Calculate the net force using the diagram below: (PLS EXPLAIN HOW U GOT TO UR ANSWER)

Calculate The Net Force Using The Diagram Below: (PLS EXPLAIN HOW U GOT TO UR ANSWER)

Answers

Answer 1

The net force acting on the 3 Kg object given in the diagram above is 30 N

How do I determine the net force?

Net force is simply defined as the resultant force acting on the object when numerous forces are directed towards the object.

Mathematically, we expresss the net force as follow:

Net force = Frictional force - force applied

Net force = Force applied - opposite force

Now, we shall determine the net force acting on the 3 Kg object as follow:

Mass of object = 3 KgForce to the right = 15 NForce to the left = 45 NUpward force = 45 NDownward force = 45 NNet force =?

Net force = Force to the left - Force to the right

Net force = 45 - 15

Net force = 30 N

Thus, from the above calaculation, we can conclude that the net force is 30 N

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Related Questions

Two cars start from the same point. one travels south at 20 miles an hour, the other goes east at 10 miles an hour. at what rate is the distance between the two cars increasing 1 hour later?

Answers


To find the rate at which the distance between the two cars is increasing, we can use the concept of relative motion.

Let's assume that the initial position of the two cars is the origin (0,0) on a coordinate plane.

The first car is traveling south at 20 miles per hour. Since it has been 1 hour, it would have traveled 20 miles. Therefore, its new position would be (0, -20).

The second car is traveling east at 10 miles per hour. In 1 hour, it would have traveled 10 miles. Therefore, its new position would be (10, 0).

Now, we can calculate the distance between the two cars using the distance formula:

Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Plugging in the coordinates, we get:
Distance = sqrt((10 - 0)^2 + (0 - (-20))^2)
Distance = sqrt(10^2 + 20^2)
Distance = sqrt(100 + 400)
Distance = sqrt(500)
Distance ≈ 22.36 miles

Therefore, the distance between the two cars is approximately 22.36 miles after 1 hour.

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Select the correct answer.
Which statement about pneumatic systems is true?
A.
Pneumatic systems generate greater force than hydraulic systems.
B.
Pneumatic systems are safe to use at any level of pressure.
C.
Pneumatic systems are more expensive than hydraulic systems.
D.
Pneumatic systems are cleaner than hydraulic systems.

Answers

Statement D about pneumatic systems is true. Pneumatic systems are cleaner than hydraulic systems.

What is the pneumatic system?

Pneumatic systems are employed in a wide range of manufacturing and assembly applications. They can be used to transport objects on production lines as well as in maintenance facilities.

In hydraulic systems liquid is used as fluid for the force transmission. While in the pneumatic system air is used causing more cleanliness in the system.

The pneumatic systems are cleaner than hydraulic systems.

Hence, a statement D about pneumatic systems is true.

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The bearing of grids of an AB alignment is 100º 22', while the magnetic declination is 8º30' E. What are the true azimuth, magnetic azimuth, and grid azimuth of this alignment?

Answers

The true azimuth of the AB alignment is 91º 52' (east of north), the magnetic azimuth is 100º 22' (east of north), and the grid azimuth is 108º 52' (east of north).

To find the true azimuth, magnetic azimuth, and grid azimuth of the AB alignment, we need to consider the magnetic declination. The magnetic declination indicates the angle between true north and magnetic north at a specific location. In this case, the magnetic declination is 8º 30' E, which means that the magnetic north is 8º 30' east of the true north.

To calculate the true azimuth, we subtract the magnetic declination from the grid azimuth. The grid azimuth is given as 100º 22', so subtracting the magnetic declination of 8º 30' E gives us a true azimuth of 91º 52' (east of north).

The magnetic azimuth remains the same as the grid azimuth, which is 100º 22' (east of north).

