CAN SOMEONE PLEASE HELP ME WITH THISSSS! Please.
If you have a liquid with a density of 14.2 g/ml and is 84.5g, what is the volume?

There are two equations which are true. They are 1.5 - k/5 = 11.5 and K/10 -3 = -8.

Given,

The equations;

The value of k = -50

We have to solve the given equations using k as -50 and find the true ones;

Lets check;

1.5 - (-50/5) = 11.5

1.5 - (-10) = 11.5

1.5 + 10 = 11.5

11.5 = 11.5

This equation is true.

(-2 x -50) + 78 = -22

100 + 78 = -22

178 ≠ -22

This equation is false

(-4 x -50) + 80 = -120

200 + 80 = -120

280 ≠ -120

This equation is false

(6 x -50) - 150 = -150

-300 - 150 = -150

-450 ≠ -150

This equation is false

(-50/10) - 3 = -8

-5 - 3 = -8

-8 = -8

This equation is true.

That is,

There are two equations which are true. They are 1.5 - k/5 = 11.5 and K/10 -3 = -8.

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Answer:

y = 12x + 10

Step-by-step explanation:

The equation of the line in slope-intercept form is y = 12x + 10.

The slope or gradient of a line in mathematics is a numerical representation of the steepness and direction of the line.

If a line passes through two points (x₁ ,y₁) and (x₂, y₂) ,

then the equation of line is

y - y₁ = (y₂- y₁) / (x₂ - x₁) x (x - x₁)

To find the slope;

m =  (y₂- y₁) / (x₂ - x₁)

The slope-intercept form of a linear equation is given by y = mx + b, where m is the slope and b is the y-intercept.

Given that the slope is 12 and the y-intercept is 10, we have:

y = 12x + 10

Therefore, the equation of the line in slope-intercept form is y = 12x + 10.

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With Alpha set to .05, increasing the sample size would not directly reduce the probability of a Type I error. The probability of a Type I error is determined by the significance level (Alpha) and remains constant regardless of the sample size.

However, increasing the sample size can indirectly affect the probability of a Type I error by increasing the statistical power of the test. With a larger sample size, it becomes easier to detect a statistically significant difference between groups, reducing the likelihood of falsely rejecting the null hypothesis (Type I error).

Increasing the sample size generally decreases the probability of a Type II error, which is failing to reject a false null hypothesis. With a larger sample size, the test becomes more sensitive and has a higher likelihood of detecting a true effect if one exists, reducing the likelihood of a Type II error. However, it's important to note that other factors such as the effect size, variability, and statistical power also play a role in determining the probability of a Type II error.

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Answer:

Example 1:

Given that y varies proportionally with x , with a constant of proportionality k=1/3 , find y when x=12 .

Write the equation of the proportional relationship.

The variable x varies proportionally with y with a constant of proportionality equal to 1/3

So, y=1/3x

Substitute the given x value.

y=1/3×12

y=4

Step-by-step explanation:

hope it helps

If f: rn → rm is a linear map, then its derivative is simply the map itself. This is because a linear map is a function that preserves vector addition and scalar multiplication.

In other words, if we take two vectors in the domain and add them together, and then apply the linear map, it is the same as applying the linear map to each vector separately and then adding the results. Similarly, if we multiply a vector in the domain by a scalar and then apply the linear map, it is the same as multiplying the result of applying the linear map to the original vector by the same scalar.
Formally, we can express this idea using the concept of a Jacobian matrix. The Jacobian matrix of a function describes the rate at which the function changes near a particular point. For a linear map, the Jacobian matrix is simply the matrix that represents the map. This means that the derivative of f is the matrix A such that f(x) = Ax for all x in rn.
To see why this makes sense, consider the simplest case of a linear map from R1 to R1, given by f(x) = ax, where a is a constant. The derivative of this function is f'(x) = a, which is just the constant coefficient of the linear map. More generally, the derivative of a linear map f: rn → rm is the matrix A such that f(x) = Ax for all x in rn.

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Step-by-step explanation:

I'm not sure but he if he puts 14 Apples a day in hot water for 3 hours, I got 90÷14

which was 6 RM 6 which means he out 14 apples in hot water 6 times and he remains with 6 apples(I don't know what he does with those) but since he puts 14 apples 6 times for 3 hours multiply 6×3=18 hours again, I'm not sure if this is correct at all but I hope I at least triggered something that you can think of?

The statement that best describes the composition of most foods is: "They contain mixtures of the three energy nutrients, although only one or two may predominate."

Most foods contain mixtures of the three energy nutrients, namely carbohydrates, proteins, and fats. However, the relative proportions of these nutrients can vary significantly from one food to another. In some foods, one or two of these nutrients may predominate, while others may contain relatively equal amounts of all three.

