Cells are the building blocks of life on Earth true or false pls quick

Answer:

the first thing you do is do your experiment then title it. then state the purpose of the experiment. included a summary of the experiment. make a list of the materials you used. present all the steps in order to make the experiment possible. note any changes to the original procedure. this is basically the steps you have to do in order to make your scientific experiment.

Answer:

The substance will be in liquid state at a temperature of 97.3 °C

Note: The question is incomplete. The complete question is given below :

Suppose a substance has a heat of fusion equal to 45 cal/g and a specific heat of 0.75 cal/g°C in the liquid state. If 5.0 kcal of heat are applied to a 50 g sample of the substance at a temperature of 24°C, what will its new temperate be? What state will the sample be in? (melting point of the substance = 27°C; specific heat of the solid =0.48 cal/g°C; boiling point of the substance = 700°C)

Explanation:

1.a) Heat energy required to raise the temperature of the substance to its melting point, H = mcΔT

Mass of solid sample = 50 g; specific heat of solid = 0.75 cal/g; ΔT = 27 - 24 = 3 °C

H = 50 × 0.75 × 3 = 112.5 calories

b) Heat energy required to convert the solid to liquid at its melting point at 27°C, H = m×l, where l = 45 cal/g

H = 50 × 45 = 2250 cal

c) Total energy used so far = 112.5 cal + 2250 cal = 2362.5 calories.

Amount of energy left = 5000 - 2362.5 = 2637.5 cal

The remaining energy is used to heat the liquid

H = mcΔT

Where specific heat of the liquid, c = 0.75 cal/g/°C, H = 2637.5 cal, ΔT = temperature change

2637.5 = 50 × 0.75 x ΔT

ΔT = 2637.5 / ( 50*0.75)

ΔT = 70.3 °C

Final temperature of sample = (70.3 + 27) °C = 97.3 °C

The substance will be in liquid state at a temperature of 97.3 °C

Answer:

There's 34,000,000,000 nanograms in 34g.

Explanation:

U can write it like 3.4e+10.

Hope I helped ya.

< Sarah >

To calculate the pH during the titration of 20.00 mL of 0.1000 M CH₃CH₂COOH with 0.1000 M CSOH after 11.09 mL of the base have been added. The pH  value is = -log₁₀[H₃O⁺]

The balanced equation for the reaction between propanoic acid (CH₃CH₂COOH) and sodium hydroxide (NaOH) is as follows:

CH₃CH₂COOH + NaOH → CH₃CH₂COONa + H₂O

(CH₃CH₂COOH) = 20.00 mL

(CH₃CH₂COOH) = 0.1000 M

(CSOH) = 11.09 mL

(CSOH) = 0.1000 M

Initial moles of propanoic acid = (20.00 mL × 0.001 L/mL) × 0.1000 M

moles of sodium hydroxide = (11.09 mL × 0.001 L/mL) × 0.1000 M

moles of propanoic acid reacted = moles of sodium hydroxide added

remaining moles of propanoic acid = initial moles of propanoic acid - moles of propanoic acid reacted

Next, we can calculate the volume of the solution after the addition of sodium hydroxide:

we need the Ka (acid dissociation constant) of propanoic acid to proceed with the calculation.

Now we can rearrange the equation to solve for [H₃O⁺]:

Ka = [H₃O⁺]/0.00200 mol[H₃O+] = Ka * 0.00200 mol / 0.0445 mol/L

[H₃O⁺] = Ka * 0.0449 mol/L

Finally, we can calculate the pH:

pH = -log₁₀[H₃O⁺]

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The reaction is an addition reaction.

Addition reactions are chemical reactions involving 2 or more reactants reacting to produce a single product.

Addition reactions are different from decomposition reactions. In the latter, a single reactant decomposes to give two or more products.

In the illustrated reaction, Cl₂O5 and H₂O react together to form a single product, HCIO3.

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Free radicals are highly reactive molecules or atoms that have unpaired electrons in their outer shells.
Negative health consequences of a high amount of free radicals in the system include, Oxidative Stress, Inflammation, Cellular Damage.
Antioxidants are substances that can neutralize or counteract the damaging effects of free radicals.


Free radicals are highly reactive molecules or atoms that have unpaired electrons in their outer shells. They are formed as natural byproducts of various biological processes in the body, such as metabolism, immune response, and environmental factors like pollution, radiation, or smoking. Free radicals are unstable and seek to stabilize themselves by oxidizing other molecules in the body, leading to a chain reaction of damage to cells, proteins, and DNA.

Negative health consequences of a high amount of free radicals in the system include:

Oxidative Stress: Excessive free radicals can cause oxidative stress, which is an imbalance between the production of free radicals and the body's antioxidant defenses. This can result in damage to cellular components and contribute to the development of chronic diseases, including cancer, cardiovascular diseases, neurodegenerative disorders, and aging.

Inflammation: Free radicals can trigger and perpetuate inflammation in the body. Chronic inflammation is associated with various health conditions, including arthritis, asthma, diabetes, and autoimmune disorders.

Cellular Damage: Free radicals can damage cell membranes, proteins, and DNA, leading to mutations, cell dysfunction, and impaired cellular processes. This can disrupt normal cell function and contribute to the development of diseases.

Antioxidants are substances that can neutralize or counteract the damaging effects of free radicals. They help inhibit or reduce the oxidation of other molecules by donating an electron to stabilize the free radicals without becoming free radicals themselves. Antioxidants can be naturally occurring compounds found in fruits, vegetables, whole grains, nuts, and seeds, as well as synthetic substances. Some common antioxidants include vitamins C and E, beta-carotene, selenium, and various phytochemicals. Consuming a diet rich in antioxidants or supplementing with antioxidants can help protect against oxidative stress and mitigate the negative health consequences associated with high levels of free radicals.


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Answer:

answer is B

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Answer:

a) longitudnal waves

b)parallel to vibration

c) transverse waves .it is used in a ripple tank

Her  estimated BAC would be approximately 0.08%.

Calculating blood alcohol content (BAC) is a complex process that depends on many factors, including weight, gender, the amount and type of alcohol consumed, and the time over which it was consumed.

Assuming each vodka tonic contains approximately 1.5 fluid ounces of 40% alcohol, and the woman consumed all three over the course of an hour, her estimated BAC would be approximately 0.08%. This is just at the legal limit for driving in most states in the US. However, it's important to note that BAC can vary widely based on individual factors, and this estimate is not a guarantee of a specific BAC level.

It's also important to remember that driving under the influence of alcohol is dangerous and illegal, and it's always best to err on the side of caution and avoid driving if you've consumed any amount of alcohol.

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The factors that can affect the equilibrium constant for a given experiment are A (changing the concentration of the reactants), B (changing the temperature), and D (changing the volume of the system).

For a gas phase chemical reaction, the equilibrium constant is determined by the ratio of the concentrations (or partial pressures) of the products to the concentrations (or partial pressures) of the reactants at equilibrium. Based on this understanding, the factors that can affect the equilibrium constant for a given experiment are:

A. Changing the concentration of the reactants: Altering the concentration of the reactants will affect the equilibrium constant since it is dependent on the ratio of concentrations. Increasing the concentration of reactants will shift the equilibrium towards the product side (to restore the equilibrium), and vice versa.

B. Changing the temperature: Temperature has a significant impact on the equilibrium constant. Changing the temperature will shift the equilibrium in a direction that either favors the forward reaction (increasing temperature for an endothermic reaction) or the reverse reaction (decreasing temperature for an exothermic reaction).

C. Adding a catalyst to increase the rate of the reaction: A catalyst affects the rate of a reaction but does not alter the position of the equilibrium or the equilibrium constant. Therefore, adding a catalyst will not directly affect the equilibrium constant for the given experiment.

D. Changing the volume of the system: Altering the volume of the system affects the equilibrium constant if the reaction involves a different number of moles of gas on the reactant and product sides. According to Le Chatelier's principle, increasing the volume will shift the equilibrium in the direction that minimizes the total number of moles of gas, and vice versa.

E. Adding an inert gas to the system: Adding an inert gas, which does not participate in the chemical reaction, will not affect the equilibrium constant. It only increases the total pressure without affecting the partial pressures of the reactants and products.

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Answer:

It’s just North Atlantic Ocean, Atlantic Ocean, Pacific Ocean and the North Pacific Ocean. NOT THE PACIFIC OCEAN ON THE RIGHT SIDE NOR THE INDIAN OCEAN.

The initial temperature (c) of a system that has pressure decreased by 10 times while the volume increased by 5 times with a final temperature of 150k is 300K .

