Calculate the power of the heater in W.​

Answer:

power=400Watt

Explanation:

work done =12kJ=12×10³=12000j

time taken=30s

power=?

as we know that

power=work done/time taken

power=12000J/30s

power=400Watt

i hope this will help you :)

Answer:

hello your question is incomplete below is the missing part of the  complete question

which statement best describes Jean-Baptiste Fourier’s influence on Jean-François Champollion? Fourier shared his research about mathematics with Champollion, which aided him in his research. Fourier was the first to introduce Champollion to the hieroglyphs on the Rosetta Stone, which fascinated him. Fourier shared his findings about the Rosetta Stone with Champollion, which helped him in his research. Fourier was the first to introduce Champollion to a variety of languages, which prompted his love of languages.

answer :  Fourier was the first to introduce Champollion to a variety of languages, which prompted his love of languages.

Explanation:

Jean-Baptiste Fourier's influence on Jean-Francois Champollion is that Fourier was the first to introduce Champollion to a variety of languages, which prompted his love of languages. also Fourier was a mathematician  who pleaded on the behalf of Champollion when he was about to be adopted into the military.

Answer: \(40\ N/C\)

Explanation:

Given

Magnitude of charge is \(q=0.5\ C\)

Force experienced is \(F=20\ N\)

Electric field intensity is the electrostatic force per unit charge

\(\therefore E=\dfrac{F}{q}\\\\\Rightarrow E=\dfrac{20}{0.50}\\\\\Rightarrow E=40\ N/C\)

Thus, the electric field intensity is \(40\ N/C\)

The result of multiplying a particle's mass by its velocity is the fluctuation in momentum of a ball, which is 30 kg per second. Since momentum has both a magnitude and a direction, it is a vector quantity.

Almost every action that involves motion has momentum. It is an important tenet of physicsFor instance, if a team is moving forward and trying to stop, it will be difficult.

mv - mu, where u = 0 and v = 10 m/s, equals change in momentum.  Note that the ball moved from rest, therefore its initial velocity was zero (u = 0).

Momentum change is equal to mv mu, which is 3*10 - 3*0, or 30.

30 kg/s = change in momentum.

Momentum can be compared to the "power" a moving body has, or the amount of force it can exert on another body. For instance, a baseball that is thrown quickly (high velocity) and has a small bulk (big mass) can have the exact same momentum as a bowling ball that is travelling very slowly (low velocity).

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Given :

Height from which ball is dropped , h = 40 m .

Acceleration due to gravity , g= 10 m/s² .

Initial velocity , u = 0 m/s .

To Find :

Velocity when ball covered 20 m and velocity when it hit the ground .

Solution :

Now , height when ball covered 20 m distance is , 40 - 20 = 20 m .

By equation of motion :

\(v^2=u^2+2gh\\\\v=\sqrt{2\times 10\times 20}\ m/s\\\\v=20\ m/s\)

Now , distance covered when body reaches ground is , 40 m .

Putting value h = 40 m in above equation , we get :

\(v=\sqrt{2\times 10\times 40}\ m/s\\\\v=20\sqrt{2}\ m/s\)

Hence , this is the required solution .

Answer:

nuclear fission

Explanation:

nuclear fission

Answer: Nuclear fission

Explanation:

Answer:

D. the universe began with an enormous explosion.

Explanation:

This theory states that the universe began as a single hot, dense, and small point. It then exploded, expanded, became less dense, and the temperature became cooler.

Hope this helps! :)

Explanation:

Advantages of physical models include accuracy, safety, visualization, education, and trying things out that would be impossible in the real world due to safety, cost, or practical concerns. You can visualize things that are extremely tiny, happened millions of years ago, or that otherwise can't be viewed directly.

Answer:

Plural cerebrums cerebra The largest part of the vertebrate brain, filling most of the skull and consisting of two cerebral hemispheres divided by a deep groove and joined by the corpus callosum, a transverse band of nerve fibers. The cerebrum processes complex sensory information and controls voluntary muscle activity.

Explanation:

Answer:

i donk know

Explanation:

I = 7 N-s

Explanation:

Impulse is defined as

I = ∆p = m(vf - vi)

We are given

m = 0.2 kg

vi = -10 m/s (to the left)

vf = +25 m/s (to the right)

Therefore, the impulse imparted on the puck is

I = (0.2 kg)[25 m/s - (-10 m/s)]

= (0.2 kg)(35 m/s)

= 7 N-s

The process used in fire investigation to determine if and where electrical circuits were energized at the time of the fire is live circuit analysis.

This is a technique in which investigators use specialized equipment to measure the voltage and amperage levels of electrical circuits in the building. Live circuit analysis is conducted once the electrical power supply is re-established on-site for investigating the fire's origin and cause. It involves checking electrical outlets, appliances, and other devices that might have been connected to electrical circuits in the building.

This process is vital for determining whether an electrical fault or malfunction caused the fire and identifying the responsible parties for negligence. In summary, the live circuit analysis is a standard fire investigation procedure that can determine the presence and location of electrical faults that led to a fire. The technique provides insights for experts to reconstruct the origin and causes of the fire to prevent future tragedies.

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Answer:

hope it helps you...........

The answer is definitely Potassium

The only quantity that will differ in the two gases is the number of moles of each gas

T

he ideal gas law is the combination of Charles's law, Boyle's and Avogadro's law. This ideal gas equation is given as follows;

PV = nRT

where;

P is the pressure of the gas

V is the volume of the gas

n is the number of moles of the gas

R is the gas constant

T is the temperature of the gas

If the pressure, volume, and temperature of the gases in the balloon are held constant, the only variable that will change is the number of moles of the gases.

Thus, the only quantity that will differ in the two gases is the number of moles of each gas

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Answer: C. The mass of each Gas

Explanation:

took the test got 100% hope you do the same peace

Answer:

A & B

Explanation:

He used 2 peach basket and a soccer ball

The power is a dependent parameter on work done for a given interval of time. The magnitude of power developed due to the applied force is 339 W.

The rate of doing work is known as Power. Mathematically, the power is equal to the ratio of work and time interval.

Given data -

The distance covered by the box is, d = 27.0 m.

The magnitude of the constant force is, F = 113 N.

The time interval for the application of force is, t = 9.00 s.

The expression for the power developed is given as,

P = W/t

here, W is the work done and its value is, W = F × d.

Solving as,

P = F × d/t

Solving as,

P = 113 × 27.0/9.0

P = 339 W

Thus, we can conclude that the magnitude of power developed due to the applied force is 339 W.

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Its magnetic axis does not lie in the same direction as its rotation axis. Uranus is the seventh planet from the Sun and the third largest planet in our solar system. Option e is Correct.

It is unique in several ways that distinguish it from every other planet in our solar system. One of these characteristics is that its magnetic axis is tilted almost 90 degrees to the plane of its orbit. The magnetic axis of a planet is the direction in which its magnetic field is pointed. The magnetic axis of a planet is usually aligned with its rotation axis, but this is not the case for Uranus. In fact, Uranus's magnetic axis is tilted by about 59 degrees relative to its orbit, which is much more than any other planet in our solar system.

In contrast, the other characteristics listed in the options are not unique to Uranus. Every planet in our solar system has its own set of moons, and the composition of their atmospheres varies. The orbits of the planets are also tilted with respect to the Sun, and some of them have magnetic fields that are tilted with respect to their rotation axes. However, the tilt of Uranus's magnetic axis is the most extreme of any planet in our solar system.  

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The net force needed to lift a full grocery sack uniformly is 32.115 N.

When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.

Given the weight of sack W = 210N and the acceleration a = 1.5m/s².

The mass of the sack will be

m = Weight / acceleration due to gravity

m = 210 N/9.81 m/s²

m = 21.41 kg

Using Newton's second law, the net force will be

F = mass x acceleration

F= 21.41 x 1.5

F = 32.115 N

Thus, the net force is 32.115 N.

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The frequency of the source that causes the wire to vibrate in 6 sections is approximately 229.63 Hz.

To find the frequency of the source causing the wire to vibrate in 6 sections, we can use the formula for the fundamental frequency of a vibrating string:

f = (1/2L) * sqrt(T/m),

where f is the frequency, L is the length of the wire, T is the tension in the wire, and m is the mass per unit length of the wire.

In this case, the length of the wire is given as 3.70 meters, the tension is 16.7 N, and the mass is 1.91 grams. However, we need to convert the mass to mass per unit length, so we divide it by the length of the wire:

m = (1.91 grams) / (3.70 meters) = 0.5162 grams/meter.

Converting the mass per unit length to kilograms per meter:

m = 0.5162 grams/meter * (1 kilogram / 1000 grams) = 0.0005162 kg/m.

Now we can substitute the values into the formula:

f = (1/2 * 3.70 meters) * sqrt(16.7 N / 0.0005162 kg/m).

Simplifying:

f = (1.85 meters) * sqrt(32365.79 kg/m^2).

Calculating:

f ≈ 229.63 Hz.

Therefore, the frequency of the source causing the wire to vibrate in 6 sections is approximately 229.63 Hz.

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Answer:

the mass of the volume unit of red copper equals 8.8gm.

a. The Sackur-Tetrode equation has the entropy to be  S = NkB [2 + 3[2 - ln(pX³h)]

b.  3S = NkB ln(V / Nλ³  shows the entropy of a gas with distinguishable particles

c.  The quantity 3S = NkB ln(V / Nλ³) is not an extensive quantity because it does not scale linearly with the size of the system.

a)

Entropy in the Sackur-Tetrode equation is denoted by S = NkB [2 + 3[2 - ln(pX3h)],

N = particle count,

kB = Boltzmann constant,

p =  gas's number density,

X = thermal wavelength,

h = Planck's factor.

When we consider two systems, each with a different number of particles and volume, the entropy of the combined system is equal to the sum of the entropies of the individual systems.

b) The entropy is given by 3S = NkB ln(V / Nλ³),

where V =  volume,

N=  total number of particles,

λ=  thermal wavelength.

The Helmholtz free energy (F) is defined as

F_ = U - TS.

IF we  differentiate the Helmholtz free energy with respect to temperature (T), we can obtain the entropy expression 3S = NkB ln(V / Nλ³).

c)  

Because it does not increase linearly with system size, the amount 3S = NkB ln(V / N3) is not a large quantity. In a large quantity, doubling the system's size would also double the quantity's value.

In this our scenario, doubling the system size would not result in a doubling of the entropy. As a result, it is not regarded as a large number.

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Since the red ball attains twice the speed of the blue ball, we know that it also travels twice the distance in the same amount of time.

Since both balls have the same mass, we can use the equation:
work = force x distance
to compare the work done on each ball.
Let's call the force applied to the red ball F1 and the force applied to the blue ball F2.
We know that the red ball attains twice the speed of the blue ball, so we can write:
v1 = 2v2
Using the equation for acceleration:
a = F/m
we can rearrange to solve for the net force on each ball:
F1 = m*a1
F2 = m*a2

We can then substitute the equation for acceleration:

F1 = m*(v1/t)

F2 = m*(v2/t)

where t is the time it takes for each ball to reach its final speed.
We can then compare the work done on each ball:
work1 = F1*d
work2 = F2*d

where d is the distance each ball travels during the time it takes to reach its final speed.

d1 = 2d2
Substituting this into the equations for work:
work1 = F1*2d2
work2 = F2*d2

Dividing these two equations:
work1/work2 = (F1*2d2)/(F2*d2)
Simplifying:
work1/work2 = F1/F2

Since we know that the red ball attains twice the speed of the blue ball, we can also conclude that the net force applied to the red ball is twice that of the blue ball:

F1 = 2F2
Substituting this into the equation for work ratio:
work1/work2 = 2F2/F2
work1/work2 = 2

Therefore, the work done on the red ball is twice that of the blue ball.
When comparing the work done on the red ball to the blue ball, the work done on the red ball is four times greater than the work done on the blue ball. Since both balls have the same mass and the red ball attains twice the speed of the blue ball, the kinetic energy (which is proportional to the work done) is greater for the red ball by a factor of 2^2, as kinetic energy is calculated as (1/2)mv^2.

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From the Rutherford's model of the atom, the electron moves round in orbits as the planets moves round the sun.

According to the Rutherford's model of the atom, the electron moves round in orbits as the planets moves round the sun. The nucleus is at the focus of concentric ellipses.

This model solved the riddle of the experiment of Rutherford which suggested  large positively charged core at the center of the atom and not the large sphere of positive and negative charges as previously opined by Thompson.

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Answer:

Action-Reaction Force Examples in Everyday Life

Recoil of a Gun.

Swimming.

Pushing the Wall.

Diving off a Raft.

Space Shuttle.

Explanation:

hope this helps

The velocity of the eagle is 12.4 m/s

Velocity is the rate of change of displacement.

The S.I unit of velocity is m/s.

To calculate the velocity of the eagle, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the velocity of the eagle is 12.4 m/s.

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Answer:

a) The closest object Anne can see, while wearing Bill's glasses is at approximately 22.39 cm relative to her eyes

b) The closest object Bill can see while wearing Anne's glasses is at approximately 26.38 cm relative to his eyes

Explanation:

The point where Bill has a near point = 125 cm

The point where Anne has a near point = 75.0 cm

Their vision are both corrected to the normal near point = 25.0 cm

The distance of their glasses from the eye, d = 2.0 cm

The lens formula is presented as follows;

\(\dfrac{1}{f} =\dfrac{1}{d_0} +\dfrac{1}{d_i}\)

The required distance of the of the object from Bill's glass, \(d_{oB}\) = 25 cm - 2.0 cm = 23.0 cm

The distance of the of the image from Bill's glass, \(d_{iB}\) = -(125 cm - 2.0 cm) = -123 cm

Therefore, for Bill, we have;

\(\dfrac{1}{f_B} =\dfrac{1}{d_{0B}} +\dfrac{1}{d_{iB}}\)

Plugging in the values gives;

\(\dfrac{1}{f_B} =\dfrac{1}{23} -\dfrac{1}{123} = \dfrac{100}{2,829}\)

Therefore;

\(f_B\) = 2,829/100 cm = 28.29 cm

The required distance of the of the object from Anne's glass, \(d_{oA}\) = 25 cm - 2.0 cm = 23.0 cm

The distance of the of the image from Anne's glass, \(d_{iA}\) = -(75 cm - 2 cm) = -73 cm

The focal length for Anne is therefore;

\(\dfrac{1}{f_A} =\dfrac{1}{d_{0A}} +\dfrac{1}{d_{iA}}\)

Plugging in the values gives;

\(\dfrac{1}{f_A} =\dfrac{1}{23} -\dfrac{1}{73} = \dfrac{50}{1,679}\)

Therefore, we have;

\(f_A\) = 1,679/50 cm = 33.58 cm

a) When Anne wears Bill's lasses, we have;

\(\dfrac{1}{f_B} =\dfrac{1}{d_{0A}} +\dfrac{1}{d_{iA}}\)

Therefore, we get;

\(\dfrac{1}{28.29} =\dfrac{1}{d_{0A}} -\dfrac{1}{73}\)

\(\dfrac{1}{d_{0A}} = \dfrac{1}{28.29} + \dfrac{1}{73} = \dfrac{10,129}{206,517}\)

\(d_{0A}\) ≈ 20.39 cm

The distance of the closest object Anne can see, from her eye, \(d_{oe}\) =  \(d_{0A}\) + d

∴ \(d_{oe}\) ≈ 20.39 cm + 2.0 cm = 22.39 cm

The distance of the closest object Anne can see, from her eye, \(d_{oe}\) ≈ 22.39 cm

b) The closest object that can be seen when Bill wears Anne's glasses, we have;

\(\dfrac{1}{f_A} =\dfrac{1}{d_{0B}} +\dfrac{1}{d_{iB}}\)

Therefore;

\(\dfrac{1}{33.58} =\dfrac{1}{d_{0B}} -\dfrac{1}{123}\)

\(\dfrac{1}{d_{0B}} = \dfrac{1}{33.58} +\dfrac{1}{123} = \dfrac{7,829}{206,517}\)

∴ \(d_{oB}\) ≈ 26.38 cm

The closest object Bill can see while wearing Anne's glasses,  \(d_{oB}\) ≈ 26.38 cm.

Answer: So, our current when our switch is open is going to be equal to the voltage across the resistors, and that's going to be our 12 volts, 12 volts, divided by the equivalent resistance of these resistors. When the switch is open, essentially, we just have R1 and R2 in series, and so this is just gonna be R1+R2.

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The phenomenon in hearing that is analogous to spatial frequency channels in vision is critical bands. Hence, the correct option is A: Critical bands.

Critical bands are regions of the audible frequency range in which a complex sound is divided into individual, discrete frequency bands by the human auditory system.

For instance, when different frequencies in a complex sound, such as a musical instrument or a human voice, are picked up by the ear, they are sent to the brain via various channels that respond to specific frequencies.

These channels are referred to as critical bands. The frequency range of these bands varies depending on the loudness of the sound.

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