Answer:
P = 49.05 Pa
Explanation:
The pressure is defined as the force applied by an external force per unit normal surface area. So, the formula of pressure is given as follows:
\(P = \frac{F}{A}\)
where,
P = Pressure
F = Force
A = Normal Surface Area
In the given scenario:
P = ?
F = Weight of Box = mg = (10 kg)(9.81 m/s²) = 98.1 N
A = Area of Contact = 2 m²
Therefore, using these values in the formula, we get:
\(P = \frac{98.1\ N}{2\ m^2}\\\\\)
P = 49.05 Pa
A lightbulb with a resistance of 45.0 ohms (R) is used in a circuit with a 9.0V battery. What is the current through the bulb?
The current that flows in the circuit is 0.2 A.
What is the current?We know that circuit is a path that has been specially prepared and set aside for the flow of current. This implies that we could only observe the flow of current in a an electric circuit. We could use the Ohm's law to be able to obtain the voltage an the current.
Ohms law states that the current that flows in the circuit is directly proportional to the voltage in the circuit. This implies that we could be able to write from this statement that; V α I. When we try to introduce the constant of proportionality then we can write;
V = IR
Where;
V = voltage
I = current
R = resistance
I = V/R
V = 9.0V
R = 45.0 ohms
I = 9.0V/ 45.0 ohms
I = 0.2 A
The current that flows in the circuit is 0.2 A.
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what is the current in each wire if the cords hang at an angle of 6.00 ∘ with the vertical?
To determine the current in each wire, we need to know the voltage applied and the resistance of the wire.
To determine the current in each wire when the cords hang at an angle of 6.00 ∘ with the vertical, we need to consider the forces acting on the cords. Gravity pulls the cords downwards, while tension in the wires pulls them upwards. Since the cords are at an angle, we can resolve the forces into their vertical and horizontal components.
Assuming that the cords and wires are perfectly vertical, we can use the sine and cosine functions to calculate the components of the tension force. Let's assume that the total tension force in each wire is T.
The vertical component of the tension force is Tcos(6.00 ∘), while the horizontal component is Tsin(6.00 ∘). Since the cords are in equilibrium, the sum of the vertical forces must be equal to the weight of the cords, which we can assume is negligible. Therefore, the current in each wire is given by:
I = Tcos(6.00 ∘)
We can use Ohm's law to relate the current to the resistance of the wire and the voltage applied to it. If we know the voltage, we can calculate the current using:
I = V/R
where R is the resistance of the wire. Therefore, to determine the current in each wire, we need to know the voltage applied and the resistance of the wire.
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can ya pls answer dis rq!
Answer:
I don't even know can u tell me how to ask questions
A physics student is adjusting the settings of their projectile launcher. If the Vx =
28 m/s and the Vy = 15 m/s, what is the magnitude of its velocity?
32 m/s
13 m/s
43 m/s
1009 m/s
Answer:
32m/s
Explanation:
obtained from V=vx square roo+ vy square root but all terms are squared.
Convert 3.8 kg to Lbs
Answer:
8.37757
Explanation:
may i have brainliest
problem 3. a ramp of mass m is at rest on a horizontal surface. a small cart of mass m is placed at the top of the ramp and released. what are the velocities of the ramp and the cart relative to the ground at the instant the cart leaves the ramp?
At the instant where the cart leaves the ramp, the velocities of the ramp and the cart are relative to the ground as \((mgh/m+M)^{1/2}\) and \((2gh(m+M)/3m)^{1/2}\) respectively.
The velocities of the ramp and cart relative to the ground at the instant the cart leaves the ramp can be calculated using conservation of energy and momentum. The velocity of the cart relative to the ground can be found using conservation of energy as follows:
mgh = 1/2mv² + 1/2Iw²
where m is mass of cart, g is acceleration due to gravity, h is height of ramp, v is velocity of cart relative to ground, I is moment of inertia of ramp about its center of mass and w is angular velocity of ramp about its center of mass.
The velocity of ramp relative to ground can be found using conservation of momentum as follows:
mv = (m+M)V
where M is mass of ramp and V is velocity of ramp relative to ground.
Solving these equations simultaneously gives:
\(V = mgh/(m+M)^{1/2}\)
\(v = 2gh(m+M)/(3m)^{1/2}\)
where h = height of ramp.
Therefore, at the instant when cart leaves the ramp, velocity of cart relative to ground will be \((2gh(m+M)/(3m))^{1/2}\) and velocity of ramp relative to ground will be \((mgh/(m+M))^{1/2}\).
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Jason throws a ball horizontally off a 300 meter cliff at 15.0 m/s. How far will it travel before it hits the
ground? Use significant figures, and estimate g to be equal to 9.81 m/s2. Round the answer to the nearest
hundredth.
117.30 m
B
130.80 m
с
51.80 m
D
101.70 m
Answer:
117,30m
Explanation:
I think the situation here is a horizontal projection to the ground. So in order to find the distance the formula = Ut, where U is the initial speed and t is the Time of flight. To get the time of flight in this case =√2h/g where h is the height and g is gravity. so to get the time = √2×300÷9.81 =7.821 .so range =ut which is equal to the time multiplied by 15m/s =117.30m
Hi there!
To find the total distance traveled, we must find the time taken to fall down.
Ignore the horizontal velocity when dealing with the vertical direction. We can use the simplified equation:
\(t = \sqrt{\frac{2h}{g}{}}\)
Plug in the given values:
\(t = \sqrt{\frac{2(300)}{9.81}} = 7.821 sec\)
Use the equation:
Δd = vt
Plug in the time and horizontal velocity:
Δd = (15)(7.821) = 117.30m
Which would take longer to cool off by 50 degrees, 1 kg of Copper or 1 kg of liquid water?
Answer:
i believe it would be water
Explanation:
Which of the following is a definite indicator of a chemical change?
Answer:
Some signs of a chemical change are a change in color and the formation of bubbles. The five conditions of chemical change: color chage, formation of a precipitate, formation of a gas, odor change, temperature change.
Explanation:
a laser pulse with a wavelength of 533 nm contains 1.83 mj of energy. how many photons are in the laser pulse? express the number of photons to three significant figures.
The laser pulse with a wavelength of 533 nm containing 1.83 mJ of energy has 3.44 x 10^18 photons.
The energy of a photon is given by E=hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. Rearranging this formula, we get λ=hc/E.
Substituting the given values, we get λ=3.31 x 10^-19 J s x 3 x 10^8 m/s / 1.83 x 10^-3 J = 5.46 x 10^-7 m or 533 nm.
Now, we can calculate the number of photons by dividing the total energy of the laser pulse by the energy of a single photon.
N= E/Ephoton= 1.83 x 10^-3 J / (hc/λ) = 3.44 x 10^18 photons.
Finally, we round off the answer to three significant figures, which gives us the answer of 3.44 x 10^18 photons.
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a wire has current 5A in it.how much charge pass a point in wire in 2 min..???
Answer:
600 Coulomb
Explanation:
Electric Current refers to the charge passing through unit cross section of a wire per second.
Current ( C / sec) = 5A = 5C / sec
So, 5C charge passes through the wire in one second, then, amount of charge passing through a cross section of the wire in 120 seconds is :
5C * 120 = 600 Coulumb
The Dulac Box plant works two 8-hour shifts each day. In the past, 500 cypress packing boxes were produced by the end of each day. The use of new technology has enabled them to increase productivity by 30%. Productivity is now approximately: Group of answer choices 40.6 boxes/hr 81.25 boxes/hr. 62.5 boxes/hr. 300 boxes/hr.
The new productivity is 40.6 boxes per hour. Therefore, the correct option is option 1.
The Dulac Box plant has increased its productivity by 30% due to the use of new technology. Previously, they produced 500 cypress packing boxes in two 8-hour shifts, which totals 16 hours. To find the new productivity, first, we need to calculate the number of boxes produced with the increased productivity:
500 boxes * 1.30 (30% increase) = 650 boxes
Now, to find the boxes produced per hour, we will divide the total number of boxes by the total number of hours worked:
650 boxes / 16 hours = 40.625 boxes/hr
So, the new productivity is approximately 40.6 boxes per hour which corresponds to option 1.
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PLEASE HELP 50 AND BEST ANSWER
Begin by printing out a copy of the periodic table. Use the file attached to the assignment page or download the file from the Course Resources folder.
1. Label the rows as the electron energy levels.
2. Label the number of valence electrons in Columns 1,2, and 13-18.
3. Label the metals, semi-metals, and non-metals using different colors. Make sure you don't obscure any of the information about different elements by coloring.
4. Label the ion charges for elements in the first 3 rows. Remember all the elements in Columns 1,2,16,17,18 will always have the same charge. Elements in Columns 13,14, or 15 can have different charges within the same row it's especially useful to write these charges on your periodic table. --
5. Label the trends for atomic size, ionization energy, and electron affinity.
Label the rows as the electron energy levels:
The rows of the periodic table are also known as periods. There are seven periods, and each period corresponds to a particular energy level. You can label them from 1 to 7, starting from the top row.
