calculate the larmor precession frequency of a hydrogen nucleus in a 5.30 t magnetic field. assume that the shielding coefficient is zero. give your answer in hz using 5 significant digits relative to (x.xxxx).

Answer:

12

Explanation:

i agree the answer is 12 because the acceleration is given by the difference in the velocity divided by the time taken

a=v-u/t

60-0/5

=12m/s²

I hope this helps

Answer:

D

Explanation:

The minimum stopping distance of the car is determined as 8 m.

The minimum stopping distance of the car is calculated as follows;

d = (u²)/(2a)

where;

when the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s

2 = (11.11²)/(2a)

a = (11.11²)/(2 x 2)

a = 30.86 m/s²

when the speed becomes 80 km/h, the minimum stopping distance is calculated as;

u = 80 km/h = 22.22 m/s

d = (22.22² )/ (2 x 30.86)

d = 8 m

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Answer:

Explanation:

The energy stored is E = 1/2 kx^2.

E1 = E2

1/2 k(1.3)^2 = 1/2 (2k)x^2

x^2 = 1/2 (1.3)^2

x = 1.3/sqrt(2) cm

x =0.919 cm

rate me thanks

Compression in a spring with twice the spring constant to store the same amount of energy is 0.919 cm

Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.

Given spring is compressed 1.3 cm. Compression in a spring with twice the spring constant to store the same amount of energy is,

The energy stored is E = 1/2 kx².

E1 = E2

1/2 k(1.3)² = 1/2 (2k)x²

x^2 = 1/2 (1.3)²

x = 1.3/√2 cm

x = 0.919 cm

Compression in a spring with twice the spring constant to store the same amount of energy is 0.919 cm.

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We multiply the magnitude of the vector even by the cosine angle referenced towards the horizontal. The horizontal force defines as the force exerted inside a direction parallel to the horizon. Acceleration is merely the rate during which velocity changes. As a result, the magnitude indicates how rapidly velocity varies, and the further calculation can be defined as follows:

For option a:

\(\to F_{foot}= 13 \ N\\\\\to m_1= 64 \ kg\\\\\to m_2=2.9 \ kg\\\\\)

Please find the graph for the direction:

\(\to |F_{ground}|= |F_{foot}| \\\\ \to F_{ground}= -F_{foot}= - 13 \ N\\\\\)

For option b:  

\(F_{ground}=(m_1+m_2)a\\\\a=\frac{F_{ground}}{m_1+m_2}\\\\\)

For option c:  

\(\bold{a=\frac{13}{64+2.9}}\\\\\)

  \(\bold{=\frac{13}{66.9}}\\\\\bold{=0.194 \ \frac{m}{s^2}}\\\\\)

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The physics behind the movement of electric charges between parallel plates is based on the principles of electrostatics. Electric charges are either positive or negative, and they are affected by electric fields.

Electric fields are created by a difference in electric potential, which is measured in volts. When a voltage is applied to a set of parallel plates, the charges within the plates will be affected by the electric field, and will move in response to it.

When a voltage is applied to a set of parallel plates, the positive charges in the plate connected to the positive voltage will be attracted to the negative voltage, while the negative charges in the plate connected to the negative voltage will be attracted to the positive voltage.

The movement of charges between the plates is also affected by the presence of any obstacles or resistances in the electric field, such as resistance in the wire. This can slow down the movement of charges and result in a decrease in the current flowing through the circuit.

In all, the movement of charges between electric parallel plates is the result of the electric field created by a difference in electric potential, and the movement of charges is called drift velocity. The movement is also affected by the presence of resistance.

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Answer:

The  diameter is  \(d = 6.5 *10^{-4} \ m\)

Explanation:

From the question we are told that

   The length of the cylinder is  \(l = 120 \ m\)

     The resistance is  \(\ 6.0\ \Omega\)

     The  resistivity of the metal is \(\rho = 1.68 *10^{-8} \ \Omega \cdot m\)

Generally the resistance of the cylindrical wire is  mathematically represented as

         \(R = \rho \frac{l}{A }\)

The cross-sectional area of the cylindrical wire is  

        \(A = \frac{\pi d^2}{4}\)

Where  d is the diameter, so

         \(R = \rho \frac{l}{\frac{\pi d^2}{4 } }\)

=>     \(d = \sqrt{ \rho* \frac{4 * l }{\pi * R } }\)

       \(d = \sqrt{ 1.68 *10 ^{-8}* \frac{4 * 120 }{3.142 * 6 } }\)

       \(d = 6.5 *10^{-4} \ m\)

The expression for the initial velocity at point A is:

0 = (velocity at point A - 0) / time

Simplifying the equation, we find:

Velocity at point A = 0

The initial velocity at point A is zero, indicating that the object starts from rest before sliding on the horizontal plane AB.

To write an expression for the initial velocity at point A, we need to analyze the forces acting on the object and apply the principles of motion.

Given:

Mass of the object, m

Radius of the semi circle, R

Coefficient of kinetic friction, μ\(_k\) = 0.5

Force applied at point C, F = 3mg

The object is initially at rest.

Let's break down the motion into two parts: the motion on the horizontal plane AB and the motion along the semi circle BCD.

1. Motion on the horizontal plane AB:

The only force acting on the object on the horizontal plane is the force of kinetic friction. The frictional force can be calculated using:

Frictional force, f = μ\(_k\)* Normal force

The normal force is equal to the weight of the object, which is mg.

Normal force, N = mg

Frictional force, f = μ\(_k\) * mg

The frictional force acts in the opposite direction to the motion, so its magnitude is negative. Thus, the net force on the object on the horizontal plane is:

Net force = -f = -μ\(_k\)* mg

Using Newton's second law, we can relate the net force to the acceleration:

Net force = mass * acceleration

-μ\(_k\) * mg = m * acceleration

The acceleration can be expressed as the rate of change of velocity:

Acceleration = (final velocity - initial velocity) / time

Since the object is initially at rest, the initial velocity is zero.

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The mass of the cold water, given the data from the question is 500 g

Heat loss = Heat gain

MᵥᵥC(Tᵥᵥ – Tₑ) = M꜀C(Tₑ – T꜀)

200 × 4.184 (75 – 25) = M꜀ × 4.184(25 – 5)

41840 = M꜀ × 83.68

Divide both side 83.68

M꜀ = 41840 / 83.68

M꜀ = 500 g

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Answer:

Water has a high latent heat of vaporization, so it takes a large amount of heat to get converted into vapor. Although evaporation takes place continuously, there is simply not enough heat produced to evaporate all the water on earth at once.

The magnitude and direction of his displacement relative to his starting point​ is \(11\sqrt{2} \mathrm{~km}\) and direction is east.

Business man travel 11km North and later travel another 11km east.

Then magnitude = \(\sqrt{11^2+11^2}\)= \(11\sqrt{2}\) = 5.55634.

And the direction of the business  is East.

By Pythagoras theorem,

\($$\begin{aligned}&\mathrm{OB}^2=\mathrm{OA}^2+\mathrm{AB}^2 \\&\Rightarrow \mathrm{OB}^2=11^2+11^2=121+121=242 \\&\Rightarrow \mathrm{OB}=11\sqrt{2} \mathrm{~km}\end{aligned}$$\)

Magnitude is described in physics as the maximum extent of size and direction of an item. In vector and scalar quantities, magnitude is employed as a common factor. Scalar quantities are those with only magnitude, as defined by definition.

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Answer:

Explanation: The moon of the Earth is much lighter in mass than the planet itself. In addition to being smaller than Earth, the Moon is also only approximately 60% as dense. A human weighs less on the Moon because there is less gravitational attraction there than there is on Earth.

Moon has lesser mass as conpared to earth, therefore gravitational force exerted by moon on any object is lesser than that of gravitational force exerted by earth on the same object, hence we can say that astronauts weight less on moon, i.e approximately 1/6 th of their weight on earth.

Explanation:

m = 70 kg

s = 3m

t =2s

g = 10 m/s²

(a)How much work is done by the man?

W = Fs

= mg X s

= 70 x 3 x 10

= 210 x 10

= 2100 Joule

(b)What is the power exerted by the man?

P = W/t

= 2100/2

P = 1050 Watt

The magnitude and direction of the resultant force can be determined by finding the vector sum of all the individual forces acting on an object using vector addition.

This is involves finding the components of the forces in x and y direction and using Pythagorean theorem to find the magnitude and using inverse tangent to find the direction.

A resultant force is the net force acting on an object, taking into account all the individual forces. The magnitude of the resultant force is the sum of the magnitudes of all the forces and the direction is the direction in which the net force is acting.

Vector addition is used to find the magnitude and direction of the resultant force, which can be determined by finding the components of the individual forces and finding the vector sum of the components. The vector sum can then be used to find the magnitude and direction of the resultant force.

For example, consider two forces F1 and F2 acting on an object. If F1 has a magnitude of 50 N and is acting at an angle of 30 degrees and F2 has a magnitude of 30 N and is acting at an angle of 60 degrees, the magnitude and direction of the resultant force can be determined using vector addition.

By finding the x and y components of each force and finding the vector sum, the magnitude and direction of the resultant force can be determined to be 50.6 N and 39.2 degrees, respectively.

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The "ln A" column was completed by calculating the natural logarithm of the disintegrations per minute (A) for each time (t) value. Plotting A vs. t shows the exponential decrease in radioactive activity over time.

To complete the column labeled "ln A" and create a graph of A vs. t, we need to calculate the natural logarithm of the disintegrations per minute (A) for each corresponding time (t) value. The natural logarithm (ln) of a number can be calculated using a calculator or software. Let's calculate and complete the table:

Time (hours) (t) Disintegrations per minute (min⁻¹¹) (A) ln A

0 363 ln(363) ≈ 5.894

6 184 ln(184) ≈ 5.214

12 93.2 ln(93.2) ≈ 4.535

18 47.3 ln(47.3) ≈ 3.857

24 24.0 ln(24.0) ≈ 3.178

Now, we have completed the "ln A" column.

To plot a graph of A vs. t, we can use these values. A represents the disintegrations per minute (activity), and t represents time in hours. The graph will show how the activity decreases over time due to radioactive decay. The x-axis will represent time (t), and the y-axis will represent the natural logarithm of activity (ln A).

Plotting ln A against t should result in a decreasing exponential curve, which is typical for radioactive decay processes.

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Answer:

i Believe the correct answer is "An open circuit being changed into a closed circuit"

Explanation:

Answer:

180

Explanation:

1) E=F*L, where E - energy of the baseball, F - the required force, L - backward moving (0.35m);

2) E=mV²/2, where E - energy of the baseball, m - the mass of the baseball (0.14kg), V - the velocity of the baseball (30m/s).

3) if E=F*L and E=mV²/2, then F*L=mV²/2, from which

\(F=\frac{mV^2}{2L};\)

4) according to the last formula

\(F=\frac{0.14*900}{2*0.35}=\frac{126}{0.7}=180(N).\)

The force exerted by the ball on the glove is 180 Newtons.

In mechanics, a force is any action that has the potential to change, maintain, or deform a body's motion. The three principles of motion outlined by Isaac Newton in his Principia Mathematica are frequently used to illustrate the concept of force (1687).

Newton's first law states that a body at rest or moving uniformly in a straight line will stay in that state until a force is applied to it. According to the second law, a body will accelerate (change in velocity) in the direction of any external force acting on it.

Given:

A baseball (m = 140 g) traveling at 30 m/s moves a fielder's glove backward 35 cm when the ball is caught,

Calculate the value of force as shown below,

Force = m × V² / 2L

Force = 0.140 × 30² / 2 × 0.35

Force = 0.140 × 900 / 0.70

Force = 126 / 0.7

Force = 180 N

Thus, the force exerted by the ball is 180 Newtons.

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The refraction of a sound wave occurs when the sound wave bends as it passes through the boundary between media. Refraction occurs when there is a difference in the speed of sound waves in two different media.

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To find the answer to this problem, we have to use the right-hand rule because the magnetic field and the current are perpendiculars.

