Answer:
From 4.9 g of sulfuric acid 8.175 g of potassium sulfate is formed.
Explanation:
Given data:
Mass of H₂SO₄ = 4.9 g
Mass of K₂SO₄ formed = ?
Solution:
Chemical reaction:
H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
Number of moles of H₂SO₄:
Number of moles = mass/ molar mass
Number of moles = 4.9 g/ 98.1 g/mol
Number of moles = 0.05 mol
Now we will compare the moles of H₂SO₄ with K₂SO₄ .
H₂SO₄ : K₂SO₄
1 : 1
0.05 : 0.05
Mass of K₂SO₄:
Mass = number of moles × molar mass
Mass = 0.05 mol × 174.3 g/mol
Mass = 8.715 g
Thus, from 4.9 g of sulfuric acid 8.175 g of potassium sulfate is formed.
Earlier in the lesson, you determined that the enthalphy for magnesium combustion could be computed using Hess’s law. The formula derived from the reaction equations was:
Delta H shown in orange equals delta H 1 in green minus delta H 2 in purple plus delta h 3 in blue.
The enthalpy of the magnesium combustion is
kJ/mol.
Answer:
-655 kj/mol
Explanation:
Answer:
look at pic
Explanation:
.kjkj;lkm'
Consider the following species when answering the following questions:
(i) PCl3 (ii) CCl4 (iii) TeCl4 (iv) XeF4 (v) SF6
For which of the molecules is the molecular geometry (shape) the same as the VSEPR electron domain arrangement (electron domain geometry)?
The molecular geometry (form) of CCl4 SF6 is identical to the configuration of the electron domains in a VSEPR.
Is VSEPR and molecular geometry equivalent?VSEPR distinguishes between molecular geometry, which defines how the atoms in a molecule are ordered, and electron group geometry, which expresses how electron groups (bonds and nonbonding electron pairs) are arranged.
What do electron domains and molecule structure reveal from VSEPR?Chemistry frequently employs the valence-shell electron-pair repulsion (VSEPR) model to foretell the three-dimensional organization, or geometry, of molecules. This model accounts for the repulsion between electron pair to estimate the structure of a molecule.
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The maximum production rate of acetyl-CoA under condition is closest to which of the following?
A. 1 micromoles sec B. 24 micromoles/sec C. 35 micromoles/sec d. 65 micromoles/se
The maximum production rate of acetyl-CoA under condition 1 is closest to 1 micromole/sec.
The correct option is A.
What is the maximum production rate of acetyl-CoA under condition 1?The maximum production rate of acetyl-CoA under condition 1 is determined from the reaction conditions.
For Condition 1:
The maximum concentration of acetyl-CoA is 60 micromoles
The time taken to reach the maximum concentration of acetyl-CoA is 60 seconds.
The maximum production rate of acetyl-CoA under condition 1 can be calculated by dividing the maximum concentration of acetyl-CoA (60 micromoles) by the time taken (60 seconds):
Maximum production rate = 60 micromoles / 60 seconds = 1 micromole/second
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true or false. the arrow labeled C represents a transfer of chemical energy to mechanical energy. explain why this is true or false.
true or false. the arrow labeled A represents a transfer of solar energy to chemical energy. explain why this is true or false.
Answer:
6. True or False. The arrow labeled C represents a transfer of chemical energy to mechanical energy. Explain why this is true or false.
a. This is __False_____ because: Factory uses Mechanical energy with is converted to chemical energy.
7. True or False. The arrow labeled A represents a transfer of solar energy to chemical energy. Explain why this is true or false.
a. This is __True_____ because: Solar energy from the sun is first, then a chemical reaction makes food for the plant.
Explanation:
Change up the spelling, put it in your own words, I didn't use advanced grammar, don't copy and paste, don't get a 0.
please help me figure out how many significant figures are in there
Answer:
A) 4 and 3
Explanation:
You don't count the scientific notations in his problem sine they are only trailing zeros which they don't count as sig figs so look at the original numbers. Remember that zeros after decimal points or in-between natural numbers count with that said 2.020 has 4 sig figs and 5.00 has 3 sig figs
explain why solid sodium chloride does not conduct electricity
Answer:
It does not contain free mobile ions
Explanation:
Solid sodium chloride does not conduct electricity because it does not contain free mobile ions.
Although sodium chloride is an ionic compound, in solid state, there is absence of free mobile ions. In aqueous solutions or in molten form, ionic compounds can conduct an electric current using free mobile ions as carriers. Therefore, they are electrolytes.In solid state ions are arranged into crystal lattice and will not conduct a current of electricity.
5gm of hydrogen diffused through a porus membrane
in 30 minutes. Find the time required to diffuse
the some amount of so2 gas at identhal conditions.
169.71 minutes
Further explanationGiven
Rate of diffused of Hydrogen=5 gm/30 min
Required
The time required for SO₂
Solution
Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or
the effusion rates of two gases = the square root of the inverse of their molar masses:
\(\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }\)
r₁=5gm/30 min
M₁=molar weight of H₂-hydrogen= 2 g/mol
M₂=molar weight of SO₂-sulfur dioxide= 64 g/mol
\(\tt \dfrac{5/30}{r_2}=\sqrt{\dfrac{64}{2} }\\\\\dfrac{5/30}{r_2}=4\sqrt{2}\\\\\dfrac{5}{30}=r_2.4\sqrt{2}\\\\r_2=\dfrac{5}{30\times 4\sqrt{2} }=\dfrac{\sqrt{2} }{48}\)
the time required (for the same amount=5 gm) :
\(\tt \dfrac{5}{x}=\dfrac{\sqrt{2} }{48}\rightarrow x=120\sqrt{2}=169.71 minute\)
A rigid vessel, with a volume of 500 liters, is divided into two regions with equal volumes. The two regions contain hydrogen, one with a temperature of 350ºC and pressure equal to 1 MPa and the other with a pressure and temperature of 4 MPa and 150ºC, respectively. The partition breaks and the hydrogen reaches equilibrium. In this condition, the temperature is equal to 100°C. Assuming that the temperature of the medium is equal to 25°C, determine the irreversibility in the process (kW)
The irreversibility in the process can be calculated as the difference between the actual entropy change and the reversible entropy change at the final equilibrium temperature: Irreversibility = ΔS_actual - R * ln(V_f/V_i) - cp * ln(T_f/T_i)
To determine the irreversibility in the process, we can use the concept of entropy change. The irreversibility in a process can be calculated as the difference between the actual entropy change and the reversible entropy change.
The reversible entropy change can be calculated using the ideal gas equation:
ΔS_rev = R * ln(V_f/V_i) + cp * ln(T_f/T_i)
where:
ΔS_rev is the reversible entropy change
R is the specific gas constant (8.314 J/mol·K)
V_f and V_i are the final and initial volumes, respectively
T_f and T_i are the final and initial temperatures, respectively
cp is the specific heat capacity at constant pressure
Given:
Volume of each region = 500 liters = 0.5 m^3
Initial pressure in region 1 = 1 MPa = 1,000,000 Pa
Initial temperature in region 1 = 350ºC = 623 K
Initial pressure in region 2 = 4 MPa = 4,000,000 Pa
Initial temperature in region 2 = 150ºC = 423 K
Final temperature in equilibrium = 100ºC = 373 K
Temperature of the medium = 25ºC = 298 K
First, let's calculate the reversible entropy change for each region using the given equations:
ΔS_rev_1 = R * ln(V_f/V_i) + cp * ln(T_f/T_i)
ΔS_rev_2 = R * ln(V_f/V_i) + cp * ln(T_f/T_i)
Substituting the given values and using the specific heat capacity of hydrogen (cp = 14.307 J/mol·K), we can calculate ΔS_rev_1 and ΔS_rev_2.
Next, we need to calculate the actual entropy change for the process, which is the sum of the reversible entropy changes of both regions:
ΔS_actual = ΔS_rev_1 + ΔS_rev_2
Finally, the irreversibility in the process can be calculated as the difference between the actual entropy change and the reversible entropy change at the final equilibrium temperature:
Irreversibility = ΔS_actual - R * ln(V_f/V_i) - cp * ln(T_f/T_i)
Substituting the calculated values, we can determine the irreversibility in kW.
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It took 20.0 mL of NaOH to neutralize 25 mL of 0.50 M HCl. What is the molarity of the base?
Answer:
5/8 M
Explanation:
NaOH + HCl ====> NaCl + H2O
in 25 mL of 0.5M acid, we have 1/80 Mol of HCl
it mean we must have 1/80 Mol of NaOH.
20 mL = 1/50 L
(1/80)Mol / (1/50)L = 5/8 M
In an oil spill, is the danger greater to birds and marine
mammals than it is to fish and other organisms that live on
the ocean bottom? Why?
Answer:
Birds and marine mammals are generally considered to be more vulnerable to oil spills because they are more likely to come into direct contact with the oil, either through exposure to the oil on the surface of the water or through ingestion of oil-contaminated prey. Birds may become coated in oil when they land on the water's surface to feed or rest, and marine mammals may be exposed to oil through inhalation or ingestion of contaminated water or prey.
Explanation:
Oil spills can have significant impacts on a variety of marine species, including birds, marine mammals, fish, and organisms that live on the ocean bottom. The specific impact of an oil spill on any given species will depend on a variety of factors, including the type and amount of oil that is released, the location of the spill, and the sensitivity of the species to oil exposure.Fish and other organisms that live on the ocean bottom may also be impacted by oil spills, but they are less likely to come into direct contact with the oil and may be less sensitive to oil exposure. However, the impacts of an oil spill on these species can still be significant, as the oil can disrupt their habitats, contaminate their food sources, and impact their reproductive and survival rates.Overall, the impacts of an oil spill on any given species will depend on a variety of factors and can vary significantly depending on the circumstances of the spill.3
Ethene burns in an excess of oxygen to form carbon dioxide and water.
The equation for the reaction is
C₂H4 & 30₂
2002 + 2H2O.
The relative molecular mass of ethene is 28 and the relative molecular mass of water is 18.
(A: 0, 16; C, 12]
(a) (1) Calculate the relative molecular mass of carbon dioxide.
...[1]
(ii) Complete the following sentences.
28 g of ethene produces ........
..g of carbon dioxide and ..
g of water.
[3]
0.7g of ethene produces ..............g of carbon dioxide.
(b) Complete the diagram to show the bonds in a molecule of ethene.
H
H
C C
H
H
Answer:
(a) (i) 44
(ii) 88 and 36
(iii) 2.2
(b)H₂–C=C–H₂
How many products, including stereoisomers, are formed when 2-methylpent-2-ene is treated with HBr in presence of perodes?
4
3
2
1
The correct answer is: 1
What is anti-Markovnikov addition?
Anti-Markovnikov addition is a type of addition reaction in organic chemistry where an electrophile adds to the carbon atom of a double bond in a way that the less substituted carbon becomes the site of attachment for the electrophile. This is in contrast to the Markovnikov addition, where the more substituted carbon of the double bond is the site of attachment.
The reaction of 2-methylpent-2-ene with HBr in the presence of peroxides undergoes a radical addition reaction known as the anti-Markovnikov addition. This reaction leads to the formation of a single product. Therefore, the correct answer is: 1
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The air in your classroom contains a mixture of gases, including oxygen and nitrogen.
Which term best describes the solubility of the gases?
Answer:
The solubility of gases in a liquid or another gas is a measure of the extent to which the gas can dissolve in the liquid or gas. It is usually expressed as the amount of gas that can dissolve in a given volume of liquid or gas at a specific temperature and pressure. The solubility of gases in a mixture, such as the air in your classroom, can vary depending on the specific gases present and their relative proportions.
pls award brainliest!
Explanation:
What is occuring when reactants are mixed ad heated and liquid collects in the side of the apparatus for esterification
When reactants are mixed and heated in an esterification reaction, a liquid product is formed along with other byproducts.
When reactants are mixed and heated in an esterification reaction, a liquid product is formed along with other byproducts. Esterification is a chemical reaction between an alcohol and a carboxylic acid, often catalyzed by an acid catalyst such as sulfuric acid. The reaction produces an ester and water as byproducts.
During the reaction, the alcohol and carboxylic acid are mixed together and heated. The acid catalyst is added to speed up the reaction. As the reaction proceeds, the ester and water are formed. The ester is a liquid, while water is a gas at the reaction temperature.
The liquid product that collects in the side of the apparatus is the ester that is being produced. This liquid can be separated from the reaction mixture and purified using various techniques, such as distillation or extraction. The byproduct water can also be removed by distillation or other means. The ester that is produced can have a wide range of applications, such as in the production of perfumes, flavorings, and plastics.
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Intermolecular forces are primarily responsible for: Select the correct answer below: holding together the atoms in a molecule holding together molecules in a material both a and b none of the above
Answer:
B holding together molecules in a material
Explanation:
Intermolecular forces are primarily responsible for holding together molecules in a material due to the fact that they are interactive forces between molecules
3. Which model has properties most similar to chlorine?
Model A
Model B
Model C
Model D
Answer:
bnsjsbbakakaisbsbwnsjznss
Explanation:
cnsjzjsnsnsjs ssnsnsnzksmnznnzna
explain how the principle of faunal succession connects prehistoric life to the age of sedimentary rocks
The principle of faunal succession is a key concept in the study of prehistoric life and the age of sedimentary rocks. It is based on the idea that the fossilized remains of different species of animals and plants found in sedimentary rocks can be used to infer the relative age of the rocks and the conditions that existed when they were formed.
What are sedimentary rocks?The principle of faunal succession states that over time, the species of animals and plants that lived in a particular area changed and evolved. As a result, the fossilized remains of different species found in sedimentary rocks can be used to infer the relative age of the rocks.
This principle is based on the idea that the fossil record is a record of the evolution of life on Earth. In addition, the principle of faunal succession also provides insight into the ancient environment and climate. For example, the presence of certain types of fossils, such as coral reefs or tropical plants, may indicate that the area was once a warm, shallow sea.
In all, the principle of faunal succession is a powerful tool that connects prehistoric life to the age of sedimentary rocks. By studying the fossilized remains of different species found in sedimentary rocks, scientists can infer the relative age of the rocks and the conditions that existed when they were formed.
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Convert 8.00 x 1020 molecules of H2 to moles.
Answer:
1.33 x 10^-3 mol H2
Explanation:
? mol H2 = 8.00 x 1020^20 molecules H2 x 1 mol H2/6.02 ! 1023 molecules H2 = 1.33 x 10^-3 mol H2
Hope that helps!
8.00 x 10²⁰ molecules of H₂ present in 1.33 x 10⁻³ mole of H₂.
What is mole?Mole is used to define the amount of quantity of any substance and 1 mole equals to the 6.023 × 10²³ elementary entities or atoms in it.
According to the question:
1 mole of H₂ = 6.023 × 10²³ molecules of H₂
or 1 molecules of H₂ = 1 mole of H₂ / 6.023 × 10²³ molecules of H₂
To convert 8.00 x 10²⁰ molecules into mole we calculate as follow:
x mole of H₂ = (8.00 x 10²⁰ molecules x 1 mole of H₂) / 6.023 × 10²³ molecules
x mole = 1.33 x 10⁻³ mole
Hence, 1.33 x 10⁻³ mole of H₂ consist 8.00 x 10²⁰ molecules.
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Analysis:
1. List the 5 metals (copper, iron, magnesium, lead, silver) in order of ease of reduction (most easily
reduced first, least easily reduced last)
Answer:
Magnesium
Iron
Copper
Lead
Silver
Explanation:
Orange light has a frequency of 4.8×1014 s−1. What is the energy of one quantum of orange light?
The energy of one quantum of orange light, given that it has a frequency of 4.8×10¹⁴ s⁻¹ is 3.18×10⁻¹⁹ J
How do I determine the energy?We know that energy and frequency are related according to the following equation:
Energy (E) = Planck's constant (h) × frequency (f)
E = hf
Using the above formula, we can obtain the energy of one quantum of the orange light. Details below:
Frequency (f) = 4.8×10¹⁴ s⁻¹Planck's constant (h) = 6.626×10⁻³⁴ JsEnergy (E) = 6.23×10⁻¹⁹ JEnergy (E) = Planck's constant (h) × frequency (f)
E = hf
E = 6.626×10⁻³⁴ × 4.8×10¹⁴
E = 3.18×10⁻¹⁹ J
Thus, the energy is 3.18×10⁻¹⁹ J
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Super find 40 gauge copper wire is a diameter of only 0.080 mm and Waze only 44.5 g/km. Suppose a spool of 40 gauge wire weighs 471. g Les after some wire is pulled off to wind a magnet. How could you calculate how much wire is used. Set the math up. Do not do any of it just leave your answer as a “math expression”Also be sure your answer includes all correct unit symbols
Answer:
10.58km
Explanations:The formula needed to calculate the amount of wire used is expressed as:
\(\text{length of wire used=}\frac{W}{w_g}\)W is the weight of wire used to wind a magnet
wg is the weight of wire per km
Given the following parameters:
\(\begin{gathered} W=471g \\ w_g=44.5\text{g/km} \end{gathered}\)Substitute the given parameters into the formula to have:
\(\begin{gathered} \text{Length of wire used=}\frac{471\cancel{g}}{44.5\cancel{g}km^{-1}} \\ \text{Length of wire used}=\frac{471}{44.5}km \\ \text{Length of wire used=}10.58\operatorname{km} \end{gathered}\)Hence the length of wire used is 10.58km
True or false; when something heats up, New energy is created, and when something cool down, Energy is destroyed.
Answer:
This is false.
Explanation:
This statement directly opposes the first law of thermodynamics which states that energy can neither be created nor destroyed, but can transfer from one source to another.
Explain how you would confirm that no oxygen gas is given off at the
anode during the electrolysis.
Answer:
ions are attracted to the anode The volume of hydrogen given off is twice the volume of oxygen given of
Explanation:
This is a sign of a chemical reaction that involves the production of bubbles or fizzing
Answer:
gas production
Explanation:
Answer:
gas formation
Explanation:
frothy bubbles produced by carbon dioxide gas are a sign that a chemical reaction has occurred when a based is mix with acid.
A car traveling at a constant speed of 75 miles/hr for 7.5 hours will go how far?
a
10 miles
562.5 miles
b
O.c
Od
751.5 miles
199 miles
Answer:
The answer is 562.5 milesExplanation:
The distance covered by an object given it's velocity and time taken can be found by using the formula
distance = velocity × time
From the question we have
distance = 75 × 7.5
We have the final answer as
562.5 milesHope this helps you
PLEASE PLEASE HURRY AND HELP WILL MARK
BRANILEST!!! List the controlled variables for this lab. (Correct me if I’m wrong on the one answered PLEASE)
Here you go hope this helps :))
what is single and double displacement reaction?
\({{\boxed{\mathcal{\red{It \: will \: be \: in \: your\: \: text \: book \: see}}}}}\)
2) a chemist combines 122.0 kg of ammonia with 211.4 kg ofcarbon dioxide, and obtains 185.1 kg of urea.a) determine the limiting reactant.b) determine the theoretical yield of urea. (answer: 215.3 kg)c) determine the percent yield for the reaction. (answer: 86.0%)d) how many kg of the excess reactant is left? (answer: 53.5 kg)
A. Ammonia is the limiting reactant.
B. Theoretical yield of urea is 215.3 kg.
C. Percent yield for the reaction is 86.0%
D. The mass of the excess carbon dioxide left is approximately 54.1 kg.
a) To identify the limiting reactant, we should compare the amount of products formed from each reactant. The chemical equation for the formation of urea \((NH_2CONH_2)\) by combining ammonia \((NH_3)\) and carbon dioxide \((CO_2)\) is as follows:
\(2 NH_3 + CO_2 - > NH_2CONH_2 + H_2O\)
The stoichiometry of the balanced equation indicates that the ratio of ammonia to urea is 2:1.
We can find the number of moles for each reactant using the following masses:
Moles of ammonia = 122.0 kg / 17.03 g/mol = 7.17 mol
Moles of carbon dioxide = 211.4 kg / 44.01 g/mol = 4.80 mol
It takes 14.34 moles of ammonia to react completely with the available carbon dioxide because the ratio of ammonia to urea is 2:1. But the amount of ammonia we have is less than we need - only 7.17 mol. As a result, ammonia is the limiting reactant.
b. Based on the limiting reactant, it is possible to calculate the theoretical yield of urea. We can use the moles of ammonia, which is the limiting reactant, to calculate the moles of urea:
Moles of urea = 7.17 mol / 2 = 3.58 mol
We can determine the theoretical yield of urea using the molar mass of urea (60.06 g/mol) as a starting point:
Theoretical yield of urea = 3.58 mol * 60.06 g/mol = 215.3 kg
C. The actual yield (185.1 kg) is calculated by dividing it by the theoretical yield (215.3 kg), then multiplying the result by 100%.
Percent yield = (185.1 kg / 215.3 kg) * 100% = 86.0%
D. We can calculate the amount of non-limiting reactant that has not reacted yet to determine the excess reactant. Since ammonia is the limiting reactant, we must determine how much excess carbon dioxide there is:
Moles of excess carbon dioxide = Moles of carbon dioxide initially - Moles of carbon dioxide used
= 4.80 mol - (7.17 mol / 2) = 1.23 mol
We can determine the mass of excess carbon dioxide using the molar mass of carbon dioxide (44.01 g/mol):
Excess carbon dioxide = 1.23 mol * 44.01 g/mol = 54.1 kg
Therefore, the mass of the excess carbon dioxide left is approximately 54.1 kg.
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Carla makes a small cardboard boat and floats it in a tub of water. When she adds a drop of dish soap behind the boat, the boat moves forward. Which statement best explains what happened? The soap increased the viscosity of the water behind the boat, allowing the water in front of the boat to flow more easily. The soap reduced the surface tension behind the boat, causing both water molecules and the boat to be pulled forward. The soap increased the kinetic energy of the water molecules behind the boat, causing both the molecules and the boat to move forward. The soap formed an immiscible layer on the water, causing the soap to spread out and push the boat forward.
Answer:
B
Explanation:
The soap reduced the surface tension behind the boat, causing both water molecules and the boat to be pulled forward, hence option B is correct.
How surface tension works?The water molecules are attracted to the surface tension, which reduces the surface tension behind the boat. The boat goes ahead because water molecules tend to travel towards higher surface tension.
Small items will "float" on the surface of a fluid due to surface tension, as long as they cannot pierce and differentiate the top layer of water molecules.
When there is an object on the fluid's surface, the surface that is under tension will act like an elastic membrane.
Therefore, the boat was dragged forward along with the water molecules as the soap decreased the surface tension behind it.
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The mass ratio of C : H : O in natural vitamin C found in rose hips is 9:1:12. Predict the mass ratio of synthetic vitamin C synthesized in the laboratory.
The predicted mass ratio of synthetic vitamin C synthesized in the laboratory is 6:8:6 for C:H:O, which corresponds to a total mass ratio of 27.
The mass ratio of C : H : O in natural vitamin C found in rose hips is 9:1:12. To predict the mass ratio of synthetic vitamin C synthesized in the laboratory, we need to consider the molecular formula of natural vitamin C, which is C6H8O6.
The molecular formula of synthetic vitamin C is the same as that of natural vitamin C, C6H8O6. This means that the mass ratio of carbon (C) to hydrogen (H) to oxygen (O) in synthetic vitamin C will also be 6:8:6.
In both cases, the total mass ratio remains the same at 27 (9 + 1 + 12 = 22 for natural vitamin C and 6 + 8 + 6 = 20 for synthetic vitamin C). However, the individual ratios within the mass ratio differ due to the different numbers of carbon, hydrogen, and oxygen atoms in the molecules.
It is important to note that the molecular structure and arrangement of atoms in synthetic vitamin C may be identical to natural vitamin C, but slight differences in isotopes or impurities could lead to minor variations in the actual mass ratio.
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