO3)2 will react. We can use this amount to calculate the mass of PbI2 precipitated:

n(PbI2) = 0.002625 mol

m(PbI2) = n(PbI2) x MW(PbI2)

        = 0.002625 mol x 461.01 g/mol

        = 1.211 g

Therefore, the maximum number of grams of PbI2 precipitated upon mixing 25.0 mL of 0.150 M KI with 15.0 mL of 0.175 M Pb(NO3)2 is 1.211 g.

Therefore, the correct answer is (c) 1.21g.

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The reaction performed with the elephant toothpaste demonstration is known as a decomposition reaction.

The process of breaking down a chemical compound into smaller molecules, atoms, or ions is known as a decomposition reaction. It is also known as analysis or disintegration. A reaction in which a single substance is broken down into two or more simpler substances is known as a decomposition reaction. The elephant toothpaste demonstration is a simple chemical reaction in which hydrogen peroxide breaks down into oxygen gas and water in a matter of seconds.

The formula for hydrogen peroxide is H₂O₂. It is a pale blue liquid that contains hydrogen, oxygen, and water. When you add yeast, soap, and food coloring, the reaction is more exciting. The yeast acts as a catalyst, breaking down hydrogen peroxide into water and oxygen gas. The oxygen gas created causes the soap to foam up, creating the "elephant toothpaste" effect. The chemical reaction that takes place during the elephant toothpaste demonstration can be written as follows:

2H₂O₂(liquid) → 2H₂O (liquid) + O₂ (gas)

This reaction is an example of a decomposition reaction.

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The normal boiling point of mercury is 629.68 K.

ΔHvap(Hg) = 58. 51 kJ/mol

ΔHvap(Hg) = 58510 J/mol; the enthalpy of vaporization of mercury

ΔSvap(Hg) = 92. 92 J/K·mol; the entropy of vaporization of mercury

Tvap(Hg) = ΔHvap(Hg) ÷ ΔSvap(Hg)

Tvap(Hg) = 58510 J/mol ÷ 92. 92 J/K·mol

Tvap(Hg) = 629.68 K; the boiling point of mercury

The enthalpy of vaporization is the amount of energy that must be added to a substance in liquid state to transform that substance into a gas.

The entropy of vaporization is proportional to the ratio of the degree of randomness in the vapor and liquid phases.

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Answer:

When water dissolves a substance, the water molecules attract and “bond” to the particles (molecules or ions) of the substance causing the particles to separate from each other. The “bond” that a water molecule makes is not a covalent or ionic bond. It is a strong attraction caused by water’s polarity.

Explanation:

Answer:

500 hits

Explanation:

If 20 hits equal 1 web 1 futz equal 2 geese 10 webs equal to 1 futz How many hits are equal to 5 geese?

Solution:

Given that:

20 hits = 1 web, 1 futz = 2 geese; 10 webs = 1 futz

10 webs = 1 futz; hence:

1 web = 1 web * 1 futz / 10 webs = 0.1 futz

1 web = 0.1 futz

1 futz = 2 geese; hence:

0.1 futz = 0.1 futz * 2 geese / 1 futz

0.1 futz = 0.2 geese

Therefore, 1 web = 0.1 futz = 0.2 geese

1 web = 0.2 geese

This means that 20 hits = 1 web = 0.2 geese

20 hits = 0.2 geese

5 geese = 5 geese * 20 hits / 0.2 geese

5 geese = 500 hits

Answer:

-1,300 kJ

Explanation:

P₄  +  3 O₂  ⇒  P₄O₆     ΔH = -1,640.1 kJ    (EQ 1)

P₄O₁₀  ⇒  P₄  +  5 O₂    ΔH = 2,940.1 kJ    (EQ 2)

These are the equations you are given.  You need to make these equations into the equation below.

P₄O₆  +  2 O₂  ⇒  P₄O₁₀  (end equation)

Look at the product side of the end equation.  You need to produce P₄O₁₀.  In the EQ 2, P₄O₁₀ is on the reactant side.  Flip the equation.  Since you flipped the equation, the enthalpy will have the opposite sign.

P₄  +  5 O₂  ⇒  P₄O₁₀    ΔH = -2,940.1 kJ

On the reactant side of the end equation, you need P₄O₆ and 2 O₂.  First, rearrange the equation so that P₄O₆ is on the right side.  In EQ 1, P₄O₆ is on the product side.  Flip the equation.  Like the last one, the sign will change.

Now, cancel out all possible values.  P₄ will cancel out since there is one on each side of the equation.  Since there is 5 O₂ on one side and 3 O₂ on the other, subtract the two and put the remainder on the side of the larger value.

P₄  +  5 O₂  ⇒  P₄O₁₀    ΔH = -2,940.1 kJ

P₄O₆  ⇒  P₄  +  3 O₂     ΔH = 1,640.1 kJ    

P₄O₆  +  2 O₂  ⇒  P₄O₁₀

This should be the resulting equation.  Now, add the two enthalpies together to find the overall enthalpy.

-2,940.1 kJ  +  1,640.1 kJ  = -1,300 kJ

The overall enthalpy is -1,300 kJ.

-867.7Answer:

Explanation:

-867.7

The number of atoms of oxygen in the sample of P2O5 is 9.33 * 10²³ atoms.

A mole of the compound P2O5 contains 5 moles of atom of oxygen and 2 moles of P.

Moles of oxygen in the sample = 0.620 * 5/2 = 1.55 moles of oxygen atoms.

The number of oxygen atoms in 1 mole of oxygen atoms is given by the Avogadro number = 6.02 * 10²³

Number of atoms of oxygen in 1.55 moles -= 1.55 * 6.02 * 10²³ = 9.33 * 10²³ atoms.

Therefore, the Avogadro number is important in determining number of atoms in a compound.

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The Lewis structure of a tetrahedral polar molecule is shown in the image attached.

A Lewis structure is a diagram used to show the bonding between atoms in a molecule or an ion. It was first introduced by the American chemist Gilbert N. Lewis in 1916.

In a Lewis structure, the valence electrons (electrons in the outermost shell) of each atom are represented as dots around the symbol of the atom. The electrons are then paired up to form covalent bonds between atoms. Single bonds are represented by a single line (-) between atoms, while double bonds are represented by two lines (=) and triple bonds by three lines (≡).

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Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\\)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

\(n = \frac{1.00 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{1}{6.02} \\ = 0.166112\)

We have the final answer as

Hope this helps you

Answer:

KNO3 (Potassium Nitrate)

Explanation:

I just know.

Answer:

2

Explanation:

Bcoz 10 g of silver has more atoms than 5 g of silver

A nucleus maintains its stability despite being composed of positively charged particles due to the strong nuclear force that overcomes the repulsion between the protons.

The neutrons in the nucleus play a crucial role in maintaining stability. Neutrons have no charge and do not contribute to the electrostatic repulsion. Their presence helps to increase the attractive nuclear force, balancing the repulsive force between protons. This shielding effect allows the nucleus to remain stable.
Another important factor is that the Coulomb force, which describes the electrostatic repulsion between charged particles, is not applicable at the nuclear level. The range of the Coulomb force is limited, and its influence diminishes at very short distances inside the nucleus. Instead, the strong nuclear force takes over and becomes the dominant force, binding the protons and neutrons together.
Additionally, the surrounding electrons in an atom contribute to the nucleus's stability. Electrons are negatively charged and are located in the electron cloud surrounding the nucleus. Their negative charge helps neutralize the positive charge of the protons, reducing the overall electrostatic repulsion within the atom. This electron-proton attraction further contributes to the stability of the nucleus.

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Answer:

Ammonia is limiting reactant

Amount of oxygen left  = 0.035 mol

Explanation:

Given data:

Masa of ammonia = 2.00 g

Mass of oxygen = 4.00 g

Which is limiting reactant = ?

Excess reactant's amount left = ?

Solution:

Balance chemical equation:

4NH₃ + 3O₂     →     2N₂ + 6H₂O

Number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 2.00 g/ 17 g/mol

Number of moles = 0.12 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 4.00 g/ 32 g/mol

Number of moles = 0.125 mol

Now we will compare the moles of ammonia and oxygen with water and nitrogen.

                       NH₃          :            N₂

                         4             :             2

                       0.12           :           2/4×0.12 = 0.06

                       NH₃         :            H₂O

                         4            :             6

                         0.12       :           6/4×0.12 = 0.18

                        O₂            :            N₂

                         3             :             2

                       0.125        :           2/3×0.125 = 0.08

                         O₂           :            H₂O

                         3              :             6

                         0.125       :           6/3×0.125 = 0.25

The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.

Amount of oxygen left:

                         NH₃          :             O₂

                            4            :              3

                            0.12       :          3/4×0.12= 0.09

Amount of oxygen react = 0.09 mol

Amount of oxygen left  = 0.125 - 0.09 = 0.035 mol

The most helpful feature of the radioisotope americium-241 for the smoke detector to work is its Long half-life.

What is Half-Life?

Half-life is the time required for a quantity to reduce by half to its initial value. The half-life of any radioisotope is represented by \(t_{1/2}\) .

Americium-241 (²⁴¹Am) is the most common isotope of americium.

Americium-241 has a half-life of 432 years.

Am-241 decays by emitting alpha particles and gamma radiation to become neptunium-237.

Thus, the most helpful feature of the radioisotope americium-241 for the smoke detector to work is its Long half-life.

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Smoke detectors are the safety devices for fire protection that detects smoke and gives alarms as a warning. The long half-life of the radioisotope would be most practical for the detector.

Radioisotopes are chemical substances that have unstable neutrons, protons and some amount of excess energy. They have a half-life which is the time by which they get reduced or decay to half quantity.

Americium-241 is the radioactive isotope of americium and have a half-life of 432.2 years. It helps in the alarm as the smoke particle disrupt the electric current produced by the isotope and results in the warning of the device to go on.

Therefore, option A. long half-life is the feature that would be most useful for the smoke sensor.

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Mixing sugar and water is a physical change because it involves the dispersion and uniform distribution of sugar molecules in water without altering their chemical composition.

When sugar (sucrose) and water are mixed, it undergoes a physical change rather than a chemical change. A physical change refers to a transformation in the physical properties of a substance without altering its chemical composition.

In the case of mixing sugar and water, the sugar molecules disperse and become uniformly distributed throughout the water. This results in the formation of a homogeneous mixture known as a solution. The sugar molecules do not undergo a chemical reaction with the water molecules, nor do they break down or form new substances.

The physical change can be reversed by evaporation, where the water molecules can be separated from the sugar molecules, leaving behind the original sugar crystals. The chemical identity of both sugar and water remains the same throughout the process.

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The girl's average speed for running the 5k trail race in 0.05 hours is 62 miles per hour (mph).

To calculate the average speed, we can use the formula:

average speed = distance/time

In this case, the distance is 3.1 miles and the time is 0.05 hours. When we divide 3.1 by 0.05, we get 62 mph.

It's important to note that this calculation gives us the girl's average speed for the entire race. It doesn't take into account any variations in her speed during the race. It's possible that she ran some portions of the race faster than others, or that she had to slow down at some point due to difficult terrain or fatigue. However, for the purpose of calculating her overall average speed, we assume that she maintained a constant pace throughout the race.

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Answer: The newest, thinnest crust on Earth is located near the center of mid-ocean ridge—the actual site of seafloor spreading

Answer:

D. mid-ocean ridge

Explanation:

Answer:you would need to add 36 mL of saline to achieve a continuous treatment lasting 3 hours using a nebulizer with an output of 12 mL/hr.

Explanation:

To calculate the total dosage of Albuterol solution, we need to multiply the concentration of the solution (2.5 mg/0.5 mL) by the total volume of the solution used (4 vials, assuming each vial is 0.5 mL):

Total dosage of Albuterol = (2.5 mg/0.5 mL) * (0.5 mL/vial) * 4 vials

Total dosage of Albuterol = 20 mg

Therefore, the total dosage of Albuterol solution is 20 mg.

To calculate the amount of saline that needs to be added for a continuous treatment lasting 3 hours, we can use the nebulizer's output rate of 12 mL/hr:

Amount of saline needed = Nebulizer output rate * Treatment duration

Amount of saline needed = 12 mL/hr * 3 hr

Amount of saline needed = 36 mL

To achieve a continuous treatment lasting 3 hours using the nebulizer with an output of 12 mL/hr, an additional 34 mL of saline solution would need to be added.

If each vial of Albuterol solution contains 2.5 mg in 0.5 mL, then adding 4 vials would result in a total dosage of 10 mg (2.5 mg/vial * 4 vials).

To achieve a continuous treatment lasting 3 hours using a nebulizer with an output of 12 mL/hr, we need to calculate the amount of saline solution that needs to be added.

The nebulizer has an output of 12 mL/hr, so over 3 hours, it would deliver a total volume of 12 mL/hr * 3 hrs = 36 mL.

Since we have already added the 4 vials of Albuterol solution, we subtract that volume from the total desired volume of 36 mL to determine how much saline needs to be added.

Therefore, the amount of saline to be added would be 36 mL - 2 mL (4 vials * 0.5 mL/vial) = 34 mL.

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