Can someone help me with this??!!

Explain the difference between -34 and (-3)4, and evaluate each power.

Answer:

Step-by-step explanation:

To find how many solutions that this system equation has, we must solve it

since y equals to both '-5x +1' and '1-5x' we can set them equal to each other and get:

     \(-5x+1 = 1-5x\\0 = 0\)

So there are infinitely many solutions as we got 0 = 0

Hope that helps!  

9514 1404 393

Answer:

  AB = [[-6, -1][-4, 6][-15, 10]]

Step-by-step explanation:

Any of a number of on-line, spreadsheet, or calculator tools will find the matrix product for you.

The input and output of one such tool is shown below.

__

As you know, each term in the product matrix is the sum of products of a row in the left matrix and a column in the right matrix. The coordinates of that row and column are the coordinates of the result in the product matrix.

For example, row 2, column 1 of the product matrix is the sum of products ...

  (4)(-3) +(-2)(-4) = -12 +8 = -4 . . . . row 2, column 1 of the result

The delivery radius for a pizza restaurant in a town with a population density of 1200 people per square mile that wants to deliver to approximately 25,000 people is 2.6 miles.

To calculate the delivery radius, we can use the following formula:

Delivery radius = square root(population / density)

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In this case, the population is 25,000 and the density is 1200 people per square mile. So, the delivery radius is:

Delivery radius = square root(25,000 / 1200) = 2.6 miles

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This means that the pizza restaurant can deliver to approximately 25,000 people within a 2.6 mile radius of its location.

Here is another way to think about it. If we imagine a circle with a radius of 2.6 miles, then the area of that circle will be approximately 25,000 square miles. This means that the pizza restaurant can deliver to approximately 25,000 people within that circle.

It is important to note that this is just an estimate. The actual delivery radius may be slightly different depending on the terrain, traffic conditions, and other factors.

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Answer:

The correct answer is D

Step-by-step explanation:

since 6*14=84, if you solve all the equations, the one that is incorrect is D

Answer: 10 railroad cars

Step-by-step explanation:

1 feet = 12 inches

Each railroad car is 6 inches in length which is half of 1 feet. If we add another railroad car, then both of them altogether will be 1 feet long.

So, if 1 feet = 2 railroad cars

then, 5 feet = 2 x 5

                    = 10 railroad cars

Answer:

\(\frac{x^3 + 2x^2 -9x-18}{x^3-x^2-6x}= \frac{(x+3)}{x}\)

\(\frac{3x^2 - 5x - 2}{x^3 - 2x^2} = \frac{3x + 1}{x^2}\)

\(\frac{6 - 2x}{x^2 - 9} * \frac{15 + 5x}{4x}=-\frac{5}{2x}\)

\(\frac{x^2 -6x + 9}{5x - 15} / \frac{5}{3-x} = \frac{-(x-3)^2}{25}\)

\(\frac{x^3 - x^2 -x + 1}{x^2 - 2x+1}= x +1\)

\(\frac{9x^2 + 3x}{6x^2} = \frac{3x + 1}{2x}\)

\(\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} / \frac{x - 1}{x} = 3x\)

Step-by-step explanation:

Required

Simplify

Solving (1):

\(\frac{x^3 + 2x^2 -9x-18}{x^3-x^2-6x}\)

Factorize the numerator and the denominator

\(\frac{x^2(x + 2) -9(x+2)}{x(x^2-x-6)}\)

Factor out x+2 at the numerator

\(\frac{(x^2 -9)(x+2)}{x(x^2-x-6)}\)

Express x^2 - 9 as difference of two squares

\(\frac{(x^2 -3^2)(x+2)}{x(x^2-x-6)}\)

\(\frac{(x -3)(x+3)(x+2)}{x(x^2-x-6)}\)

Expand the denominator

\(\frac{(x -3)(x+3)(x+2)}{x(x^2-3x+2x-6)}\)

Factorize

\(\frac{(x -3)(x+3)(x+2)}{x(x(x-3)+2(x-3))}\)

\(\frac{(x -3)(x+3)(x+2)}{x(x+2)(x-3)}\)

Cancel out same factors

\(\frac{(x+3)}{x}\)

Hence:

\(\frac{x^3 + 2x^2 -9x-18}{x^3-x^2-6x}= \frac{(x+3)}{x}\)

Solving (2):

\(\frac{3x^2 - 5x - 2}{x^3 - 2x^2}\)

Expand the numerator and factorize the denominator

\(\frac{3x^2 - 6x + x - 2}{x^2(x- 2)}\)

Factorize the numerator

\(\frac{3x(x - 2) + 1(x - 2)}{x^2(x- 2)}\)

Factor out x - 2

\(\frac{(3x + 1)(x - 2)}{x^2(x- 2)}\)

Cancel out x - 2

\(\frac{3x + 1}{x^2}\)

Hence:

\(\frac{3x^2 - 5x - 2}{x^3 - 2x^2} = \frac{3x + 1}{x^2}\)

Solving (3):

\(\frac{6 - 2x}{x^2 - 9} * \frac{15 + 5x}{4x}\)

Express x^2 - 9 as difference of two squares

\(\frac{6 - 2x}{x^2 - 3^2} * \frac{15 + 5x}{4x}\)

Factorize all:

\(\frac{2(3 - x)}{(x- 3)(x+3)} * \frac{5(3 + x)}{2(2x)}\)

Cancel out x + 3 and 3 + x

\(\frac{2(3 - x)}{(x- 3)} * \frac{5}{2(2x)}\)

\(\frac{3 - x}{x- 3} * \frac{5}{2x}\)

Express \(3 - x\) as \(-(x - 3)\)

\(\frac{-(x-3)}{x- 3} * \frac{5}{2x}\\\)

\(-1 * \frac{5}{2x}\)

\(-\frac{5}{2x}\)

Hence:

\(\frac{6 - 2x}{x^2 - 9} * \frac{15 + 5x}{4x}=-\frac{5}{2x}\)

Solving (4):

\(\frac{x^2 -6x + 9}{5x - 15} / \frac{5}{3-x}\)

Expand x^2 - 6x + 9 and factorize 5x - 15

\(\frac{x^2 -3x -3x+ 9}{5(x - 3)} / \frac{5}{3-x}\)

Factorize

\(\frac{x(x -3) -3(x-3)}{5(x - 3)} / \frac{5}{3-x}\)

\(\frac{(x -3)(x-3)}{5(x - 3)} / \frac{5}{3-x}\)

Cancel out x - 3

\(\frac{(x -3)}{5} / \frac{5}{3-x}\)

Change / to *

\(\frac{(x -3)}{5} * \frac{3-x}{5}\)

Express \(3 - x\) as \(-(x - 3)\)

\(\frac{(x -3)}{5} * \frac{-(x-3)}{5}\)

\(\frac{-(x-3)(x -3)}{5*5}\)

\(\frac{-(x-3)^2}{25}\)

Hence:

\(\frac{x^2 -6x + 9}{5x - 15} / \frac{5}{3-x} = \frac{-(x-3)^2}{25}\)

Solving (5):

\(\frac{x^3 - x^2 -x + 1}{x^2 - 2x+1}\)

Factorize the numerator and expand the denominator

\(\frac{x^2(x - 1) -1(x - 1)}{x^2 - x-x+1}\)

Factor out x - 1 at the numerator and factorize the denominator

\(\frac{(x^2 - 1)(x - 1)}{x(x -1)- 1(x-1)}\)

Express x^2 - 1 as difference of two squares and factor out x - 1 at the denominator

\(\frac{(x +1)(x-1)(x - 1)}{(x -1)(x-1)}\)

\(x +1\)

Hence:

\(\frac{x^3 - x^2 -x + 1}{x^2 - 2x+1}= x +1\)

Solving (6):

\(\frac{9x^2 + 3x}{6x^2}\)

Factorize:

\(\frac{3x(3x + 1)}{3x(2x)}\)

Divide by 3x

\(\frac{3x + 1}{2x}\)

Hence:

\(\frac{9x^2 + 3x}{6x^2} = \frac{3x + 1}{2x}\)

Solving (7):

\(\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} / \frac{x - 1}{x}\)

Change / to *

\(\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} * \frac{x}{x-1}\)

Expand

\(\frac{x^2-2x-x+2}{4x} * \frac{12x^2}{x^2 - 2x} * \frac{x}{x-1}\)

Factorize

\(\frac{x(x-2)-1(x-2)}{4x} * \frac{12x^2}{x(x - 2)} * \frac{x}{x-1}\)

\(\frac{(x-1)(x-2)}{4x} * \frac{12x^2}{x(x - 2)} * \frac{x}{x-1}\)

Cancel out x - 2 and x - 1

\(\frac{1}{4x} * \frac{12x^2}{x} * \frac{x}{1}\)

Cancel out x

\(\frac{1}{4x} * \frac{12x^2}{1} * \frac{1}{1}\)

\(\frac{12x^2}{4x}\)

\(3x\)

Hence:

\(\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} / \frac{x - 1}{x} = 3x\)

Remember that

The area of a triangle is given by the formula

where

A=160 m2

h=1600 cm=16 m

substitute in the formula given values

The area of the shaded sector is 4π square units.

To find the area of the shaded sector, we need to calculate the central angle formed by the sector. In this case, we are given that the angle JIK is 90 degrees, which means it forms a quarter of a full circle.

Since a full circle has 360 degrees, the central angle of the shaded sector is 90 degrees.

Next, we need to determine the radius of the circle. The line segment IJ represents the radius of the circle, and it is given as 4 units.

The formula to calculate the area of a sector is A = (θ/360) * π * r², where θ is the central angle and r is the radius of the circle.

Plugging in the values, we have A = (90/360) * π * 4².

Simplifying, A = (1/4) * π * 16.

Further simplifying, A = (1/4) * π * 16.

Canceling out the common factors, A = π * 4.

Hence, the area of the shaded sector is 4π square units.

Therefore, the area of the shaded sector, expressed as a fraction times π, is 4π/1.

In summary, the area of the shaded sector is 4π square units, or 4π/1 when expressed as a fraction times π.

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Answer:

y = -17

Step-by-step explanation:

In this question, you would solve the equation by plugging in 9 to "x", then solve for "y".

Solve:

y = 1 − 2(9)

y = 1 - 18

y = -17

Your final answer would be y = -17

Four comparisons of treatment means can be made.

When the null hypothesis for an ANOVA analysis comparing four treatment means is rejected, it implies that at least one of the treatment means significantly differs from the others. In this case, four comparisons of treatment means can be made to identify which specific treatments are significantly different. These post hoc comparisons are typically performed using methods such as Tukey's test, Bonferroni correction, or Scheffe's method. By conducting these pairwise comparisons, researchers can determine the specific treatments that exhibit statistically significant differences in means.

The number of comparisons that can be made when the null hypothesis for an ANOVA analysis comparing four treatment means is rejected is four. This implies that at least one treatment mean significantly differs from the others, and conducting posthoc tests allows researchers to identify the specific treatments with significant differences.

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hi

Step-by-step explanation:

I

don't

know

see you in next question

The quadratic equations are given as follows:

37. y = 1.6(x² - 2x - 3).

38. y = x² - x.

39. y = 0.4074(x² - 12x + 11).

The roots of the quadratic equation are at x = -1 and x = 3, hence it can be written as follows:

y = a(x + 1)(x - 3)

In which a is the leading coefficient.

Hence:

y = a(x² - 2x - 3)

When x = 1, y = -8, hence the leading coefficient a can be found as follows:

-8 = a(1 - 2 - 3)

5a = 8

a = 8/5

a = 1.6

Hence the equation is:

y = 1.6(x² - 2x - 3).

The roots of the quadratic equation are at x = 0 and x = 1, hence it can be written as follows:

y = ax(x - 1)

Hence:

y = a(x² - x)

When x = 2, y = -2, hence the leading coefficient a can be found as follows:

2 = a(2² - 2)

2a = 2

a = 1.

Hence the equation is:

y = x² - x.

The roots of the quadratic equation are at x = 1 and x = 11, hence it can be written as follows:

y = a(x - 1)(x - 11)

Hence:

y = a(x² - 12x + 11)

When x = 2, y = -11/3, hence the leading coefficient a can be found as follows:

-11/3 = a(4 - 24 + 11)

9a = 11/3

a = 11/27

a = 0.4074.

Hence the equation is:

y = 0.4074(x² - 12x + 11).

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Answer:

OPTION A:

SEE IMAGE FOR SOLUTION

The population of Medway, Ohio, is expected to be approximately 3728 in the year 2020.

From the question, we have the following parameters that can be used in our computation:

Initial, a = 4007

Rate = 0.36% per year

The decay function is represented as

y = a(1 - rate)^x

So, we have

y = 4007 * (1 - 0.36%)^x

This gives

y = 4007 * (0.9964)^x

The year 2020 is 20 years from 2000

So, we have

x = 20

Substitute the known values in the above equation, so, we have the following representation

y = 4007 * (0.9964)^20

Evaluate

y = 3728

Hence, the approximate solution is 3728

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For the inequality  x > y > 0 and a > b > 0 the expression ( x /y)> (x +b)/ (y+ a) > b/a is true if x/b > y/a.

For  x > y > 0 and a > b > 0

The inequality x/b > y/a

Simplify by cross-multiplication we get,

⇒xa > yb

Adding xy to both sides,

⇒xy + xa > xy + yb

Factoring the left-hand side,

⇒ x(y + a) > y(x + b)

Dividing both sides by (y + a)(x + b), as x > y > 0 and a > b > 0,

⇒ x/(x + b) > y/(y + a)

Multiplying both sides by x/y  we get the expression,

⇒x/y > (x + b)/(y + a) __(1)

It proves the half part of the expression, x/y > (x + b)/(y + a)

Now second part x/y > (x + b)/(y + a) > b/a.

Using inequality x/b > y/a to get:

a/b > y/x

Multiplying both sides by (x + b)/(y + a),

⇒(a/b) × (x + b)/(y + a) >(y/x) × (x + b)/(y + a)

Expand both sides and simplifying,

⇒ ( ax + ab ) / (by + ab ) > ( xy + by ) / ( xy + ax )

⇒( ax + ab )( xy + ax ) > ( xy + by ) (by + ab )

⇒ ax²y + a²x² + abxy + a²bx > by²x + abxy + b²y² + ab²y

⇒ (ax -by )( x + b )( y + z) > 0

⇒ax - by > 0 or ( x + b )> 0 or ( y + z) > 0

⇒ ax > by

⇒ x /y > b /a

As a > b > 0

⇒ (x +b)/ (y+ a) > b/a  __(2)

From (1) and (2) we have,

( x /y)> (x +b)/ (y+ a) > b/a

Therefore , the expression ( x /y)> (x +b)/ (y+ a) > b/a is true for the given condition.

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The above question is incomplete, the complete question is:

Suppose x > y > 0 and a > b > 0. Is it true that x/b > y/a then expression

( x /y)> (x +b)/ (y+ a) > b/a.

Answer:

Just set up an equation. You'll be fine

Step-by-step explanation:

I don't want to do it.

Answer:

10. 40+ 3*q = Total Points

11. m + 240 ÷ 9 = Miles per Hour

A possible solution to the equation cos(x+2)=sin(3x) is x = 22 degrees

The correct answer is an option (C)

Consider a trigonometric equation,

cos(x+2) = sin(3x)

For value x = 0.5 degrees,

cos(x + 2) = cos(2.5)

                = 0.999

and sin(3x) = sin(1.5)

                 = 0.026

For x = 1 degree,

cos(x + 2) = cos(3)

                =0.9986

sin(3x) = sin(3)

           = 0.052

For x = 22 degrees

cos(x + 2) = cos(24)

                = 0.913

sin(3x) = sin(66)

           = 0.913

for x = 44 degrees,

cos(x + 2) = cos(46)

                = 0.69

sin(3x) = sin(132)

           = 0.743

Therefore, the solution to an equation cos(x+2) = sin(3x) is x = 22 degrees

The correct answer is an option (C)

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The number of elements common to sets A and B, given that set A contains 39 elements and set B contains 68 elements, and the total number of elements in either set A or set B is 88, is 19.

To determine the number of elements common to sets A and B, we can use the principle of inclusion-exclusion.

The total number of elements in either set A or set B is given by the sum of the number of elements in set A (39) and the number of elements in set B (68), minus the number of elements common to both sets.

Mathematically, this can be represented as |A ∪ B| = |A| + |B| - |A ∩ B|. We are given that |A ∪ B| = 88, |A| = 39, and |B| = 68.

Substituting these values into the equation and solving for |A ∩ B|, we find that |A ∩ B| = 39 + 68 - 88 = 19.

Therefore, there are 19 elements common to sets A and B.

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Answer:

A.The dependent variable is the cost, and the independent variable is the area of the floors.

Step-by-step explanation:

Because I had a quiz with the same question and got it right, and because the paragraph says "The cost depends on the area of the floors."

Answer:

A.

Step-by-step explanation:

"The cost depends on the area of the floors"

The independent variable is the cause and the dependent variable is the effect. Took the test.

Answer:

124 miles

Step-by-step explanation:

$14.99 + ($0.80 x m) = $114.19 (where m is miles driven)

$0.80m = $99.20

m = 124

Answer:

9a^3b^3

Step-by-step explanation:

The greatest common factor is the greatest factor that divides both numbers. To find the greatest common factor, first list the prime factors of each number

Find the prime factors of each term in order to find the greatest common factor (GCF).

Therefore, the estimated population of great white sharks that have migrated from Mexico to Hawaii is 2,500.

Shark population estimation is the process of determining the size and trends of shark populations in a given area. It involves collecting and analyzing data on shark abundance, distribution, behavior, and other factors to understand their population dynamics.

There are different methods used to estimate shark populations, including mark-recapture studies, aerial surveys, acoustic tracking, and genetic analysis. These methods allow researchers to estimate the number of sharks in a given area, monitor changes in their population over time, and identify potential threats to their survival.

To estimate the population of great white sharks that have migrated from Mexico to Hawaii, we can use the capture-recapture method, also known as the Lincoln-Petersen index.

Let:

The Lincoln-Petersen index formula is:

\(N = (n_1 * n_2 * n_3) / (m_1 * m_2 * m_3)\)

Plugging in the given values, we get:

\(N = (45 * 20 * 20 * 20) / (3 * 2 * 4)\)

\(N = 60,000 / 24\)

\(N = 2,500\)

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Answer:

f your number is x, then the difference between that number and 8 would be x-8. Twice that is 2(x-8)

Three times the sum of the number and 3 would be 3(x+3). So, you get the equation:

2(x-8)=3(x+3)

2x-16=3x+9

x=-25

\(~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$2000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &10 \end{cases} \\\\\\ A = 2000\left(1+\frac{0.08}{1}\right)^{1\cdot 10}\implies A=2000(1.08)^{10} \implies A \approx 4317.85\)

Answer:

I think the answer is 2.7

Step-by-step explanation:

3x√64

√64=8

3x=8

x=8/3

x=2.7

Shania ramp will fit within the guidelines, since the angle is 3.4°

Trigonometric ratio is used to show the relationship between the sides and the angles of a right angled triangle.

Let θ represent the angle the ramp makes with the ground. Using trigonometric ratios:

sin(θ) = 1.5/25

θ = 3.4°

Shania ramp will fit within the guidelines, since the angle is 3.4°

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Copyright protection for works of authorship available through the Internet is expressly provided by the WIPO Copyright Treaty (b).

The WIPO Copyright Treaty (WCT) specifically addresses copyright protection in the digital environment, including works of authorship available through the Internet. The treaty was adopted in 1996 by member states of the World Intellectual Property Organization (WIPO). It aims to address the challenges posed by digital technologies and the Internet to the protection of copyright. The WCT provides a framework for protecting digital works, ensuring that authors' rights are respected and their works are protected from unauthorized copying, distribution, and other forms of infringement. Therefore, the WIPO Copyright Treaty is the international agreement that expressly provides copyright protection for works of authorship available through the Internet.

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Answer:

4

Step-by-step explanation:

if you take -6 and subtract it by 2 it equals -4

Answer:

Dang that’s Hard

Step-by-step explanation:

Using Horner's algorithm P(4) = 946

Horner's algorithm is a fast and efficient way to evaluate a polynomial at a particular point. It involves using the distributive property of multiplication to rewrite a polynomial in a nested form, then evaluating the polynomial from the inside out.

Given that, p(z) = 3z⁵ - 7z⁴ - 5z³ + z² - 8z + 2

Using Horner's algorithm, we show the equation like:

p(z) = ((((3z - 7)z - 5)z + 1)z - 8)z +2

p(4) = ((((3*4 - 7)4 - 5)4 + 1)4 - 8)4 + 2

⇒ p(4) = ((((12 - 7)4 - 5)4 + 1)4 - 8)4 + 2

⇒ p(4) = (((5*4 - 5)4 + 1)4 - 8)4 + 2

⇒ p(4) = (((20 - 5)4 + 1)4 - 8)4 + 2

⇒ p(4) = ((15*4 + 1)4 - 8)4 + 2

⇒ p(4) = ((60 + 1)4 - 8)4 + 2

⇒ p(4) = (61*4 - 8)4 + 2

⇒ p(4) = (244 - 8)4 + 2

⇒ p(4) = 236*4 + 2

⇒ p(4) = 944 + 2

⇒ p(4) = 946

Finding the Taylor series expansion of p(z) about z0 = 4:

To find the Taylor series expansion of p(z) about z0 = 4, we need to compute the derivatives of p(z) at z0 = 4. First, we compute p'(z) = 6z^2 - 28z^3 - 10z^2 + 2z - 8, then p''(z) = 12z - 84z^2 - 20z + 2, p'''(z) = 12 - 168z - 20, and so on.

Using these derivatives, we can write the Taylor series expansion of p(z) about z0 = 4 as follows:

p(z) = p(4) + p'(4)(z - 4) + p''(4)(z - 4)^2/2! + p'''(4)(z - 4)^3/3! + ...

Substituting in the values we computed, we get:

p(z) = 946 + 10(z - 4) - 41(z - 4)^2/2! - 14(z - 4)^3/3! + ...

Therefore, the Taylor series expansion of p(z) about z0 = 4 is:

p(z) = 946 + 10(z - 4) - 20.5(z - 4)^2 - 2.333(z - 4)^3 + ...

Using Newton's method to find a root of p(z):

To use Newton's method to find a root of p(z), we start with an initial guess z0 = 4 and iterate the formula z1 = z0 - p(z0)/p'(z0) until we reach a desired level of accuracy.

We already computed p'(z) in part 2, so we can use the formula to compute z1 as follows:

z1 = z0 - p(z0)/p'(z0)

= 4 - (946 + 10(4) - 20.5(4 - 4)^2 - 2.333(4 - 4)^3)/[6(4)^4 - 28(4)^3 - 10(4)^2 + 2(4) - 8]

= 3.46874

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