Answer:
B
Explanation:
The disorganized-disoriented kind of attachment has been linked to caregivers who have been observed to be violent or neglectful.
Therefore, option B. is correct.
Who are caregivers?A caregiver seems to be a salaried member of someone's social network who assists them with everyday routines. Because they lack formal training, they are frequently referred to as informal caregivers.
The disorganized-disoriented kind of attachment has been linked to caregivers who have been observed to be violent or neglectful.
Therefore, option B. is correct.
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3. Conduction will occur between objects at different temperatures that are
A separated, but not in contact with each other
B in contact with each or separated
C in contact with each other, but not separated
an airplane flies horizontally from east to west at 290 relative to the air. if it flies in a steady wind that blows horizontally toward the southwest (45 south of west), find the speed and direction of the airplane relative to the ground.
The speed of the airplane relative to the ground is the vector sum of the speed of the airplane relative to the air and the speed of the wind relative to the ground, and the direction is the angle of the resultant vector with respect to the ground.
In this case, we need to break down the velocities into their horizontal and vertical components. The horizontal component of the airplane's velocity is given by V_airplane * cos(290°), and the vertical component is V_airplane * sin(290°).
Similarly, the horizontal and vertical components of the wind's velocity are V_wind * cos(45°) and V_wind * sin(45°), respectively.
To find the resultant velocity, we add the horizontal and vertical components of the airplane's velocity to the horizontal and vertical components of the wind's velocity.
The magnitude of the resultant velocity is calculated using the Pythagorean theorem, and the direction is determined using trigonometric functions.
Therefore, to find the speed and direction of the airplane relative to the ground, we need to calculate the resultant velocity vector using the given information and trigonometric calculations.
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find the horizontal and vertical forces to hold stationary the nozzle The Fluid Flowing Through It Is 10 Degree C Liquid Water; A_1 = 1.0
The horizontal and vertical forces required to hold the nozzle stationary are calculated as follows:
Horizontal force: FH = (1/2)*ρ*(A1 - A2)
Vertical force: FV = (1/2)*ρ*(v22 - v12)
The horizontal and vertical forces required to hold a stationary nozzle with liquid water flowing through it at 10°C can be calculated using Bernoulli’s equation. Bernoulli's equation states that the sum of all the static and dynamic pressure forces acting on a fluid flowing through a system is constant. Using this equation, the pressure forces can be calculated using the area of the nozzle (A1), the density of the water (ρ), the gravitational acceleration (g), and the velocity of the liquid flow (v):
P1 + ρ*g*h + (1/2)*ρ*v2 = P2 + ρ*g*h2 + (1/2)*ρ*v22
The horizontal force is equal to the difference between the static pressures P1 and P2. The static pressure P1 can be calculated using the area of the nozzle (A1) and the density of the water (ρ).
P1 = (1/2)*ρ*A1
The vertical force is equal to the difference between the dynamic pressures at heights h1 and h2. The dynamic pressure at height h1 is calculated using the velocity of the liquid flow (v) and the density of the water (ρ).
P1 = (1/2)*ρ*v2
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PLEASE HELP I WILL GIVE 20 POINTS!!!! A 0.5 kg football is moving at a velocity of
20 ms where it hits a receiver's hands who stops the ball in 0.075 seconds. What force did the receiver put on the ball?
A 15 m/s throw of a 0.50 kilogramme football is made to the right. In 0.020 seconds, a motionless player receives the ball and pulls it to a stop.
What role does velocity have in football?It is beneficial to be capable to kick the ball far or quickly in all football codes. The speed of the foot at the moment it makes contact with the ball is a crucial factor in determining ball speed or kick distance.
In football, what forces are employed?The four forces are gravity, shear forces, contact pressure, and applied force. Football players continually use the force of gravity when they kick, throw, or leap into the air to dodge a tackle or receive the ball.
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A 15 m/s throw of a 0.50 kilogramme football is made to the right. In 0.020 seconds, a motionless player receives the ball and pulls it to a stop.
What role does velocity have in football?It is beneficial to be capable to kick the ball far or quickly in all football codes. The speed of the foot at the moment it makes contact with the ball is a crucial factor in determining ball speed or kick distance.
In football, what forces are employed?The four forces are gravity, shear forces, contact pressure, and applied force. Football players continually use the force of gravity when they kick, throw, or leap into the air to dodge a tackle or receive the ball.
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A metal ring is placed over the top of the extending core rod of an electromagnet so that it lies still on a platform as shown below. At t = 0, the switch for the electromagnet is closed and it produces an AC magnetic field B(r, t) = B(r) sin(ωt), i.e., as a fixed B(r) pattern with cylindrical symmetry modulated by a sinusoidal time factor sin(ωt), and the associated magnetic flux through the ring, while still over the magnet core rod, is Φ(t) = Φ(0) sin(ωt) where Φ0 = R B(r)· da is the time-independent flux of B(r) through the ring, and is taken to be positive. Take the upward direction to be +ˆz. The following steps guide us to find the force on the ring.a.) Take the ring to have a self inductance L, but negligible resistance. Find the induced current I(t) in the ring with the initial condition I(0) = 0. Express your answer in terms of Φ0 and L.
b.) Give sketches showing the directions of I, B acting on the ring, and the Force dF = IdL × B acting on a small segment of the ring for (i) 0 < t < T/4, (ii) T/4 < t < T/2, (iii) T/2 < t < 3T/4, and (iv) 3T/4 < t < T, where T = 2π/ω is the period of the AC magnetic field
c.) Now find the total magnetic force F(t) acting on the whole ring, and the time averaged force F¯ over one full cycle T. Express your answer in terms of Φ0, L, B(R0), and θ. Here R0 is the radius of the ring, B(R0) is the strength of magnetic field at the position of the ring, and θ is the angle B(R0) makes with the vertical as shown in the figure.
d.) Now suppose the ring has negligible self inductance, but a finite resistence R. Repeat (b) for this case. What will F¯ be now?
a) The induced current I(t) in the ring with the initial condition I(0) = 0 is:
I(t) = (Φ0/ωL) cos(ωt)
b) Sketches showing directions of I, B, and dF for different time intervals
c) The total magnetic force is:
F(t) = Φ0^2 R0 B(R0) sin^2(θ) sin(2ωt)/L, F¯ = (Φ0^2 R0 B(R0) sin^2(θ))/2ωL
d) Sketches showing directions of I, B, and dF for different time intervals, F¯ = Φ0^2 R0 B(R0) sin^2(θ)/2R
a) Using Faraday's law, we have ε = -dΦ/dt, where ε is the emf induced in the ring. Since the resistance is negligible, the induced current is given by I = ε/L = -dΦ/dtL.
From the given equation for the magnetic flux, we have Φ(t) = Φ0 sin(ωt). Therefore, I(t) = (Φ0/ωL) cos(ωt).
b) For 0 < t < T/4, the induced current flows clockwise and the magnetic field points upward. Therefore, the force dF on the segment is to the right. For T/4 < t < T/2, the induced current flows counterclockwise and the magnetic field points downward.
Therefore, the force dF on the segment is again to the right. For T/2 < t < 3T/4, the induced current flows clockwise and the magnetic field points downward.
Therefore, the force dF on the segment is to the left. For 3T/4 < t < T, the induced current flows counterclockwise and the magnetic field points upward. Therefore, the force dF on the segment is again to the left.
c) The force on the ring is given by F(t) = ∫IdL × B = Φ0^2 R0 B(R0) sin^2(θ) sin(2ωt)/L. To find the time-averaged force over one cycle T, we integrate F(t) over one cycle and divide by T.
After some algebraic manipulation, we obtain F¯ = (Φ0^2 R0 B(R0) sin^2(θ))/2ωL.
d) When the ring has a finite resistance R, there will be a voltage drop across the ring due to the induced current. Therefore, the induced current will be:
I(t) = (Φ0/ωL) cos(ωt) - (Φ0/RL) sin(ωt).
The direction of the force dF on the segment will depend on the sign of the product of I and B. For T/4 < t < 3T/4, the force on the segment will be in the opposite direction compared to the case where R = 0.
The time-averaged force F¯ can be found by integrating F(t) over one cycle and dividing by T. After some algebraic manipulation, we obtain F¯ = Φ0^2 R0 B(R0) sin^2(θ)/2R.
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The loudness of a sound is related to the logarithm of the ratio of the measured intensity, 1 , to a reference intensity, I. The loudness, L, of a sound is measured in decibels, dB, and can be determined using the formula L=10log 10 ( I 0I). If the intensity of the sound of a rocket launching is 4500 times that of a jet engine and the rocket has a loudness of 170 dB, then the loudness of the jet engine, to the nearest decibel, is
The loudness of a sound is related to the logarithm of the ratio of the measured intensity, 1, to a reference intensity, I. The loudness, L, of a sound, is measured in decibels, dB, and can be determined using the formula L=10log10 (I0I).
Given, The intensity of the sound of a rocket launching = 4500 times that of a jet engine. The loudness of the rocket launching, L = 170 dBNow, we can determine the value of L0 as follows:L = 10 log10 (I0/I)170 = 10 log10 (I0/I) (Equation 1)Therefore, I0/I = antilog (17) (from Equation 1)I0/I = 50,119.41Since the loudness of the rocket launching, L = 170 dB is already given, we can calculate the loudness of the jet engine as follows:L = 10 log10 (I0/I)dB = 10 log10 (I0/I)dB = 10 log10 (50,119.41)dB = 10 (4.700)dB = 47
The intensity of a rocket launching sound is 4500 times that of a jet engine sound, and its loudness is already provided as 170 dB. The loudness of a sound is related to the logarithm of the ratio of the measured intensity to a reference intensity, I.
To calculate the loudness of a jet engine, we can use the formula L = 10 log10 (I0/I).To determine I0/I, we substitute the loudness of the rocket launching, 170 dB, into the formula. We find that I0/I is equal to 50,119.41. We then substitute this value into the formula for the loudness of the jet engine. We find that the loudness of the jet engine is 47 dB. To the nearest decibel, the loudness of the jet engine is 47 dB.
Therefore, the loudness of the jet engine is 47 dB. 150 words to calculate the loudness of a jet engine, we must first determine the intensity of the sound it produces.
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source of error in pendulum investigation
The distance between two successive crests or two successive troughs on a transverse wave is known asA. PitchB. LoudnessC. WavelengthD. Rarefaction
Explanation:
That would be the definition of WAVELENGTH
Fluorine has an atomic number of 9. What can you conclude about an atom of fluorine from this fact?
Answer:
it is placed 9th in the periodic table
it is in the the 7th column and the 2nd period
it is a gas
it valence shell has 7 electrons and it can take 1 electron during ionic bonding
Explanation:
this is all that can into my mind. hope it helps
Fish oil in your diet will improve your memory. Independent variable? Dependent variable
Identify one common electrostatic phenomeno
Answer:
I need to be yourself and your family and friends is 7 units to the south side of the coordinates of the coordinates of the coordinates of the
Explanation:
I need to be yourself and your family and friends is 7 units to the south side of the coordinates of the coordinates of the coordinates of the coordinates of the coordinates of the coordinates of the coordinates of the coordinates of the coordinates of the coordinates of the coordinates of the coordinates of the coordinates of the coordinates of the coordinates of the coordinates of the coordinates of the coordinates of the coordinates and friends and your name the south side to the south end up RM8 the south side and your family are well and that you have received this link and your team nya kek mamang of the south end of G if you are good for me and I love it will take someone who has the coordinates and your family are a hero and heroine of the year of the year of experience as an example the south side to be yourself n the south side and your family are doing great in the year and your team to the south side of the coordinates.
What is the element, atomic number, mass number, and charge of the image?
Answer:
1. Beryllium
2. 4
3. 9
4. 0
Explanation:
• The element shown in the image is beryllium because the atom shown contains four protons and the only element with four protons is beryllium.
• The atom's atomic number is 4, because atomic number is the number of protons of an element, and the atom shown contains 4 protons.
• The mass number of the atom is 9. Mass number is the sum of the number of protons and neutrons in the nucleus of an atom, and the atom shown contains 4 protons and 5 neutrons; therefore its mass number is (4 + 5 =) 9.
• The charge of the atom is 0. This is because it has 4 protons which give it a +4 charge, but it also has 4 electrons which give it a -4 charge. Therefore its net charge is: 4 + (-4) = 0.
4. How long will it take a rotating wheel starting from rest to rotate 38 revolutions if it's constant angular acceleration is 22rads/s^2 ?
If a rotating wheel is starting from rest to rotate 38 revolutions if it's constant angular acceleration is 22rads/s^2, it will take approximately 7.453 seconds to do so.
To determine the time it takes for a rotating wheel to complete a certain number of revolutions with a constant angular acceleration, we can use the following formula:
θ = ω₀t + (1/2)αt²
where:
θ is the angle rotated (in radians)
ω₀ is the initial angular velocity (in radians per second)
α is the angular acceleration (in radians per second squared)
t is the time taken (in seconds)
In this case, the wheel starts from rest, so the initial angular velocity ω₀ is 0.
Given:
Number of revolutions (θ) = 38 revolutions
Angular acceleration (α) = 22 radians per second squared
First, we need to convert the number of revolutions to radians:
1 revolution = 2π radians
38 revolutions = 38 * 2π radians
θ = 76π radians
Next, we can rearrange the equation and solve for time (t):
θ = (1/2)αt²
76π = (1/2) * 22 * t²
Simplifying:
76π = 11t²
Dividing by 11:
(76π) / 11 = t²
Taking the square root:
t = √((76π) / 11)
Calculating the numerical value:
t ≈ 7.453 seconds
Therefore, it will take approximately 7.453 seconds for the rotating wheel to complete 38 revolutions with a constant angular acceleration of 22 radians per second squared.
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The equation y = 2x + 3 represents the cost y (in dollars) of mailing a package that weighs x pounds.
Answer:
what is your question though
Explanation:
??? ??? ??? ??? ???
In the spectrum of a galaxy that is travelling away from Earth a hydrogen line is observed to be shifted from 394 nm to 450 nm. Calculate the velocity of recession of the galaxy.
The velocity of recession of the galaxy will be 37.3×10⁶ m/sec. The concept of Doppler effect is employed in the given problem.
What is the Doppler effect?A sudden change in the frequency due to the distance between the objects and source is explained by the Doppler effect.
As the source and observer travel toward each other, the frequency of sound, light, or other waves increases or decreases.
A passing siren's rapid change in pitch, as well as astronomers' redshift, are both caused by this phenomenon.
Applications of the Doppler effect;
The rest wavelength is,\(\rm \lambda_0 = 394 \ nm\)
The distant wavelength is,\(\rm \lambda = 450 \ nm\)
The velocity of recession is,V
The recession velocity is found as;
\(\rm V = (1-\frac{\lambda}{\lambda_0} )C \\\\ \rm V = (1-\frac{394}{450} )\times 3 \times 10^8 \\\\ V = (1- 0.875)\times 3 \times 10^8 \\\\ V = 37.3 \times 10^6 \ m/sec\)
Hence, the velocity of recession of the galaxy will be 37.3×10⁶ m/sec.
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If an object is not moving, the forces acting upon it are...
A.Balanced
B. Weak
C.Unbalanced
D.Hulk SMASH!
One end of an insulated metal rod is maintained at 100°C while the other end is maintained at 0°C by an ice–water mixture. The rod is 60 cm long and has a cross-sectional area of 1.25 cm2. The heat conducted by the rod melts 8.5 g of ice in 10 min. Find the thermal conductivity k of the metal. For water, Lf = 3.34 × 105 J/kg.
227 W/(m · K)
241 W/(m · K)
253 W/(m · K)
232 W/(m · K)
The thermal conductivity of the metal is approximately B, 241 W/(m · K).
How to determine thermal conductivity?To find the thermal conductivity (k) of the metal, use the formula:
Q = k × A × (ΔT/Δx) × t
Where:
Q = Heat conducted by the rod (in Joules)
A = Cross-sectional area of the rod (in square meters)
ΔT = Temperature difference across the rod (in Kelvin)
Δx = Length of the rod (in meters)
t = Time (in seconds)
Given:
Q = 8.5 g of ice melted = 8.5 × Lf (latent heat of fusion of ice)
Lf = 3.34 × 10⁵ J/kg
Δx = 60 cm = 0.6 m
A = 1.25 cm² = 1.25 × 10⁻⁴ m²
t = 10 min = 600 seconds
ΔT = (100°C - 0°C) = 100 K
Substituting the given values into the formula:
8.5 × Lf = k × (1.25 × 10⁻⁴) × (100 K / 0.6 m) × 600 s
Simplifying the equation:
k = (8.5 × Lf) / [(1.25 × 10⁻⁴) × (100 K / 0.6 m) × 600 s]
Calculating the value:
k = (8.5 × 3.34 × 10⁵) / [(1.25 × 10⁻⁴) × (100 / 0.6) × 600]
k ≈ 241 W/(m · K)
Therefore, the thermal conductivity of the metal is approximately 241 W/(m · K).
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6.A truck drives to a rock quarry at a speed of 20 m/s. The truck takes on a load of
rocks, which doubles its mass, and leaves at the same speed of 20 m/s. Compare the
kinetic energy of the truck as it left the quarry with its kinetic energy on the way to the
quarry. Explain your answer.
Explanation:
The kinetic energy is basically the energy possesses by virtue of a body's motion
1. The truck moving to the quarry
let the mass be x
and the velocity is given as 20m/s
we know that the kinetic energy is given as
KE=1/2mv^2
KE=1/2(x)*20^2
KE=1/2(x)400
KE=200x
2. The truck leaving to the quarry
let the mass be 2x
and the velocity is given as 20m/s
we know that the kinetic energy is given as
KE=1/2mv^2
KE=1/2(2x)*20^2
KE=1/2(2x)400
KE=400x
From the analysis the kinetic energy is a function of mass, doubling the mass doubles the kinetic energy
If the potential energy of a spring when stretched through a distance ‘a’ is 25 J, thenwhat
is the amount of work done on the same spring so as to stretch it by an additionaldistance
‘5a’?
The potential energy stored in a spring stretched through a distance 'x' is given by:
U = (1/2)kx^2
where k is the spring constant.
In this problem, we are given that the potential energy of the spring when stretched through a distance 'a' is 25 J. Therefore, we can write:
25 = (1/2)ka^2
Solving for k, we get:
k = (2*25)/a^2 = 50/a^2
Now, we need to find the amount of work done on the spring to stretch it by an additional distance '5a'. The work done can be found using the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy plus the change in its potential energy.
In this case, there is no change in kinetic energy since the spring is not moving. Therefore, the work done is equal to the change in potential energy:
W = U_final - U_initial
where U_final is the potential energy of the spring when stretched through a distance '6a' (i.e., 'a' plus an additional '5a'), and U_initial is the potential energy of the spring when stretched through a distance 'a'.
The potential energy of the spring when stretched through a distance '6a' is:
U_final = (1/2)k(6a)^2 = (1/2)(50/a^2)(36a^2) = 900 J
Therefore, the amount of work done on the spring to stretch it by an additional distance '5a' is:
W = U_final - U_initial = 900 J - 25 J = 875 J
So, the amount of work done on the spring is 875 J.
check the correctness of physical equation f is equals to MV square upon R where f is the centripetal force acting on a body of mass M performing uniform circular motion along a circle of radius r with liner speed v
Answer:
We know ForceF=mass×acceleration----------(1)
And given ForceF=
r
mv
2
----------(2)
Equating 1 and 2 dimensionaly we get ,
ma=
r
mv
2
MLT
−2
=ML
2
T
−2
L
−1
MLT
−2
=MLT
−2
Two forces of 564 newtons and 466 newtons act on a point. The resultant force is 997 newtons. Find the angle between the two forces The angle between the two forces is (Round to the nearest integer as
The angle between the two forces in the question is 102°.
The angle between two forces can be calculated using the following formula:
F² = F₁² + F₂² + 2F₁F₂cosθ
where F is the magnitude of the resultant force, F₁ and F₂ are the magnitudes of the two forces and θ is the angle between them.
Using this formula, we can calculate the angle between the two forces in question.
Given that two forces of 564 newtons and 466 newtons act on a point and the resultant force is 997 newtons, we can calculate the angle between them as follows:
997²= 564² + 466² + 2 x 564 x 466 x cosθ
cosθ = (997² - 564² - 466²) / (2 x 564 x 466) = -0.186
θ = cos⁻¹(-0.186) = 102 degrees
Therefore, the answer is 102 degrees (rounded to the nearest integer).
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Using 300,000,000 kmkm for the diameter of earth's orbit, calculate the speed of light based on roemer's 1300- ss estimate.
Using 300000,000 km for the diameter of Earth's orbit, calculate the speed of light based on Roemer's 1300-s estimate. How does it differ from a modern value fro the speed of light? speed = distance\time = 300,000,000 km\ 1300 s = 231,000 km/s. This value is 77 percent of the modern value.
What is an orbit?A planet's orbit around a star, a natural satellite's orbit around a planet, or an artificial satellite's orbit around a space object or location like a planet, moon, asteroid, or Lagrange point are all examples of curved trajectory objects that make up an orbit in celestial mechanics. Orbit often refers to a trajectory that repeats itself on a regular basis, while it can also apply to a non-repeating trajectory. According to Kepler's rules of planetary motion, planets and satellites roughly follow elliptic orbits, with the center of mass orbiting at a focal point of the ellipse.
Newtonian mechanics, which explains gravity as a force obeying an inverse-square law, can generally mimic orbital motion well.
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A solenoid of 100 turns has a length of 50.0 cm and a cross-sectional area of 0.385m^2. a) Find the self-inductance of the solenoid. b) Suppose the current in the solenoid increases according to the following formula. I(t)=(5.00A)e^t/2.00s
Find the induced emf in the solenoid when t=20.0 s.
Length of the solenoid, l = 50.0 cm = 0.50 mA = 0.385 m²µ₀ = 4π x 10⁻⁷ H/m. L = (µ₀N²A)/lL = [4π x 10⁻⁷ H/m × (100)² × 0.385 m²]/0.50 mL = 7.87 x 10⁻⁴ H. The induced emf in the solenoid when t=20.0 s is -4.13 V
a) Find the self-inductance of the solenoid.
A solenoid is a type of electromagnet, the wire coiled up such that it produces a magnetic field when electric current passes through it.
The self-inductance of the solenoid can be given by the formula:
L= (µ₀N²A)/
lwhere µ₀ is the permeability of free space
N is the number of turns of the solenoid
l is the length of the solenoid
A is the cross-sectional area of the solenoid
Given that, Number of turns, N = 100
Length of the solenoid, l = 50.0 cm = 0.50 mA = 0.385 m²µ₀ = 4π x 10⁻⁷ H/m. L = (µ₀N²A)/lL = [4π x 10⁻⁷ H/m × (100)² × 0.385 m²]/0.50 mL = 7.87 x 10⁻⁴ H.
b) Find the induced emf in the solenoid when t = 20.0 s.
The induced emf (ε) can be calculated by the formula;
ε = -L dI/dt
where L is the self-inductance of the solenoid and dI/dt is the time rate of change of the current given by;
I(t)=(5.00A)e^t/2.00s
Differentiating I(t) with respect to t gives; dI/dt = 5e^t/2 V/s (Volts per second)Given that L = 7.87 x 10⁻⁴ HWhen t = 20.0s; ε = - L dI/dt = -7.87 × 10⁻⁴ H × (5e^20/2) = -4.13 V
Therefore, the induced emf in the solenoid when t=20.0 s is -4.13 V.
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Why do tin roofs make creaking sounds on hot days?
Answer: Yes, on many slate-roofed homes as temperatures change, such as cooling at night or heating during the day, thermal expansion or contraction of the slates may cause movement that in turn causes snapping, popping, or cracking noises, even bangs and clanks or clicks from the roof.
Explanation:
Answer:
because of its mealting
Explanation:
hope it helps you
Which of the following is an example of a projectile? A Dropped ball B. Airplane C Missile D. Bird
I guess a missile?
A bird is not a projectile, a ball isn't really, and an airplane isn't, so, yeah.
?:]
What happens when heavy exercise results in too much acid in the human body? Excess H+ is absorbed by bicarbonate ions.
Bicarbonate releases one H+ to become carbonate.
H2CO3 is formed from H2O and CO2.
Bicarbonate is formed from carbonate.
Answer:
A: Excess H+ is absorbed by bicarbonate ions.
Explanation:
(ii) Let R be a rotation and S be a reflection of the euclidean plane E. Give a precise deion of RS, relating it to the classification of isometries of E². Be careful of special cases.
RS is a composition of rotation and reflection in the Euclidean plane E². The precise description of RS depends on the specific properties of the rotation R and reflection S.
In general, if R and S have the same axis or line of symmetry, the composition RS results in a translation. If R and S have intersecting lines of symmetry, RS yields a glide reflection. If R and S have perpendicular lines of symmetry, RS produces a rotation.
It is important to consider special cases, such as parallel lines of symmetry, coinciding axes, or perpendicular lines of reflection, as they may lead to different outcomes. The classification of isometries in E² involves understanding how rotations and reflections combine to create different transformations in the plane.
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What would happen to the boiling point of water at 8000 m above sea level where air pressure is lower
Answer:
As altitude increases and atmospheric pressure decreases, the boiling point of water decreases.
A person is considered to have a certain symptom when his or her temperature is higher than 102.2\deg F. The formula F=(9)/(5)C+32 can be used to convert Celsius temperatures C to Fahrenheit temperatures temperatures F. For which Celsius temperatures is the person considered to have the symptom?
The degree celsius temperature at which the person is considered to have the symptom is 39°F.
How to convert °F to °C?Fahrenheit and Celsius both describe a temperature scale.
Fahrenheit is now defined with 32°F equal to 0°C, and each degree Fahrenheit equal to 5/9 of a degree Celsius or 5/9 kelvin.
This means that Fahrenheit can be calculated to degrees Celsius as follows:
Temperature in degrees Celsius (°C) = (Temperature in degrees Fahrenheit (°F) - 32) × 5/9
°C = (102.2 - 32) × 5/9
°C = 39°F
Learn more about Fahrenheit at: https://brainly.com/question/516840
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pls answer if u know the answer ^w^ thx!
Friction _____.
A) is always and unwanted force
B) works in the opposite direction of motion
C) causes machines to work 100 percent efficiently
D) can be increased using lubricants, like oil
Answer:
works in the opposite direction of motion