calculate the molarity of hcl when the mass percent is 6.640 % . the density of the solution is 1.012 g/ml.

Answer:

Endothermic animals are those that must generate their own heat to maintain an optimal body temperature.

Explanation:

Answer:

There

Explanation:

Endothermic animals are those that must generate their own heat to maintain an optimal body temperature. In ordinary language, these animals are commonly referred to as "warm-blooded." The term endotherm comes from the Greek endon, meaning within, and thermos, which means heat

The percent ionization of a 0.15 M formic acid solution in a solution containing 0.11 M potassium formate is 4.88%.

Formic acid (HCOOH) is a weak acid that ionizes in water to form hydrogen ions (\(H^+\)) and formate ions (\(HCOO^-\)). The equilibrium expression for the ionization of formic acid is:

\(HCOOH + H_2O = H_3O^+ + HCOO^-\)

The equilibrium constant for this reaction is the acid dissociation constant (Ka) for formic acid, which is \(1.77 * 10^{-4}\) at 25°C.

When a solution of formic acid is mixed with potassium formate (HCOOK), the formate ions from the salt will react with the hydrogen ions from the acid to form more formic acid molecules. This is known as the common ion effect and results in a decrease in the percent ionization of the weak acid.

To calculate the percent ionization of the formic acid in a solution containing potassium formate, we first need to calculate the initial concentration of formic acid (HCOOH) and formate ions (\(HCOO^-\)) in the solution.

The initial concentration of formic acid can be calculated as follows:

[HCOOH] = 0.15 M

The initial concentration of formate ions can be calculated from the concentration of potassium formate and the stoichiometry of the reaction:

[\(HCOO^-\)] = [HCOOK] = 0.11 M

Next, we can use the equilibrium constant expression to calculate the concentration of hydrogen ions at equilibrium:

\(Ka = [H_3O^+][HCOO^-]/[HCOOH]\)

Solving for [\(H_3O^+\)], we get:

\([H_3O^+] = \sqrt{Ka*[HCOOH]/[HCOO-]}\)

Substituting the values, we get:

\([H_3O^+] = \sqrt{1.77 x 10^{-4} x 0.15/0.11} = 0.00732 M\)

The percent ionization of the formic acid can now be calculated as:

% ionization = [\(H_3O^+\)]/[HCOOH] x 100%

% ionization = 0.00732/0.15 x 100% = 4.88%

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Answer:

Physical conditions like temperature and pressure affect state of matter. ... When thermal energy is added to a substance, its temperature increases, which can change its state from solid to liquid (melting), liquid to gas (vaporization), or solid to gas (sublimation)

Answer:

Temperature is a measure of the kinetic energy of particles in a substance. As temperature increases, the atoms or molecules in a substance gain energy. As temperature decreases, the particles lose energy. A change in the energy of particles causes a change in their arrangement. A change in the arrangement of particles can lead to a physical change.

Explanation:

on edge 2021

The half-life of palladium-100 is 4 days. after 16 days a sample of palladium-100 has been reduced to a mass of 7 mg.

The initial mass ( in mg) of the sample is 112 mg. The mass of the sample 8 weeks after the start is approximately 0.0068 mg.

The half-life of palladium-100 is 4 days, which means that every 4 days the amount of palladium-100 in a sample is reduced by half.

Let's use N(t) to represent the mass of the sample at time t, and N0 to represent the initial mass of the sample.

Since the half-life of palladium-100 is 4 days, we know that:

N(t) = N0 * (1/2)^(t/4)

We are given that after 16 days, the mass of the sample is 7 mg. So we can plug in these values and solve for N0:

7 = N0 * (1/2)^(16/4)

7 = N0 * (1/2)^4

7 = N0 * 1/16

N0 = 7 * 16

N0 = 112 mg

So the initial mass of the sample was 112 mg.

Now we can use the same formula to find the mass of the sample after 8 weeks (which is 56 days):

N(56) = 112 * (1/2)^(56/4)

N(56) = 112 * (1/2)^14

N(56) = 112 * 1/16384

N(56) = 0.00683594 mg.

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The most reactive dienophile in a Diels-Alder reaction with 1,3-butadiene is CH2=CHCHO (acrolein)

The Diels-Alder reaction is a chemical reaction that combines a conjugated diene and a dienophile to form a cyclic compound.

The reactivity of a dienophile is determined by its ability to accept electron density and undergo the necessary bond-forming process.

Among the given options, CH2=CHCHO (acrolein) is the most reactive dienophile in a Diels-Alder reaction with 1,3-butadiene. This is because acrolein contains an electron-withdrawing carbonyl group (C=O) attached to an alkene (CH2=CH).

The electron-withdrawing nature of the carbonyl group increases the electrophilic character of the alkene, making it more susceptible to nucleophilic attack by the electron-rich diene, 1,3-butadiene.

The other compounds in the options (CH3CH≡CHCH3, CH2=CHOCH3, CH2=CH2, and (CH3)2C=CH2) lack the electron-withdrawing carbonyl group, reducing their reactivity as dienophiles in a Diels-Alder reaction with 1,3-butadiene.

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Answer:

\(31.8\ moles = 1.91 * 10^{25}\ molecules\)

Explanation:

Given

31.8 moles of water

Required

Determine the number of molecule

In standard units: 1 molecule of water is:

\(1\ mole = 6.022 * 10^{23}\ molecules\)

Multiply both sides by 31.8

\(31.8 * 1\ mole = 31.8 * 6.022 * 10^{23}\ molecules\)

\(31.8\ moles = 31.8 * 6.022 * 10^{23}\ molecules\)

\(31.8\ moles = 191.4996 * 10^{23}\ molecules\)

Express 191.4996 as a standard form

\(31.8\ moles = 1.914996 * 10^2 * 10^{23}\ molecules\)

Apply law of indices:

\(31.8\ moles = 1.914996 * 10^{2+23}\ molecules\)

\(31.8\ moles = 1.914996 * 10^{25}\ molecules\)

Approximate:

\(31.8\ moles = 1.91 * 10^{25}\ molecules\)

Answer:

Titanium; lowest density  

Explanation:

The cart would use the same volume of metal, no matter which one it was made of.

If weight were the only consideration, the company would choose the metal with the lowest density.

The values I find for the metals are

Ti   4.5 g/cm³

Fe  7.9 g/cm³

Zn  7.1  g/cm³

Titanium would be the best metal for this application.

Answer:

Titanium would be the best metal for this application because it is a low density metal that is still strong  and ductile

Explanation:

Answer:

7.1 g

Explanation:

A way to figure this out is by using the molecular formula.

\(Na + Cl\) ⇒ \(NaCl\)

(Sodium + Chloride ⇒ Sodium Chloride)

From this formula it's one mol sodium + one mol chloride = one mol of sodium chloride.

Then you can substitute the values:

4.6 grams sodium + x grams chlorine = 11.7 g of sodium chloride

By using algebra you get:

x = 11.7 - 4.6 = 7.1 g

You can check this by using the molar masses of sodium and chlorine which can take a more time and is kind of unnecessary.

Hope that helps!

According to the concept of diffusion the water will move from 5% salt solution to 15%salt solution.

Diffusion is defined as the process of movement of molecules which takes place under concentration gradient. It helps in movement of substances in and out from the cell.The molecules move from lower concentration region to a higher concentration region till the concentration becomes equal.

There are 2 main types of diffusion:

1) simple diffusion-process in which substances move through a semi-permeable membrane without the aid of transport proteins.

2) facilitated diffusion- It is a passive movement of molecules across cell membrane from higher concentration region to lower concentration.

There are 2 types of facilitated diffusion one is osmosis and dialysis.

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Answer:

A

Explanation:

l took the test

The first thing we need to do is calculate the molar mass of PbS. They give us the atomic weights of lead (P) and sulfur (S), the molecular weight will be equal to the sum of the atomic weights multiplied by the atoms of each element, as follows:

Now, to calculate the number of moles we use its molecular mass and apply the following equation:

In 458g of PbS there are 1.9 mol PbS

Answer: To determine the elements on other planets. The Mercury Surface, Space Environment, Geochemistry, and Ranging (MESSENGER) Gamma-Ray Spectrometer (GRS) can measure gamma rays emitted by the nuclei of atoms on planet Mercury's surface that are struck by cosmic rays.

Explanation:

Answer:

false

Explanation:

when the particles get in the water they just simply vibrate

Answer: jar for 1 team!!!!

Explanation:

Answer: Pollution is removed from the atmosphere (or "sequestered") when it is absorbed by plants as part of the biological carbon cycle.

Hopes This helped:)

Answer:

1. guidance counselor

2.mental health worker

3.social worker

4.human resources worker

5. substance abuse counselor

Answer:

1. Therapist

2. Psychology program director

3. Behavior analyst

4. Researcher

5. Psychology professor

The polarity of a molecule is determined by the presence of polar bonds and the molecular geometry. If a molecule has polar bonds and the geometry allows for an uneven distribution of electron density, the molecule is polar. The molecules \(SBr_{2} and NF_{3}\) can be classified as polar.

The polarity of a molecule is determined by the presence of polar bonds and the molecular geometry. If a molecule has polar bonds and the geometry allows for an uneven distribution of electron density, the molecule is polar. On the other hand, if the molecule has only nonpolar bonds or the geometry results in an even distribution of electron density, the molecule is nonpolar.

Let's analyze the given molecules:

\(SBr_{2}\): Sulfur dibromide (\(SBr_{2}\)) has a central sulfur atom (S) bonded to two bromine atoms (Br). The S-Br bond is polar because bromine is more electronegative than sulfur. However, the geometry of \(SBr_{2}\) is linear, resulting in an even distribution of electron density. Therefore,\(SBr_{2}\) is a polar molecule.

\(NF_{3}\): Nitrogen trifluoride (\(NF_{3}\)) has a central nitrogen atom (N) bonded to three fluorine atoms (F). The N-F bond is polar because fluorine is more electronegative than nitrogen. Additionally, the geometry of \(NF_{3}\) is trigonal pyramidal, with one lone pair of electrons on nitrogen. This results in an uneven distribution of electron density and gives \(NF_{3}\) a polar character.

Therefore ,\(SBr_{2}\) and  \(NF_{3}\) are both polar molecules due to the presence of polar bonds and their respective molecular geometries.

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The molarity of the solution if 1.600 moles of a solute are dissolved in enough water to make 400.0 ml is 4M

Before we calculate the molarity we should know that molarity is a unit of concentration measuring the number of moles of a solute per liter of solution.

The molarity can be calculated as follows:

as we know, 400 mL = 0.4L

Molarity = moles/volume

molarity = 1.600 moles/ 0.4L

Molarity = 4M

so,The molarity of the solution if 1.600 moles of a solute are dissolved in enough water to make 400.0 ml is 4M

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The major product of the reaction between 2-methyl-2-pentene and HBr is 2-bromo-2-methylpentane. When we have an unsymmetrical alkene, hydrogen it reacts with HBr to give two possible products depending on the regioselectivity of the reaction.

There are two possible pathways for the reaction to occur: Markovnikov addition, in which the hydrogen attaches to the carbon that has the highest number of hydrogen atoms and the halogen attaches to the carbon that has the lowest number of hydrogen atoms. Non-Markovnikov addition, in which the halogen attaches to the carbon that has the highest number of hydrogen atoms and the hydrogen attaches to the carbon that has the lowest number of hydrogen atoms.2-Methyl-2-pentene is an example of an unsymmetrical alkene, and it can react with HBr via both Markovnikov and non-Markovnikov pathways. The Markovnikov addition product, 2-bromo-3-methylpentane, can be formed as a minor product. However, the major product is 2-bromo-2-methylpentane, which is the non-Markovnikov addition product. The reason for this is that the reaction occurs through a radical mechanism. In the first step, the H-Br bond is cleaved heterolytically to produce a hydrogen atom and a bromide ion. In the second step, the hydrogen atom adds to the carbon that has the lowest number of hydrogen atoms to form a primary radical, and the bromide ion adds to the carbon that has the highest number of hydrogen atoms to form a tertiary radical. Finally, the two radicals combine to form the product.

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When you walk across the water, heat is transferred from your feet to the water by conduction causing your feet to cool down.

We know that energy can be transferred in three ways;

1) Conduction

2) Convection

3) Radiation

The energy from the sun gets to the earth by the process of radiation and this energy causes the temperature of the sand to increase. When you walk across the water, heat is transferred from your feet to the water by conduction causing your feet to cool down.

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Answer:

7.06

Explanation:

because its improper

The empirical formula of the compound is C2N3H2.

What is an Empirical formula?

An empirical formula is a type of chemical formula that shows the simplest ratio of atoms in a molecule, rather than the total number of atoms. It is the simplest possible chemical formula that shows the relative numbers of each type of atom in a molecule.

This formula is determined by dividing the mass of each element by its atomic weight, and then dividing the result by the lowest of the results. The lowest result is 0.817 g/mol for carbon. This means that 2.61 g of carbon is equivalent to 3.17 moles of carbon. Thus, the ratio of elements in the compound is 3.17 moles of carbon, 7.44 moles of nitrogen, and 1.6 moles of hydrogen. Dividing each of these numbers by the lowest number (3.17) gives the ratio of 2 for carbon, 2.35 for nitrogen, and 0.5 for hydrogen. This ratio is simplified to 2:2:1, which corresponds to the empirical formula C2N3H2.

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Answer:

Base

Explanation:

Bases on dissolving with water release hydroxide ions

Take a example of Sodium hydroxide

In the amino acid (AA) sequence of collagen, every third position must be occupied by glycine. Collagen is a structural protein, and its unique structure is due to the regular occurrence of glycine at the third position of its amino acid sequence.

Glycine (Gly) must occupy every third place in the AA (amino acid) sequence of collagen. This is due to the fact that glycine is the smallest amino acid and enables the close packing of collagen molecules, which is required for the development of collagen's distinctive triple helix structure.

The other two sites can be filled by any of the remaining 18 amino acids, although proline and hydroxyproline are frequently found there because they help the triple helix structure become more stable by forming hydrogen bonds.

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Answer:

Answer:

a

Explanation:

The heat capacity of a substance is the heat energy required to rise its temperature per one degree Celsius. Hence its unit is J/°C.

Heat capacity is the amount of heat energy required to raise the temperature of a substance by 1 degree Celsius or 1 Kelvin. It is expressed in the following units:

Joules per degree Celsius (J/°C)

Joules per Kelvin (J/K)

Calories per degree Celsius (cal/°C)

Calories per Kelvin (cal/K)

Joules per gram per degree Celsius (J/(g·°C))

Joules per gram per Kelvin (J/(g·K)) etc.

If in terms of simply the energy, then, The following units are used.

Joules (J) , Calories (cal) , Degrees Celsius (°C), Kelvin (K)

The choice of unit depends on the specific application and the system of units being used. The SI unit for heat capacity is J/K, while the traditional unit is cal/°C.

The use of per gram units is common in the context of specific heat capacity, which is the amount of heat energy required to raise the temperature of a unit mass of a substance by 1 degree Celsius or 1 Kelvin.

Therefore, here, the unit of heat capacity is J/°C.

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Answer:

positive

Explanation:

protons have a positive charge

Answer:

Positive

Explanation:

Answer:

Control group:

Test section covered with the "Steel Seal" floor wax

Explanation:

In a scientific experiment, the control group is the standard group to which comparison is made, to determine the effect of the experimental agent on the test subjects. In this example, the Steal Seal floor wax is the standard wax being used, and the experimenter wants to see if the "Tough Stuff" wax is better, hence after the treatment with the Tough Stuff wax, the number of scratches observed is compared with the standard wax area and the difference determines if it is a better waxing agent or not.