Charcoal is found in a cave. It is determined that the amount of C-14 present is 1/50 the amount when the wood was burned. How long ago was it burned

Each organ system performs specific functions for the body, and each organ system is typically studied independently. However, the organ systems also work together to help the body maintain homeostasis. For example, the cardiovascular, urinary, and lymphatic systems all help the body control water balance.

Answer:

All objects can have the same size but have a different mass!

This is true, although it sounds fake. This is one example, there is a Neutron star, and Neutron stars are as big as a city, but they have a mass which is hundreds of times greater than our sun's mass. Because of them having so much mass, they are also having so much gravitational energy, which makes them also have gravity. They're so small, but have so much mass that they can do much. Even a drop of a neutron star can punch open the earth! It's true, so yes, it is possible for objects the SAME size to be having different masses according to that example.

But let's look on how they can have different mass.

They can have different masses becase of different densities. Put a iron ball inside water, and put an apple as close to the iron ball's side, what happens? The apple floats, becuase the apple's mass is less than the water, and the iron ball's mass is MORE than the water. So, because the iron ball is denser than the apple, that's why, it has more mass than the apple. The apple isn't much dense, it isn't as dense as water or the iron ball. But the iron ball is much more denser than the water. So because of the different material densities of the material, that's why it can have different masses.

Remember to Remember those 2 examples I gave you... (neutron star vs sun, iron ball vs apple on water)

Answer:

A physical property of a substance would be if its soft ,hard, shiny, (ect.)

Explanation:

"Electric charge is a characteristic of subatomic particles that causes them to feel a force when put in an electric and magnetic field." Positive and negative electric charges are usually transported by charge carriers protons and electrons.

When put in an electromagnetic field, the physical feature of matter known as electric charge causes matter to experience a force. A positive or negative electric charge can exist (commonly carried by protons and electrons respectively, by convention). Similar charges repel one another, whereas unlike charges attract one another.

Electric charge, which may be either positive or negative, exists in distinct natural units and cannot be generated or destroyed. Electric charges are classified into two types: positive and negative.

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Answer: D

Explanation:

apex

Given:

Crystal shield (CuSO4 . 5H2O) dissolves in water in the large tank.CuSO4′5H2O(s) → CuSO4 (aq) + 5H2O(l)0.01 mm = thickness of film layer24.3 g crystal/100 g water at 275 K, density 1140 kg/m3Diffusion of CuSO4 in dilute aqueous solution 3.6x10-10 m2/s at 275 K

Concentration can be taken at an average of 55.93 kmol/m3, water density 1000 kg/m3The mass of CuSO4 that dissolves per unit area per unit time is called flux.The transfer rate per unit area from the crystal surface to the bulk solution is given by;\(\frac{dn}{dt} = D.

A\frac{dc}{dx}\)Where, D is diffusion coefficient A is the area of the interfacec is the concentration of the diffusing species in the filmx is the direction of diffusion

From the given data, crystal density can be calculated as;\(\frac{24.3}{100+24.3}=0.1955\)

Now, we can calculate the mass transfer flux from the given data;\(\frac{55.93}{159.61}=\frac{C_{CuSO_4}}{1140}\)\(C_{CuSO_4}=39.76 kmol/m^3\)\(J = -D\frac{dc}{dx}\)

Since the inner film is saturated, \(c_0 = 39.76 kmol/m^3\)

At the outer surface, there is no CuSO4 present and the concentration gradient is;\(\frac{39.76-0}{0.01*10^{-3}}= 3.976*10^6 kmol/m^4\)\(J = -3.6*10^{-10}*3.976*10^6\)\(= -1.43456*10^{-3} kmol/m^2s\)

Thus, the mass transfer flux is -1.43456 * 10^-3 kmol/m^2s.

The transfer rate per unit area from the crystal surface to the bulk solution is -1.43456 * 10^-3 kmol/m^2s.

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Answer:

(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl

Explanation:

This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.

The strong acid and strong base has high rate constant of dissociation. The rate constant for weak acid and base for the dissociation is low, they do not easily dissociate in water. Therefore, HF is the strongest acid in the reaction.

Acid is a solution which releases H⁺ hydrogen ion when dissolved in water. Base releases hydroxide ion OH⁻ ion when dissolved in water.

pH is a measurement of amount of hydronium ion H₃O⁺ in a given sample. Strength of acidic nature is directly proportional to the concentration of hydronium ion.

On subtracting pH from 14, we get pOH which measures the concentration of hydroxide ion in a given solution. Temperature affect the pH. At room temperature pH scale is between 0 to 14. 7 is the pH of neutral solution.

HCN + F⁻ \(\rightarrow\) CN⁻ + HF

HF is the strongest acid in the reaction.

Therefore, HF is the strongest acid in the reaction.

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Answer: .5m

Explanation:

The statement "oxides of group 1a and 2a metals are basic (exception: beo is amphoteric)." is True.

Oxides of group 1a and 2a metals are generally basic, meaning they react with water to form solutions with a pH greater than 7. This is because these metal oxides have a tendency to donate electrons to water molecules, forming hydroxide ions (OH-) and cations of the metal. The resulting solution is basic due to the presence of hydroxide ions.

Beryllium oxide (BeO) is an exception because it is amphoteric, meaning it can react with both acids and bases. It can react with acids to form salts and with bases to form beryllate salts.

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The amount of work done is 450.0 atm L given that a system is compressed from 50.0 L to 5.0 L at a constant pressure of 10.0 atm.

To find the amount of work done when a system is compressed from 50.0 L to 5.0 L at a constant pressure of 10.0 atm, we can use the equation:

Work = Pressure x Change in Volume

The change in volume is calculated by subtracting the initial volume from the final volume:

Change in Volume = Final Volume - Initial Volume
Change in Volume = 5.0 L - 50.0 L
Change in Volume = -45.0 L

Since the change in volume is negative (indicating compression), we can use the absolute value of the change in volume in the calculation.

Plugging in the values into the equation, we have:

Work = 10.0 atm x |-45.0 L|
Work = 10.0 atm x 45.0 L
Work = 450.0 atm L

Therefore, the amount of work done is 450.0 atm L

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n H2 = m H2 / Mr H2

n H2 = 2 / 2

n H2 = 1 mol

n O2 = m O2 / Mr O2

n O2 = 4 / 32

n O2 = 0.125 mol

O2 is a limiting reactant

n H2O = (coef. H2O / coef. O2) • n O2

n H2O = (2 / 1) • 0.125

n H2O = 0.25 mol

m H2O = n H2O • Mr H2O

m H2O = 0.25 • 18

m H2O = 4.5 gr

The statements which  are true of water molecules as per forces of attraction are water molecules are polar.Water molecules undergo hydrogen bonding.Water molecules have a bent geometry.

Forces of attraction  is a force by which atoms in a molecule  combine. it is basically an attractive force in nature.  It can act between an ion  and an atom as well.It varies for different  states  of matter that is solids, liquids and gases.

The forces of attraction are maximum in solids as  the molecules present in solid are tightly held while it is minimum in gases  as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.

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Your question is incomplete, but most probably your full question was,Which of these statements would be true if the water molecule was linear instead of bent? Check all that apply. Water molecules are polar. Water molecules are nonpolar. Water molecules undergo hydrogen bonding. Water molecules have a linear geometry. Water molecules have a bent geometry.

Answer:6

Explanation:

Answer:10

Explanation:

bc yea :)

Answer:

256.66cm³is the capacity of the cone.

False. Table salt, or sodium chloride, forms from an ionic bond between sodium and chloride ions. This bond occurs as a result of the attraction between the positively charged sodium ion and the negatively charged chloride ion.

Hydrogen bonding, on the other hand, is a type of intermolecular bonding that occurs between molecules, not ions. It involves the attraction between a hydrogen atom bonded to a highly electronegative atom (such as oxygen or nitrogen) and a nearby electronegative atom in another molecule.

So, while hydrogen bonding may be involved in the formation of certain types of compounds, it is not involved in the formation of table salt.

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Yes, it is the right response. Although the elements are imaginary, they resemble actual elements .Nomenclature is an organism name system used in biological classification.

The Latin words nomen (name) and calare (to call) are the source of the word nomenclature. Both the Latin word nomenclatura and the English word nomenclator, which also denotes a source or broadcaster of names, relate to a list of names.

Nomenclature is an organism name system used in biological classification. Genus & species names, two Latinized nouns drawn from numerous sources, serve as indicators of the species whereby the creature belongs.

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Answer:

The average osmotic pressure of blood is about 7 atm. Therefore the average blood pressure is about 7 atm. All of the statements listed are true the average pressure inside the body is about 7 atm above the external pressure. a pressure of about 7 atm would be required to prevent osmosis if blood is in contact with pure water across a semipermeable membrane.

Explanation:

please mark me as a brainlist...

Using the given mass of the compound (0.520 g) and the calculated moles, we can determine the molar mass of the compound.

To find the molar mass of the compound, we can use the formula:

ΔT = Kf * m

where ΔT is the freezing point depression, Kf is the cryoscopic constant (in this case, 3.90 °C/m), and m is the molality of the solution.

First, we need to calculate the molality (m) of the solution:

m = moles of solute / mass of solvent (in kg)

The mass of the solvent (lauric acid) is given as 4.62 g. Since the unknown compound is a solute, we need to convert its mass to moles:

moles = mass / molar mass

Given that the mass of the unknown compound is 0.520 g, we can now calculate the moles of the compound.

Next, we convert the mass of the solvent to kg by dividing by 1000:

mass of solvent (lauric acid) = 4.62 g / 1000 = 0.00462 kg

Now we can calculate the molality:

m = moles of solute / mass of solvent = (moles of the compound) / (mass of solvent)

Finally, we can use the freezing point depression formula to find the molar mass of the compound:

ΔT = Kf * m

Substituting the given values:

4.20 °C = 3.90 °C/m * m

Now solve for m:

m = (4.20 °C) / (3.90 °C/m)

Once we have the molality, we can calculate the moles of the compound:

moles = molality * mass of solvent (in kg)

Finally, we calculate the molar mass:

molar mass = mass of solute / moles of solute

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The molar mass of the gas : 18 x 10⁻³ kg/mol

Given

An unknown gas has one third the root mean square speed of H2 at 300 K

Required

the molar mass of the gas

Solution

Average velocities of gases can be expressed as root-mean-square (V rms)  

\(\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}\)

T = temperature, Mm = molar mass of the gas particles  , kg/mol

R = gas constant 8,314 J / mol K  

v rms An unknown gas = 1/3 v rms H₂

v rms H₂ :

\(\tt v_{rms}=\sqrt{\dfrac{3\times 8.314\times 300}{2.10^{-3}} }\\\\v_{rms}=1934.22\)

V rms of unknown gas =

\(\tt \dfrac{1}{3}\times 1934.22=644.74\)

\(\tt 644.74^2=\dfrac{3\times 8.314\times 300}{M_{gas}}\\\\M_{gas}=18\times 10^{-3}~kg/mol\)

The pH of the solution is 3.63.

The Henderson-Hasselbalch equation is pH = pKa + log ([A-]/[HA]), where [A-] is the concentration of the conjugate base (sodium formate, HCOONa) and [HA] is the concentration of the weak acid (formic acid, HCOOH). First, we need to find the pKa of formic acid, which is 3.75.

Now, we can plug in the given concentrations into the equation:
pH = 3.75 + log ([0.270]/[0.130])
pH = 3.75 + log (2.0769)
pH = 3.75 + 0.3174
pH = 3.63

Summary: Using the Henderson-Hasselbalch equation, we calculated the pH of a solution containing 0.270 M sodium formate and 0.130 M formic acid to be 3.63.

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The cosine function of a chemical reaction that occurs at temperatures between 40 and 180 degrees Celsius is \(f (t) = -70\cos \left(\frac{\pi}{6}\right)t+110\).  Option c is the correct expression.

A cosine function's amplitude is equal to half the vertical distance between its highest and lowest points. The distance between the tallest point and the center line is equal to this.  This is of the form f (t) = A cos (bt)+k where A is the wave amplitude, t is the time period, and k is the vertical displacement.

In this problem, the temperature is measured by f(t), which ranges from 40 to 180 degrees Celsius. Then the temperature is not negative. The amplitude will be,

\(A=\frac{|180-40|}{2}=70\)

Given the time period is 12 hours.

\(\begin{aligned}\text{Period}&= \frac{2\pi}{b}\\12&= \frac{2\pi}{b}\\b&= \frac{2\pi}{12}\\b&=\frac{\pi}{6}\end{aligned}\)

When, t = 0, the wave must be at its lowest point. Then, f(t)=40. Find k using this.

\(\begin{aligned}f(t=0)&=40\\40&=-70\cos\left(\frac{\pi}{6}\times 0\right)+k\\40&=-70+k\\k&=110\end{aligned}\)

The required cosine function will be of the form, \(f (t) = -70\cos \left(\frac{\pi}{6}\right)t+110\)

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Answer:

75 g

Explanation:

1 half life = 600/2 = 300g

2 half life = 300/2 = 150g

3 half life = 150/2 = 75g

The amount of 600 gram remaining after 3 half-lives is 75 g.

The half life of a substance is given by:

\(N=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} } \\\\where\ N\ is\ substance\ remaining\ after\ t\ years,N_o\ is\ the \ original\ sample\\t_\frac{1}{2}\ is\ the\ half\ life\\\\\\Given\ that:\\N_o=600\ g, t=3t_\frac{1}{2} , hence:\\\\N=600(\frac{1}{2} )^\frac{3t_\frac{1}{2} }{t_\frac{1}{2} } \\\\N=600(\frac{1}{2} )^3=75\ g\)

The amount of 600 gram remaining after 3 half-lives is 75 g.

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The concentration of A decreases and then levels out. Option A

In many chemical reactions, a reactant is consumed as the reaction progresses, leading to a decrease in its concentration over time. The reactant molecules are transformed into products, and as the reaction proceeds, the concentration of the reactant gradually diminishes.

At equilibrium, the concentrations of both reactants and products remain relatively constant over time, although they can coexist.

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The difference between an independent variable and a dependent variable is an independent variable is the variable that is manipulated by the experimenter, and a dependent variable is the variable that is measured to see if it is affected by the independent variable.

In statistics, an independent variable is a variable that is manipulated or controlled by the researcher to observe its effect on a dependent variable.

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The independent variable in an experiment is the factor that researchers deliberately change to test its effects, while the dependent variable is the factor that they measure to see if it changes in response to the manipulation of the independent variable.

The difference between an independent variable and a dependent variable is that an independent variable is a factor in an experiment that the researcher manipulatively changes to see if it has any effect, while a dependent variable is the factor the researcher measures to see if it changes as a result of the manipulation of the independent variable.

For example, if you were running an experiment to see if different amounts of sunlight affected the rate at which a plant grows, the independent variable would be the amount of sunlight the plant receives (because you, the researcher, are changing it), and the dependent variable would be the growth rate of the plant (because you are measuring this to see if it changes in response to the changing amount of sunlight).

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The heat that is absorbed in each case or the mass obtained are;

1)  305 g

2) -27.4 J

3) 523°C

4) 465 g

5)  -58.9 J

Let us now go on to look at the question that have been asked and the things that we need to find in each case. If we look at the question we can see that;

q = heat

dT = temperature change

m = mass

1) q = 119150 J

ΔT = 1409.71

c = 0.2772

q = mcdT

m = q/cdT

m = 119150 J/1409.71 *  0.2772

m = 305 g

2) q = 83.5 * 2.05 * (-0.16)

q = -27.4 J

3) dT = q/mc

= 57984 J/535.2 * 0.207

= 523°C

4) m = q/dT * c

m = 1914.9 J/(-17.27) * 0.2386

m = 465 g

5) q = 30.3 * 0.2772 * (-7.01)

q = -58.9 J

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If we were sent back in time before the invention of the scanning tunneling microscope, it would be challenging to directly observe the existence of atoms and molecules, but there are other lines of evidence that we could use to support the theory that all matter is made of atoms and molecules.

One approach would be to study the behavior of matter under different conditions and compare the results to the predictions of atomic theory. For example, the kinetic theory of gases, which was developed in the 19th century, describes the behavior of gases in terms of the motion of individual molecules.

The theory predicts that the pressure, volume, and temperature of a gas are related, and this relationship has been confirmed through numerous experiments. This provides strong evidence for the existence of atoms and molecules, even though they cannot be directly observed.

Another line of evidence comes from chemical reactions. Chemical reactions involve the rearrangement of atoms and molecules, and the stoichiometry of chemical reactions can be explained in terms of the relative numbers of atoms and molecules involved.

The law of conservation of mass, which was discovered by Antoine Lavoisier in the late 18th century, states that the total mass of the reactants in a chemical reaction is equal to the total mass of the products. This observation is consistent with the idea that matter is made of discrete, indivisible particles.

Furthermore, the field of crystallography, which studies the arrangement of atoms in crystals, was developed before the invention of the scanning tunneling microscope.

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