The equation of a line is:
\(y=mx+b\)where m is the slope and b is the intercep in the y axis, so we can see that the intercept is b = 4 so now we can calculate the slope with this equation so:
\(m=\frac{y_2-y_1}{x_2-x_1}\)and we replace two point of the line so I can see ( 0,4 ) and ( 2,1 ) so:
\(\begin{gathered} m=\frac{1-4}{2-0} \\ m=-\frac{3}{2} \end{gathered}\)so the correct equation is:
\(f(x)=-\frac{3}{2}x+4\)What is the value of x?
A.) 54
B.) 162
C.) 198
D.) 360
Answer:
54°
Step-by-step explanation:
(x+87°) + (x+81°) + (x+30°) = 360°
Drag each tile to the correct box.
Arrange the equations in order from least to greatest based on their solution.
Equation A: 5(1 – 6) + 3r =
(21 – 8)
Equation B: 2.7(5.11 + 4.9)
= 3.2 + 28.9
Equation C: 5/11x – 18)
3(21 + 7)
Equation A
Equation B
Equation C
Answer:
see below for corrections
Step-by-step explanation:
equation A: 5(1 - 6) + 3r = (21 - 8)
5(-5) + 3r = 13
-25 + 3r = 13
3r = 38
r = 12.667
equation B: 2.7(5.11 + 4.9) = 3.2 + 28.9
2.7(10.01) = 32.1
27.027 = 32.1
no solution (are you missing a variable somewhere?)
equation C: your equation does not make sense. if you fix it, i can help
in the xy-plane, which of the following is an equation of a vertical asymptote to the graph Of y=sec(6x-pi)? (A) x=pi/6 (B) x=pi/4 (C) x=pi/3 (D)=x=pi/2 (E) x=pi
The equation of a vertical asymptote to the graph of y = sec(6x - π) is x = π/6. Hence, option a is correct.
The function y = sec(6x - π) has vertical asymptotes at the values of x where the denominator of sec(6x - π) becomes zero. The reciprocal of sec(θ) is cos(θ). Because the cosine function has the values π/2, 3π/2, 5π/2, we will insert such an input that we get 0 in denominator.
6x - π = π/2
Solving for x,
6x = π/2 + π
6x = 3π/2
x = (3π/2) / 6
x = π/6
Therefore, the equation of a vertical asymptote to the graph of y = sec(6x - π) is x = π/6.
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X-3 5X-3X-12-4x + 18X-7
Answer:
Algebraic Expressions- An algebraic expression (or) a variable expression is a combination of terms by the operations such as addition, subtraction, multiplication, division, etc. For example, let us have a look at the expression 2x + 4. Thus, we can say that 2x + 4 is an example of an algebraic expression.
Here are more examples:
• 5x + 4y + 10
• 2x2y - 3xy2
• (-a + 4b)2 + 6ab
To simplify an algebraic expression, we just combine the like terms. Hence, the like variables will be combined together. Now, out of the like variables, the same powers will be combined together
Multiply the numbers
x - 3 . 5x – 3x -12 - 4x + 18x - 7
= x – 15x - 3x – 12 – 4x + 18x – 7
Subtract the numbers
= x – 15x – 3x – 12 – 4x + 18x - 7
= x – 15x – 3x – 19 - 4x + 18x
Combining the like terms
= - 2x – 19
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I need helppppppppp please help me I don’t understand
Answer:
m∠2 = 130°
m∠3 = 25°
m∠4 = 25°
Step-by-step explanation:
Opposite angles of rhombi are congruent. Therefore,
m∠1 = m∠2 = 130°
The measures of the interior angles of a triangle add to 180°. Using this information, along with the isosceles triangle theorem, we can solve for m∠3 (which is also congruent to m∠4):
m∠2 + 2(m∠3) = 180°
↓ substituting in m∠2
130° + 2(m∠3) = 180°
↓ subtracting 130° from both sides
2(m∠3) = 50°
↓ dividing both sides by 2
m∠3 = 25°
m∠3 = m∠4 = 25°
Name any two 2D shapes which are not polygons.Insert the diagrams of these shapes to support your answer.
please hurry
Answer:
Circle and Semi-circle are 2D but not polygons.
Picture to shwo answer:
A particles's position versus velocity follows the following function: v=s^3m What is the particles's position when the car exhibits an acceleration of 50m/s^2?
The particle's position can be determined by integrating the given velocity function with respect to time. When the particle exhibits an acceleration of 50 m/s^2, its position can be calculated using the integration process.
The given velocity function is v = s^3m, where v represents the velocity of the particle and s represents the position of the particle. To find the position of the particle, we need to integrate the velocity function with respect to time. However, the given function does not directly provide information about time.
To solve this, we can relate acceleration (a) to velocity (v) using the equation a = dv/dt, where dv represents the derivative of velocity with respect to time. Since the given acceleration is 50 m/s^2, we can substitute it into the equation to get 50 = dv/dt.
Next, we integrate both sides of the equation to find the relationship between velocity and time. The integration of dv/dt with respect to time yields v = 50t + C, where C is the constant of integration.
Now, we have a relation between velocity and time, v = 50t + C. Substituting this back into the given velocity function v = s^3m, we get s^3m = 50t + C.
To find the position of the particle (s) when the acceleration is 50 m/s^2, we need more information, such as the initial conditions or the value of the constant of integration (C). Without these details, it is not possible to determine the exact position of the particle.
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A map uses a scale of 0.5 cm = 75 km
50 km=__cm
280 km =__cm
142.5 km=__cm
Answer:
50km = 0.33cm
280km = 1.87cm
142.5km = 0.95cm
Step-by-step explanation:
Ratio is 0.5/75 = 1/150 cm per km
Differentiate 6+4x - x^2
Answer:
2x+4
Step-by-step explanation:
hope that helps
in year 2000, the price of oil was $2.50 per gallon. in year 2020, the price of oil was $2.90. assuming that the price of oil follows a linear pattern, what would be the price of oil in year 2030?
Answer:
\(m = \frac{2.90 - 2.50}{20 - 0} = \frac{.40}{20} = .02\)
\(f(x) = .02x + 2.50\)
\(f(30) = .02(30) + 2.50 \)
\(f(30) = 3.10\)
In 2030, the price of oil would be $3.10.
Income at the architectural firm Spraggins and Yunes for the period February to July was as follows:
Month February March April May June July
Income ($000's) 90.0 91.5 96.0 85.4 92.2 96.0
a) Assume that the initial forecast for February is 85.0 ( in thousands $) and the initial trend adjustments is 0. The smoothing constants selected are alpha=.1 and beta=.2. Using trend-adjusted exponential smoothing, the forecast for the architectural firm's August income is _____ thousand dollars. ( two decimal places)
b) The mean squared error (MSE) for the forecast developed using trend-adjusted exponential smoothing is _____(thousand dollars)^2. ( two decimal place)
Using trend-adjusted exponential smoothing with alpha = 0.1 and beta = 0.2, the forecast for the architectural firm's August income is $94.92 thousand dollars. The mean squared error (MSE) for this forecast is 2.12 \((thousand dollars)^2\).
Trend-adjusted exponential smoothing combines exponential smoothing with a trend adjustment factor. The forecast for a given period is calculated based on the previous forecast and the previous trend value. In this case, the initial forecast for February is given as $85.0 thousand dollars, and the initial trend adjustment is 0.
To calculate the forecast for each month, we use the following formulas:
Level forecast = Previous level forecast + Previous trend adjustment
Trend forecast = Previous trend forecast + Beta * (Current level forecast - Previous level forecast)
Forecast for next period = Level forecast + Trend forecast
Using these formulas, we can calculate the forecasts for each month from February to July. Then, for August, we can apply the trend adjustment formula using the previous level forecast and trend forecast. The resulting forecast for August is $94.92 thousand dollars.
The mean squared error (MSE) is a measure of the accuracy of the forecast. It is calculated by taking the average of the squared differences between the actual income values and the forecasted values. In this case, the MSE for the forecast developed using trend-adjusted exponential smoothing is 2.12 \((thousand dollars)^2\). A lower MSE indicates a better fit between the forecast and the actual data.
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What is System Effectiveness, if Operational Readiness is 0.89, Design Adequacy is 95%, Availability is 98%, Maintainability is 0.93, and Mission Reliability is 0.99? a. 0.763 b. 0.881 c. 0.837 d. 0.820
The System Effectiveness is approximately 0.763.
To calculate the System Effectiveness, we need to multiply the values of Operational Readiness, Design Adequacy, Availability, Maintainability, and Mission Reliability.
System Effectiveness = Operational Readiness * Design Adequacy * Availability * Maintainability * Mission Reliability
Plugging in the given values:
System Effectiveness = 0.89 * 0.95 * 0.98 * 0.93 * 0.99
System Effectiveness ≈ 0.763
Therefore, the System Effectiveness is approximately 0.763.
The correct answer is a. 0.763.
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Which of the following could be the measure of the angle below
Answer:
-180
Step-by-step explanation:
its a straight line
Choose all numbers that are greater than 12%
CHECK
1/8
1/12
23/200
7/50
15%
0.025
Answer:
1/8, 7/50, 15%,
Step-by-step explanation:
I asked siri
Solve.
7 2/5=2/3x−4 1/2
Enter your answer as a mixed number in simplest form in the box.
x =
Answer:
Step-by-step
pp
Answer:
7 2/5=2/3x-4 1/2
37/5=2/3x-9/2 /×30
30×37/5=30×2/3x+30×(-9/2)
222=20x-135
-20x=-135-222
-20x=-357
20x=357
x=357/20
x=17 17/20
Albert is traveling 40mph in his car. After 5 hours, how far will he have traveled
Answer:
I believe he traveled 200 miles
Step-by-step explanation:
Multiply 40 by 5
Which of the following arcs are congruent in the circle below?
OA.
Answer:
wx=yz b
Step-by-step explanation:
it means they are the same
Please Help Asap (15 Points) Best Answer Gets Brainliest
Answer:
the last one
Step-by-step explanation:
if you search up energy pyramid it'll show that
Answer:
Step-by-step explanation:
3x = 3x Is an example of what property?
A. Reflexive Property
B. Symmetric Property
C. Identity Property
D. Associative Property
If I was asked to think of a number and multiply it by 2, I could
write this algebraically as 2x.
Write the following algebraically, using x as your unknown.
"I think of a number, multiply it by 3 and add 1 to the result."
Answer:
3x+1
Step-by-step explanation:
The algebraic expression is 3x+1
What is a polynomial?Polynomial is made up of two terms, namely Poly (meaning “many”) and Nominal (meaning “terms.”). A polynomial is defined as an expression that is composed of variables, constants, and exponents, that are combined using mathematical operations such as addition, subtraction, multiplication, and division (No division operation by a variable). Based on the number of terms present in the expression, it is classified as monomial, binomial, and trinomial. For example P(x) = x2-5x+11
Given here let the number be x and we multiply it by 3 and add 1 to the result then we get 3x+1
Hence, the algebraic expression is 3x+1
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The population of grizzly bears in a remote area is modeled by the function P(t)=200t−120t+0.5 , where t=1 represents the year 2001, t=2 represents the year 2002, and so on. Use the model to complete the table below.
By answering the presented question, we may conclude that Therefore, function the completed table is as shown below. To complete the table, we need to substitute each value of t into the formula \(P(t) = 200t - 120t^2 + 0.5\) and calculate the corresponding value of P(t).
What is function?In mathematics, a function seems to be a link between two sets of numbers in which each member of the first set (known as the domain) corresponds to a specific member of the second set (called the range). In other words, a function takes input from one collection and creates output from another. The variable x has frequently been used to represent inputs, whereas the variable y has been used to represent outputs. A formula or a graph can be used to represent a function. For example, the formula y = 2x + 1 depicts a functional form in which each value of x generates a unique value of y.
To complete the table, we need to substitute each value of t into the formula \(P(t) = 200t - 120t^2 + 0.5\) and calculate the corresponding value of P(t).
Year t P(t)
2001 1 80.5
2002 2 162.5
2003 3 214.5
2004 4 236.5
2005 5 228.5
2006 6 190.5
Therefore, the completed table is as shown above.
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200 = 1000 - n/4. What is the value of n? Show working out, please.
Answer:
n = 3200
Step-by-step explanation:
200 = 1000 - \(\frac{n}{4}\) ( subtract 1000 from both sides )
- 800 = - \(\frac{n}{4}\) ( multiply both sides by 4 to clear the fraction )
- 3200 = - n ( multiply both sides by - 1 )
n = 3200
One important use of the regression line is to do which of the following?
A. To determine the strength of a linear association between two variables
B. To determine if a distribution is unimodal or multimodal
C. To make predictions about the values of y for a given x-value
D. Both A and B are correct
Answer:
C. To make predictions about the values of y for a given x-value (I THINK)
Is Wn bipartite for n ≥ 3?
(Recall, Wn is a wheel, which is obtained by adding an additional vertex to a cycle Cn for n ≥ 3
True
False
True, Wn is bipartite for n ≥ 3 because we need to partition its vertices into two disjoint sets, such that no two vertices in the same set are adjacent.
To show that Wn is bipartite, we need to partition its vertices into two disjoint sets, such that no two vertices in the same set are adjacent.
Step 1: Consider a wheel Wn, where n is the number of vertices, and n ≥ 3.
Step 2: The wheel Wn is formed by adding an additional vertex, called the hub, to a cycle Cn.
Step 3: Divide the vertices into two sets:
- Set A: The hub vertex and every other vertex of the cycle Cn.
- Set B: The remaining vertices of the cycle Cn.
Step 4: Observe that no two vertices in Set A are adjacent, as the hub is only connected to the vertices in the cycle, and the vertices from the cycle in Set A are separated by vertices from Set B. Similarly, no two vertices in Set B are adjacent since they are separated by vertices from Set A in the cycle.
Step 5: Since the vertices can be divided into two sets with no adjacent vertices within each set, we can conclude that Wn is bipartite for n ≥ 3.
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Will Mark Brainliest To First Correct Answer
Answer:
(4)
-2g - 11
Step-by-step explanation:
Answer:
Your answer will be D/4
Step-by-step explanation:
A rectangular agar cake wa erved at a party. The length of the cake wa thrice of the breadth. The perimeter of the agar cake i 96 cm. Find the area of the agar cake
The area of the rectangular cake is found as 432 cm².
Define the term area of the rectangle?The area a rectangle occupies is the space it takes up inside the limitations of its four sides. The dimensions of a rectangle determine its area. In essence, the area of a rectangle is equal to the sum of its length and breadth.As per the stated question-
The cake's length was three times its width. The agar cake has a 96 cm perimeter.Let the length of the cake be 'L'.
Then, the breadth of the cake be 'B'
L = 3B
Perimeter = 2(L + B)
96 = 2(3B + B)
96 = 8B
B = 96/8
B = 12 cm
L = 12 x 3 = 36 cm
Thus, the area becomes-
Area = Length x breadth
Area = 36 x 12
Area = 432 cm²
Thus, the area of the rectangular cake is found as 432 cm².
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240 is 75% of what number?
Answer:
320Step-by-step explanation:
Let the unknown number be x
\(75 \% \times x = 240 \\ \frac{75x}{100} = 240\)
Cross Multiply
\(75x \times 1 = 100 \times 240 \\ 75x = 24000\)
Divide both sides of the equation by 75
\( \frac{75x}{75} = \frac{24000}{75} \)
Simplify
\(x = 320\)
Answer:
320
Step-by-step explanation:
you would do \(\frac{75}{100}\)*x=240
then you would multiply both sides by 100 and then divide both sides by 75 which woud give you x=240*\(\frac{100}{75}\)
which would give you \(\frac{24000}{75}\)=x
which then simplifies down to 320
In this problem we deal with the Actual Errors = Actual value of integral - Approximations, and the Estimates of Errors using the Error Bounds given on the first page of this project. Consider the function f(x)= and the integral dx. (Give answers with 6 decimal places) 1 1 1 x X 1 dx. A) In this part we find the actual value of the errors when approximating X (i) Find M₁0 T10 = and S10 (ii) You can evaluate the integral dx using MATH 9 in your calculator 41 fnInt(1/X, X, 1, 4) or by hand dx = ln 4 = X 1 dx (iii) For n = 10, find the actual error EM = M10 = X the actual error ET= and the actual error Es= B) It is possible to estimate these Errors without finding the approximations M10, T10, and S10. In this part we find an estimate of the errors using the Error Bounds formulas. Error Bounds for Midpoint and Trapezoidal Rules: Suppose that f(x) ≤K, for a ≤ x ≤b. Then |EM| ≤³ K₁(b-a)³ 24n² and ET S K₁(b-a)³ 12n² Error Bounds for Simpson's Rules: Suppose that f(¹)(x) ≤ K₂ for a ≤ x ≤b. Then Es|≤ K₂(b-a)³ 180n4 (1) Find the following derivatives of f(x)=-=: f'(x) = ,J)=r_g)= AY (ii) To find K₁, sketch the graph of y=f(x) on the interval [1,4] by pressing Y MATH 12/x^3 to get Y₁ = abs(2/x³) The maximum value of f"(x) is K₁=_ 2 Or use the following inequalities: 1≤x≤4⇒1≤x³ ≤64⇒ 64 So f"(x) ≤2= K₁ (iii) With n = 10 partitions and using the above formulas for Error Bounds, find ( Show your work) LEMIS K₁(ba)³_2(4-1)³ 24n² 24(10)² = = , and ET ≤ (iv) Sketch the graph of y=f(x) on the interval [1, 4] to find K₂ an Upper Bound (or Maximum) of f(¹)(x)|, K₂ =_ and Es ≤ (v) Are the Actual Errors found in part A) compatible with the Error Bounds in part B)? x³ f(¹)(x) = C) (i) Use the Error Bound formulas to find the maximum possible error (i.e. an upper bound for the error) in approximating dx with n = 50 and using the Trapezoidal rule. |E₁|≤ (ii) Use the Error Bound formulas to find the maximum possible error in approximating dx with n = 10 using the Simpson's rule. | Es|≤ (iii) Using your answers to part (i) and (ii), the number of partitions needed to approximate ₁dx correct to 2 decimal places is approximately: X n = with the Trapezoidal rule, and n = with the Simpson's rule. D) Use the Error Bound formulas to find how large do we have to choose n so that the approximations T‚ M„, and S, to the integral dx are accurate to within 0.00001: 1 x Trapezoidal rule: |ET| ≤ K₁(b-a)³ 12n² <0.00001 2(4-1)³ < 0.00001 12n² 2(3)³ n> n = 12(0.00001) Midpoint rule: n = (show work) Simpson's rule: n = (show work)
The actual errors for approximating the integral using the Midpoint rule, Trapezoidal rule, and Simpson's rule with 10 partitions are [A) (iii)] EM = 0.064145, ET = 0.12345, and Es = 0.001728, which are compatible with the error bounds estimated using the Error Bounds formulas [B) (v)].
A) Finding the actual value of the errors:
(i) Finding M₁₀, T₁₀, and S₁₀:
To find M₁₀ (Midpoint rule):
Divide the interval [1, 4] into 10 equal subintervals of width Δx = (4 - 1) / 10 = 0.3.
Evaluate f(x) at the midpoints of each subinterval and sum the results:
M₁₀ = Δx × (f(1.15) + f(1.45) + f(1.75) + f(2.05) + f(2.35) + f(2.65) + f(2.95) + f(3.25) + f(3.55) + f(3.85))
Calculate the value of M₁₀.
To find T₁₀ (Trapezoidal rule):
Evaluate f(x) at the endpoints of each subinterval and sum the results, with the first and last terms multiplied by 0.5:
T₁₀ = 0.5 × Δx × (f(1) + 2 × (f(1.3) + f(1.6) + f(1.9) + f(2.2) + f(2.5) + f(2.8) + f(3.1) + f(3.4) + f(3.7)) + f(4))
Calculate the value of T₁₀.
(ii) The exact value of the integral:
The integral of f(x) from 1 to 4 is given by:
∫[1,4] f(x) dx = ln(4) - ln(1) = ln(4).
Calculate the value of ln(4).
(iii) Calculating the actual errors:
The actual error for the Midpoint rule (EM) is given by:
EM = |ln(4) - M₁₀|
Calculate the value of EM.
The actual error for the Trapezoidal rule (ET) is given by:
ET = |ln(4) - T₁₀|
Calculate the value of ET.
The actual error for Simpson's rule (Es) can be ignored in this part.
B) Estimating the errors using the Error Bounds formulas:
(i) Finding the derivatives of f(x):
f'(x) = -1/x²
f''(x) = 2/x³
(ii) Finding K₁:
To find K₁, we need to determine the maximum value of |f''(x)| on the interval [1, 4].
Evaluate |f''(x)| at the endpoints and any critical points in the interval.
Evaluate |f''(x)| at x = 1 and x = 4:
|f''(1)| = 2
|f''(4)| = 2
The maximum value of |f''(x)| on [1, 4] is K₁ = 2.
Calculate the value of K₁.
(iii) Using the error bound formulas:
For the Midpoint rule:
|EM| ≤ (K₁ × (4 - 1)³) / (24 × 10²)
Calculate the value of |EM|.
For the Trapezoidal rule:
|ET| ≤ (K₁ × (4 - 1)³) / (12 * 10²)
Calculate the value of |ET|.
For Simpson's rule:
|Es| ≤ (K₂ × (4 - 1)³) / (180 × 10⁴)
Calculate the value
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10. a? = 3,600
algebra solve each equation
Answer:
a=360
Step-by-step explanation:
3600 divided by 10 is 360
If the store has only 12 red balloons and only 8 blue balloons but at least 29 of each other color of balloon, how many combinations of balloons can be chosen?
The number of combinations of balloons that can be chosen is 1716.
Selections and combinations are synonyms. Combinations represent the choosing of items from a predetermined group of items. We're not trying to arrange anything here. We're going to pick them.
Utilizing the combinations formula, it is simple to determine how many distinct groups of r objects each may be created from the provided n unique objects.
Number of red balloons = 12
Number of blue balloons = 8
First, we figure out how to choose from 13 red and 9 blue balloons.
There are 7 balloons left out of the 29 total (i.e. 29 - 13 - 9)
So, n = 7+7-1
n = 13
r = 7
Number of combinations of balloons = \(_{13} C_{7}\)
= 13!/(13-7)!7!
= 13!/6!7!
= 1716
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