Calculate the magnitude of the electric field in terms of q and the distance r from the common center of the two shells for r
Answers
In terms of q and the distance r from the common center of the two shells, the electric field's magnitude for r < R is q / 4πε0r², and for R < r < D, the electric field's magnitude is given by q / 4πε0r² - q / 4πε0(R + D - r)².
Two shells, each of radius R, are concentric with a common center and separated by a distance D. The first shell carries a positive charge q, and the second shell carries an equal negative charge -q.
We need to calculate the magnitude of the electric field in terms of q and the distance r from the common center of the two shells for r < R and R < r < D.
Calculation of Electric FieldWe have two options to calculate electric fields;
Gauss's law is the first option, and Coulomb's law is the second option.Since we are dealing with a charged shell here, Gauss's law is the most appropriate one.Gauss's law:
∫E.dA = qenc / ε0
From the Gauss's law, the electric field generated by a charged shell of radius R and charge q isE = q / 4πε0r²We can calculate the electric field at points P1 and P2 with this formula.
Calculation for r < R:
Since r < R, the electric field E1 at point P1 (at a distance r from the common center of the shells) is due only to the charge on the inner shell, which is positive.
E1 = q / 4πε0r²
Calculation for R < r < D:Since R < r < D, the electric field E2 at point P2 (at a distance r from the common center of the shells) is due to the charges on both shells, positive and negative.
Because the negative charge is more extensive than the positive charge and has a higher surface area, the negative charge's electric field is more significant than the positive charge's electric field.
As a result, the electric field at P2 points in the negative charge's direction.
E2 = q / 4πε0r² - q / 4πε0(R + D - r)²
Thus, in terms of q and the distance r from the common center of the two shells, the electric field's magnitude for r < R is q / 4πε0r², and for R < r < D, the electric field's magnitude is given by q / 4πε0r² - q / 4πε0(R + D - r)².
The question should be:
Two shells, each of radius R, are concentric with a common center and separated by a distance D. The first shell carries a positive charge q, and the second shell carries an equal negative charge -q. Calculate the magnitude of the electric field in terms of q and the distance r from the common center of the two shells for r < R and R < r < D
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Related Questions
How do astronomers explain the fact that some planetary systems (besides our own) have jovian-size planets that orbit very close to their stars? group of answer choices jovian planets must be created by collisions of terrestrial planets. Jovian planets must be objects from outside the system that were captured. The solar nebula theory must be wrong because jovian planets cannot be that close. The observations must have been misinterpreted. The planets likely formed farther out, then migrated inward
Answers
Astronomers explain the presence of jovian-size planets that orbit very close to their stars through the theory of planetary migration.
According to this theory, the planets likely formed farther out from their host stars and then migrated inward over time.This migration process can occur due to various mechanisms, such as gravitational interactions with other planets, interactions with the protoplanetary disk, or tidal forces. As the planets migrate inward, they may end up in close proximity to their host stars, even if they initially formed farther away.This explanation is supported by observational evidence, including the detection of hot Jupiters—gas giant planets with short orbital periods—around other stars. The migration theory provides a plausible explanation for why these massive planets can be found so close to their stars.Therefore, the correct answer from the given choices would be: The planets likely formed farther out, then migrated inward.
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An engineer is designing a small toy car that will be launched from rest. The engineer wants to maximize the kinetic energy of the car when it is launched by a compressed spring. He can only make one adjustment to the initial conditions of the car. Which of the following modifications to the car design would have the greatest effect on increasing the kinetic energy of the car?
A. Decrease the mass of the car slightly.
B. Increase the mass of the car slightly.
C. Decrease the launch speed of the car slightly.
D. Increase the weight of the car slightly.
Answers
The modifications to the car design that would have the greatest effect on increasing the kinetic energy of the car is to increase the mass of the car slightly (option B).
What is kinetic energy?Kinetic energy is the energy possessed by an object because of its motion. The kinetic energy equal (nonrelativistically) to one half the mass of the body times the square of its speed.
According to this question, an engineer is designing a small toy car that will be launched from rest. The engineer wants to maximize the kinetic energy of the car when it is launched by a compressed spring.
However, he can only make one adjustment to the initial conditions of the car. Considering the fact that the mass of an object is directly proportional to the kinetic energy.
This suggests that the modifications to the car design that would have the greatest effect on increasing the kinetic energy of the car is to increase the mass of the car slightly.
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Explain how skeletal muscles work in pairs.
plzzzz answer asap !!
