Carbon and oxygen combine to form the molecular compound CO2, while silicon and oxygen combine to form a covalent network solid with the formula unit SiO2. Explain the difference in bonding between the two group 4A elements and oxygen. g

1. The IUPAC name of N is nitrogen.

2. Nitrogen dioxide

3.The IUPAC name of O is oxygen

4.The IUPAC name of OH is hydroxyl.

The IUPAC name of ·0 is a radical. It is commonly found in organic chemistry and plays an important role in many reactions.

IUPAC names for the given compounds are:1.1. N: Nitrogen

The IUPAC name of N is nitrogen.

It is a non-metal and belongs to group 15 in the periodic table. It has an electronic configuration of 1s2 2s2 2p3.1.2. NO2: Nitrogen dioxide

Explanation: NO2 is a chemical compound that is formed by the combination of nitrogen and oxygen. It is a reddish-brown gas that has a pungent odor.

The IUPAC name of NO2 is nitrogen dioxide.1.3. O: Oxygen

Explanation: The IUPAC name of O is oxygen.

It is a non-metal and belongs to group 16 in the periodic table. It has an electronic configuration of 1s2 2s2 2p4.

X: UnknownExplanation: No IUPAC name can be given to an unknown compound as the structure and composition are not known.

Y: Hydroxyl Explanation: The IUPAC name of OH is hydroxyl.

It is a functional group that is composed of an oxygen atom and a hydrogen atom (-OH). It is commonly found in alcohols and phenols. ·0: RadicalExplanation: A radical is a molecule or an ion that contains an unpaired electron.

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Note: The complete question is given below

Provide the IUPAC names for the following compounds:

\(CH_3CH_2CH(CH_3)CH_2CH_2CH_2CH_3\)

C6H5CH(CH3)2

H2NCH2CH2CH2CH2CH2NH2

CH3CH2CH2CH2CH2OH

CH3CH2CH2CHOHCH3

Answer:

i dont see it

Explanation:

Answer:

A fractionating column or fractional column is an essential item used in the distillation of liquid mixtures to separate the mixture into its component parts, or fractions, based on the differences in volatilities.

Explanation:

The displacement of the balloon at an altitude where the atmospheric pressure is 10.82 inHg would be 9,603.7 L

The displacement of a balloon is determined by the volume of air that it displaces.

Apply Boyle's as follows;

V₁P₁ = V₂P₂

V₂ = (V₁P₁) / P₂

Where;

The final volume is calculated as follows;

V₂ = (3473 x 29.92) / (10.82)

V₂ = 9,603.7 L

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Explanation:

The given chemical equation is:

Fe(CN)63-(aq) + Re(s)-> Fe(CN)64-(aq) + ReO4-(aq)

Consider oxidation half reaction and balance it first in acidic conditions:

\(Re(s)->ReO_4^-(aq)\)

Add water on the left side to balance the O-atoms:

\(Re(s)+4H_2O->ReO_4^-(aq)\\\)

Add protons on the right side to balance H-atoms:

\(Re(s)+4H_2O->ReO_4^-(aq)+8H^+\)

To balance the charge add electrons:

\(Re(s)+4H_2O->ReO_4^-(aq)+8H^++7e^-\)------------(1)

Reduction half reaction:

Fe(CN)63-(aq) -> Fe(CN)64-(aq)

Add electrons to balance the charge:

\(Fe(CN)_6^3^-(aq) + e^- -> Fe(CN)_6^4^-(aq)\)---------------(2)

Multiply equation(2) with seven :

\(7 Fe(CN)_6^3^-(aq) + 7e^- -> 7Fe(CN)_6^4^-(aq)\) ------(3)

Add (1) and (3)

\(7 Fe(CN)_6^3^-(aq) +Re(s)+4H_2O -> 7Fe(CN)_6^4^-(aq)+ReO_4^-(aq)+8H^+\)

Add 8OH- on both sides:

\(7 Fe(CN)_6^3^-(aq) +Re(s)+4H_2O+8OH^- -> 7Fe(CN)_6^4^-(aq)+ReO_4^-(aq)+8H_2O\)

It becomes:

\(7 Fe(CN)_6^3^-(aq) +Re(s)+8OH^- -> 7Fe(CN)_6^4^-(aq)+ReO_4^-(aq)+4H_2O\)

This is the final equation in the basic medium.

