Can u help me thanks so
Much ❤️

During the collision between the bike and the truck, the two objects will experience forces and accelerations. The force of the collision will be the result of the difference between the momentum of the two objects before and after the collision. The momentum of an object is the product of its mass and velocity, represented as p = mv.

Before the collision, the bike has a momentum of 20 kg * 10 m/s = 200 kg m/s to the right and the truck has a momentum of 3,000 kg * -20 m/s = -60,000 kg m/s to the left.

After the collision, since the truck has a much greater mass than the bike, it will experience a much smaller change in momentum than the bike, and the final velocities of the two objects will be close to the initial velocity of the truck.

So, the force of the collision will be the difference between the initial momentum of the bike and truck and the final momentum of the bike and truck. This force will be acting on the bike, causing it to experience an acceleration. The truck will experience a force as well, but it will be much smaller in magnitude because of its much larger mass.

Therefore, the best statement that describes the forces and accelerations involved during the collision is: The bike experiences a large force during the collision, causing it to experience a large acceleration, while the truck experiences a smaller force and acceleration due to its much larger mass.

Answer:

How do you find the net force?

Explanation:

i think this is want you asked for?

Explanation:

c because there is element

Answer:

C. H2 and N2 would react to produce more NH3

Explanation:

A.P.E.X

Answer:

Explanation:

Wavelength = 100m. Speed = V. 2.) Frequency = 20 Hz. Wavelength = 200 m. Speed = ... 2=1.7m. F=Y/2 f=2×10. 5.) Wavelength = 502 km. Speed= 100 m/s.

The earth-atmosphere energy balance is achieved as the energy from the Sun is the same as the energy lost by the Earth. Thus, the correct option is C.

The Earth-atmosphere energy balance refers to the balance between the energy the Earth receives from the sun and the energy the Earth radiates back into space.

The earth-atmosphere energy balance is achieved as the energy received from the Sun balances the energy lost by the Earth's surface back into space. Through this mechanism, the Earth maintains a stable average temperature and therefore also a stable climate on the planet.

Therefore, the correct option is C.

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Complete Question

Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the electric field strength between them, if the potential 8.00 cm from the zero volt plate(and 2.00 cm from the other) is 450 V?

Answer:

\(V'=562.5v\)

Explanation:

From the question we are told that:

Separation distance \(d=10cm\)

Voltage at 8cm \(V_8=450v\)

Generally the equation for Voltage is mathematically given by

\(|V|=|E.d|\)

Where

E=electric field

Therefore

At \(d=0.8\)

 \((450-0)V=E*(0.08m)\)

 \(E=\frac{450}{0.08}\)

 \(E=5625v/m\)

Therefore

 At \(d=10\)

 \(V'=Ed\)

 \(V'=5625*0.1m\)

 \(V'=562.5v\)

Answer:

A 5.00- kg block is placed on top of a 10.0 -kg block (Fig. P5.68). A horizontal force of 45.0 N is applied to the 10.0-kg block, and the 5.00- kg block is tied to the wall. The coefficient of kinetic friction between all surfaces is 0.200. (a) Draw a free-body diagram for each block and identify the action-reaction forces between the blocks.

(b) Determine the tension in the string and the magnitude of the acceleration of the 10.0-kg block.

The horizontal acceleration of the block is 5 m/s².

To calculate the horizontal acceleration on the block, we use the formula below.

Formula:

Where:

Make "a" the subject of the equation.

Substitute these values into equation 2

Substitute these values into equation 2

Hence the horizontal acceleration of the block is 5 m/s².

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Explanation:

- Charge = 60c

time = 30 sec

current

Current = Charge/time

I = V/T

I = 60/30

I = 2 ampere

More to know -

I = Current

V = Charge

T = Time

Answer:

For a given system, there can be particular transformations for which the explicit equations of motion are the same for both the old and new variables. Transformations for which the equations of motion are invariant, are called invariant transformations. It will be shown that if the Lagrangian does not explicitly contain a particular coordinate of displacement  qi, then the corresponding conjugate momentum,  pi, is conserved. This relation is called Noether’s theorem which states “For each symmetry of the Lagrangian, there is a conserved quantity".