Answers
Answer:
it holds the bone and helps to move
I don't know if this is right
6. A car accelerates from rest to 5m/s in 20 s. The force from the engine is 2000N. The force of air resistance and friction acting is 1000N. What is the cars mass?
Answers
Answer:
net force= 2000-1000=1000
a=v-u/t=5/20=1/4
m=?
m=f/a
=1000÷1/4=4000kg
unbalanced forces make an object:
A.accelerate
B.move at a constant speed
C.explode
D.come to rest
Answers
Answer:
i would have to say B makes the most sense
Explanation:
suppose you have two socks sticking together in the clothes dryer from static electrity. what happens if they are spun gently?
Answers
As the two socks are being spun too slowly, they are probably not going to stick together since the static charge would be too small to cause them to adhere.
An imbalance in the charged particles of the thing is what causes static electricity, according to this definition. Until they are released or discharged, these charges remain on the object's surface. Static electricity is produced at the surface of the object as a result of these charges.
When a dryer's electricity supply is turned on, clothing spin faster and become stuck to one another, creating friction force between them. When the supply gets off, the spinner stopped its movement and the result is the static electricity that causes the socks to stuck together.
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Mass can be expressed in
Answers
Answer:
mass can be expressed in newtons
The component of a refrigeration system that picks up heat particles from the refrigeration cabinet is called
Answers
The component of a refrigeration system that picks up heat particles from the refrigeration cabinet is called the evaporator.
The evaporator is an essential component of a refrigeration system responsible for absorbing heat from the refrigeration cabinet or the area to be cooled. It acts as a heat exchanger, allowing the refrigerant to evaporate and absorb heat from the surroundings, thus cooling the interior of the cabinet or space. The evaporator facilitates the transfer of heat energy from the refrigeration load to the refrigerant, enabling the cooling process within the system.
In a refrigeration system, the component that picks up heat particles from the refrigeration cabinet is called the evaporator. The evaporator is typically a coil or series of coils that are in direct contact with the air or surface to be cooled. As the refrigerant flows through the evaporator, it undergoes a phase change from a liquid to a gas, absorbing heat from the surrounding environment in the process. This heat transfer allows the refrigerant to remove the heat from the refrigeration cabinet, effectively cooling it down. The evaporator is a crucial part of the refrigeration cycle that facilitates the removal of heat and enables the system to maintain low temperatures inside the cabinet or space.
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ehicle collisions involve huge amounts of energy. How does the crashworthiness of a car affect the transfer and transformations of the energy and, ultimately, protect the occupants with consideration of the Law of Conservation of Energy.
Answers
When the two-vehicle collides transformation of the energy is done in terms of kinetic energy.
What is the law of conservation of energy?According to the Law of Conservation of Energy, energy can neither be created nor destroyed, but it can be transferred from one form to another.
The total energy is the sum of all the energies present in the system. The potential energy in a system is due to its position in the system.
In the above problem, the Vehicle get collides so that the kinetic energy of the vehicle is converted into the kinetic energy of another vehicle the speed of the vehicle will reduce when they collide.
Momentum also gets conserved when the two vehicles collide.
Hence, the transformation of the energy is done in terms of kinetic energy.
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select the planetary properties which we can measure with current doppler method.
-eccentricity of orbit
-semimajor axis of orbit
-lower limit mass
-orbital period
Answers
The Doppler method can measure the eccentricity of orbit, semimajor axis of orbit, lower limit mass, and orbital period of exoplanets.
Eccentricity of orbit: The Doppler method can provide information about the eccentricity of a planet's orbit by detecting the periodic variations in the star's radial velocity caused by the planet's gravitational pull.
Semimajor axis of orbit: The Doppler method allows for the determination of the semimajor axis of a planet's orbit. By measuring the periodic changes in the star's radial velocity, scientists can infer the distance between the star and the planet, which corresponds to the semimajor axis.
Lower limit mass: The Doppler method can provide a lower limit estimate of a planet's mass. By observing the periodic variations in the star's radial velocity, scientists can calculate the minimum mass of the planet based on the gravitational influence it exerts on the star.
Orbital period: The Doppler method is particularly effective in determining the orbital period of a planet. By measuring the time it takes for the periodic changes in the star's radial velocity to repeat, scientists can accurately determine the planet's orbital period.
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give any 2 evidence of the unsual expansion of water
Answers
Answer:
The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4o C to 0o C, and it becomes less dense.
Explanation:
The density is maximum at 4 degree centigrade and decreases below that temperature as shown in graph.
1. Draw the free body diagram for a parked car
2. Draw the free body diagram for a book being pushed across a smooth desk with no friction
3. Draw the free body diagram for a book being pushed across an old table top with a bumpy surface
Answers
Answer:
can't do it here
Explanation:
can't draw in here sorry dude
An elevator, mass 4750kg, is designed so that the maximum acceleration is 0.50m/s2. What are themaximum and minimum forces the motor exerts on the cable?
Answers
The free body diagram of the elevator can be shown as,
According to free body diagram, the net force acting on the elevator is,
\(F_n=T_{\max }-mg\)According to Newton's law,
\(F_n=ma\)Plug in the known expression,
\(\begin{gathered} ma=T_{\max }-mg \\ T_{\max }=ma+mg \\ =m(a+g) \end{gathered}\)Substitute the known values,
\(\begin{gathered} T_{\max }=(4750kg)(0.50m/s^2+9.8m/s^2) \\ =(4750\text{ kg)(}10.3m/s^2)(\frac{1\text{ N}}{1kgm/s^2}) \\ =48925\text{ N} \end{gathered}\)Thus, the maximum force exerted on the cable is 48925 N.
For minimum, tension the net force can be expressed as,
\(F_n=mg-T_{\min }\)Plug in the known expression,
\(\begin{gathered} ma=mg-T_{\min } \\ T_{\min }=mg-ma \\ =m(g-a) \end{gathered}\)Substitute the known values,
\(\begin{gathered} T_{\min }=(4750kg)(9.8m/s^2-0.5m/s^2) \\ =(4750\text{ kg)(}9.3m/s^2)(\frac{1\text{ N}}{1kgm/s^2}) \\ =44175\text{ N} \end{gathered}\)Thus, the minimum force exerted on the cable is 44175 N.
Resolve the weight of the box to find the component of the weight acting parallel to the slope.
W = 50N
30
Answers
Answer:
here's your answer below
Explanation:
sorry something went wrong
.
A +2.0-nC point charge is placed at one corner of a square (1.5 m on a side), and a -3.0-nC charge is placed on a corner diagonally away from the first charge. What is the magnitude of the electric field at either of the two unoccupied corners? *
Answers
With the charges of the square as +2.0-nC point charge and -3.0-nC point charge, The magnitude of the electric field is mathematically given as
Et= 14.42 N/c
What is the magnitude of the electric field at either of the two unoccupied corners?Question Parameters:
A +2.0-nC point charge is placed at one corner of a square (1.5 m on a side), and a -3.0-nC charge
Generally, the equation for the electric field is mathematically given as
E = k*q1/a^2
Therefore
E1= 9*10^9*2*10^-9/1.5^2
E1= 8 N/c
For E2
E2= 9*10^9*3*10^-9/1.5^2
E2= 12 N/c
In conclusion, The magnitude of the electric field at either of the two unoccupied corners
\(Et = \sqrt{E1^2 + E2^2}\)
Et= 14.42 N/c
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Can someone please help me with science.
Answers
Answer:
I think it is D or A
Explanation:
I have not done this in a long time, so sorry if wrong.
A spring has natural length 24 cm. Compare the work (in J) W₁ done in stretching the spring from 24 cm to 34 cm with the work (in J) W₂ done in stretching it from 34 cm to 44 cm. (Use k for the spring constant.) W₁ = J W₂ = J How are W₂ and W₁ related? W₂ = w₁
Answers
W1=W2, they are directly related, k= spring constant x= change on length of spring. x= 34-24= 10 cm
The spring constant is calculated by dividing the force required to stretch or compress a spring by the lengthening or shortening of the spring. It is used to identify whether a spring is stable or unstable, and consequently, what system it should be employed in.
It is stated mathematically as k = - F/x, which reworks Hooke's Law. Where x is the displacement caused by the spring in N/m, F is the force applied over x, and k is the spring constant.
Only in the range where the force and displacement are proportionate does Hooke's law adequately explain the linear elastic deformation of materials. Whatever the mass, a spring's elasticity will revert to its initial shape once the external force is eliminated. A characteristic is the spring constant.
Thus, W1=W2, they are directly related, k= spring constant x= change on length of spring. x= 34-24= 10 cm.
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How can you tell, based on observing an object, that there is a net force acting upon that object?
Answers
Answer:
Net force is the sum of all forces acting on an object. The net force can be calculated using Newton's second law, which states that F = ma, where: F is the net force. m is the mass of the object.
Explanation:
Answer:
accelerating
Explanation:
If accelerating it has a net ( unbalanced) force acting on it .
with zero net forces it will either remain at rest or continue moving (but not accelerate)
A meteor is falling towards the earth. The mass and the radius of the earth is 6×10^24 kg and 6.4×10^3 km respectively. What is the height of the meteor from the earth surface at which the acceleration due to gravity is 4m/s^2
Answers
Answer:
3600km
Explanation:
gravitational constant is the gravitational attraction between any two things
G = gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg²
g = acceleration due to gravity = 4 m/s²
M = mass of the earth = 6 × 10²⁴
r = radius of Earth + height of meteor
Since F = mg and F = GMm/r², mg = GMm/r²
g = GM/r²
r² = GM/g
r = √(GM/g)
r = √((6.67 × 10⁻¹¹ Nm²/kg²) × (6 × 10²⁴ kg))/(4 m/s²)) =
1 × 10⁷ m = 1 × 10⁴ km
To calculate the height of the meteor above the earth,
subtract the radius of the earth from the calculated radius.
height of meteor = 1 × 10⁴ km - 6 × 10³ km = 4 × 10³ km
quora Meave Gilchrist
snapsolve
quora
Answer:
Explanation:
MALAI TIMRO FB ID DEU NA
A sample contains 16 g of a radioactive isotope. how much radioactive
isotope remains in the sample after 1 half-life?
Answers
After one half-life, 8 g of radioactive isotope will remain in the sample.
What is radioactivity?The act of producing radiation spontaneously is known as radioactivity. This is accomplished by an unstable atomic nucleus that want to give up some energy in order to move to a more stable form.
The following formula is used to compute the number of half lives elapsed:
\(\rm N=\frac{N_0}{2^n} \\\\ N=\frac{16}{2} \\\\ N= 8 \ gram\)
Hence,8 gram of radioactive isotope remains in the sample after 1 half-life.
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Answer:
Answer is below
Explanation:
8 g
Which of the following is the best example to explain that the force on an object may change its shape?
Riding a bike
Driving a car
Making model using clay
All of the above
Answers
Answer:
C
Explanation:
Making a model using clay is the only example which is correct. The force applied to the clay from your hands reshapes the clay
whats the life cycle of a star
Answers
Answer:
huge cloud of gas and dust
A mouse eats 20 kJ of energy. The mouse uses 8 kJ of energy moving around. What would most of the leftover energy be turned into? ant is the leftover energy useful or wasted?
Answers
Answer:
to be turned into glycogen not wasted
Explanation:
Since the body has a lot of energy left it will turn that energy into glycogen which is a storage form of glucose which will when neccassary will be converted into glucose from the horomone glucagon and be given to the body to be used as energy so the energy is never wasted
Online physics Electrostatic lab
Answers
Asteroids move much slower and less frequently than stars. True False
it's false
Answers
Answer:
false plz mark brainliest
False for sure :)
Có mấy cách đo đại lượng vật lí
Answers
Answer:
please write in english
a pair of 15-watt computer speakers are connected to a 12-volt power supply. what is the electric current running through the speakers?
Answers
The current running through the speakers is 2.5A
What is electrical power?Electric power is the rate at which electrical energy is transferred by an electric circuit. The SI unit of power is the watt or joule per second.
Power can also be defined as the product of the voltage and current.
therefore power = VI
The total power of the two speakers = 15+15
= 30W
30W = 12 I
divide both sides by 12
I = 30/12
I = 2.5A
Therefore the current that will flow in the two speakers is 2.5A
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PLEASE HELP FILL IN TWO OPTIONS I WILL MARK BRAINLIEST IF RIGHT!
Answers
Answer:
Your answers are Continental crust and Mountain range.
Explanation:
Continental crust is the first blank, and Mountain range the second.
I hope I helped, and I always appreciate Brainliest!!! :)
a microscope has a 13.0x eyepiece and a 58.0x objective lens 20.0 cm apart. a. draw the ray diagram for the microscope under normal use. b. calculate the total magnification. c. calculate the focal length of each lens. d. calculate where the object must be located for a normal, relaxed eye to see it in focus.
Answers
a. Ray Diagram: The objective lens produces a real image inside the focal length of the eyepiece lens, which is then magnified to create a virtual image at infinity.
b. Total Magnification: The microscope has a total magnification of 754x, calculated by multiplying the magnification of the eyepiece (13x) by the magnification of the objective lens (58x).
c. Focal Length: To calculate the focal length of each lens, we can use the lens formula. Assuming the image distance for the objective lens is -20.0 cm (on the same side as the object) and the image distance for the eyepiece lens is infinity (virtual image), we find that both lenses have a focal length of -20.0 cm.
d. Object Location: To find where the object must be located for a normal, relaxed eye to see it in focus, consider the near point of around 25 cm. Use the lens formula for the objective lens to calculate the object distance that corresponds to the image distance of 20.0 cm.
a. Ray Diagram for the Microscope:
To draw the ray diagram for the microscope, we need to understand the basic principles of how a compound microscope works. In a compound microscope, the objective lens produces a magnified real image of the object, which is then further magnified by the eyepiece to create the final virtual image. The eyepiece acts as a magnifying lens for the image produced by the objective lens.
In the ray diagram, draw an arrow representing the object placed to the left of the objective lens. The objective lens will produce a real, inverted, and magnified image of the object. This image is located inside the focal length of the eyepiece lens. The eyepiece lens will then magnify this real image to create the final virtual image, which is located at infinity. Draw the refracted rays for each lens, showing the path of the rays as they pass through each lens and are refracted.
b. Total Magnification:
The total magnification of a compound microscope is calculated by multiplying the magnification of the objective lens by the magnification of the eyepiece. In this case, the eyepiece has a magnification of 13.0x, and the objective lens has a magnification of 58.0x. To find the total magnification, multiply these two values:
Total Magnification = Eyepiece Magnification × Objective Lens Magnification
Total Magnification = 13.0x × 58.0x
Total Magnification = 754x
c. Focal Length of Each Lens:
To calculate the focal length of each lens, we can use the lens formula:
1/f = 1/v - 1/u
Where:
f = focal length of the lens
v = image distance
u = object distance
For the objective lens:
Given that the objective lens and eyepiece are 20.0 cm apart, the image produced by the objective lens will serve as the object for the eyepiece.
Let's assume the image distance for the objective lens is -20.0 cm (since it is on the same side as the object). Plugging the values into the lens formula:
1/\(f_o_b_j_e_c_t_i_e\) = 1/-20.0 - 1/u
For the eyepiece lens:
Since we're dealing with the virtual image produced by the objective lens, the image distance for the eyepiece lens is infinity (as the virtual image appears at infinity when viewed through the eyepiece).
Plugging the values into the lens formula:
1/\(f_e_y_e_p_i_e_c_e\) = 1/infinity - 1/20.0
Simplifying the equation:
1/\(f_e_y_e_p_i_e_c_e\) = 0 - 1/20.0
Now, we can solve for the focal lengths:
\(f_o_b_j_e_c_t_i_e\) = -20.0 cm
\(f_o_b_j_e_c_t_i_e\) = -20.0 cm
The negative sign indicates that the lenses are diverging lenses commonly used in microscopes.
d. Object Location for Normal, Relaxed Eye to See in Focus:
To calculate the object location for a normal, relaxed eye to see the image in focus, we need to consider the concept of the near point (the closest distance at which the eye can focus). The near point is typically considered to be around 25 cm for a relaxed eye.
Using the lens formula for the objective lens, we can find the object distance (\(u_o_b_j_e_c_t_i_v_e\)) that corresponds to the image distance (\(v_o_b_j_e_c_t_i_v_e\)) of 20.0 cm:
1/\(f_o_b_j_e_c_t_i_v_e\) = 1/20.0 - 1/\(u_o_b_j_e_c_t_i_v_e\)
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The question probable may be:
a microscope has a 13.0x eyepiece and a 58.0x objective lens 20.0 cm apart.
A. explain how the ray diagram should be drawn for the microscope under normal use.
B. calculate the total magnification.
C. calculate the focal length of each lens.
D. calculate where the object must be located for a normal, relaxed eye to see it in focus.
A body is at equilibrium under the action of three forces. One force is 10N acting due east and one is 5N in the direction 60° north east. What is the magnitude and direction of the third force?
Answers
Answer:
If the body is in equilibrium the two forces add up and the third is the opposite of the resultant.
F(1x)=F(1)=10 N
F(2x)=F(2)cos60=5•0.5=2.5 N
F(2y) =F(2)sin60 = 5•0.866= 4.33 N
F(3x) =- F(x)=- (10+2.5 )= -12.5 N
F(3y) =- F(2y)= - 4.33 N
F(3) = sqrt{ F(3x)²+F(3y)²} =13.23 N
tan φ = F(3y)/F(3x) =4.33/12.5=0.364
φ = 19.1⁰ (south-west)
Explanation: