calculate the theoretical yield (in grams) 28.6 kg of c reacts with 88.2 kg of tio2.

Generally, Equilibrium is defined as a state in which opposing forces or actions are balanced so that one is not stronger or greater than the other.

Concentration of CH₄ = 1.39

So X here is = -1.39 + 4 = 2.61

So concentration of,

H₂S = 8 - 2 × (2.61) = - 2. 78 M

Cs₂ = 4 - 2.61 = 1.39 M

H₂ = 8 - 4 (2.61) = -2.44 M

Concentration is defined as the amount of a substance, such as a salt, that is in a certain amount of tissue or liquid, such as blood. When less water is present in a substance it usually becomes more concentrated.

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Answer:

the molar amount of the gas.

Explanation:

This viewpoint contends that biological and genetic variables have an impact on personality. One illustration of the way a biological perspective may be utilised to explain human personality is temper.

A few behavioural and psychological features that each person's DNA can influence include intelligence, personality, and propensity for mental illness. The both adults and the children in a family may be impacted by these characteristics.

According to Hans Eysenck's theory, personality has a biological basis and that genetic legacy contributes to personality differences [62,115]. Extraversion, neuroticism, and psychoticism are the three independent super-factors in the Eysenck model.

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Answer:

The response is an unlearned behavior demonstrating the natural ability to form emotional connections.

Explanation:

I just know (;

Answer:

The nuclear fuel used in a nuclear reactor needs to have a higher concentration of the U 235 isotope than that which exists in natural uranium ore. U235 when concentrated (or "enriched") is fissionable in light-water reactors (the most common reactor design in the USA).

Explanation:

Answer:

Chloro-Flouro-Carbon

Explanation:

Chloro-Flouro-Carbon (CFC Gas) is used as a refrigerant in fridges and freezers.

Answer:

covalent

Explanation:

Answer: Science and Mathematics- Anthropologist, Meteorologist

Engineering and technology- Fuel Cell Technician, Computer programmer, electrical Drafter, Civil Drafter

Answer:

i have the same question  

Explanation:math and science is the meteorologs and the  anthropologist

The following actions describe deposition as flowing soil or mud due to gravity. Option D.

Sedimentation is the accumulation of sediments carried by the wind running water sea or ice. Sediments are carried as pebbles sand mud, or dissolved salts in water. A deposition is the direct transition of a substance from the gaseous state to the solid state on cooling without going through the liquid state.

Sedimentation is the geological process in which sediments soils and rocks are added to form landforms or land masses. Wind ice water and gravity cause previously weathered surface material to deposit and lose sufficient kinetic energy within the fluid to form a layer of sediment. Several factors influence how sediment settles. Sediment is removed from new surface locations. Precipitation is the change of state of a gaseous substance into a solid.

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The specific heat of the metal with a mass of 100g that absorbed 2500 joules of energy is 0.33J/g°C

The specific heat capacity of a metal can be calculated by using the following expression:

Q = m × c × ∆T

Where;

c = Q ÷ m∆T

c = 2500 ÷ (100 × 74.8)

c = 2500 ÷ 7480

c = 0.33J/g°C

Therefore, the specific heat of the metal with a mass of 100g that absorbed 2500 joules of energy is 0.33J/g°C.

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The average speed = 6.52 m/s

Given

distance = 150 m

time = 23 s

Required

The average speed

Solution

The average speed : distance traveled divided by time taken or total distance divided by total elapsed time

Can be formulated :

avg speed = distance : time

avg speed = d : t

Input the value :

avg speed = 150 m : 23 s

avg speed = 6.52 m/s

Bogs: Wet, muddy wetland with very soft ground and varying salinity

Delta: A triangular track of sediment deposited at the mouth of a river

Estuary:A wetland at the mouth of a river with varying water levels and salinity

Swamp:A forested wetland with varying salinity

NH₄Cl and NH₄CN will make the solutions slightly acidic, while H₂CO₃, KOH, and KClO₄ will result in basic or neutral solutions.

1. The pH of the final solution will be slightly basic, around 9. This is because NH₄Cl is a salt of a weak acid (NH₃) and a strong base (HCl). When NH₄Cl dissolves in water, it will dissociate into NH₄⁺ and Cl⁻ ions. The NH₄⁺ ions will react with the OH⁻ ions from the water to form NH3 and H₂O. This will increase the concentration of OH⁻ ions in the solution, making it basic.

2. The pH of the final solution will be 10. This is because the H₂CO₃ is a weak acid and the KOH is a strong base. When the two solutions are mixed, the H₂CO₃ will react with the KOH to form K₂CO₃ and H₂O. The K₂CO₃ is a salt that does not hydrolyze, so it will not affect the pH of the solution. The only ions in solution will be K⁺ and OH⁻, which will make the solution basic.

3. The pH of the final solution will be 13. This is because KOH is a strong base. When KOH dissolves in water, it will dissociate completely into K⁺ and OH⁻ ions. The OH⁻ ions will make the solution basic.

4. The pH of a 0.50 M H₃PO₄ solution will be 2.1. This is because H₃PO₄ is a strong acid. When H₃PO₄ dissolves in water, it will dissociate completely into H⁺ and H₂PO₄⁻ ions. The H⁺ ions will make the solution acidic.

5. The pH of a solution of NH₄CN will be < 7. This is because NH₄CN is a salt of a weak acid (NH₄⁺) and a weak base (CN⁻). When NH₄CN dissolves in water, it will dissociate into NH₄⁺ and CN⁻ ions. The NH₄⁺ ions will react with the OH⁻ ions from the water to form NH₃ and H₂O. This will decrease the concentration of OH⁻ ions in the solution, making it acidic.

6. The pH of a solution of KClO₄ will be 7. This is because KClO₄ is a salt of a strong acid (HClO₄) and a strong base (KOH). When KClO₄ dissolves in water, it will dissociate completely into K and ClO₄⁺ ions. The K⁺ and ClO₄⁻ ions will not react with the water, so they will not affect the pH of the solution. The pH of the solution will be determined by the concentration of H⁺ ions in the water, which is 10⁻⁷ M.

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Complete question :

What is the pH of the final solution when 50.0 gNH_4 Cl_(s) dissolved in 1.0 L of a 0.50 M NH_3 solution? (Assume NO CHANGE IN VOLUME) What is the pH of the final solution when 50.0 mL of 0.10 M H_2 CO_3 solution is mixed with 25.0 mL of a 0.20 M KOH solution? What is the pH of a solution made by dissolving 112.2 g KOH_(s) in enough water to make 1.0 L. What is the pH of a 0.50 M H_3 PO_4 solution? Will the pH of a solution of NH_4 CN be > 7, < 7, or = 7? MUST show reasoning. Will the pH of a solution of KClO_4 be > 7, < 7, or = 7? MUST show reasoning.

The formula managers use to calculate a food service operation's total expense percentage is to divide the total cost of food by total sales.

The resulting amount should then be multiplied by 100 to get the percentage. A food service operation's total expense percentage is the percentage of its total sales that are spent on food.

The formula to calculate the food service operation's total expense percentage is:

Expense percentage = (Total cost of food / Total sales) * 100

This formula gives the total amount or the total expense percentage which a food service operation spends on its food to generate its total sales or revenue.

In this calculation, the total cost of food includes all expenses associated with purchasing, preparing, and serving the food, such as ingredients, labor, and supplies.

The calculation of the food service operation's total expense percentage is critical for the management and profitability of the business. It helps to determine the actual cost of the food and the operation's overall profitability.

By comparing the expense percentage of the business with industry standards and previous performance, management can make informed decisions to control costs, increase revenue, and maximize profits.

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Answer:A

Explanation:

Answer:

Explanation:

not sure what 10# is

but you solve this way

(2.5 X 10 #) divide by (6.02 X 10^23)  X 28 g

6.02 x 10^23  is avogadros number use cause its in molecules

28 is the molar mass from the periodic table for CO

if I calculate it with 2.5 X 10 this is the answer  1.16 X 10^-21 g CO

Answer:

1 kPa = 760/101.325 = 7.5 mmHg; atm = atmosphere; kPa = kilo Pascal; mmHg = millimetres of mercury.

