Yes, an object can have zero velocity and non-zero acceleration at the same time.
Let's take an example of a tennis ball. If we throw the tennis ball vertically upward, the ball will have zero velocity at the highest point. At that point, the gravity is still acting downwards on the tennis ball. At this point, the ball has zero velocity and accelerates downward with gravitational acceleration = 9.8m/s.
Another example is oscillatory motion. In oscillatory motion, the acceleration is always opposite to the velocity. When the velocity becomes zero at the extreme position the body has non-zero acceleration.
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Compared to the inertia of a 2.0 kg ball, the inertia of a 4.0 kg ball is
A) Half as great
O B) twice as great
the same
OD) four times as great
a 0.12 g honeybee acquires a charge of 22pc while flying. the earth's electric field near the surface is typically (100 n/c , downward).
A). What is the ratio of the electric force on the bee to the bee's weight? Fe/W = ?
B). What electric field strength would allow the bee to hang suspended in the air? (in N/C)
C). What would be the necessary electric field direction for the bee to hang suspended in the air? Upward, downward or horizontally directed?
A. the ratio of electric force on the bee to the bee's weight is\(1.87 * 10^{-9}\), B. the electric field strength required to suspend the bee in air is \(4.72 * 10^6 N/C\), and C. the electric field direction for a bee to hang suspended in air must be upward.
A) To calculate the ratio of the electric force on the bee to the bee's weight, we need to first find the electric force acting on the bee. Using the formula F = qE, where q is the charge on the bee and E is the electric field strength, we get:\(F = (22 pc)(100 n/C) = 2.2 * 10^{-12} N\)To find the weight of the bee, we can use the formula W = mg, where m is the mass of the bee and g is the acceleration due to gravity (\(9.8 m/s^2)\):\(W = (0.12 g)(9.8 m/s^2) = 1.176 * 10^{-3} N\)Now, we can calculate the ratio of electric force to weight:\(Fe/W = (2.2 * 10^{-12} N)/(1.176 * 10^{-3} N) = 1.87 * 10^{-9}\)Therefore, the ratio of electric force on the bee to the bee's weight is \(1.87 * 10^{-9}\).B) For the bee to hang suspended in the air, the electric force on the bee should be equal and opposite to the weight of the bee. Thus, we can set F = W and solve for E:qE = mg\(E = (mg)/q = (0.12 g)(9.8 m/s^2)/(22 pc) = 4.72 * 10^6 N/C\)Therefore, the electric field strength required to suspend the bee in air is\(4.72 * 10^6 N/C.\)C) Since the electric field near the surface of the earth is typically directed downward, the necessary electric field direction for the bee to hang suspended in air would be upward.For more such question on electric force
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A massive light hangs over the table in Jeremy's dining room. The light is supported by four strong chains which make an angle of 72° with the horizontal. The force in each chain is 36.4 N. Determine the mass of the light in kilograms (kg). Use the approximation g ≈ 10 m/s^2.
Given
A massive light hangs over the table in Jeremy's dining room. The light is supported by four strong chains which make an angle of 72° with the horizontal.
The force in each chain is F=36.4 N.
To find
The mass of the light in kg
Explanation
Let the mass of the light be m
The weight of the light acts downwards.
To balance thisi force the force on the string vertically upward is considered
In equillibrium
\(\begin{gathered} mg=4Fsin72^o \\ \Rightarrow10m=4\times36.4\times sin72^o \\ \Rightarrow m=13.84\text{ kg} \end{gathered}\)Conclusion
The mass of the light is 13.84 kg
When a body is lifted through a height h, the work done on it appears in the form of its: (a) kinetic energy (b) potential energy (c) elastic potential energy (d) geothermal energy
The work done on a body when it is lifted through a height h appears in the form of its potential energy. Therefore, option (b) is the correct answer.
What is Geothermal Energy?
Geothermal energy is a type of renewable energy that is derived from the heat generated deep beneath the Earth's surface. It is produced by harnessing the naturally occurring heat from the Earth's core, which can be used to generate electricity or heat buildings directly. This energy can be accessed by drilling deep wells into the Earth's crust and tapping into the hot water and steam that is naturally present in underground reservoirs.
When a body is lifted through a height h, the work done on it appears in the form of potential energy. This is because the energy is stored in the body due to its position or configuration, rather than its motion.
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Which statement correctly identifies the products in photosynthesis?
CO2 + H2O
C6H12O6 + O2
CO2 + H2O + O2
C6H12O6 + O2 + energy
Answer:
CO2 + H2O + O2
Explanation:
The correct statement that identifies the products of photosynthesis is C6H12O6 + O2. In photosynthesis, carbon dioxide, water, and light are used to produce glucose and oxygen.
Explanation:Photosynthesis is a biological process that converts light energy, usually from the Sun, into chemical energy in plants, algae and certain types of bacteria. The photosynthesis formula is usually depicted as: 6CO2 + 6H2O + light energy = C6H12O6 + 6O2. This means that the correct statement that identifies the products of photosynthesis is C6H12O6 + O2. In this reaction, carbon dioxide (CO2), water (H2O) and light are used to produce glucose (C6H12O6) and oxygen (O2). The glucose is used by the plant for energy and growth while oxygen is a byproduct released into the atmosphere.
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If Wile E. Coyote had enough money to buy all that ACME stuff, why didn't he just buy dinner?
Answer:
I dont know but nice question
Explanation:
I laughed super hard when I saw this
What type of reproduction occurs when a cell divides to form two new cells?
a. autotrophic b. heterotrophic c. asexual reproduction d. sexual reproduction
Answer:
d. sexual reproduction
Explanation:
A single cell divides to make two cells and these two cells then divide to: we call this process "cell division" and "cell reproduction," and there are two ways cells divide—mitosis and meiosis. This is all part of sexual reproduction.
The electric force generated by two point charges separated by Distance A is 4 times greater than the electric force generated when separated by distance B. How does Distance A compare to Distance B?
A. Distance A is longer by a factor of 2
B. Distance A is longer by a factor of 4
C. Distance A is shorter by a factor of 2
D. Distance A is shorter by a factor of 4
if a person is weighs 800 n and is sitting on double pulley, how much force is needed to move the man
To move a person weighing 800 N using a double pulley system, a force of 400 N is needed.
To calculate the force needed to move a person weighing 800 N using a double pulley system, you can use the following steps:
1. Determine the person's weight: In this case, the person weighs 800 N.
2. Identify the type of pulley system: Here, it's a double pulley system.
3. Calculate the mechanical advantage: For a double pulley system, the mechanical advantage is 2.
4. Divide the person's weight by the mechanical advantage to find the force needed: 800 N / 2 = 400 N.
To move a person weighing 800 N using a double pulley system, a force of 400 N is needed.
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Dave Ramsey mentions that insurance is the defense for managing your money. Why is this true?
It is true that insurance is the defense for managing money because it ensures that your money is efficiently utilized even in your absence.
What is insurance?Insurance refers to a means of indemnity against a future occurrence of an uncertain event such as an accident, death, robbery etc.
Insurance is a way to protect one's assets from getting lost when faced with unforeseen circumstances.
For example;
A liability insurance protects one in case another person sues for injuries or loss caused by one's negligence or improper actions. Life insurance protects one's beneficiaries from loss of income by paying them money after one's death.Therefore, it is true that insurance is the defense for managing money because it ensures that your money is efficiently utilized even in your absence.
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A box has a mass of 75 g. It has a length of 2.0 cm, a width of 2.0 cm and a height of 3.0 cm. What is the density?
Answer:
6.25 g/cm³
Explanation:
2 cm * 2 cm * 3 cm = 12 cm³ (volume)
75 g / 12 cm³ = 6.25 g/cm³
What is the use of intrinsic attributes?
Intrinsic attributes refer to the inherent characteristics or qualities of an object, concept, or entity. These attributes are essential in defining and understanding the nature of something.
The use of intrinsic attributes can vary depending on the context, but here are a few common applications:
1. Classification and categorization: Intrinsic attributes help in categorizing and classifying objects or entities based on their inherent properties. For example, in a product catalog, intrinsic attributes such as size, color, and material are used to classify items into different categories.
2. Descriptive analysis: Intrinsic attributes analyze and describe objects by detailing their characteristics and features. Product reviews use attributes like performance, durability, and design for comprehensive evaluations.
3. Search and retrieval: Intrinsic attributes aid information retrieval by enabling efficient search and filtering. Attributes like author, title, and genre in a book database facilitate specific book searches.
4. Decision making: Intrinsic attributes are often used as factors in decision-making processes. By considering the intrinsic attributes of various options, individuals or systems can make informed choices. For example, when purchasing a car, attributes such as fuel efficiency, safety features, and price are considered to make a decision.
5. Personalization and customization: Intrinsic attributes personalize experiences by tailoring offerings to individual preferences. E-commerce websites utilize attributes like purchase history and preferences for personalized recommendations. Customization based on intrinsic attributes enhances user satisfaction and engagement.
Overall, the use of intrinsic attributes helps in understanding, organizing, and making informed decisions about objects, concepts, or entities by considering their inherent qualities and characteristics.
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Suppose that you walk 15 meters at 30 degrees as measured from the East. Then you walk another 25 meters at 60 degrees from the East what is your net displacement
Answer:
The net displacement is
\(R= \sqrt{A^2+B^2+2AB \cos \theta}\)
\(=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m\)
Explanation:
Suppose that you walk 15 meters at 30 degrees as measured from the East. Then you walk another 25 meters at 60 degrees from the East what is your net displacement
Given data
A = 15 m
B = 25 m
Angle between the vectors A and B is θ = 30°
The net displacement is
\(R= \sqrt{A^2+B^2+2AB \cos \theta}\)
\(=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m\)
What is the oxidation number of oxygen in HNO3?
a cepheid variable is an object considered to be a 'standard candle.' why are cepheid variables important?
A Cepheid variable is an important astronomical object because it is considered a "standard candle." A standard candle is a type of astronomical object that has a well-known intrinsic brightness, which allows astronomers to use it to determine the distance to other objects in the universe.
Since Cepheid variables are relatively bright and can be observed in distant galaxies, they have been used extensively to measure the distances to galaxies beyond our own Milky Way. This has allowed astronomers to map the large-scale structure of the universe and study the expansion of the universe itself. In fact, the discovery of Cepheid variables played a crucial role in the development of modern cosmology and the determination of the Hubble constant, which describes the rate at which the universe is expanding.
In summary, Cepheid variables are important because they are a reliable way for astronomers to measure distances to other galaxies, which in turn has allowed us to better understand the large-scale structure of the universe and the fundamental properties of our cosmos.
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Find the electric field E⃗ (r⃗ )E→(r→)E_vec(r_vec) inside the sphere (for rrr< aaa) in terms of the position vector r⃗ r→r_vec. Express your answer in terms of r⃗ r→r_vec, rhorhorho (Greek letter rho), and ϵ0ϵ0epsilon_0.
Solution :
Using the Gauss law, the electric field intensity of a sphere is given by :
\($E. 4 \pi r^2 = \frac{Q_{enc}}{\epsilon_0}$\)
\($E = \frac{Q_{enc}}{4 \pi r^2 \epsilon_0}$\)
Now the enclosed charge inside the sphere (r<a) is
\($Q_{enc}= \rho V$\)
\($Q_{enc}= \rho \left( \frac{4}{3} \pi r^3 \right)$\)
Hence, the electric field intensity becomes as follows :
\($E= \frac{\rho \left(\frac{4}{3} \pi r^3\right)}{4 \pi \epsilon_0 r^2}$\)
\($E =\frac{\rho r}{3 \epsilon_0}$\)
Thus, the electric field inside the sphere is given by :
\($\vec {E} = \frac{\rho \vec{r}}{3 \epsilon_0}$\)
Object A is 4 kg while Object B is 2 kg. If Object A moves towards the stationary Object B at 5 m/s, what will be the resulting motion of Object A after the Elastic Collision?
At a speed of 3 m/s, object A will advance away from object B.
Conservation of linear momentumThe conservation of linear momentum can be used to determine how Item A will move following the elastic collision. According to this, the total of the linear momentums of the two objects' beginning and final states must match.
A's initial momentum = 4*5 = 20 kg m/s,
while object B's starting momentum is
2*0 =0 kg m/s. 20 kg m/s is the entire starting momentum.
The conservation of linear momentum can be used to determine the final momentum of Item A. As object B is stationary and the overall final momentum must equal 20, object A's final momentum also needs to equal 20 kg/s.
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why does a proton that enter and exists a magnetic field with the same speed
The proton will experience the same magnitude of magnetic force at both the entry and exit points of the magnetic field, and its speed will not be affected by the magnetic field.
A proton that enters and exits a magnetic field with the same speed will experience the same magnitude of magnetic force in both cases. This is because the magnetic force on a charged particle moving through a magnetic field depends only on the particle's velocity vector and the magnetic field vector, and not on the particle's speed.
