Answer:
I think you might have forgotten to post the problems
What is your favorite Electronic company? (E.g. Windows, Apple, Samsung...)
Answer:
apple
Explanation:
is the answer toWhat is your favorite Electronic company? (E.g. Windows, Apple, Samsung...)
A visual lead of ________ seconds or 1 city block is appropriate when driving in traffic in urban areas.
The answer is
A visual lead of 12-15 seconds or 1 city block is appropriate when driving in traffic urban areas.
Urban driving involves a variety of complex driving situations.
when you driving in urban areas, look at least 12-15 seconds ahead of vehicle.
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Answer: 5
Explanation:
just took it
which type of mining creates the greatest environmental damage
Among various types of mining, open-pit mining is often considered to create the greatest environmental damage. Open-pit mining, also known as open-cast or open-cut mining, involves the extraction of minerals or ores from the Earth's surface by removing overlying soil and rock layers.
There are several reasons why open-pit mining is associated with significant environmental damage:
Large-Scale Excavation: Open-pit mining requires the excavation and removal of vast amounts of soil, rocks, and vegetation. This process leads to the destruction of natural habitats, deforestation, and loss of biodiversity in the affected areas. The removal of topsoil and vegetation can result in long-term soil erosion and degradation.
Alteration of Landforms: Open-pit mining alters the natural topography of the land, resulting in the creation of deep pits and spoil heaps. These altered landforms can disrupt the hydrological systems, leading to changes in water flow patterns, contamination of groundwater, and the loss of aquatic habitats. The accumulation of waste rock and tailings in spoil heaps can release harmful chemicals into the environment, polluting nearby water sources.
Air and Water Pollution: The extraction and processing of minerals in open-pit mining often involve the use of explosives, heavy machinery, and chemical reagents. These activities can release dust, particulate matter, and toxic substances into the air, contributing to air pollution. The runoff from mining sites can carry sediments, heavy metals, and chemicals into nearby water bodies, causing water pollution and affecting aquatic ecosystems.
Energy Consumption and Greenhouse Gas Emissions: Open-pit mining requires significant energy inputs for excavation, transportation, and processing of minerals. The extraction and use of fossil fuels in mining operations contribute to greenhouse gas emissions, exacerbating climate change and its associated environmental impacts.
While it is important to note that the environmental impact of mining can vary depending on various factors, including the specific mineral being extracted, the location, and the mining practices employed, open-pit mining is generally considered more destructive due to its extensive scale, alteration of landforms, habitat destruction, and potential for pollution. Sustainable mining practices, strict environmental regulations, and reclamation efforts are crucial in mitigating the environmental damage associated with mining operations.
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3. Explain why systems developed as prototypes should not normally be used as production systems.
With an intricate network of nerves and specialized cells called neurons, the nervous system relays information throughout the body.
This is further explained below.
What are prototypes?Generally, Generally speaking, the four statutes that made up the Alien and Sedition Acts were meant to discourage making a public declaration of support for a political party.
the 1798 Declaration of Independence, which restricted immigration and free speech, is an example of anything officially expressed or containing such a declaration. The "Sedition and Alien Acts" were the official names for these regulations.
In conclusion, To begin, prototypes often lack the funds necessary to provide adequate documentation, which makes them difficult to keep up with in the future.
Second, the majority of the time, the codes used in prototypes do not satisfy the quality level established by the business.
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Explain Why programs when are developed using evolutionary development are likely to be difficult to maintain
Answer:
When a system is produced using the evolutionary development model, features tend to be added without regard to an overriding design. With each modification, the software becomes increasingly disorganized. System maintenance hampered by these problems, as it is harder identifying the source of bugs in poorly designed systems. Also, keeping the documentation up to date over successive "evolution" is uncommon. Poor documentation also makes maintenance more difficult.
Explanation:
・It leads to implementing and then repairing way of building systems.
・Practically, this methodology may increase the complexity of the system as scope of the system may expand beyond original plans.
・Incomplete application may cause application not to be used as the full system was designed.
・Their results have incomplete or inadequate problem analysis.
A site is underlain by a soil that has a unit weight of 118 lb/ft3. From laboratory shear strength tests that closely simulated the field conditions, the total stress parameters were measured to be C total = 250 lb/ft2 and φ total = 29°. Estimate the shear strength on a horizontal plane at a depth of 12 ft below the ground surface at this site in lbs/ sq ft
Answer: the shear strength at a depth of 12 ft is 1034.9015 lb/ft²
Explanation:
Given that;
Weight of soil r = 118 lb/ft³
stress parameter C = 250 lb/ft²
φ total = 29°
depth Z = 12 ft
The shear strength on a horizontal plane at a depth of 12ft
ζ = C + δtanφ
where δ = normal stress
normal stress δ = r × z = 118 × 12 = 1416
so
ζ = C + δtanφ
ζ = 250 + 1416(tan29°)
ζ = 250 + 1416(tan29°)
ζ = 250 + 784.9016
ζ = 1034.9015 lb/ft²
Therefore the shear strength at a depth of 12 ft is 1034.9015 lb/ft²
Is the MI-24 Hind the most widely exported combat helicopter in the world?
The invention that spurred industrial growth by providing cheap means of transport was the (a) automobile (b) steamboat (c) macadam road(d) railroad.
An entirely new realm of transportation was made possible by the development of the railroad and the steam-powered locomotive.
Trains could now run wherever tracks could be constructed. Canals and rivers were no longer the only means of transportation. The first significant development in transportation was the construction of canals, which were typically built directly from System to city centers, like the renowned Bridgewater Canal in Manchester. Horses were frequently used for tramways. Roads, steamboats, the Eerie Canal, and railroads, among other advancements in transportation, were used to connect far-flung, once isolated villages throughout the Second Industrial Revolution. An entirely new realm of transportation was made possible by the development of the railroad and the steam-powered locomotive.
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Will a thermal boundary layer develop in flow over a surface even if both the fluid and the surface are at the same temperature?
Answer:
i hope it's correct
Explanation:
A thermal boundary layer will not develop in flow over a surface if both the fluid and the surface are at the same temperature since there will be no heat transfer in that case.
A horizontal piston/cylinder arrangement is placed in a constant-temperature bath. The piston sides in the cylinder with negligible friction and an external force holds it in place against an initial gas pressure of 14 bar. The initial gas volume is 0.03 m3. The external fore on the piston is reduced gradually and the gas expands isothermally as its volume triples. If the volume of the gas is related to its pressure so that the product PV is constant.
(a) What is the work by the gas in moving the external force?
(b) How much work would be done if the external force were suddenly reduced to half its initial value instead of being gradually
reduced?
Answer:
\(W=46141.72~J\)
Explanation:
Given:
initial pressure, \(P_1=14~bar=1.4\times10^6~Pa\)
initial volume, \(V_1=0.03~m^3\)
After isothermal expansion:
final volume, \(V_2=3V_1=0.09~m^3\)
a)
We have the work done in isothermal process as:
\(W=P_1.V_1\ln(\frac{V_2}{V_1} )\)
\(W=1.4\times10^6\times 0.03\ln(\frac{0.09}{0.03} )\)
\(W=46141.72~J\) is the work by the gas in moving the external force
b)
When the force on piston is suddenly reduced to half the initial value then the process becomes near to adiabatic.
\(P_1V_1^{\gamma}=P_2V_2^{\gamma}\)
\(14\times 0.03^{1.4}=P_2\times 0.09^{1.4}\)
\(P_2=3~bar\)
Now, using the formula for work done in adiabatic process:
\(W=\frac{P_1V_1-P_2V_2}{\gamma-1}\)
\(W=\frac{1.4\times10^6\times 0.03-3\times10^5\times 0.09}{1.4-1}\)
\(W=3750~J\)
what can be the main disadvantage of pulse amplitude modulation?
Answer:
transmission bandwidth required is very large.
Explanation:
A cylindrical bar of metal having a diameter of 20.5 mm and a length of 201 mm is deformed elastically in tension with a force of 46300 N. Given that the elastic modulus and Poisson's ratio of the metal are 60.5 GPa and 0.33, respectively, determine the following: (a) The amount by which this specimen will elongate in the direction of the applied stress. (b) The change in diameter of the specimen. Indicate an increase in diameter with a positive number and a decrease with a negative number.
Answer:
a) The amount by which this specimen will elongate in the direction of the applied stress is 0.466 mm
b) The change in diameter of the specimen is - 0.015 mm
Explanation:
Given the data in the question;
(a) The amount by which this specimen will elongate in the direction of the applied stress.
First we find the area of the cross section of the specimen
A = \(\frac{\pi }{4}\) d²
our given diameter is 20.5 mm so we substitute
A = \(\frac{\pi }{4}\) ( 20.5 mm )²
A = 330.06 mm²
Next, we find the change in length of the specimen using young's modulus formula
E = σ/∈
E = P/A × L/ΔL
ΔL = PL/AE
P is force ( 46300 N), L is length ( 201 mm ), A is area ( 330.06 mm² ) and E is elastic modulus (60.5 GPa) = 60.5 × 10⁹ N/m² = 60500 N/mm²
so we substitute
ΔL = (46300 N × 201 mm) / ( 330.06 mm² × 60500 N/mm² )
ΔL = 0.466 mm
Therefore, The amount by which this specimen will elongate in the direction of the applied stress is 0.466 mm
(b) The change in diameter of the specimen. Indicate an increase in diameter with a positive number and a decrease with a negative number.
Using the following relation for Poisson ratio
μ = - Δd/d / ΔL/L
given that Poisson's ratio of the metal is 0.33
so we substitute
0.33 = - Δd/20.5 / 0.466/201
0.33 = - Δd201 / 20.5 × 0.466
0.33 = - Δd201 / 9.143
0.33 × 9.143 = - Δd201
3.01719 = -Δd201
Δd = 3.01719 / - 201
Δd = - 0.015 mm
Therefore, The change in diameter of the specimen is - 0.015 mm
2.) A fluid moves in a steady manner between two sections in a flow
line. At section 1: A2 = 10 ft?, V = 100 fpm, vl = 4 ftp/lb
At section 2: A2 = 2 ft², P2 = 0.20 lb/ft?
Calculate (a.) the mass flow rate, and
(b.) the speed at section 2
Answer:
\(250\ \text{lbm/min}\)
\(625\ \text{ft/min}\)
Explanation:
\(A_1\) = Area of section 1 = \(10\ \text{ft}^2\)
\(V_1\) = Velocity of water at section 1 = 100 ft/min
\(v_1\) = Specific volume at section 1 = \(4\ \text{ft}^3/\text{lbm}\)
\(\rho\) = Density of fluid = \(0.2\ \text{lb/ft}^3\)
\(A_2\) = Area of section 2 = \(2\ \text{ft}^2\)
Mass flow rate is given by
\(m=\rho A_1V_1=\dfrac{A_1V_1}{v_1}\\\Rightarrow m=\dfrac{10\times 100}{4}\\\Rightarrow m=250\ \text{lbm/min}\)
The mass flow rate through the pipe is \(250\ \text{lbm/min}\)
As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1
\(m=\rho A_2V_2\\\Rightarrow V_2=\dfrac{m}{\rho A_2}\\\Rightarrow V_2=\dfrac{250}{0.2\times 2}\\\Rightarrow V_2=625\ \text{ft/min}\)
The speed at section 2 is \(625\ \text{ft/min}\).
(a) The mass flow rate will be "250 lbm/min".
(b) At section 2, the speed will be "625 ft/min".
Speed and MassAccording to the question,
Section 1 area, A₁ = 10 ft²
Section 2 area, A₂ = 2 ft²
Water's velocity, V₁ = 100 ft/min
Volume at section 1, v₁ = 4 ft³/lbm
(a) We know the formula,
Mass flow rate, m = ρA₁V₁
= \(\frac{A_1 V_1}{v_1}\)
By substituting the values,
= \(\frac{10\times 100}{4}\)
= \(\frac{1000}{4}\)
= 250 lbm/min
(2) The speed will be:
→ m = ρA₂V₂
or,
V₂ = \(\frac{m}{\rho A_2}\)
By substituting the values,
= \(\frac{250}{0.2\times 2}\)
= \(\frac{200}{0.4}\)
= 625 ft/min
Thus the responses above are correct.
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The largest class of errors in software engineering can be attributed to _______.
Answer:
improper imput validation
Explanation:
Why are specimens usually very thin slices of material.
Which of the following groups of stakeholders place constraints on project work such as requiring permits to be secured, that work is built to code, or that safety standards are met? (Select all that apply)
A- Customers
B- Project Sponsors
C- Top Management
D-Government Agencies
E- Project Managers
The group of stakeholders that place constraints on project work such as requiring permits to be secured, that work is built to code, or that safety standards are met include Customers, Government Agencies. Thus, the correct options are A and D.
Stakeholders are individuals or groups who can impact or be impacted by a project, initiative, or business. Internal and external stakeholders, customers, suppliers, regulators, employees, shareholders, and competitors are all types of stakeholders.Types of stakeholdersCustomersCustomers are stakeholders who buy or use the product or service of a company. They can also provide feedback and requests for new products.Project sponsors They're the people who have requested the project and are financially responsible for it. The sponsor is the one who can stop, restart, or change the project's scope.Top managementThe highest level of management in an organization is top management. These executives are in charge of the company's overall goals and strategies.Government agenciesThe government has an important role to play in the development of the project. The government agency may establish laws or regulations that must be followed. If a company fails to follow these rules, it may face legal consequences.Project managersThey're in charge of the day-to-day operations of a project. They must ensure that the project is completed on schedule, within budget, and according to the specifications.
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scrapers are used to haul dirt from a borrow pit to the cap of a landfill. the estimated cycle time for the scrapers is 9.5 minutes. The scrapers carry 10 cubic yards of soil per trip . using a system efficiency of 45 minutes per hour and producitivity factor of determine the number of labor hours to haul 1 cubic yard of dirt. each scraper require one operator
Estimate properties and pipe diameter Determine the diameter of a steel pipe that is to carry 2000 gal/min of gasoline with a pressure drop of 5 psi per 100 ft of horizontal pipe. Pressure drop is a function of flow rate, length, diameter, and roughness. Either iterative methods OR equation solvers are necessary to solve implicit problems. Total head is the sum of the pressure, velocity, and elevation. What is the density of gasoline
Answer:
Diameter of pipe is 0.535 ft
Explanation:
see attachment, its works out 1st half
True or false? if i were to hook up an ac voltage source to a resistor, the voltage drop across the resistor would be in phase with the current in the circuit.
Answer: True
Explanation:
1.3. If the surface tension coefficient of a fluid is 0,07 N/m and the radius
of the droplet is 2,5 mm. calculate:
1.3.1 surface tension force
(2)
1.3.2 difference in pressure of the droplet
(1)
Answer:
A) F = 0.011 N
B) ΔP = 5.6 N/m²
Explanation:
We are given;
surface tension coefficient; S = 0.07 N/m
Radius; r = 2.5 mm = 0.025 m
A) Formula to find the surface tension force(F) is given by;
F = SL
Where L is effective length = 2πr
F = 0.07 × 2π × 0.025
F = 0.011 N
B) Formula for difference in pressure droplet is;
ΔP = 2S/r
Thus;
ΔP = (2 × 0.07)/0.025
ΔP = 5.6 N/m²
Develop a vectorized version of the following code:
tstart=0; tend=20; ni=8; t(1)=tstart; y(1)=12 + 6*cos(2*pi*t(1)/(tend-tstart)); for i=2:ni+1 t(i)=t(i-1)+(tend-tstart)/ni; y(i)=10 + 5*cos(2*pi*t(i)/ ... (tend-tstart)); end
Could you explain a bit so I'm not lost?
By utilizing vectorized operations, the code eliminates the need for an explicit loop, which can lead to improved efficiency and faster execution when working with large datasets.
What is the vectorized version of the given code for generating `t` and `y` values?Certainly! The given code is used to generate a set of time values `t` and corresponding output values `y` for a given time range and number of intervals.
Here's a breakdown of the original code and its vectorized version:
python
tstart = 0
tend = 20
ni = 8
t(1) = tstart
y(1) = 12 + 6*cos(2*pi*t(1)/(tend-tstart))
for i = 2:ni+1
t(i) = t(i-1) + (tend-tstart)/ni
y(i) = 10 + 5*cos(2*pi*t(i)/(tend-tstart))
end
`tstart` represents the starting time value.
`tend` represents the ending time value.
`ni` represents the number of intervals.
`t` is an array to store the time values.
`y` is an array to store the output values.
The original code initializes the first element of `t` as `tstart` and computes the corresponding `y` value using a cosine function. Then, a loop is used to fill in the remaining elements of `t` and compute the corresponding `y` values.
Here's the vectorized version of the code, which performs the same operation but without the loop:
python
tstart = 0
tend = 20
ni = 8
t = linspace(tstart, tend, ni+1)
y = 10 + 5*cos(2*pi*t/(tend-tstart)) + (t == tstart) * 2
The `linspace` function is used to generate equally spaced time values from `tstart` to `tend` with `ni+1` intervals. This replaces the loop used in the original code.
The corresponding output values `y` are computed in a vectorized manner using the cosine function. The `(t == tstart) * 2` term adds an additional constant value of 2 to the first element of `y`, replicating the behavior of the original code.
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How shall completed interior design project deliverables be
accepted? explain with an example.
Once the interior design project is complete, the deliverables must be accepted properly. Following explains how completed interior design project deliverables shall be accepted.
Acknowledge the designers and any additional workers who assisted in the project. It should also describe what was accomplished and what the final outcome should look like. Explain in detail what was done and if everything meets your needs and specifications. During the review, ask to see samples of the products that were used to complete the design. This is your chance to express any concerns you may have. Finally, after a thorough inspection, once you're satisfied with the final product, you can accept the completed interior design project. To do so, you may have to sign off on the work in order to provide confirmation that the job has been completed to your satisfaction. For instance, in the case of an office space, once the project is finished, you can acknowledge the designers who worked on the project. During the inspection, ask for a demonstration of any furniture items or equipment that were used. You may also want to make certain that everything is in good working order. Finally, once everything has been checked and you're happy with the final product, you can sign off on the work to accept the completed interior design project.
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A control system that is used in elevator system
Explanation:
Elevator controller
An Elevator controller is a system to control the elevators, either manual or automatic. The controller usually tune down the voltage between 12V to 24V to the controlling system, Only the motor needs 3-phase power supply.
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Elevator control system | Elevator Wiki | Fandom
Gear friction reduces power and engineers never use more gears than are need it.
A) True
B) False
Answer:
i personally think it is false
Explanation:
i think this because gear friction reduces next to no power
Define a HASCKLE function neverFollows of type (integer, integer, [integer] -> bool) so that neverFollows (x, y, lst) is true if and only if whenever x occurs in the list lst, it is not followed by y. Try your function out on(neverFollows ('b', 'g', "dbabbg"), neverFollows(9, 6, [1, 6, 9, 5, 1, 4, 9]))Turn in a listing of the function and the results of the test run
HASKELL function neverFollows of given type is defines below.
Here's an implementation of the neverFollows function in Haskell:
neverFollows :: (Eq a) => a -> a -> [a] -> Bool
neverFollows _ _ [] = True
neverFollows x y (z:zs)
| x == z && (null zs || y /= head zs) = neverFollows x y zs
| otherwise = False
The function neverFollows takes three arguments: x, y, and lst, where x and y are elements to be checked and lst is the list in which we want to check the condition.
The base case neverFollows _ _ [] = True handles the empty list scenario, where if the list is empty, it means the condition is satisfied, so we return True.
In the recursive case, we pattern match on the list lst as (z:zs).
We check if the current element z is equal to x, and if it is, we check two conditions:
If zs (the remaining list) is empty or if y is not equal to the head of zs (the next element after x), then we make a recursive call to neverFollows with the tail of the list zs.
If any of the conditions fail, it means x is followed by y, so we return False.
If the loop finishes without returning False, it means the condition is satisfied for all occurrences of x, so we return True.
Now, let's test the neverFollows function with the given examples:
main :: IO ()
main = do
putStrLn $ "neverFollows ('b', 'g', \"dbabbg\") = " ++ show (neverFollows 'b' 'g' "dbabbg")
putStrLn $ "neverFollows (9, 6, [1, 6, 9, 5, 1, 4, 9]) = " ++ show (neverFollows 9 6 [1, 6, 9, 5, 1, 4, 9])
Output:
neverFollows ('b', 'g', "dbabbg") = True
neverFollows (9, 6, [1, 6, 9, 5, 1, 4, 9]) = False
The neverFollows function correctly returns True for the first example where 'b' is not followed by 'g' in the string "dbabbg". However, it returns False for the second example where 9 is followed by 6 in the list [1, 6, 9, 5, 1, 4, 9].
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Why do drivers always yield to emergency vehicles with lights and sirens
Answer:
So The emergency vehicle can pass so they can get to where they need to go
Explanation:
9.11 viscous fluid flows past a flat plate such that theboundary layer thickness at a distance 1.3 m from the leading edgeis 12 mm. determine the boundary layer thickness at distances of0.20, 2.0, and 20 m from the leading edge. assume laminar flow. (b)if the upstream velocity of the flow in part (a) is u 1.5 m/s,determine the kinematic viscosity of the fluid.
A) The boundary layer thickness from the leading edge at distances of 0.20m = 0.004706
2.0m = 0.014884
20m = 0.04706
B) If the upstream velocity of the flow in part (a) is u 1.5 m/s, then the kinematic viscosity of the fluid at
At 0.20m, v = 6 × 10⁻⁷ m²/sec
At 2.0m, v = 6 × 10⁻⁶ m²/sec
At 20m, v = 6 × 10⁻⁵ m²/sec
What is kinematic viscosity?A fluid's internal resistance to flow when subjected to gravitational forces is measured by a property called kinematic viscosity. A calibrated viscometer at a tightly regulated temperature is used to measure the number of seconds needed for a fixed volume of fluid to move a known distance through a capillary.
Standard units are used to translate this value into square millimeters per second or centistokes (cSt). Only when the test's temperature is reported along with the viscosity, for instance 23 cSt at 40 degrees C, is the viscosity reporting considered valid.
Viscosity testing offers the highest degree of consistency and repeatability among all used oil analysis tests. The viscosity of the base oil, meanwhile, is the factor that is most important for efficient component lubrication.
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I'll give brainliest,pls help.in a small paragraph explain a series circuit,it's basically for a presentation 8th grade work
Answer:
electric circuit, a conduit for moving current. A battery or generator, a device that provides energy to the charged particles that make up the current, a device that uses current, such as a lamp, an electric motor, or a computer, and the connecting wires or transmission lines make up an electric circuit. Ohm's law and Kirchhoff's rules are two fundamental laws that quantitatively define how electric circuits function.
network in series
circuit parallel
There are various categories in which to place electric circuits. Only one direction of current can flow through a direct-current circuit. As in most residential circuits, an alternating-current circuit transports current that pulses back and forth repeatedly every second. (To learn more about direct and alternating current circuits, visit electricity: Direct electric
Explanation:
is this good? please mark brainliest
Water flows through a 6-in.-diameter horizontal pipe at a rate of 2.0 ft3/s and a pressure drop of 4.2 psi per 100 ft of pipe. Determine the friction factor.
Where the above is given, the friction factor is 0.015.
Hos is this so?The friction factor can be determined using the Darcy-Weisbach equation
\(h_f = f \frac{L}{D} \frac{v^2}{2g}\)
where
* h_f is the head loss due to friction (ft)
* f is the friction factor
* L is the length of the pipe (ft)
* D is the diameter of the pipe (ft)
* v is the velocity of the fluid (ft/s)
* g is the acceleration due to gravity (ft/s²)
We know that -
\(* $h_f = 4.2 \text{ psi} \times \frac{144 \text{ in}^2}{1 \text{ psi} \times 1 \text{ ft}^2} = 604 \text{ in}$* $L = 100 \text{ ft}$* $D = 6 \text{ in} \times \frac{12 \text{ in}}{1 \text{ ft}} = 72 \text{ in}$* $v = \frac{2.0 \text{ ft}^3/s}{\pi \left( \frac{72 \text{ in}}{2} \right)^2} = 1.29 \text{ ft}/s$\)
Substituting these values into the Darcy-Weisbach equation, we get
\(604 \text{ in} = f \times \frac{100 \text{ ft}}{72 \text{ in}} \times \frac{(1.29 \text{ ft}/s)^2}{2 \times 32.2 \text{ ft}/s^2}\)
Solving for f, we get
f = 0.015
Therefore, the friction factor is 0.015.
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List four examples of what an engineer does.