charges between reactants and products do not cancel out. look at it as
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When a chemical reaction occurs, electrons are transferred or shared between the reactants to form products. However, the charges of the reactants and products do not cancel out. This is because the number of electrons transferred or shared may not be equal, leading to an imbalance of charges.
For example, in the reaction between sodium (Na) and chlorine (Cl) to form sodium chloride (NaCl), Na loses an electron to Cl to form Na+ and Cl-. The charges of the reactants are +1 for Na and 0 for Cl, while the charges of the products are +1 for Na+ and -1 for Cl-. These charges do not cancel out, resulting in an overall charge of 0 for NaCl.
This is important to consider when balancing chemical equations and predicting the behavior of reactions. It also highlights the importance of understanding the concept of charges in chemistry.
In some chemical reactions, the charges between reactants and products may not cancel out completely. This is often the case when the reaction involves ions with different charges. It is important to note that charge conservation must be maintained, meaning the total charge on the reactants' side must equal the total charge on the products' side.
To better understand this concept, let's consider a simple example. In the reaction between sodium (Na) and chlorine (Cl) to form sodium chloride (NaCl), the charges between reactants and products do cancel out.
Reactants: Na (neutral) + Cl (neutral)
Products: Na^+ (positive) + Cl^- (negative)
The charges on the reactants' side are neutral, and on the products' side, the positive and negative charges of the ions balance each other, maintaining charge conservation.
However, in a reaction like the following:
2 Al + 3 Br2 → 2 AlBr3
Reactants: 2 Al (neutral) + 3 Br2 (neutral)
Products: 2 Al^3+ (6 positive charges) + 6 Br^- (6 negative charges)
In this case, the charges between reactants and products do not cancel out individually, but the total charges on both sides of the reaction are still equal (zero). The charge conservation principle is maintained as the sum of charges on the reactants' side equals the sum of charges on the products' side.
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Related Questions
To prepare a buffer solution for an experiment, a student measured out 53.49g of NH4Cl(s) (molar mass 53.49g/mol) and added it to 1.0L of 1.0MNH3(aq). However, in the process of adding the NH4Cl(s) to the NH3(aq), the student spilled some of the NH4Cl(s) onto the bench top. As a result, only about 50.g of NH4Cl(s) was actually added to the 1.0MNH3(aq). Which of the following best describes how the buffer capacity of the solution is affected as a result of the spill?
A) The solution has a greater buffer capacity for the addition of base than for acid, because [NH3]<[NH4+]
B) The solution has a greater buffer capacity for the addition of base than for acid, because [NH3]>[NH4+]
C) The solution has a greater buffer capacity for the addition of acid than for base, because [NH3]<[NH4+]
D) The solution has a greater buffer capacity for the addition of acid than for base, because [NH3]>[NH4+]
Answers
The buffer solution is made by mixing NH3(aq) and NH4Cl(s) where NH3 acts as a base and NH4+ acts as an acid.
The solution has a greater buffer capacity for the addition of acid than for base, because [NH3]>[NH4+].When the NH4Cl(s) was added to the NH3(aq) for the experiment, only about 50g of NH4Cl(s) was added, although 53.49g of NH4Cl(s) was measured. This means that the buffer capacity of the solution will be affected.
The pH of the buffer solution is determined by the concentration of NH3 and NH4+. If there is more NH3 than NH4+, the pH will be basic, and if there is more NH4+ than NH3, the pH will be acidic.
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the molecular formula mass for sulfur dioxide is 54 grams. T and f
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The statement that the molecular formula mass for sulfur dioxide is 54 grams is false. The correct molecular formula mass for sulfur dioxide is 64 grams.
Sulfur dioxide (SO2) is a chemical compound composed of one sulfur atom (atomic mass of 32 grams) and two oxygen atoms (atomic mass of 16 grams each). To calculate the molecular formula mass of sulfur dioxide, we add the atomic masses of each atom in the compound. In this case, 32 grams (sulfur) + 16 grams (oxygen) + 16 grams (oxygen) equals a total molecular formula mass of 64 grams. Therefore, the molecular formula mass for sulfur dioxide is 64 grams, not 54 grams.
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PLEASE HELP!!
Electron configuration using the aufbau configuration. Which means filing in the order of lowest energy level
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6) Cobalt - [Ar] 3d⁷4s²
7) Silver -[Kr] 4d¹⁰5s¹
8) tellurium - [Kr] 4d¹⁰ 5s² 5p⁴
9) radium - Rn 7s²
10) lawrencium - [Rn] 5f¹⁴ 7s² 7p¹
11) 1s² 2s² 2p⁴ 3s² 3p⁶ 4s² 3d¹⁰4p⁶ 5s¹ - strontium
13) [Kr] 5s² 4d¹⁰ 5p³- antimony atom
14) [Xe] 6s² 4f¹⁴ 5d⁶ - Osmium
15)[Rn] 5f¹⁴ 7s² 7p¹ - Einsteinium
16) 1s² 2s² 2p⁴ 3s² 3p⁶ 4s² 4d¹⁰ 4p⁵ - Bromine
17) 1s² 2s² 2p6 3s² 3d⁵ - Chlorine
18) [Ra]7s²5f⁶ - Einsteinium
19) [Kr] 5s² 4d¹⁰ 5p⁵ - Tellurium
20) [Xe] - Xenon.
How do you determine the configuration of electrons?The shell number (n) is the first symbol used to represent an electron configuration, followed by the type of orbital and the superscript number of electrons in the orbital. Consider this: The periodic table shows that oxygen has eight electrons.
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Which of the following is the correct calculation for determining the density of an object with a mass of 54 g and a volume of 6mL
Answers
Answer:
d=m/v=9
Explanation:
3.25 kcal is the same amount of energy as A. 3.25J. B. 0.7771. C. 777J. D. 13600 j.
Answers
Kilocalorie is a unit of measuring the amount of energy of a reaction, but this is not the only unit, we can also have Joules as a unit, and the conversion is:
1 Kcal = 4184 Joules
Therefore if we have 3.25 Kcal, we will have:
3.25 * 4184 = 13600 Joules of energy, therefore letter D
If 4.50 mol of ethane, C2H6, undergo combustion according to the unbalanced equation C2H6+ O2 CO2 + H20, how many moles of each product are formed?
Answers
Taking into account the reaction stoichiometry, 9 moles of CO₂ and 13.5 grams of H₂O are formed if 4.50 mol of ethane undergo combustion.
Reaction stoichiometryIn first place, the balanced reaction is:
2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
C₂H₆: 2 molesO₂: 7 molesCO₂: 4 gramsH₂O: 6 molesMoles of each product formedThe following rule of three can be applied:
if by reaction stoichiometry 2 moles of C₂H₆ form 4 moles of CO₂, 4.50 moles of C₂H₆ form how many moles of CO₂?moles of CO₂= (4.50 moles of C₂H₆×4 moles of CO₂)÷ 2 moles of C₂H₆
moles of CO₂= 9 moles
if by reaction stoichiometry 2 moles of C₂H₆ form 6 moles of H₂O, 4.50 moles of C₂H₆ form how many moles of H₂O?moles of H₂O= (4.50 moles of C₂H₆×6 moles of H₂O)÷ 2 moles of C₂H₆
moles of H₂O= 13.5 moles
Finally, 9 moles of CO₂ and 13.5 grams of H₂O are formed.
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True or False: Polypeptides inside the ER are usually smaller than polypeptides synthesized from the same mRNA that have not entered the ER.
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True. For these before leaving the ER undergo a process called N-terminal signal peptide cleavage. During this process, the signal peptide, which is an amino acid sequence that helps guide the protein into the ER, is cleaved, resulting in a smaller polypeptide.
What are Polypeptides?Polypeptides are composed of a variety of different amino acids that are linked together in a sequence. This sequence of amino acids determines the structure and function of the protein that they make up. Polypeptides are essential components of cells, playing a role in many essential processes, including:
MetabolismSignalingGene expressionThey are found in the cytoplasm and nucleus of cells, as well as in extracellular fluid. Polypeptides are also important components of:
HormonesEnzymesAntibodiesLearn more about The Polypeptides:
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Use standard enthalpies of formation to calculate the standard enthalpy of reaction for the following reaction:
2 H2S(g) + 3 O2(g) → 2 H2O(l) + 2 SO2(g) ΔH∘rxn
Answers
The standard enthalpy of the reaction for the given equation is -863.2 kJ/mol.
The standard enthalpy of the reaction can be calculated by subtracting the sum of the standard enthalpies of the formation of the reactants from the sum of the standard enthalpies of the formation of the products:
ΔH∘rxn = ΣnΔH∘f(products) - ΣmΔH∘f(reactants)
where n and m are the coefficients in the balanced chemical equation, and ΔH∘f is the standard enthalpy of formation.
The standard enthalpy of formation for H2S(g), H2O(l), and SO2(g) can be found in tables as follows:
ΔH∘f(H2S(g)) = -20.2 kJ/mol
ΔH∘f(H2O(l)) = -285.8 kJ/mol
ΔH∘f(SO2(g)) = -296.8 kJ/mol
O2(g) is an elemental form and has a standard enthalpy of formation of 0 kJ/mol.
Using these values and the balanced chemical equation, we can calculate the standard enthalpy of the reaction:
ΔH∘rxn = [2(-285.8 kJ/mol) + 2(-296.8 kJ/mol)] - [2(-20.2 kJ/mol) + 3(0 kJ/mol)]
= -863.2 kJ/mol
Therefore, the standard enthalpy of the reaction for the given equation is -863.2 kJ/mol.
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SOMEONE PLZZZZ HELP 30 POINTS!!!!!!!!!
How does concentration, temperature and catalyst relate to Forensic Science and toxicology?
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Concentration, temperature and catalyst is directly related to Forensic Science and toxicology due to their effects.
Relation of quantity, temperatureThe concentration, temperature and catalyst is related to Forensic Science and toxicology because different substances show their effects at different dosage which is responsible for the change in the subject who is allowed to them.
At a normal range, a substance or liquid has no negative effect when it is used at high concentration it can cause adverse effect on the body. Some chemicals are in good condition when it is placed in normal temperature range but shows adverse effect when the temperature becomes high so we can conclude that concentration, temperature and catalyst is directly related to Forensic Science and toxicology.
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Determine whether each of the following atoms will form a nonpolar covalent compound or a polar covalent compound, and give the formula of the compound.
(a) 2 oxygen
(b) hydrogen and bromine
(c) oxygen and 2 hydrogen
(d) 2 iodine
Answers
(a) Nonpolar covalent compound: O2 , (b) Polar covalent compound: HBr, (c) Nonpolar covalent compound: H2O and (d) Nonpolar covalent compound: I2 .
What is Nonpolar ?Nonpolar molecules are molecules that have no electrical charge and a symmetrical distribution of electrons. This means that the molecules have a uniform distribution of electrons around its nucleus, creating no electrical imbalance. Nonpolar molecules are not attracted to other molecules, so they tend to be more stable and have lower boiling points than molecules with electrical charges. Examples of nonpolar molecules include methane, carbon dioxide, and hydrogen. Nonpolar molecules are also hydrophobic, meaning they do not mix with water, so they tend to be less soluble in water than polar molecules.
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The total number of d orbitals in the third principal energy
level is
Answers
Answer:
Five.
Explanation:
The third principal energy level has one s orbital, three p orbitals, and five d orbitals, which can each hold up to 10 electrons. This allows for a maximum of 18 electrons.
Methanol, CH3OH , is formed from methane and water in a two‑step process. Step 1:Step 2:CH4(g)+H2O(g)CO(g)+2H2(g)⟶CO(g)+3H2(g)⟶CH3OH(l)Δ∘=214.7 J/KΔ∘=−332.3 J/K Calculate ΔH∘ and Δ∘ at 298 K for step 1. Standard enthalpy of formation values can be found in the table of thermodynamic properties.ΔH∘= kJΔ∘= kJwhy is the production of methanol from methane and water performed in a two‑step process instead of a one‑step process?
Answers
A one-step process would require a higher energy input and may not be as economically viable. The two-step process for producing methanol from methane and water is used because it is more thermodynamically favorable.
The first step, which produces carbon monoxide and hydrogen gas, has a positive ΔH∘ of 214.7 J/K, meaning it requires energy input. However, the second step, which produces methanol from the carbon monoxide and hydrogen gas, has a negative ΔH∘ of -332.3 J/K, meaning it releases energy. By combining these two steps, the overall ΔH∘ for the reaction is negative and energy is released, making the process more efficient. A one-step process would require a higher energy input and may not be as economically viable.
Methanol (CH3OH) is produced from methane (CH4) and water (H2O) through a two-step process. In Step 1, methane and water react to form carbon monoxide (CO) and hydrogen gas (H2). This reaction has a standard enthalpy change (ΔH°) of 214.7 kJ and a standard entropy change (ΔS°) of -332.3 J/K at 298 K.