Answer:

1. U=mgh

2. 200 (if u use mgh (m is mass g is gravitational field strength and h is height) it will be 2×10×10)

3. k= 1/2mv2 the third one

4. 100 J

5. Heat (property of heat is to be released to the lower concentration area)

1. \(mgh\)  \\

2. \(200 Joules \)\\

3. \(\frac{1}{2} mv^{2} \) \\

4. \(100 Joules\)\\

5. \(heat\)

To solve this problem, we will use Newton's second law of motion.

Newton's second law states that the force is equal to mass times acceleration.

Hence, the formula is as follows:Force = mass x acceleration

To calculate the force, we need to know the mass of the cart and the acceleration at which it is being towed.

As per the question, the cart's mass is 400 kg, and it is being accelerated at a rate of 3 m/s^2.

Hence, the force required to accelerate the cart can be calculated as follows:

Force = mass x acceleration \(Force = 400 kg\times3 m/s^2\)

\(Force = 1200 N\)

Therefore, the tension in the rope is 1200 N.

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The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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The y component of the vector is 37.7 N and the angle between the vectors is 26.2⁰.

The y component of the vector will be determined from the resultant vector and the x component of the vector.

R² = Y² + X²

Y² = R² - X²

Where;

Y² = 85.2² - 76.4²

Y² = 1,422.08

Y = √1,422.08

Y = 37.7 N

θ = arc tan (Y/X)

θ = arc tan (37.7/76.4)

θ = 26.2⁰

Thus, the y component of the vector is 37.7 N and the angle between the vectors is 26.2⁰.

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Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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Answer:

2 Pascal (Pa)

Explanation:

Pressure is defined as the force acting per unit area. Mathematically, it is expressed as:

Pressure (P) = Force (F) / Area (A)

Given:

Force exerted by the air inside the balloon (F) = 1 N

Area of the balloon (A) = 0.5 m^2

Plugging in the given values into the formula for pressure, we get:

P = F / A

P = 1 N / 0.5 m^2

Using basic arithmetic, we can calculate the pressure inside the balloon:

P = 2 N/m^2

So, the pressure inside the balloon is 2 N/m^2, which is also commonly referred to as 2 Pascal (Pa) since 1 Pascal is equal to 1 N/m^2.

Answer:

(a) The ratio of the pressure amplitude of the waves is 43.21

(b) The ratio of the intensities of the waves is 0.000535

Explanation:

Given;

density of gas, \(\rho _g\) = 2.27 kg/m³

density of liquid, \(\rho _l\) = 972 kg/m³

speed of sound in gas, \(C_g\) = 376 m/s

speed of sound in liquid, \(C_l\) = 1640 m/s

The of the sound wave is given by;

\(I = \frac{P_o^2}{2 \rho C} \\\\P_o^2 = 2 \rho C I\\\\p_o = \sqrt{2 \rho CI}\)

Where;

\(P_o\) is the pressure amplitude

\(P_o_g= \sqrt{2 \rho _g C_gI} -------(1)\\\\P_o_l= \sqrt{2 \rho _l C_lI}---------(2)\\\\\frac{P_o_l}{P_o_g} = \frac{\sqrt{2 \rho _l C_lI}}{\sqrt{2 \rho _g C_gI}} \\\\\frac{P_o_l}{P_o_g} = \sqrt{\frac{2 \rho _l C_lI}{2 \rho _g C_gI} }\\\\ \frac{P_o_l}{P_o_g} = \sqrt{\frac{ \rho _l C_l}{ \rho _g C_g} }\\\\ \frac{P_o_l}{P_o_g} = \sqrt{\frac{ (972)( 1640)}{ (2.27)( 376)} }\\\\\frac{P_o_l}{P_o_g} = 43.21\)

(b) when the pressure amplitudes are equal, the ratio of the intensities is given as;

