Can you please help me with this question

Answer:

Yup, it is indeed a function.

Step-by-step explanation:

As long as an input is not mapped to two or more outputs, it is a function.

In this web, no inputs are mapped to more than one output.

The proportion of a normal distribution located between z = .50 and z = -.50 will be 38.2%.

We have,

A normal distribution located between z = 0.50 and z = -0.50,

So,

Now,

From the Z-score table,

We get,

The Probability corresponding to the Z score of -0.50,

i.e.

P(-0.50 < X < 0) = 0.191,

And,

The Probability corresponding to the Z score of -0.50,

i.e.

P(0 < X < 0.50) = 0.191,

Now,

The proportion of a normal distribution,

i.e.

P(Z₁ < X < Z₂) = P(Z₁ < X < 0) + P(0 < X < Z₂)

Now,

Putting values,

i.e.

P(-0.50 < X < 0.50) = P(-0.50 < X < 0) + P(0 < X < 0.50)

Now,

Again putting values,

We get,

P(-0.50 < X < 0.50) = 0.191 + 0.191

On solving we get,

P(-0.50 < X < 0.50) = 0.382

So,

We can write as,

P(-0.50 < X < 0.50) = 38.2%

So,

The proportion of a normal distribution is 38.2%.

Hence we can say that the proportion of a normal distribution located between z = .50 and z = -.50 will be 38.2%.

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1. The solution to the equation 4x/x-2 = 3 is a single value of x that satisfies the equation. In this case, we can simplify the equation to 4x = 3(x-2), which gives us x = 6. Therefore, the solution to this equation is x = 6.

On the other hand, the solution to the inequality 4x/x-2 ≤ 3 is a range of values of x that satisfy the inequality. We can start by simplifying the inequality to 4x ≤ 3(x-2), which gives us 7x ≤ 6. Solving for x, we get x ≤ 6/7. Therefore, the solution to this inequality is all values of x that are less than or equal to 6/7.

2. No, it is not possible to have a linear function whose reciprocal does not have any restrictions on domain and range. The reciprocal of a linear function is a rational function, and all rational functions have restrictions on their domain and range. In particular, the domain of a rational function cannot include any values that make the denominator equal to zero, and the range cannot include any values that make the numerator equal to zero.

3. Yes, it is possible to have a reciprocal of a quadratic function that has only one vertical asymptote. For example, consider the quadratic function f(x) = (x-1)(x+2). The reciprocal of this function is g(x) = 1/((x-1)(x+2)), which has a vertical asymptote at x = 1 and no other vertical asymptotes. This is because the denominator of g(x) has two linear factors, and when one of these factors is set to zero (i.e., when x = 1), the denominator is still nonzero due to the other factor.
1. The difference between the solution to the equation 4x/(x-2) = 3 and the solution to 4x/(x-2) ≤ 3 lies in the type of solution they provide. The first equation seeks an exact value for x that makes the equation true, whereas the second equation seeks a range of values for x that make the inequality true.

2. No, it is not possible to have a linear function whose reciprocal does not have any restrictions on domain and range. Linear functions are of the form y = mx + b. If we take the reciprocal, we have y = 1/(mx + b). The domain will be restricted because if mx + b = 0, then the denominator will be zero, which is undefined. Similarly, the range will be restricted as y cannot take the value of zero.

3. Yes, it is possible to have a reciprocal of a quadratic function that has only one vertical asymptote. Consider the quadratic function y = (x-1)^2. Its reciprocal is y = 1/((x-1)^2). In this case, there is only one vertical asymptote at x = 1, since the denominator will be zero at this point, making the function undefined.

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Answer:

sorry for being late  :P

Step-by-step explanation:

slope = rise / run

by inspection of the graph.. it looks like the line goes over 2 units and then up one unit  so   1/2.... and b/c it's going up... like up hill.. it's positive...

+ 1/2  is the slope

Answer:

1st choice

Step-by-step explanation:

(r² -4r + 5 - r² -2r + 8) / (r - 4)

= (-6r + 13) / (r - 4)

Answer:

A.

1) 60

2) 27

B)

1.cm³

2.cm³

3.m³

Step-by-step explanation:

A)

5x3x4 =60cm³

3x3x3=27cm³

B)

1.cm³

2.cm³

3.m³

The vector normal to the plane passing through the points (-7,2,-1), (-2,1,-5), and (-2,2,-3) is <4,17,11>.

To find the vector normal to the plane passing through three given points, we need to first find two vectors lying on the plane. We can do this by taking the difference between the first two points and the last two points.

Vector 1: (-7,2,-1) - (-2,1,-5) = <-5,1,4>

Vector 2: (-2,2,-3) - (-2,1,-5) = <0,1,2>

Next, we take the cross product of these two vectors to get the normal vector:

<4,17,11> = <-5,1,4> x <0,1,2>

The resulting vector is perpendicular to both vector 1 and vector 2, and hence lies on the plane passing through the three given points.

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Answer:

69cups of fruit

Step-by-step explanation:

12c + 23c + 34c= answer

Answer:

y-value is direct variation

Step-by-step explanation:

Solve the equation for inverse and cross multiply.

The monthly loan payment for the offer made by Juanita, given the cost of the car and the dealership, is A. 248.62

First, find the amount taken on loan :

= 15, 000 x ( 1 - 10 % down payment )

= $ 13, 500

The periodic rate is:

= 4 % / 12

= 1 / 3 %

The number of periods :

= 5 years x 12 months a year

= 60 months

The monthly payment is:

Present value of loan = Monthly Payment x Present value interest factor of annuity, 1 / 3 %, 60 months

13, 500 = 54.299068906557 x Monthly payment

Monthly payment = 13, 500 / 54.299068906557

= 248. 62

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1/2 fraction of the day will the clock show the correct time when  it is supposed to display a 1 , it mistakenly displays a 9.

An element of a whole is a fraction. The number is represented mathematically as a quotient, where the numerator and denominator are divided. Both are integers in a simple fraction. A fraction appears in the numerator or denominator of a complex fraction. The numerator of a proper fraction is less than the denominator.

Here,

=2/3(1-15/60)

=2/3(3/4)

=2/4

=1/2

When the clock should be displaying a 1, but instead shows a 9, the correct time will be displayed for 1/2 of the day.

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Answer:

Here is your answer

((3 * 6) ^ 8) ^ 7 =

(18 ^ 8) ^ 7 =

11019960576 ^ 7 = 19736052228807988194997231645899399052500495522364054175325333567307776

Step-by-step explanation:

The water output rate for Reed's sprinkler is 25L/hour. We have to find the water output rate for each sprinkler if the sum of the two rates was 45L per hour. We know that the Rogers family sprinkler was used for 15 hours and the Reed family sprinkler was used for 30 hours.

Therefore the combined time the two sprinklers were used for was:15 + 30 = 45 hours

Therefore, The Rogers family's sprinkler output rate: r₁

The Reed family's sprinkler output rate: r₂

Given that the sum of the two rates was 45L per hour: r₁ + r₂  = 45 -----Equation (1)

Now, let's calculate the water output of each sprinkler using their respective times:

Water output of Rogers' sprinkler = r₁ × 15

Water output of Reed's sprinkler = r₂  × 30

The total output was 1050L:

r₁ × 15 + r₂  × 30 = 1050 -----Equation (2)

We have two equations and two variables. We will solve for r₁ and r₂ :

r₁ + r₂ = 45r₂ = 45 - r₁

Substituting the value of r₂ in equation (2), we get:

r₁ × 15 + (45 - r₁) × 30 = 105015r₁ + 1350 - 30r₁

= 1050-15r₁

= -300r₁

= 20r₂

= 45 - r₁

= 45 - 20 = 25

Therefore, The water output rate for Rogers' sprinkler is 20L/hour.

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Answer:

it is B how are you

Step-by-step explanation:

trust me

Karen is wrong as she wrote the second angle as (x - 10) instead of

(x + 10).

An algebraic expression is a combination of terms both constants and variables. For example -

2x + 3y + z

3x + y

Given is that the sum of the measures of the three interior angles of a triangle is 180°. One angle is 10 more than the first angle, while the third angle is 20 more than thrice the first.

No, Karen is completely wrong. She wrote the second angle as (x - 10). However, it is given that one angle is 10 more than the first angle. This means that the second angle is (x + 10).

Therefore, Karen is completely wrong as she wrote the second angle as (x - 10) instead of (x + 10).

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Answer:

a×

a×_

a×_12

Step-by-step explanation:

1

_

-6

_

2

6×2=12

a×

_

6

_

2

ax

_12

The value of x is obtained as follows:

128º.

The measure of angle A is given as follows:

m < A = 132º.

For a parallelogram, the opposite angles are congruent, meaning that they have the same measure, hence the value of x is obtained as follows:

5x - 508 = x + 4.

4x = 512

x = 512/4

x = 128.

Then the measure of angle A is given as follows:

m < A = 5(128) - 508

m < A = 132º.

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1. Multiply both sides by 2. 4 + 3x = 5 * 2
2. Simplify. 4 + 3x = 10
3. Subtract 4 from both sides to single out x. 3x = 10 - 4
4. Simplify. 3x = 6
5. Divide by 3. x = 6/3
6. Simplify. x = 2

Input 2 into the original equation to check this answer and you will get 5 = 5 which means that x = 2 is your final answer.

Answer: x = 2

Step-by-step explanation:

    To solve for x, we will isolate the variable (x).

Given:

    \(\displaystyle \frac{4+3x}{2}=5\)

Multiply both sides of the equation by 2:

    4 + 3x = 10

Subtract 4 from both sides of the equation:

    3x = 6

Divide both sides of the equation by 3:

    x = 2

Answer:

9/13, The numerator is always on top and the denominator is always on the bottom.

The output of the function when x=4 is 23

Given the function as;

f(x)=4x+7

We are told to find f ( 4)

This explains that we should substitute the value of x as 4 in the function:

To find the value of the function at x = 4 we have:

If  f(x)=4x+7

Then,

Put 4 as a replacement for x, we have:

f ( 4) = 4 ( 4) + 7

Expand the bracket

f ( 4) = 16 + 7

Add the values

f ( 4)  = 23

The value of the function is 23

We can see that the value of the function when x is 4 is 23

Thus, the output of the function when x=4 is 23

The complete question is;

For each function what is the output for the given input?

For f(x)=4x+7, find f(4)

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a). We have proved all the given conditions.

b). It is true that condition 3 holds for all regular languages L1 and L2.

(a) Regular languages L1 and L2 can be suggested as follows:

Let \(L_1={0^{(n+1)} | n\geq 0}\)

and

\(L_2={1^{(n+1)} | n\geq 0}\)

We have to prove three conditions:1. L1 ⊈ L2:

The given languages L1 and L2 both are regular but L1 does not contain any string that starts with 1.

Therefore, L1 and L2 are distinct.2. L2  L1:

The given languages L1 and L2 both are regular but L2 does not contain any string that starts with 0.

Therefore, L2 and L1 are distinct.3. (L1 ∪ L2)* = L1* ∪ L2*:

For proving this condition, we need to prove two things:

First, we need to prove that (L1 ∪ L2)* ⊆ L1* ∪ L2*.

It is clear that every string in L1* or L2* belongs to (L1 ∪ L2)*.

Thus, we have L1* ⊆ (L1 ∪ L2)* and L2* ⊆ (L1 ∪ L2)*.

Therefore, L1* ∪ L2* ⊆ (L1 ∪ L2)*.

Second, we need to prove that L1* ∪ L2* ⊆ (L1 ∪ L2)*.

Every string that belongs to L1* or L2* also belongs to (L1 ∪ L2)*.

Thus, we have L1* ∪ L2* ⊆ (L1 ∪ L2)*.

Therefore, (L1 ∪ L2)* = L1* ∪ L2*.

Therefore, we have proved all the given conditions.

(b)It is true that condition 3 holds for all regular languages L1 and L2.

This can be proved by using the fact that the union of regular languages is also a regular language and the Kleene star of a regular language is also a regular language.

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Answer:

0, 2, 4, 6, 8

Step-by-step explanation:

the first couple of multiples of 2 are...

2, 4, 6, 8, 10

the last digits are 0, 2, 4, 6, 8...

so, 0, 2, 4, 6, 8 are the last digits!

The boundary of the "triangular" region in the first quadrant enclosed by the x-axis, the line x = 1, and the curve y = x^3 is given by the line segment from (0, 0) to (1, 1) and the curve y = x^3 in the interval [0, 1].

To find the boundary of the triangular region, we need to identify the points where the x-axis, the line x = 1, and the curve y = x^3 intersect in the first quadrant.

The x-axis: The x-axis is the line y = 0. Therefore, the point of intersection with the x-axis is (x, y) = (x, 0).

The line x = 1: This is a vertical line passing through x = 1. Therefore, the point of intersection with the line x = 1 is (x, y) = (1, y).

The curve y = x^3: This is a curve in the first quadrant defined by y = x^3. To find the intersection points with this curve, we equate y = x^3 and solve for x. This gives us x = y^(1/3).

Now, let's analyze the boundary of the triangular region in the first quadrant:

a) Starting point: (0, 0) - The boundary begins at the origin (0, 0).

b) Line segment: From (0, 0) to (1, 0) - This segment lies along the x-axis.

c) Curve segment: From (1, 0) to (1, 1) - This segment lies on the curve y = x^3 and corresponds to x = 1.

d) Final point: (1, 1) - The boundary ends at the point (1, 1).

In conclusion, the boundary of the "triangular" region in the first quadrant enclosed by the x-axis, the line x = 1, and the curve y = x^3 consists of the line segment from (0, 0) to (1, 0) along the x-axis, and the curve segment from (1, 0) to (1, 1) on the curve y = x^3.

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The equation that represents this parabola in standard form is y = x²

From the question, we have the following parameters that can be used in our computation:

(0,0) , (1,1) and (-1, 1)

A parabola in standard form is represented as

y = ax² + bx + c

Using the points, we have

(0)²a + (0)b + c = 0

c = 0

Next, we have

(1)²a + (1)b + 0 = 1

a + b = 1

(-1)²a + (-1)b + 0 = 1

a - b = 1

Add the equations

2a = 2

a = 1

So, we have

1 + b = 1

b = 0

This means that the equation is y = x²

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Question

Given three points that lie on the parabola, find the equation that represents this parabola in standard form

(0,0) , (1,1) and (-1, 1)

For a system with nn = 2, the probability of finding the particle in the left one-third of the box can be calculated using quantum mechanics. The probability is approximately 0.667, rounded to three significant figures.

1. In quantum mechanics, the wave function describes the probability distribution of a particle's position. For a system with nn = 2, there are two possible states: the left state (L) and the right state (R). The wave function for this system can be represented as a linear combination of these two states: Ψ = aL + bR.

2. To calculate the probability of finding the particle in the left one-third of the box, we need to determine the coefficients a and b. The probabilities are given by the absolute squares of the coefficients. Since the particle is equally likely to be in either state at the beginning, we can assume a = b = 1/√2.

3. To find the probability of the particle being in the left state (PL), we square the absolute value of the coefficient a and divide it by the sum of the squared absolute values of both coefficients: PL = |a|^2 / (|a|^2 + |b|^2) = (1/√2)^2 / [(1/√2)^2 + (1/√2)^2] = 1/2 / (1/2 + 1/2) = 1/2.

4. Since the left one-third of the box occupies half of the total space, the probability of finding the particle in this region is half of the probability of being in the left state: P(left one-third) = PL / 2 = 1/2 / 2 = 1/4 = 0.25. Rounded to three significant figures, the probability is approximately 0.250.

5. Therefore, for a system with nn = 2, the probability that the particle will be found in the left one-third of the box is approximately 0.667, rounded to three significant figures.

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Answer:

-1.18

Step-by-step explanation:

4/√10 - √6

= (4-√60) /√10

= -1.18 (3 sig. fig.)

Answer:

−8+2/5√10(Decimal: -6.735089)

Step-by-step explanation:

Thats the answer ._.

Answer:

-4y-12+4b

Step-by-step explanation:

Use the Distributive Property:

\( - 4(y + 3 - b)\)

\( - 4y - 12 + 4b\)

\(-4y-12+4b\) is an equivalent expression.

Answer:

The answer is---

x=10

Step-by-step explanation:

(4x+9)+(7x+4)+57=180

11x+13+57=180

11x=110

x=10

Answer:

x ≥ 0

Step-by-step explanation:

The absolute value of x+8 equals itself, thus x must be a real number (0 or any positive number).

The value of x in |x+8|=x+8 is -8.

An equation is an expression that shows the relationship between two or more numbers and variables.

A mathematical equation is a statement with two equal sides and an equal sign in between. An equation is, for instance, 4 + 6 = 10. Both 4 + 6 and 10 can be seen on the left and right sides of the equal sign, respectively.

We are given that;

|x+8|=x+8

Now,

To solve this equation, we need to consider two cases:

Case 1: x+8 is positive or zero. Then |x+8|=x+8 and we can solve for x by subtracting 8 from both sides:

|x+8|=x+8

x+8=x+8

x=x

This means that any value of x is a solution in this case.

Case 2: x+8 is negative. Then |x+8|=-(x+8) and we can solve for x by adding 8 to both sides and dividing by -2:

|x+8|=-(x+8)

x+8=-(x+8)

2x=-16

x=-8

Therefore, by the given equation the answer will be -8.

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Therefore, the solution expressed in inequality notation is x < 6 or x > 18. (C). In interval notation, this solution can be written as (-∞, 6) ∪ (18, +∞).

To solve the inequality \(x^2 + 27 > 12x\), we can rearrange the equation to bring all terms to one side:

\(x^2 - 12x + 27 > 0\)

Now, we can use a sign chart to analyze the inequality.

Step 1: Find the critical points by setting the expression equal to zero and solving for x:

\(x^2 - 12x + 27 = 0\)

This equation does not factor nicely, so we can use the quadratic formula:

x = (-(-12) ± √\(((-12)^2 - 4(1)(27))\)) / (2(1))

x = (12 ± √(144 - 108)) / 2

x = (12 ± √36) / 2

x = (12 ± 6) / 2

The critical points are x = 6 and x = 18.

Step 2: Create a sign chart using the critical points and test points within the intervals.

Interval (-∞, 6):

Choose a test point, e.g., x = 0:

Substitute the value into the inequality: \(0^2 + 27 > 12(0)\)

27 > 0 (true)

The sign in this interval is positive (+).

Interval (6, 18):

Choose a test point, e.g., x = 10:

Substitute the value into the inequality: \(10^2 + 27 > 12(10)\)

127 > 120 (true)

The sign in this interval is positive (+).

Interval (18, +∞):

Choose a test point, e.g., x = 20:

Substitute the value into the inequality: \(20^2 + 27 > 12(20)\)

427 > 240 (true)

The sign in this interval is positive (+).

Step 3: Express the solution in inequality notation based on the sign chart:

Since the inequality is greater than (>) zero, the solution can be expressed as x < 6 or x > 18.

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