Calculate the volume of H2 formed at STP (in dm3 ) if 7,3 g of HCl reacts in the reaction below: Zn + 2HCl → ZnCl2 + H2

Explanation:

Balanced Equation

P

2

O

3

+

3H

2

O

→

2H

3

PO

3

First use the balanced equation to determine the mole ratio between

H

3

PO

3

and

P

2

O

3

. This ratio will be used to determine the moles

P

2

O

3

required to produce

10.2

moles

H

3

PO

3

.

Mole Ratio Between

P

2

O

3

and

H

3

PO

3

from the balanced equation.

1

mol P

2

O

3

2

mol H

3

PO

3

and

2

mol H

3

PO

3

1

mol P

2

O

3

Multiply the moles

H

3

PO

3

by the molar mass that cancels

H

3

PO

3

and leaves

P

2

O

3

10.2

mol H

3

PO

3

×

1

mol P

2

O

3

2

mol H

3

PO

3

=

5.10 mol P

2

O

3

Now that the moles

P

2

O

3

required to produce

10.2 mol H

3

PO

3

are known, multiply the number of moles by its molar mass,

109.945 g/mol

. https://www.ncbi.nlm.nih.gov/pccompound?term=P2O3 This will give the mass in grams needed for

P

2

O

3

to produce

10.2 mol H

3

PO

3

.

5.10

mol P

2

O

3

×

109.945

g P

2

O

3

1

mol P

2

O

3

=

561 g P

2

O

3

rounded to three significant figures

Monovalent Valency, Divalent Valency and Multivalent Valency are three types of valency.

Valency refers to the combining capacity of an atom to form chemical bonds. There are three types of valency:

Monovalent: Atoms with a valency of 1 can form only one bond. Examples include hydrogen (H) and chlorine (Cl), which can each form one bond.

Divalent: Atoms with a valency of 2 can form two bonds. Oxygen (O) and calcium (Ca) are examples of divalent atoms.

Multivalent: Atoms with multiple valencies can form different numbers of bonds. Transition metals such as iron (Fe) and copper (Cu) exhibit multivalency, allowing them to form varying numbers of bonds, depending on the specific compound and oxidation state.

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Answer:

the boiling point of solution at 3 decimal point is 100.329०C Ans.

Explanation:

given data -

molality of Nacl = 0.321 m

molal boiling point elevation constant (Kb) =0.512०C/m

# formula of change of boiling point of sample =

∆ Tb =i × Kb × m

Kb = molal boiling point of elevation constant

m = molality

i = vont's hoff factor.

Nacl is strong electrolyte and its 100% dissociate so the value of i for Nacl is 2

put value in the formula

∆ Tb = 2 × 0.512 ०C/m × 0.321m

= 0.3287

= 0.329०C

∆Tb = T'b - Tb

T'b = boiling point of solution

Tb= boiling point of solvent( water)

0.329०C = T'b - 100०c ( boiling point of water = 100०C)

T'b = 0.329०C + 100०C

= 100.329०C

hope this helps

Answer:

Molarity = 1.4 M

Explanation:

Given data:

Mass of LiCl = 15.25 g

Volume of solution = 250 mL (250/1000 = 0.25 L)

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will calculate the number of moles of LiCl.

Number of moles = mass/molar mass

Number of moles = 15.25 g/ 42.39 g/mol

Number of moles = 0.36 mol

Molarity:

Molarity = 0.36 mol / 0.25 L

Molarity = 1.4 M           (M= mol/L)

Explanation:

pls the question is not clear to me

Answer:

*The molar volume of any gas at standard conditions of temperature and pressure is 22.4 L/mol

V= 101.3 L , n=? , Vm = 22.4 L/mol

101.3 = n × 22.4

n=101.3 / 22.4

n = 4.52 mol

I hope I helped you ^_^

Answer:

\(\boxed {\boxed {\sf 4.522 \ mol}}\)

Explanation:

We are asked to find how many moles of gas occupy a volume of 101.3 liters.

1 mole of any gas at STP (standard temperature and pressure) has a volume of 22.4 liters. We can use this information to make a proportion.

\(\frac {1 \ mol}{22.4 \ L}\)

We are converting 101.3 liters to moles, so we multiply the proportion by that value.

\(101.3 \ L *\frac {1 \ mol}{22.4 \ L}\)

The units of liters (L) cancel.

\(101.3 *\frac {1 \ mol}{22.4}\)

\(\frac {101.3}{22.4} \ mol\)

Divide.

