Check the rate of evaporation in a wide mouthed container and narrow mouthed container. Note your observation during the peak of summer & the start of monsoon.​

Answers

Answer 1

Answer:

Because of the summer season

Explanation:

The water in the dish which is uncovered will evaporate faster as compared to the one which is

covered. This is because the air above the uncovered dish has less water vapour over it as

compared to the one which is covered. The covered dish has good amount of moisture over it as

the closed lid does not allow the moisture to come in direct contact with air.


Related Questions

Create your very own cosmic address for your home or school using the following

template.
Name
street
city
state
country
planet
planetary system
Galaxy
Galaxy Group
Galaxy supercluster

Answers

The cosmic address would be as given below:

Name: Micky Michael Street : 120 White Bridge Road NashvilleCity: NashvilleState: Tennessee Country: United state of AmericaPlanet: EarthPlanetary system: Solar systemGalaxy: Milky way galaxyGalaxy group: Local galaxyGalaxy supercluster: Virgo supercluster

What is a galaxy?

A galaxy is a huge collection of gas, dust, and billions of stars and their solar systems.

The Sun is a part of the Milky Way Galaxy.

The cosmic address indicating my address in the universe will be: Micky Michael , 120 White Bridge Road Nashville, Nashville, Tennessee , United state of America, Earth, Solar system, Milky way galaxy, Local galaxy, Virgo supercluster in that order.

In conclusion, a cosmic address is an address showing where one can be found in the universe.

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Consider a galvanic cell with a beaker of sulfuric acid and a beaker of nitric acid. The sulfuric acid beaker contains a strip of tin, and the nitric acid cell contains a strip of platinum. A wire runs between the strips. The reaction that occurs is as follows:

3Sn(s) + 2NO3–(aq) + 8H+(aq) → 3Sn2+(aq) + 2NO(g) + 4H2O(l)

In three to five sentences, list which electrode is the anode and which is the cathode and the half reactions that occur at each electrode.

Answers

I wrote, The platinum electrode is the cathode in this reaction. The tin electrode is the anode in this reaction. In the half reactions that occur the nitrate is reduced to nitric oxide(NO) while the tin electrode is oxidized to Sn2+.

Oxidation occurs at the tin half cell(anode) while reduction occurs at the nitrate half cell(cathode).

A galvanic cell refers to a cell that produces electrical energy spontaneously by redox reaction. Oxidation occurs at the anode while reduction occurs at the cathode in a galvanic cell.

The oxidation half equation at the anode occurs as follows;

3Sn(s) → 3Sn^2+(aq) + 6e

The reduction half equation that occurs at the cathode is;

2NO3–(aq) + 8H+(aq) + 6e→  2NO(g) + 4H2O(l)

We can see that electron loss occurs at the cathode while electron gain occurs at the anode as we can see in the equations above.

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Dubnium-262 has a half-life of 34 seconds. How long will it take to decay to 1g if the original amount was 300g?

Dubnium-262 has a half-life of 34 seconds. How long will it take to decay to 1g if the original amount

Answers

Answer:

305 seconds

Explanation:

Which of these scientist is know for his work in understanding climate change a : edwin hubble b : christian doppler c : warren washington d : charles kuen kao

Answers

Answer: just trust me its c

Explanation: i dont cap

ammonia can be synthesized according to the reaction: a 200.0-l reaction container initially contains 1.27 kg of and 0.310 kg of at 725 k. assuming ideal gas behavior, calculate the mass of (in g) present in the reaction mixture at equilibrium. what is the percent yield of the reaction under these conditions?

Answers

The result suggests that the assumptions made in the calculation may not be valid, since the calculated yield is greater than 100%.

The balanced chemical equation for the synthesis of ammonia is:

N2 + 3H2 → 2NH3

From the given data, we can calculate the number of moles of nitrogen and hydrogen present in the reaction container:

n_N2 = m_N2 / M_N2 = 1.27 kg / 28.02 g/mol = 45.34 mol

n_H2 = m_H2 / M_H2 = 0.310 kg / 2.016 g/mol = 154.09 mol

We can assume that the reaction goes to completion, which means that all of the nitrogen and hydrogen react to form ammonia. According to the stoichiometry of the balanced equation, 3 moles of hydrogen react with 1 mole of nitrogen to form 2 moles of ammonia. Therefore, the total number of moles of ammonia formed is:

At equilibrium, the total number of moles of gas in the container remains constant. Therefore, the number of moles of unreacted nitrogen and hydrogen can be calculated as:

