Can unit rate represent how much for one unit

Answer:

22.5%

Explanation

% composition = Molar mass of S

------------------------ x 100

Molar mass of Na2SO4

= 32.065

------------ x 100

142

=0.225 x 100

= 22.5%

Answer:

B

Explanation:

The heat of combustion of ethane (C2H6) in kilojoules per mole can be determined by subtracting the sum of the enthalpies of formation of the products from the sum of the enthalpies of formation of the reactants.

The enthalpy of formation is the change in enthalpy when one mole of a compound is formed from its constituent elements in their standard states. By referring to the table of thermodynamic properties, the enthalpies of formation for ethane (C2H6), carbon dioxide (CO2), and water (H2O) can be obtained.

The heat of combustion of ethane can be calculated using the following equation:

ΔHcomb = ΣΔHf(products) - ΣΔHf(reactants)

For the combustion of ethane, the reaction equation is:

C2H6 + 3.5O2 → 2CO2 + 3H2O

Using the enthalpies of formation from the table, the heat of combustion of ethane can be calculated.

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The types of emissions that mostly occur when an isotope undergoes radioactive decay include alpha particles, beta particles, and gamma rays.

The types of emissions that can occur when an isotope undergoes radioactive decay are alpha, beta, and gamma radiation. Alpha particles are made up of two protons and two neutrons and are positively charged. Beta particles are either electrons or positrons, and they are negatively or positively charged, respectively. Gamma radiation is a high-energy electromagnetic radiation that has no charge.

During alpha decay, the nucleus of an atom emits an alpha particle. This changes the atomic number of the element, but not its mass number. Beta decay occurs when a neutron in the nucleus of an atom transforms into a proton and an electron or positron is emitted. This can change the atomic number of the element, but not its mass number. Gamma decay occurs when the nucleus of an atom releases energy in the form of gamma radiation. This does not change the atomic number or mass number of the element.

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To deploy configuration profiles for computers from Jamf Pro, the Apple Push Notification service (APNs) must be available.

APNs is a cloud-based service provided by Apple that enables the secure transfer of data between Apple devices and servers. It is essential for communication between Jamf Pro and Apple devices during the deployment of configuration profiles.

APNs is used to initiate the connection between the devices and Jamf Pro, allowing for the transfer of the configuration profiles. Without APNs, it would be impossible to deploy configuration profiles to Apple devices using Jamf Pro.

Therefore, it is critical to ensure that APNs is available and functioning correctly before attempting to deploy configuration profiles using Jamf Pro.

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extracting energy from nuclear fuels is more expensive than extracting energy from fossil fuels

Answer:

Everyday Examples of Convection

boiling water - When water boils, the heat passes from the burner into the pot, heating the water at the bottom. This hot water rises and cooler water moves down to replace it, causing a circular motion.

Explanation:

Answer:

common sedimentary rocks include sandstone, limestone, and shale.

The compound is C₈H₁₀O. The peak shown at 3000 cm⁻¹ is for C-H and for and -CN group, the peak will be shown as 2250 cm⁻¹.

The IR spectrum is a plot of % transmittance (or absorbance) of the radiation through the molecule as opposed to wave quantity of the radiation. Infrared spectroscopy (IR spectroscopy or vibrational spectroscopy) is the size of the interplay of infrared radiation with count number with the aid of using absorption, emission, or reflection. It is used to have a look at and discover chemical materials or useful corporations in solid, liquid, or gaseous forms. It may be used to signify new substances or discover and confirm acknowledged and unknown samples.

The peak shown at 3000 cm⁻¹ is for C-H and for and -CN group, the peak will be shown as 2250 cm⁻¹.

For cyclic compound, the peak of C-H at sp³ carbon is 2980 cm⁻¹ and for c=o or saturated cyclic six membered ring is 1720 cm⁻¹.

The compound is C₈H₁₀O.

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Answer: plastic

Explanation:

The thermal conductivity of a material is highly depending on composition and structure. Generally speaking dense material such as medals and stone are good conductors of heat while load density substances such as gas and porous installations are poor conductors of heat

Answer:

Or plastic

Explanation:

May be useful................

Answer:

1×10^-14 mol^2dm^-6

Explanation:

Ionic product is defined as the product of the concentrations of ions, each raised to the power specified by its stoichiometric coefficient in a solution. The product of concentrations of H+ and OH- ions in water at a particular temperature is known as ionic product of water. The value of Kw increases with the increase of temperature, i.e., the concentration of H+ and OH- ions increases with increase in temperature. The value of Kw at 25°C is 1 x 10-14.

At any given time, the amount of hydrogen ions and hydroxide ions present in water is extremely small and consequently the concentration of undissociated water molecules is almost unchanged by any minute ionization thus it is considered a constant. The product of the concentration of both hydrogen and hydroxide ions is a constant referred to as the ionic product for water.

Answer:

ALP is an enzyme found throughout the body, but it is mostly found in the liver, bones, kidneys, and digestive system. When the liver is damaged, ALP may leak into the bloodstream. High levels of ALP can indicate liver disease or bone disorders

Answer:

magnesium+ hydrochloric acid is the reactants

Explanation:

the reactants are always in the left and the products are always in the right by

magnesium+hydrochloric acid ⇒ magnesium chloride + hydrogen

by combining magnesium and hydrochloric acid it produces magnesium chloride and hydrogen.

hope this helps..

Answer:

Answer:

time

Explanation:

time can be controlled and set while all the others can't be necessarily controlled

i mean my mom takes all my electronics at night.

The heat transfer rate for each degree Celsius rise is 32656 J.

Heat is transferred between materials in direct physical contact through a process called conduction that involves molecular collisions. A material's thermal conductivity, cross-sectional area, and temperature differential are all directly related to its heat transfer rate. Varies inversely with material thickness. To the question asked:

The heat transfer coefficient Q is:

Q=kA(ΔT/L)

among them,

k = thermal conductivity of material - 52 (W/m K)

Area of ​​the surface of heat flow A:

A = πr²

= 3.14*5*5

A = 78.5 square inches

Temperature difference ΔT = 1 degree Celsius.

Material thickness L = 0.125 inch

set the value.

Q=kA(ΔT/L)

Q = 52*78.5 (1/0.125)

Q = 32656 J

Therefore, the heat transfer coefficient is 32656 J for each degree Celsius increase.

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With every increase in degree Celsius, there is a 32656 J heat transfer cofficient.

Via a process called conduction, which involves molecular collisions, heat is transported between materials that are in direct physical touch. The rate of heat transmission through a material depends on its thermal conductivity, cross-sectional area, and temperature differential. inversely relates to material thickness. To the query posed:

The heat transfer coefficient Q is:

Q=kA(ΔT/L)

k = the thermal conductivity of material - 52 (W/m K)

Area of ​​the surface of heat flow A:

A = πr²

= 3.14*5*5

A = 78.5 square inches

Temperature difference ΔT = 1 degree Celsius.

Material thickness L = 0.125 inch

set the value.

Q=kA(ΔT/L)

Q = 52*78.5 (1/0.125)

Q = 32656 J

Therefore, the heat transfer coefficient is 32656 J for each degree Celsius increase.

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a) Resonance structures showing how the aryl group of trans- anethole stabilizes the intermediate carbocation:

Carbocation (I) gets stabilized by the resonance effect of the aryl group of trans-anethole, which results in intermediate carbocation (II) shown below.

The intermediate carbocation (II) formed has a stabilized aryl group, which makes the intermediate relatively stable and more reactive than the corresponding cation of styrene or vinyl chloride.

b) Based on your results, explain any differences or similarities in the stereochemistry of the bromine addition reactions of trans-cinnamic acid and trans-anethole:

In both the cases of trans-anethole and trans-cinnamic acid, the addition of bromine takes place in a stereospecific way. In trans-anethole, addition takes place with the formation of trans-2,3-dibromoanethole, which is similar to the formation of the anti-addition of bromine in trans-cinnamic acid to form trans, trans-2,3-dibromocinnamic acid. Therefore, both the bromine addition reactions lead to the formation of the corresponding anti-isomers in high yields due to the steric factor involved in the intermediate carbocation formation.

Intermediate carbocation plays a crucial role in this reaction. In the case of trans-anethole, intermediate carbocation gets stabilized by the resonance effect of the aryl group of trans-anethole, which results in a relatively stable intermediate. On the other hand, in the case of trans-cinnamic acid, intermediate carbocation formation occurs at the more substituted carbon atom, which leads to the formation of the anti-isomer. This is because the aryl group gets stabilized by the delocalization of electrons due to its π-electron-rich nature.

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A) The activation energy for the reaction is approximately 96.4 kJ/mol.

B) The frequency factor for the reaction is approximately 2.36 x 10^13 s^-1.

A) To determine the activation energy, we can use the Arrhenius equation ln(k) = -Ea/RT + ln(A), where k is the rate constant, Ea is the activation energy, R is the gas constant, T is the temperature in Kelvin, and A is the frequency factor. By plotting ln(k) versus 1/T, we can calculate the slope, which is equal to -Ea/R.

B) To determine the frequency factor, we can use the Arrhenius equation and solve for A.

C) To determine the rate constant at 15 degrees Celsius, we can use the Arrhenius equation and the values of k, Ea, and A that we have calculated.

D) To calculate the initial rate of the reaction at 85 degrees Celsius, we can use the rate law, which is rate = k[C2H5Br][OH-]. We can plug in the given concentrations and the value of k at 85 degrees Celsius to calculate the rate.

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Based on the characteristics provided, the most likely element that fits this description is sulfur (S), which has 6 valence electrons and an atomic mass of approximately 32 amu

Based on the information provided, let's analyze the statements:

"My family has two fewer valence electrons than the noble gases": Noble gases have a full valence shell, meaning they have a stable configuration with the maximum number of valence electrons. If your family has two fewer valence electrons than the noble gases, it suggests that your family has either 6 valence electrons (Group 16) or 7 valence electrons (Group 17) since noble gases typically have 8 valence electrons.

"I am almost twice as heavy as the lightest element in my group": The lightest element in Group 16 is oxygen (O), with an atomic mass of approximately 16 atomic mass units (amu). If you are almost twice as heavy as oxygen, your atomic mass would be around 32 amu.

Considering both statements, it appears that your family belongs to Group 16 (Group VI) of the periodic table, and you are an element with 6 valence electrons and an atomic mass close to 32 amu. Based on these characteristics, the most likely element that fits this description is sulfur (S), which has 6 valence electrons and an atomic mass of approximately 32 amu.

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Answer:

D

Explanation:

molecules have potential energy and kinetic energy.

Tempreture is defined as the average kinetic energy and internal energy is PE+KE. Pptential energy in particles or molecules is just there position relative to one another. A gas which has seperated particles will have a greater potential energy than a solid/liquid.

The carbon dioxide reacts with water to form carbonic acid (H2CO3).Carbon dioxide is an odorless, colorless gas produced when organic matter is burned, breathed, fermented, or decayed.

Carbon dioxide is emitted into the atmosphere when fossil fuels are burned. It is necessary for photosynthesis in plants, and it is absorbed by the ocean, acting as a carbon sink.

CO2 (carbon dioxide) is a chemical compound that consists of one carbon atom and two oxygen atoms. It is a colorless, odorless gas with a slightly acidic taste.

Carbon dioxide reacts with water to form carbonic acid (H2CO3), which is represented by the following chemical equation:CO2 (carbon dioxide) + H2O (water) ⇌ H2CO3 (carbonic acid)

The reaction of carbon dioxide with water leads to the formation of carbonic acid (H2CO3). Carbonic acid is a weak acid that can further dissociate into bicarbonate ions (HCO3-) and hydrogen ions (H+).

This reaction is an important process in various natural and industrial systems, such as the dissolution of carbon dioxide in oceans, the carbonation of beverages, and the regulation of blood pH in living organisms.

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The standard entropy change, ΔS°, for reaction 1 (C(graphite) + O\(^{2}\)(g) → CO\(^{2}\)(g)) is predicted to be positive. The standard entropy change, ΔS°, for reaction 2 (2 CO(g) + O\(^{2}\)(g) → 2 CO\(^{2}\)(g)) is expected to be close to zero or very small.

To determine whether the standard entropy change, ΔS°, is positive or negative for each of the given reactions, we can consider some general principles.

Reaction 1: C(graphite) + O\(^{2}\)(g) → CO\(^{2}\)(g)

In this reaction, solid graphite (C) reacts with gaseous oxygen (O\(^{2}\)) to form gaseous carbon dioxide (CO\(^{2}\)). The reactants are in different states of matter compared to the products. Generally, when a substance changes from a solid to a gas, its entropy increases. Additionally, the number of gas molecules increases from one molecule of O\(^{2}\) to one molecule of CO\(^{2}\), which also tends to increase entropy. Therefore, based on these factors, we can predict that the standard entropy change, ΔS°, for reaction 1 is positive.

Reaction 2: 2 CO(g) + O\(^{2}\)(g) → 2 CO\(^{2}\)(g)

In this reaction, gaseous carbon monoxide (CO) reacts with gaseous oxygen (O\(^{2}\)) to form gaseous carbon dioxide (CO\(^{2}\)). The reactants and products are all in the gaseous state. Since there is no change in the states of matter, we need to consider the change in the number of moles of gas molecules. The reactants consist of three gas molecules (2 CO + 1 O\(^{2}\)), while the products also consist of three gas molecules (2 CO\(^{2}\)). Therefore, there is no net change in the number of gas molecules. Consequently, the standard entropy change, ΔS°, for reaction 2 is expected to be close to zero or very small.

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Answer: D

Explanation:

electrons have no mass

According to the given statement these two changes have in common in Both are only chemical changes.

The correct option is C.

Chemical changes happen when bonds among atoms or molecules are formed, broken, or both. This suggests that a substance is transformed from one with a particular set of characteristics (such melting point, color, flavor, etc.) into one with a different set of characteristics.

The majority of our energy is produced by chemical reactions. Many different types of materials are tested, identified, and analyzed using chemical reactions (such as pool testing kits and forensic tests from TV shows like "CSI").

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Answer:

Mechanical Energy, Thermal Energy, By Feeding Them Food, Light Energy, Electromagnetic Energy, it's right on Edge

Explanation:

Answer:

1. mechanical energy, 2. thermal energy, 3. by feeding them food, 4. light energy 5. electromagnetic energy

Explanation:

got it right on edg ;))

Answer:

Boiling of pure water is not a chemical reaction.

It is a physical change from liquid state to gaseous state.

Explanation:

We know that,

acceleration (a) = final velocity(V)-initial velocity(U)/ Time taken(T)

Electron and molecular geometries, respectively, for hydrogen sulfide H₂S is electron geometry is linear and molecular geometry is bent

Molecular geometry is the three dimensional arrangement of atom that constitute a molecule and there are two lone pair present on the sulfur central atom in the H₂S molecule hence it will contract the bond pair and this make its shape appear like a bent structure and therefore the molecular geometry or shape of H₂S is bent while its electron geometry is tetrahedral because of four electron group around the sulfur

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Answer:

electronegativity increases