The magnetic force on a charged particle is given by the formula F = q(v x B), where F is the magnetic force, q is the charge of the particle, v is the velocity of the particle, and B is the magnetic field vector. The cross product v x B produces a vector perpendicular to both the velocity and magnetic field vectors, and its magnitude determines the strength of the magnetic force on the particle.
Since the speed of the proton entering and exiting the magnetic field is the same, the magnitude of its velocity vector is the same in both cases. Additionally, if the magnetic field is uniform and the proton's trajectory through the field is symmetric, then the magnitude and direction of the magnetic field vector at the entry and exit points of the field will also be the same.
Therefore, the proton will experience the same magnitude of magnetic force at both the entry and exit points of the magnetic field, and its speed will not be affected by the magnetic field.
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What conditions must be satisfied for momentum to be conserved in a system?
The conditions that must be satisfied for momentum to be conserved in a system are; The total external force acting on a system must be zero. In other words, the net force on the system must be zero.
If there is no net force on the system, the momentum of the system will remain constant with time.The mass of the system must remain constant with time. If the mass of the system is changing with time, the momentum of the system will also change with time. Therefore, it is essential to keep the mass of the system constant.
The collision must be elastic. In an elastic collision, the total kinetic energy of the system is conserved, and the momentum of the system is conserved. In other words, the system behaves as if there were no external forces acting on it. If the collision is not elastic, the total kinetic energy of the system will not be conserved. Instead, some of the kinetic energy will be converted into other forms of energy, such as thermal energy or sound energy.If the above three conditions are satisfied, the momentum of the system will be conserved.
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A softball player moving 3.89 m/s
starts a slide, decelerating at -1.44 m/s2
for 4.80 m. How much time does the
slide take? (She does not come to a stop.)
Answer:
0.119 s is the correct answer to this question.
Explanation:
As mentioned in the question
U=3.89\ m/s
a=-1.44\ m/s^2
S=4.8\ m
Consider the final speed of the softball covering the distance of 4.8m is v
Now using the equation
\(v^2=U^2+2aS\)
Putting the value of U, A, S in the previous equation we get
\(V^2=3.89^2-2\times 1.44\times 4.8\\V=3.7\ m/s\\\)
Now again using the equation
v=U+at
where U=intial velocity, t= time
Substituting the value of v, U, a
\(3.7=3.89-1.44\times t\\t=0.119\ s\\\)
Hence the slide time is 0.119 s
what is acceleration time-graph and velocity time-graph
Answer:
The acceleration time graph is the graph that is used to determine the change in velocity in the given interval of the time. ... The acceleration time graph is used to find the change in the velocity of the moving object for the given period of time and this can be determined by finding the area under the curve
Explanation:
how many laws are named after sir issac newton
Answer:
Three Laws
Newton's Three Laws of Motion. Sir Isaac Newton: The Universal Law of Gravitation. Sir Isaac Newton and the Unification of Physics & Astronomy.
Explanation:
a 2.50-l sample of nitric oxide gas at 100c is cooled to 20c. if pressure remains constant, what is the final volume
The final volume of the nitric oxide gas when cooled to 20°C at constant pressure is approximately 1.96 liters.
We use the Gas Law formula for constant pressure, which is Charles's Law: V₁/T₁ = V₂/T₂, where V₁ and V₂ are the initial and final volumes, and T₁ and T₂ are the initial and final temperatures in Kelvin.
Given: V₁ = 2.50 L, T₁ = 100°C, T₂ = 20°C
First, convert the temperatures to Kelvin:
T₁ = 100°C + 273.15 = 373.15 K
T₂ = 20°C + 273.15 = 293.15 K
Now, use Charles's Law to find V₂:
V₁/T₁ = V₂/T₂
2.50 L / 373.15 K = V₂ / 293.15 K
Solve for V₂:
V₂ = (2.50 L / 373.15 K) × 293.15 K = 1.96 L
So, the final volume of the nitric oxide gas when cooled to 20°C at constant pressure is approximately 1.96 liters.
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What are the two factors of energy?
how much mass or speed will the object have
What is the magnitude of the acceleration of a modified Atwood machine if the mass of the cart is 1 kg and the hanging mass is 4 kg? (Use g = 9.8 m/s2. Express your answer to one decimal point)
The magnitude of the acceleration of the modified Atwood machine is 5.88 \(m/s^{2}\), when the mass of the cart is 1 kg and the hanging mass is 4 kg, assuming g = 9.8 \(m/s^{2}\).
A modified Atwood machine consists of two masses hanging over a pulley. The acceleration of the system can be found using the formula:
a = (\(m_{1}\) - \(m_{2}\))g / (\(m_{1}\) + \(m_{2}\))
where m1 is the mass of the larger object, \(m_{2}\) is the mass of the smaller object, and g is the acceleration due to gravity.
In this case, the mass of the cart is \(m_{1}\) = 4 kg, and the hanging mass is \(m_{2}\) = 1 kg. Using the given value of g = 9.8 \(m/s^{2}\), we can substitute the values into the formula to find the acceleration:
a = (4 kg - 1 kg) × 9.8 \(m/s^{2}\) / (4 kg + 1 kg)
a = 3 × 9.8 \(m/s^{2}\) / 5 kg
a = 5.88 \(m/s^{2}\)
It's important to note that the direction of the acceleration is not specified in the problem, as it depends on the direction in which the masses are moving. If the hanging mass is heavier than the cart, the cart will accelerate upwards and the hanging mass will accelerate downwards. If the cart is heavier, the opposite will occur.
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diagram 1 shows a teenage boy skating along a straight path. His velocity decreases from 5.0ms-1 to 3.0ms-1 as he moves through a distance of 16.0 m. What is his deceleration?, in ms-2?
The moon completes one (circular) orbit of the earth in 23.7 days. The distance from the earth to the moon is 3.84×10^8m. Calculate the centripetal acceleration.
Given that distance of moon from the earth is, R= 3.84 x 10^8 m
Also, time taken to complete one revolution is, T= 23.7 days = 2047680 seconds
Mass of the moon is, m= 7.347 Kg
To find the centripetal acceleration,
\(a_c=\frac{m4\pi^2R}{T}\)Substituting the values, we get
\(undefined\)19 dm expressed in millimeters
Is the true resistance greater or smaller than the measured resistance?.
Answer:
greater or smaller as errorss can be there
Explanation:
A 0.060 kg ball hits the ground with a speed of –32 m/s. the ball is in contact with the ground for 45 milliseconds and the ground exerts a 55 n force on the ball. what is the magnitude of the velocity after it hits the ground? 9.3 m/s 12 m/s 41 m/s 73 m/s
Answer:
Approximately \(9.3\; {\rm m\cdot s^{-1}}\).
Explanation:
Apply unit conversion:
\(t = 45\; {\rm ms} = 45 \times 10^{-3}\; {\rm s}\).
At a velocity of \(v\), the momentum \(p\) of an object of mass \(m\) would be \(p = m\, v\).
Initial momentum of this ball:
\(\begin{aligned}p_{0} &= m\, v_{0} \\ &= 0.060\; {\rm kg} \times (-32\; {\rm m\cdot s^{-1}}) \\ &= (-1.92\; {\rm kg \cdot m \cdot s^{-1}})\end{aligned}\).
When a constant force \(F\) is exerted on an object for a duration of length \(t\), the impulse \(J\) applied to that object would be \(J = F\, t\).
Impulse that the ground applied to this ball:
\(\begin{aligned}J &= F\, t \\ &= 55\; {\rm N} \times (45 \times 10^{-3}\; {\rm s}) \\ &= 2.475\; {\rm N \cdot s}\end{aligned}\).
Note that \(1\; {\rm N} = 1\; {\rm kg \cdot m \cdot s^{-2}}\). Thus, the impulse applied to this ball would be equivalent to:
\(\begin{aligned}J &= 2.475\; {\rm (kg \cdot m \cdot s^{-2}) \cdot s} \\ &= 2.475\; {\rm kg \cdot m \cdot s^{-1}}\end{aligned}\).
After this impulse was applied, the momentum of this ball would become:
\(\begin{aligned}p_{1} &= p_{0} + J \\ &= (-1.92\; {\rm kg \cdot m \cdot s^{-1}}) + 2.475\; {\rm kg \cdot m \cdot s^{-1}} \\ &= 0.555\; {\rm kg \cdot m \cdot s^{-1}}\end{aligned}\).
The new velocity of this ball would be:
\(\begin{aligned}v_{1} &= \frac{p_{1}}{m} \\ &= \frac{0.555\; {\rm kg \cdot m \cdot s^{-1}}}{0.060\; {\rm kg}} \\ &\approx 9.3\; {\rm m\cdot s^{-1}}\end{aligned}\).
Answer:
(A)
Explanation:
I took the test