Answer:
6.7%
Explanation:
The formula of the compound is given as:
C₆ H₁₂ O₆
The problem here is to find the percent composition of hydrogen.
First;
Find the molar mass of C₆ H₁₂ O₆ = 6(12) + 12(1) + 6(16) = 180g/mol
Secondly;
Percentage composition of H = \(\frac{molar mass of H}{Molar mass of compound}\) x 100
Percentage composition of H = \(\frac{12(1)}{180}\) x 100 = 6.7%
Temperature (°C)
Heating Curve for Water
160
140
120
100
80
60
40
20
0
-20
1 2 3 4 5 6 7 8 9 10
Time (min)
At what temperature does the solid start melting?
O -20°C
0°C
O 20°C
O 80 c
Answer:
heating point for water - 100°
The melting point (MP) of a substance is the temperature at which it melts. A solid's melting point is a physical characteristic that can be used to identify a substance. Here the correct option is B.
The melting point of a solid is the temperature at which it begins to liquefy. A substance's normal melting point is its melting point under atmospheric pressure. Ice often melts at 0 degrees Celsius.
A physical process called melting or fusing causes a substance to change its phase from a solid to a liquid. This happens when the solid's internal energy rises, usually as a result of heat or pressure being applied, which raises the substance's temperature to the melting point.
Thus the correct option is B.
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In acidic solution. A 70.0 mL sample of a solution containing Fe2+ requires 70.0 mL of a 0.150 M KMnO4 solution for complete reaction. What is the concentration of the Fe2+ in the original solution?
Answer:
0.75M Fe²⁺
Explanation:
First, we need to balance the redox reaction in acidic medium. Then, we can obtain moles of KMnO4 and with the reaction moles and molarity of the Fe²⁺ solution:
Redox Balance:
Fe²⁺ → Fe³⁺ + 1e⁻
5e⁻ + 8H⁺ + MnO₄⁻ → Mn²⁺ + 4H₂O
___________________________
5Fe²⁺ + 5e⁻ + 8H⁺ + MnO₄⁻ → 5Fe³⁺ + 5e⁻ + Mn²⁺ + 4H₂O
5Fe²⁺ + 8H⁺ + MnO₄⁻ → 5Fe³⁺ + Mn²⁺ + 4H₂OMoles of KMnO₄:
70.0mL = 0.0700L * (0.150mol / L) = 0.0105 moles KMnO₄
Moles and molarity Fe²⁺:
0.0105 moles KMnO₄ * (5 moles Fe²⁺ / 1mol KMnO₄) = 0.0525 moles Fe²⁺
In 70.0mL = 0.0700L:
0.0525 moles Fe²⁺ / 0.0700L =
0.75M Fe²⁺write and balance the equation for the reaction between nitric acid and potassium iodide. the products are potassium nitrate, iodine, nitrogen monoxide, and water.
The balanced equation for the reaction between nitric acid and potassium iodide is: 8HNO₃ + 6KI → 3I₂ + 4NO + 4KNO₃ + 6H₂O
This equation represents a redox reaction, where nitric acid (HNO₃) acts as the oxidizing agent and potassium iodide (KI) acts as the reducing agent. The reaction results in the formation of potassium nitrate (KNO₃), iodine (I₂), nitrogen monoxide (NO), and water (H₂O).
In order to balance the equation, we need to make sure that the number of atoms of each element is equal on both sides of the equation. This is achieved by adjusting the coefficients in front of the chemical formulas.
In this case, we need to multiply the nitric acid by 8, the potassium iodide by 6, the iodine by 3, the nitrogen monoxide by 4, and the potassium nitrate and water by 4 and 6, respectively.
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When the [CO2] and [H2CO3] are both horizontal lines, the rate of the forward reaction is
the rate of the reverse reaction
faster than
slower than
the same as
When \(CO_{2}\) and \(H_{2} CO_{3}\) are both horizontal lines, the rate of the forward reaction is the same as the rate of the reverse reaction. The reaction is occurring at equilibrium, with no net change in the concentrations of reactants and products over time.
When the concentration of carbon dioxide \(CO_{2}\) and the concentration of carbonic acid \(H_{2} CO_{3}\) are both horizontal lines, it indicates that their concentrations remain constant over time. In such a scenario, the rate of the forward reaction is the same as the rate of the reverse reaction. A horizontal line on a concentration-time graph suggests that the concentrations of the reactants and products are not changing, implying that the reaction has reached equilibrium. At equilibrium, the rate of the forward reaction equals the rate of the reverse reaction. This is a fundamental principle of chemical equilibrium, described by the principle of microscopic reversibility.
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__C2H5OH + __O2 -> __CO2 + H2O Balance the Equation
Answer: C2H5OH + 3O2-------=2CO2 + 3H2O
Explanation:
Use the following chemical equation to answer the following problems:
2 C4H6+11 02-> 8 CO2 + 6 H20
If 20 moles of fuel are combusted in the above equation, how many moles
of 02 are consumed?
What is the limiting reactant for this equation based on the previous
question?
110 moles of O2 are consumed when 20 moles of C4H6 are combusted ; Based on the amount of O2 available, it is the limiting reactant in this equation.
What is meant by combustion reaction?A reaction in which substance reacts with the oxygen gas and producing energy in the form of light and heat is called as combustion reaction.
2 C4H6 + 11 O2 -> 8 CO2 + 6 H2O
(11 moles O2 / 2 moles C4H6) x 20 moles C4H6 = 110 moles O2
Therefore, 110 moles of O2 are consumed when 20 moles of C4H6 are combusted.
From the previous calculation, we know that 110 moles of O2 are consumed when 20 moles of C4H6 are combusted. This means that we need 20/2 = 10 moles of O2 to react with the available 20 moles of C4H6.
However, if we only have 8 moles of O2 available, then O2 will be the limiting reactant, as there is not enough O2 to react with all of the C4H6.
Therefore, based on the amount of O2 available, it is the limiting reactant in this equation.
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The chart shows the properties of four elements.
Based on these properties, which element(s) is most likely a metal?
Question 1 options:
Element 1
Element 2
Element 3
Element 4
Answer:
Element 3
Explanation:
Properties of metals are:
- Being shiny
- Are good conductors of electricity
- Are good conductors of heat
- Have a high melting point
Element 3 has all of these properties, so it is most likely a metal.
Hope this helps!
Answer: 1 and 3
Explanation:
How do you calculate enthalpy change from Gibbs free energy?
To calculate enthalpy change from Gibbs free energy, you can use the following equation:
ΔH = ΔG + TΔS
ΔH is the enthalpy change ΔG is the Gibbs free energy change T is the temperature in Kelvin ΔS is the entropy changeGibbs free energy is a thermodynamic property that is used to determine the amount of energy available to do work in a system. It is denoted by the symbol G and is defined as the difference between the enthalpy (H) and the product of the temperature (T) and entropy (S)
Gibbs free energy is a useful tool for predicting the direction of a chemical reaction and the spontaneity of a process. If the Gibbs free energy of a reaction is negative, the reaction is spontaneous and will proceed in the forward direction. If the Gibbs free energy of a reaction is positive, the reaction is non-spontaneous and will not proceed in the forward direction without the input of energy. If the Gibbs free energy of a reaction is zero, the reaction is at equilibrium and there is no net change in the system.
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is air a pure substance
No, air is not a pure substance. Because air contains other gases like Nitrogen, Carbon monoxide etc..,
if 8.00 g of pentane is mixed with 10.0 g of oxygen, which is the limiting reactant? (hint: compare it to either of the products).
Pentane is the limiting reactant.
C5H12 (l) + 8O2 → 5Co2 (g) + 6H2O (g)
1mol. of C5H12. reacts with. 8mol of O2
Molar mass of C5H12 = 8 g/mol
Molar mass of O2 = 10g/mol
8 g of C5H12 reacts with 8 × 32 = 256 g of O2
10 g of C5H12 reacts with 256 × 10/8 = 320 g of O2
Limiting reagent is the substance which is not consumed when the chemical reaction is complete.
Pentane is the limiting reactant.
The first liquid among the alkanes, pentane is a colorless, flammable liquid that is lighter than water. At 900 ppm, it can be smelled, and at 5000 ppm, there is a substantial amount of odour strength. There are two other isomers that it can take, namely isopentane [(CH3)2CHCH2CH3] and neopentane [C(CH3)4]. It appears that straight-chain pentane and isopentane (2-methylbutane) have similar physical and physiological properties. In terms of its physical and physiological properties, neopentane (2,2-dimethylpropane) is comparable to butane. C5 pentane in air is equivalent to 3 mg m3 per part per million. A naturally occurring component of the main paraffin portion of crude oil and also present in natural gas, pentane is a five-carbon aliphatic molecule.
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10) A student’s calculation w as found to have a 15.6% error, and the actual value w as determined to be 25.7 mL. W hat are the tw o possible values for the student’s experimental measurement?
Answer:
The actual value = 25.7 ml
The error = 15.6%
This means that the value of error = 0.156 * 25.7 = 4.0092 ml
Now, the error percentage found means that the student got the value either greater than the actual one with the value of error or less than the actual one with the value of error.
This means that the two possible readings are:
either : 25.7 + 4.0092 = 29.7092 ml
or : 25.7 - 4.0092 = 21.6908 ml
Explanation:
a tank contains 1.5 moles of gas a, 2.0 moles of gas b, and 2.5 moles of gas c. if the total pressure of the gas mixture is 0.80 atmospheres, what is the partial pressure of gas a?
The term "partial pressure" refers to the amount of pressure that each gas in a mix exerts. A mole fraction of the a gas,x, can also be used to formulate Dalton's law.
The partial pressure formula: what is it?
Partial pressures can be calculated in one of two ways: 1) To determine the individual pressures of each gas in a mixture, use PV = nRT. 2) Determine the proportion of pressure from of the total pressure that may be assigned to each single gas by using the molar concentration of each gas.
What is the name for partial pressure?
The idea of partial pressure is derived from the fact so each individual gas contributes to the overall pressure in a given proportion, which corresponds to its partial pressure. In order to characterise all the pieces, it is essentially equivalent to taking a percent or proportion of the whole.
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How do you find the molar mass of C2H5OH?
Molar mass is the mass of one mole of a substance, and is often used in chemistry to calculate the number of moles in a given mass of a substance. To find the molar mass of a substance, we add up the molar masses of each element present in the compound.
In the case of C2H5OH, also known as ethanol, the molar mass can be found by adding up the molar masses of carbon, hydrogen, and oxygen.
First, we know that there are 2 carbon atoms present in the compound. The molar mass of carbon is 12.01 g/mol. So, the mass of 2 carbon atoms is 2 x 12.01 = 24.02 g/mol.
Next, we know that there are 6 hydrogen atoms present in the compound. The molar mass of hydrogen is 1.01 g/mol. So, the mass of 6 hydrogen atoms is 6 x 1.01 = 6.06 g/mol.
Finally, we know that there is 1 oxygen atom present in the compound. The molar mass of oxygen is 16.00 g/mol. So, the mass of 1 oxygen atom is 1 x 16.00 = 16.00 g/mol.
To find the molar mass of the compound, we add up the molar masses of the individual elements. So, the molar mass of C2H5OH is:
24.02 g/mol + 6.06 g/mol + 16.00 g/mol = 46.08 g/mol
Therefore, the molar mass of C2H5OH is 46.08 g/mol.
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Why is brass more suitable than copper for a key?
Answer:
Brass does not bend as easily as copper.
Explanation:
Brass has more durability due to it having zinc in it.
Answer: Alloy strength
Explanation:
Copper and zinc atoms are different sizes. This distorts the regular lattice structure in brass, so layers of atoms cannot slide over each other so easily. This makes brass stronger than copper or zinc alone.
What is the mole fraction of each component in a solution made
by mixing 300 g of ethanol (C2H5OH) and 500.0 g of water?
The mole fraction of ethanol in the solution is 0.1903, and the mole fraction of water in the solution is 0.8097.
Mole fractionsTo calculate the mole fraction of each component in the solution, we need to determine the number of moles of each component first.
The molar mass of ethanol (C2H5OH) is:
2(12.01 g/mol) + 6(1.01 g/mol) + 1(16.00 g/mol) = 46.07 g/mol
Number of moles of ethanol = mass/molar mass = 300 g / 46.07 g/mol = 6.5166 mol
The molar mass of water (H2O) is:
2(1.01 g/mol) + 1(16.00 g/mol) = 18.02 g/mol
Number of moles of water = mass/molar mass = 500.0 g / 18.02 g/mol = 27.7459 molThe total number of moles in the solution is: 6.5166 mol + 27.7459 mol = 34.2625 molThe mole fraction of ethanol is:
moles of ethanol / total moles = 6.5166 mol / 34.2625 mol = 0.1903
The mole fraction of water is:
moles of water / total moles = 27.7459 mol / 34.2625 mol = 0.8097
Therefore, the mole fraction of ethanol in the solution is 0.1903, and the mole fraction of water in the solution is 0.8097.
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Oxalic acid (98%) is a polyprotic acid. It has a density of 1.65 g/cm^3 and a melting point of 189.5°C. Oxalic acid has a molecular mass of 90.03 g/mol and with a pka1 of 5.62 x10^-2. What volume of oxalic acid must be added to sufficient water to give a 1.500 liter solution that is 0.300 F (in formal concentration)?
Approximately 24.55 cm^3 of oxalic acid must be added to sufficient water to give a 1.500 liter solution with a formal concentration of 0.300 F.
To find the volume of oxalic acid needed to make a 1.500 liter solution with a formal concentration of 0.300 F, we need to use the equation:
Formal concentration (F) = (moles of solute) / (volume of solution in liters)
First, we need to calculate the moles of oxalic acid required. The formal concentration (F) is given as 0.300, so:
0.300 = (moles of oxalic acid) / 1.500
Rearranging the equation, we find:
moles of oxalic acid = 0.300 * 1.500
moles of oxalic acid = 0.450
Next, we can calculate the mass of oxalic acid needed using its molecular mass:
mass of oxalic acid = moles of oxalic acid * molecular mass
mass of oxalic acid = 0.450 * 90.03
mass of oxalic acid = 40.5145 g
Finally, we can calculate the volume of oxalic acid needed using its density:
volume of oxalic acid = mass of oxalic acid / density
volume of oxalic acid = 40.5145 g / 1.65 g/cm^3
volume of oxalic acid = 24.55 cm^3
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1 mole of hydrogen gas and 0.5 moles of oxygen gas is produced from 1 mole of liquid water collected in separate 10 L containers at 1 atm. Will the temperatures of the gases be equal
According to the given statement, 1 mole of hydrogen gas and 0.5 moles of oxygen gas are produced from 1 mole of liquid water collected in separate 10 L containers at 1 atm. We have to determine whether the temperatures of the gases will be equal or not. Yes, the temperature of the gases will be equal.
Given:1 mole of hydrogen gas and 0.5 moles of oxygen gas are produced from 1 mole of liquid water collected in separate 10 L containers at 1 atm.
2H₂ + O₂ → 2H₂ONow, the mole ratio between H₂ and O₂ is 2:1. So the mole of H₂ is greater than that of O₂, which means hydrogen will be the limiting reactant. Let's find out the moles of H₂ and O₂ used:1 mole of H₂O produces 1 mole of H₂ and 0.5 moles of O₂∴ 1 mole of H₂O requires 0.5 mole of O₂0.5 mole of O₂ is used in the reaction So, the number of moles of H₂ used = number of moles of O₂ used = 0.5 moles.
The ideal gas law is: P V = n R T where, P = pressure V = volume of the gas = number of moles of gas = universal gas constant T = temperature of the gas . Now, as the volume of both the gases is equal and the pressure of both the gases is equal, then we can compare their temperatures as: P₁V₁/T₁ = P₂V₂/T₂V₁ = V₂ and P₁ = P₂ .
So, P₁V₁/T₁ = P₂V₂/T₂ can be written as T₁/T₂ = n₂/n₁
By substituting the given values we get, T₁/T₂ = 0.5/1 = 1/2T₁ = 2T₂So, the temperature of the gases is in the ratio of 1:2. The temperature of oxygen gas is half of that of hydrogen gas, but the temperature of both the gases is not given so we cannot determine the actual value of the temperature of the gases.
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the reported molar absorptivity of red dye number three is 0.715 mol if a solution of red dye number three displays in observance of 1.358 and a cute bed that is 0.244 cm
The reported molar absorptivity of red dye number three is 0.715 mol/L*cm. If a solution of red dye number three displays an absorbance of 1.358 and has a cuvette path length of 0.244 cm, you can use the Beer-Lambert law to calculate the concentration of the solution. The Beer-Lambert law is given by:
A = ε * c * l
Where A is the absorbance, ε is the molar absorptivity (0.715 mol/L*cm), c is the concentration, and l is the path length of the cuvette (0.244 cm).
Rearrange the equation to solve for the concentration (c):
c = A / (ε * l)
Substitute the given values:
c = 1.358 / (0.715 * 0.244)
Calculate the concentration:
c ≈ 7.724 mol/L
Therefore, the concentration of the red dye number three solution is approximately 7.724 mol/L.
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As Nicole walks to her dorm room after a study group in the library she sees a backpack being stolen. The neurotransmitter activated during this emergency situation is
Multiple choice question.
a. norepinephrine.
b. endocrine.
c. insulin.
d. serotonin.
The neurotransmitter activated during the emergency situation is option A: norepinephrine.
A neurotransmitter and a hormone, norepinephrine is also known as noradrenaline. Dopamine is converted into norepinephrine, a neurotransmitter. Nerve cells in the brainstem region and a region close to the spinal cord produce norepinephrine. Your adrenal glands release norepinephrine, a hormone, in response to stress. The fight-or-flight response is a response that alters several bodily functions. Thus, it perceives danger as mentioned in the question.
The sympathetic nervous system, which is a component of your body's immediate "fight-or-flight" response to danger, produces norepinephrine. The flight-or-flight reaction is also referred to as the acute stress response in medicine.
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What volume of zero. Zero 105 – M HBR solution is required to ta trait 125 ML of zero. Zero 100 – by M Ca (OH)2 solution.
Step 1
The reaction:
Ca(OH)2 (aq) + 2 HBr (aq) => CaBr2 (aq) + 2 H2O (l) (compelted and balanced)
----------------
Step 2
Information provided:
0.0105 M HBr
125 mL of 0.0100 M Ca(OH)2
----------------
Step 3
The number of moles of Ca(OH)2:
Molarity (mol/L) = moles of Ca(OH)2/volume of the solution (L)
Volume = 125 mL x (1 L/1000 mL) = 0.125 L
Therefore,
Molarity x volume (L) = moles
0.0100 mol/L x 0.125 L = 1.25x10^-3 moles of Ca(OH)2
-----------------
Step 4
The number of moles of HBr, by stoichiometry:
Ca(OH)2 (aq) + 2 HBr (aq) => CaBr2 (aq) + 2 H2O (l)
1 mol Ca(OH)2 ------ 2 moles HBr
1.25x10^-3 moles ------ X
X = 1.25x10^-3 moles x 2 moles HBr/1 mol Ca(OH)2
X = 2.5x10^-3 moles HBr
----------------
Step 5
The volume of HBr needed:
Molarity = moles of HBr/volume of solution (L)
Volume = moles of HBr/molarity
Volume = 2.5x10^-3 moles HBr/0.0105 mol/L
Volume = 0.238 L
Volume = 0.238 L x (1000 mL/1 L) = 238 mL
Answer: 238 mL or 0.238 L (there are no matches)
Use the change of base rule to find the logarithm to four decimal places. log 143.2 O 0.2213 O 4.5186 2.2593 O
0.4771
Using the change of base rule to find the logarithm to four decimal places. the correct answer is 11.4235.
To find the logarithm of 143.2 using the change of base rule, we can choose any base we prefer. Let's use base 10 and natural logarithm (base e) for this calculation.
First, we'll use the change of base formula, which states that log(base b) x = log(base c) x / log(base c) b. In this case, we'll calculate log(base 10) 143.2.
We'll use the natural logarithm (ln) as our intermediary step. The natural logarithm of 143.2 can be calculated as ln(143.2).
Using a calculator, we find that ln(143.2) is approximately 4.9628.
Next, we need to calculate log(base 10) e, which is the logarithm of e with base 10. Using a calculator, we find log(base 10) e is approximately 0.4343.
Finally, we apply the change of base formula:
log(base 10) 143.2 ≈ ln(143.2) / log(base 10) e
≈ 4.9628 / 0.4343
≈ 11.4235
Rounding to four decimal places, the logarithm of 143.2 using base 10 is approximately 11.4235.
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Calculate the mass in kilograms for
204 mol BrCl3
The molar mass of Br is 79.904 grams/mole and the molar mass of Cl is 35.453 grams/mole.
There are 3 Cl atoms so we'll multiply it's molar mass by 3. So:
35.453 x 3 = 106.359
Now we add this number to the molar mass of Br and we get:
106.359 + 79.904 = 186.263
The molar mass of BrCl3 is 186.263 grams/mole
Now we just multiply this number by the amount of moles in the question which is 204.
186.263 x 204 = 37997.652 g which is 37.997652 kg or 38.0 kg if significant figures are important.
A sample of ideal gas at room temperature occupies a volume of 28.0 L at a pressure of 882 torr. If the pressurechanges to 4410 torr , with no change in the temperature or moles of gas, what is the new volume, V?Express your answer with the appropriate units.
To solve this problem, we could use the Boyle's law since there's a sample of ideal gas and temperature is constant.
Boyle's law tells us that:
Replacing the values of the problem:
The new volume V equals 5.6L.
What’s different about the object floating and the water?
I need help plz.
Answer:
Different objects float at different levels in the water because as most regular objects are lowered into the surface of water, the upward push of the water steadily increases until it is in balance with the weight force of the object, and the object then continues floating at this level with the two forces in balance.
Karina strikes a match to light a candle
Answer:
A burning match represents an exothermic reaction. The chemicals release energy in the form of heat and light as the reaction progresses.
Explanation:
Sample Response
Chemical _____
energy is the energy stored in the chemical
bonds.
Answer:
yeah
Explanation:
it is a form of stored energy that is released when needed by a conversion chemical energy therefore it is a form of potential energy
hope this helps
Is Mg(CH3COO)2 soluble or insoluble
Answer:
It is Soluble
Explanation:
Name- Magnesium acetate
It dissolves easily in water and alcohol.
describe how to identify the smell of gas in the laboratory
Answer:
When you are in the laboratory and take a direct sniff the chemicals you are using, you run the risk of damaging your mucous membranes or your lungs. When its necessary to smell chemicals in the lab, the proper technique is to cup your hand above the container and waft the air towards your face.
Gas is a naturally odourless substance, but the completely harmless artificial smell is added to make it more detectable. The substance is called mercaptan and gives off a strong sulphur like smell.
Which of the following best describes the impact of glaciers upon the surface of the earth?
a.
Ice buried continents under a few hundred feet of ice.
b.
Glaciers scraped across the surface and altered landscapes and the course of rivers.
c.
The passage of glaciers created new ecosystems.
d.
All of the above.
Answer:
New Answer is : B - Glaciers scraped across the surface and altered landscapes and the course of rivers.
Explanation:
Edge 2020
The impact of glaciers on the surface is that glaciers scraped across the surface and altered landscapes and the course of rivers.
What is a glacier?A glacier refers to a heap of ice that has stayed there for a large number of years. The earth is filled with many glaciers and about 90% of fresh water are trapped in glaciers.
The impact of glaciers on the surface is that glaciers scraped across the surface and altered landscapes and the course of rivers.
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Describe what occurs when a metal is placed into an acid and the equation and what is occurring within it
When a metal is placed into an acid, a chemical reaction called a redox reaction occurs. In this process, the metal loses electrons (oxidation) and the acid gains electrons (reduction). This results in the formation of a salt and hydrogen gas is released. The general equation for this reaction is:
Metal + Acid → Salt + Hydrogen gas
For example, when zinc is placed into hydrochloric acid, the reaction is:
Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)
In this reaction, zinc is oxidized to form zinc chloride (ZnCl₂) while hydrogen ions (H⁺) in the hydrochloric acid are reduced to form hydrogen gas (H₂).
The release of hydrogen gas can be observed as bubbles forming in the solution. This process demonstrates the reactivity of metals with acids, which depends on the metal's position in the reactivity series.
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