\(I = \frac{P_o^2}{2 \rho C}\\\\I_g = \frac{P_o^2}{2 \rho _g C_g}-------(1)\\\\I_l = \frac{P_o^2}{2 \rho _l C_l}-------(2)\\\\\frac{I_l}{I_g} = (\frac{P_o^2}{2 \rho _l C_l})*(\frac{2\rho_gC_g}{P_o^2} )\\\\\frac{I_l}{I_g} = \frac{\rho _gC_g}{\rho_lC_l} \\\\\frac{I_l}{I_g} = \frac{(2.27)(376)}{(972)(1640)}\\\\ \frac{I_l}{I_g} = 0.000535\)

The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

The formula for acceleration due to gravity is:

g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet

In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.

Therefore, g is proportional to 1/r².

So, using the ratio of radii given (1.8), we can write:

r = 1.8 x r Earth, where r Earth is the radius of Earth.

Substituting this value of r in the formula for acceleration due to gravity, we get:

g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²

We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².

Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:

gh = (1/3.24) x g Earth = 3.02 m/s²

Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

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Answer:a car with 1,000kg

Explanation: A car with a mass of 1,000kg has more inertia than 150 kg

Out of the two objects a 1000-kilogram car and a 150-kilogram golf cart, the 1000-kilogram cart will have more inertia as the inertia of any object is directly proportional to its mass.

According to Newton's first law, until pushed to alter its condition by the intervention of an external force, every object will continue to be at rest or in uniform motion along a single direction.

The larger the mass of the object, the greater would be the inertia of the object.

Thus, a 1000-kilogram automobile will have higher inertia than a 150-kilogram golf cart since any object's inertia is directly proportionate to its mass.

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Answer:

A) f = 1.28x10¹⁵ Hz

B) y = 0.20 m

Explanation:

A) The frequency of light can be found as follows:

\( f = \frac{c}{\lambda} \)

Where:

c: is the speed of light = 3.0x10⁸ m/s

λ: is the wavelength

The wavelength can be calculated using the following equation:

\( sin(\theta) = \frac{\lambda(m - 1/2)}{d} \)

Where:

m = 3, d = 6 μm, θ = 5.6°        

\( \lambda = \frac{d*sin(\theta)}{m - 1/2} = \frac{6 \cdot 10^{-6} m*sin(5.6)}{3 - 1/2} = 2.34 \cdot 10^{-7} m \)      

Now, the frequency is:

\( f = \frac{c}{\lambda} = \frac{3.0 \cdot 10^{8} m/s}{2.34 \cdot 10^{-7} m} = 1.28 \cdot 10^{15} Hz \)    

Hence, the frequency of light used for this experiment is 1.28x10¹⁵ Hz.

B) The distance between the second bright fringe and central fringe (y) is:

\( tan(\theta) = \frac{y}{D} \)        

\( y = D*tan(\theta) = 2 m*tan(5.6) = 0.20 m \)

Therefore, the distance between the second bright fringe and central fringe is 0.20 m.

I hope it helps you!

Speed of the rock at the bottom of the cliff is 44.3 m/s.

Kinetic energy of the rock at the bottom of the cliff is 4915 J.

Work done by air resistance is -2250 J

Average force exerted by the air on the rock is 11.25 N.

a) The speed of the rock at the bottom of the cliff can be calculated using the equation:

v = √(2gh)

where v = final velocity, g = acceleration due to gravity (9.81 m/s²), and h = height of the cliff (200 m).

Plugging in the values:

v = √(2 x 9.81 x 200) = 44.3 m/s

Therefore, the speed of the rock at the bottom of the cliff is 44.3 m/s.

b) The kinetic energy of the rock at the bottom of the cliff can be calculated using the equation:

KE = (1/2)mv²

where KE = kinetic energy, m = mass of the rock (5 kg), and v = velocity (44.3 m/s).

Plugging in the values:

KE = (1/2) x 5 x (44.3)² = 4915 J

Therefore, the kinetic energy of the rock at the bottom of the cliff is 4915 J.

c) The work done by air resistance can be calculated using the work-energy principle:

Work done by air resistance = KE_initial - KE_final

where KE_initial = initial kinetic energy of the rock, and KE_final = final kinetic energy of the rock (at terminal velocity).

Since the rock was initially at rest, its initial kinetic energy is zero. At terminal velocity, the kinetic energy of the rock is:

KE_final = (1/2)mv_terminal²

where m = mass of the rock (5 kg), and v_terminal = terminal velocity (30 m/s).

Plugging in the values:

KE_final = (1/2) x 5 x (30)² = 2250 J

Therefore, the work done by air resistance is:

Work done by air resistance = 0 - 2250 = -2250 J

The negative sign indicates that the work done by air resistance is in the opposite direction to the motion of the rock.

d) The average force exerted by the air on the rock can be calculated using the equation:

Work done by air resistance = Force x Distance

where Force = average force exerted by air on the rock, and Distance = distance travelled by the rock.

Rearrange the equation to solve for Force:

Force = Work done by air resistance / Distance

Plugging in the values:

Force = -2250 / 200 = -11.25 N

Therefore, the average force exerted by the air on the rock is 11.25 N. The negative sign indicates that the force is in the opposite direction to the motion of the rock.

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Answer:

a)  P = 807.85 N,  b)  P = 392.15 N,  c)  P = 444.12 N

Explanation:

For this exercise, let's use Newton's second law, let's set a reference frame with the x-axis parallel to the plane and the direction rising as positive, and the y-axis perpendicular to the plane.

Let's use trigonometry to break down the weight

         sin θ = Wₓ / W

         cos θ = W_y / W

         Wₓ = W sin θ

         W_y = W cos θ

         Wₓ = 1200 sin 30 = 600 N

          W_y = 1200 cos 30 = 1039.23 N

Y axis  

      N- W_y = 0

      N = W_y = 1039.23 N

Remember that the friction force always opposes the movement

a) in this case, the system will begin to move upwards, which is why friction is static

       P -Wₓ -fr = 0

       P = Wₓ + fr

as the system is moving the friction coefficient is dynamic

      fr = μ N

      fr = 0.20 1039.23

      fr = 207.85 N

we substitute

       P = 600+ 207.85

       P = 807.85 N

b) to avoid downward movement implies that the system is stopped, therefore the friction coefficient is static

        P + fr -Wx = 0

       fr = μ N

       fr = 0.20 1039.23

        fr = 207.85 N

we substitute

        P =  Wₓ -fr

        P = 600 - 207,846

        P = 392.15 N

c) as the movement is continuous, the friction coefficient is dynamic

         P - Wₓ + fr = 0

         P = Wₓ - fr

         fr = 0.15 1039.23

         fr = 155.88 N

         P = 600 - 155.88

         P = 444.12 N

There are multiple questions in your prompt, so let's break them down one by one.

How much gravitational potential energy does the goat gain?

The gravitational potential energy gained by the goat can be calculated using the formula:

GPE = mgh

where m is the mass of the goat, g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the cliff.

Substituting the given values, we get:

GPE = 50 kg x 9.8 m/s^2 x 450 m

GPE = 220500 J

Therefore, the goat gains 220500 J of gravitational potential energy.

How much gravitational potential energy does Evan gain?

The gravitational potential energy gained by Evan can be calculated using the same formula as above:

GPE = mgh

where m is the mass of Evan (including his parachute gear), g is the acceleration due to gravity, and h is the height of the jump.

Substituting the given values, we get:

GPE = 90 kg x 9.8 m/s^2 x 2.0 m

GPE = 1764 J

Therefore, Evan gains 1764 J of gravitational potential energy.

How much kinetic energy does the goat have just before it hits the ground?

The conservation of energy principle tells us that the total energy of the system (in this case, the goat) remains constant. So, the kinetic energy gained by the goat just before it hits the ground is equal to the gravitational potential energy it had at the top of the cliff. Therefore, the kinetic energy of the goat just before it hits the ground is:

KE = GPE = 220500 J

Note that we have assumed that there is no loss of energy due to air resistance or other factors during the goat's fall.

How much GPE does Evan gain given: h = 2.0 m

We have already calculated the gravitational potential energy gained by Evan earlier. Using the same formula, we get:

GPE = mgh

GPE = 90 kg x 9.8 m/s^2 x 2.0 m

GPE = 1764 J

What is the kinetic energy of the aircraft at a height of 5000.00 m?

We cannot calculate the kinetic energy of the aircraft with the given information. The kinetic energy of an object depends on its mass and velocity, but we only have information about its height. If we assume that the aircraft is stationary at a height of 5000.00 m, then its kinetic energy would be zero.

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The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.

Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.

The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:

P = ρgh + Po

where:

P is the absolute pressure at the given depth

ρ is the density of the water

g is the acceleration due to gravity (assumed to be 9.81 m/s²)

h is the depth of the ocean

Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)

Substituting the given values, we get:

P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa

P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa

P = 1.002 x 10^8 Pa.

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Answer:

Solar energy? Solar rays? Solar Power?

Explanation:

not too sure what you mean, its kinda in the sentence. lmk if you need any help however

Answer:

Solar system is the energy output from the sun

By Solving for ϕ, we found that one possible value for ϕ is approximately 1.29 radians.

To find the value of ϕ in the equation x(t) = xmcos(ωt + ϕ), you need to know the values of x, xm, and ω.

The angular frequency ω is given by the formula:

ω = √(k/m)

where k is the spring constant and m is the mass of the object on the spring.

Plugging in the values, we get:

ω = √(7.83 N/m / 0.18 kg) = 13.47 rad/s

The maximum displacement xm is equal to the amplitude of the oscillation, which is 12 cm = 0.12 m.

At t = 0.225 s, the mass is at x = 4.53 cm = 0.0453 m.

We can now use the equation x(t) = xmcos(ωt + ϕ) to find the value of ϕ:

0.0453 m = 0.12 mcos(13.47 rad/s * 0.225 s + ϕ)

Solving for ϕ, we find that one possible value for ϕ is approximately 1.29 radians.

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The magnitude of the displacement is 1,097.7 mi, and the angle is 89.9°

To find the displacement from Dallas to Chicago, we can break down the vectors representing the distances and directions into their x and y components. Since the Earth is modeled as flat, we can use basic trigonometry to calculate the components.

Let's start by considering the vector from Dallas to Atlanta. The magnitude of this vector is given as 730 miles, and the direction is 5.00° north of east. To calculate the x and y components, we can use the following equations:

Substituting the values:

x = 730 * cos(5.00°)

y = 730 * sin(5.00°)

Similarly, for the vector from Atlanta to Chicago, with a magnitude of 560 miles and a direction 21.0° west of north:

x = magnitude_AC * sin(angle_AC)

y = magnitude_AC * cos(angle_AC)

Substituting the values:

x = 560 * sin(21.0°)

y = 560 * cos(21.0°)

To find the displacement from Dallas to Chicago, we can sum the x and y components:

Now, we can calculate the magnitude and direction of the displacement using these x and y components:

magnitude_displacement = √(x_displacement² + y_displacement²)

angle_displacement = atan(y_displacement / x_displacement)

Finally, we can substitute the calculated values and solve for the magnitude and direction:

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Acceleration is the change in velocity over time. We can calculate the acceleration of the bicyclist during the time 2.0 s to 5.0 s using the formula acceleration = (final velocity - initial velocity) / time.

The initial velocity of the bicyclist at 2.0 s is 2.0 m/s and the final velocity at 5.0 s is 8.0 m/s. The time interval between 2.0 s and 5.0 s is 3.0 s.

Substituting these values into the formula, we get acceleration = (8.0 m/s - 2.0 m/s) / 3.0 s = 6.0 m/s / 3.0 s = 2.0 m/s^2.

So, the acceleration of the bicyclist during the time 2.0 s to 5.0 s was 2.0 m/s^2.

Answer:

mass and distance

Explanation:

mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.