Can you please help me

Answer:

As engine size increases, highway mileage decreases.

Step-by-step explanation:

The least-squares linear correlation coefficient for the given dataset can be determined using the Desmos graphing calculator. The options provided are: r=0.74, r=0.938, r=0.968, and r=0.811.

To find the least-squares linear correlation coefficient, we need to calculate the Pearson correlation coefficient (r). This coefficient measures the strength and direction of the linear relationship between two variables. In this case, the dataset consists of pairs of values (x, y).

Using the Desmos graphing calculator, we can input the dataset and generate a scatter plot. Then, by selecting the option to display the line of best fit or the regression line, we can obtain the equation of the line and the value of r, the least-squares linear correlation coefficient.

Based on the options provided, we need to calculate the value of r using the Desmos graphing calculator and compare it to the given options. After performing the calculations, the correct answer is the option that matches the calculated value of r.

Therefore, the option that corresponds to the least-squares linear correlation coefficient calculated using the Desmos graphing calculator for the given dataset should be selected as the answer.

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Given

Procedure

Now for y

The answer would be x = 2.75 and y = 1.25

When the residual is negative it represents the predicted value is very much high.

Therefore, the negative residual value on the regression line represents the predicted value is very much high.

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The option that is true with regard to the following functions is Option B. "The domain g(x) and h(x) include all real number while the domain of i(x) and h(x) are restricted"

Note that this function is indicative of a straight-line. See the attached graph for function 1. Note that it doesn't have any end points. That is, it is Asymptote.

This represents an exponential graph. Just like the function above it doesn't have any end point. It however has an asymptote:

y = 0

This is indicative of logarithm graph. It doesn't have any end but has an asymptote x == 0

Notice that in the mid point there is an end point given as (0, -14). Thus, it is correct to state that the function in Option B is the only one that exhibits end behavior and as such is restricted.

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12/22 aaannnssswwweeerrr

Answer:

226.2 in³ and 452.4 in³

Step-by-step explanation:

Volume of original shape:

Volume = base area x height
Volume = πr² x 2
Volume = π(6)² x 2
Volume = 113.10 x 2
Volume = 226.2 in³

Volume with same radius but double the height:

Volume = base area x height
Volume =  πr² x 2(2) ----------> multiplied by 2 because height is being doubled
Volume = 113.10 x 4
Volume = 452.4 in³

Answer:

95

Step-by-step explanation:

Formula -

Triangle Area - 1/2bh

Square - l x w

Triangle - 5 x 7 = 35/2 = 17.5

Since there are four triangle, we will multiply 17.5 x 4 which is equal to 70

Square  - 5 x 5 = 25

Now we add both 70 and 25 which is 95

So the total surface area is 95

Answer:

95

Step-by-step explanation:

Area of the triangles:

Area of a square:

Put them together:

I hope this helps!

The value of z that corresponds to a cumulative probability of 0.901 can be found by using the standard normal distribution table or a statistical calculator and that is approximately -1.67.

In the standard normal distribution, the area under the curve between -z and z represents the cumulative probability from negative infinity to z. Since the distribution is symmetric, the area from negative infinity to -z is also 0.5 - 0.901/2 = 0.0495.

To find the value of z, we need to locate the z-score that corresponds to an area of 0.0495 in the standard normal distribution. By looking up this value in the standard normal distribution table or using a statistical calculator, we find that z is approximately -1.67.

Therefore, the value of z that corresponds to a cumulative probability of 0.901 is approximately -1.67.

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Step-by-step explanation:

?Can you please explain more??

    ︵‿︵‿୨♡୧‿︵‿︵

In 1996, the cooperative expects approximately 40% of cranberries processed to be water-harvested.

This is a decrease of 18% from 1995. This decrease is likely due to the fact that water-harvested cranberries cost more to process than traditional dry-harvested cranberries.

Additionally, the cooperative may not be able to find enough cranberry farmers willing to switch to the water-harvesting method, which is a labor-intensive process.

Thus, the cooperative is likely to experience a decrease in the percentage of water-harvested cranberries processed in 1996.

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Answer:

\(\large \boxed{\sf \ \ 70\% \ \ }\)

Step-by-step explanation:

Hello,

We assume that the year is 52 weeks, and we note r the interest rate we are looking for. The rate is expressed in percent and is annually, meaning that the investment is, after the first week :

   \(1000\cdot (1+\dfrac{r\%}{52})=1000\cdot (1+\dfrac{r}{5200})\)

For the second week

   \(1000\cdot (1+\dfrac{r}{5200})^2\)

After 52 weeks

   \(1000\cdot (1+\dfrac{r}{5200})^{52}\)

and we want to be equal to 2000 so we need to solve:

\(1000\cdot (1+\dfrac{r}{5200})^{52}=2000\\\\\text{*** divide by 1000 both sides ***}\\\\(1+\dfrac{r}{5200})^{52}=\dfrac{2000}{1000}=2\\\\\text{*** take the ln **}\\\\52\cdot ln(1+\dfrac{r}{5200})=ln(2)\\\\\text{*** divide by 52 ***}\\\\ln(1+\dfrac{r}{5200})=\dfrac{ln(2)}{52}\\\\\text{*** take the exp ***}\\\\\displaystyle 1+\dfrac{r}{5200}=exp(\dfrac{ln(2)}{52})=2^{(\dfrac{1}{52})}=\sqrt[52]{2}\\\\r = 5200\cdot (\sqrt[52]{2}-1)=69.77875...\)

Rounded to the nearest percent, the solution is 70%.

If you want to double your capital in one year with weekly compounding you need an interest rate of 70% !!

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

4%

Step-by-step explanation:

Answer: ? What are you talking about?

Step-by-step explanation:

Answer:

\(m\angle 2=95^{\circ}\)

Step-by-step explanation:

It is given that ∠1 and ​∠2​ are a linear pair. So, there sum is 180 degrees.

\(m\angle 1+m\angle 2=180^{\circ}\)    ...(1)

∠2​ and ​∠3​ are vertical angles. So, both are equal.

\(m\angle 2=m\angle 3\)     ...(2)

From (1) and (2), we get

\(m\angle 1+m\angle 3=180^{\circ}\)

Substitute \(m\angle 1=(3y+10)^{\circ}\) and \(m\angle 3=(5y-30)^{\circ}\) in the above equation.

\((3y+10)^{\circ}+(5y-30)^{\circ}=180^{\circ}\)

\((8y-20)^{\circ}=180^{\circ}\)

\(8y-20=180\)

\(8y=180+20\)

Divide both sides by 8.

\(y=\dfrac{200}{8}\)

\(y=25\)

The value of y is 25.

Using equation (2), we get

\(m\angle 2=m\angle 3=(5y-30)^{\circ}\)

Substitute y=25.

\(m\angle 2=(5(25)-30)^{\circ}\)

\(m\angle 2=(125-30)^{\circ}\)

\(m\angle 2=95^{\circ}\)

Therefore, \(m\angle 2=95^{\circ}\).

Answer:

let difference be x

Step-by-step explanation:

you can solve for x by keeping the 2 statesments as conditions.

then you solve for both equations together by adding subtracting or multiplying.

eg: let x be the number.

the. proceed with conditions as equations

then solve

then your answer is here

The upper and lower limits for the sample mean control chart are:

UCL = 6.66

LCL = 3.36

To calculate the upper and lower limits for the sample mean control chart, we need to use the given data and formulas.

Sample size (n) = 15

Sample mean values: 13.30, 3.16, 3.21, 3.30, 3.27, 3.20

Range values: 0.49, 1.41, 2, 3, 0.47, 14, 5, 6, 0.49, 0.46, 0.54

First, we calculate the average range (R-bar) using the range values:

R-bar = (Sum of ranges) / (Number of samples)

R-bar = (0.49 + 1.41 + 2 + 3 + 0.47 + 14 + 5 + 6 + 0.49 + 0.46 + 0.54) / 11

R-bar ≈ 2.86 (rounded to 2 decimal places)

Next, we use the average range (R-bar) to calculate the control limits for the sample mean chart:

Upper Control Limit (UCL) = X-double bar + A2 * R-bar

Lower Control Limit (LCL) = X-double bar - A2 * R-bar

Where X-double bar is the average of sample means and A2 is a constant based on the sample size (n). For n = 15, A2 is 0.577.

Calculating the average of sample means (X-double bar):

X-double bar = (Sum of sample means) / (Number of samples)

X-double bar = (13.30 + 3.16 + 3.21 + 3.30 + 3.27 + 3.20) / 6

X-double bar ≈ 5.01 (rounded to 2 decimal places)

Calculating the control limits:

UCL = 5.01 + 0.577 * 2.86 ≈ 5.01 + 1.65 ≈ 6.66 (rounded to 2 decimal places)

LCL = 5.01 - 0.577 * 2.86 ≈ 5.01 - 1.65 ≈ 3.36 (rounded to 2 decimal places)

Therefore, the upper and lower limits for the sample mean control chart are:

UCL = 6.66

LCL = 3.36

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In both the U.S.A. and England, there are only two days of the year that share the same symbol: May 2 (5/2) and February 5 (5/2).

In the United States, the symbol 5/2 is interpreted as the 5th month and 2nd day, representing May 2. On the other hand, in England, 5/2 denotes the 5th day and 2nd month, indicating February 5. To determine how many days of the year have the same symbol in both countries, we need to find the dates that match.

In the U.S., there are 12 months, so there are 12 possible combinations with 5 as the month. However, only May 2 (5/2) coincides with the English interpretation.

In England, there are 31 days in January, so there is no match with the American format. However, in February, there are 28 days (or 29 in a leap year), and February 5 (5/2) aligns with the American interpretation.

Hence, there are only two days of the year that share the same symbol in both the U.S. and England: May 2 (5/2) and February 5 (5/2).

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Answer:

72 cm

Step-by-step explanation:

You can solve this problem using the properties of the 45-45-90 right triangle. Assuming the 12 cm is a diagonal of the square, each side of the square can be modeled as x, and the diagonal will be x\(\sqrt{2}\).

This means \(x\sqrt{2} =12\), so  \(x=\frac{12}{\sqrt{2} }\).

Next, to find the area of the square you take the square of any of its sides. Since x is the length of one side, and \(x=\frac{12}{\sqrt{2} }\) , you can square \(\frac{12}{\sqrt{2} }\) to get the area. This is equal to \(\frac{144}{2}\) or 72 cm.

The Standard form of a number is also known as "Scientific notation". The form is:

Where the coefficient "a" is a number from 1 to 10, but not including 10, and the exponent "b" is an Integer. The base is always 10.

By definition, the decimal point must be after the first digit of the coefficient.

In this case, in order to write 36 in Standard form, you must move the decimal point one place to the left:

Notice that the exponent is 1 because you had to move the decimal point one place to the left in order to locate it after the first digit of the coefficient.

Now, to write the exponent form of a number is:

Where the exponent "n" indicates how many times "b" must be multiplied by itself.

You know that:

Then:

The answer is:

a. Exponent form:

b. Standard form:

Answer:

z = 54 − 45. 12.

Step-by-step explanation:

Answer:

D.

Step-by-step explanation:

It is simple. Subtract 7* from 65* to get you 58* F.

Based on common factors, Fatoumata can increase each dimension of the deck by 2 feet so that the deck's new area is increased by 50% to 126 ft².

Common factors are the numbers that can divide another number evenly without a remainder.

In this situation, 9 and 14 can divide 126 equally and the product of 9 and 14 are 126.

The old dimensions of the deck:

Width = 7 feet

Length = 12 feet

Area = 84 ft² (7 x 12)

The expected new area of the deck:

Increase in the new area = 5%

Increased factor for the area = 1.5 (100% + 50%)

Area = 126 ft² (84 x 1.5)

The common factors of 126 include 9 and 14 and the product of 9 and 14 = 126.

Therefore, we can increase each length of the deck by 2 feet.

Check:

Width = 9 feet

Length = 14 feet

Area = 126 ft² (9 x 14)

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Substituting the values in the formula:zx = (11.7 - 7) / 3.522zx = 1.2778 ≈ 1.28Therefore,x = zxσ + μ= (1.28 × 3.522) + 7= 4.512 + 7= 11.512 ≈ 11.7Thus, the values of x and μ are 11.7 and 7 respectively.

Given,Rainforest data:Mean (μ) = 7Standard Deviation (σ) = √12.405 ≈ 3.522For calculating the z-score, we need to find the value of x. And it is given thatzx = (x - μ)/σLet's calculate the value of x using the given data.Z-score formula is defined aszx = (x - μ) / σWhere,zx is the z-score of the given value x.x is the raw data that needs to be standardized to get the z-score.μ is the mean of the data set.σ is the standard deviation of the data set.Substituting the values in the formula:zx = (11.7 - 7) / 3.522zx = 1.2778 ≈ 1.28Therefore,x = zxσ + μ= (1.28 × 3.522) + 7= 4.512 + 7= 11.512 ≈ 11.7Thus, the values of x and μ are 11.7 and 7 respectively.

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The graph of the equation  ​y−2=−3/4(x−6)​ that passes through a point is shown below.

To graph an equation that is given in point-slope form as y - b = m(x - a), determine the values of:

The slope would be the rise over the run of the graph to be made, while the line must pass through the given point.

Given the equation, y−2=−3/4(x−6), the slope of line is m = -3/4, while the point on the line can be (a, b) = (6, 2).

The graph of y−2=−3/4(x−6) is shown below.

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The value of the expression ∛8^5 is 32

The expression is given as:

∛8^5

Express 8 as 2^3

∛8^5 = ∛(2^3)^5

Take the cube root of 2^3

∛8^5 = 2^5

Evaluate 2 exponent 5

∛8^5 = 32

Hence, the value of the expression ∛8^5 is 32

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The crank angle value when the piston is at Top Dead Center (TDC) is 0 radians or 0 degrees. The maximum ratio of the crank radius to the connected length is 0.3.

The crank angle value refers to the angle between the crankshaft and a reference point when measuring the position of the piston. When the piston is at Top Dead Center (TDC), it is at its highest point in the cylinder. The crankshaft is positioned such that the connecting rod is aligned with the crank radius and the piston is at the topmost position. This corresponds to a crank angle value of 0 radians or 0 degrees.

Regarding the maximum ratio of the crank radius to the connected length, this value is given as 0.3. The crank radius is the distance from the center of the crankshaft to the center of the crank pin, and the connected length is the distance from the center of the crank pin to the center of the piston pin. The maximum ratio of 0.3 indicates that the crank radius is 0.3 times the connected length.

It's important to note that these values are specific to the context of the problem statement provided. Different engines or mechanisms may have different values for the crank angle at TDC and the maximum ratio of crank radius to connected length.

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Answer:

900 L

Step-by-step explanation:

after 10 hours : 10*10=100 liters

1000-100=900 liter

is the answer I recived

My work is below:

Next after 10 hours (10*10=100 liters )

1000-100=900 liter

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