What are the responses to other questions?Label the number of valence electrons in Columns 1, 2, and 13-18:
Columns 1 and 2 are the s-block elements, and they have 1 and 2 valence electrons, respectively. Columns 13-18 are the p-block elements, and they have 3 to 8 valence electrons, respectively. You can label the number of valence electrons in each column.
Label the metals, semi-metals, and non-metals using different colors:
Metals are on the left side of the periodic table, semi-metals are in the middle, and non-metals are on the right side. You can use different colors to label them without obscuring any of the information about different elements.
Label the ion charges for elements in the first 3 rows:
Elements in the first 3 rows of the periodic table have predictable ion charges. The alkali metals (Group 1) have a charge of +1, the alkaline earth metals (Group 2) have a charge of +2, and the elements in Group 13 have a charge of +3. For Groups 15, 16, and 17, the charges are -3, -2, and -1, respectively. The noble gases (Group 18) are unreactive and do not form ions. You can write these charges for each element in their respective positions.
Label the trends for atomic size, ionization energy, and electron affinity:
Atomic size generally decreases from left to right across a period and increases from top to bottom within a group. Ionization energy generally increases from left to right across a period and increases from bottom to top within a group. Electron affinity generally increases from left to right across a period and becomes less negative from top to bottom within a group. You can label these trends on your periodic table as well.
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Find the magnitude of the torque that acts on the molecule when it is immersed in a uniform electric field of 6.19×105 N/C with its electric dipole vector at an angle of 69.9∘ from the direction of the field.
Answer:
\(\tau=5.81\times 10^5p\ N-m\)
Explanation:
We have,
Electric field, \(E=6.19\times 10^5\ N/C\)
The electric dipole vector at an angle of 69.9 degrees from the direction of the field.
The torque acting on a molecule is given by :
\(\tau=p\times E\\\\\tau=pE\sin\theta\)
p is electric dipole moment
\(\tau=p\times 6.19\times 10^{5}\times \sin (69.9)\\\\\tau=5.81\times 10^5p\ N-m\)
So, the magnitude of the torque acting on the molecule is \(5.81\times 10^5p\ N-m\).
Measurements of the height of various plants in an experiment are called
Answer:
ExplaMeasurements of the height of various plants in an experiment are called (Data).nation:
Please help me am I correct?
Answer:
sa tingin ko tama po yung answer niyo
a beam of light strikes an air/water surface. water has an index of refraction of 1.33. the angle of incidence is 4.00 degrees. what is the angle of reflection?
The angle of reflection, for a beam of light strikes an air/water surface at angle of incidence 4.00 degrees is, 2.88 degrees.
Assuming that the incident beam of light is coming from air, we can use the law of reflection and Snell's law to find the angle of reflection:
The law of reflection states that the angle of incidence is equal to the angle of reflection, so:
\(\theta_{i} = \theta_{r}\)
where \(\theta_{i}\) is the angle of incidence and \(\theta_{r}\) is the angle of reflection.
Snell's law relates the angles of incidence and refraction to the refractive indices of the two media:
n₁sinθ₁ = n₂sinθ₂
where n₁ and n₂ are the refractive indices of the two media (air and water, respectively), and θ₁ and θ₂ are the angles of incidence and refraction, respectively.
We can rearrange Snell's law to solve for θ₂:
θ₂ = sin⁻¹[(n₁/n₂)sinθ₁]
Plugging in the values given in the problem:
n₁ = 1 (refractive index of air)
n₂ = 1.33 (refractive index of water)
θ₁ = 4.00 degrees
θ₂ = sin⁻¹[(1/1.33)sin(4.00°)]
θ₂ = 2.88°
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Your total calorie _____ is an estimation of how many calories you burn when you exert yourself. A.Moderate B.Conditions C.Expenditure D.Anaerobic ( Subject P.E )
Answer:
C. Expenditure
Explanation:
I took the quiz
If a main-sequence star suddenly started burning hydrogen at a faster rate in its core, it would become. a. larger, hotter, and more luminous. b. larger, cooler, and more luminous. c. smaller, hotter, and more luminous. d. smaller, cooler, and more luminous.
If a main-sequence star suddenly started burning hydrogen at a faster rate in its core, it would become larger, hotter, and more luminous.
The increase in the rate of hydrogen burning in the star's core would lead to a release of more energy, causing the outer layers of the star to expand and become less dense, which results in an increase in the star's size.
At the same time, the increase in energy production would cause the temperature of the star's core to increase, which would increase the star's overall temperature and luminosity.
Therefore, the star would become larger, hotter, and more luminous, moving away from the main sequence towards the giant branch on the Hertzsprung-Russell diagram.
The increased luminosity and temperature would make the star appear brighter and bluer.
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in a tape recorder, the tape is pulled past the read-write heads at a constant speed by the drive mechanism. consider the reel from which the tape is pulled: as the tape is pulled off, the radius of the roll of remaining tape decreases. (a) how does the torque on the reel change with time? increases decreases stays the same (b) if the tape mechanism is suddenly turned on so that the tape is quickly pulled with a large force, is the tape more likely to break when pulled from a nearly full reel or from a nearly empty reel? nearly full nearly empty equally likely
(a) The torque on the reel increases with time as the radius of the roll of remaining tape decreases. This is because as the radius decreases, the leverage of the tape pulling on the reel increases, requiring more torque to maintain the constant speed of the tape.
(b) The tape is more likely to break when pulled from a nearly full reel because the larger radius of the roll provides more support for the tape and reduces the tension on the tape. When the tape is pulled quickly with a large force, the tension on the tape increases and a nearly full reel may not be able to support the tension, causing the tape to break.
On the other hand, a nearly empty reel has a smaller radius and therefore less support for the tape, which already has lower tension due to the smaller radius. So, it is less likely to break when pulled with a large force.
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A 26.5 kg crate is pushed with a force of 1,893 N, moving the crate a distance of 13.0 m. 579 W of power was used. For how much time was the force applied
Explanation:
\(t = \frac{f \times d}{p} \)
t = ?
f = 1893N
d = 13m
P = 579W
t = { 1893×13}/(579)
t = 42.5secs
Consider two celestial objects with masses m1 and m2 with a separation distance between their centers r. If the first mass m1 were to double and the second mass m2 were to triple, what would happen to the magnitude of the force of attraction
The new magnitude of the force of attraction will be 6 times the original force of attraction
How to determine the initial force Mass 1 = m₁Mass 2 = m₂ Gravitational constant = GDistance apart = rInitial force (F₁) = ?F = Gm₁m₂ / r²
F₁ = Gm₁m₂ / r²
How to determine the new force Mass 1 = 2m₁Mass 2 = 3m₂ Gravitational constant = GDistance apart (r) = rNew force (F₂) =?F = Gm₁m₂ / r²
F₂ = G × 2m₁ × 3m₂ / r²
F₂ = 6Gm₁m₂ / r²
But
F₁ = Gm₁m₂ / r²
Therefore
F₂ = 6Gm₁m₂ / r²
F₂ = 6F₁
Thus, the new magnitude of the force of attraction will be 6 times the original force of attraction
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You toss a ball straight upward, in a positive direction. The ball falls freely under the influence of gravity. At the highest point in the ball's motion.
A.) its velocity is zero and its acceleration is positive (upward).
B.) its velocity is zero and its acceleration is negative (downward).
C.) its velocity is positive (upward) and its acceleration is zero.
D.) its velocity is zero and its acceleration is zero.
Answer:
B.) its velocity is zero and its acceleration is negative (downward).
Explanation:
When the ball is thrown upwards in the air, the ball starts with its velocity being high and positive upwards against the force of gravity. Due to force of gravity pulling the object to the center of the earth, its velocity decreases as it reaches the maximum height where the velocity is instantaneously zero. At this maximum height its acceleration is -9.81 m/s².
At the highest point in the ball's motion, its velocity is zero and its acceleration is negative (downward).
All objects within the earth's gravitational field are affected by the force of gravity. Gravity is the reason why objects fall to the ground when they are thrown upwards.
If you toss a ball upward, the ball will fall freely under the influence of gravity. At the highest point in the ball's motion, its velocity is zero and its acceleration is negative (downward).
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The earth absorbs 240 W/m² of energy from the sun and radiates when measured at the earth's surface. • 240 W/m2
• 150 W/m2
• 390 W/m2
• 643 W/m2
The earth absorbs 240 W/m² of energy from the sun and radiates it back to space when measured at the earth's surface.
When measured at the Earth's surface, the amount of energy that the Earth absorbs from the sun and radiates back into space is approximately 240 W/m². This value represents the net energy balance at the Earth's surface, taking into account both incoming solar radiation and outgoing thermal radiation. The Earth's surface absorbs sunlight, which provides energy for various processes such as heating the atmosphere, evaporating water, and supporting biological activity. At the same time, the Earth's surface also emits thermal radiation, primarily in the form of infrared radiation, to maintain a thermal equilibrium. The balance between incoming solar radiation and outgoing thermal radiation is essential for maintaining the Earth's climate and temperature.
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An official major league baseball has a mass of 0. 14 kg. A pitcher throws a 40 m/s fastball which is hit by the batter straight back up the middle at a speed of 46 m/s.
-12.04 kg m/s is the change in momentum of the ball during the collision with the bat.
What is momentum and how is it calculated?An object with mass m with velocity v has momentum p, which is defined by the equation p = mv. Keep in mind that inertia is a vector of both magnitude and direction, just like velocity. The momentum of such an object increases together with its mass or speed.
Briefing:A ball weighs m = 0.14 kg.
The ball's initial speed is 40 m/s.
The ball's final velocity was -46 m/s.
(a) The following equation describes how the ball's momentum changes when it collides with the bat:
AP = m (v- u)
= 0.14 (-46-40)
= -12.04 kg m/s
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The complete question is -
An official major league baseball has a mass of 0.14 kg. A pitcher throws a 40 m/s fastball which is hit by the batter straight back up the middle at a speed of 46 m/s.
a) What is the change in momentum of the ball during the collision with the bat?
Please give an explanation on how to do this
The time that is taken by the cart is given as 34.7 s.
What is the time taken?
Let us have it at the back of our minds that what we are dealing with here is the velocity and that the velocity of the object can be said to be a vector quantity. If it is a vector quantity, we would need to look at the magnitude and the direction of the quantity.
We can now see that the velocity of the object can be defined as the change in the velocity of the object with time. We can now write;
V = Δx/t
V = velocity
Δx = change in the displacement
t = time
Then;
-0.418 = 5.40 - 19.9/t
t = -14.5/-0.418
t = 34.7 s
In the movement of the cart from one point on the plane to the other, the time that has been taken by the cart is about 34.7 s.
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The vertical columns on the periodic table of elements are called groups.
O A. True
B. False
Answer:
A. True
Explanation:
The vertical columns on the periodic table are called groups or families because of their similar chemical behavior.
Brainlist Pls!
As a city planner, you receive complaints from local residents about the safety of nearby roads and streets. One complaint concerns a stop sign at the corner of Pine Street and 1st Street. Residents complain that the speed limit in the area ( 8989 km/h) is too high to allow vehicles to stop in time. Under normal conditions this is not a problem, but when fog rolls in visibility can reduce to only 4747 meters. Because fog is a common occurrence in this region, you decide to investigate. The state highway department states that the effective coefficient of friction between a rolling wheel and asphalt ranges between 0. 5360. 536 and 0. 5990. 599 , whereas the effective coefficient of friction between a skidding (locked) wheel and asphalt ranges between 0. 3500. 350 and 0. 4800. 480. Vehicles of all types travel on the road, from small cars with a mass of 563563 kg to large trucks with a mass of 39513951 kg. Considering that some drivers will brake properly when slowing down and others will skid to stop, calculate the minimum and maximum braking distance needed to ensure that all vehicles traveling at the posted speed limit can stop before reaching the intersection
The minimum and maximum braking distances needed to ensure that all vehicles traveling at the posted speed limit can stop before reaching the intersection are as follows:
- For small cars: Minimum ≈ 1773.028 m, Maximum ≈ 1568.850 m
- For large trucks: Minimum ≈ 3285.760 m, Maximum ≈ 2409.595 m
To calculate the minimum and maximum braking distances, we can use the equations of motion for a decelerating vehicle.
The equation for the braking distance of a vehicle is given by:
d = (v^2) / (2 * μ * g)
where d is the braking distance, v is the initial velocity of the vehicle, μ is the coefficient of friction between the tires and the road, and g is the acceleration due to gravity.
Let's calculate the minimum and maximum braking distances separately for small cars and large trucks.
For small cars with a mass of 563 kg:
- Minimum braking distance:
v = 8989 km/h = (8989 * 1000) / 3600 m/s = 2496.944 m/s
μ_min = 0.536
d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.536 * 9.8) ≈ 1773.028 m
Maximum braking distance:
μ_max = 0.599
\(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.599 * 9.8) ≈ 1568.850 m\)
For large trucks with a mass of 3951395 kg:
- Minimum braking distance:
v = 8989 km/h = 2496.944 m/s (same as for small cars)
μ_min = 0.350
\(d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.350 * 9.8) ≈ 3285.760 m\)
Maximum braking distance:
μ_max = 0.480
\(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.480 * 9.8) ≈ 2409.595 m\)
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What is the SI unit for measuring Force?
A. Pounds
B. Grams
C. Newtons
D. Kilograms
Answer:
Newton.........
.....
1. The core of a red dwarf will eventually turn into a(n): a) medium mass star b) white dwarf c) planetary nebula d) sun e) black dwarf
Answer:
B
Explanation:
White dwarf. I love this type of science.
Answer:
I think planetary nebula but I'm not 100% sure
Explanation: