Carlos should expect tomorrow’s score to be about how many points greater than today’s score?

Answer:

x=27

Step-by-step explanation:

a(a+b)=c(c+d)

10(42+10)=13(x+13)

520=13x+169

x=27

Answer:

8

Step-by-step explanation:

1+1+1+1+1+1+1+1=8

take 4 ones and group them into 2 groups gives you 8

Answer:

lets count the hundreths 20 + 28 = 48 tenths which would be .48 as a decimal then it would be 48/100, then 480% I think please wait for more responses if needed.

Stockton lake lost the least amount of water.

What is Denominator?

In mathematics, the denominator is the bottom number in a fraction that indicates the number of equal parts into which a whole is divided.

To compare the amount of water lost by each lake, we need to express the amounts lost in the same units. One way to do this is to find a common denominator for the fractions and percentages involved.

Lake Jensen lost 5/6 of its water, which can be expressed as a fraction with a common denominator of 300:

5/6 = 250/300

Lake Parlow lost 85% of its water, which can be expressed as a fraction with a denominator of 100:

85% = 85/100 = 255/300

Lake Stockton lost 246/300 of its water, which is already in terms of a common denominator of 300.

Now we can compare the amounts lost directly:

Lake Jensen lost 250/300 of its water

Lake Parlow lost 255/300 of its water

Lake Stockton lost 246/300 of its water

To determine which lake lost the least amount of water, we need to find the smallest fraction among these three.

We can see that Lake Stockton lost the least amount of water, since 246/300 is smaller than both 250/300 and 255/300. Therefore, Lake Stockton lost the least amount of water.

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Answer:

Step-by-step explanation:

a. supplementary

b. adds up to 180 degrees

c. 63 + 6x + 2x + 30 = 180

   3(21 + 2x) + 2x + 30 = 180

   8x + 93 =180

 8x = 87

  x = 10 7/8

The gradient vector field of function f(x,y) is given as follows:

grad(f(x,y)) = (1 + 9xy)e^(9xy) i + 9x²e^(9xy) j.

The gradient vector field of a function

Suppose that  a function defined as follows:

f(x,y).

The gradient function is defined considering the partial derivatives of function f(x,y), as follows:

grad(f(x,y)) = fx(x,y) i + fy(x,y) j.

The gradient of a function is a vector field. It is obtained by applying the vector operator V to the scalar function f(x, y). Such a vector field is called a gradient (or conservative) vector field.

In which:

fx(x,y) is the partial derivative of f relative to variable x.

fy(x,y) is the partial derivative of f relative to variable y.

The function in this problem is defined as follows:

f(x,y) = xe^(9xy).

The partial derivative relative to x  as follows:

fx(x,y) = e^(9xy) + 9xye^(9xy) = (1 + 9xy)e^(9xy).

The partial derivative relative to y  as follows:

fy(x,y) = 9x²e^(9xy).

Hence the gradient vector field of the function is defined as follows:

grad(f(x,y)) = (1 + 9xy)e^(9xy) i + 9x²e^(9xy) j.

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It takes twice the time to travel a given distance while going uphill

compared to traveling downhill.

Response:

Given parameters are;

The distance to the top = 6 km

The length of the descent = 4 km

Duration of the whole journey, t = 8 hours

Speed the army travelled downhill = 2 × The speed while traveling uphill

Required:

How long it takes Napoleon to reach the top.

Solution:

Let v represent the speed while traveling uphill, we have;

The time it takes to travel uphill, t₁ = \(\dfrac{6 \, km}{v}\)

The time it takes to travel downhill, t₂ = \(\mathbf{\dfrac{4 \, km}{2 \cdot v}}\)

Duration of the journey, t = 8 = The total time = t₁ + t₂

Which gives;

\(8 = \mathbf{\dfrac{6}{v} + \dfrac{4}{2 \cdot v}}\)

\(\dfrac{2 \times 6 + 4}{2 \cdot v} = 8\)

8 × 2·v = 12 + 4

16·v = 16

\(v = \dfrac{16}{16} = 1\)

v = 1 km/hr

The time it takes to travel uphill, t₁ = \(\dfrac{6 \, km}{1 \, km/hr}\) = 6 hours

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The greatest common factor of \(20x^{6} y+40x^{4} y^{2} -10x^{5} y^{5}\) is \(10x^{4} y\) .

The greatest common factor of a set of numbers is defined as the largest number that divides all the numbers in that given set and leaves 0 as remainder in each case.

In the given expression

\(20x^{6} y+40x^{4} y^{2} -10x^{5} y^{5}\)

Applying Prime Factorization and Writing all the terms in the above expression as

\(20x^{6} y=10x^{4}y *2x^{2}\)

\(40x^{4} y^{2} =10x^{4} y*4y\)

\(10x^{5} y^{5} =10x^{4}y*xy^{4}\)

As we can see that \(10x^{4} y\) is common and greatest in all the terms .

Hence \(10x^{4} y\) is the Greatest common factor.

Therefore , the greatest common factor of \(20x^{6} y+40x^{4} y^{2} -10x^{5} y^{5}\) is \(10x^{4} y\) , the correct option is (a)\(10x^{4} y\).

The given question is incomplete , the complete question is

What is the greatest common factor of \(20x^{6} y+40x^{4} y^{2} -10x^{5} y^{5}\)

(a)\(10x^{4} y\)

(b)\(5x^{2} y^{5}\)

(c)\(5x^{4} y\)

(d)\(20x^{6} y\)

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The probability of household views between 5 and 11 hours will be 0.7653. Number of hours needed in order to be in top 3% will be 13.03 hours. Probability of views more than 3 hours will be 0.9838.

a) The probability of television views between than 5 and 11 hours.

 P( 5≤X≤11) = P[ (5-μ)/σ ≤ (X-μ)/σ ≤ (11-μ)/σ]

                   = P [ (5-8.35)/2.5 ≤ z ≤ (11-8.35)/2.5)

                    = P ( -1.34 ≤ z ≤ 1.06)

                    = P ( z≤ 1.06) - P(z ≤ -1.34)

Substituting values from the z-table

   P ( 5≤X≤11) = 0.85543 - 0.09012 = 0.76531

Probability that household views between 5 and 11 hours is  0.7653.

b) Hours needed to be in top 3% of all households.

 P( X> h) = 0.03

 P[ (X-μ)/σ > (h-μ)/σ] = 0.03

P ( z >h-8.35/2.5) = 0.03

P ( z ≤ h-8.35/2.5) = 0.97

From the table

  (h - 8.35)/ 2.5 = 1.87

   h = (1.87× 2.5) + 8.35

      = 13.025 = 13.03 hours

So if the viewing time is more than 13.03, the household will be in the top 3%.

c) Probability of viewing more than 3 hours

 P(X> 3) = P[ (X-μ)/σ > (3-μ)/σ]

               = P( z < -2.14) = 0.9838

So probability the household will have views more than 3 hours will be 0.9838.

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By using Chebyshev's inequality, n = (o² * δ) / e² samples are sufficient to guarantee that P(|Sn - u| > e) < δ for the sample mean estimator.

In order to solve this question we need to consider Optimal Mean Estimation via Concentration Inequalities and use sample mean and median of means estimator.

To find the sample size n that guarantees P(|û - u| > e) < δ using Chebyshev's inequality, follow these steps:

1. Define Sn as the sample mean estimator:

Sn = (1/n) * Σ(Xi) for i = 1 to n.

2. We know the variance o² is known, and Chebyshev's inequality states that P(|X - E(X)| > k * σ) ≤ 1/k², where X is a random variable, E(X) is the expected value of X, σ is the standard deviation, and k is a constant.

3. Apply Chebyshev's inequality to Sn - u:

P(|Sn - u| > k * (o / sqrt(n))) ≤ 1/k², where k = e * sqrt(n) / o.

4. We want P(|Sn - u| > e) < δ, so we can rewrite Chebyshev's inequality as 1/k² < δ. Substitute k with e * sqrt(n) / o: 1/((e * sqrt(n) / o)²) < δ.
5. Solve for n: n = (o² * δ) / e².

By using Chebyshev's inequality, n = (o² * δ) / e² samples are sufficient to guarantee that P(|Sn - u| > e) < δ for the sample mean estimator.

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The constant of proportionality of the table is 4.

Proportional relationships are relationships between two variables where their ratios are equivalent. In other words, a proportional relationship is one in which two quantities vary directly with each other.

Therefore, a proportional relationship can be represented as follows:

y = kx

where,

Therefore, using (1, 4)

y = kx

4 = k × 1

Therefore,

k = 4

Hence,

constant of proportionality = 4

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Answer:

so as you see im in middle school but i can solvee it

Step-by-step explanation:

even im in 6th grade i do well with high school stuff ok now let me xplain you just read it carifully eamil your teacher ask for help and doneee your brain is working bam bam bam

Answer:

9 minutes

Step-by-step explanation:

The amount of time t that it takes to put out a fire varies inversely with the volume of water used, G

t = k/G

Where,

k = constant

When G is 3, t is 15

t = k/G

15 = k/3

Cross product

15 * 3 = k

k = 45

Find t when G = 5

t = k/G

t = 45/5

t = 9 minutes

Answer:

If s₃ is the length of the 3rd side, the possible values are in the interval.

5 < s₃ < 19

Step-by-step explanation:

For a triangle, we know that the sum of any two sides is always larger than the other side.

So if a triangle has 3 sides:

s₁, s₂, and s₃, we have:

s₁ + s₂ > s₃

s₁ + s₃ > s₂

s₂ + s₃ > s₁

In this case, we know that two sides are:

s₁ = 7

s₂ = 12

And we want to find the possible values of s₃.

Then if we use the above inequalities, we get:

7 + 12 > s₃

7 + s₃ > 12

12 + s₃ > 7

With the first one we get:

19 > s₃

Now we can rewrite the other two as:

s₃ > 12 - 7 = 5

s₃ > 7 - 12 = -5

The first one is more restrictive than the second:

s₃ > 5 > -5

So we can use only the first one.

Then the two inequalities are

s₃ > 5

s₃ < 19

Then the range is:

5 < s₃ < 19

This means that any value between 5 and 19 can be a possible length of the third side (5 and 19 are not possible lengths)

Yes, the figure shown in the xy-coordinate plane is a parallelogram because side OP is parallel to side TS and side OT is parallel to side PS

In order for any quadrilateral to be considered a parallelogram, two pairs of its parallel sides must be equal (congruent). Therefore, we would determine the slope of each side by using this mathematical equation:

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

For side OP, the slope is given by:

Slope (m) = (b - 0)/(a - 0)

Slope (m) = b/a.

For side TS, the slope is given by:

Slope (m) = (0 - )/(c - (a + c))

Slope (m) = -b/-a = b/a

Therefore, side OP is parallel to side TS.

For side OT, the slope is given by:

Slope (m) = (0 - 0)/(c - 0)

Slope (m) = 0.

For side PS, the slope is given by:

Slope (m) = (b - b)/((a + c) - c)

Slope (m) = 0

In conclusion, the figure shown above is a parallelogram because side OT is parallel to side PS and side OP is parallel to side TS.

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the variance of Y, Var(Y), is 2.

To find the probability density function (PDF) of the random variable Y = |2Z|, where Z follows a standard normal distribution, we need to determine the distribution of Y.

1. Probability Density Function (PDF) of Y:

First, let's express Y in terms of Z:

Y = |2Z|

To find the PDF of Y, we need to consider the transformation of random variables. In this case, we have a transformation involving the absolute value function.

When Z > 0, |2Z| = 2Z.

When Z < 0, |2Z| = -2Z.

Since Z follows a standard normal distribution, its PDF is given by:

f(z) = (1 / √(2π)) * e^(-z^2/2)

To find the PDF of Y, we need to determine the probability density function for both cases when Z > 0 and Z < 0.

When Z > 0:

P(Y = 2Z) = P(Z > 0) = 0.5 (since Z is a standard normal distribution)

When Z < 0:

P(Y = -2Z) = P(Z < 0) = 0.5 (since Z is a standard normal distribution)

Thus, the PDF of Y is given by:

f(y) = 0.5 * f(2z) + 0.5 * f(-2z)

    = 0.5 * (1 / √(2π)) * e^(-(2z)^2/2) + 0.5 * (1 / √(2π)) * e^(-(-2z)^2/2)

    = (1 / √(2π)) * e^(-2z^2/2)

Therefore, the probability density function of Y is f(y) = (1 / √(2π)) * e^(-2z^2/2), where z = y / 2.

2. Mean and Variance of Y:

To find the mean and variance of Y, we can use the properties of expected value and variance.

Mean:

E(Y) = E(|2Z|) = ∫ y * f(y) dy

To evaluate the integral, we substitute z = y / 2:

E(Y) = ∫ (2z) * (1 / √(2π)) * e^(-2z^2/2) * 2 dz

     = 2 * ∫ z * (1 / √(2π)) * e^(-2z^2/2) dz

This integral evaluates to 0 since we are integrating an odd function (z) over a symmetric range.

Therefore, the mean of Y, E(Y), is 0.

Variance:

Var(Y) = E(Y^2) - (E(Y))^2

To calculate E(Y^2), we have:

E(Y^2) = E(|2Z|^2) = ∫ y^2 * f(y) dy

Using the same substitution z = y / 2:

E(Y^2) = ∫ (2z)^2 * (1 / √(2π)) * e^(-2z^2/2) * 2 dz

       = 4 * ∫ z^2 * (1 / √(2π)) * e^(-2z^2/2) dz

E(Y^2) evaluates to 2 since we are integrating an even function (z^2) over a symmetric range.

Plugging in the values into the variance formula:

Var(Y) = E(Y^2) - (E(Y))^2

      = 2 - (0)^2

      = 2

Therefore, the variance of Y, Var(Y), is 2.

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january- $2.00

Feb 4.00

March 8.00

Apr 16.00

may 32.00

jun 64.00

jul 128.00

she ends up with $128

:)

Answer:

The answer is 15

Step-by-step explanation:

125/5=25

25-10=15

An= 5[15+10]=125

Answer:

A) spinning a number less than 3

B) spinning a 4 or 5

D) Spinning a number greater than 8

Step-by-step explanation:

You want to choose the ones where there are two outcomes.

A) spinning a number less than 3

B) spinning a 4 or 5

D) Spinning a number greater than 8

The correct answers are A, B and D

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur.

Given that,  Total numbers on spinner = 10

We have to find the event that has theoretical probability of exactly 1/5.

A) Spinning a number less than 3

Number less than 3 = 1  and 2

Favourable cases = 2

Probability, P(E) = 2/10 = 1/5

It is true.

B) Spinning a 4 or 5

Favourable cases = 2

Probability, P(E) = 2/10 = 1/5

It is true.

D) Spinning a number greater than 8

Number greater than 8=9 and 10

Favourable cases=2

Probability, P(E) = 2/10 = 1/5

It is true.

Hence, Option A, B and D are true.

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Rays AB and AC form a line when extended infinitely in both directions, and they also form an angle at point A.,

The line formed by ray AB and ray AC is explained as follows;

The given sketch of the rays;

<-----C-----------------A---------------------B------>

From the given diagram, we can see that ray AB starts from point A and extends indefinitely towards point B. Similarly, ray AC starts from point A and extends indefinitely towards point C. Both rays share a common starting point, which is point A.

Because these two rays share common point, they will form an angle, whose size will depends on the relative position of point C and point B.

If points B and C are close to each other, the angle formed will be small, and if they are farther apart, the angle will be larger.

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Answer:An angle is defined as two rays with a common endpoint, so CAB (or BAC) is an angle. A line is described as an infinite set of points that extend forever in either direction, which these rays also do.

Step-by-step explanation: it worked

Using fraction, the total number of cupcakes is obtained to be 5.

What is fraction?

In mathematics, a fraction is used to denote a portion or component of the whole. It stands for the proportionate pieces of the whole. Numerator and denominator are the two components that make up a fraction. The numerator is the number at the top, and the denominator is the number at the bottom.

If 4 cupcakes represent 80% of the order, then we can use proportional reasoning to find the total number of cupcakes.

Specifically, if x is the total number of cupcakes, then we can write -

4/x = 80/100

where the left-hand side represents the fraction of the order that is Nom-Nom-Nom cupcakes, and the right-hand side represents the percentage of the order that is Nom-Nom-Nom cupcakes.

Solving for x, we get -

x = 4 / (80/100) = 5

So the total number of cupcakes is 5. Since 4 of them are Nom-Nom-Nom cupcakes, the remaining 1 cupcake must be a Wow cupcake.

Therefore, in total there are 5 cupcakes.

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I've been waiting to order your cupcakes all day! I'll have 4 Nom-Nom-Nom cupcakes -- that's 80% of my order. The rest of the order are Wow.
Find the total number of cupcakes.

Answer:

7.07143

Step-by-step explanation:

Diameter: 18

Angle: 45

Radius: 9

The reasonable area for the square piece of plywood he must purchase if he only wants to make one cut in the wood would be 216 sq inches.

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

We have been given that the flag is to be 18 inches by 12 inches, then;

The area of the rectangle = length × Width

The area of the rectangle = 18 x 12

= 216
Since the area of flag will be equal to area for the square piece of plywood.

The area of a square of side length l is given by l squared;

A(l) = l²

216 = 14.6²

Hence, the reasonable area for the square piece of plywood he must purchase if he only wants to make one cut in the wood would be 216 sq inches.

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The reasonable area for the square piece of plywood he must purchase if he only wants to make one cut in the wood would be 216 sq inches.

What is the area of the rectangle?

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

We have been given that the flag is to be 18 inches by 12 inches, then;

The area of the rectangle = length × Width

The area of the rectangle = 18 x 12

= 216

Since the area of flag will be equal to area for the square piece of plywood.

The area of a square of side length l is given by l squared;

A(l) = l²

216 = 14.6²

Hence, the reasonable area for the square piece of plywood he must purchase if he only wants to make one cut in the wood would be 216 sq inches.

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Answer:

The distance between the last water shop and the end of the race is 2.1 miles

Step-by-step explanation:

Keep on adding 2.75 until you get the number 11 or you can just multiply 2.75 by 4 and get 11. Subtract 11 from 13.1 and you will get 2.1 miles.

I hope this helps

Answer:

2 packets of chocolates

Step-by-step explanation:

Find how many packets of chocolates they made by dividing 1/3 by 1/6:

1/3 / 1/6

= 1/3 x 6

= 2

So, the factory made 2 packets of chocolates

Based on Gru's schemes the probability that a. less than 101 schemes will succeed: 0.9983; b. more than 95 schemes will succeed: 0.0018; c. between 95 and 101 schemes will succeed: 0.9966.

Gru's schemes have a 7% chance of succeeding. Total number of Gru's schemes = 1100.

Using binomial distribution, we can find out the probability of number of successes in n number of trials.

Probability of success in each trial p = 0.07

Probability of failure in each trial q = 1 - 0.07 = 0.93

a) Probability that less than 101 schemes will succeed.

Total number of trials n = 1100

P(X < 101) = P(X ≤ 100)

P(X ≤ 100) = ∑P(X = x) for x = 0, 1, 2, ..., 100

Now we can use normal distribution to approximate this probability as the sample size is large enough to apply central limit theorem. So,

mean (μ) = np = 1100 × 0.07 = 77

standard deviation (σ) = √[npq] = √[1100 × 0.07 × 0.93] = 7.233

Using standard normal distribution,

Z = (X - μ) / σ

Z = (100 + 0.5 - 77) / 7.233 = 2.99

So, P(X ≤ 100) = P(Z ≤ 2.99)

From standard normal distribution table,

P(Z ≤ 2.99) = 0.9983

Therefore, P(X < 101) = P(X ≤ 100) = 0.9983

b) Probability that more than 95 schemes will succeed.

P(X > 95) = P(X ≥ 96)

P(X ≥ 96) = ∑P(X = x) for x = 96, 97, ..., 1100

Now we can use normal distribution to approximate this probability as the sample size is large enough to apply central limit theorem. So,

mean (μ) = np = 1100 × 0.07 = 77

standard deviation (σ) = √[npq] = √[1100 × 0.07 × 0.93] = 7.233

Using standard normal distribution,

Z = (X - μ) / σ

Z = (96 - 0.5 - 77) / 7.233 = 2.91

So,

P(X ≥ 96) = P(Z ≥ 2.91)

From standard normal distribution table,

P(Z ≥ 2.91) = 0.0018

Therefore, P(X > 95) = P(X ≥ 96) = 0.0018

c) Probability that between 95 and 101 schemes will succeed.

P(95 ≤ X ≤ 101) = P(X ≤ 101) - P(X < 95)

P(X < 95) is already calculated in (a).

P(X ≤ 101) = 0.9983

Therefore,

P(95 ≤ X ≤ 101) = P(X ≤ 101) - P(X < 95) = 0.9983 - 0.0017 = 0.9966

Hence, the probability that less than 101 schemes will succeed is 0.9983. The probability that more than 95 schemes will succeed is 0.0018. The probability that between 95 and 101 schemes will succeed is 0.9966.

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By applying the concept of discriminant, the discriminant of the quadratic equation 2 · x² - 9 · x + 2 = - 1 is equal to  57.

For a quadratic equation of the form a · x² + b · x + c = 0, the discriminant is equal to d = b² - 4 · a · c. In this problem we must transform the polynomial into the canonical form and calculate the discriminant:

2 · x² - 9 · x + 2 = - 1

2 · x² - 9 · x + 3 = 0

d = (-9)² - 4 · (2) · (3)

d = 81 - 24

d = 57

By applying the concept of discriminant, the discriminant of the quadratic equation 2 · x² - 9 · x + 2 = - 1 is equal to  57.

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Answer:

Kindly check explanation

Step-by-step explanation:

Given the question:

Play 1: Quarterback was sacked for a loss of 4 yards

Play 2 : Another loss of 10 yards

Play 3: a gain of 12 yards

Write an addition expression to represent the situation. Then find the sum and explain its meaning.

A loss of 4 yards = - 4

Loss of 10 yards = - 10

Gain of 12 yards = + 12

Addition expression for the scenario :

(-4) + (-10) + 12

Result :

-4 + (-10) + 12

= - 4 - 10 + 12

= - 14 + 12

= - 2

Hence, after two consecutive losses of 4 and 10 yards, the team wins 12 yards on the third play and the aggregate yards lost is reduced to 2 yards.