\(n_N2_unreacted = n_N2_initial - (1/3) * n_NH3 = 45.34 mol - (1/3) * 136.02 mol = 3.25 mol\\n_H2_unreacted = n_H2_initial - (1/3) * n_NH3 = 154.09 mol - (1/3) * 136.02 mol = 109.02 mol\)

The total number of moles of gas at equilibrium is:

\(n_total = n_N2_unreacted + n_H2_unreacted + n_NH3 = 3.25 mol + 109.02 mol + 136.02 mol = 248.29 mol\)

The mass of gas present at equilibrium can be calculated from the ideal gas law:

\(PV = nRTm_total = (n_total)(M_total) = (248.29 mol)(28.01 g/mol) = 6958.27 g\)

Therefore, the mass of gas present in the reaction mixture at equilibrium is 6958.27 g.

The percent yield of the reaction can be calculated as the actual amount of ammonia produced (136.02 mol) divided by the theoretical amount of ammonia that could have been produced based on the amount of nitrogen initially present (45.34 mol):

percent yield = (actual yield / theoretical yield) * 100

\(percent yield = (136.02 mol / 45.34 mol) * 100 = 300.3%\)

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Chose all of the correct statements pure vs mixture

Chose all of the correct statements pure vs mixture

Answers

Answer:

I think that a  pure substance is a form of matter that has a constant composition and properties that are constant throughout the sample. Mixtures are physical combinations of two or more elements and/or compounds.

Explanation:

What is the 3D shape of H3o+

Answers

3D view of H3O+

The stronger line means that the Hydrogen is closer to us in a 3D view, meanwhile the line with traces, or you cal also see as a weaker line, it means that the Hydrogen is farther from us in a 3D view

Lewis Structure of H3O+

What is the 3D shape of H3o+
What is the 3D shape of H3o+


How many total atoms found in 2AClCl3

Answers

Answer: 4 atoms.

Explanation:

the volume of a given mass of an ideal gas at a constant pressure is

Answers

Answer:

Charles's law, or the law of volumes, was found in 1787 by Jacques Charles.

A student in the chemistry lab heated a sample of potassium chlorate solid KCIO, (M=122.55 g/mol). 3 The following reaction took place: 2 KClO 2 KCl +30₂ The oxygen gas (M=32 g/mol) produced was collected at 22 °C and 0.964 atm and of vasume 0.65 L. The mass of KCLO 3 that was decomposed in the above reaction is 0.83 2.12 3.17 28.37 grams.​

Answers

The mass of KClO₃ that was decomposed in the given reaction by the ideal gas equation is approximately 7.19 grams.

Given:

Pressure (P) = 0.964 atm

Volume (V) = 0.65 L

Temperature (T) = 22 °C = 22 + 273.15 = 295.15 K

The ideal gas law: PV = nRT

Where:

P = Pressure in atm

V = Volume in liters

n = Number of moles

R = Ideal gas constant = 0.0821 L·atm/(mol·K)

T = Temperature in Kelvin

n = (PV) / (RT)

n = (0.964 atm) × (0.65 L) / (0.0821 L·atm/(mol·K) × 295.15 K)

n ≈ 0.0294 mol

2 moles of KClO₃ produce 1 mole of O₂. Therefore, the number of moles of KClO₃decomposed would be:

Moles of KClO₃= 2 × 0.0294 mol

Moles of KClO₃≈ 0.0588 mol

Molar mass of KClO₃= 122.55 g/mol

Mass of KClO₃= Moles of KClO₃× Molar mass of KClO₃

Mass of KClO₃≈ 0.0588 mol × 122.55 g/mol

Mass of KClO₃≈ 7.19 grams

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Convert 2.68 mol H2O to molecules H2O
Timed test

Answers

Molecules h20 is .134

Consider the reaction HNO2(aq) + H2O(l) H3O+(aq) + NO2-(aq). Which species is a conjugate base?
A) HNO2(aq)
B) H2O(l)
C) H3O+(aq)
D) NO2-(aq)
E) two of these

Answers

A species which a conjugate base is NO₂⁻(aq).

So, the correct answer is D.

What's conjugate base

In the given reaction, the acid HNO₂ donates a proton to water to form the hydronium ion (H₃O⁺) and the nitrite ion (NO₂⁻).

A conjugate base is the species that remains after an acid loses a proton.

In this case, HNO₂ donates a proton, so it is the acid and its conjugate base is the NO₂⁻ ion.

Therefore, the answer is option D) NO₂⁻(aq) is the conjugate base in the given reaction.

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How does a ligand bind to the proper receptor?

Answers

Answer:

The ligand crosses the plasma membrane and binds to the receptor in the cytoplasm.

Answer:

The receptor then moves to the nucleus, where it binds DNA to regulate transcription.

Which statement best describes comparative and descriptive investigations?

Answers

Answer:

they both include a question, procedure and conclusion.

Explanation:

A 2.65 g sample of a salmon colored poweder contains 0.70 g of chromium, 0.65 g of sulfur, and 1.30 g of oxygen. The molar mass is 392.2. What is the formula of the compound

Answers

The formula of the compound is \($\mathrm{Cr}_{2} \mathrm{~S}_{3} \mathrm{O}_{12}$\)

Given

Salmon colored powder = 2.65 g

Chromium = 0.70 g

Sulfur = 0.65 g

Oxygen = 1.30 g

Molar mass = 392.2

Formula

Molar mass = gram / moles

Molecular formulaA chemical equation that specifies how many atoms of each element there are in each substance's molecules.The simplest whole-number ratio of the various atoms in a compound is represented by an empirical formula. The precise number of various atom types present in a compound's molecule is indicated by the molecular formula.

Molar mass of chromium

= 0.70 / 0.0135

= 52

Molar mass of salmon

= 0.65 / 0.0203

= 32.06

Molar mass of oxygen

= 1.30 / 0.0813

= 16

Molecular formula = 392.2 / (Cr + 3 S + 12 O)

                              = 392.2 / (52.00 + (3 x 32.06 + 12 x 16.00) ≈ 1

So, The formula of the compound is \($\mathrm{Cr}_{2} \mathrm{~S}_{3} \mathrm{O}_{12}$\)

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3 natural compounds of chlorine

Answers

The a awnser is above me

5. When placed in water, objects with a density of greater than 1 gm/cm3 will
a: Sink
b:Float


Explain your answer.​

Answers

Answer:

A: sink

Explanation: If an object's density is:

GREATER than \(1gcm^{3}\), it will SINK in water.

LESS than \(1gcm^{3}\), it will FLOAT in water.

hope this helps

List the physical properties that most metals have in common.

Answers

Answer:

Typical physical properties of metals :

high melting points.

good conductors of electricity.

good conductors of heat.

high density.

malleable.

ductile.

Explanation:

Answer:

-high melting points.

-good conductors of electricity.

-good conductors of heat.

-high density.

-malleable.

-ductile.

Explanation:

have a nice day

6.2
A student investigates the decomposition reaction in the laboratory. The student prepares two small beakers, adding 20.0mL20.0mL of 9.77MH2O2(aq)9.77MH2O2(aq) to each one. Each beaker is placed on an electronic balance. The student adds 0.10g0.10g of MnO2(s)MnO2(s) to the second beaker and records the mass of each beaker and its contents at 10-second intervals for one minute. The beakers and the data are shown below.
(c) For beaker 2 during the 60-second period, calculate the following.
(ii) The mass of H2O2(aq)H2O2(aq) that decomposed

Answers

The decomposed mass of H₂O₂(aq) in beaker 2 is m1 - m2.

How to calculate the decomposed H2O2(aq) mass?

To calculate the mass of H₂O₂(aq) that decomposed in beaker 2 during the 60-second period, we need to find the difference in mass before and after the reaction.

Let's assume that the mass of beaker 2 with H₂O₂(aq) and MnO₂(s) at the start of the 60-second period is m1, and the mass at the end of the 60-second period is m2.

The mass of H₂O₂(aq) that decomposed can be calculated as:

Mass of H₂O₂(aq) decomposed = m1 - m2

Note that the mass of MnO₂(s) added (0.10g) does not affect the calculation since it remains unchanged throughout the reaction.

Since we don't have the actual mass values provided, you will need to refer to the recorded data or measurements from the experiment to calculate the mass of H₂O₂(aq) that decomposed in beaker 2.

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arrange the bromine-containing compounds cabr2, br2, asbr3, cbr4 in order of increasing normal boiling point.

Answers

Answer:

Br2, CBr4, AsBr3, CaBr2. this is the increasing order of boiling point

The arrangement of given compound in the increasing order of normal boiling point is Br₂ < CBr₄ < AsBr₃ < CaBr₂.

What is normal boiling point?

Norma boiling point of any liquid is that point where the vapor pressure is equal to the standard sea level atmospheric pressure.

And boiling point is directly proportional to the strength of bond which is present between the atoms of any compound.

As we know that ionic bond is the strongest bond and in CaBr₂ ionic bond is present so the boiling point of this compound will be highest.In AsBr₃, bromine is more electronegative than arsenic and arsenic also have one lone pair on it so some dipole moment develope in it and then this compound will have boiling point less than CaBr₂.CBr₄ is a covalent compound as in this compound bromine is present which is more electronegative but overall dipole moment of this compound is zero.Br₂ is also a covalent molecule and it has no dipole moment in it and have minimun boiling point among all compounds.

So, correct order will be Br₂ < CBr₄ < AsBr₃ < CaBr₂.

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if H2SO4 contacts the skin, it is cleaned fast with a dry cloth and then rinsed with:

A) H20+vinegar
B) H2O+baking soda
C) H2O+table salt​

Answers

Answer:

(B) H2O + Baking soda

Explanation:

H2SO4 is commonly known as Sulfuric acid. It is a strong acid which can cause severe damage to body parts when comes in contact. If H2SO4 contacts the skin then it will be quite irritating for the skin so its better to apply water (H2O) with Baking soda.

Baking soda is of alkaline nature when it will react with H2SO4 it will undergo neutralization and the effect of the strong acid H2SO4 will be minimized.

The chemical reaction between baking soda and H2SO4 is

H2SO4(aq) + 2NaHCO3(aq) →  Na2SO4(aq) + 2CO2(g) + 2H2O(l)

Therefore the reaction is known as neutralization reaction. This aqueous baking soda reacting with Sulfuric acid neutralizes its effect and minimize its effect on the skin.

The reactant which is consumed completely in a reaction is called the excess reactant. TRUE or FALSE​

Answers

Answer:

False

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Which of following will increase the non-ideal behavior of gases? 1. Increasing system volume II. Increasing system temperature III. Increasing system pressure IV. Increasing the number of gas molecules OIV only O II, III and IV lll and IV O land II Previous​

please helpp!!

Answers

The ideal gas behavior is only observed when the gases have zero volume and no intermolecular forces among them. However, in reality, gases have a small volume and some weak intermolecular forces. The behaviour of the gases is more non-ideal under certain conditions.

Out of the given options, the following will increase the non-ideal behavior of gases are increasing the system volume, increasing the system temperature and increasing the number of gas molecules. Therefore, the correct options are (II), (III) and (IV). When the gas particles come closer to each other, the intermolecular forces between them start to become important, and the gas no longer obeys the ideal gas laws. The ideal gas law is described as PV=nRT, where P is pressure, V is volume, n is the number of molecules, R is the universal gas constant, and T is temperature. Ideal gases have high temperature and low pressure. Ideal gas behavior is observed when the volume is high, the temperature is high, and pressure is low, whereas non-ideal behavior is observed when the volume is low, temperature is low, and pressure is high.

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Choose all of the items needed to complete a
circuit

resistor

wire

battery

pencil

plug

Answers

Answer:

wire battery and maybe something to use that power but a simple circuit is just electricity coning from the source and going back after powering something sorry if this is a little lacking

The following balanced equation shows the formation of ammonia. n2 3h2 right arrow. 2nh3 how many moles of nitrogen are needed to completely convert 6.34 mol of hydrogen? 1.02 mol 2.11 mol 12.68 mol 19.02 mol

Answers

The required moles of nitrogen which are needed to completely convert 6.34 moles of hydrogen is 2.11 moles.

What is the stoichiometry?

Stoichiometry of any reaction gives idea about the relative amount of reactants and products are present in any chemical reaction in terms of moles.

Given chemical reaction is:

N₂ + 3H₂ → 2NH₃

From the stoichiometry of the reaction:

3 moles of H₂ = reacts with 1 mole of N₂

6.34 moles of H₂ = reacts with 1/3×6.34=2.11 moles of N₂

Hence required moles of nitrogen are 2.11.

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Tetraphosphorus decoxide (solid) and phosphorous pentachloride (solid) react to produce phosphorus oxychloride (POCl3). Write out the molecular equation with phases.

A: How many grams of phosphorus oxychloride can theoretically produce when we react with 75.00 grams of tetraphosphorus decoxide and 225.0 grams of phosphorus pentachloride?

B: How many grams of the excess recess reactant would remain?

C: If someone reacts 15.33 grams of phosphorus pentachloride with excess of the other reactant, She isolates 5.74 grams of the product. What is the percent yield?

Answers

A)  The theoretical yield of phosphorus pentachloride(POCl3) is 406.0 grams.

The balanced molecular equation:

P4O10 (s) + 10 PCl5 (s) → 10 POCl3 (l) + 4 PCl3 (g)

To determine the theoretical yield of phosphorus oxychloride (POCl3), we first need to calculate the limiting reactant:

Molar mass of P4O10 = 4(31.0) + 10(16.0) = 284.0 g/mol

Molar mass of PCl5 = 5(35.5) + 1(30.97) = 208.2 g/mol

n(P4O10) = 75.00 g / 284.0 g/mol = 0.264 mols

n(PCl5) = 225.0 g / 208.2 g/mol = 1.081 mols

From the balanced equation, we can see that 1 mol of P4O10 reacts with 10 mols of PCl5 to produce 10 mols of POCl3. Therefore, P4O10 is the limiting reactant as it only produces 2.64 mols of POCl3 while PCl5 can produce 10.81 mols of POCl3.

The theoretical yield of POCl3 is calculated as:

n(POCl3) = n(P4O10) × 10 = 0.264 mol × 10 = 2.64 mol

Mass of POCl3 = n(POCl3) × Molar mass of POCl3

= 2.64 mol × 153.82 g/mol

= 406.0 g

Therefore, the theoretical yield of POCl3 is 406.0 grams.

B)  170.1 grams of excess PCl5 will remain after the reaction.

To determine the mass of the excess reactant that remains, we need to calculate the amount of PCl5 that reacts with P4O10, and then subtract it from the initial amount of PCl5:

n(PCl5) reacted = n(POCl3) produced / 10 = 2.64 mol / 10 = 0.264 mol

n(PCl5) remaining = n(PCl5) initial - n(PCl5) reacted

= 1.081 mol - 0.264 mol

= 0.817 mol

Mass of excess PCl5 remaining = n(PCl5) remaining × Molar mass of PCl5

= 0.817 mol × 208.2 g/mol

= 170.1 g

Therefore, 170.1 grams of excess PCl5 will remain after the reaction.

C) the percent yield of POCl3 is 2.43%.

The percent yield can be calculated using the actual yield and theoretical yield of the reaction:

Actual yield = 5.74 g

Theoretical yield of POCl3 = 15.33 g PCl5 × (1 mol POCl3 / 1 mol PCl5) × (153.82 g POCl3 / 1 mol POCl3) = 235.7 g

Percent yield = (Actual yield / Theoretical yield) × 100%

= (5.74 g / 235.7 g) × 100%

= 2.43%

Therefore, the percent yield of POCl3 is 2.43%.

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The initial pressure of a balloon floating in the air is 0.53 atm. After the balloon has reached a certain point in the sky, the volume of the air particles in the balloon is 4.3 liters at a final pressure of 0.42 atm. What was the initial volume of the balloon?

Answers

Answer:

The initial volume of the balloon is 3.41 L.

Explanation:

The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature, and moles.

As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them fewer times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law which says:

"The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure"

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

or P * V = k

Now it is possible to assume that you have a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:

P1 * V1 = P2 * V2

In this case:

P1= 0.53 atmV1= ?P2= 0.42 atmV2= 4.3 L

Replacing:

0.53 atm* V1= 0.42 atm* 4.3 L

Solving:

\(V1=\frac{0.42 atm* 4.3 L}{0.53 atm}\)

V1= 3.41 L

The initial volume of the balloon is 3.41 L.

what is the mass of this tiny bubble of dry air? molecular masses are 28 for nitrogen and 32 for oxygen.

Answers

The mass of the tiny bubble of dry air containing 78% N₂ and 22 % O₂ is 28.88 g/mol.

The molecular masses of  N₂  and O₂  are 28 g/mol and 32 g/mol respectively.

Tiny bubbles found in dry air is the air inside a solid, liquid or surrounded by a colloid within a fluidic environment.

The approximate molecular mass of dry air is calculated as

=  [molecular mass of  N₂ × mass percentage of  N₂] +  [molecular mass of  O₂× mass percentage of  O₂] / mass percent of  N₂ + mass percent of   O₂

=[28×78]+[32×22]/78 +22

=28.88 g/mol

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Single strand RNA is made using the genetic instructions from double strand DNA.
Proteins are made from the instructions in RNA.

True
False

Answers

False I’m pretty sure

what is the concentration, in m/v percent, of a solution prepared from 50. g nacl and 2.5 l of water?

Answers

The concentration, in m/v percent, of a solution prepared from 50. g nacl and 2.5 l of water is 2 %.

The mass/volume percent is the ratio of a solution's total volume to the mass of the solute that makes up that solution. Since this type of concentration has been expressed as a percentage, the given proportion should be multiplied by 100.

The calculation if concentration is shown as:

It can be calculate as follows:

% NaCl = Mass of NaCl / Total mass × 100 %

% NaCl = 50 gram / 2500 × 100 %

%  NaCl = 2 %.

As a result, the solution made from 50 g of nacl and 2.5 l of water will have a 2% concentration.

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