Answer:

Explanation:

b

Answer:

As thermal energy increases,there is more particle movement

Any object that has mass has a gravitational force proportional to that objects size.

Here "mass" is thought to be inextricably linked to gravitational forces. Every object in the universe is attracted to one another by gravity. The gravitational pull between two objects is proportional to their masses and becomes weaker as their distance from one another grows. A falling object attracts the Earth with a force equal to that with which the Earth attracts it. Both objects exert an equal attractive force on one another. The Earth's movement is inexorably small due to the enormous mass disparity between it and the falling object.

Therefore, the magnitude of the gravitational force is directly proportional to the masses of the objects and inverse to the square of the distance between the objects. Gravitational force is a force of attraction that exists between all objects with mass.

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To show an object's direction and location, motion maps are employed. The motion map provides the following information about the object's position and speed: With a high velocity, the object begins to travel away from the origin.

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If a 5kg mass starts from rest at xo = -1 and moves under the action of a variable force F(x) = √1-x² to point xf = 1. Then the total work done by the force is equal to π/2 + 1.

To calculate the total work done by the force in this scenario, we can use the formula for work:

Work = ∫F(x) dx

where F(x) is the force as a function of position and dx represents an infinitesimal displacement.

In this case, the force is given by F(x) = √(1 - x²), and we need to find the total work done as the object moves from xo = -1 to xf = 1.

Let's break down the calculation step by step:

Write the integral for work:

Work = ∫F(x) dx

Substitute the given force:

Work = ∫√(1 - x²) dx

Integrate with respect to x:

To integrate the square root of (1 - x²), we use the trigonometric substitution. Let's substitute x = sin(θ) and dx = cos(θ) dθ.

Work = ∫√(1 - sin²(θ)) cos(θ) dθ

Simplify the integrand:

Using the trigonometric identity sin²(θ) + cos²(θ) = 1, we can rewrite the integrand as cos²(θ).

Work = ∫cos²(θ) dθ

Apply the power-reducing formula:

The power-reducing formula states that cos²(θ) = (1 + cos(2θ)) / 2. We can use this formula to simplify the integrand further.

Work = ∫(1 + cos(2θ))/2 dθ

Integrate the terms separately:

Work = (1/2) ∫dθ + (1/2) ∫cos(2θ) dθ

The first integral, ∫dθ, is simply θ, and the second integral, ∫cos(2θ) dθ, can be calculated as sin(2θ)/2.

Work = (1/2) θ + (1/2) (sin(2θ)/2) + C

Evaluate the integral limits:

To find the total work done, we need to evaluate the integral at the upper and lower limits of integration.

At xf = 1, the angle θ is π/2, and at xo = -1, the angle θ is -π/2.

Work = (1/2) (π/2) + (1/2) (sin(2(π/2))/2) - [(1/2) (-π/2) + (1/2) (sin(2(-π/2))/2)]

Simplifying further:

Work = π/4 + (1/2) - (-π/4 + (1/2))

Work = π/4 + 1/2 + π/4 + 1/2

Work = π/2 + 1

Therefore, the total work done by the force is equal to π/2 + 1.

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The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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The speed of the microwaves is 3 × 10^10 meters per second. This result indicates that microwaves, like all electromagnetic waves, travel at the speed of light in a vacuum.

The speed of a wave can be calculated using the formula: speed = frequency × wavelength. In this case, the frequency of the microwaves is given as 10,000 million Hz, which is equivalent to 10,000 × 10^6 Hz or 10^10 Hz. The wavelength is given as 0.03 m.

Plugging these values into the formula, we have:

Speed = (10^10 Hz) × (0.03 m)

Simplifying the calculation, we find:

Speed = 3 × 10^10 m/s

Therefore, the speed of the microwaves is 3 × 10^10 meters per second. This result indicates that microwaves, like all electromagnetic waves, travel at the speed of light in a vacuum. The speed of light is approximately 3 × 10^8 meters per second, so microwaves have a slightly higher speed due to their longer wavelength. It's important to note that the speed of light is a fundamental constant of nature and does not depend on the properties of the specific electromagnetic wave being considered.

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Answer:

The amount of charge that flow through a point is \(\Delta q = 0.126 \ C\)

Explanation:

From the question we are told that

    The number of turns is  \(N = 100\)

    The area is  \(A = 5.87 *10^{-3} m^2\)

       The total resistance is \(R = 14.9 \ \Omega\)

       The magnetic field in first direction  is  \(B_1 = 1.93 \ T\)

        The magnetic field in second   direction  is \(B_2 = -1.93 \ T\)

The change in magnetic field is evaluated as

     \(\Delta B = B_1 - B_2\)

substituting values

      \(\Delta B = 1.93 - [- 1.93]\)

       \(\Delta B =3.2 \ T\)

The induced emf due to the change is mathematically evaluated as

        \(e = NA \frac{\Delta B }{\Delta t }\)

This can also be mathematically represented as

     \(e = IR\)

     Where I can be mathematically represented as

     \(I = \frac{\Delta q }{\Delta t}\)

So  

     \(e = \frac{\Delta q}{\Delta t } R\)

Now  

      \(\frac{\Delta q}{\Delta t } R = NA \frac{\Delta B }{\Delta t }\)

=>   \(\Delta q = \frac{N A (\Delta B)}{R}\)

substituting values

     \(\Delta q = \frac{100 * 5.87 *10^{-3} (3.2}{14.9}\)

     \(\Delta q = 0.126 \ C\)

The equations for rotary motion is based on motion in a circular path

a) Time taken by clothes to come up to speed during washing is approximately 1.325 s

b) The tub turns approximately 24.016 revolutions in the 20.0 s interval

Reasons:

Known parameter are;

Operating speed of an automatic washing machine = 5.5 rad·s⁻¹

Average angular acceleration of the washing machine, α = 4.15 rad·s⁻²

Angular speed in the spin-dry mode, ω = 6.0 revolution per second

Time it takes to reach angular speed in spin-dry mode = 7.0 s

a) The relationship between angular acceleration and time are;

\(\alpha = \dfrac{\Delta \omega}{\Delta t}\), \(\Delta t = \dfrac{\Delta \omega}{\alpha}\)

Where;

Δω = ω₂ - ω₁ = 5.5 rad·s⁻¹

Δt = The time it takes to accelerate

Therefore;

\(\Delta t = \dfrac{5.5 \ rad\cdot s^{-1}}{4.15 \ rad \cdot s^{-2}} \approx 1.325 \ s\)

The time it takes for the clothes to come up to speed during the washing mode, Δt ≈ 1.325 s

b) The angular acceleration of the spin-dry mode is given as follows;

6 revolutions per second = 2·π ×6  rad per second = 12·π rad/s

\(\alpha = \dfrac{\Delta \omega}{\Delta t}\)

The acceleration during spin up

\(\therefore \alpha = \dfrac{12 \cdot \pi }{7.0} \ rad \cdot s^{-2} \approx 5.39 \ rad \cdot s^{-2}\)

The acceleration during slowing down;

\(\therefore \alpha = \dfrac{12 \cdot \pi }{13.0} \ rad \cdot s^{-2} \approx 2.9 \ rad \cdot s^{-2}\)

The angle turned in the 20.0 second interval is therefore;

\(\dfrac{1}{2} \times 5.39 \times 7^2 + 12 \cdot \pi \times 7-\dfrac{1}{2} \times 2.9 \times 13^2 \approx 150.9\)

The angle turned in the 20.0 s is approximately 150.9 radians

\(Number \ of \ revolutions \ =\dfrac{\theta}{2 \cdot \pi}\)

Therefore;

\(Number \ of \ revolutions \ in \ 20.0 \ s =\dfrac{150.9 }{2 \cdot \pi} \approx 24.016\)

The number of revolutions of the tub in the 20.0 s interval is approximately 24.016 revolutions

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Answer:

The  value is  \(\Delta t  =  0.01 \ s\)

Explanation:

From the question we are told that

   The time of flight is  \(T  =  0.02 \  s\)

Given that the value of the time of flight is in three decimal place then the error quote is

     \(\Delta t  =  0.01 \ s\)