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What is this picture an example of?
A. carbon cycle
B. nitrogen cycle
C. water cycle
D. ecological succession
PLEASE HELP
Sorry if the picture is bad Quality
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Answer:
i think it is D
Explanation:
i dont know what you are learning but ecological succession is the change of enviroment pretty much.
How do I memorize all the elements on the periodic table?
Answers
Answer:
write down each element and what you need to know about it repeatedly, and it will burn into your brain
Explanation:
when the concentration of a and b were 0.023 m and 0.054 m, the reaction rate was 8.31x10-2 m/sec, calculate the value for k (with units).
Answers
The reaction takes place in third order. The rate constant of the reaction for the given rate and concentrations is 1.23 × 10³ mol⁻² L² /s.
What is reaction rate?The rate of a reaction is the rate of increase in the concentration of products or rate of decrease in the concentration of the reactants.
For the given reaction, the rate law is written as:
rate = k[A][B]²
[A] = 0.023
[B] = 0.054
rate = 8.31 ×10⁻² M/s
Rate constant k = rate/[A] [B]²
K = 8.31 ×10⁻² M/s/(0.023 × 0.054²)
= 1.23 × 10³ mol⁻² L² /s
Therefore, the rate constant for the reaction is 1.23 × 10³ mol⁻² L² /s.
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Your question is incomplete. But your complete question probably was:
The rate of a reaction is, Rate = k[A][B]2.when the concentration of a and b were 0.023 m and 0.054 m, the reaction rate was 8.31x10-2 m/sec, calculate the value for k (with units).
What is the Lewis dot structure of SO3?
Answers
The Lewis dot structure of SO₃ with oxygen and sulfur atoms is attached in the image below .
What are Lewis dot structures?Lewis dot structures are also called as electron dot structures and can be drawn if the molecular formula of a compound is known. It provides information regarding the nature of bond and the position of atoms .
They are also capable of exhibiting the lone pair if any present in a molecule or compound.Lewis defined a base to be an electron pair donor and an acid to be an electron pair acceptor.
They are capable of reflecting electronic structure of elements and even the pairing of electrons . In the diagram, each dot represents an electron while a pair of dots represent a bond between the atoms.
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A student proposed the Bohr model below for sodium (Na). Is this student’s model correct? Justify your answer
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The Bohr model is a representation of the electronic configuration of the atom. According to this model, each energy level can hold a certain number of electrons. In the first energy there can only be 2 electrons, in the second and the following energy levels there can be a maximum of 8 electrons.
Sodium, Na which has 11 electrons in total so in the first level it will have two electrons, in the second level it will have 8 electrons and in the third level it will have the missing electron.
In the model proposed by the student, the electrons are represented in blue. The model proposed by the student is incorrect.
We see that in the second energy level he drew 9 electrons, this is incorrect since from the second energy level there can only be 8 electrons, the remaining electron must be located in the third energy level.
12. Determine the number of moles of boric acid that react in the equation to produce 10 moles of water.
Answers
In the preceding equation, 6.67 moles of boric acid (\(H_3BO_3\)) will react to generate 10 moles of water (\(H_2O\)).
To determine the number of moles of boric acid that react in the equation to produce 10 moles of water, we need to examine the balanced chemical equation and use stoichiometry.
1. Begin by examining the balanced chemical equation for the reaction involving boric acid and water. Let's assume the equation is:
\(3H_2O\) + \(3H_2O\) -> \(B_2O_3\) + \(6H_2O\)
2. From the balanced equation, we can see that 2 moles of boric acid (H3BO3) react with 3 moles of water (\(H_2O\)) to produce 6 moles of water (\(H_2O\)).
3. Use the given information that 10 moles of water (\(H_2O\)) are produced. Since the stoichiometric ratio between boric acid and water is 2:3, we can set up a proportion to find the number of moles of boric acid:
2 moles \(H_3BO_3\) / 3 moles \(H_2O\) = x moles \(H_3BO_3\) / 10 moles \(H_2O\)
4. Cross-multiply and solve for x:
(2 moles \(H_3BO_3\))(10 moles \(H_2O\)) = (3 moles \(H_2O\))(x moles \(H_3BO_3\))
20 moles \(H_2O\) = 3x moles \(H_3BO_3\)
5. Divide both sides of the equation by 3 to isolate x:
x moles \(H_3BO_3\) = (20 moles \(H_2O\)) / 3
6. Calculate the value of x:
x moles \(H_3BO_3\) ≈ 6.67 moles \(H_3BO_3\)
Therefore, approximately 6.67 moles of boric acid (\(H_3BO_3\)) will react to produce 10 moles of water (\(H_2O\)) in the given equation.
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what is the kinetic energy of an object with velocity of 7m /s and a 14kg mass?
Answers
Answer:
343 JExplanation:
The kinetic energy of an object can be found by using the formula
\(k = \frac{1}{2} m {v}^{2} \\ \)
m is the mass
v is the velocity
We have
\(k = \frac{1}{2} \times 14 \times {7}^{2} \\ = 7 \times49 \\ = 343 \: \: \: \: \: \)
We have the final answer as
343 JHope this helps you
Solar energy does not warm Earth’s surface evenly. For example, during the day, land areas warm up faster than nearby bodies of water. How does this uneven warming affect the movement of air over land and water?
Answers
Answer:
Land and sea breeze
Explanation:
This uneven warming of the land during the day results in the phenomenon called land and sea breeze.
During the day, the land heats up faster than the nearby ocean. Ocean is made up of water with a high specific heat capacity. This derives pressurized air near the surface of the land to the ocean. At night, the ocean does not easily lose heat after the land has lost its own. Pressurized air moves from the ocean to the land. This causes the warming of the land during the night.Which of these are intensive properties? There can be more than one answer.
A) a substance has a density of 4.13 g/cm3
B) a substance has a melting point of 40°C
C) a substance is very malleable (it can be hammered into a shape)
D) a substance has a mass of 1.25 g
E) a substance has a volume of 5.4 mL
Answers
The intensive properties among the options provided are:
A) a substance has a density of 4.13 g/cm3
D) a substance has a mass of 1.25 g
E) a substance has a volume of 5.4 mL
Intensive properties are those that do not depend on the amount or size of the substance but are characteristic of the substance itself.
These properties, density, mass, and volume, are intrinsic to the substance and do not change with the quantity of the substance present. They are independent of the amount of the substance and remain constant regardless of the sample size.
On the other hand, melting point (B) and malleability (C) are not considered intensive properties. Melting point can vary depending on external conditions such as pressure, and malleability is influenced by the structure and composition of the substance, which can be affected by impurities or processing methods. These properties can change with the amount or size of the substance and are considered extensive properties.
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Please help the question is on the photo attached
Answers
Answer:
296,875,000 mol
Explanation:
1mol of SO2 is 64g
1.9×10⁷ kg ----> 1.9×10¹⁰g
1mol ----> 64g
x -----> 1.9×10¹⁰g
x= 1.9×10¹⁰/64 mols
= 296,875,000 mol
provide an explanation for thermohaline circulation. what is it? what drives it? describe the pattern of water movement. how and why might climate change cause thermohaline currents to be interrupted?
Answers
Thermohaline circulation is very important because it supplies heat to the polar regions. If this circulation stopped, the average temperature of polar regions would cool down to 5-10 degrees Celsius. It could be fatal to underwater creatures and might trigger hurricanes in those regions.
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The Earth has always been a hospitable haven for life. ture or flase
Answers
Answer:
True and false at the same time
Explanation:
It is true that Earth is heaven for life but It's also hell for life because people suffer a lot and so does the Earth. Earth is a hell for life because of all the bullying, criticism, racism, sexism, and homophobic people. Life is a great thing to enjoy but with all the negative things that happened and keep happening in the world, it's a living hell for a life. The only good things are that you can explore and do things you never thought of doing before and you are ale=ways surrounded by people who love you and appreciate you for who you are but it's a 5-50 chance of you getting an opportunity like that.
I'm not a negative person it's just the ways that things are. I hope this answers your question!
Have a nice day! UwU
2.9g of a gas at 95°C occupied the same volume as 0.184g of dihydrogen at 17°C at the same pressure. What is the molar mass of the gas?
Answers
The molar mass of the gas at the same pressure is M = 40g/mol.
Equation :Let M, be the molar mass of the gas
The number of moles of the gas,
n= 2.9 / M
The volume of the gas,
V= P/nRT
V = 2.9R x 368 / MP
The number of moles of dihydrogen,
n = 0.184 / 2
n =0.092
The volume of dihydrogen gas,
v = 0.092×R×290 / P
At the same pressure P,
The volume of gas = volume of dihydrogen
0.092R×290= 2.9R×368 / M
M= 2.9×368 / 0.092×290
M = 40
Hence, the molar mass of the gas is 40g/mol.
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compared with an electron transition from the first excited state to the ground state, a transition from the third excited state to the second excited state emits a photon of
Answers
A transition from the third excited state to the second excited state emits a photon of higher energy than an electron transition from the first excited state to the ground state.
Electrons can occupy discrete energy levels in an atom, which are known as orbitals or shells. The amount of energy that must be absorbed or emitted for an electron to move between two different energy levels is determined by the difference between the orbital energies.
When an electron transitions from a higher energy level to a lower energy level, a photon is emitted with energy equal to the difference between the two levels.
Thus, when an electron transitions from the third excited state to the second excited state, it emits a photon of higher energy than when an electron transitions from the first excited state to the ground state.
This is because the difference between the orbital energies of the third excited state and the second excited state is greater than the difference between the orbital energies of the first excited state and the ground state. The higher the energy difference between the two levels, the higher the energy of the photon that is emitted.
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3. Given the following equation: CH4(g) + 2 O2(g) > CO2(g) + 2 H2O(l) AH = -890.4 kJ a. How much energy is given off when 5.00 moles of CH4 are burned? And How much energy is released when 85.6 grams of CH4 are burned?
Answers
Answer:
-4452 kJ is given off from 5.00 moles of CH4.
-4763.64 kJ is given off from 85.6 grams of CH4.
Explanation:
First, let's write the equation:
\(CH_4+2O_2\rightarrow CO_2+2H_2O,\text{ }\Delta H=-890.4\text{ kJ.}\)a. We want to know how much energy is given off when 5.00 moles of CH4 are burned, so if we 'multiply' all the coefficients by 5.00 moles, the enthalpy change (ΔH) will also be multiplied by 5.00, so we're going to have:
\(\Delta H\cdot5=-890.4\text{ kJ}\cdot5=-4452\text{ kJ.}\)-4452 kJ is given off from 5.00 moles of CH4.
Now, to find how much energy is released when 85.6 g of CH4 are burned, we have to find the number of moles using the molar mass of CH4 which is 16 g/mol (you can calculate the molar mass of a compound using the periodic table). The conversion will look like this:
\(85.6\text{ g CH}_4\cdot\frac{1\text{ mol CH}_4}{16\text{ g CH}_4}=5.35\text{ moles CH}_4.\)We have 5.35 moles of CH4, so we have to follow the same steps that we did before:
\(\Delta H\cdot5.35=-890.4k\text{ kJ}\cdot5.35=-4763.64\text{ kJ.}\)-4763.64 kJ is given off from 85.6 grams of CH4.
if 243 mg of mg(oh) 2 was neutralized with 0.0500 m hcl, what volume of hcl would you need for the neutralization?
Answers
volume of HCl would you need for the neutralization is 4 ml .
What is neutralization reaction ?
In chemistry, neutralization or neutralization (see spelling difference) is a chemical reaction in which acids and bases react quantitatively with each other. When reacting in water, neutralization does not generate excess hydrogen or hydroxide ions in solution. The pH of the neutralized solution depends on the acidity of the reactants.
In the context of chemical reactions, the term neutralization is used for reactions between acids and bases or alkalis. Historically, this reaction was expressed as
Example:
HCl + NaOH → NaCl + H2O
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what is the conjugate base of HC6H6O6-
Answers
Answer:
the conjugate base of the compound is
C6h6O2/6-
Explanation:
subscript
The conjugate base of \(\rm HC_6H_6O_6^-\; is \; C_6H_6O_6^-\).
What are conjugate acids and bases?Conjugate acid is the acid that donates a hydrogen ion to a base, conjugate acid contains a hydrogen ion.
The base that gains a hydrogen ion from a conjugate acid is called the conjugate base.
The acid is NH4 converts into a conjugate base NH3-
When a conjugate acid donates a hydrogen ion, it converts into the conjugate base.
Thus, the conjugate base is \(\; C_6H_6O_6^-\)
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compound that increases the number of hydronium ions when dissolved in water is called?
Answers
Arrhenius acid
An Arrhenius acid is a compound that increases the concentration of H+ ions that are present when added to water. These H+ ions form the hydronium ion (H3O+) when they combine with water molecules.