Temperature is a measure of the average kinetic energy of particles in a system. It is used to characterize the degree of hotness or coldness of a material or object. Temperature is expressed in units of degrees Celsius (°C), Kelvin (K), and Fahrenheit (°F). Temperature is an important physical quantity that plays a major role in determining the physical properties of a system. It can affect the pressure, volume, density, and viscosity of a substance.

The initial temperature (T1) of the system can be calculated using the ideal gas law, which states that PV = nRT, where P is pressure, V is volume, n is the number of moles, and R is the ideal gas constant.

To calculate T1, we rearrange the equation to T = (PV/nR).

Since the pressure decreased by 10 times and the volume increased by 5 times, we can calculate the new P and V values. P2 = P1/10 and V2 = V1*5.

We can then plug these values into the equation and solve for T1.

T1 = (P1V1/nR) * (10/5)

T1 = 150K * (10/5)

T1 = 300K

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с. сarbon is most likely the chemical formula for graphite.

The chemical formulation of graphite is C, Molecular weight: 12.01. Nanotubes, diamond and graphite are allotropes of carbon, and the chemical formulation may be expressed by "C".

Graphite is manufactured from pure carbon. Carbon atoms are able to form bonds that create a number of one-of-a-kind structures. Diamond and graphite are of the maximum bureaucracy (allotropes) of carbon.

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Answer:

b

Explanation:

The required number of moles of C that must fully react to produce 2. 0 moles of \(C_{2} xH_{6}\) is  2.

The balanced equation for the reaction of carbon (C) and hydrogen (H2) to produce ethane (C2H6) is:

C + 2H2 -> C2H6

From the balanced equation, we can see that for every 1 mole of carbon that reacts, 2 moles of hydrogen are also required. Therefore, in order to produce 2 moles of C2H6, we need 2 moles of hydrogen.

Since the balanced equation states that for every 1 mole of C we need 2 moles of H2, we can say that we need 2*2 =4 moles of hydrogen.

So the number of moles of C that must completely react to produce 2.0 moles of C2H6 is 2 moles.

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Considering the definition of atomic mass, isotopes and atomic mass of an element, sb121 has a percent natural abundance of 0.5726 or 57.26% and sb123 has a percent natural abundance of 0.4284 or 42.84%.

The atomic mass is obtained by adding the number of protons and neutrons in a given nucleus of a chemical element.

Isotopes are the chemical elements in which atomic numbers are the same, but the number of neutrons is different.

The atomic mass of an element is the weighted average mass of its natural isotopes.

This is, the atomic masses of elements are usually calculated as the weighted average of the masses of the different isotopes of each element, considering the relative abundance of each of them.

In this case, antimony has two naturally occuring isotopes, sb121 and sb123. You know:

The average mass of antimony is expressed as:

121.7601 u= 120.9038 u x + 122.9042 u× (1 -x)

Solving:

121.7601 u= 120.9038 u x + 122.9042 u - 122.9042 u x

121.7601 u - 122.9042 u= 120.9038 u x - 122.9042 u x

(-1.1441 u)= (-2.0014) x

(-1.1441 u)÷ (-2.0014)= x

0.5726= x or 57.26%

So, 1 -x= 1- 0.5716 → 1-x= 0.4284 or 42.84%

Finally, sb121 has a percent natural abundance of 0.5726 or 57.26% and sb123 has a percent natural abundance of 0.4284 or 42.84%.

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Action potentials, a type of electrical event, and chemicals neurotransmitters are two ways that neurons can communicate with one another  well at intersection of two neurons (synapse),

The typical 1.5-volt cell, which powers various electrical devices like TV remote controls and clocks, is an instance of an electrolytic cell. Electrolytic cells or single pv cells are those that can produce an electric charge as a result of chemical reactions going to take place inside of them.

Electrochemistry, as its title suggests, is the investigation of modifications that cause the movement of electrons. Electricity is the term given to this flow of electrons. Electric Chemistry

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Answer:

the answer should be A

Answer:

The activation energy of a reaction can be related to the reaction rate constant using the Arrhenius equation:

k = Ae^(-Ea/RT)

Where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant, and T is the temperature in Kelvin.

By rearranging the equation, we can find the temperature needed to double the rate constant:

T = (-Ea/R) * (ln(2k/A))^-1

We know k at 30°C, k = 0.0190 s^-1 and Ea = 48.8 kJ/mol, so we can substitute these values:

T = (-48.8 kJ/mol / 8.31 J/mol*K) * (ln(2 * 0.0190 s^-1 / A))^-1

Since we don't know the value of A, we cannot find an exact temperature. However, we can use the approximation that the pre-exponential factor is constant over a small range of temperatures and calculate a rough estimate.

Based on this, we can conclude that the reaction would go twice as fast at a higher temperature than 30°C.

The temperature at which the reaction would go twice as fast is approximately 47°C.

The rate constant of a reaction is given by the Arrhenius equation:

k = Ae^(-Ea/RT)

where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant, and T is the absolute temperature in Kelvin.

We are given the activation energy of the reaction as 48.8 kJ/mol and the rate constant at 30°C (which is 303 K) as 0.0190 s^-1. Using this information, we can calculate the pre-exponential factor A:

A = k e^(Ea/RT)

= 0.0190 s^-1 e^(48.8 kJ/mol / (8.314 J/mol*K * 303 K))

= 1.74 x 10^12 s^-1

Now, we want to find the temperature at which the reaction would go twice as fast. Let's call this temperature T'. We can use the Arrhenius equation again with this new temperature and twice the rate constant (i.e., 2k):

2k = A e^(-Ea/RT')

=> ln(2k) = ln(A) - Ea/RT'

=> ln(2k) - ln(A) = -Ea/RT'

=> T' = -Ea / (R * (ln(2k) - ln(A)))

Plugging in the values we have calculated, we get:

T' = -48.8 kJ/mol / (8.314 J/mol*K * (ln(2 * 0.0190 s^-1) - ln(1.74 x 10^12 s^-1)))

= 320 K

Converting this to Celsius, we get:

T' = 320 K - 273.15

= 46.85°C

Therefore, the temperature at which the reaction would go twice as fast is approximately 47°C.

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The higher animals in the food chain would probably not survive.

The specific heat capacity of a substance is the amount of heat needed to elevate it by 1 degree kelvin per gram. The easier it is for something to heat up, then, the smaller the heat capacity. We would suppose that a cook in a hurry would want a pan that heats up more quickly and would choose one with a lesser heat capacity.

0.385 for copper and 0.900 for aluminum.

Despite using non-SI units, we can still compare using it. It is obvious to him that copper has a lower specific heat, so he will pick that.

In case you're curious, you can also approach this issue from the perspective of heat conduction. To do this, look up the thermal conductivities of each material, and then apply Fourier's rule of heat conduction to determine that Copper would be best.

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Answer:

C, A, A, B, B

Explanation:

Question 5: C. continental drift

Question 6: A. new rock forms

Question 7: A. happens at deep-ocean trenches

Question 8: B. convection currents in the mantle

Question 9: B. convergent boundary

Based  on the given equation, 4.96 grams of nitrogen gas, N2, will be produced from the decomposition of 23.0 grams of sodium azide, NaN3.

The number of grams of nitrogen gas, N2, that will be produced from the decomposition of 23.0 grams of sodium azide, NaN3, we need to use stoichiometry.
From the balanced equation, we can see that 2 moles of NaN3 will produce 1 mole of N2. To calculate the number of moles of NaN3 in 23.0 grams, we need to divide the mass by the molar mass:
23.0 g NaN3 / 65.01 g/mol NaN3 = 0.353 mol NaN3

Now that we know the number of moles of NaN3, we can use the stoichiometric ratio to calculate the number of moles of N2: 0.353 mol NaN3 × (1 mol N2 / 2 mol NaN3) = 0.177 mol N2
Finally, we can calculate the mass of N2 produced by multiplying the number of moles by the molar mass:
0.177 mol N2 × 28.02 g/mol N2 = 4.96 g N2

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Answer:

5.02 mol

Explanation:

number of mole =given mass/molar mass

Answer: 63.55

Explanation:

The attached chart shows the calculation.  The orange line points to the % abundance of Cu-65, which is the difference of 100% less the % Abundance of Cu-65 (since there are only 2 isotopes).

The weighted average contribution of each istope is calculated (blue arrow) and then summed to find the atomic mass of copper.

Answer:

The molar mass of \(NI_{3}\) is 394.719 g/mol.

Explanation:

This was on my periodic table.