Calculate the molar volume of ethane at P bar and T oC using the Virial Equation of state truncated to 3 terms. The experimental values for B and C can be taken as −156.7 cm3 /mol and 9650 cm6 /mol2 . Use P=18 and T=52. [10 Marks]
b) Redo part (a) using the Redlick Kwong Equation of state. [20 Marks]
c) Comment on the difference in the molar volume you obtained in part (a) and part (b) and give your opinion on the most accurate answer between the two. [5 Marks

Answer:

See explanation.

Explanation:

Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.

If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,

P=2×pi×N×T/60 or T=60×p/2×pi×N

Where P=power transmitted by the shaft=50×10³W

N=rotation speed of the shaft in rpm=730rpm

Pi=3.142

T is the twisting moment

By substituting the values for pi, N and P, we get

T=654Nm or 654×10³Nmm

Also, T=pi×rho×d³/16 or rho=16×T/pi×d³

Where rho=maximum shear stress

T = twisting moment=654×10³Nmm

d= diameter of shaft= 40mm

By substituting T, pi and d

Rho=52Mpa

b. For a hollow shaft, the value for rho is unknown

T=pi×rho(do⁴-di⁴/do)/16

Rho=T×16×do/pi×(do⁴-di⁴)

Where

T= twisting moment=654×10³Nmm gotten above

do=outside shaft diawter=40mm

di= inside shaft diameter =30mm

Pi=3.142

Substituting values for pi, do, di and T.

Rho=76Mpa

Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

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The electron transport chain is an essential process in cellular respiration and is vital to the survival of most living organisms

The electron transport chain (ETC) is a series of protein complexes and molecules that carry electrons to create a gradient of hydrogen ions (protons) that power ATP synthase. It is a series of protein complexes and molecules within the mitochondria that are involved in the generation of ATP molecules.The main purpose of the electron transport chain is to create a hydrogen ion gradient across the inner mitochondrial membrane.

This gradient can then be used to produce ATP, which is the cell's main energy source. The electron transport chain works by transferring electrons from electron donors to electron acceptors via a series of redox reactions. As the electrons move through the ETC, they release energy that is used to pump protons from the mitochondrial matrix into the intermembrane space. This creates a concentration gradient of protons across the inner mitochondrial membrane.

The gradient then drives the ATP synthase enzyme, which uses the energy to produce ATP.The electron transport chain is an essential process in cellular respiration and is vital to the survival of most living organisms. Without the ETC, cells would not be able to produce enough ATP to carry out essential functions, leading to cell death and ultimately organism death.

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Answer: Ohm Ω

Explanation:

The resistance can be defined as the hindrance offered to the flow of current. Lower the current the higher is the resistance. The SI unit of resistance is ohm Ω. When one ampere current flows from an object or wire the application of one volt of potential difference on it the resistance so produce is one ohm. Resistance can be achieved by the application of the certain gadgets in the circuit which can prevent the flow of excess current from devices and can prevent shock circuit.

Answer:

871.8008 KJ/kg

2573.42085 KJ/kg

0.3743

Explanation:

Solution:-

- We are to analyze an ideal Rankine cycle, where the condenser and boiler operating temperatures are defined.

- We start of by evaluating the properties of water at each state before and after the process.

State 1: Condenser Exit / Pump Inlet

           T1 = 40°C   ---> P1,sat = 7.3851 KPa , v1 = vf = 0.001008 m^3/kg

            sat liquid         h1 = hf = 167.53 KJ/kg , s1 = sf = 0.5724 KJ/kg.K

            P1 = condenser pressure

State 2: Pump Exit / Boiler Inlet

           P2 = P3 = Psat,300°C = 8587.9 KPa

Process 1: " Isentropic Compression - constant volume "

The work done by pump in the compression process is:

          wp = v1* ( P2 - P1 )

          wp = ( 0.001008 ) * ( 8587.9 - 7.3851 )

          wp = 8.64915 KJ /kg

Determine the enthalpy at " State 2 " by energy balance on pump ( control  Volume) :

          h2 = h1 + wp

          h2 = 167.53 + 8.64915

          h2 = 176.17915 KJ/kg

State 3: Boiler Exit / Turbine Inlet

          T1 = 300°C   ---> P3,sat = 8587.9 KPa

           sat vapor         h3 = hg =  2749.6 KJ/kg , s3 = sg =  5.7059 KJ/kg.K

           P3 = Boiler pressure

Process 2: " Heat Addition - constant pressure "

The heat supplied in the boiler is:

          qb = h3 - h2

          qp = ( 2749.6 - 176.17915 )

          qb = 2573.42085 KJ /kg    .... Answer ( b )

State 4: Turbine Exit / Condenser Inlet ( Isentropic )

          P4 = P1 = 7.3851 KPa         ..... sfg = 7.685 KJ/kg.K

          s4 = s3 = 5.7059 KJ/kg.K       sf = 0.5716994 KJ/kg.K

                                                           hf = 170.32524 KJ/kg

                                                          hfg = 2406.11 KJ/kg

Process 3: Isentropic Expansion - Determine the quality of liquid-vapor mixture phase ( x ) at state (4):

          x = (s4 - sf) / sfg

          x = (5.7059 - 0.5716994) / 7.685

          x = 0.66808

          h4 = hf + x*hfg

          h4 = 170.32524 + 0.66808*2406.11

          h4 = 1777.79920 KJ/kg

- The work-done by the turbine in the isentropic expansion process ( wt ) is:

          wt = h3 - h4

          wt = 2749.6 - 1777.7992

          wt = 971.8008 KJ/kg   ... Answer ( a )

- To determine the thermal efficiency ( nth ) of the rankine cycle. We need to determined the net work produced by the cycle ( wn ). The net work is the energy balance between the isentropic compression ( work done - pump ) and isentropic expansion ( work produced - turbine ):

          wn = wt - wp

          wn = 971.8008 - 8.64915

          wn = 963.15165 KJ/kg

- The thermal efficiency of a power cycle is the ratio of net work-produced ( wn ) and the heat supplied to the working fluid in the boiler ( qb ) as follows:

         nth = wn / qb

         nth = 963.15165 / 2573.42085

         nth = 0.3743    ..... Answer ( c )

Answer:

a.) Time = 17.13 seconds

b.) 31.88 m

c.) V = 11.18 m/s

d.) V = 7.1 m/s

Explanation:

The initial velocity U of the automobile is 15.65 m/s.

 At the instant that the two vehicles are abreast of each other, the police car starts to pursue the automobile with initial velocity U = 0 at a constant acceleration of 1.96 m/s². Because the police is starting from rest.

For the automobile, let us use first equation of motion

V = U - at.

Acceleration a is negative since it is decelerating with a = 3.05 m/s² . And

V = 0.

Substitute U and a into the formula

0 = 15.65 - 3.05t

15.65 = 3.05t

t = 15.65/3.05

t = 5.13 seconds

But the motorist noticed the police car in his rear view mirror 12 s after the police car started the pursuit and applied his brakes and decelerates at 3.05 m/s².

The total time required for the police car to overtake the automobile will be

12 + 5.13 = 17.13 seconds.

b.) Using the third equation of motion formula for the police car at V = 11.18 m/s and a = 1.96 m/s²

V^2 = U^2 + 2aS

Where S = distance travelled.

Substitute V and a into the formula

11.18^2 = 0 + 2 × 1.96 ×S

124.99 = 3.92S

S = 124.99/3.92

S = 31.88 m

c.) The speed of the police car at the time it overtakes the automobile will be in line with the speed zone which is 11.18 m/s

d.) That will be the final velocity V of the automobile car.

We will use third equation of motion to solve that.

V^2 = U^2 + 2as

V^2 = 15.65^2 - 2 × 3.05 × 31.88

V^2 = 244.9225 - 194.468

V = sqrt( 50.4545)

V = 7.1 m/s

Answer:

False

Explanation:

Resistance occurs when the flow of charge through a wire is hindered. Resistance of flow of charge increases where the cable length increases .In a longer cable the charge carriers and the atoms in the cable collide more resulting to higher resistance.

The correct answer choice is: False.

The first answer is incorrect because resistance to flow of charge in a cable has a direct relation with length of cable in that increase in length of conducting cable will result to increase in resistance to flow of charges through the cable, not decrease in resistance.

Question:

All of the following are advantages of using a pressure transducer rather than a vacuum gauge EXCEPT:

A. greater accuracy.  

B. easier identification of the cylinder.

C. measuring higher pressures.

D. ability to see the levels graphically

Answer:

The correct answer is D) ability to see the levels graphically

Explanation:

The above question derives from the Rudiments of Automotive Technology.

The function of the pressure transducer is to enable the diagnostic who is testing the engine vacuum to detect the cylinder with a faulty vacuum.

The pressure transducer does allow its user to see the vacuum graphically NOT  the levels.

Cheers.

True, it should come from behind the electrode and

between the base metal and the electrode.

True is the correct answer.

The airstream should penetrate or come between the base metal and the electrode from the back during the CAC-A operation.

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Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

Answer:

20% of the critical value. Determine (a) the damping factor, (b) the

Explanation:

echo "The arguments were: $*" #List of positional parametersThe output are This script was called as ./all.sh, This script was called with 5 arguments .

Parameters are variables that can be used to control the behavior of a system or process. They are used to customize and fine-tune the performance of a system or process, and can be adjusted to suit the needs of a particular application or situation. Parameters can be adjusted manually, or automatically based on feedback from the system or process. Examples of parameters include settings such as speed, temperature, pressure, frequency, voltage, and current.

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The dimensions that are a part of the primary dimension of the English System is Length (ft), Temperature (R) and Mass (lbm). These are also known as English units.

English units, which combined the Anglo-Saxon and Roman systems of measure, were the units of measurement used in England up until 1826 (when they were replaced by Imperial ones). English units have been subject to a variety of standards over time, in various locations, and for various purposes.

The phrase "English units" can be used in an unclear way, it is occasionally used to refer to both the descendant system of United States customary units and the units of the descendant Imperial system.

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This is false. project members should either have strong technical skills or soft skills.

Project members ideally possess a combination of strong technical skills and soft skills. Technical skills are essential for performing the specific tasks and responsibilities related to the project's objectives. These skills can include expertise in areas such as engineering, programming, data analysis, design, or any other technical domain relevant to the project.

On the other hand, soft skills are equally important as they enable effective communication, collaboration, problem-solving, leadership, and adaptability.

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A synchronous modulo-3 counter is a type of digital circuit that can count up to three before resetting back to zero.

It is called "synchronous" because all of its flip-flops change state at the same time, based on a clock signal.

A modulo-3 counter has three states: 0, 1, and 2. It uses two flip-flops, with their outputs connected in a specific way to produce the counting sequence.

The circuit works as follows:

Initially, both flip-flops are reset to 0.

When the clock input goes from 0 to 1, the first flip-flop (Q1) changes state based on its previous state and the value of the second flip-flop (Q0).

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A heat exchanger is considered, that uses hot air to heat cold water. Air enters this heat exchanger at 20psia and 200 °F at a rate of 100cfm and leaves at 17psia and 100 °F. Water enters at 20psia and 50 °F at a rate of 0.5lbm/s and exits at 17psia.

The exit temperature of the water and the fan and pump powers necessary to drive the air and water flows, respectively, is to be determined. It is required to determine the exit temperature of the water and the fan and pump powers necessary to drive the air and water flows, respectively. Considering the air-side first, using the formula for enthalpy change, ∆h = C p * m * ∆T where ∆h is the enthalpy change, C p is the specific heat capacity, m is the mass flow rate, and ∆T is the temperature difference.

In this case: ∆h = C p * m * ∆T∆ h = 0.24 * 100 * (200 − 100) = 2400 BTU/h The air-side pressure drop is given by:∆P = P f − Pi = 20 − 17 = 3 psi. The air-side power required is given by the formula, Power = ∆P * V * f where V is the volumetric flow rate and f is the fluid density. Rearranging this, Power = ∆P * m / f where m is the mass flow rate. Thus, Power = (3 * 100 / 60) * 100 / 14.7 = 15.3 h p Now consider the water-side.

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Sandpaper.

Rubble.

Pyramid.

Wrinkled.

Marbled.

The basic requirement of measurements is to have a standard or reference point against which to compare the quantity being measured. This standard or reference point should be well-defined and stable, and the measurement process should be repeatable and consistent. Additionally, it is important to ensure that the measurement equipment is calibrated and in good working condition.

Answer:

The most basic requirement for measurements is the presence of a standard or reference point against which the quantity being measured can be compared. The measurement process should be repeatable and consistent, and the standard or reference point should be well-defined and stable. Furthermore, ensure that the measurement equipment is calibrated and in good working order.

Explanation:

Answer:

10

Explanation:

Answer:

a) 4.51 lbf-s^2/ft

b) 65.8 kg

c) 645 N

d) 23.8 lb

e) 65.8 kg

Explanation:

Weight of the man on Earth = 145 lb

a) Mass in slug is...

32.174 pound = 1 slug

145 pound = \(x\) slug

\(x\) = 145/32.174 = 4.51 lbf-s^2/ft

b) Mass in kg is...

2.205 pounds = 1 kg

145 pounds = \(x\) kg

\(x\) = 145/2.205 = 65.8 kg

c) Weight in Newton = mg

where

m is mass in kg

g is acceleration due to gravity on Earth = 9.81 m/s^2

Weight in Newton = 65.8 x 9.81 = 645 N

d) If on the moon with acceleration due to gravity of 5.30 ft/s^2,

1 m/s^2 = 3.2808 ft/s^2

\(x\) m/s^2 = 5.30 ft/s^2

\(x\) = 5.30/3.2808 = 1.6155 m/s^2

weight in Newton = mg = 65.8 x 1.6155 = 106

weight in pounds = 106/4.448 = 23.8 lb

e) The mass of the man does not change on the moon. It will therefore have the same value as his mass here on Earth

mass on the moon = 65.8 kg

Recursion is a programming technique where a function calls itself to solve a problem by breaking it down into smaller, similar sub-problems until a base case is reached.

To arrive at this answer, we need to understand that the method sum is recursive, meaning it calls itself within its own code. We also need to understand that we want the method to compute the sum of all numbers from 1 to n, where n is a positive integer.

Option I: is incorrect because it is only adding n to the sum of all numbers from 1 to n-1. This means that it is not taking into account the first number, 1, which should be included in the sum.

Option III: is incorrect because it is calling the sum method twice, with n and n-1 as arguments. This creates an infinite loop and will cause the program to crash.

Option II is correct because it checks if n equals 1, which is the base case for the recursion. If n does equal 1, it simply returns 1. If n is not equal to 1, it adds n to the sum of all numbers from 1 to n-1, which is the recursive call to the sum method with n-1 as the argument. This way, the method will keep calling itself with decreasing values of n until it reaches the base case of n=1, at which point it will start returning values and computing the sum correctly.

For example, if we call sum(5), the method will compute:

sum(5) = 5 + sum(4)
sum(4) = 4 + sum(3)
sum(3) = 3 + sum(2)
sum(2) = 2 + sum(1)
sum(1) = 1

So the final result will be:

sum(5) = 5 + 4 + 3 + 2 + 1 = 15

Therefore, the correct answer is B, II only.
Your answer: B. II only

Explanation:
We are looking for a method that correctly computes the sum of numbers from 1 to n (1 + 2 + 3 + ... + n) for any positive integer n.

I. return n + sum(n-1);
This option doesn't have a base case, which means it will result in an infinite recursion and eventually cause a stack overflow error.

II. if (n==1)
return 1;
else
return n + sum(n-1);
This option has a base case (n == 1) and returns the correct sum by using recursion. When n == 1, the method returns 1. For other values of n, it adds n to the sum of all the numbers from 1 to (n-1). This is the correct implementation of the sum method.

III. if (n==1)
return 1;
else
return sum(n) + sum(n-1);
This option unnecessarily computes sum(n) in addition to sum(n-1), leading to incorrect results. For example, when n == 2, the correct sum should be 3 (1+2), but this method will return 4 (1+1+2).

Thus, the correct answer is B. II only.

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Answer:

C. 14.55

Explanation:

12 x 10 = 120

120 divded by 10 is 12

so now we do the left side

7 x 3 = 21 divded by 10 is 2

so now we have 14

and the remaning area is 0.55

so 14.55

Answer:

Freon Refrigerant

Explanation:

As of January 1, 2020 Freon Refrigerant can no longer be manufactured or imported to the United States. This is because R-22 (the principal component in Freon) has been banned in the states. Along with other greenhouse gasses, due to their contribution to damaging Earth’s ozone layer and global warming.

hope this helps:)

Answer:

Freon Refrigerant Is Now Banned in the US

As of January 1, 2020, a once very popular air conditioning refrigerant can no longer be made in or imported into the United States.

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Answer:They are two types of receptacles used in this (A 16) circuit. i.) Receptacles at 120W: 5 Numbers ii.) Weatherproof receptacles at 120W: 1 Number!

Explanation:

The agile software development methodology is characterized by several key principles and practices that differentiate it from traditional software development approaches. Here are the characteristics commonly associated with agile methodology:

Iterative and Incremental Development: Agile emphasizes the iterative and incremental delivery of software, with frequent feedback and adaptation throughout the development process.Collaboration and Customer Involvement: Agile promotes close collaboration between developers and stakeholders, including customers or end-users, to ensure that the software meets their needs.

Flexibility and Adaptability: Agile embraces change and encourages teams to be flexible and adaptable in responding to evolving requirements and priorities.Self-Organizing Teams: Agile teams are self-organizing and empowered to make decisions, fostering collaboration, accountability, and ownership.

Continuous Delivery and Continuous Improvement: Agile teams strive for continuous delivery of working software and continuous improvement through regular reflection and adaptation.Based on these characteristics, there is no specific characteristic of agile methodology that can be excluded. Therefore, the statement "The agile software development methodology is categorized by all of the following, except" does not have an accurate answer.

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Sealant composites have higher viscosity compared to flowable composites, allowing them to better adhere to pits and fissures on tooth surfaces for effective sealing and protection against tooth decay.

Sealant composites are a type of dental material used for sealing pits and fissures on the chewing surfaces of teeth to prevent tooth decay. They are similar to flowable composites, but they typically have higher viscosity or thickness.

The increased viscosity of sealant composites enables the material to flow into the deep grooves and irregularities of the tooth's chewing surfaces and effectively "stick" to them. This property allows for better penetration and adaptation of the sealant material, ensuring a more thorough seal and better protection against bacteria and food particles that can cause decay.

The viscosity of sealant composites is carefully formulated to strike a balance between flowability and retention on the tooth surface. It should be high enough to facilitate placement and adherence to the pits and fissures but not so low that it becomes excessively runny and fails to effectively seal the tooth.

Overall, the higher viscosity of sealant composites compared to flowable composites helps to optimize their sealing properties and enhance their ability to protect vulnerable areas of the teeth from cavities.

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Explanation:

rational

Step-by-step explanation:

The discriminant (d) of a quadratic equation ax^2 + bx + c = 0ax

2

+bx+c=0 is:

\boxed{\mathrm{d =} \ b^2 - 4ac}

d= b

2

−4ac

.

If:

• d > 0, then there are two real solutions

• d = 0, then there is a repeated real solution

• d < 0, then there is no real solution.

In this question, we are given the quadratic equation 3x^2 + 4x - 2 = 03x

2

+4x−2=0 . Therefore, the discriminant of the equation is:

b² - 4ac = (4)² - 4(3)(-2)

= 16 - (-24)rational

Step-by-step explanation:

The discriminant (d) of a quadratic equation ax^2 + bx + c = 0ax

2

+bx+c=0 is:

\boxed{\mathrm{d =} \ b^2 - 4ac}

d= b

2

−4ac

.

If:

• d > 0, then there are two real solutions

• d = 0, then there is a repeated real solution

• d < 0, then there is no real solution.

In this question, we are given the quadratic equation 3x^2 + 4x - 2 = 03x

2

+4x−2=0 . Therefore, the discriminant of the equation is:

b² - 4ac = (4)² - 4(3)(-2)

= 16 - (-24)

= 40

Since the discriminant, 40, is greater than zero, the quadratic equation has 2 rational solutions.

= 40

Since the discriminant, 40, is greater than zero, the quadratic equation has 2 rational solutions.

Answer:

The time required to reduce the diameter of solid spherical ball from 2 cm to 0.50 cm = 61.60 hours

Explanation:

Given that:

The bulk gas temperature T = 347 K

The pressure = 1.0 atm

Molecular weight of naphthalene = 128 g/mole

density of the solid = 1.145 g/cm³

diffusivity in the air of coefficient = 8.19 × 10 ⁻⁶ m²/s

vapor pressure = 5.0 Torr (666 Pa)

The shape of the ball in this given study is spherical. So, the first step we need to carry out is to state the general differential equation for the mass transfer in the system of the spherical coordinates. After that , we will make use of simplified differential expression form of Fick's Flux. From there we'll determine the surface concentration (c) of the species and finally determine the material balance equation on the naphthalene which will be used in solving the time required to reduce the diameter from 2.0 cm to 0.50cm.      

THE DETAILED EXPLANATION OF WHAT WE JUST SAID CAN BE SEEN IN THE ATTACHED IMAGES BELOW.