Can the following list of entries L be sorted by the stable Radix-Sort using a bucket array (N=15)? And why? L = (1,2), (3,2), (2,12), (3,3), (12,3), (15,1), (2,2), (1,7), (13,12)

Answers

Answer 1

Answer:

Yes, the given list of entries L can be sorted by using a stable Radix-Sort with a bucket array of size 15. In Radix-Sort, the numbers are sorted digit by digit for each element in the list. In this case, each element in the list has two digits, so we will perform two passes through the list.

On the first pass, we will sort the list by the second digit (the ones place). This will result in the following intermediate list:

(1,2), (3,2), (15,1), (2,2), (3,3), (12,3), (2,12), (1,7), (13,12)

Note that the order of the elements with equal second digits is preserved, as required for a stable sort.

On the second pass, we will sort the list by the first digit (the tens place). This will result in the final sorted list:

(1,2), (1,7), (2,2), (2,12), (3,2), (3,3), (12,3), (13,12), (15,1)

Again, note that the relative order of the elements with equal first digits is preserved, because we used a stable sorting algorithm.

Therefore, we can use a stable Radix-Sort with a bucket array of size 15 to sort the given list of entries L.

Explanation:


Related Questions

one of the unresolved problems of flood forecasting is the precise determination of how often a flood (having a given discharge) can be expected to occur. because only a small percentage of all the streams in the united states have been gaged for more than a few decades. it is difficult to determine, for exampie, the loq-year or soo-year flood. consider the data below, which is the instantaneous peak discharge ior rapid creek in rapid city, south dakota, in each of forty-three years of record:
Water Year Discharge (m3/s)
1951 4.05
1952 73.6
1953 4.30
1954 3.90
1955 9.23
1956 3.68
1957 12.3
1958 2.29
1959 2.32
1960 2.32
1961 2.82
1962 37.1
1963 5.41
1964 7.59
1965 17.4
1966 3.96
1967 12.4
1968 5.61
1969 3.94
1970 6.94
1971 10.9
1972 885.0
1973 4.9
1974 14.6
1975 2.61
1976 18.0
1977 5.49
1978 12.3
1979 4.75
1980 3.37
1981 3.74
1982 7.48
1983 8.01
1984 7.05
1985 3.79
1986 2.52
1987 2.80
1988 3.57
1989 3.14
1990 3.51
1991 5.69
1992 2.97
1993 9.29
a. Included in the data is the exceptionally large flood of 1972, which killed 238 people in the Rapid City area, Based simply on the number of years of record and the fact that 1972 flood occurred one time during this interval, how often would a flood of this magnitude be expected?
b. The simplistic approach described above can be improved by a mathematical treatment such as shown in Table 8.2 and Figure 8.20. Using the graph paper below, plot a recurrence curve for the Rapid Creek flood data. [ Hint: Suggest that an eyeball, best fit, straight line plotted through the points, except ignore the 1972 flood. Assume that, because of its magnitude, the 1972 flood does not nicely conform to the rest of the data, and as such. Can be ignored.] What is the 100 year flood discharge?
c. What is the recurrence interval of the 1972 flood, using the curve thus drawn?
d. Given the range of values from a and c above, what can be stated relative to the frequency of floods as large as the one which occurred in 1972?y-three years of record:
Water Year Discharge (m3/s)
1951 4.05
1952 73.6
1953 4.30
1954 3.90
1955 9.23
1956 3.68
1957 12.3
1958 2.29
1959 2.32
1960 2.32
1961 2.82
1962 37.1
1963 5.41
1964 7.59
1965 17.4
1966 3.96
1967 12.4
1968 5.61
1969 3.94
1970 6.94
1971 10.9
1972 885.0
1973 4.9
1974 14.6
1975 2.61
1976 18.0
1977 5.49
1978 12.3
1979 4.75
1980 3.37
1981 3.74
1982 7.48
1983 8.01
1984 7.05
1985 3.79
1986 2.52
1987 2.80
1988 3.57
1989 3.14
1990 3.51
1991 5.69
1992 2.97
1993 9.29
a. Included in the data is the exceptionally large flood of 1972, which killed 238 people in the Rapid City area, Based simply on the number of years of record and the fact that 1972 flood occurred one time during this interval, how often would a flood of this magnitude be expected?
b. The simplistic approach described above can be improved by a mathematical treatment such as shown in Table 8.2 and Figure 8.20. Using the graph paper below, plot a recurrence curve for the Rapid Creek flood data. [ Hint: Suggest that an eyeball, best fit, straight line plotted through the points, except ignore the 1972 flood. Assume that, because of its magnitude, the 1972 flood does not nicely conform to the rest of the data, and as such. Can be ignored.] What is the 100 year flood discharge?
c. What is the recurrence interval of the 1972 flood, using the curve thus drawn?
d. Given the range of values from a and c above, what can be stated relative to the frequency of floods as large as the one which occurred in 1972?

Answers

a. Based on the 43 years of record and the fact that the 1972 flood occurred once during this interval, it can be estimated that a flood of this magnitude would be expected to occur once every 43 years, on average.

b. Using the graph paper, plot a recurrence curve for the Rapid Creek flood data. Ignoring the 1972 flood, an eyeball, best fit, and a straight line should be plotted through the points. The 100-year flood discharge can be determined by looking at the point on the graph which is at the 100-year recurrence interval.

c. The recurrence interval of the 1972 flood, using the curve drawn, can be determined by looking at the point on the graph which is nearest to the 1972 flood discharge.

d. Given the range of values from a and c above, it can be stated that floods as large as the one which occurred in 1972 are rare events and occur infrequently.

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Fill in the blank to output the quotient of dividing 100 by 42. print (100______42)​

Answers

Answer:

print(100/42)

Explanation:

This is the operand for division in python and some other languages.

When a branch circuit supplies an air conditioning system that consists of a hermetic motor-compressor and other loads, the circuit rating must not exceed ____ percent of the hermetic motor load plus the sum of the additional loads.

Answers

When a branch circuit supplies an air conditioning system consisting of a hermetic motor-compressor and other loads, the circuit rating must not exceed 125 percent of the hermetic motor load plus the sum of the additional loads.

This requirement is in place to ensure that the branch circuit can handle the increased demand placed on it by the air conditioning system without overloading or posing a safety risk. The hermetic motor-compressor is a crucial component of the air conditioning system, responsible for compressing the refrigerant and ensuring proper cooling. The additional loads may include components like fans, controls, and other auxiliary equipment.

By sizing the circuit to accommodate 125 percent of the hermetic motor load plus the sum of the additional loads, the electrical system is safeguarded against potential issues such as overheating, short circuits, or damage to the equipment. Following this guideline helps maintain efficient operation and prolongs the life of the air conditioning system.

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how hardness of mineral can be identify​

Answers

Answer:

ANS DOWN BELOW! PLS MARKN AS BAINLIEST

Explanation:

hardness of a mineral is determined by observing whether its surface is scratched by a substance of known or defined hardness.

Can someone tell me what car year and model this is please

Can someone tell me what car year and model this is please

Answers

Answer:

i think 1844

Explanation:

2005 BMW 5 Series , that should be it

(2pts) In _______________, the pulse amplitude is made proportional to the amplitude of the modulating signal. pulse-amplitude modulation (PAM) pulse-position modulation (PPM) pulse-code modulation (PCM) pulse-width modulation (PWM)

Answers

Answer:

  (a)  pulse-amplitude modulation (PAM)

Explanation:

It should be no surprise that pulse amplitude is modulated in pulse-amplitude modulation (PAM).

cubical tank 1 meter on each edge is filled with water at 20 degrees C. A cubical pure copper block 0.46 meters on each edge with an initial temperature of 100 degrees C is quickly submerged in the water, causing an amount of water equal to the volume of the smaller cube to spill from the tank. An insulated cover is placed on the tank. The tank is adiabatic. Estimate the equilibrium temperature of the system (block + water). Be sure to state all applicable assumptions.

Answers

Answer:

final temperature = 26.5°

Explanation:

Initial volume of water is 1 x 1 x 1 = 1 \(m^{3}\)

Initial temperature of water = 20° C

Density of water = 1000 kg/\(m^{3}\)

volume of copper block = 0.46 x 0.46 x 0.46 = 0.097 \(m^{3}\)

Initial temperature of copper block = 100° C

Density of copper = 8960 kg/\(m^{3}\)

Final volume of water = 1 - 0.097 = 0.903 \(m^{3}\)

Assumptions:

since tank is adiabatic, there's no heat gain or loss through the wallsthe tank is perfectly full, leaving no room for cooling airtotal heat energy within the tank will be the summation of the heat energy of the copper and the water remaining in the tank.

mass of water remaining in the tank will be density x volume = 1000 x 0.903 = 903 kg

specific heat capacity of water c = 4186 J/K-kg

heat content of water left Hw = mcT = 903 x 4186 x 20 = 75.59 Mega-joules

mass of copper will be density x volume = 8960 x 0.097 = 869.12 kg

specific heat capacity of copper is 385 J/K-kg

heat content of copper Hc = mcT = 869.12 x 385 x 100 = 33.46 Mega-joules

total heat in the system = 75.59 + 33.46 = 109.05 Mega-joules

this heat will be distributed in the entire system

heat energy of water within the system = mcT

where T is the final temperature

= 903 x 4186 x T = 3779958T

for copper, heat will be

mcT = 869.12 x 385 = 334611.2T

these component heats will sum up to the final heat of the system, i.e

3779958T + 334611.2T = 109.05 x \(10^{6}\)

4114569.2T = 109.05 x \(10^{6}\)

final temperature T = (109.05 x \(10^{6}\))/4114569.2 = 26.5°

What should you do if you encounter a fishing boat while out in your vessel?.

Answers

Answer:

if you encounter fishing or hunting boats while you are paddling, be courteous.

Give them a wide berth.

Never run overfishing lines. Be aware that anglers may have lines out to the sides of their boat or trolling behind them.

Explanation:

Determine (a) the principal stresses and (b) the maximum in-plane shear stress and average normal stress at the point. Specify the orientation of the element in each case. 60 45 30

Answers

Answer:

a) 53 MPa,  14.87 degree

b) 60.5 MPa  

Average shear = -7.5 MPa

Explanation:

Given

A = 45

B = -60

C = 30

a) stress P1 = (A+B)/2 + Sqrt ({(A-B)/2}^2 + C)

Substituting the given values, we get -

P1 = (45-60)/2 + Sqrt ({(45-(-60))/2}^2 + 30)

P1 = 53 MPa

Likewise P2 = (A+B)/2 - Sqrt ({(A-B)/2}^2 + C)

Substituting the given values, we get -

P1 = (45-60)/2 - Sqrt ({(45-(-60))/2}^2 + 30)

P1 = -68 MPa

Tan 2a = C/{(A-B)/2}

Tan 2a = 30/(45+60)/2

a = 14.87 degree

Principal stress

p1 = (45+60)/2 + (45-60)/2 cos 2a + 30 sin2a = 53 MPa

b) Shear stress in plane

Sqrt ({(45-(-60))/2}^2 + 30) = 60.5 MPa

Average = (45-(-60))/2 = -7.5 MPa

A 13 kg rock sits on a spring with a spring constant of 23,000 N/m. The spring has a natural length of 1.2 meters.
a. If the spring is oriented horizontally, how much must the spring be compressed so that the rock will be traveling at 35 mph when it leaves contact with the spring?
b. If the spring is oriented vertically, how high will the rock get above the ground if the spring is compressed by 0.5 meters before the rock is released from a resting position?
c. If the rock is dropped vertically onto the spring (with the bottom of the spring on the ground) from a height of 14 meters above ground, how far will the spring compress before the rock stops moving? This is harder than it first appears and you should end up solving a quadratic equation.

Answers

a. To find the compression of the spring needed to launch the rock horizontally at 35 mph, we can use conservation of energy. The potential energy stored in the compressed spring is equal to the kinetic energy of the rock when it leaves the spring:

1/2 k x^2 = 1/2 m v^2

where k is the spring constant, x is the compression distance, m is the mass of the rock, and v is the velocity of the rock.

Converting the velocity to meters per second:

35 mph = 15.6 m/s

Plugging in the values and solving for x:

1/2 (23,000 N/m) x^2 = 1/2 (13 kg) (15.6 m/s)^2

x = sqrt[(13 kg) (15.6 m/s)^2 / (23,000 N/m)] = 0.263 m

Therefore, the spring must be compressed by 0.263 meters.

How high will the rock get above the ground if the spring is compressed by 0.5 meters before the rock is released from a resting position?

b. To find the maximum height the rock will reach when the spring is oriented vertically, we can again use conservation of energy. The potential energy stored in the compressed spring is converted into gravitational potential energy of the rock when it leaves the spring:

1/2 k x^2 = m g h

where g is the acceleration due to gravity and h is the maximum height reached by the rock.

Plugging in the values and solving for h:

1/2 (23,000 N/m) (0.5 m)^2 = (13 kg) (9.8 m/s^2) h

h = (1/2) (23,000 N/m) (0.5 m)^2 / (13 kg) (9.8 m/s^2) = 0.605 m

Therefore, the rock will reach a height of 0.605 meters above the ground.

c. To find the compression distance when the rock is dropped onto the spring from a height of 14 meters, we need to consider both the potential energy of the rock and the energy absorbed by the spring. When the rock hits the spring, it will come to a stop, so all of its initial potential energy will be converted into potential energy stored in the compressed spring:

m g h = 1/2 k x^2

where h is the initial height of the rock and x is the compression distance of the spring.

Plugging in the values and solving for x, we get a quadratic equation:

1/2 (23,000 N/m) x^2 - (13 kg) (9.8 m/s^2) (14 m) = 0

Simplifying and solving for x using the quadratic formula:

x = sqrt[(13 kg) (9.8 m/s^2) (14 m) / (23,000 N/m)] = 0.473 m

Therefore, the spring will compress by 0.473 meters before the rock comes to a stop.

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a. To find the compression of the spring needed to launch the rock horizontally at 35 mph, we can use conservation of energy. The potential energy stored in the compressed spring is equal to the kinetic energy of the rock when it leaves the spring:

1/2 k x^2 = 1/2 m v^2

where k is the spring constant, x is the compression distance, m is the mass of the rock, and v is the velocity of the rock.

Converting the velocity to meters per second:

35 mph = 15.6 m/s

Plugging in the values and solving for x:

1/2 (23,000 N/m) x^2 = 1/2 (13 kg) (15.6 m/s)^2

x = sqrt[(13 kg) (15.6 m/s)^2 / (23,000 N/m)] = 0.263 m

Therefore, the spring must be compressed by 0.263 meters.

How high will the rock get above the ground if the spring is compressed by 0.5 meters before the rock is released from a resting position?

b. To find the maximum height the rock will reach when the spring is oriented vertically, we can again use conservation of energy. The potential energy stored in the compressed spring is converted into gravitational potential energy of the rock when it leaves the spring:

1/2 k x^2 = m g h

where g is the acceleration due to gravity and h is the maximum height reached by the rock.

Plugging in the values and solving for h:

1/2 (23,000 N/m) (0.5 m)^2 = (13 kg) (9.8 m/s^2) h

h = (1/2) (23,000 N/m) (0.5 m)^2 / (13 kg) (9.8 m/s^2) = 0.605 m

Therefore, the rock will reach a height of 0.605 meters above the ground.

c. To find the compression distance when the rock is dropped onto the spring from a height of 14 meters, we need to consider both the potential energy of the rock and the energy absorbed by the spring. When the rock hits the spring, it will come to a stop, so all of its initial potential energy will be converted into potential energy stored in the compressed spring:

m g h = 1/2 k x^2

where h is the initial height of the rock and x is the compression distance of the spring.

Plugging in the values and solving for x, we get a quadratic equation:

1/2 (23,000 N/m) x^2 - (13 kg) (9.8 m/s^2) (14 m) = 0

Simplifying and solving for x using the quadratic formula:

x = sqrt[(13 kg) (9.8 m/s^2) (14 m) / (23,000 N/m)] = 0.473 m

Therefore, the spring will compress by 0.473 meters before the rock comes to a stop.

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how many dfma principals are used in concurrent engineering

Answers

Answer:

aqswdefrtghyujkijuhygtfrdesw

Explanation:

five principles
From the Prodevent project we learn that there are five principles that can be used in a well designed production (order phase), (figure 15). These principles can be used when designing the production system in the Concurrent Engineering. Hope this helps :)

normally counters are retentive. this means that if your accumulated count is up to 300 and power to your system is lost, when power is restored the a

Answers

The correct answer is when retentive power is restored the accumulated count will be 300.

PLC counters are normally retentive; that is, whatever count was contained in the counter at the time of a proces- sor shutdown will be restored to the counter on power-up. The counter may be reset, however, if the reset condition is activated at the time of power restoration.A counter instruction is an input instruction. A counter's input signal can come from an external device such as a sensor. Up and down counters may be programmed together to count up and down. Counters can count past their preset values.

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the lift experienced by a helicopter involves an action-reaction pair of forces between the

Answers

The lift experienced by a helicopter involves an action-reaction pair of forces between the rotor blades and the air.

As the rotor blades rotate, they push air downwards, creating a force known as thrust. According to Newton's third law of motion, for every action, there is an equal and opposite reaction. In this case, the action is the thrust force created by the rotor blades pushing air downwards, and the reaction is the lift force that is generated as a result. This lift force is what allows the helicopter to rise into the air and stay airborne. Therefore, the lift experienced by a helicopter is a result of the action-reaction pair of forces between the rotor blades and the air.

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All of these are part of the seat belt assembly EXCEPT the:
O latch plate
O D-ring
O retractor.
O cushion

Answers

Answer: Cushion
Explanation: All parts going together to form a seat belt except the cushion
The answer is the last one: cushion

Find the value of P(-1.5≤Z≤2)

Answers

Answer:

  0.9104

Explanation:

Suitable technology can tell you the probability.

P(-1.5≤Z≤2) ≈ 0.9104

__

A phone app gives the probability as 0.9104426667829628.

Find the value of P(-1.5Z2)

Anyone help me please ?

Anyone help me please ?

Answers

Answer:

I can help but I need to know what it looking for

Steam enters and leaves a horizontal 1D pipe steadily at a constant speed with the specific enthalpy to be 4000 kJ/kg and 1500 kJ/kg respectively. Assuming a mass flow rate of 0.5 kg/sec and If there is no significant change in potential energy from inlet to exist, determine the rate of heat transfer between the pipe and its surroundings.

Answers

Answer:

The rate of heat transfer between pipe and its surrounding is found to be 1250 KW

Explanation:

Assuming no significant change in potential energy. When we apply the first law of thermodynamics to the given system of 1-D pipe, we get the following expression:

Q = m(h₁ - h₂)

where,

Q = Heat Transfer between pipe and surrounding = ?

m = mass flow rate of steam = 0.5 kg/sec

h₁ = Specific Enthalpy of steam at entrance = 4000 KJ/kg

h₂ = Specific Enthalpy of steam at exit = 1500 KJ/kg

Therefore, using these values in the equation, we get the value of heat transfer:

Q = (0.5 kg/sec)(4000 KJ/kg - 1500 KJ/kg)

Q = 1250 KW

Which of the following is useful for actually resolving moral controversies rather than merely classifying them?

Answers

Answer: you forgot to add the rest of the Questions in.

The energy transferred between objects at different temperatures a.temperatureb.thermal energyc.heat

Answers

The energy transferred between objects at different temperatures is called heat. Heat is a form of energy that flows spontaneously from hotter objects to cooler objects until thermal equilibrium is achieved. This transfer of energy occurs due to the difference in temperature between the two objects and the thermal energy stored within them.

Thermal energy refers to the total energy stored within a substance due to the motion of its atoms and molecules. When two objects of different temperatures are brought into contact, the atoms and molecules in the hotter object transfer some of their thermal energy to the cooler object through the process of heat transfer.

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based on these s-n curves, would you expect ductile cast iron to fail under cyclic loading of 200 mpa for 109 cycles?

Answers

Based on these s-n curves, it is difficult to say for certain whether or not ductile cast iron would fail under cyclic loading of 200 MPa for 109 cycles.

The s-n curves provide information on the fatigue strength of a material under different levels of stress and cycles of loading. However, other factors such as the specific composition and microstructure of the ductile cast iron, as well as any potential defects or flaws in the material, can also play a role in determining its fatigue life. Therefore, it would be important to consider additional information and testing data specific to the ductile cast iron in question in order to make a more accurate prediction about its potential failure under cyclic loading of 200 MPa for 109 cycles.
Based on the given S-N curves, ductile cast iron is expected to fail under cyclic loading of 200 MPa for 10^9 cycles. The S-N curves help to predict the fatigue life of a material under cyclic loading, and in this case, it indicates that ductile cast iron would not be able to withstand 200 MPa stress for 10^9 cycles.

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Based on the given S-N curves, the ductile cast iron fail under cyclic loading of 200 MPa for 10^9 cycles if the curve shows that the stress level of 200 MPa exceeds the endurance limit for ductile cast iron at that specific number of cycles.

To determine this, follow these steps:

1. Locate the S-N curve for ductile cast iron.
2. Find the 10^9 cycles point on the horizontal axis (number of cycles).
3. Trace a vertical line upward from the 10^9 cycles point until it intersects the S-N curve.
4. Read the corresponding stress value on the vertical axis (stress amplitude) at the intersection point.
5. Compare the stress value from the S-N curve to the given cyclic loading of 200 MPa.

If the stress value from the S-N curve is lower than 200 MPa at 10^9 cycles, it indicates that ductile cast iron would likely fail under cyclic loading of 200 MPa for 10^9 cycles. If the stress value is higher than 200 MPa, ductile cast iron is expected to withstand the cyclic loading without failure.

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a relationship between two nominal variables is summarized by a contingency table. t/f

Answers

True. a relationship between two nominal variables is summarized by a contingency table.

A contingency table is a way to summarize and display the relationship between two nominal variables. It organizes the data into rows and columns, with each cell representing the frequency or count of observations that fall into a specific combination of categories for the two variables. Contingency tables are commonly used in statistical analysis, especially in fields such as social sciences, market research, and epidemiology, to examine the association or dependency between categorical variables.

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An air-cooled condenser that is operating in a climate that has four distinct seasons must ____.a. have some type of head pressure controlb. use a water regulating valvec. have a multi-circuit evaporatord. operate with zero degrees of sub-cooling

Answers

An air-cooled condenser operating in a climate with four distinct seasons must have some type of head pressure control. This is because the varying temperatures and weather conditions throughout the year can significantly affect the performance and efficiency of the condenser.

Head pressure control is essential to maintain the proper functioning and reliability of the refrigeration system, regardless of external temperature fluctuations.

Head pressure control ensures that the pressure and temperature within the condenser remain at optimal levels for efficient heat transfer and proper refrigerant flow. By adjusting the airflow or condensing surface area, the control system can maintain a consistent pressure differential across the system, preventing issues such as reduced cooling capacity, compressor damage, or system failure.

Water regulating valves, multi-circuit evaporators, and operating with zero degrees of sub-cooling are not necessarily required for an air-cooled condenser in a four-season climate. While these components can improve the performance or efficiency of certain refrigeration systems, they are not essential for maintaining proper head pressure control in an air-cooled condenser subjected to varying seasonal conditions.

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Merchandise without an expiration date like electronics, tools and home goods typically have a longer

Answers

Answer:

Shelf life.

Explanation:

In Business, an inventory is a term used to describe a list of finished goods, goods still in the production line and raw materials that would be used for the manufacturing of more goods in a bid to meet the unending consumer demands.

Simply stated, an inventory can be classified into three (3) main categories; finished goods, work in progress, and raw materials.

An inventory is recorded as a current asset on the balance sheet because it's primarily the most important source of revenue for a business entity.

Also, the three (3) main cost concept associated with an inventory are;

1. First In First Out (FIFO).

2. Last In First Out (LIFO).

3. Weighted average cost.

Shelf life can be defined as a measure of the length of time that a particular product could be kept or stored without it getting bad or becoming unsuitable for use by the consumers. Thus, the shelf life of a product is largely dependent on its expiration date.

Hence, merchandise without an expiration date like electronics, tools and home goods typically have a longer shelf life.

A cube of edge 4 inches is cut by a plane containing 2 diagonally opposite edges
of the cube find the area of the section formed.

Answers

Answer:

 So its area A = 4 * 4sqrt(2) = 16sqrt(2) inches^2

Explanation:

In order to find the area of the section, we need to find the length of one of the diagonals.

Using the Pythagorean Theorem, a^2 + b^2 = c^2, we pick any side of the cube which in

itself is a square with sides 4 inches each.  The length of the diagonal of the square is

2(4^2) = c^2  or c = 4sqrt(2).

To calculate the area of the section, we must first determine the length of one of the diagonals. Using the Pythagorean Theorem, \(\bold{a^2 + b^2 = c^2}\), one selects any side of the cube which in its a square with four-inch sides.

The diagonal of a square has a length:

           \(\to 2(4^2) = c^2 \\\\ \to c = 4\sqrt{(2)}\)

A section is now a rectangle with sides 4 and \(4\sqrt{(2)}\). So its area

      \(\to A = 4 \times 4\sqrt{(2)} = 16\sqrt{(2)}\ inches^2\)

Therefore, the answer is "\(\bold{ 16\sqrt{(2)}\ inches^2}\)".

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Sadie is the props manager for a small community theater. Because she does not have a part onstage, Sadie is not part of the Performing Arts pathway of the Arts, AV Technology and Communication cluster.


True


False

Answers

Answer:

I think it is false!

Explanation:

Answer: I think it's true

Explanation:

Because if you were part of a play, you would have a part but if you work on props, you don't have a part onstage.


Q. Text-styling feature of MS word is
A. WordColor
B. WordFont
C. WordArt
D. WordFill

Answers

Answer:

C. WordArt

Explanation:

WordArt feature of MS word is used for styling the text n order to make it look neater or more noticeable. These features are found in the top home menu. They feature text size, text style, text color, and options to make text bold, italic, underlined, etc. There are also many features to make text flashy, colorful, and add special effects. It can be shaded, neon, have shadows, etc.

Braking hard will help with the recovery from the skid. A.) TRUE B.) FALSE.

Answers

The statement Braking hard will help with the recovery from the skid is false.

Braking hard is not the appropriate action to recover from a skid.

In fact, braking hard can often exacerbate the skid and make it more difficult to regain control of the vehicle.

When a vehicle skids, it means that the tires have lost traction with the road surface.

In such a situation, sudden or excessive braking can cause the wheels to lock up, leading to further loss of control and potentially causing the vehicle to slide even more.

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what do you need to craft netherite ingots come on man you should know this

Answers

4 netherite scrap and 4 gold

in a crafting table

An oil pump is drawing 18 kW of electric power while pumping oil with density 860 kg/m3 at a rate of 0. 1 m3/s. The inlet and outlet diameters of the pipe are 8 cm and 13 cm, respectively. If the pressure rise of oil in the pump is measured to be 250 kPa and the motor efficiency is 95 percent, determine the mechanical efficiency of the pump

Answers

The mechanical efficiency of the pump is approximately 138.9%.

To determine the mechanical efficiency of the pump, we need to calculate the actual power delivered to the oil being pumped and compare it to the power input from the electric motor.

Calculate the work done by the pump:

The work done by the pump can be calculated using the formula:

Work = Pressure Rise * Volume Flow Rate

Given:

Pressure Rise = 250 kPa = 250,000 Pa

Volume Flow Rate = 0.1 m^3/s

Work = 250,000 Pa * 0.1 m^3/s = 25,000 N·m/s = 25,000 W

Calculate the actual power delivered to the oil:

The actual power delivered to the oil is the work done divided by the time taken:

Actual Power = Work / Time = Work

Given that the pump is drawing 18 kW of electric power, which represents the input power, we can calculate the mechanical efficiency:

Mechanical Efficiency = (Actual Power / Input Power) * 100

Actual Power = 25,000 W

Input Power = 18,000 W (18 kW)

Mechanical Efficiency = (25,000 W / 18,000 W) * 100 = 138.9%

Therefore, the mechanical efficiency of the pump is approximately 138.9%.

The mechanical efficiency represents the efficiency with which the pump converts the input power into useful work to pump the oil. In this case, the mechanical efficiency is greater than 100% because the actual power delivered to the oil (25,000 W) exceeds the input power from the electric motor (18,000 W). This could be due to factors such as measurement errors, losses, or inefficiencies in the system.

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A ___ is a device that has a stand leg piped to the top and bottom of a boiler or other pressure vessel.

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A bridle is a device that has a stand leg piped to the top and bottom of a boiler or other pressure vessel.

The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure. In comparison to the surrounding pressure, gauge pressure is the pressure. Pressure is expressed using a variety of units. Usually, pressure is expressed as a force per unit of surface area. The SI unit for measuring pressure is the pascal, and the sign for pressure in physical science is pa. One Newton per square meter of force exerted perpendicularly on a surface is equal to one pascal. In order to assess the product's consistency and quality, it's critical to collect precise data. For these reasons, precise sensors are essential for gathering this data.

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