Carbohydrates are a primary source of energy for the body and can be found in various forms such as sugars, starches, and fibers. Foods like grains (e.g., rice, wheat, oats), fruits, vegetables, and legumes tend to be rich in carbohydrates. However, the specific types and amounts of carbohydrates can vary widely.

Proteins are crucial for building and repairing tissues, as well as for various metabolic functions. Foods like meat, poultry, fish, eggs, dairy products, legumes, nuts, and seeds are excellent sources of protein. Again, the protein content in different foods can vary.

Fats, also known as lipids, are an important energy source and provide essential fatty acids. Foods such as oils, butter, avocados, nuts, and fatty meats are high in fats. Like carbohydrates and proteins, the fat content in foods can differ significantly.

It's worth noting that some foods may predominantly consist of one specific nutrient. For example, pure sugar is almost entirely composed of carbohydrates, while pure oil is almost entirely composed of fats. However, most whole foods, such as fruits, vegetables, grains, meats, and dairy products, contain a mixture of these energy nutrients.

Furthermore, a balanced diet typically includes a combination of these nutrients in appropriate proportions. A varied diet that incorporates a range of foods from different food groups helps ensure an adequate intake of carbohydrates, proteins, and fats, along with other essential nutrients required for optimal health.

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According to the statement the integral is (x² - 10x - 6) ln |x³ + 8x| - (2/3) ln |x³ + 8x| ln |x³ - 8| - (2/3) ln (x² + (8/3)) - (2/3) Li2(|x³ - 8|) + C.

Integration by parts is a useful technique for solving integrals where one factor differentiates while the other integrates. The formula for integration by parts is as follows:∫u dv = uv - ∫v duwhere u and v are functions of x.∫ (x² - 10x - 6) / (x³ + 8x) dxLet u = x² - 10x - 6 and dv = (x³ + 8x)-1dxSo, du = 2x - 10dx and v = ln |x³ + 8x|Using the formula, we get:∫u dv = uv - ∫v du= (x² - 10x - 6)ln |x³ + 8x| - ∫ ln |x³ + 8x| (2x - 10)dx

We can integrate the second term using substitution, where t = x³ + 8x and dt/dx = 3x² + 8. Then dx/dt = 1/(3x² + 8). Therefore, dx = dt/(3x² + 8).∫ ln |x³ + 8x| (2x - 10)dxLet t = x³ + 8x =⇒ dt/dx = 3x² + 8=⇒ dx/dt = 1/(3x² + 8)∫ ln |t| (2x - 10) dx∫ ln |t| (2x - 10) (dt/(3x² + 8))= ∫ ln |t| (2t/ (t - 8)) (1/(3x² + 8)) dtLet u = ln |t| and dv = (2t/ (t - 8)) (1/(3x² + 8))dtSo, du = (1/t)dt and v = (2/3) ln |t - 8| - (2/3) ln (x² + (8/3))

Using the formula, we get:∫u dv = uv - ∫v du= (2/3) ln |t| ln |t - 8| - (2/3) ln (x² + (8/3)) - ∫(2/3) ln |t - 8| (1/t) dt∫u dv = uv - ∫v du= (2/3) ln |t| ln |t - 8| - (2/3) ln (x² + (8/3)) - (2/3) Li2(|t - 8|) + C∫ (x² - 10x - 6) / (x³ + 8x) dx= (x² - 10x - 6) ln |x³ + 8x| - (2/3) ln |x³ + 8x| ln |x³ - 8| - (2/3) ln (x² + (8/3)) - (2/3) Li2(|x³ - 8|) + C.

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Answer:

y = 47

Step-by-step explanation:

y = 5x + 7

Since x is equal to 8, replace the x in the equation with 8 and solve.

y = 5(8) + 7

y = 40 + 7

y = 47

Answer: ( 8,47 )

Step-by-step explanation: took the quiz

Answer:

comparing the means of three or more groups

Step-by-step explanation:

Step-by-step explanation:

Ariana and Mackenzie exercised for 20 minutes more than Brinley and Seth.

x = Seth exercise minutes

Ariana minutes = 3x

Brinley minutes = 3x - 17

Mackenzie minutes = 1/2 × (3x - 17)

so, in total we have

3x + ½(3x - 17) = x + (3x - 17) + 20

statement 1 is true.

6x + (3x - 17) = 2x + 2(3x - 17) + 40

6x + 3x - 17 = 2x + 6x - 34 + 40

9x - 17 = 8x + 6

x = 23

statement 2 is false.

Brinley and Seth exercised together for

x + 3x - 17 = 23 + 3×23 - 17 = 4×23 - 17 = 75 minutes

statement 3 is false.

Mackenzie exercised for

½(3x - 17) = ½(3×23 - 17) = ½(69 - 17) = ½×52 = 26 minutes

statement 4 is true.

Answer:

-14

Step-by-step explanation:

-8 = 3/2 x 4 + ?

-8 = 6 + ?

-8 - 6 = -14

Your answer will be -14.

Have an amaizng day!!

Please rate and mark brainliest!!

Answer:

I love algebra anyways

The ans is in the picture with the  steps how i got it

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

The mass of lamina with density ρ = k is ka² and the center of mass is (a/2 , a/2)

The center of the mass can be described by determining the moment about x , y and z axis letter lemma cover a reason R of the plane with density function ρ(x , y) to find the center of mass we compute the following:

Mass , Moment about X axis, Moment about y axis and Centre of mass(x,y)

Given vertices of the triangle are (0, 0), (0, a), (a, a)

(a)  ρ = k

Mass of the lamina :

\(mass = \int\limits^a_0 \int\limits^a_0{k} \, dy dx \\= \int\limits^a_0 [ky]^a_0 dx\\= \int\limits^a_0 ka dx\\= [kax]^a_0\\= ka^2\)

Moments ,

\(M_x= \int\limits^a_0 \int\limits^a_0{ky} \, dy dx \\= \int\limits^a_0 [ky^2/2]^a_0 dx\\= \int\limits^a_0 ka^2/2 dx\\= [kax^2/2]^a_0\\= ka^3/2\)

\(M_y= \int\limits^a_0 \int\limits^a_0{kx} \, dy dx \\= \int\limits^a_0 [kx^2/2]^a_0 dy\\= \int\limits^a_0 ka^2/2 dy\\= [kay^2/2]^a_0\\= ka^3/2\)

Center of mass :

\((\bar{x} , \bar{y}) = (\frac{M_y}{m} , \frac{M_x}{m})\\= > (\frac{\frac{ka^3}{2}}{ka^2} , \frac{\frac{ka^3}{2}}{ka^2} )\\= > (\bar{x} , \bar{y}) = (\frac{a}{2} , \frac{a}{2})\)

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Answer:

22

Step-by-step explanation:

Hey There!

So if you didn't know angle H is a right angle. So we are given two angles and they want us to find the missing angle

Remember all of the angles of a triangle add up to equal 180

so we subtract the given angles from 180 to find the missing angle

180-90-68=22

so we can conclude that angle G = 22

Answer:4

Step-by-step explanation:22-4=18-4=14-4=10-4=6=2

The two positive real numbers with a product of 11 that have the smallest possible sum are √11 and √11. In decimal form, these numbers are approximately 3.3166 and 3.3166.

To determine two positive real numbers whose product is 11 and have the smallest possible sum, we can use the concept of the arithmetic mean-geometric mean inequality.

Let the two numbers be x and y.

We have the following conditions:

1. xy = 11 (product of the two numbers is 11)

2. x > 0, y > 0 (both numbers are positive)

According to the AM-GM inequality, the arithmetic mean of two numbers is always greater than or equal to the geometric mean of those numbers.

Using this inequality, we have:

(x + y)/2 ≥ √(xy)

Substituting the value of xy as 11, we get:

(x + y)/2 ≥ √11

To minimize the sum (x + y), we need to make it as close as possible to the right side of the inequality.

This occurs when equality holds, that is, when:

x = y = √11

So, the answer is approximately (3.3166, 3.3166).

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Answer: 4

Step-by-step explanation:

Answer:

The last one (f) hope u still have time

The equation of motion for a medium can be given as gvi = p fit (x+p) √3, i5 + ß vi, Ĵ5. In this equation, the known constants are p, g, ß, and Ĵ5. The components of the stress tensor & or a continuum are given as ti^= x Sij dkk +2ß dij depending on the strain tensor.

We have to show that the equations of motion for this medium can be written in the above form.Let us consider the stress tensor's divergence to derive the equations of motion for this medium.

According to the principle of conservation of mass, the divergence of the stress tensor is equal to the force density, which is given by the following equation:ti^,j = fjHere, the comma indicates partial differentiation. Therefore, the force density is given as:f = tii,j = x Sij,k dkk,j + 2ß dij,j = x (∂Sij/∂xi + ∂Sij/∂xj) dkk + 2ß ∂dij/∂xjThe equilibrium of forces in this medium can be given as follows:gvi = - fi - p δi3 (x+p) √3.

The divergence of the stress tensor and the force density is used to derive the above equation. Now, let us consider the force density to derive the equations of motion of the medium. According to Newton's second law of motion, the force acting on a body is equal to the product of its mass and acceleration.

Therefore, the force density can be given as:f = p(dv/dt)Here, p is the density of the medium. The acceleration of the medium can be given as follows:a = dv/dtTherefore, the force density can be rewritten as:f = paHere, a is the acceleration of the medium.

Equating the two expressions for force density, we get:pa = x (∂Sij/∂xi + ∂Sij/∂xj) dkk + 2ß ∂dij/∂xjWe know that the stress tensor is symmetric. Therefore, the above equation can be simplified as:pa = x (∂Sij/∂xi + ∂Sji/∂xi) dkk + 2ß ∂dij/∂xjNow, we can simplify the above equation further by introducing a tensor notation.

Therefore, the above equation can be given as:pa = x (∂Si j/∂xi) dkk + 2ß (∂di j/∂xj)The above equation is the equation of motion for the medium in tensor notation. We can simplify this equation further by introducing the stress tensor and the Kronecker delta.

Therefore, the equation of motion can be given as follows:pa = x (∂Si j/∂xi) δkk + 2ß (∂di j/∂xj)Here, the Kronecker delta is used to simplify the above equation. Therefore, we can rewrite the equation as:

pa = x (∂Si j/∂xi) δij + 2ß (∂di j/∂xj)Here, we have used the Einstein summation convention to simplify the above equation.

Therefore, the equations of motion for this medium can be written as:gvi = p fit (x+p) √3, i5 + ß vi, Ĵ5.

The equations of motion for a medium can be derived using the stress tensor's divergence and the force density. The stress tensor components & or a continuum can be given as ti^= x Sij dkk +2ß dij depending on the strain tensor.

The equations of motion for this medium can be written as gvi = p fit (x+p) √3, i5 +ß vi, Ĵ5.

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Answer:

theyre correct

Step-by-step explanation:

Answer:

x =< 2

Step-by-step explanation:

5x - 6 =< 2 + (3x - 4)

5x - 6 =< 2 + 3x - 4

5x - 3x =< 2 - 4 + 6

2x =< 4

x =< 2

Answer:

5:4

Step-by-step explanation:

In Mrs. Nathan's class,  the ratio of girls to boys is 5:4.

The ratio can be defined as the number that can be used to represent one quantity as a percentage of another. Only when the two numbers in a ratio have the same unit can they be compared. Ratios are used to compare two objects.

Given, In Mrs. Nathan's class, there are 16 boys and 20 girls.

the ratio of girls to boys = 20/16

the ratio of girls to boys = 5/4

Therefore, the ratio of girls to boys in Mrs. Nathan's class is 5: 4.

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The smallest possible value for the sum of the 81 draws is 411.

To find the smallest possible value of the sum of the 81 draws, we need to minimize the value of each individual ticket. Since we have six tickets with values of 2, 9, 5, 6, 4, and 4, we can assume that each ticket will be drawn 13 or 14 times (since 13 x 6 = 78 and 14 x 6 = 84).

To minimize the sum of the draws, we want to have as many tickets with a value of 2 and 4 as possible. Let's assume that we have 14 draws for each ticket except for the 9 (which we will assume is drawn 13 times).

So, our calculation would be:

(2 x 14) + (9 x 13) + (5 x 14) + (6 x 14) + (4 x 14) + (4 x 14) = 28 + 117 + 70 + 84 + 56 + 56 = 411

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Value of cos(x+π) = \(\bold{\frac{\sqrt{3} }{2}}\)

Given cosine of x = \(-\frac{\sqrt{3} }{2}\)

i.e., cos(x) =  \(-\frac{\sqrt{3} }{2}\)

Also cos(\(\frac{\pi}{6}\)) =  \(\frac{\sqrt{3} }{2}\). So x = \(\frac{\pi}{6}\).

We need to find cos(x+π) = cos(\(\frac{7\pi}{6}\)).

But its value is not easy to find. So we use trigonometric formulas.

We have the trigonometric formula, cos (x+π) = - cos(x) = -  \(-\frac{\sqrt{3} }{2}\) =  \(\bold{\frac{\sqrt{3} }{2}}\)

Cos(x+π) lies in the 3rd quadrant. So there cosine has negative values. That is why, cos (x+π) = - cos(x).

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Answer:

0.799

Step-by-step explanation:

0.799

Answer:

7.6 times 10 to the 6th power

Step-by-step explanation:

7.6 for the first two digits and there are 6 zeros so to the 6th power. Hope this helped!

Step-by-step explanation:

7.6 x 10^7