Calculate the kinetic energy of a 1500 kg car moving at 42 km/hr.

The question is incomplete as it does not have the options which are:

The waves have a trough.

Particles move only small distances.

particles travel the length of the wave, moving in an up-and-down motion.

The waves have a crest.

The energy is transferred perpendicular to the direction of the wave motion.

Answer:

Explanation:

Transverse waves are the waves which can be characterised easily by their oscillation in a perpendicular direction to the path of the wave propagation.

The particle follows the wave nature and moves only to a small distance like ripples in the water and these waves possess the trough, the lower part and the crest the upper part.

These waves can be observed in ripples of the water, in a string of the guitar while playing and the electromagnetic waves.

Thus, the selected options are correct.

Answer:

B

Explanation:

Answer:

c

Explanation:

because it is a hypthesis led up by earths crust is made up of large, but dont get to wrong! it is slow so answer is

HYPOTHESIS

Magnification of the compound microscope with given values is 3.4 x 10², which means it can magnify 340 times.

The enhancing power of a compound amplifying focal point is given by the recipe:

Enhancement = (1 + (f0/fe)) x (do/de)

Where f0 is the focal length of the objective point of convergence, fe is the focal length of the eyepiece, do is the distance between the article and the objective point of convergence, and de is the distance between the eyepiece and the virtual picture.

Subbing the given characteristics into the situation, we get:

Enhancement = (1 + (0.50 cm/2.0 cm)) x (0.52 cm/(25 cm - 0.50 cm))

Enhancement = 3.4 x 10²

The given condition for the strengthening force of a compound magnifying lens is utilized with the given qualities to compute the amplification of the magnifying instrument. The subsequent worth of 3.4 x 10² implies that the magnifying lens can amplify an item multiple times its unique size when seen a ways off of 25 cm.

Consequently, the intensifying power of the amplifying instrument is 3.4 x 10², and that suggests that the amplifying focal point can enhance a thing on numerous occasions its one of a kind size when seen a distance away of 25 cm.

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Answer: the answer is A

Explanation: The independent or manipulated variable in Experiment III was the treatments used to prevent corrosion. The dependent or responding variable was the amount of corrosion, rated on a scale of 0 to 5.

a. The kinetic energy at this moment is 81J.

b. The net work done on the object when its velocity changes to (8.00i - 4.00j) m/s is 63J.

a. The kinetic energy of the object can be found using the formula KE = (1/2)mv^2, where m is the mass of the object and v is its velocity. Plugging in the given values, we get:

KE = (1/2)(3.00 kg)((6.00 m/s)^2 + (-2.00 m/s)^2)
KE = 81 J

Therefore, the kinetic energy of the object at this moment is 81 J.

b. The net work done on the object can be found using the work-energy theorem, which states that the net work done on an object is equal to its change in kinetic energy. That is:

Net work = KE(final) - KE(initial)

To find the net work, we need to first calculate the final kinetic energy of the object. Using the same formula as before, but with the new velocity, we get:

KE(final) = (1/2)(3.00 kg)((8.00 m/s)^2 + (-4.00 m/s)^2)
KE(final) = 144 J

Now we can plug in both the initial and final kinetic energies to find the net work:

Net work = KE(final) - KE(initial)
Net work = 144 J - 81 J
Net work = 63 J

Therefore, the net work done on the object is 63 J.

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Answer:

1.) 347,000,000

2.)7,940

3.)0.00196

4.)4,500,000,000

5.)0.00000961

6.)102,000

7.).000000000701

8.)44.4

Explanation:

when the power is positive, you just need to move decimal point to your right , for a number of times which is similar to the value of the power.

Eg. 3.47×10 raised to the power 8.

with this, move the decimal point to the right eight times which will be 347,000,000.

But when the power is negative, move the decimal point to the left for a number times which will be similar to the value of the power.

Eg. 1.96×10 raised to the power negative 3.

move the decimal point leftwards three times which will be 0.00196

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Electric current is a term used to describe how much electricity flows across a circuit and how it flows in an electronic circuit. Amperes are used to measure it (A).

The energy of charged particles is referred to as electricity. One option for storing electricity is a battery. Electricity flows when you connect a battery to a light bulb. Due to the fact that electrical charges (electrons) can freely transport energy from the battery through the bulb, this occurs.

Disconnect the power source. This is the first and most crucial requirement to abide by. This is the first and most crucial rule to adhere to. If you ever need to repair electrical equipment in your house, be sure to first unplug it from the power source. It might not be sufficient to simply turn it off.

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Explanation:

where are the statements

The characteristic of metal woods or hybrids that would result in more playing loft in an on-plane swing is a higher loft angle on the clubface.

The loft angle of a clubface plays a crucial role in determining the trajectory and distance of a golf shot. In an on-plane swing, where the clubhead moves along a consistent path, the loft angle becomes the primary factor in controlling the launch angle and spin rate of the ball.

Metal woods and hybrids typically have adjustable loft options, allowing golfers to customize the loft angle to suit their swing and desired ball flight. By increasing the loft angle on the clubface, more playing loft can be achieved. This means that the ball will launch higher into the air and have a steeper descent angle, which can be advantageous in certain situations, such as when trying to carry hazards or hold a green.

It's important to note that loft angle is not the only factor influencing playing loft. Swing dynamics, such as the angle of attack and impact conditions, also contribute to the launch and trajectory of the ball. However, when assuming an on-plane swing and eliminating other factors, adjusting the loft angle of metal woods or hybrids would be the primary characteristic to consider for achieving more playing loft.

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After watching the Ted Talk, there were still a few questions that I had about supermassive black holes. Firstly, I wanted to know more about the event horizon and what it exactly entails. Although the speaker briefly touched upon this subject, I would have appreciated a more in-depth explanation. Additionally, I would have liked to know more about the role of supermassive black holes in the universe.

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Answer:

heyyy

May I Know the full question

a) The relation among the COPHP and COPR for an ideal refrigerator (R) and an ideal heat pump (HP) working with the same temperature range is given as,COPHP = COPR+1 / COPR-1b) The effect of reducing the condenser temperature of a standard vapor compression refrigeration cycle.

while maintaining a constant evaporator temperature, which is not observed is Increase in the amount of heat rejection.c) The chemical symbol for the refrigerant R12 is CHCIF2.d) The option among the following which increases both thermal efficiency and turbine exit steam quality of a steam power (Rankine) cycle is to Increase the maximum cycle temperature.

Open feed water heater, reheater, and superheater are components commonly found in a steam power plant.f) The consequence of adding a regenerator to a Brayton cycle that is not observed is Reduction in the exhaust gas temperature. The other consequences of adding a regenerator to a Brayton cycle are an increase in thermal efficiency, reduction in heat input requirement, and increase in the specific work output.

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Answer:

answer is 4

Explanation:

The charge that is moved is required.

The magnitude of charge moved is option 4. \(2\times 10^{-3}\ \text{C}\)

V = Potential difference = 10.0 V

W = Work done = \(2\times10^{-2}\ \text{J}\)

q = Magnitude of charge

When work done on moving a charge is divided by the potential difference we get the magnitude of the charge that is moved.

The charge of an object is the result of an excess or a lack of positive or negative charges on a body.

So, the magnitude of charge is given by

\(q=\dfrac{W}{V}\\\Rightarrow q=\dfrac{2\times 10^{-2}}{10}\\\Rightarrow q=2\times 10^{-3}\ \text{C}\)

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The number of choices you have in this scenario is equal to the number of available quantities for each fruit.

If the number of pears you buy must be equal to the number of bananas you buy, then the choices you have will be limited. Let's say there are n available quantities for each fruit. In this case, you will have n choices because for each possible quantity of pears, there is only one corresponding quantity of bananas that you can buy to maintain the equal count.

For example, if there are 3 available quantities for each fruit (n = 3), your choices could be:

Buy 1 pear and 1 banana

Buy 2 pears and 2 bananas

Buy 3 pears and 3 bananas

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Answer:

KE (5) = 1/2 M V^2 = 25/2 M

KE (10) = 1/2 M V^2 = 100/2 M

KE (10) - KE (5) = M/2 (100 - 25) = 75/2 / M

An object traveling at 10 m/s has 4 times the kinetic energy as an object traveling at 5 m/s

Total work would depend on the mass being accelerated

Answer:

hmmmm

Explanation:

Question :-

Answer :-

Explanation :-

As per the provided information in the given question, we have been given that the Current of the Device is 3.0 Ampere . The Resistance is given as 6.0 Ohm's . And, we have been asked to calculate the Potential Difference .

As we know ,

Where ,

Therefore , by Substituting the given values in the above Formula :-

\( \sf {\dag \: \: \: Potential \: Difference \: = \: Current \: \times \: Resistance} \)

\( \sf {\Longrightarrow \: \: \: \sf Potential \: Difference \: = \: 3.0 \: \times \: 6.0} \)

\( \sf {\Longrightarrow \: \: \: \sf Potential \: Difference \: = \: 3 \: \times \: 6} \)

\( \bf {\Longrightarrow \: \: \: \bf {Potential \: Difference \: = \: 18 \: }} \)

Hence :-

\( \underline {\rule {210pt}{4pt}} \)

Additional Information :-

\( \Longrightarrow \: \: \: \sf {Voltage \: = \: Current \: \times \: Resistance} \)

\(\Longrightarrow \: \: \: \sf {Current \: = \: \dfrac {Voltage}{Resistance} } \)

\(\Longrightarrow \: \: \: \sf {Resistance \: = \: \dfrac {Voltage}{Current} } \)

\( \underline {\rule {210pt}{4pt}} \)

Note :-

The points about the stars from the appendix are: Sirius A is the most luminous star within 12 parsecs. It is also the brightest star in our sky, even though it is not the closest. The list of the brightest stars will include the very luminous hot stars from distances greater than 12 light-years, while the list of the fainter yet closer low-mass stars will not.

The list of stars within 12 light-years is volume-limited, which means that almost all of the stars within that distance are listed regardless of luminosity. Such a list is a better representative of the total population of stars and is more plausible to be dominated by low-mass stars. The list of brightest stars includes only those stars that are above a certain apparent brightness threshold.

Therefore, the faintest nearby stars are excluded, but the brightest and rarer hot stars are included in higher proportion than they are in a volume-limited list.

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Answer:

mg i would say an atomic number of 12 the um i would say stands for micrometer

Explanation:

The angular momentum of a rotating turntable with initial angular speed 9.8 rad/s and mass 24 kg, changes when a clay mass of 9.3 kg is dropped and sticks at a point 1.8 m away. The final angular speed of the turntable and clay together is 8.11 rad/s.

We can use the conservation of angular momentum to solve this problem. Initially, the turntable is rotating with an angular speed of 9.8 rad/s, and after the clay is dropped, the angular momentum of the system is conserved.

The initial angular momentum of the turntable is

L1 = I1 * ω1

where I1 is the moment of inertia of the turntable and ω1 is the initial angular speed. The moment of inertia of a thin cylindrical disk is given by

I1 = (1/2) * M * R²

where M is the mass of the turntable and R is its radius. Substituting the given values, we get

I1 = (1/2) * 24 kg * (3.1 m)² = 114.48 kg m²

Therefore,

L1 = 114.48 kg m² * 9.8 rad/s = 1123.90 kg m²/s

After the clay is dropped, the system consists of the turntable and the clay rotating together.

The moment of inertia of the system can be found using the parallel axis theorem, which states that the moment of inertia of a body rotating about an axis is equal to the moment of inertia of the body about its center of mass plus the product of its mass and the square of the distance between the two axes

I2 = I1 + M * d²

where d is the distance between the point of rotation and the point where the clay sticks. Substituting the given values, we get

I2 = 114.48 kg m² + 9.3 kg * (1.8 m)² = 138.58 kg m²

The final angular speed of the system can be found by equating the initial and final angular momentum

L1 = L2

where L2 is the final angular momentum of the system. The final angular momentum of the system is

L2 = I2 * ω2

where ω2 is the final angular speed of the system. Solving for ω2, we get

ω2 = L1 / I2 = 1123.90 kg m²/s / 138.58 kg m² = 8.11 rad/s

Therefore, the final angular speed of the turntable and the clay together is 8.11 rad/s.

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The phenomenon bending of a wave as it crosses from one medium to another is said to be refraction. The speeds of light in the water will be 2.25×10⁸ m/sec.

The phenomenon bending of a wave as it crosses from one medium to another is said to be refraction. The difference in density is the cause of the bending.

Refraction is a term that is used to describe the phenomenon of refraction."The change in direction of a wave traveling through one medium to another is known as refraction."

The following data are given in the problem;

C is the Speed of light in a vacuum =3×10⁸ m/sec.

n is an index of refraction for water = 1.333

v is the speed of light in the water=?

The index of refraction is the ratio of the speed of light in a vacuum to the speed of light in water. By the formula of the index of refraction.

\(\rm n=\frac{C}{V} \\\\ \rm V=\frac{C}{n}\\\\ \rm V=\frac{3\times10^8}{1.333}\\\\\ \rm V=225056264.1\;m/sec.\\\\\rm V=2.25\times10^8\;m/sec.\)

Hence the speed of light in the water will be 2.25×10⁸ m/sec.

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The phenomenon bending of a wave as it crosses from one medium to another is said to be refraction. The speeds of light in the water will be 2.25×10⁸ m/sec.

The phenomenon bending of a wave as it crosses from one medium to another is said to be refraction. The difference in density is the cause of the bending.

Refraction is a term that is used to describe the phenomenon of refraction."The change in direction of a wave traveling through one medium to another is known as refraction."

The following data are given in the problem;

C is the Speed of light in a vacuum =3×10⁸ m/sec.

n is an index of refraction for water = 1.333

v is the speed of light in the water=?

The index of refraction is the ratio of the speed of light in a vacuum to the speed of light in water. By the formula of the index of refraction.

\(n=\dfrac{c}{v}\)

\(V=\dfrac{c}{n}\)

\(V=\dfrac{3\times10^8}{1.333}\)

\(V=2.25\times 10^8 m/s\)

Hence the speed of light in the water will be 2.25×10⁸ m/sec.

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We can see here completing the sentences, we have:

Right now, my biggest challenge in developing information literacy is understanding how to effectively evaluate sources for accuracy and reliability.

I'll know that I've overcome this challenge when I am able to confidently and consistently identify trustworthy sources of information and explain my reasoning for doing so.

Information literacy refers to the ability to identify, locate, evaluate, and effectively use information from a variety of sources. It involves a set of skills and competencies that enable individuals to effectively navigate the vast amounts of information available in today's digital age.

Continuation:

By the time I finish this course, I intend for my score on the Information Literacy section of the Discovery Wheel to be significantly higher than it is currently.

To overcome my biggest challenge in developing information literacy, I will practice evaluating sources regularly and seek feedback from peers and instructors.

To act on my intentions, I will adopt the following habits: regularly fact-checking information before accepting it as true, seeking out multiple sources to corroborate information, and utilizing critical thinking skills to evaluate the credibility of sources.

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The water can be raised to a height of approximately 15.7 m above the water surface at point A.

To solve this problem, we need to use the principles of fluid mechanics, specifically the Bernoulli's equation and the continuity equation.

A1v1 = A2v2

We know that the diameter of the 8.0 in. pipe is 8 in. = 0.6667 ft, so its cross-sectional area is:

A1 = \(π/4 x (0.6667 ft)^2 = 0.349 ft^2\)

Similarly,

A2 = \(π/4 x (0.3333 ft)^2 = 0.0873 ft^2\)

v1 = (A2v2)/A1 = \((0.0873 ft^2 x 12 ft/s)/0.349 ft^2\) = 2.39 ft/s

Next, we can use the Bernoulli's equation between points A and C to relate the pressure difference to the velocity difference:

P/ρ +\(v^2/2g\) + h = constant

h = (P/ρ - Patm)/g + z

We are given that the pump delivers 25 hp with 60% efficiency, so the power input to the pump is:

Pin = 25 hp/0.6 = 41.7 hp = 31.1 kW

Pin = QP/η

The volumetric flow rate can be calculated from the continuity equation:

Q = A1v1 = \(0.349 ft^2 x 2.39 ft/s = 0.834 ft^3/s\)

Substituting this into the above equation, we get:

P = Pinη/Q = \((31.1 kW x 0.6)/0.834 ft^3/s\) = 1773 Pa

Finally, we can substitute the known values into the Bernoulli's equation:

h = \((P/ρ - Patm)/g + z = (1773 Pa/1000 kg/m^3 - 101325 Pa)/9.81 m/s^2 + 0 m\)

h ≈ 15.7 m

Therefore, the water can be raised to a height of approximately 15.7 m above the water surface at point A.

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Matt's speed is 10 meters per second. Matt's speed can be calculated by dividing the distance he traveled by the time it took him to travel that distance.

In this case, Matt traveled 250 meters in 25 seconds, so his speed is:

Speed = distance / time
Speed = 250 meters / 25 seconds
Speed = 10 meters per second

Therefore, Matt's speed is 10 meters per second.

In HTML format:

Matt's speed can be calculated by dividing the distance he traveled by the time it took him to travel that distance. In this case, Matt traveled 250 meters in 25 seconds, so his speed is:

Speed = distance / time

Speed = 250 meters / 25 seconds

Speed = 10 meters per second

Therefore, Matt's speed is 10 meters per second.

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Answer:

kinetic energy

Explanation:

Answer:

5 years

Explanation:

\(\frac{1}{8}(40)\\\\= 5\)

The statement accurately describes the motion of the object in the graph above is from 2s to 6s, the object is moving at 1.5 cm/s.

option D is the correct answer

A speed time graph is a graph that shows the motion of an object against time. They can also be referred to as velocity-time graphs.

The motion of the object in the graph above can be described as follows;

between 0 to 2 seconds, the speed of the object = 0 cm/s

between 2 to 6 seconds, the speed of the object = 1.5 cm/s

between 6 to 8 seconds, the speed of the object = 0 cm/s

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Answer:

To obtain the thickness of the solid by dividing its volume by its length and its width

Explanation:

Example:

we divide 24 cm3 by 4 cm and 3 cm. In this example, the thickness of the solid is 2 cm. (NOT THE ANSWER! JUST AN EXAMPLE)

I hope this helps =)

Answer:

what is the answers? so i can't answer.

Explanation:

The statement that is true as regards movement of the box when pushed horizontally with constant velocity is given by;

Option D; The friction is equal to the applied force

The missing options are;

a) The friction is less than the applied force

b) There is no friction acting on the box

c) The friction is greater than the applied force

d) The friction is equal to the applied force

Now, if the frictional force was less than the applied force, it means the velocity of the box will gradually be increasing but we are told the velocity is constant.

Finally, if the frictional force is equal to the applied force, then the box will move with a constant motion.

Thus, in conclusion the friction is equal to the applied force.

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