\(4.52232143 \ mol\)

The original value of liters (101.3 L) has 4 significant figures, so our answer must have the same. For the number we calculated, that is the thousandths place. The 3 in the ten-thousandths place to the right tells us to leave the 2 in the thousandths place.

\(4.522 \ mol\)

101.3 liters of gas is equal to approximately 4.522 moles of gas.

Answer:

show me a pic of the problem

Explanation:

show me a pic of the problem

Answer:

uR making us work hard for this and yet all u give is 5 points

Answer:

$474.30

Explanation:

23.25 × 102 = 2371.5 (total amount of money produced from pallets)

2371.5/5 = 474.3 (payout per worker)

Answer:

The physical and human forces that work in combination to form and transform the world, for example, erosion, the water cycle, migration or urbanisation. Geographical processes can operate within and between places.

Answer:

5 atoms

Explanation:

3 sodium

2 oxygen

Answer:

○\(No. Of Moles = \frac{mass of the substance}{atomic mass of the substance} \\\)

No of moles = 93 g ÷ 138 amu

No of moles = 0.67 moles

93 grams of potassium carbonate contain 0.67 moles.

There are 0.67 moles present in 93 grams of potassium carbonate (K2CO3). Details about no of moles can be found below.

The number of moles of a substance can be calculated by dividing the mass of the substance by its molar mass.

According to this question, there are 93 grams of potassium carbonate.

Molar mass of K2CO3 = 138.205 g/mol

No of moles = 93g ÷ 138.205g/mol = 0.673mol

Therefore, there are 0.67 moles present in 93 grams of potassium carbonate (K2CO3).

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The kJ of the energy absorbed for the every mole of the carbon reacted is 104.8 kJ.

The chemical equation is as :

2C + 2H ---> C₂H₄   ,     ΔH = + 52.4 kJ/mol

The ΔH is the enthalpy change that is determined by the subtracting the energy of the reactants to the products.

The  ΔH = energy of the products - energy of the reactants

The expression for the energy is as :

q = n ΔH

Where,

n = number of the moles

ΔH = enthalpy change

The kJ of the energy absorbed for the every mole of the carbon reacted :

q = 2 mol × 52.4 kJ/mol

q = 104.8 kJ

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Answer:

Umm … can you make it horizontal Please

Explanation:

Answer:

123.0*12.35/(0.05*6.049)

first do in small bracket 123.0*12.35/0.30245

and then divide 123.0*40.83319557

and multiply 5022.483055

The Streeter-Phelps equation, which links dissolved oxygen (DO) concentration in a river to the ultimate biochemical oxygen demand (BODu), the reaeration rate coefficient (K2), the rate constant for oxygen consumption (K1), and the distance downstream from the pollution source, must be used to solve this problem (x).

Streeter-Phelps formula

DO(x) is defined as DOs plus (DOu - DOs) * e(-K1x) - (BODu / K2) * (1 - e(-K2x))

where:

DO(x) is the dissolved oxygen concentration downstream from the pollution source at a distance of x (mg/l).

(mg/l) DOs stands for saturated dissolved oxygen content.

DOu is the dissolved oxygen content (mg/l) upstream of the source of the contamination

BODu stands for the maximum upstream biochemical oxygen requirement (mg/l).

K1 is the oxygen consumption rate constant (1/d).

K2 is the (1/d) reaeration rate coefficient.

x is the separation from the pollutant source (m)

It is necessary to determine the values of K1, K2, DOs, and x in order to apply the Streeter-Phelps equation to this issue.

The following formula can be used to determine K1 from the final BOD (BODu) and the wastewater discharge rate (Qw):

K1 equals BODu / (1.39 * Qw)

where:

(m3/s) Qw = wastewater discharge rate

K1 is equal to 45 mg/l/1.39 * 0.6 m3/s, or 53.6 d-1.

K2 can be calculated using the equation below:

K2 = (L * (DOs - DOu)) / (2 * U * S)

where:

U = the river's average speed (in m/s)

S is the river's cross-sectional area (m2)

L stands for the reach (m)

We can use the average velocity to calculate K2 if the reach length is long enough to allow for complete mixing and the river velocity is constant across the river's breadth and depth.

DOmin = DOs + (DOu - DOs) * e^(-K1x) - (BODu / K2) * (1 - e^(-K2x))

Rearranging this equation, we get:

ln[(DOs - DOmin) / (DOs - DOu)] = -K1x - ln[1 - (K2 / K1) * (1 - e^(-K1x))]

Using trial and error or a numerical method, we can solve for x when DOmin = 5 mg/l, which is the minimum DO concentration that is typically considered acceptable for

U = Q / S = 1.5 m * 30 m / (2.1 m3/s) = 0.0467 m/s

K2 = (11.5 mg/l - 8.4 mg/l) / (1.5 m * (0.0467 m/s * 1.5 m * 30 m)) = 0.0615 d-1

The formula below can be used to determine DOs:

Temperature * DOs = 14.6 - 0.0072

Assuming a constant temperature of 20°C, DOs is equal to 14.6 - 0.0072 * 20°C, or 14.26 mg/l.

The final step is to determine the distance (x) downstream from the pollution source at which the DO concentration is at its lowest (DOmin). You can calculate this using the

DOmin is equal to DOs plus (DOu - DOs)* e(-K1x) - (BODu / K2)* (1 - e(-K2x))

If we rewrite this equation, we obtain:

(DOs - DOu) / (DOs - DOmin) = -K1x - ln[1 - (K2 / K1)* (1 - e-K1x)]

We can determine x at DOmin = 5 mg/l, which is the minimal DO concentration that is commonly accepted, either by trial and error or a numerical approach.

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The number of atoms :

C = 6 x 5 x 10²¹ = 3 x 10²²

H = 12 x 5 x 10²¹ = 6 x 10²²

O =  6 x 5 x 10²¹ = 3 x 10²²

Given

1.5 g glucose(C₆H₁₂O₆)

Required

The number of atoms

Solution

mol of glucose(MW=6.12+12.1+6.16=180 g/mol) :

mol = mass : MW

mol = 1.5 : 180

mol = 0.0083

Number of molecules = 0.0083 x 6.02 x 10²³ = 5 x 10²¹

There are 6 C, 12 H and 6 O, so number or atoms :

C = 6 x 5 x 10²¹ = 3 x 10²²

H = 12 x 5 x 10²¹ = 6 x 10²²

O =  6 x 5 x 10²¹ = 3 x 10²²

Answer:

A=no

B= yes when liquid or solution

C=yes

D=no

E=yes

Explanation:

According to the given table, the placement of items A-E are

A) ⇒ No

B) ⇒Yes, when liquid or solution

C) ⇒Yes

D) ⇒No

E) ⇒Yes

What is conductivity and Malleability?

Malleability - Those metals that can be beaten into thin sheets with a hammer or any heavy object. For example - Cu, Au etc

Conductivity - Conductivity is the measure of the ease at which an electric charge or heat can pass through a material. For example - Metals are good conductors of heat and electrolytic solution is conductors of electricity.

Therefore, according to the given table, the placement of items A-E are

A) ⇒ No

B) ⇒Yes, when liquid or solution

C) ⇒Yes

D) ⇒No

E) ⇒Yes

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Answer:

you cant post pictures on brainly answers.... can you?

Explanation:

The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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The compound that is shown as X can be seen in the option labelled C

The process of esterification involves the condensation of an alcohol (or phenol) with an acid to produce an ester. To create the ester bond, the water molecule must be removed from the alcohol and acid (dehydration).

Usually, an acid catalyst is used to catalyze the reaction, which makes it easier to remove water and encourages the creation of the ester. The acid catalyst aids in protonating the acid's carbonyl oxygen, which increases its electrophilicity and makes it more vulnerable to alcohol's nucleophilic attack.

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The amount of lithium nitrate needed to make 230 grams of lithium sulfate depends on the amount of lead (IV) sulfate provided and is equal to half of the moles of lithium sulfate produced, which is 2.091/2 = 1.046 mol. The mass of lithium nitrate required can be calculated using its molar mass.

To calculate the amount of lithium nitrate required to make 230 grams of lithium sulfate, we can use the following steps:

Calculate the molar mass of lithium sulfate:

Li2SO4: 2(6.94 g/mol) + 1(32.06 g/mol) + 4(16.00 g/mol) = 109.94 g/mol

Determine the number of moles of lithium sulfate:

n = m/M = 230 g / 109.94 g/mol = 2.091 mol

Since 2 moles of lithium sulfate are produced for every 1 mole of lead (IV) sulfate, we need 2.091/2 = 1.046 mol of lead (IV) sulfate to react with the lithium sulfate.

Calculate the mass of lead (IV) sulfate required:

m = nM = 1.046 mol x Pb(SO4)2 molar mass (assuming it's provided)

From the balanced equation, we know that for every 2 moles of lithium sulfate, we need 1 mole of lithium nitrate.

The amount of lithium nitrate needed to make 230 grams of lithium sulfate depends on the amount of lead (IV) sulfate provided and is equal to half of the moles of lithium sulfate produced, which is 2.091/2 = 1.046 mol. The mass of lithium nitrate required can be calculated using its molar mass.

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1. The IUPAC name of N is nitrogen.

2. Nitrogen dioxide

3.The IUPAC name of O is oxygen

4.The IUPAC name of OH is hydroxyl.

The IUPAC name of ·0 is a radical. It is commonly found in organic chemistry and plays an important role in many reactions.

IUPAC names for the given compounds are:1.1. N: Nitrogen

The IUPAC name of N is nitrogen.

It is a non-metal and belongs to group 15 in the periodic table. It has an electronic configuration of 1s2 2s2 2p3.1.2. NO2: Nitrogen dioxide

Explanation: NO2 is a chemical compound that is formed by the combination of nitrogen and oxygen. It is a reddish-brown gas that has a pungent odor.

The IUPAC name of NO2 is nitrogen dioxide.1.3. O: Oxygen

Explanation: The IUPAC name of O is oxygen.

It is a non-metal and belongs to group 16 in the periodic table. It has an electronic configuration of 1s2 2s2 2p4.

X: UnknownExplanation: No IUPAC name can be given to an unknown compound as the structure and composition are not known.

Y: Hydroxyl Explanation: The IUPAC name of OH is hydroxyl.

It is a functional group that is composed of an oxygen atom and a hydrogen atom (-OH). It is commonly found in alcohols and phenols. ·0: RadicalExplanation: A radical is a molecule or an ion that contains an unpaired electron.

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Note: The complete question is given below

Provide the IUPAC names for the following compounds:

\(CH_3CH_2CH(CH_3)CH_2CH_2CH_2CH_3\)

C6H5CH(CH3)2

H2NCH2CH2CH2CH2CH2NH2

CH3CH2CH2CH2CH2OH

CH3CH2CH2CHOHCH3

Answer:

A. 1 J=1kg•m^2/s^2

Explanation:

Energy refers to the capacity to do work. According to the International System of units (SI units), energy is measured in Joules.

Energy is represented by the force applied over a distance. Force is measured in Newton (N) and distance in metres (m). Hence, energy is Newton × metre (N.m)

Newton is derived from the SI units of mass (Kilograms), and acceleration (metres per seconds^2) i.e Kg.m/s^2, since Force = mass × acceleration.

Since; Energy = Newton × metres

If Newton = Kg.m/s^2 and metres = m

Energy (J) will therefore be; Kg.m/s^2 × m

1J = Kg.m^2/s^2

Answer:

During the early Paleozoic Era, the Earth's surface was very different from what it is today. The continents were arranged differently, forming one large supercontinent called Pangea. This landmass was surrounded by a single large ocean called Panthalassa. The climate was much warmer and wetter than it is today, with no ice caps at the poles.

The first land plants, known as bryophytes, appeared during the early Silurian Period, around 430 million years ago. These plants were small and simple, lacking roots and vascular tissue. They grew in damp environments, such as along the edges of lakes and streams. They were important in the development of soils and in the colonization of land by other organisms, such as insects and other arthropods.

The mass, in grams, of NaCl needed to use to make the solution is 1.76grams.

The mass of a substance can be calculated by multiplying the number of moles by its molar mass.

However, the number of moles must first be calculated by using the following expression:

Molarity = no. of moles ÷ volume

no. of moles = 0.249 × 0.1208

no. of moles = 0.03moles

Molar mass of NaCl = 23 + 35.5 = 58.5g/mol

mass of NaCl = 0.03 × 58.5 = 1.76g

Therefore, the mass, in grams, of NaCl needed to use to make the solution is 1.76grams.

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If 100 s of heat is added to a system and 0.100 ks of work is done by the system, then the value of ΔE or DE (change in internal energy) is 200 J, which is in option A. This is as per the first rule of thermodynamics.

ΔE = Q - W

ΔE (change in internal energy)

Given that 100 J (joules) of heat is added to the system (Q = 100 J) and 0.100 kJ (kilojoules) of work is done by the system (W = -0.100 kJ), we need to ensure that the units are consistent.

Since 1 kJ = 1000 J, we can convert the work done to joules:

W = -0.100 kJ = -0.100 × 1000 J = -100 J

Now one can substitute the values into the equation:

ΔE = Q - W

= 100 J - (-100 J)

= 100 J + 100 J

= 200 J

Therefore, the value of ΔE (change in internal energy) is 200 J.

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complete question is below

if 100s of heat is added to a system and 0.100ks of work is done by the system, what is the value of DE​

A. 200 j

B.50 j

C.2 j

D. 10000j

Answer:

kinetic

Explanation: