CAN SOMEONE HELP ME!!!!!!!!!!!!!

119.37 g/mol

Relative atomic mass (Ar) and relative molecular mass / molar mass (M)  

the molar mass/molecular mass of a compound : the sum of the relative atomic mass (Ar) of the constituent atoms

M AxBy = (x.Ar A + y. Ar B)  

Atomic weight (Ar) of :

The molar mass of CHCl₃

\(\tt CHCl_3=12.0107+1,00784+(35,453\times 3)=119.37~g/mol\)

The molar mass of \(CHCl_3\) (chloroform) is 119.37 g/mol. Therefore, the correct option is C.

The organic compound chloroform, which has the molecular formula \(CHCl_3\), is well known for its use as a solvent and anaesthetic. It consists of three chlorine atoms (Cl), one hydrogen atom (H), and one carbon atom (C).

The molar mass of carbon (C) is approximately 12.01 g/mol, the molar mass of hydrogen (H) is approximately 1.01 g/mol, and the molar mass of chlorine (Cl) is approximately 35.45 g/mol. We add up the molar masses of all the individual atoms to determine the molar mass of \(CHCl_3\):

(1 * molar mass of C) + (1 * molar mass of H) + (3 * molar mass of Cl)

(1 * 12.01 g/mol) + (1 * 1.01 g/mol) + (3 * 35.45 g/mol)

12.01 g/mol + 1.01 g/mol + 106.35 g/mol

The molar mass of \(CHCl_3\) is approximately 119.37 g/mol.

Therefore, the correct answer is C.

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The solubility of silver chromate in a 1.10 M silver nitrate solution is 0.344 moles per liter (M).

To calculate the solubility of silver chromate (Ag2CrO4) in a 1.10 M silver nitrate (AgNO3) solution, we need to use the solubility product constant (Ksp) of silver chromate.

The Ksp expression for silver chromate is: Ksp = [Ag+]^2[CrO4^2-]

Let's assume that x moles of Ag2CrO4 dissolves in the solution, then the concentration of Ag+ ions in the solution will be 2x (since each Ag2CrO4 produces 2 Ag+ ions), and the concentration of CrO4^2- ions will also be x. Therefore, we can set up the Ksp expression as follows:

Ksp = (2x)^2(x) = 4x^3

We also know that the concentration of Ag+ ions in the solution is 1.10 M, since this is the concentration of the AgNO3 solution. Therefore:

[Ag+] = 1.10 M

Substituting this value into the Ksp expression, we get:

Ksp = (2x)^2(x) = 4x^3 = (1.10 M)^2

Solving for x, we get:

x = 0.344 M

Therefore, the solubility of silver chromate in a 1.10 M silver nitrate solution is 0.344 moles per liter (M).

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Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl

To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7.  Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.

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Bromination took place at the position on the ring indicated by the experimental results due to its relatively more electron density.

In the experiment 40, acetanilide and aniline were reacted with bromine to observe the relative reactivities of several aromatic compounds. The substituent that was found to be least activating was the nitro group (-NO2).Nitro group has a high electron-withdrawing effect on the ring, which makes it a deactivating group.

As a result, it slows down the rate of electrophilic substitution reaction. Bromination, being an electrophilic substitution reaction, occurs slowly on nitro-substituted aromatic compounds. The reaction is likely to take place at a position on the ring that has relatively more electron density than the other positions.

This is because the bromine, being an electrophile, is attracted to the electron-rich part of the ring.The experiment's results indicated that bromination took place at the position ortho to the nitro group (-NO2). This is because the ortho position has relatively more electron density than the para and meta positions.

The ortho position is the most preferred position for bromination on a nitro-substituted benzene ring. The reason is that the nitro group (-NO2) has a +M effect on the ortho position, which makes it relatively more electron-rich than the para and meta positions. Thus, the bromine is attracted to the ortho position, where it replaces a hydrogen atom, forming the ortho-bromonitrobenzene product.

In conclusion, the nitro group (-NO2) is a deactivating group that slows down the rate of electrophilic substitution reaction. Bromination occurs slowly on nitro-substituted aromatic compounds, and it takes place at the position ortho to the nitro group (-NO2) due to its relatively more electron density.

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The centers for disease control and prevention (CDC) develops recommendations for water fluoridation along with technical requirements for each major compound used.

Almost all water contains some fluoride, but usually not enough to prevent tooth decay. Fluoride can also be added to drinking water supplies as a public health measure for reducing cavities. Water fluoridation is the process of adding fluoride to the water supply so the level reaches approximately 0.7 ppm or 0.7 milligrams of fluoride per liter of water, this is the optimal level for preventing tooth decay.

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Answer:

When it is farther from the Sun.

Explanation:

A planet moves with constantly changing speed as it moves about its orbit. The fastest a planet moves is at perihelion (closest) and the slowest is at aphelion (farthest)

Answer:

When a planet is further away from the sun the Sun’s gravitational pull is weaker, so the planet moves slower in its orbit.

Explanation:

Answer:

big brain

Explanation:

Answer:

The water cycle or hydrologic is a continuous cycle where water evaporates, travels into the air and becomes part of a cloud, falls down to earth as precipitation, and then evaporates again. ... These areas are usually close to oceans or large bodies of water that allow more water to evaporate and form clouds.

Explanation:

The number of mmoles in 5.0 ml of the 3.0 M HCl is 1.5 x 10⁻² mmoles HCl.

To calculate the number of moles (mmoles) of a solution, we use the formula:

moles = concentration (M) x volume (L)

where M is the molarity of the solution and L is the volume in liters.

Molarity (M) is a unit of concentration that measures the number of moles of a solute dissolved per liter of a solution. It is expressed in moles per liter (mol/L) or in some cases, in millimoles per liter (mmol/L).

Given that we have 5.0 ml of a 3.0 M HCl solution, we can convert the volume to liters by dividing by 1000:

volume = 5.0 ml / 1000 = 0.005 L

Using the formula above, we can calculate the moles of HCl:

moles = concentration x volume

moles = 3.0 M x 0.005 L

moles = 0.015 mmol

Therefore, 5.0 ml of a 3.0 M HCl solution contains 0.015 mmoles or 1.5 x 10⁻² mmoles (to one decimal place) of HCl.

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Answer:

The relation between individual and society is very close. Essentially, “society” is the regularities, customs and ground rules of antihuman behavior. These practices are tremendously important to know how humans act and interact with each other. Society does not exist independently without individual.

Explanation:

Answer:

No, the molrcules of water are different from carbon dioxide

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The value of ΔG⁰rxn given an equilibrium constant of 1. 32 × 103 at 25°c is 12191.14 J/mole

A chemical reaction's equilibrium constant is the value of its reaction quotient at chemical equilibrium, a state attained by a dynamic chemical system after a sufficient amount of time has passed in which its composition has no measurable tendency to change further.

The equation below expresses the relationship between standard free energy and equilibrium constant.

ΔG⁰rxn = -RT(㏑ K)

Gas constant R= 8.314 J/mole K

T is the temperature in kelvin unit

The equation below expresses the relationship between standard free energy and equilibrium constant.

We will substitute the values into the described equation to determine ΔG⁰rxn of the reaction with an equilibrium constant of 135.96.

ΔG⁰rxn= 8.314(J/mole K)×(25+273.5K)×㏑(135.96)

ΔG⁰rxn=12191.14 J/mole

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One way to climb from the bottom of a flight of stairs to the top in O(n2) time is to use a brute force approach. This involves considering every possible combination of steps that can be taken at each stair and keeping track of the minimum number of steps needed to reach the top.

This can be done by recursively considering all possible steps from each stair and choosing the minimum among them. While this approach may not be the most efficient, it guarantees that the solution will be found in no more than O(n2) time.

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Answer:

Frequency is 2Hz

Explanation:

They will move backward at a lower speed than the basketball moves forward.

The principle of conservation of linear momentum states that the sum of the initial momentum is equal to sum of final momentum.

Initial momentum = Final momentum

The forward momentum of the basketball = Backward momentum of the person and the chair

Since the mass of the person and the chair is greater than the mass of the basketball, the person and the rolling chair will move backward at a lower speed than the basketball moves forward.

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Answer:

The answer to question 1 should be D. All of the above.

The answer to question 2 should be B. The temperature.

Explanation:

Carboxylic acids are more acidic than water or ethyl alcohol esters due to their stronger resonance stabilization. Carboxylic acids contain a carboxyl group (COOH) that is able to stabilize the extra electron density of the conjugate base (COO-) through resonance. The more electron-withdrawing atoms in the carboxyl group, the more stable the resonance structure and therefore the stronger the acid. Water and ethyl alcohol esters, on the other hand, have less electron-withdrawing atoms, so their conjugate base is not as stable and their acidity is less than that of carboxylic acids.

Additionally, carboxylic acids tend to have smaller molecules than water or ethyl alcohol esters. This means that their conjugate base will have a stronger interaction with the proton and therefore the acid is stronger. In contrast, water and ethyl alcohol esters are larger molecules and their conjugate base is less capable of stabilizing the proton and thus making the acid less acidic.  

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assuming all of the xenon has reacted, The formula of the product is XFe2

In this situation, xenon and fluorine are reacting to form a binary compound. The reaction can be viewed by the below balanced chemical equation:

Xe + 2F2 -> XeF2

The reactants, xenon and fluorine, are initially present at partial pressures of 1.24 atm and 10.10 atm, respectively.Since the reactants are initially present at a total partial pressure of 1.24 atm + 10.10 atm = 11.34 atm, and the final partial pressure of fluorine is 7.62 atm, the partial pressure of the xenon fluoride compound must be 11.34 atm - 7.62 atm = 3.72 atm.

we can set up the following equation:1.24 atm + 10.10 atm = 3.72 atm + 7.62 atm

Solving for the number of moles of fluorine gives:

10.10 atm - 3.72 atm = 7.62 atm

= 6.38 atm

Since the pressure of a gas is directly proportional to the number of moles of the gas present,

n = P / (R * T

= 6.38 atm / (0.08206 Latm/molK * 298 K / 100 mL)

= 0.5 molThe number of moles of xenon present can be calculated in a similar way:

n = P / (R * T

= 1.24 atm / (0.08206 Latm/molK * 298 K / 100 mL)

= 0.05 mol

Since the ratio of moles of xenon to moles of fluorine in the product is 1:2, the formula of the product must be XeF2.

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Answer:

Elements

Explanation:

Elements are pure substances that cannot be broken down into simpler substances by ordinary chemical means.

Answer:

To calculate the pressure exerted by 0.25 moles of chlorine gas in a volume of 5.00 L at 37°C using the ideal gas equation, we can use the following formula: PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. We first need to convert the temperature from Celsius to Kelvin by adding 273.15 to the temperature:

T = 37°C + 273.15 = 310.15 K

Substituting the values given in the problem, we get:

P(5.00 L) = (0.25 mol)(0.08206 L·atm/mol·K)(310.15 K)

Solving for P, we get: P = 3.15 atm

Therefore, the pressure exerted by 0.25 moles of chlorine gas in a volume of 5.00 L at 37°C using the ideal gas equation is 3.15 atm.

To calculate the pressure using the van der Waals equation, we need to use the following formula: (P + a(n/V)^2)(V - nb) = nRT

Where a and b are constants specific to the gas, and n/V is the molar density. For chlorine gas, a = 6.49 L^2·atm/mol^2 and b = 0.0562 L/mol.

We can calculate n/V as follows: n/V = 0.25 mol / 5.00 L = 0.05 mol/L

Substituting the values given in the problem, we get: (P + 6.49 L^2·atm/mol^2 (0.05 mol/L)^2)(5.00 L - 0.0562 L/mol (0.25 mol)) = (0.25 mol)(0.08206 L·atm/mol·K)(310.15 K)

Simplifying and solving for P, we get:

P = 3.11 atm

Therefore, the pressure exerted by 0.25 moles of chlorine gas in a volume of 5.00 L at 37°C using the van der Waals equation is 3.11 atm.

Explanation:

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True. Sediments are small particles of rock, minerals, and organic matter that are transported by natural processes such as wind, water, and ice, and deposited in new locations.

Sediments are small particles of rock, soil, and organic material that are transported and deposited by wind, water, or ice. Sediments are formed through a process called erosion, in which the surface of the Earth is worn away by the action of wind, water, or ice. This process can occur over a long period of time, such as when a river erodes its banks, or more suddenly, such as when a landslide rapidly transports debris down a mountain. Sediments can be composed of a variety of materials, ranging from sand and soil particles to pieces of broken rocks and shells. Once sediment is deposited, it can accumulate to form sedimentary rocks or be buried and later exposed through tectonic activities.

This process can occur as a result of natural forces such as rainfall, wind, and glacial movement. In addition, human activities such as construction and agriculture can also contribute to the movement of sediment. In conclusion, the answer to the question is true; sediment transport is caused by the natural forces of erosion and can be further accelerated by human activities.

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The type of battery used in the Prius, a hybrid car produced by Toyota, is a Nickel-Metal Hydride (NiMH) battery. According to the maker's claims, this battery should not have to be recharged or replaced.

The Prius originally used Nickel-Metal Hydride (NiMH) batteries for its hybrid powertrain. NiMH batteries are known for their higher energy density compared to conventional lead-acid batteries. They are capable of storing and delivering a significant amount of energy, making them suitable for powering the electric motor in hybrid vehicles like the Prius. The manufacturer claims that the NiMH battery in the Prius is designed to last for the lifetime of the car without needing to be recharged or replaced.

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If excess ammonium sulfate reacts with 20.0g of calcium hydroxide then liters of ammonia are produced at STP 0.081L

Ammonium sulphate is the organic solvent and the primary use of ammonium sulphate is as a fertilizer for alkaline soils

Here given reaction is

(NH₄)₂SO₄ + Ca(OH)₂ → CaSO₄ + NH₃ + H₂O

Here given data is

Calcium hydroxide  = 20.0g

We have to find liters of ammonia are produced at STP =?

20.0g of (NH₄)₂SO₄ STP = ?

Then 20.0g of (NH₄)₂SO₄×1 mol/132g×0.54L/1 mol = 0.081L

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Answer:

Oxidation takes place at anode

Reduction takes place at cathode

In the equation Zn has changed to Zn2+. This means oxidation number of Zn has increased from 0 to +2. So Zn is oxidised.

In CuSO4 , Cu2+ and SO4 2- ions are present.

Cu2+ has changed to Cu(s) meaning oxidation number of Cu has reduced from +2 to 0. So Copper is reduced.

So Copper rod is the cathode since it has been reduced and Zn rod is the anode because it has been oxidised.

Also electrons always move from anode to cathode so that also shows us Copper is the cathode

The 1H NMR signals of the indicated protons would be split into three peaks.

What are Protons?

Protons are subatomic particles that are present in the nucleus of an atom. They have a positive electric charge and are one of the three main components of an atom, along with electrons and neutrons. Protons are the heaviest of the three particles and make up a large portion of an atom's mass. The number of protons in an atom is known as its atomic number and is what determines an element's chemical behavior and properties.

The split happens because each proton is coupled to two other protons, and each proton is affected by the other two, resulting in a triplet.

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The mass of copper metal obtained from this process is 483 tons.

To calculate the mass of copper metal obtained from the given copper ore, we need to use the percentage composition and the mass of the ore processed.

1. Calculate the mass of Cu2S in the ore:

Since the ore contains 2.30% Cu2S by mass, we can calculate the mass of Cu2S in 21000 tons of ore:

mass of Cu2S = (2.30/100) × 21000 tons

2. Calculate the molar mass of Cu2S:

Copper (Cu) has a molar mass of approximately 63.55 g/mol, and sulfur (S) has a molar mass of approximately 32.07 g/mol. The molar mass of Cu2S can be calculated as:

molar mass of Cu2S = (2 × molar mass of Cu) + molar mass of S

3. Calculate the moles of Cu2S:

Using the mass of Cu2S and its molar mass, we can calculate the number of moles of Cu2S:

moles of Cu2S = mass of Cu2S / molar mass of Cu2S

4. Calculate the moles of copper (Cu):

Since each formula unit of Cu2S contains 2 moles of copper (Cu), the moles of copper can be calculated as:

moles of Cu = 2 × moles of Cu2S

5. Calculate the mass of copper (Cu):

The mass of copper can be calculated by multiplying the moles of copper by its molar mass:

mass of Cu = moles of Cu × molar mass of Cu

Finally, convert the mass of copper from grams to tons by dividing by 1000:

mass of Cu (in tons) = mass of Cu / 1000

Performing these calculations will provide the mass of copper metal obtained from the given ore in tons.

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Answer:

C. 3

Explanation:

The balanced chemical equation for the combustion of methanol (CH3OH) is: 2 CH3OH + 3 O2 = 2 CO2 + 4 H2O. Therefore, the coefficient of O2 is 3. The correct answer is C) 3.