Answer:

5,000

Explanation:

ed2021

Answer:

The answer will be "B"

Explanation:

It is B, because as we can see in the problem, it shows that there are three hydrogen gas, which is H₂. So, it shows that the ratio of Hydrogen gas to Ammonia is 3:2. In the answer, it says for every 3 mol of H₂ 2 moles of ammonia is produce. Therefore, B is correct.

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Nuclear fission occurs when a nucleus breaks up into two equal fragments that release and separate more atoms. So, the correct option is B.

Nuclear fission is a process in which the nucleus of an atom breaks apart into two or more smaller nuclei. This process releases a significant amount of energy.

This energy is utilized in various applications, including nuclear power generation and nuclear weapons. Nuclear fission reactions are carefully controlled in nuclear power plants to ensure the sustained release of energy without leading to uncontrolled chain reactions. Hence the correct option is B.

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1.78 grams of silver can be produced from 1.40 g silver nitrate and excess copper. The balanced chemical equation for the reaction of copper with silver nitrate (use cu2) is as follows: Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag

To determine how many grams of silver can be produced from 1.40 g of silver nitrate and excess copper, we first need to calculate the limiting reactant.

The stoichiometry of the reaction is such that 2 moles of silver nitrate react with 1 mole of copper to produce 2 moles of silver. The molar mass of silver nitrate is 169.87 g/mol while that of copper is 63.55 g/mol,

therefore, the number of moles of silver nitrate present in 1.40 g can be calculated as follows:Number of moles of silver nitrate = mass/molar mass= 1.40/169.87= 0.008240 molSimilarly, the number of moles of copper required to react with this quantity of silver nitrate is 0.004120 mol (half of the number of moles of silver nitrate).

Since there is an excess of copper, it will not limit the reaction and hence the limiting reactant is silver nitrate.To calculate the mass of silver produced, we use the molar mass of silver, which is 107.87 g/mol.Mass of silver produced = number of moles of silver x molar mass= 0.01648 x 107.87= 1.78 g

Therefore, 1.78 grams of silver can be produced from 1.40 g silver nitrate and excess copper.

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The order of increasing bond length is B22 > B2 > B2-.In summary, the order of increasing bond order is B22 < B2 < B2-, the order of increasing bond energy is B22 < B2 < B2-, and the order of increasing bond length is B22 > B2 > B2-.

Molecular orbital (MO) diagrams are used to assess the bonding in a molecule and provide information about bond order, bond energy, and bond length. In this question, we have to rank B22, B2, and B2- in order of increasing bond order, bond energy, and bond length using MO diagrams.

Bond order: Bond order refers to the number of chemical bonds between two atoms. It is determined by the number of bonding electrons minus the number of antibonding electrons divided by two. A higher bond order indicates stronger bonding between two atoms. B22 has a bond order of 1, B2 has a bond order of 1, and B2- has a bond order of 2. Therefore, the order of increasing bond order is B22 < B2 < B2-.

Bond energy: Bond energy refers to the energy required to break a chemical bond. A higher bond energy indicates a stronger bond. B22 has the weakest bond and the smallest bond energy because it is composed of two atoms in the ground state, which do not bond. B2 has a slightly stronger bond than B22, but the bond energy is still low. B2- has the strongest bond because it has the highest bond order. Therefore, the order of increasing bond energy is B22 < B2 < B2-.

Bond length: Bond length refers to the distance between the nuclei of two bonded atoms. A shorter bond length indicates a stronger bond. B22 has the largest bond length since it has no bond. B2 has a slightly shorter bond length than B22. B2- has the shortest bond length since it has the highest bond order.

Therefore, the order of increasing bond length is B22 > B2 > B2-.In summary, the order of increasing bond order is B22 < B2 < B2-, the order of increasing bond energy is B22 < B2 < B2-, and the order of increasing bond length is B22 > B2 > B2-.

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the identity of element E in the nuclear reaction (238)U --> (234)E + (4)He is thorium (Th).

What is Nuclear Reaction?

A nuclear reaction is one in which the nucleus of an atom is transformed into the nucleus of one or more daughter nuclei. This differs from a a chemical reaction in which atoms are changed from one form to another.

To identify the element E in the nuclear reaction (238)U --> (234)E + (4)He, we need to consider the conservation of mass number and atomic number.

In the given reaction, the mass number is conserved, as 238 = 234 + 4. This indicates that the total mass on the left side (238) is equal to the total mass on the right side (234 + 4).

Next, we consider the atomic number. The atomic number is the number of protons in the nucleus of an atom. In the reaction, uranium (U) has an atomic number of 92. Since helium (He) has an atomic number of 2, the sum of the atomic numbers on the right side should be equal to the atomic number on the left side.

92 (atomic number of U) = atomic number of E + 2

Solving this equation, we find:

atomic number of E = 92 - 2 = 90

The element with atomic number 90 is thorium (Th).

Therefore, the identity of element E in the nuclear reaction (238)U --> (234)E + (4)He is thorium (Th).

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The mass of sodium chloride, NaCl produced from the reaction is 18474 g

MgCl₂ + 2Na —> 2NaCl + Mg

Molar mass of MgCl₂ = 24 + (35.5 × 2) = 95 g/mole

Mass of MgCl₂ from the balanced equation = 1 × 95 = 95 g = 0.095 Kg

Molar mass of Na = 23 g/mole

Mass of Na from the balanced equation = 2 × 23 = 46 g = 0.046 Kg

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mole

Mass of NaCl from the balanced equation = 2 × 58.5 = 117 g = 0.117 Kg

SUMMARY

From the balanced equation above,

0.095 Kg of MgCl₂ reacted with 0.046 Kg of Na to produce 0.117 Kg of NaCl

From the balanced equation above,

0.095 Kg of MgCl₂ reacted with 0.046 Kg of Na

Therefore,

15 Kg of MgCl₂ will react with = (15 × 0.046) / 0.095 = 7.26 Kg of Na

From the above calculation, only 7.26 Kg of Na out of 50 Kg given is needed to react completely with 15 Kg of MgCl₂.

Thus, MgCl₂ is the limiting reactant

From the balanced equation above,

0.095 Kg of MgCl₂ reacted to produce 0.117 Kg of NaCl

Therefore,

15 Kg of MgCl₂ will react to produce = (15 × 0.117) / 0.095 = 18.474 Kg = 18474 g of NaCl

Thus, 18474 g of NaCl were obtained from the reaction

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Answer:

Thermal energy typically flows from a warmer material to a cooler material.

Explanation:

Approximately 35.90 grams of ice must melt to lower the water temperature to 0.0°C.

To solve this problem, we need to calculate the amount of heat that needs to be transferred from the water to the ice in order to lower the water temperature to 0.0°C.

First, let's calculate the initial heat content of the water. The specific heat capacity of water is 4.186 J/(g·K), and the mass of the water can be calculated using its density (1 g/mL) and volume (7.30 × 10^2 mL):

Mass of water = density × volume = 1 g/mL × 7.30 × 10^2 mL = 7.30 × 10^2 g

The initial heat content of the water can be calculated using the formula:

Heat content = mass × specific heat capacity × temperature change

Heat content = 7.30 × 10^2 g × 4.186 J/(g·K) × (25.0°C - 0.0°C) = 7.30 × 10^2 g × 4.186 J/(g·K) × 25.0°C

Next, we need to calculate the amount of heat that needs to be transferred from the water to the ice to lower the water temperature to 0.0°C. This heat transfer occurs during the melting of the ice.