Re(s) is oxidised. So it is the reducing agent.

Fe(CN)63- is reduced.It is the oxidising agent.

Answer:

1) Shortage of gas

2) shortage of electricity

Answer:

53.28%

(you could also write 55.33%, but I rounded it so just go with the answer above ---> 53.28%)

Explanation:

Answer: 8 (feet)

Explanation:

24 inches = 2 feet

48 inches = 4 feet

12 inches = 1 foot

To find volume you do Base * Width * Height

2*4*1 = 8

Hope this helps!

The correct answer is  8 (feet).

How to calculate ?

Therefore, 2*4*1 = 8

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An example of an agricultural use for radiation is option B which is irradiating wheat to kill fungus is an example of an agricultural use for radiation.

Radiation in agriculture refers to the use of various forms of ionizing radiation (such as gamma rays, X-rays, and electron beams) for agricultural purposes. This includes using radiation to improve crop yield and quality, preserve food, and control pests and diseases. Radiation can also be used to induce mutations in plants, which can lead to the development of new varieties with desirable traits such as increased yield, disease resistance, and drought tolerance. Additionally, radiation can be used to sterilize soil and agricultural products, such as spices and herbs, to eliminate harmful pathogens and pests. Overall, the use of radiation in agriculture has the potential to improve food safety, increase productivity, and reduce waste in the agricultural industry.

Therefore, radiation can be used to kill harmful organisms such as fungi and bacteria that can cause disease and spoilage in crops, as well as to improve breeding and seed production in plants.

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Answer:

1.5M

Explanation:

M1V1=M2V2

(0.75M)(100ml)=(M2)(50 ml)

M2= 1.5 M

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Answer:

Therefore, the concentration of the resulting dilute solution is 0.190 M.

Explanation:

To determine the concentration of the resulting dilute solution, we can use the equation:

M1V1 = M2V2

where M1 and V1 are the initial concentration and volume of the solution, and M2 and V2 are the final concentration and volume of the solution.

In this case, the initial solution is 10.0 mL of 4.00 M NaCl, which can be expressed as:

M1 = 4.00 M

V1 = 10.0 mL = 0.0100 L

The final volume of the solution is the sum of the initial volume and the volume of water added:

V2 = V1 + V_water

V2 = 0.0100 L + 0.200 L

V2 = 0.2100 L

Since the amount of NaCl in the solution does not change upon dilution, we can set up the equation and solve for the final concentration:

M1V1 = M2V2

(4.00 M)(0.0100 L) = M2(0.2100 L)

M2 = (4.00 M)(0.0100 L)/(0.2100 L)

M2 = 0.190 M

Therefore, the concentration of the resulting dilute solution is 0.190 M.

Answer: Hope this helps:

The balanced chemical reaction for the formation of sodium ion (Na+) and tetrahydroxyborate anion (B(OH)4-) from sodium tetrahydroxyborate (NaB(OH)4) is:

NaB(OH)4 → Na+ + B(OH)4-

This reaction represents the dissociation of sodium tetrahydroxyborate in water to form the sodium ion and tetrahydroxyborate anion, which are both strong electrolytes and therefore completely dissociate in aqueous solution.

Answer:

Power plants are not located in cities. Power has to travel a long distance over power lines to reach cities.

Explanation:

The concentration of species in the reaction changes the reaction in the following ways: decrease carbon dioxide = forward direction of reaction.

The direction of the reaction can be assessed by the following.  On increasing the concentration of the reactant the reaction processes in the forward direction. On increasing the concentration of product the reaction processes in the backward direction.  

The given equilibrium is:

2CO(g) + O2(g) ↔ 2CO2(g)

increase CO = forward direction of reaction  

increase oxygen = forward direction of reaction

decrease CO = no change in equilibrium as reaction not processes.  

decrease oxygen = no change in equilibrium as reaction not processes.  

increase carbon dioxide= reverse direction  

decrease carbon dioxide = forward direction of reaction.

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Answer:

0.551 moles

Explanation:

To calculate the number of moles in 22 grams of argon, divide the mass by the molar mass:

Number of moles = Mass / Molar mass

Number of moles = 22 g / 39.95 g/mol

Number of moles ≈ 0.551 moles

Therefore, there are approximately 0.551 moles of argon in 22 grams of argon.

Answer: Decomposition

Explanation:

The compound, (Aluminum Oxide), decomposes to form Aluminum and Oxygen.

Answer:

Salt is effective as a preservative because it reduces the water activity of foods. .

Answer:

0m

Explanation:

I dont know why the distance is 0 minutes but if he returns to the starting place displacement =0m

The balanced reaction is shown as ;\(2H_{2} O + 2OH^- + 2CoCl_{2} +Na_{2} O_{2} ---- > 2CoCl_{3} + 4Cl^- + 2Na^+\)

We know that a redox reaction is a kind of reaction where one specie is oxidized while the other specie is reduced in the reaction. In this case, we are trying to see how to balance the reaction that is shown under basic conditions.

We know that under basic conditions, we would have to add the hydroxide ions and water so that we can be able to balance the reaction as shown. We would now have; \(2H_{2} O + 2OH^- + 2CoCl_{2} +Na_{2} O_{2} ---- > 2CoCl_{3} + 4Cl^- + 2Na^+\). Thus the reaction is balanced under basic conditions.

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PPE should be worn in the presence of chemical hazards to protect the individual from potential harm. Its usage should be dictated by the presence of the hazard, not by memory or peer action.

You should wear Personal Protective Equipment (PPE) to protect yourself from chemical hazards whenever chemical hazards are present (Option B). PPE is designed to protect you from harmful exposure and injuries. The use of PPE must be based on the hazard presented, not simply when remembered or when others are using it. Hence, whenever you are dealing with chemical hazards, it's crucial to wear the appropriate PPE, which could include items such as gloves, eye protection, protective clothing, and respirators.

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Answer: you have to talk to someone who wont mind wanting to wanting to like you a lot like that.

Explanation:  I wish I could be able to talk to someone who would want to get to like me like that, so its a very relatable situation.

The container will expand to 4.0 L when it holds 2.4 moles of the same gas.

To answer your question, we will use the concept of Avogadro's law, which states that the volume of a gas is directly proportional to the number of moles (n) of the gas when the temperature and pressure remain constant.

Mathematically, it can be represented as:
V1/n1 = V2/n2

where,

V1 and n1 = initial volume and moles of the gas

V2 and n2 = final volume and moles of the gas

Given the initial conditions,

V1 = 3.0 L

n1 = 1.8 moles

The final condition,

n2 = 2.4 moles.

To find V2, Using the given values and rearranging the formula, we have:

V2 = V1 * (n2/n1)

V2 = 3.0 L * (2.4 moles / 1.8 moles)

V2 = 3.0 L * (1.3333)

V2 = 4.0 L

So, when the container holds 2.4 moles of the same gas, it will expand to a volume of 4.0 L. This is because the number of moles of the gas has increased, and according to Avogadro's law, the volume must also increase proportionally to maintain a constant temperature and pressure.

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Answer:Evolution

Evolution is the process by which populations of organisms change over generations. … If a trait is advantageous and helps the individual survive and reproduce, the genetic variation is more likely to be passed to the next generation (a process known as natural selection).

Answer:

Liquid

Explanation:

Answer:

hshssytdtctdyeheb

Explanation:

yye6d66d6d6dududyydydydyehwj2

Answer:

2 MOLES

Explanation:

FIRSTLY CALCULATE GMM OF PROPANE WHICH IS

(12)*3 + 1*8 = 44 GM

THEN, MOLES= GIVEN MASS/44

WHICH IS 88/44=2 MOLES

The aquarium has 0.35 g of dissolved oxygen in it.