The grid azimuth is calculated by adding the magnetic declination to the true azimuth. Since the magnetic declination is east, we add it to the true azimuth. Adding 8º 30' E to the true azimuth of 91º 52' gives us a grid azimuth of 108º 52' (east of north).

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If the rock was going 90m/s when it hit the ground. How many seconds would it have been falling for?

Answers

Answer:

it will hit 80

Explanation:

because evey sec

is 10

How are mass and acceleration related (if you change one of them, what happens to the other one)?​

Answers

acceleration is inversely proportional to the mass. If mass increases acceleration decreases.

Question: In an average year, the Creek drainage basin (150 mi^2) receives 550 mm of precipitation. Has an average stream discharge of 1.8 m^3s^-1. (1 mile = 1.609 km).
Please develop the water budget equation for this problem.

Answers

The water budget equation for the Creek drainage basin is: Precipitation = Stream discharge + Evapotranspiration ± Change in storage.

To develop the water budget equation for this problem, we need to account for the inputs and outputs of water in the Creek drainage basin. The water budget equation can be expressed as,

P = Q + ET ± ΔS

P = Precipitation input (mm)

Q = Stream discharge (m³/s)

ET = Evapotranspiration (mm)

ΔS = Change in storage (mm)

First, let's convert the units of the given values,

Precipitation input (P) = 550 mm

Stream discharge (Q) = 1.8 m³/s

Now, let's determine the evapotranspiration (ET) and change in storage (ΔS) terms. However, the problem doesn't provide information about ET, so we cannot calculate it accurately. The problem doesn't provide information about ΔS, so we cannot calculate it accurately.

Given these limitations, we can write the simplified water budget equation for this problem,

550 mm = 1.8 m³/s + ET ± ΔS

Please note that without information about evapotranspiration and changes in storage, we cannot fully determine the water budget for the Creek drainage basin.

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Select the compensator zero to cancel one pole of GHP(z) {other than z=1}. α = Determine 3 based on the angle condition: zeros - 4poles = 180° You need to draw a figure as the Figure below to calculate ß = Im z-plane z = a + ib Zero of GHP(Z) Zzero Zpole(B) 0 B Figure: Determine ß Zpole(1) pole 1 of GHP(z) Re
The angle condition is: Zzero- (pole(1) + 4pole(B))= 180º Zzero = Zpole(1) = Zpole(B) = Determine the compensator gain k based on magnitude condition: z-α Gc (2) GHP (2)|2=a+ jb = 1 → k Ghp(2) = 1 z-ß |z=a+jb 1 k z-α GHP(z) |z-ß |z=a+jb Write down the final compensator (PID Controller) transfer function Gc(z)=kz-a z-ß

Answers

Analyze system dynamics and design compensator to achieve desired response by selecting compensator zero and canceling one pole of GHP(z).

How to select the compensator zero cancel one pole of GHP(z)?

To select a compensator zero to cancel one pole of GHP(z), we need to use the given angle condition:

Zzero - (pole(1) + Zpole(B)) = 180°

Here, Zzero represents the compensator zero, pole(1) represents the first pole of GHP(z), and Zpole(B) represents the compensator pole.

Let's proceed with the solution step by step:

1. First, we need to determine the value of Zzero. The angle condition states that Zzero = Zpole(1), which means the compensator zero is equal to the first pole of GHP(z).

2. Now, we need to find the value of Zpole(B). We can rewrite the angle condition as follows:

Zpole(B) = Zzero - pole(1) + 180°

Since we already know that Zzero = Zpole(1), we can substitute Zzero in the above equation:

Zpole(B) = Zpole(1) - pole(1) + 180°

Simplifying further:

Zpole(B) = 180°

Therefore, the value of Zpole(B) is 180°.

To summarize, we can select the compensator zero (Zzero) to cancel one pole of GHP(z) as Zpole(1), and the compensator pole (Zpole(B)) is determined to be 180° based on the given angle condition.

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8. What is the total mechanical energy of a penny dropped off of the top of the Empire
State Building if it has a potential energy of 47 J, and a kinetic energy of 23 J?
A.18J
B.24 J
C.70 J
D.667 J

Answers

Answer:

C 70 Joules because all of the energy of converted to potential energy.

A 20-gram bullet traveling at 250 m/s strikes a block of wood that weighs 2 kg. With what velocity will the block and bullet move after the collision? [convert g to kg]

Answers

Answer:

the velocity of the bullet-wood system after the collision is 2.48 m/s

Explanation:

Given;

mass of the bullet, m₀ = 20 g = 0.02 kg

velocity of the bullet, v₀ = 250 m/s

mass of the wood, m₁ = 2 kg

velocity of the wood, v₁ = 0

Let the velocity of the bullet-wood system after collision = v

Apply the principle of conservation of linear momentum to calculate the final velocity of the system;

Initial momentum = final momentum

m₀v₀ + m₁v₁ = v(m₀ + m₁)

0.02 x 250  + 2 x 0    =    v(2  + 0.02)

5 + 0 = v(2.02)

5 = 2.02v

v = 5/2.02

v = 2.48 m/s

Therefore, the velocity of the bullet-wood system after the collision is 2.48 m/s

Which of the following was NOT created as a result of big bang nucleosynthesis?
a. Hydrogen
b. Duterium
c. Tritium
d. Helium
e. Carbon

Answers

The element which is not formed during big bang nucleosynthesis is Carbon.

The Big Bang nuclear synthesis process did not result in the creation of this statement. It results in the production of nuclear which is other than the nuclear with lesser mass, according to Big bang nucleosynthesis. The process of nuclear synthesis in the Big Bang results in the formation of the isotopes of hydrogen and helium, as well as traces of lithium. The process will form to some extent because of it. The carbon element is not directly created as a result of this big band nuclear synthesis process, but it may be formed as a result of another process by which these nuclear make combined. It wasn't formed as a result of the Big Bang. The element that is not created as a result of the Big bang nucleosynthesis is carbon.

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when the voltage on each side of the charge indicator lamp is equal (between the lamp and the diode trio), there is no current flow through the lamp and the lamp is turned off
true
false

Answers

When the voltage on each side of the charge indicator lamp is equal (between the lamp and the diode trio), there is no current flow through the lamp and the lamp is turned off. The answer is true.

When the voltage on each side of the charge indicator lamp is equal, this means there is no potential difference across the lamp. As a result, no current flows through the lamp, and the lamp remains turned off. In this case, according to Ohm's Law (V = IR), if the voltage is zero, the current flowing through the lamp would also be zero (I = 0), and the lamp would be turned off. The equal voltage on both sides of the lamp ensures that there is no potential gradient to drive any current through it, resulting in the lamp remaining inactive.

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what are effects of high gravity on blood pressure, blood circulatory system, size of lungs, bone fragility and density​

Answers

Answer:

Explanation:

On return to Earth, gravity once again “pulls” the blood and fluids into the abdomen and legs. The loss of blood volume, combined with atrophy of the heart and blood vessels that can occur in space, reduces the ability to regulate a drop in blood pressure that happens when we stand on Earth.

Which statement below could be used as evidence to support the claim that using nuclear energy to produce electricity is better than using fossil fuels?

A. Radioactive waste can be stored deep underground in order to minimize the risk of exposure to dangerous radiation.

B. Nuclear energy does not produce harmful pollution.

C. Nuclear does not produce greenhouse gases that contribute to global warming.

D. Nuclear energy is cheaper than using fossil fuels.

Answers

Answer:

C

Explanation:

C would make the most sense because the problem with fossil fuels is the fact that it emits greenhouse gases that warm up the earth over a long period of time as the climate has changed because of it.

Briefly explain the big bang theory.

Answers

Astronomers use the big bang theory to describe how the cosmos came into being. It is the hypothesis that the universe started out as a single point, then grew and stretched to reach its current size and is still stretching.

The most widely accepted cosmological model for explaining the beginnings of the observable universe and the consequent large-scale evolution is the big bang theory. The model offers a comprehensive explanation for a vast array of well-known phenomena and explains how the cosmos expanded from a high-density, high-temperature starting point.Modern estimates place this event at a time of about 13.8 billion years ago. After the universe's first expansion (inflation), it calmed down enough for the emergence of subatomic particles and, subsequently, fundamental atoms.Hydrogen and helium, two massive clouds of these fundamental elements, finally combined because to gravity to form stars and galaxies.

The big bang theory contends that the universe has been expanding since its creation in all directions.

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DESPERATE WILL GIBE BRAINLIST AND THANKS
Radiometric dating is a form of relative dating.
Question 4 options:
True
False

Answers

Answer:

True

Radiometric dating is a process of identifying the age of a material based on known half-lives of decaying radioactive materials found in both organic and inorganic objects. Radiometric dating is often used to determine the age of rocks, bones, and ancient materials.

Answer:

false

Explanation:

two scientists work with a radioactive source of constant activity. scientist a stands 1 m away from it and needs two hours to complete his task. scientist b stands only 0.5 m away from the source, but can complete the job in just one hour. how do the doses that the two receive compare?

Answers

The dose received by Scientist B is twice as much as the dose received by Scientist A, despite being closer to the source.

To compare the doses that the two scientists receive, we need to consider the principles of radioactive decay and the relationship between distance and radiation intensity.

The intensity of radiation from a radioactive source follows an inverse square law. According to this law, the intensity of radiation decreases with the square of the distance from the source. Mathematically, it can be expressed as:

I ∝ 1/\(d^{2}\)

Where I is the intensity of radiation and d is the distance from the source.

In this case, Scientist A stands at a distance of 1 m from the source, while Scientist B stands at a distance of 0.5 m.

Let's compare the intensities of radiation received by Scientist A and Scientist B:

Intensity for Scientist A (IA) ∝ 1/\(1^2\) = 1/1 = 1

Intensity for Scientist B (IB) ∝ 1/\(0.5^2\) = 1/0.25 = 4

From the above calculations, we can see that the intensity of radiation received by Scientist B is four times higher than that received by Scientist A.

Now, let's consider the time spent by each scientist on their task. Scientist A takes 2 hours to complete the task, while Scientist B completes the job in 1 hour.

The dose of radiation received by an individual is proportional to the product of the radiation intensity and the exposure time. Mathematically, it can be expressed as:

Dose ∝ Intensity × Time

Comparing the doses received:

Dose for Scientist A ∝ IA × 2 = 1 × 2 = 2

Dose for Scientist B ∝ IB × 1 = 4 × 1 = 4

From the calculations, we can see that Scientist B receives a higher dose (4) compared to Scientist A (2). This is because Scientist B is exposed to a higher intensity of radiation due to being closer to the source and completes the task in a shorter time.

Therefore, the dose received by Scientist B is twice as much as the dose received by Scientist A, despite being closer to the source.

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The stars of the Milky Way are all near a great circle on the Celestial Sphere. This great circle?
A. is the Celestial Equator.
B. is the Ecliptic.
C. passes through the Celestial Poles.
D. is none of the other things listed here.

Answers

It is D. is none of the other things listed here. The stars of the Milky Way are all near a great circle on the Celestial Sphere. This great circle is called the milky circle

The Milky Circle is a great circle on the celestial sphere that is defined by the stars of the Milky Way. It is visible to the n_aked eye and is one of the most recognizable features of the night sky, stretching across the entire sky from horizon to horizon. It is composed of millions of stars, all of which reside in the same galactic plane and are moving in the same direction around the galactic center. The Milky Circle is a beautiful sight to behold, especially during a clear night, when it appears as a wide band of light. It is a reminder of the vastness of the universe and the beauty of the night sky. It is also a great way to orient oneself in the night sky, as its stars form a familiar pattern that can help one find constellations and other objects.

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The half-life of radium-226 is 1590 years. (a) A sample of radium-226 has a mass of 100mg. Find a formula for the mass of the sample that remains after t years. (b) Find the mass after 1000 years correct to the nearest milligram. (c) When will the mass be reduced to 30mg ?

Answers

The formula for the mass remaining after t years for a sample of radium-226 with an initial mass of 100mg is given by \($M(t) = 100 \times 0.5^{t/1590}$\). After 1000 years, the mass is approximately 87mg. The mass will be reduced to 30mg after approximately 2167 years.

(a) The decay of radium-226 follows an exponential decay model, where the amount of radium remaining decreases by half every 1590 years. The formula for the mass remaining after t years can be derived using the half-life concept. Let M(t) represent the mass remaining after t years, then the equation can be written as \($M(t) = 100 \times 0.5^{t/1590}$\). Here, 100 represents the initial mass of the sample, and 0.5 is the decay constant derived from the half-life.

(b) To find the mass after 1000 years, we substitute t = 1000 into the formula: \($M(1000) = 100 \times 0.5^{1000/1590}$\). Evaluating this expression gives us approximately 87mg.

(c) To determine when the mass will be reduced to 30mg, we need to solve the equation \($M(t) = 30$\) for t. Substituting M(t) and rearranging the equation gives us \($100 \times 0.5^{t/1590} = 30$\). Solving this equation, we find t ≈ 2167 years. Therefore, it will take approximately 2167 years for the mass of the radium-226 sample to be reduced to 30mg.

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what is the total displacement, in meters, of the ball going through its entire motion: traveling from the ground to the top and then falling back to the ground?

Answers

The total displacement, in meters, of the ball going through its entire motion: traveling from the ground to the top and then falling back to the ground is 0.

What do you mean by displacement?

 An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a lecturer moves to the right in relation to a whiteboard. Displacement describes this shift in location.

The total displacement of an object is the distance and direction between its initial and final positions. If a ball is thrown upward, travels to the top and then falls back to the ground, its total displacement is zero.

This is because the ball travels upward and then downward, covering the same distance in opposite directions. The upward motion and the downward motion cancel each other out, resulting in a net displacement of zero.

So, the ball will be back to the ground where it was originally thrown.

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Aurora binge drinks. what does this most likely mean for aurora? a she drinks enough alcohol to become intoxicated. b she only drinks at social occasions. c she drinks one or two drinks every night. d she avoids alcohol altogether.

Answers

The most likely mean for aurora. She drinks one or two drinks every night. Option C is correct.

What is Binge-drinking?

Binge-drinking is explained as having five or more drinks in one sitting for males, and four or more drinks in one sitting for women.

The majority of people who binge-drink do not have a serious alcohol problem. Binge-drinking, on the other hand, is a dangerous risk behavior linked to significant injuries and a variety of disorders.

Hence, option C is correct.

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Crates of masses 1 kg , 4 kg , and 6 kg are placed in a line on a frictionless table. They remain in contact as they are pushed by a 60 N force applied to the 1 kg block.

A) What is the magnitude of the force that the 4 kg block deals to the 6 kg block?
B) What is the magnitude of the force dealt by the 4 kg block on the 1 kg block?

Answers

Answer:

Approximately \(33\; {\rm m\cdot s^{-2}}\).

Approximately \(55\; {\rm m\cdot s^{-2}}\).

(Assume that the table is level, and that the \(60\; {\rm N}\) force is horizontal.)

Explanation:

Consider all three blocks as one object of mass \(m = (1 + 4 + 6)\; {\rm kg} = 11\; {\rm kg}\). Among all the forces that are in action, the only unbalanced external force on this \(m = 11\; {\rm kg}\) object will be the \(60\; {\rm N}\) force. Hence, the resultant force of this combined object of mass \(m = 11\; {\rm kg}\) will be \(F_{\text{net}} = 60\; {\rm N}\).