The amount of heat required to melt the ice can be calculated using the formula:

Heat = mass of ice melted × latent heat of fusion

Let's assume that x grams of ice melts. The mass of the ice can be calculated using its density (0.92 g/mL) and volume (same as the volume of water):

Mass of ice = density × volume = 0.92 g/mL × 7.30 × 10^2 mL = 6.716 × 10^2 g

Heat = x g × 333.7 J/g

Now, we need to ensure that the heat transferred from the water to the ice is enough to lower the water temperature to 0.0°C. The heat transferred from the water to the ice is equal to the heat transferred from the water when its temperature drops to 0.0°C:

Heat content of water = Heat transferred to ice

7.30 × 10^2 g × 4.186 J/(g·K) × 25.0°C = x g × 333.7 J/g

Now, we can solve for x:

x = (7.30 × 10^2 g × 4.186 J/(g·K) × 25.0°C) / (333.7 J/g)

x ≈ 35.90 g

Therefore, approximately 35.90 grams of ice must melt to lower the water temperature to 0.0°C.

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The correct balanced equation of a beta decay undergone by Mercury-203 is as follows:

203 80 Hg → 203 81 + 0 -1 e

Beta decay in radioactivity refers to the release of a beta particle by a radioactive element.

Beta particle is characterized by the possession of mass number 0 and atomic number -1.

This means that if Mercury-203 undergoes beta decay, the atomic number of the resulting isotope will be +1 as follows:

203 80 Hg → 203 81 Tl + 0 -1 e

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The simplest straight-chain alkynes containing seven to twelve carbons are:

1. Heptyne (7 carbons)

2. Octyne (8 carbons)

3. Nonyne (9 carbons)

4. Decyne (10 carbons)

5. Undecyne (11 carbons)

6. Dodecyne (12 carbons)

Here are the structures and names of the simplest straight-chain alkynes containing seven to twelve carbons:

1. Heptyne:

  Structure: H-C≡C-C≡C-C≡C-C≡C-H

  Name: 1-Heptyne

2. Octyne:

  Structure: H-C≡C-C≡C-C≡C-C≡C-C≡C-H

  Name: 1-Octyne

3. Nonyne:

  Structure: H-C≡C-C≡C-C≡C-C≡C-C≡C-C≡C-H

  Name: 1-Nonyne

4. Decyne:

  Structure: H-C≡C-C≡C-C≡C-C≡C-C≡C-C≡C-C≡C-H

  Name: 1-Decyne

5. Undecyne:

  Structure: H-C≡C-C≡C-C≡C-C≡C-C≡C-C≡C-C≡C-C≡C-H

  Name: 1-Undecyne

6. Dodecyne:

  Structure: H-C≡C-C≡C-C≡C-C≡C-C≡C-C≡C-C≡C-C≡C-C≡C-H

  Name: 1-Dodecyne

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The lower reactivity of 2,2-dimethyl-1-bromopropane in the Sn2 reaction compared to bromoethane can be attributed to steric hindrance. The two methyl groups on the carbon adjacent to the bromine in 2,2-dimethyl-1-bromopropane create a bulky structure that hinders the approach of the nucleophile during the Sn2 reaction.

This hindrance slows down the reaction and makes it less favorable compared to bromoethane, which has a simpler structure with no such hindrance.

Therefore, even though both are primary alkyl halides, the presence of the bulky methyl groups makes the Sn2 reaction of 2,2-dimethyl-1-bromopropane significantly lower than bromoethane.
The Sn2 reaction of 2,2-dimethyl-1-bromopropane is significantly lower than bromoethane because of the steric hindrance in the former compound.

Both are primary alkyl halides, but 2,2-dimethyl-1-bromopropane has two methyl groups attached to the carbon bearing the bromine atom, making it more sterically hindered. This steric hindrance reduces the accessibility of the nucleophile to the reaction site, resulting in a lower Sn2 reaction rate compared to bromoethane, which has a less hindered structure.

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if the formula of an oxide of element X is XO, the formula of the nitride of X would be X3N2. So the correct answer is option D: X3N2.

Oxides are chemical compounds that contain at least one oxygen atom as well as at least one other element. Most of the earth's crust consists of oxides. Oxides are formed when elements are oxidized by oxygen in the air.

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