CAN SOMEONE HELLP MEE? *cries

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Explanation:

If his father saves 18%, then he pays the remaining 82% since 100-18 = 82.

The 82% then converts to 0.82 which is one of the multipliers we'll use to get the answer.

The other multiplier is 1.10 to represent an increase of 10%

The net multiplier is 0.82*1.10 = 0.902

Therefore, his father pays 0.902*60 = 54.12 dollars after the discount and maintenance fee are applied.

Answer:

$4.89

Step-by-step explanation:

$1.63 x 3 = $4.89

Answer:

$4.89

Step-by-step explanation:

x= number of days

cost for one cappuccino: $1.63

1.63x -----> 1.63(3)= $4.89

Answer:

Choice 3 and 5

Step-by-step explanation:

Answer: A,B,E

Step-by-step explanation:

Just trust me

Here are the general steps for using the u-substitution method to evaluate a definite integral:

1. Identify a part of the integrand that looks like the derivative of another function.

This is usually denoted as u, and u should be a function that is easy to integrate.

2. Replace the selected part of the integrand with u. In other words, substitute u for the expression inside the integral.

3. Take the derivative of u with respect to the variable of integration, and then multiply by dx to obtain du.

4. Replace dx with the expression in terms of du, using the relationship you found in step 3.

5. Rewrite the entire integral in terms of u and du, and simplify as much as possible.

6. Evaluate the integral using u and the limits of integration. Replace u with the original expression, and then evaluate the expression at the upper and lower limits of integration.

7. Substitute the values obtained in step 6 into the original equation to get the final answer.

The u-substitution method is a powerful technique for evaluating definite integrals.

The general idea behind the u-substitution method is to replace a complicated expression inside the integral with a simpler expression, which is equal to the original expression.

Here are the general steps for using the u-substitution method to evaluate a definite integral:

Let's take an example to illustrate these steps:

Evaluate the definite integral ∫\((2x + 1)^(3/2) dx from x = 1 to x = 2.\)

Let u = 2x + 1.

Replace 2x + 1 with u in the integral to get ∫\(u^{3/2} dx.\)

Take the derivative of u with respect to x to get du/dx = 2, and then multiply by dx to obtain du = 2dx.

Replace dx with 1/2 du.

Rewrite the entire integral in terms of u and du to get ∫\(u^{3/2} (1/2) du.\)

Evaluate the integral using u and the limits of integration to get (2/5) \(u^{5/2}\) from 3 to 5.

Substitute the values obtained in step 6 into the original equation to get the final answer, which is\((2/5) [(5^{5/2}- 3^{5/2}].\)

Therefore, the value of the definite integral ∫\((2x + 1)^{3/2}\)dx from x = 1 to x = 2 is approximately 6.243.

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The value of the annuity at the end of 5 years, rounded to the nearest dollar is $10,833.

The formula that can be used to determine the future value of the annual annuity is:

Yearly deposity x annuity factor

Annuity factor = {[(1+r)^n] - 1} / r

Where:

2000 x {[(1.04^5) - 1] / 0.04} = $10,832.65

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Answer:

2.25

Step-by-step explanation:

hope this helps :)....

Answer:4log5=4log5

Step-by-step explanation:

Take the log of both sides

log5^4 =log 625

By log log a^b=b loga

4log 5=log5^4

4log5 =4log 5

Expressions and equations can be written in logarithmic forms.

The logarithmic form of \(5^4 = 625\) is \(\log_5(625) = 4\)

The equation is given as:

\(5^4 = 625\)

Take the logarithm of both sides of the equation

\(\log(5^4) = \log(625)\)

Apply law of logarithm

\(4\log(5) = \log(625)\)

Divide both sides of the equation by log(5)

\(4 = \frac{\log(625)}{\log(5)}\)

Apply change of base law of logarithm

\(4 = \log_5(625)\)

Rewrite the equation as follows:

\(\log_5(625) = 4\)

Hence, the logarithmic form of \(5^4 = 625\) is \(\log_5(625) = 4\)

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Answer:

142

Step-by-step explanation:

Answer:

142

Step-by-step explanation:

The function f(x) is vertically compressed to form g(x) while the function f(x) is vertically compressed and then reflected across the x-axis to form h(x)

The functions are given as

f(x) =x^2

g(x) =3x^2

h(x) = -3x^2

Substitute f(x) =x^2 in g(x) =3x^2 and h(x) = -3x^2

g(x) =3f(x)

h(x) = -3f(x)

This means that the function f(x) is vertically compressed to form g(x)

Also, the function f(x) is vertically compressed and then reflected across the x-axis to form h(x)

See attachment for the functions g(x) and h(x)

Also, functions f(x) and g(x) have the same domain and range

While functions f(x) and h(x) have the same domain but different range

The complete table is:

x      -2    -1    0   1    2

g(x)  12    3    0    3   12

h(x)  -12    -3    0    -3   -12

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Answer:

65D

Step-by-step explanation:

The area of the sector is 113.14 square cm.

Step1:

Given, central angle, θ = 120°

Radius of circle, r = 21 cm

We have to find the area of a sector of the circle.

Area of sector = πr²θ/360°

= π(21)²(120°)/360°

= π(21)²(1/3)

= (22/7)(21)(21)(1/3)

= (22/7)(21)(7)

= (22)(21)

= 462 square cm.

Step2:

Therefore, the area of the sector is 462 square cm.

the area of a sector of circle of radius 12 cm and central angle 90°.

central angle, θ = 90°

Radius of circle, r = 12 cm

We have to find the area of a sector of the circle.

Area of sector = πr²θ/360°

= π(12)²(90°/360°)

= (22/7)(12)(12)(1/4)

= (11/7)(6)(12)

= 113.14 square cm

Therefore, the area of the sector is 113.14 square cm.

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The content dimension of a message deals with the what of a message, while the relational dimension of a message deals with the how of a message is the correct answer.

Content dimensions is a generic concept to have multiple variants of a content node. It involves the information being explicitly discussed. The content repository supports any number of dimensions. The content dimension is the meaning of the actual message itself.

"Relational dimension of communication is a concept in which we have similar weight and impact as that of the message. This concept deals with the quality or nature of the relationships and networks."

Hence we can conclude that the content dimension of a message deals with the what of a message, while the relational dimension of a message deals with the how of a message is the correct answer.

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Answer:

The energy transformation taking place are;

1) Chemical energy → Mechanical Energy (Kinetic energy)  in the muscles of the the person shooting the slingshot

2) Kinetic energy from the muscle → Elastic potential energy of the slingshot before it is released

3) Elastic potential energy of the slingshot → Kinetic energy in the small ball as the starts moving up into the air

4) Kinetic energy in the upward moving ball  → Gravitational potential energy in the ball as it slows down while increasing in height

5) Maximum gravitational energy at the highest point where upward motion stops and downward motion starts then, gravitational potential energy → Kinetic energy as the ball comes back down with increasing speed

6)  Kinetic energy → Sound, heat, kinetic energy (received by other items at collision) when the ball reaches the ground

Step-by-step explanation:

The degree of that polynomial is 5

What is the Degree of Polynomial?

The degree of polynomial is the highest degrees of individual term.

The first is to find each term.

The term is 3\(p\)\(q^{4}\), 2\(p^{2}\)\(q\), and \(q^{3}\) (or can also be written as 3\(p^{1}\)\(q^{4}\), 2\(p^{2}\)\(q^{1}\), and \(p^{0}\)\(q^{3}\)

The next step is to add up the exponents for each term and select the highest result.

3\(p^{1}\)\(q^{4}\) : 1+4 = 5
2\(p^{2}\)\(q^{1}\) : 2+1 = 3
\(p^{0}\)\(q^{3}\) : 0+3 = 3

Therefore the degree of polynomial is 5

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Answer:

45 cups

Step-by-step explanation:

15x3 because there are 3 cups and 15 is one of the cups so 15x3=45

Answer:

45 Cups

Step-by-step explanation:

Use a proportion with cups in the numerator and pail in the denominator .

15/(1/3) = X/ 1

15 ÷1\3 = 15 x 3 =45 cups

We're dealing with linear functions. f(x) = mx + b, We have here the first function. g(x) = 3x That is a linear function with a slope and no linear coefficient because, However, because all of the functions below have the same slope value, they all describe parallel lines.  

Their non-zero linear coefficients are -6,-18,6,18, despite the fact that they all have the same slope value. The first one, though, was

\($\begin{aligned} & h(x)=3(9 x-2) \rightarrow h(x)=27 x-6 \\ & i(x)=9(3 x-2) \rightarrow i(x)=27 x-18 \\ & j(x)=3(9 x+2) \rightarrow j(x)=27 x+6 \\ & k(x)=9(3 x+2) \rightarrow k(x)=27 x+18\end{aligned}$\)

A possible solution would be adjusting any of these, whose operation would result in g(x)=3x, but

Like

\($y=9\left(\frac{3 x}{9}-2\right)+18=3 x$\)

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Answer:

got em

Step-by-step explanation:

The value for a in quadratic function a(x-1)²+3 is obtained as a = 2.

What is a quadratic function?

A polynomial function with one or more variables, where the largest exponent of the variable is two, is referred to as a quadratic function. It is also known as the polynomial of degree 2 since the greatest degree term in a quadratic function is of second degree.

The vertex of the quadratic function is (1,3).

The line passes through the points (3,5).

The equation is in the form - a(x-1)²+3

It is known that the vertex form of a quadratic function is f(x) = a(x-h)² + k, where (h,k) is the vertex of the parabola.

So it can be written -

f(x) = a(x-1)² + 3

Substitute the value of (1,3).

f(1) = a(1-1)² + 3 = 3

And for the point (3,5) the equation will be -

f(3) = a(3-1)² + 3 = 5

Set up a system of equations -

a(1-1)² + 3 = 3

a(3-1)² + 3 = 5

Solving for a in these equations -

a = 2

Therefore, the value of a is obtained as 2.

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To determine if there is evidence that the outcomes are not independent of age group, we can use statistical analysis. First, we need to define the null and alternative hypotheses.

In this case, the null hypothesis would be that the outcomes are independent of age group, while the alternative hypothesis would be that the outcomes are dependent on age group. Next, we can conduct a chi-squared test of independence to analyze the data. This test compares the observed frequencies of the outcomes across different age groups to the expected frequencies if the outcomes were independent of age group. If the calculated chi-squared value is greater than the critical value, we can reject the null hypothesis and conclude that there is evidence that the outcomes are not independent of age group. On the other hand, if the calculated chi-squared value is less than or equal to the critical value, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest a relationship between the outcomes and age group.

In conclusion, by conducting a chi-squared test of independence, we can determine if there is evidence that the outcomes are not independent of age group.

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In the given system of linear inequalities,

Solutions: (1, 0), (-2, 5)

Non-solutions: (2, 0), (0, 1)

To graph the system of linear inequalities, we will plot the boundary lines for each inequality and shade the appropriate regions based on the given inequalities.

1. Graphing the inequality y < −x + 3:

To graph y < −x + 3, we first draw the line y = −x + 3. This line has a slope of -1 and a y-intercept of 3. We can plot two points on this line, for example, (0, 3) and (3, 0), and draw a dashed line passing through these points. Since y is less than −x + 3, we shade the region below the line.

2. Graphing the inequality y ≥ 2x − 1:

To graph y ≥ 2x − 1, we first draw the line y = 2x − 1. This line has a slope of 2 and a y-intercept of -1. We can plot two points on this line, for example, (0, -1) and (1, 1), and draw a solid line passing through these points. Since y is greater than or equal to 2x − 1, we shade the region above the line.

Now let's find two ordered pairs that are solutions and two that are not solutions.

Ordered pairs that are solutions:

- (1, 0): This point satisfies both inequalities. Plugging in the values, we get y = -1 and y ≥ 1, which are both true.

- (-2, 5): This point satisfies both inequalities. Plugging in the values, we get y = 7 and y ≥ 3, which are both true.

Ordered pairs that are not solutions:

- (2, 0): This point does not satisfy the first inequality y < −x + 3 since 0 is not less than -2 + 3.

- (0, 1): This point does not satisfy the second inequality y ≥ 2x − 1 since 1 is not greater than or equal to -1.

By graphing the system of linear inequalities and examining the solutions and non-solutions, we have:

Solutions: (1, 0), (-2, 5)

Non-solutions: (2, 0), (0, 1)

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Answer:

\(\textsf{(a)} \quad -4 < x\leq 1\)

\(\textsf{(b)} \quad [3, 19)\)

Step-by-step explanation:

Given compound inequality:

\(\dfrac{9+x}{5} < 5+x\leq 6\)

\(\textsf{If\: $a < u\leq b$ \:then\: $a < u$ \:and\: $u\leq b$}.\)

\(\textsf{Therefore \:$\dfrac{9+x}{5} < 5+x$ \:and\: $5+x\leq 6$}\)

Solve the inequalities separately:

Inequality 1

\(\begin{aligned}\dfrac{9+x}{5} & < 5+x\\9+x & < 5(5+x)\\9+x & < 25+5x\\9+x -5x& < 25+5x-5x\\9-4x & < 25\\ 9-4x-9 & < 25-9\\-4x & < 16\\-x & < 4\\x & > -4\\ \end{aligned}\)

Inequality 2

\(\begin{aligned} 5+x & \leq 6\\ 5+x-5 & \leq 6-5\\x & \leq 1 \end{aligned}\)

Combine the intervals:

\(-4 < x\leq 1\)

Given equation:

\(y=x^2+3\)

As the domain is restricted to  -4 < x ≤ 1, the range is also restricted.

The vertex (minimum point) of  \(y = x^2 + 3\)  is when x = 0.

As x = 0 lies within the restricted domain, y = 3 is the lowest value of the range.

\(x=-4 \implies y=(-4)^2+3=19\)

Therefore, the range is:

Adjusted Bank Balance: Rs. (12,550 + 8,000 + 2,550 + 3,500 - 5,500 - 1,000 - 5,100)

Based on the given information, let's summarize the items in the bank reconciliation statement:

a. Cheques drawn but not yet cleared by the bank: Rs. 8,000.

b. Direct payment made by a customer into the bank but not recorded in the cash book: Rs. 2,550.

c. Commission paid by the bank as per standing instruction: Rs. 3,500.

d. Cheque paid to the bank but not yet credited by the bank: Rs. 5,500.

e. Wrong amount credited in the passbook but not in the cash book: Rs. 1,000.

f. Undercast in the credit side of the cash book: Rs. 5,100.

g. Cash book balance: Rs. 12,550.

To prepare the bank reconciliation statement, we need to adjust the cash book balance by considering the items mentioned above. The statement would look as follows:

Cash Book Balance: Rs. 12,550

Add: Cheques drew but not enhanced: Rs. 8,000

Add: Direct payment made by a customer into the bank but not recorded in the cash book: Rs. 2,550

Add: Commission paid by bank as per standing instruction: Rs. 3,500

Less: Cheque paid to bank but not credited by the bank: Rs. 5,500

Less: Wrong amount credited in passbook but not in cash book: Rs. 1,000

Less: Undercast in the credit side of cash book: Rs. 5,100

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The correct answer is B

Answer:

1024

Step-by-step explanation:

We can solve this using areas.

The small triangle has a base b and a height h.

The area of the small triangle is bh/2.

The large triangle has a perimeter that is 32 times the perimeter of the small triangle. Perimeters are linear measures, so the linear scale factor from the small triangle to the large triangle is 1:32. That means that the base of the large triangle measures 32b, and the height of the large triangle measures 32h.

The area of the large triangle is

base × height / 2 = (32b)(32h)/2 = 512bh

Now we compare the areas of the the large triangle and the small triangle by division.

512bh / (bh/2) = 512 × 2 = 1024

Answer: 1024

Answer:

42 square units

Step-by-step explanation:

Find the diagram attached

Area of the diagram = Area of the triangle + Area of rectangle

Area of rectangle = Length * Width

Area of rectangle = 3 * 6

Area of rectangle = 18 square units

Area of triangle = 1/2 * base * height

Get the base of the tringle using the pythagoras theorem;

b^2 = 10^2-6^2

b^2 = 100 - 36

b^2 = 64

b = 8units

height = 6 units

Area of the triangle = 1/2 * 8 * 6

Area of the triangle = 48/2

Area of the triangle  = 24 square units

Area of the figure = 18+24

Area of the figure = 42 square units

Therefore, the value of v(t) at time t = -1 is -3. The function v(t) is a nonperiodic waveform, which means that it does not repeat itself after a certain period of time.

The function is defined as follows:

v(t) = 2 u(t - 1) - 3 u(t + 5)

where u(t) is the unit step function. The unit step function is a function that is equal to 1 for all values of t greater than or equal to 0, and 0 for all values of t less than 0.

To find the value of v(t) at time t = -1, we simply substitute -1 into the function. This gives us:

v(-1) = 2 u(-1 - 1) - 3 u(-1 + 5)

The first unit step function evaluates to 0, because -2 < 0. The second unit step function evaluates to 1, because 4 > 0.

Therefore, the value of v(-1) is equal to:

v(-1) = 2 * 0 - 3 * 1 = -3

Therefore, the value of v(t) at time t = -1 is -3.

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The lift and drag if the shear stress is neglected, than the values of F0 = 1.1955 KN & F1 = 8.014 KN.

The average pressure and shear stress acting on the surface of the 1-m-square flat plate.

P1 = 2.3 * 3 = 6.9 KN/m^2

P2 = -1.2 KN/m^2

T1 = 7.6 * 10^-2 * 2 = 0.152 KN/m^2

T2 = 0.058 KN/m^2

Now,

Drag force

F0 = F1sinα - F2sinα + FS1cosα+FS2cosα

= P1Asinα - P2sinα + T1Acosα + T2Acosα

= Asinα(P1-P2) + Acosα(T1 + T2)

= 1.sin(T)[6.9-(-1.2)] + 1. cos (T)[0.152 + 0.058]

= 0.98714 + 0.20843

= 1.1955 KN

Lift force

F1 = F1cosα - F2cosα - FS1sinα - FS2sinα

= P1cosα - P2Acosα - T1Asinα - T2Asinα

= Acosα(P1 - P2) - A.sinα(T1 + T2)

= 1. cos(T)(6.9 - (-1.2)) - 1. sin(T)(0.152 + 0.058)

= 8.014 KN

Hence the answer is the lift and drag if the shear stress is neglected, than the values of F0 = 1.1955 KN & F1 = 8.014 KN.

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When gravity acts on the air, the air exerts a force upon the earth called pressure. The typical pressure at sea level is 1013.25 millibars or 14.7 pounds per square inch.

The lift and drag if the shear stress is neglected, than the values of F0 = 1.1955 KN & F1 = 8.014 KN.

The average pressure and shear stress acting on the surface of the 1-m-square flat plate.

P1 = 2.3 * 3 = 6.9 KN/m^2

P2 = -1.2 KN/m^2

T1 = 7.6 * 10^-2 * 2 = 0.152 KN/m^2

T2 =0.058 KN/m^2

Now,

Drag force

F0 = F1sinα - F2sinα + FS1cosα+FS2cosα

= P1Asinα - P2sinα + T1Acosα + T2Acosα

= Asinα(P1-P2) + Acosα(T1 + T2)

= 1.sin(T)[6.9-(-1.2)] + 1. cos (T)[0.152 + 0.058]

= 0.98714 + 0.20843

= 1.1955 KN

Lift force

F1 = F1cosα - F2cosα - FS1sinα - FS2sinα

= P1cosα - P2Acosα - T1Asinα - T2Asinα

= Acosα(P1 - P2) - A.sinα(T1 + T2)

= 1. cos(T)(6.9 - (-1.2)) - 1. sin(T)(0.152 + 0.058)

= 8.014 KN

Hence the answer is the lift and drag if the shear stress is neglected, than the values of F0 = 1.1955 KN & F1 = 8.014 KN.

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The probability of getting exactly one face card is 0.72.

According to the questions two cards are drawn from a deck.

Since, we know that

Total number of cards in a deck = 52

Total number of face cards =  3 × 4 = 12

So, the number of ways of selecting 2 cards from a deck = \(^{52} C_{2}\)

And, the total number of ways of  getting exactly one face cards

= \(^{12} C_{1} \times ^{40} C_{1}\)  + \(^{40} C_{1} \times ^{12} C_{1}\)

= 2\(^{40} C_{1} \times ^{12} C_{1}\)

Therefore, the probability of getting exactly one face card

= \(\frac{2(^{40} C_{1} \times ^{12} C_{1})}{^{52C_{2} } }\)

\(= \frac{2(\frac{40 \times 39!}{1!\times 39!} \frac{12\times 11!}{11!}) }{\frac{52\times 51\times 50!}{2!\times50!} }\)

\(= \frac{2(40\times 12)}{26\times 51}\)

\(=\frac{2\times 480}{1326}\)

= 0.72

Hence, the probability of getting exactly one face card is 0.72.

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Center point of dilation is a fixed point in a plane about which all the points of the figure expanded or contract. And scale factor of a dilation is the ratio of new formed image to the old given image.

Explanation:

Therefore, the center of the dilation can be find using the translation and scale factor can be calculated using the ratio of the new to the old images.

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Answer:

C

Step-by-step explanation:

because when converted to decimal its roughly 8.2. which is more than eight, yes, but 8 is the closest thing to 8.2