The quantity of matter in an object is expressed in terms of mass. It is a scalar number, and units like grams, kilograms, and pounds are used to measure it. Weight, the force of gravity acting on an object, is not the same as mass. An object's mass is a fundamental characteristic that exists regardless of where it is or the gravitational environment it is in.

Henry's law, which connects the concentration of a gas in a solution to its partial pressure, can be used to determine the mass of oxygen (O2) that would be dissolved in a 40 L aquarium:

C = kH x P

where P is the partial pressure of the gas, kH is the Henry's law constant, and C is the concentration of the gas in the solution.

To solve the concentration by rearranging the equation, we obtain:

C = (kH x P) 

Using the above values for kH and P, we obtain:

C = (1.3 10^-3 M/atm) x (0.21 atm) = 2.73 10^-4 M.

This indicates that the aquarium's dissolved oxygen concentration is 2.73 x 10^-4 M.

We can use the following equation to determine the mass of O2 dissolved in the aquarium:

Mass = concentration x volume x molar mass.

where O2 has a molar mass of 32 g/mol.

Inputting the values provided yields:

mass = (2.73 x 10^-4 M) x 40 L x 32 g/mol = 0.35 g

As a result, the aquarium has 0.35 g of dissolved oxygen in it.

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Answer:

3CO(g) + Fe₂O₃(s)

Explanation:

In a chemical equation, the reactants are the substances that undergoes a chemical reaction to form the products. In this case, 3CO(g) and Fe₂O₃(s) react to form 2 {Fe}(s) and 3CO₂(g).

The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

The volume of the gas at 30 °C is approximately 760.67 mL.

To determine the volume of the gas at 30 °C, we can use the combined gas law equation, which relates the initial and final conditions of temperature and volume for a gas.

The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where:

P1 and P2 are the initial and final pressures, respectively

V1 and V2 are the initial and final volumes, respectively

T1 and T2 are the initial and final temperatures in Kelvin, respectively

We need to convert the temperatures from Celsius to Kelvin by adding 273.15 to each value.

Given:

V1 = 550 mL

T1 = -55 °C = 218.15 K

T2 = 30 °C = 303.15 K

Assuming the pressure remains constant, we can rearrange the equation to solve for V2:

V2 = (P1 * V1 * T2) / (P2 * T1)

Since the pressure is not specified in the problem, we can assume it remains constant, allowing us to cancel out the pressure terms. Thus, the final equation becomes:

V2 = (V1 * T2) / T1

Plugging in the given values:

V2 = (550 mL * 303.15 K) / 218.15 K

Simplifying the calculation, we find:

V2 ≈ 760.67 mL

Therefore, the volume of the gas at 30 °C is approximately 760.67 mL.

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An exothermic reaction releases 325 kJ. 1359.8 kJ energy is this in calories.

An exothermic reaction is a chemical reaction that releases heat energy into the surroundings. During an exothermic reaction, the products of the reaction have less potential energy than the reactants, and the excess energy is released in the form of heat.

One calorie is defined as the amount of energy required to raise the temperature of one gram of water by one degree Celsius.

One joule is defined as the amount of energy required to apply a force of one newton over a distance of one meter.

1 cal = 4.184 J

1 cal = 0.004184 kJ

325000 cal = x kJ

0.004184/ 1 = x / 325000

x = 1359.8 kJ

Thus, 1359.8 kJ energy is this in calories.

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Molar volume of hydrogen gas is because 'some bubbles of hydrogen gas remained clinging to the sides of the tube'

The volume occupied by 1 mole of the molecules of a gas at STP i.e. standard temperature and pressure

Here if liquid is not vaporized completely then bubbles of hydrogen gas remained clinging to the sides of the tube and then the condensed vapor in the flask contains the air which is initially occupied before the liquid is heated and when calculating the molar mass of the vapor the moles of air which are initially present are not excluded, so that the molar mass of the vapor would be increase in large value

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