Can anyone tell me what is new about atomic theory over the last 23 years?

Answer:

here is answer!

Explanation:

Question 1:

Light bends when it transitions from air to glass due to differences in refractive indices. It follows an incident path in air, refracts at the air-glass boundary, and continues through the glass as a transmitted ray. Total internal reflection may occur if the angle of incidence is large enough.

Question 2:

Brightness in the wave model of light is determined by the amplitude and intensity of the light waves. Higher amplitudes and intensities correspond to brighter light. When multiple light waves overlap, their amplitudes add up, resulting in increased brightness

Given:

The voltage of the battery, V=10.0 V

The resistor of the resistance, R=2.00 Ω

To find:

The current coming out of the battery.

Explanation:

From Ohm's law, the voltage across a circuit is directly proportional to the current through the circuit.

Thus, the voltage of the battery is given by,

Where I is the current coming out of the battery.

On substituting the known values,

Final answer:

The current coming out of the battery is 5.00 A.

Thus the correct answer is option E.

Answer:

See Below

Explanation:

Mass of child = 21 kg

Mass of bicycle = 5.9 kg

Total mass = 22 + 5.9 = 27.9 kg

Velocity = 4.5 m/s

1) Total momentum of the child and the bike together

= Total mass * Velocity

= 27.9*4.5

= 125.55 kg m per second

2) Momentum of the child

= Mass of child*Velocity

= 21*5.9

= 123.9 kg m per second

3) Momentum of the bike

= Mass of bike*Velocity

= 5.9*4.5

= 26.55 kg m per second

The final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

The time of motion of the girl is calculated as follows;

h = vt + ¹/₂gt²

where;

Substitute the given parameters and solve for time of motion;

50.8 = 0 + ¹/₂(9.8)t²

2(50.8) = 9.8t²

101.6 = 9.8t²

t² = 101.6/9.8

t² = 10.367

t = √10.367

t = 3.22 seconds

vf = vi + gt

where;

vi is the initial vertical velocity = 0

vf = 0 + 9.8(3.22)

vf = 31.56 m/s

Thus, the final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

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Answer:

The factors include age and puberty

Explanation:

Glandular secretion release chemicals such as hormones in response to the body’s metabolic needs.

As an individual ages , the metabolic rate of the body also reduces . This is due to the stress and ageing of the cells of the body. This explains why glandular secretion is optimal with young people and Lower in older people. It also explains why the immune system of a young person is mostly stronger than older people.

Puberty is another factor which affects glandular secretion as during puberty there is usually a high amount of hormonal changes due to high levels of secretions of some hormones. These hormones could however inhibit the other glandular secretions.

Answer: 134 = 143 = 151 = 166 = 176

Hope this helps!!

Sorry if it's incorrect!!

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Answer:

12g/cm³

Explanation:

Given parameters:

Mass of the metal  = 1200g

Volume of water in the measuring cylinder  = 150cm³

Volume of the metal  = 100cm³

Unknown:

Density of the metal  = ?

Solution:

Density is the mass per unit volume of a substance;

  Density  = \(\frac{mass}{volume}\)

Now insert the parameters and solve;

    Density  = \(\frac{1200}{100}\)   = 12g/cm³

The particle is moving toward the wall and is being deflected at the same time.

The time to reach the wall will be 18.4/7.2  =2.56 sec. The direction of the acceleration is not specified but since the ask for how high  we will assume it is upward. S=1/2 at^2  t= 2.56.

s = 0.5X 1.7 m/s 2 x 2.56*2.56 = 5.5 meters. Two velocities on x one way  the up velocity  is 1.7*2.56 = 4.3 m/s or the arctan of  4.3/7.2 =30.8 degrees.

Vertical gardens, sometimes known as "green walls," are large-scale plant arrangements that are affixed to wall-mounted structures. They serve as an effective ornamental element while also being quite practical because they improve the indoor air quality and the comfort level of the surrounding area.

Therefore, The particle is moving toward the wall and is being deflected at the same time.

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Answer:

special change will happen between popcorn and floor it falls on love and attractions and do marriage . they will get baby after 1 year

Although we do not have the necessary information to provide an exact answer, we can confirm that the object will have fallen by a multiple of 9.8 meters due to gravity.

When an object is dropped, its acceleration is determined by gravity. This force applies a constant acceleration of 9.8 meters per second. Therefore, to calculate its speed at distance h, we would need to know the time it has taken the object to reach this point, and use that together with our known acceleration in order to calculate its current speed.

Therefore, we can confirm that in order to calculate the current speed of the object at point h, we require the time taken to reach this point or the value of the distance itself and that the answer will be a multiple of 9.8, due to gravity.

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Answer:

10.88kJ

Explanation:

Given data

mass= 10kg

heigth= 111m

Applying

PE= mgh

assume g= 9.81m/s^2

substitute

PE= 10*9.81*111

PE=10889.1 Joules

PE=10.881kJ

Hence the potential energy is 10.88kJ

Change in velocity per unit time.

Explanation

Acceleration is defined as rate of change of velocity w.r.t time.

\(\boxed{\sf Acceleration=\dfrac{dv}{dt}}\)

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;

Take moment about the joint to determine the magnitude of the force along part BC.

120 kN x 750 mm  =  F x 1000 mm

F = ( 120 kN x 750 mm ) / ( 1000 mm )

F = 90 kN

Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.

Stress in AB = 2 times stress in BC

P/A₁  = 2F/A₂

where;

A₁ =  πd²/4  =  π(50 x 10⁻³)²/4

A₁ = 1.96 x 10⁻⁵ m²

A₂ = πd²/4  =  π(75 x 10⁻³)²/4

A₂ = 4.42 x 10⁻³ m²

P/A₁ = 2F/A₂

P = (2F x A₁) / (A₂)

P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = 798.2 N

P = 0.798 kN

P ≈ 0.8 kN

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Answer: 3 dimensional solid like cubes and parallelepipeds

Explanation:

Field investigations and classroom experiments can differ in several ways due to the unique characteristics and limitations of each setting.

Here are some reasons why field investigations can differ from classroom experiments:Real-world context: Field investigations take place in the natural environment, allowing students to observe and study phenomena in their natural setting. This context provides a more authentic experience and helps students understand the complexities and interactions of the real world. In contrast, classroom experiments often involve controlled conditions that may not accurately reflect real-world scenarios.Complexity and unpredictability: Field investigations often deal with complex and unpredictable variables, such as weather, terrain, and natural processes. This complexity can make it challenging to control and manipulate variables compared to classroom experiments, where conditions can be tightly controlled.Scale and scope: Field investigations can involve larger scales and broader scopes than classroom experiments. For example, studying the ecosystem of a forest or the geological features of a landscape requires observing and collecting data over a large area, which may not be feasible within a classroom setting.Resources and equipment: Classroom experiments often have access to a controlled and well-equipped laboratory, whereas field investigations may require specialized equipment, transportation, and logistical planning to conduct research in the field. This can add logistical challenges and resource constraints to field investigations. Ethical considerations: Field investigations may involve interactions with living organisms and ecosystems, raising ethical considerations related to environmental impact and the well-being of organisms. Classroom experiments, on the other hand, can be designed with ethical considerations in mind, ensuring the well-being and safety of participants.Overall, field investigations provide students with valuable opportunities to engage with the natural world, understand its complexity, and develop skills in observation, data collection, and critical thinking. Classroom experiments, on the other hand, offer controlled environments for testing specific hypotheses and concepts. Both approaches have unique benefits and play important roles in science education, providing complementary learning experiences for students.

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Mechanical energy changes when a roller coaster starts at a height of 40 meters and reaches a height of 20 meters. The potential energy decreases, while the kinetic energy increases.

When a roller coaster starts at a height of 40 meters and reaches a height of 20 meters, mechanical energy changes. In physics, mechanical energy is the sum of potential and kinetic energy that is present in the objects. When an object is moved, it gains or loses energy, thus the mechanical energy changes. There are two forms of mechanical energy, namely kinetic energy and potential energy. Kinetic energy is the energy that a moving object possesses due to its motion, while potential energy is the energy that an object possesses due to its position or shape.
In the case of a roller coaster, when it starts at a height of 40 meters, it has potential energy that is equal to its mass multiplied by the acceleration due to gravity multiplied by its height. As it moves down the track, the potential energy gets converted into kinetic energy, which is the energy of motion. When the roller coaster reaches a height of 20 meters, it has a lower potential energy compared to when it started. The difference in potential energy is equal to the amount of work done by the force of gravity in bringing the roller coaster down from a height of 40 meters to a height of 20 meters. At the same time, the roller coaster has a higher kinetic energy than when it started, as it gained speed during the descent.
Therefore, in summary, mechanical energy changes when a roller coaster starts at a height of 40 meters and reaches a height of 20 meters. The potential energy decreases, while the kinetic energy increases.

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a) The car moved 73.333 feet when its speed has been reduced to 30 miles per hour.

b) The car moved 117.333 feet when its speed has been reduced to 15 miles per hour.

c) The curve is described by \(v = \sqrt{4356 -33\cdot \Delta s}\), where \(v\), in feet per second, and \(\Delta s\), in feet, and the graph is included in the image below.

In this question we must use the following kinematic formula to determine the deceleration rate (\(a\)), in feet per square second, experimented by the vehicle:

\(a = \frac{v^{2}-v_{o}^{2}}{2\cdot \Delta s}\) (1)

Where:

If we know that \(\Delta s = 132\,ft\), \(v_{o} = 66\,\frac{ft}{s} \left(45\,\frac{mi}{h}\right)\) and \(v = 0\,\frac{ft}{s}\), the deceleration rate experimented by the car is:

\(a = \frac{\left(0\,\frac{ft}{s}\right)^{2}-\left(66\,\frac{ft}{s} \right)^{2}}{2\cdot (132\,ft)}\)

\(a = -16.5\,\frac{ft}{s^{2}}\)

By using (1) and knowing that \(v_{o} = 66\,\frac{ft}{s} \,\left(45\,\frac{mi}{h} \right)\), \(v = 44\,\frac{ft}{s}\left(30\,\frac{mi}{h} \right)\) and \(a = -16.5\,\frac{ft}{s^{2}}\), we find the distance travelled by the vehicle:

\(\Delta s = \frac{v^{2}-v_{o}^{2}}{2\cdot a}\) (1b)

\(\Delta s = \frac{\left(44\,\frac{ft}{s} \right)^{2}-\left(66\,\frac{ft}{s} \right)^{2}}{2\cdot \left(-16.5\,\frac{ft}{s^{2}} \right)}\)

\(\Delta s = 73.333\,ft\)

The car moved 73.333 feet when its speed has been reduced to 30 miles per hour. \(\blacksquare\)

By using the same approach used in part (a) and knowing that  \(v_{o} = 66\,\frac{ft}{s} \,\left(45\,\frac{mi}{h} \right)\), \(v = 22\,\frac{ft}{s}\left(15\,\frac{mi}{h} \right)\) and \(a = -16.5\,\frac{ft}{s^{2}}\), we find the distance travelled by the vehicle:

\(\Delta s = \frac{v^{2}-v_{o}^{2}}{2\cdot a}\)

\(\Delta s = \frac{\left(22\,\frac{ft}{s} \right)^{2}-\left(66\,\frac{ft}{s} \right)^{2}}{2\cdot \left(-16.5\,\frac{ft}{s^{2}} \right)}\)

\(\Delta s = 117.333\,ft\)

The car moved 117.333 feet when its speed has been reduced to 15 miles per hour. \(\blacksquare\)

In this case we must use (1) in the following form to obtain every speed associated with each travelled distance:

\(v = \sqrt{v_{o}^{2}+2\cdot a\cdot \Delta s}\) (1c)

If we know that \(v_{o} = 66\,\frac{ft}{s} \,\left(45\,\frac{mi}{h} \right)\) and \(a = -16.5\,\frac{ft}{s^{2}}\), then we have the following formula and respective graph.

\(v = \sqrt{4356 -33\cdot \Delta s}\) \(\blacksquare\)

And the graph is presented in the image attached below. \(\blacksquare\)

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To calculate the torque required to create an angular acceleration, we can use the formula:

Torque = Moment of Inertia × Angular Acceleration

The moment of inertia of a disk can be calculated using the formula:

Moment of Inertia = (1/2) × Mass × Radius^2

Given:

Mass = 15,000 kg

Radius = 6.14 m

Angular Acceleration = 0.0500 rad/s^2

First, calculate the moment of inertia:

Moment of Inertia = (1/2) × Mass × Radius^2

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Next, calculate the torque:

Torque = Moment of Inertia × Angular Acceleration

Torque = Moment of Inertia × 0.0500 rad/s^2

Now, let's plug in the values and calculate:

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Moment of Inertia ≈ 283,594.13 kg·m^2

Torque = 283,594.13 kg·m^2 × 0.0500 rad/s^2

Torque ≈ 14,179.71 N·m

Rounding to three significant figures, the torque required to create an angular acceleration of 0.0500 rad/s^2 is approximately 14,180 N·m.

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Answer:

(a) 29.0m/s

(b) 42.05m

Explanation:

(a) Since the motion is in one dimension (i.e vertical), we can use one of the equations of motion as follows;

v = u + at            ------------(i)

Where;

v = final velocity of the baseball at a time t

u = initial velocity of the baseball at launch time

a = acceleration due to gravity

t = time taken to reach a certain height

Now;

At maximum height;

v = 0  (velocity is zero when the baseball reaches maximum height)

t = 2.90s

a = -g = -10m/s² (negative sign because the base ball moves upwards against gravity)

Substitute these values into equation (i) as follows;

0 = u - 10(2.90)

u = 29.0m/s

Therefore, the initial velocity of the baseball is 29.0m/s

(b) To get the height reached we use another equation of motion as follows;

Using one of the equations of motion as follows;

v² = u² + 2as             -----------------(ii)

Where;

v = final velocity of the baseball

u = initial velocity of the baseball

a = acceleration of the baseball

s = vertical distance covered by the baseball

Remember that;

At maximum height,

v = 0

Also,

u = 29.0m/s     (as calculated above)

a = -10m/s²

Substitute these values into equation(ii) as follows;

0² = 29.0² + 2(-10)s

0 = 841 - 20s

841 = 20s

s =  \(\frac{841}{20}\)

s = 42.05m

Therefore, the maximum height reached is 42.05m

Explanation:

\(V = f \lambda \\ 15.0 = 9.3 \lambda \\ \lambda = \frac{15}{9.3} \\ \lambda = 1.61 \: m\)

Answer:

plane on edge

Explanation:

For an airplane whose speed is 60 m/s is flying at an altitude of 500 m over the ocean toward a stationary sinking ship, the horizontal distance  is mathematically given as

x=606m

Generally, the equation for the y axis distance  is mathematically given as

y=vt+0.5gt^2

Therefore

500=0t+1.2(9.8)t^2

t=10.1s

In conclusion,  the horizontal distance

x=vt

x=60*10.1

x=606m

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Answer:

78 kg/s^2

Explanation:

Answer = 78 kg per second squared

Force = mass (acceleration)

F = (6)(13)

F = 78 kg / sec squared

Answer:

The angular acceleration of the wheel is 15.21 rad/s².

Explanation:

Given that,

Time = 5 sec

Final angular velocity = 96.0 rad/s

Angular displacement = 28.0 rev = 175.84 rad

Let \(\alpha\) be the angular acceleration

We need to calculate the angular acceleration

Using equation of motion

\(\theta=\omega_{i} t+\dfrac{1}{2}\alpha t^2\)

Put the value in the equation

\(175.84=\omega_{i}\times 5+\dfrac{1}{2}\times\alpha\times(5)^2\)

\(175.84=\omega_{i}\times 5+12.5\alpha\)......(I)

Again using equation of motion

\(\omega_{f}=\omega_{i}+\alpha t\)

Put the value in the equation

\(96.0=\omega_{i}+\alpha \times 5\)

On multiply by 5 in both sides

\(480=\omega_{i}\times 5+\alpha\times 25\)....(II)

On subtract equation (I) from equation (II)

\(480-175.84=\alpha(25-5)\)

\(304.16=\alpha\times20\)

\(\alpha=\dfrac{304.16}{20}\)

\(\alpha=15.21\ rad/s^2\)

Hence, The angular acceleration of the wheel is 15.21 rad/s².

The volume of the piece of metal is 3×10⁻⁵ m³ and the density of the piece of metal is 6666.67 kg/m³.

To calculate the volume of the metal piece, we use the formula below.

Using formula,

Dw = (m-m')g/Vg       (Equation 1)

where,

Dw = density of water

V = volume of water displaced by the metal = volume of the metal piece.

m = mass of the metal in the air

m' = mass of the metal in water

g = acceleration due to gravity

V is the subject of the equation,

V = (m-m)/Dw      (Equation 2)

From the question,

Given,

Dw = 1000 kg/m³

m = 200 g

m = 0.2 kg

m' = 170 g

m' = 0.17 kg

g = 9.8 m/s²

Putting these values into equation 2

V = (0.2-0.17) / 1000

V = 0.03 / 1000

V = 0.00003 m³

V = 3×10⁻⁵ m³

To calculate the density of the metal piece, we use the formula below

Using formula,

D = m/V      (Equation 3)

Where,

D = Density of the metal piece

m = mass of the metal piece in the air

V = Volume of the metal piece.

Given,

m = 200 g

m = 0.2 kg

V = 0.00003 m³

Putting these values into equation 3

D = 0.2 / (0.00003)

D = 6666.67 kg/m³

Thus, the volume of the piece of metal is 3×10⁻⁵ m³ and the density of the piece of metal is 6666.67 kg/m³.

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Answer:

4.552m/s

Explanation:

\(V=\frac{m_{1}v_{1}+m_{2}v_{2}}{m_{1} } =\frac{2400*4.33+60*8.88}{2400}=4.552m/s\)

The answer is  energy 3 times as much. option A.

To calculate the amount of energy released when a 5 kg object is converted to pure energy, we can use Einstein's famous equation: E = mc². In this equation, E represents energy, m represents mass, and c represents the speed of light.

Given that the mass of the object is 5 kg, we can calculate the energy using the equation:

E = (5 kg) * (c²)

Now, to compare this energy with the amount of energy the Earth receives from the Sun every second, we need to determine the Earth's solar energy input.

The solar constant is the amount of solar radiation received per unit area at the Earth's distance from the Sun. Its average value is approximately 1361 Watts per square meter (W/m²). Multiplying this value by the surface area of the Earth (approximately 510 million square kilometers), we can estimate the total energy received by the Earth from the Sun every second.

Energy from the Sun = (1361 W/m²) * (510,000,000,000 m²)

To compare the energy released from converting a 5 kg object to energy with the energy received from the Sun, we divide the former by the latter:

Energy conversion / Energy from the Sun = [(5 kg) * (c²)] / [(1361 W/m²) * (510,000,000,000 m²)]

Simplifying the equation, we find:

Energy conversion / Energy from the Sun = (5 kg * c²) / (1361 W/m² * 510,000,000,000 m²)

The value of c² is approximately (3x10^8 m/s)² = 9x10^16 m²/s².

Plugging in the values, we get:

Energy conversion / Energy from the Sun = (5 kg * 9x10^16 m²/s²) / (1361 W/m² * 510,000,000,000 m²)

Simplifying further:

Energy conversion / Energy from the Sun ≈ 3.52

Therefore, the amount of energy released when a 5 kg object is converted to pure energy is approximately 3.52 times larger than the amount of energy the Earth receives from the Sun every second.

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