Acceleration \(a\) of this combined object will be:
\(\begin{aligned}a &= \frac{F_{\text{net}}}{m} \\ &= \frac{60\; {\rm N}}{11\; {\rm kg}} \\ &= \frac{60}{11}\; {\rm m\cdot s^{-2}}\end{aligned}\).

Since the three crate blocks are moving together, each will have the same acceleration, \(a = (60/11)\; {\rm m\cdot s^{-2}}\).

Resultant force on each of the crate blocks will be:

\(1\; {\rm kg}\) crate: \(F_{\text{net}} = m\, a = (1\; {\rm kg})\, (60/11\; {\rm m\cdot s^{-2}}) = (60/11)\; {\rm N}\).\(4\; {\rm kg}\) crate: \(F_{\text{net}} = m\, a = (4\; {\rm kg})\, (60/11\; {\rm m\cdot s^{-2}}) = (240/11)\; {\rm N}\).\(6\; {\rm kg}\) crate: \(F_{\text{net}} = m\, a = (6\; {\rm kg})\, (60/11\; {\rm m\cdot s^{-2}}) = (360/11)\; {\rm N}\).

Assume that the \(60\; {\rm N}\) external force on the \(1\; {\rm kg}\) block points to the right.

When the crates are considered individually, external forces on the \(1\; {\rm kg}\) crate will include:

the \(60\; {\rm N}\) external force to the right, anda normal force the \(4\; {\rm kg}\) block exerts on the \(1\; {\rm kg}\) block (to the left.) Assume that this force is of magnitude \(x\; {\rm N}\).(In the vertical direction, the weight of this block and the upward normal force from the table are balanced.)

Since these two forces are in opposite directions, the resultant force on this \(1\; {\rm kg}\) block will be \((60\; {\rm N} - x\; {\rm N})\). However, since the actual resultant force on this block (calculated from acceleration) is \((60 / 11)\; {\rm N}\):

\(\displaystyle 60\; {\rm N} - x\; {\rm N} = \frac{60}{11}\; {\rm N}\).

Therefore, the force that the \(4\; {\rm kg}\) block exerts on the \(1\; {\rm kg}\) block will be

\(\displaystyle 60\; {\rm N} - \frac{60}{11}\; {\rm N} = \frac{600}{11}\; {\rm N} \approx 55\; {\rm N}\).

When considered individually, the only unbalanced external force on the \(m = 6\; {\rm kg}\) block is the normal force from the \(4\; {\rm kg}\) block. Hence, this force will be equal to the resultant force on the \(m = 6\; {\rm kg}\) block, \((360 / 11)\; {\rm N} \approx 33\; {\rm N}\).

What is the frequency of a raido wave with a wavelength of 1.0 mm?

Answers

Answer:

3×10^6

Explanation:

frequency is the speed of light ( c) which is a constant number divided the wavelength

f = 3×10^6 / 1.0

Show that the form of Newton’s second law is invariant under the Galilean transformation. According to Newton’s second law, the net force acting on an object is equal to the product of its mass and acceleration. Newton’s second law of motion is given by following expression:

Answers

Newton’s second law of motion states that the force F acting on an object of mass m produces an acceleration a in the object, and is given by, F = ma. The law s invariant under Galilean transformation.

The Galilean transformation is a set of equations that describe the relationship between two reference frames that are in relative motion with constant velocity. It has no effect on the form of Newton’s second law because it only involves a change of coordinates and time, which do not affect the physical laws.

To see this, consider two reference frames S and S', where S' moves with constant velocity v with respect to S. Let an object of mass m be at rest in S, and let F be the net force acting on it in S. According to Newton’s second law in S, we have:

F = ma

Now, let us apply the Galilean transformation to the equation. The position of the object in S' is given by:

x' = x - vt

where x is the position of the object in S, and t is time. Taking the derivative of x' with respect to t, we get:

v' = dx'/dt

= dx/dt - v

= v - v

= 0

This means that the velocity of the object is the same in both reference frames. Similarly, the acceleration is also the same in both reference frames, since it is the derivative of velocity,

a' = dv'/dt = da/dt = a

Therefore, we can write Newton’s second law in S' as,

F' = ma'

where F' is the net force acting on the object in S'. Substituting a' = a, we get:

F' = ma

which is the same form as in S. Thus, we see that the form of Newton’s second law is invariant under the Galilean transformation.

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Light travels from air, index of refraction of 1.00, and is incident on water, index of refraction of 1.33. How will the light refract when it enters the water?

Answers

Answer:

23.8 What is the speed of light in water (n = 1.33)? ... 23.14 Two light pulses are emitted simultaneously from a source. ... The index of refraction for ice is 1.305 ... reflection so all of it is reflected with an angle of reflection of 53° and none of it is refracted into the air. ... For a diamond in air (n2 = 1.00), then, the critical angle is.

Explanation:welcome

A batted ball is fair if it hits third base. *
True
O O
False

Answers

Answer:

True

Explanation:

true, batted balls that first contact the field between home plate and first or third base are considered fair if they subsequently bounce over or directly contact either base, or otherwise pass either base while in fair territory. that's what the mlb glossary says, at least.

the amplitude of a system moving with simple harmonic motion is doubled. the total energy will then begroup of answer choicesthe same as it wasnone of the other answers is correct3 times as large2 times as largehalf as much4 times as large

Answers

The amplitude of a system undergoing simple harmonic motion is doubled, the total energy of the system will be four times as large.

In simple harmonic motion, the total energy of the system is the sum of the kinetic energy and potential energy. The equation for the total energy (E) in terms of the amplitude (A) is:

E = (1/2) k A^2

where k is the spring constant.

When the amplitude is doubled, the new amplitude becomes 2A. Plugging this into the equation, we have:

E' = (1/2) k (2A)^2

Simplifying:

E' = (1/2) k 4A^2

E' = 2kA^2

Comparing this to the original total energy (E), we can see that the new total energy (E') is four times larger than the original total energy (E). Therefore, the correct answer is that the total energy will be four times as large.

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For writing a scientific lab report, when you write the discussion do you need to include every single result in your data? Or do you just include a summary of your data?

Answers

Answer:

include a summary of data

Explanation:

In writing a scientific laboratory report, only the summary of the data is included in the discussion and not the entire result.

The discussion section of a lab report deals with the interpretation and explanation of findings during the course of the experiment in relation to the background information leading to the experiment/research. Hence, only the summary of the data generated is required. The detailed results are usually reported in the result section, not the discussion section.

When an electron is removed from a neutral atom, it becomes....
A) A positive ion
B) a negative ion
C) heavier
D) a bipolar atom

Answers

Answer:

A

Explanation:

PLZZZZ HELP ASAP ASAP ASAP​

PLZZZZ HELP ASAP ASAP ASAP

Answers

Answer:

A - B = 20 m/s

C - D = 10 m/s

section AB is moving fastest so A for the last question

if correct please give brainliest

Explanation:

speed = distance / time

AB - 200 / 10 = 20 m/s

CD - 300 / 30 = 10 m/s

Examine the Pythagorean theorem below. In this form you can find the length of the hypotenuse c) of a right triangle if you know the lengths of the two short sides (a &). Solve this equation for the short side b. If you need to indicate a square root in your answer, type it like this: root * (e + f) to mean the square root of the sum (e + f) . For example, the equation below can be typed as c = root (a^ ^ 2+b^ ^ 2)

Examine the Pythagorean theorem below. In this form you can find the length of the hypotenuse c) of a

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Answer:

what is the number

Explanation:

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