can someone help, fasttt!

Answer: 15.1

Step-by-step explanation: subtracting a negative (ex. 1 - (-1)) just change to addition (prev. ex. would be 1+1) (also adding decimals is like adding normal numbers just remember the place values

⇒ Given:

Inner radius of the cylindrical pipe = 5 cm

Outer radius of the cylindrical pipe = 5.5 cm

In this question, we have to find the area of the cross section of the cylindrical pipe.

Let the inner radius be r and the outer radius be R.

Formula to be used :

\(\pi {r}^{2} - \pi {r}^{2} \)

→ Taking out the common terms:

\(\pi ( {r}^{2} - {r}^{2} )\)

Hence the required area is :

\(\pi ( {r}^{2} - {r}^{2} )\)

Now,

r = 5 cm

R = 5.5 cm

Substituting the values in the equation:

\(\pi ( {5.5}^{2} - {5}^{2} ) \\ \)

Giving the value of π as 3.14:

\(3.14(30.25 - 25) \\ 3.14 \times 5.25 \\ {16.485}^{2} \)

\(hence the area of \\ cross- section of the cylinder \\ pipe \: is \: {16.485}^{2} \)

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Area of cross - section :

Solution is in attachment ~

A figure has a surface area of 496 m². If the dimensions are doubled by half, the surface area of the new figure is 124 m².

Firstly, we will assume it being a rectangle then calculate the new area using the formula and then we will put the values of original figure into new figure.

Assume we're working with a rectangle. We know that the area equals the length (l) multiplied by the width (w).

A = l x w

If we divide the dimensions in half, we get A = (1 / 2)l x (1 / 2)w.

A = (1 / 4) × (l  x w)

As a result, the new surface area would be one-quarter of the original:

\(A_{original}\) = 496 m²

\(A_{new}\) = (1/4) × \(A_{original}\)

\(A_{new}\) = (1 / 4) × (496)

\(A_{new}\) = 124 m²

As a result, the new area would be 124 m².

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Answer:

Samantha has 8 quarts of milk.  The ratio of quarts to gallons is 4:1. How many gallons of milk does Samantha have?   x  a. 1 over 32   x  b. begin mathsize 16px style 1 half end style   x  c. 2   x  d. 32

Step-by-step explanation:Samantha has 8 quarts of milk.  The ratio of quarts to gallons is 4:1. How many gallons of milk does Samantha have?   x  a. 1 over 32   x  b. begin mathsize 16px style 1 half end style   x  c. 2   x  d. 32Samantha has 8 quarts of milk.  The ratio of quarts to gallons is 4:1. How many gallons of milk does Samantha have?   x  a. 1 over 32   x  b. begin mathsize 16px style 1 half end style   x  c. 2   x  d. 32Samantha has 8 quarts of milk.  The ratio of quarts to gallons is 4:1. How many gallons of milk does Samantha have?   x  a. 1 over 32   x  b. begin mathsize 16px style 1 half end style   x  c. 2   x  d. 32

Answer:

A

Step-by-step explanation:

Got it right on Edge.

Hope this helps, and please mark me the Brainliest!

the probability of transitioning from state 1 to state 2 after the first transition is:

P(X(t) enters state 2 after the first transition | X(0) = 1) = 1 / 3

To write the system of ordinary differential equations (ODEs) for the transition probabilities Pᵢⱼ(t) of the given continuous-time Markov chain, we need to consider the rate at which the system transitions between different states.

Let Pᵢⱼ(t) represent the probability that the Markov chain is in state j at time t, given that it started in state i at time 0.

The ODEs for the transition probabilities can be written as follows:

dP₁₂(t)/dt = q₁₂ * P₁(t) - q₂₁ * P₂(t)

dP₁₃(t)/dt = q₁₃ * P₁(t) - q₃₁ * P₃(t)

dP₂₁(t)/dt = q₂₁ * P₂(t) - q₁₂ * P₁(t)

dP₂₃(t)/dt = q₂₃ * P₂(t) - q₃₂ * P₃(t)

dP₃₁(t)/dt = q₃₁ * P₃(t) - q₁₃ * P₁(t)

dP₃₂(t)/dt = q₃₂ * P₃(t) - q₂₃ * P₂(t)

where P₁(t), P₂(t), and P₃(t) represent the probabilities of being in states 1, 2, and 3 at time t, respectively.

Now, let's consider the second part of the question: Suppose that the initial state is 1. We want to find the probability that after the first transition, the process X(t) enters state 2.

To calculate this probability, we need to find the transition rate from state 1 to state 2 (q₁₂) and normalize it by the total rate of leaving state 1.

The total rate of leaving state 1 can be calculated as the sum of the rates to transition from state 1 to other states:

total_rate = q₁₂ + q₁₃

Therefore, the probability of transitioning from state 1 to state 2 after the first transition can be calculated as:

P(X(t) enters state 2 after the first transition | X(0) = 1) = q₁₂ / total_rate

In this case, the transition rate q₁₂ is 1, and the total rate q₁₂ + q₁₃ is 1 + 2 = 3.

Therefore, the probability of transitioning from state 1 to state 2 after the first transition is:

P(X(t) enters state 2 after the first transition | X(0) = 1) = 1 / 3

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The approximate area of the park on the grid is: E. about 40 km² to 50 km².

The number of square on a coordinate grid that is covered determines the area covered. We can make an estimate by counting how many of this square on the coordinate grid that is covered, then find out the area depending on how much square area each grid represents.

In the coordinate plane given, which shows a park, we are told that each of the square on the grid equals 1 k = square kilometer.

The number of each of these squares we can find that is covered by the park on the grid is: 48 squares.

Therefore, the area of 48 squares on the grid = 48 × 1 = 48 km². Since not all squares are fully covered by the park, we can state that the approximate area of the park on the grid is: E. about 40 km² to 50 km².

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The probability that the selected pool has a ph level not considered safe is approximately 0.22 (or 22%). This can be calculated using the cumulative probability of a normal distribution with a mean of 7.5 and a standard deviation of 0.2.

1. Calculate the z-score for the lower limit of 7.2: (7.2 - 7.5) / 0.2 = -1.5

2. Calculate the z-score for the upper limit of 7.8: (7.8 - 7.5) / 0.2 = 1.5

3. Calculate the cumulative probability of the lower limit: P(-1.5) = 0.0668

4. Calculate the cumulative probability of the upper limit: P(1.5) = 0.9332

5. Calculate the probability that the selected pool has a ph level not considered safe: P(not safe) = 1 - (P(1.5) - P(-1.5)) = 0.22

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Solution

Step 1

To convert seconds to hours, divide the seconds by 3600.

Step 2

1 million seconds = 1000000 seconds

Answer:

3x-4ab+3y

Step-by-step explanation:

I think false as we can see there is not such numbers which makes 9 when multiplied and 4 when added

The exact values of sin, cos, and tan for the given coordinate (-1, √3) at the end of a terminal arm with an angle of 8 in standard position are:

sin(θ) = √3 / 2

cos(θ) = -1 / 2

tan(θ) = -√3.

To determine the exact values of sine, cosine, and tangent for the given coordinate (-1, √3) at the end of a terminal arm with an angle of 8 in standard position, we can use the trigonometric definitions.

Let's denote the angle between the positive x-axis and the terminal arm as θ.

We can see that the x-coordinate is -1 and the y-coordinate is √3. Using these values, we can determine the values of sine, cosine, and tangent.

Sine (sin):

sin(θ) = y / r

In this case, y = √3 and r is the distance from the origin to the point (-1, √3), which is the hypotenuse of the right triangle formed by the coordinates. We can calculate r using the Pythagorean theorem:

r = √((-1)² + (√3)²) = √(1 + 3) = √4 = 2

Therefore, sin(θ) = √3 / 2.

Cosine (cos):

cos(θ) = x / r

In this case, x = -1. Substituting the values, we have:

cos(θ) = -1 / 2.

Tangent (tan):

tan(θ) = y / x

Substituting the values, we have:

tan(θ) = (√3) / -1 = -√3.

Therefore, the exact values of sin, cos, and tan for the given coordinate (-1, √3) at the end of a terminal arm with an angle of 8 in standard position are:

sin(θ) = √3 / 2

cos(θ) = -1 / 2

tan(θ) = -√3.

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Answer:

Step-by-step explanation:

x=-2+ root 5

x=-2- root 5

The values of \(x\) are required.

The values are \(x=-2+\sqrt{5},-2-\sqrt{5}\)

The given equation is

\(x^2+4x-1=0\)

The required formula to solve the equation \(ax^2+bx+c=0\) is

\(x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\)

Here,

\(a=1\)

\(b=4\)

\(c=-1\)

Substituting the values

\(x=\dfrac{-4\pm \sqrt{4^2-4\times1\times\left(-1\right)}}{2\times 1}\\\Rightarrow x=-2+\sqrt{5},-2-\sqrt{5}\)

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Work Shown:

-2 + 11(17y + 15)

-2 + 11(17y) + 11(15) .... distributive property

-2 + 187y + 165

187y + (-2+165)

187y + 163

Answer:

1 or 2

Step-by-step explanation:

8x + 4x < 36

the number x could either be 1 or 2

Answer:

C) nervous

In this organelle, carbon dioxide and water are converted to _________ and oxygen.

~glucose

Step-by-step explanation:

According to the model, it will take 0 days for 300 grams of Mercury 203 to completely decay.

The natural logarithm, often denoted as ln(x), is a mathematical function that represents the logarithm to the base e, where e is the mathematical constant approximately equal to 2.71828.

To find out how long it will take for 300 grams of Mercury 203 to decay, we can use the exponential decay model.

The general formula for exponential decay is given by:

A(t) = A₀ * e^(-rt),

where A(t) represents the amount of the substance at time t, A₀ is the initial amount, r is the decay rate, and e is the base of the natural logarithm.

In this case, we have the initial amount A₀ = 300 grams and the decay rate r = 0.01481 (1.481% written as a decimal).

We want to find the time t when the amount A(t) is equal to zero. Substituting these values into the formula, we have:

0 = 300 * e^(-0.01481t).

To solve for t, we can divide both sides of the equation by 300 and take the natural logarithm of both sides:

ln(0) = ln(e^(-0.01481t)),

0 = -0.01481t.

To isolate t, we divide both sides by -0.01481:

0 / -0.01481 = t,

t = 0.

Therefore, according to the model, it will take 0 days for 300 grams of Mercury 203 to completely decay.

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Answer:

Measure of arc TSU = 201°

Step-by-step explanation:

For the inscribed circle of  triangle XYZ, we have;

∠XZY = 21°

Segment TZ and segment  UZ are tangent to circle R

Therefore, ∠ZUR = ∠ZTR = 90° (angle formed by a tangent)

Length UR = Length TR = Radius of circle R

∴ ΔZTR ≅ ΔZUR Side Angle Side (SAS) rule of Congruency

∴ ∠RZT ≅ ∠RZU, (Congruent Parts of Congruent Triangles are Congruent, CPCTC)

∠XZY = ∠RZT + ∠RZU (Angle summation)

21° = ∠RZT + ∠RZU  = 2×∠RZU (Transitive property)

∠RZU = 21°/2 = 10.5° = ∠RZT

∴ ∠URZ = 180- 90 - 10.5 = 79.5° = ∠TRZ (CPCTC)

arc TU = ∠URT = ∠URZ + ∠TRZ = 79.5 + 79.5 = 159° (angle addition)

∴ Measure of arc TSU = 360° - 159° = 201° (Sum of angles at the center of the circle R)

Measure of arc TSU = 201°.

Answer:

A

Step-by-step explanation:

The tallest lighthouse in the world is the Jeddah Light. It is 133 m tall. A dhow is sailing away from this lighthouse. From the top of the lighthouse, the angle of depression to the dhow is 65° Later, the angle of depression has changed to 40°.

How far did the dhow travel during that time?

To solve this problem, we can use trigonometry and the fact that the angles in a triangle add up to 180°.

Let's call the distance between the lighthouse and the dhow "d".

We know that the angle of depression from the top of the lighthouse to the dhow is 65°, and the angle of depression later changed to 40°.

Let's call the angle between the horizontal and the line of sight from the lighthouse to the dhow, "x"

Since the angles in a triangle add up to 180°, we can say that:

x + 65 + 40 = 180

x = 75

Now, we can use the tangent function to find the distance d. We know that:

tan(x) = d / h

tan(75) = d / 133

d = 133 * tan(75)

Therefore, the dhow traveled 133 * tan(75) distance during that time.

The minim she can get for a score is a 90%

Answer:

See Explanation

Step-by-step explanation:

The best description of the information about the medians is B. The exam median is much higher than the class median.

The class median shown is around the point of 85 out of 100 while the exam median is given to be around 94 out of hundred. Indeed, the class median is at the same point as the first quartile of the exam scores.

What this shows is that the class median is lower than the exam median. Some might even say that the almost 10 point gap means that the exam median is much higher than the class median.

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The statement "A regular polygonal pyramid and a cone both have height h units and base perimeter P units. Therefore, they have the same total surface area" is false.

To understand why, let's break down the concept step by step:

1. A regular polygonal pyramid is a three-dimensional shape with a polygonal base and triangular faces that converge to a single point called the apex or vertex.

2. A cone is also a three-dimensional shape with a circular base and a curved surface that converges to a single point called the apex or vertex.

3. While both a regular polygonal pyramid and a cone may have the same height (h units) and base perimeter (P units), they have different shapes and structures.

4. The total surface area of a regular polygonal pyramid includes the areas of the triangular faces and the base. The formula to calculate the surface area of a regular polygonal pyramid is:

  Surface Area = (0.5 * Perimeter of Base * Slant Height) + Base Area

  The slant height refers to the height of the triangular faces, and the base area refers to the area of the polygonal base.

5. On the other hand, the total surface area of a cone includes the curved surface area and the base area. The formula to calculate the surface area of a cone is:

  Surface Area = (π * Radius * Slant Height) + Base Area

  The slant height refers to the height of the curved surface, and the base area refers to the area of the circular base.

6. Since the regular polygonal pyramid and the cone have different formulas for calculating their total surface areas, they will not have the same surface area, even if they have the same height and base perimeter.

In conclusion, the statement that a regular polygonal pyramid and a cone with the same height and base perimeter have the same total surface area is false.


They have different shapes and structures, leading to different formulas for calculating their surface areas.

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 Recursive formula of an arithmetic sequence is given by the expression,

                          \(T_n=a+(n-1)d\)

                 Where, \(T_n=\) nth term

                              \(a=\) First term of the sequence

                              \(n=\) Number of term

                              \(d=\) Common difference

Therefore, number of sticks in the 6th pattern are 32.

                   And number of sticks in the nth pattern are \(T_n=5n+2\)

From the picture attached,

Number of sticks in 1st pattern = 7

Number of sticks in 2nd pattern = 12

Number of sticks in 3rd pattern = 17

Sequence formed is 7, 12, 17..... nth term

This sequence has a common difference of 5 in each successive term so it will be an arithmetic sequence.

Therefore, nth term of the sequence will be,

       \(T_n=a+(n-1)d\)

       \(T_n=7+(n-1)5\)

       \(T_n=5n+2\)

If \(n=6,\)

       \(T_n=7+(6-1)5\)

       \(T_n=7+25\)

       \(T_n=32\)

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Answer:

71

you just had to add them

Step-by-step explanation:

\(\huge\text{Hey there!}\)

\(\large\text{-4x + 10 = 50}\)

\(\large\text{SUBTRACT by 10 to BOTH SIDES}\)

\(\large\text{-4x + 10 - 10 = 50 - 10}\)

\(\large\text{Cancel out: 10 - 10 because that gives you 0}\)

\(\large\text{Keep: 50 - 10 because it helps us solve for your x value}\)

\(\large\text{50 - 10 = 40}\)

\(\large\text{New equation: -4x = 40}\)

\(\large\text{DIVIDE by -4 to BOTH SIDES}\)

\(\mathsf{\dfrac{-4x}{4}=\dfrac{40}{-4}}\)

\(\large\text{Cancel out: }\mathsf{\dfrac{-4}{-4}}\large\text{ because that gives you 1}\)

\(\large\text{Keep: }\mathsf{\dfrac{-40}{4}}\large\text{ because it helps find x}\)

\(\mathsf{\dfrac{-40}{4}= -40\div4 \rightarrow \bf -10}\)

\(\boxed{\boxed{\large\text{Answer: \bf x = -10}}}\huge\checkmark\)

\(\text{Good luck on your assignment and enjoy your day!}\)

~\(\frak{Amphitrite1040:)}\)

The outward flux of the vector field F across the boundary of the region D, which is the cube bounded by the planes x = ±1, y = ±1, and ±1, can be found using the divergence theorem.

The outward flux is the integral of the divergence of F over the volume enclosed by the boundary surface.The first step is to calculate the divergence of F. The divergence of a vector field F = P i + Q j + R k is given by div(F) = ∂P/∂x + ∂Q/∂y + ∂R/∂z. In this case, div(F) = ∂/∂x(5y - 4x) + ∂/∂y(-4z - 5y) + ∂/∂z(-3y - 2x). Simplifying these partial derivatives, we have div(F) = -4 - 2 - 3 = -9.

Applying the divergence theorem, we can relate the flux of F across the boundary surface to the triple integral of the divergence of F over the volume enclosed by the surface. Since D is a cube with sides of length 2, the volume enclosed by the surface is 2^3 = 8.

Therefore, the outward flux of F across the boundary of D is given by ∬S F · dS = ∭V div(F) dV = -9 * 8 = -72. The negative sign indicates that the flux is inward.

In summary, the outward flux of the vector field F across the boundary of the cube D, as described by the given vector components, is -72. This means that the vector field is predominantly flowing inward through the boundary of the cube.

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Answer:

D. A positive association between hours studied and test score.

Step-by-step explanation:

The scatter plot appears to have an upward trend.

Ashley's fuel efficiency is approximately 23.19 miles per gallon. To calculate Ashley's fuel efficiency in miles per gallon, you can follow these steps:

Step:1. Fuel efficiency = Miles driven / Gallons of fuel used                                                                                                                Step:2. Fuel efficiency = 385 miles / 16.6 gallons                                                                                                                               Step:3. Fuel efficiency = 23.193 miles/gallon (rounded to three decimal places)
Therefore, Ashley's fuel efficiency for this particular fill-up was approximately 23.193 miles per gallon.                               This means that for every gallon of fuel used, Ashley's car was able to travel approximately 23.193 miles. It's important to note that fuel efficiency can vary depending on factors such as driving habits, vehicle condition, and fuel quality.

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