Answer:
Answer for the qn is 55.88%
Step-by-step explanation:
Find the volume and round to the nearest hundredths place when necessary.
Answer:
477
Step-by-step explanation:
Answer:
half of 8 is 4
4^4 = 16
16 x 3.14 = 50.24 (area of a circle)
Now we multiply it by the height:
50.24 x 19 = 954.56 rounded to the nearest hundredths place is:
954.56 yd3 is your answer.
Please help me answer this question it's part of my question that are due today please please help
Answer:
around 82.75
Step-by-step explanation:
please help! will make u brainliest
Answer:
i. Rs6,000
ii. Rs6,900
Step-by-step explanation:
i. FV = PV(1 + r)^d
FV = 40,000(1 + 0.15)^1
FV = 40,000(1.15)
FV = 46, 000
46, 000 - 40,000
Interest = Rs6, 000
ii. FV = PV(1 + r)^d
FV = 46,000(1 + 0.15)^1
FV = 46, 000(1.15)
FV = 52, 900
52, 900 - 46, 000
Interest = Rs6, 900
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Answer is on the attachment...
☆...hope this helps...☆
_♡_mashi_♡_
The weekly amount spent for maintenance and repairs in a certain electricity company was
observed, over a long period of time, to be approximately normally distributed with a mean
of C400 and a standard deviation of C20. If C450 is budgeted for the week, what is the
probability that the actual costs will exceed the budgeted amount?
This problem involves finding the probability that the actual costs for maintenance and repairs in a certain electricity company will exceed the budgeted amount of C450.
We can standardize the distribution of the weekly costs using the z-score formula given:
z = (x - μ) / σ
where x is the budgeted amount, μ is the mean, and σ is the standard deviation.
Substituting the given values, we get:
z = (450 - 400) / 20 = 2.5
Using the z-table, we can find the probability that the actual costs will exceed the budgeted amount as:
P(z > 2.5) = 1 - P(z < 2.5)
From the z-table, we find that P(z < 2.5) = 0.9938
Therefore:
P(z > 2.5) = 1 - 0.9938 = 0.0062
Hence, the probability that the actual costs for maintenance and repairs in the electricity company will exceed the budgeted amount of C450 is 0.0062 or approximately 0.62%.
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A researcher wished to compare the average amount of time spent in extracurricular activities by high school students in a suburban school district with that of high schoolers in a school district of a large city. The researcher obtained an SRS of 60 high school students in a large suburban school district and found the mean time spent in extracurricular activities per week to be x1 = 6 hours, with a standard deviation s1 = 3 hours. The researcher also obtained an independent SRS of 40 high school students in a large city school district and found the mean time spent in extracurricular activities per week to be x2 = 4 hours, with a standard deviation s2 = 2 hours. Let u1 and u2 represent the mean amount of time spent in extracurricular activities per week by the populations of all high school students in the suburban and city school districts, respectively. Assume the two-sample t-procedures are safe to use.
With a level of 5%, test the hypothesis that the amount of time spent on extracurricular activities is no different in the two groups.
For the problem above, a 95% confidence interval for u1-u2 is (use the conservative value for the degrees of freedom)
a. 2 +- 0.5 hours.
b. 2 +- 0.84 hours.
c. 2 +- 1.01 hours.
d. 2 +- 1.34 hours
Evaluate the algebraic expression
p√+(q+6p)2 ; p =14, q=12
This is so confusing pls help
Select the correct answer.
Based on the data in this two-way table, which statement is true?
Type of Flower/Color Red Pink Yellow Total
Rose 40 20 45 105
Hibiscus 80 40 90 210
Total 120 60 135 315
A. A flower being pink and a flower being a rose are independent of each other.
B. A flower being pink is dependent on a flower being a rose.
C. A flower being a rose is dependent on a flower being pink.
D. A flower being pink and a flower being a rose are the same.
Answer: The answer would be A. A flower being pink and a flower being a rose are independent of each other.
Step-by-step explanation:took the test and it was correct on edmentun!!
(Chapter 12) For any vectors u and v in V3, (u X v) * u =0
We can see that the statement is not always true for any vectors u and v in V3.
What are the cross product of vectors?The statement is not always true.
The cross product of vectors u and v in V3 is a vector that is orthogonal to both u and v. That is,
u x v ⊥ u and u x v ⊥ v
However, this does not necessarily mean that (u x v) * u = 0 for all u and v in V3.
For example, let u = <1, 0, 0> and v = <0, 1, 0>. Then,
u x v = <0, 0, 1>
(u x v) * u = <0, 0, 1> * <1, 0, 0> = 0
So in this case, the statement is true. However, consider the vectors u = <1, 1, 0> and v = <0, 1, 1>. Then,
u x v = <1, -1, 1>
(u x v) * u = <1, -1, 1> * <1, 1, 0> = 0
So in this case, the statement is also true. However, if we take the vector u = <1, 0, 0> and v = <0, 0, 1>, then
u x v = <0, 1, 0>
(u x v) * u = <0, 1, 0> * <1, 0, 0> = 0
So in this case, the statement is true as well.
However, if we take the vector u = <1, 1, 1> and v = <0, 1, 0>, then
u x v = <1, 0, 1>
(u x v) * u = <1, 0, 1> * <1, 1, 1> = 2
So in this case, the statement is not true.
Therefore, we can see that the statement is not always true for any vectors u and v in V3.
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82.6>-11.8d
What is d?
Answer:
d > - 7
Step-by-step explanation:
Swap the sides :
- 11.8d < 82.6
Then, divide both sides of the inequality by -11.8 and flip the inequality sign
Determine which representation corresponds to a decreasing speed with an increasing time.
Simon drives faster as
Time Speed
Raphael rolls his ball
he enters the freeway
0
downhill.
0
from the entrance
2.
15
ramp.
4
25
6
45
(spl) poods
Ncho C
00
70
1 2 3 4 5 6 7 8
Time (s)
O
Answer:
the 3rd on edge
Step-by-step explanation:
i did it
Answer:
The 3rd one.
Time (S)
Which inequality represents all the solutions of -2(3x + 6) ≥ 4(x + 7)?
The inequality that represents all the solutions of -2(3x + 6) ≥ 4(x + 7) is x ≤ -4
How to determine the solution of the inequality?From the question, we have the following parameters that can be used in our computation:
-2(3x + 6) ≥ 4(x + 7)
Divide both sides of the inequality by -2
So, we have the following representation
3x + 6 ≤ -2(x + 7)
Open the brackets
This gives
3x + 6 ≤ -2x - 14
Add 2x to both sides of the inequality
So, we have the following representations
5x + 6 ≤ -14
Subtract 6 from both sides of the inequality
So, we have the following representations
5x ≤ -20
Divide both side of the inequality
x ≤ -4
Hence, the solution is x ≤ -4
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the 6 term of a G.P is -2\27 and it's first term is 18.what is the common ratio
Answer:
r = - \(\frac{1}{3}\)
Step-by-step explanation:
The n th term of a GP is
\(a_{n}\) = a₁ \(r^{n-1}\)
where a₁ is the first term and r the common ratio
Here a₁ = 18 and a₆ = - \(\frac{2}{27}\) , then
18 \(r^{5}\) = - \(\frac{2}{27}\) ( divide both sides by 18 )
\(r^{5}\) = - \(\frac{1}{243}\) ( take the fifth root of both sides )
r = \(\sqrt[5]{-\frac{1}{243} }\) = - \(\frac{1}{3}\)
What are three motives of money demand according to Keynes? b. What is equation linking velocity and demand for money according to Keynesian Approach? c. What is the impact on velocity as a result of i. Economy goes in to a recession ii. Credit cards are made illegal iii. Interest rate rises
a) 1.. Transactions motive or Md
2. Speculative motive or Md
3. Precautionary motive or Md
b) Money × Velocity = Price × Transactions or, M × V = P × T.
c) Impact velocity support at the moment of impact.
a) The three motives of money demand according to Keynes are:
1.. Transactions motive or Md
2. Speculative motive or Md
3. Precautionary motive or Md
b) The more money they need for such transactions, the more money they hold. The relation between transactions and money is expressed in equation, called the quantity equation:
Money × Velocity = Price × Transactions or, M × V = P × T.
c) The velocity of money is a measurement of the rate at which money is exchanged in an economy. It is the number of times that money moves from one entity to another. Impact velocity is the velocity of the striker relative to the support at the moment of impact.
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look at the following pseudocode algorithm. algorithm test14(int x) if (x < 8) return (2 * x) else return (3 * test14(x - 8) 8) end test14 what is the base case for the algorithm?
The base case for the given pseudocode algorithm is 150. A base case is an initial and simplest case in an algorithm that does not necessitate further recursion.
It is the condition that aids in the determination of the smallest size of a problem that can be solved without recursion. A base case is a unique and basic condition that is considered to be true in a specific algorithm. A recursive algorithm cannot be used if there is no base case.
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what is 1/10 of 8,000
Answer:
800
Step-by-step explanation:
Please help, thank you!
Answer:
Correct answer is option D
Cheryl is sailing on Lake Superior. A shipwreck lies below her and its location is represented by a negative amount. A helicopter is flying above her and its location is represented by a positive amount. The shipwreck is a greater distance from Cheryl than the helicopter. Which expression could represent a comparison of the possible absolute values of the shipwreck and helicopter?
A) |–125| < |45|
B) |–98.5| < |23.7|
C) |–174.6| > |204|
D) |–362.5| > |45.8|
Answer:
D
Step-by-step explanation:
To solve this, we can go through each answer and see if it is correct.
A)
|–125| < |45|
When comparing absolute values, and the absolute value signs (the | lines) are only around one number, we can ignore the negative. Thus, we have
125 < 45
125 is greater than 45, so this is false
B)
|–98.5| < |23.7|
98.5 < 23.7
98.5 is greater than 23.7, so this is false
C)
|–174.6| > |204|
174.6 > 204
174.6 is less than 204, so this is false
D)
|–362.5| > |45.8|
362.5 > 45.8
362.5 is greater than 45.8, so this is true
shawna is going out of town for the day, so she asks a friend to watch her 3 dogs. she wants to leave 12 of a pound of food for each dog. if a can of dog food has 0.75 pounds of food, how many cans should shawna leave?write your answer as a whole number, decimal, fraction, or mixed number. simplify any fractions.
Shawna wants to make sure her three dogs are fed and cared for when she leaves town for the day. She intends to give each of her dogs 12 ounces of food to achieve this. She must therefore leave a total of 36 ounces of food (3 dogs x 12 ounces of food per dog). 36 ounces are equivalent to 2.25 pounds of food because 16 ounces make up one pound.
There are 0.75 pounds of food in each can of dog food. We must divide 2.25 by 0.75 to find the quantity of dog food Shawna should leave for her companion. 3 dog food cans are the end outcome.Shawna ought to give her buddy three cans of dog food so that she can feed her dogs.
Shawna may make sure her dogs have enough food and are well cared for while she is away by leaving adequate food for them. Shawna may put any fears or concerns about her pets' welfare to rest by leaving ample food and clear directions.
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Sarah has 6 more marbles than Jane. Two times Jane's plus 3 times Sarah's is 68. How many marbles does Jane have?
Answer:
10
Step-by-step explanation:
Construct the equation
Let S=Sarah J=Jane
S=J+6
2J+3S = 68
Using substitution you can get
3(J+6)+2J = 68
5J + 18 = 68
5J = 50
J= 10
Answer:
answer is 10
Step-by-step explanation:
The fraction n/16 is between 1/2 and 3/4. Write down all the possible values of n
Answer:
9,10,11 are the values of n
19. francisco teaches group lessons to all of the violin and
viola students at the scott school of music. all of his
classes have the same number of students. what is the
greatest number of students he can have in each class?
Francisco teaches group lessons to all of the violin and viola students at the Scott School of Music. All of his classes have the same number of students.
What is the greatest number of students he can have in each class We can determine the greatest number of students that Francisco can teach in each class by finding the greatest common factor (GCF) of the total number of violin and viola students at the school.
Suppose there are a total of m violin students and n viola students. Then the total number of students at the school is m + n. Let's find the GCF of m and n in order to determine the greatest number of students Francisco can teach in each class.
GCF of m and n will give us the number of students that can be divided equally among all the classes. Following the steps to find GCF :
Step 1 :List down all factors of m and n
Step 2 :Identify the common factors of both m and n
Step 3 :Find the largest common factor m and n. We find the factors of m and n below: Suppose m = 36 and n = 72.Therefore, the greatest common factor of m and n is 36.So, the greatest number of students that Francisco can teach in each class is 36.
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find an equation of the tangent line to the curve at the given point. y = x3 − 2x + 2, (4, 58)
Answer:Y=10X-16
Step-by-step explanation:
y = x3- 2x 2,( 2, 4)( Given)
Find the first outgrowth, calculate the pitch and find the equation.
We should first know the pitch of the wind at(,4)
pitch at any point on the wind is written by its first outgrowth as
dy/ dx = 3x2- 2
pitch at x = 2
m = 3( 2) 2- 2 = 12- 2 = 10
Equation of a digression is given as
c mx = y
Where m is the pitch
Substituting the values
c 10 × 2 = 4
On farther computation
c 20 = 4
c = 16
The equation of the digression is y = 10 x- 16
Thus, the equation of the digression line to the wind is y = 10x-16
find all points at which the direction of fastest change of the function f(x, y) = x2 y2 − 6x − 8y is i j. (enter your answer as an equation.)
The required equation is \(x^2y^4 + 4x^3y^3 - 4x^2y^2 - 12x^2y\) + 25 = 0
How to find points at which the direction of fastest change of the function?The direction of fastest change of a function at a point is given by the gradient of the function at that point. Therefore, to find the points at which the direction of fastest change of the function f(x, y) = \(x^2 y^2\) − 6x − 8y is in the direction of the vector i j, we need to find the gradient of f(x, y) and then find the points where the gradient is parallel to the vector i j.
The gradient of f(x, y) is given by:
∇f(x, y) = <∂f/∂x, ∂f/∂y> =\(< 2xy^2 - 6, 2x^2y - 8 >\)
To find the points at which the direction of fastest change is in the direction of i j, we need to find the points where the gradient is parallel to i j. This means that the dot product of the gradient and i j should be equal to the product of their magnitudes:
∇f(x, y) · i j = ||∇f(x, y)|| ||i j||
Substituting the values, we get:
\((2xy^2 - 6, 2x^2y - 8)\)· (1, 0) = sqrt((\(2xy^2 - 6)^2 + (2x^2y - 8)^2\)) * sqrt(\(1^2 + 0^2\))
Simplifying this equation, we get:
\(2xy^2\)- 6 = sqrt((\(2xy^2 - 6)^2\) + (\(2x^2y - 8)^2\))
Squaring both sides and simplifying, we get:
\(x^2y^4 + 4x^3y^3 - 4x^2y^2 - 12x^2y + 25 = 0\)
Therefore, the points at which the direction of fastest change of f(x, y) is in the direction of i j are given by the solution of the quartic equation above.
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Find a general term a, for the sequence whose first four terms are given.
1 /1,1/4,1/9,1/16
Answer:
an = 1/n^2
Step-by-step explanation:
We notice that the denominators are the squares of successive integers. The general term will be ...
\(\boxed{a_n=\dfrac{1}{n^2}}\)
Divide using Synthetic Division
2. x3 - 4x² + 2x +5
X-2
Answer:
the answer is 9
Step-by-step explanation:
Answer:
x3-4x2+2x-2
Step-by-step explanation:
Marta Fuentes had a balance of $1,200.50 in her checking account. The bank issued her a credit of
$505 and charged her $12 for new checks. Thee will be no outstanding checks or deposits. What
should her checkbook balance be?
Answer:
$683.50Step-by-step explanation:
Initial balance of Marta Fuentes = $1200.50
Charge made by her bank;
Credit of $505 and Charge on new checks is $12.
Total charge incurred = $505+$12
Total charge incurred = $517
Since there will be no outstanding checks or deposit, her checkbook balance will be the difference between the initial balance and amount charged by the bank.
Checkbook balance = $1200.50 - $517
Checkbook balance = $683.50
Hence her checkbook balance should be $683.50
Rational numbers that are not intergers
Answer:
This includes numbers that are not whole numbers (+ or -). For example, 6.79, 20,193.917017, 4/25, etc.
Find the slope of the line passing through the points (-5, 3) and (7, 9)
Answer:
1/2
Step-by-step explanation:
The slope of the line passing through the points (-5, 3) and (7, 9) is \(\frac{1}{2}\).
What is the expression of slope of a line that passes through two points?If the line passes through points (x, y) and (x, y) then the slope of the line will be: \(m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\)
Given, two points are (-5, 3) and (7, 9).
Therefore, slope of the line that passes through above two points is:
\(m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\)
\(= \frac{9 - 3}{7 - (- 5)}\\= \frac{6}{12}\\ = \frac{1}{2}\)
Therefore, the slope of the line will be \(\frac{1}{2}\).
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what is the measure of an angle if the measure of its two adjacent supplementry angles add up to 100 degrees.
The measure of the angle if the measure of its two adjacent supplementary angles add up to 100 degrees is 80 degrees.
Let the measure of the angle be x.
We are given that the measure of its other two supplementary angles is 100°
We know that:
The sum of the supplementary angles is equal to 180°.
So, we get that:
100° + x = 180°
Subtract 100° from both the sides:
x = 180° - 100°
Simplify the expression:
x = 80°
Therefore, we get that, the measure of the angle if the measure of its two adjacent supplementary angles add up to 100 degrees is 80 degrees.
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What is the laterral surface area?
Answer:
In other words, the surface area is the sum of all the areas of all the shapes that cover the surface of the object. On the other hand, the lateral surface area refers to the area of the sides of a shape , excluding its base and top area.
Step-by-step explanation: