calculate the initial concentration of s2o82- and i- ions in experiments 1, 2, and 3. use the dilution formula m1 x v1

Answer:

Lithium

Explanation:

it is the only metal listed.

The question requires us to choose the best option to explain why bubbles rise faster from a warm can of soda than a cold can, based on the solubility of gases in liquids.

Adding heat to a solution composed of a liquid and a gas (i.e., increasing its temperature) provides thermal energy to the gas that makes it possible to overcome the forces that maintain molecules of solvent (liquid) and solute (gas) together. In this way, the molecules of solvent and solute tend to separate, therefore decreasing the solubility of the gas. Based on this, we can say that the solubility of gases in liquids increase with increasing temperature.

Therefore, the best option to answer the question is the first one, "gases become less soluble in liquids at higher temperatures".

The final temperature of the air after compression is approximately 552.67 K.

To determine the final temperature of the air when it is compressed in a car engine from 22 °C and 95 kPa in a reversible and adiabatic manner with a compression ratio \(V_1/V_2\)of 8, we need to consider the following assumptions:

1. The compression process is reversible and adiabatic. This means there is no heat transfer to or from the system and the process is carried out with no entropy generation.
2. The air is an ideal gas. This implies that the air obeys the ideal gas law (PV = nRT) and its properties depend only on temperature.
3. The specific heat capacities of air (cv,air and cp,air) and the adiabatic index (kair) are constant during the compression process.
4. The molar mass of air (Mair) is provided and constant.

Given the information and assumptions, we can use the adiabatic relation for ideal gases to calculate the final temperature ( \(T_2\)) of the air:

\(T_2\) =  \(T_1\) ×\((V_1/V_2)^(k_a_i_r_ -_1)\)
Where:
\(T_1\) = Initial temperature = 22 °C = 295.15 K (converting to Kelvin)
\(V_1/V_2\)= Compression ratio = 8
kair = Adiabatic index = 1.4

Now, calculate \(T_2\):

\(T_2\) = 295.15 × \((8)^(^1^.^4 ^- ^1^)\)
\(T_2\) = 295.15×\((8)^0^.^4\)
\(T_2\) ≈ 552.67 K

Therefore, The final temperature of the air after compression is approximately 552.67 K.

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The number of mole of water, H₂O present, given that 2.43 g of H₂O was vaporized is 0.13 mole

From the above question, the following parameters were obtained:

Mole and mass of a substance are related by the following formula:

Mole = mass / molar mass

Inputting the given parameters, we can obtain the mole of water, H₂O as follow:

Mole of water, H₂O = 2.43/ 18.02

Mole of water, H₂O = 0.13 mole

Thus, we can say that the mole of water, H₂O present is 0.13 mole

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Answer:

The atomic number is specific to an element, and the element with atomic number 7 is Nitrogen.

Atomic number is equal to the number of protons or number of electrons for aa neutral atom.

Mass number is the sum of number of neutrons and number of protons.

Atomic mass is the sum of masses of all protons and neutrons.

Protons and neutrons are located in the nucleus. Electrons are located outside the nucleus in the shells.

atomic number = Number of protons =  number of electrons = 7

Mass number =  number of neutrons + number of protons  = 14

Number of neutrons = Mass number - number of protons = 14 - 7= 7

Answer:

It contains seven protons in the nucleus.

It contains seven neutrons in the nucleus.

It contains seven electrons in orbitals around the nucleus.

Its atomic number is its number of protons.

Its atomic mass is the mass of protons and neutrons.

Explanation:

on edg 2021

Answer: sodium sulfide

The precipitate that forms when aqueous solutions of barium nitrate and sodium sulfate are mixed is barium sulphate.

Barium Nitrate is a colorless to white, odorless, crystalline powder. It is used in making fireworks, for green lights and neon lights, and in ceramic glazes.

Sodium Sulfate Anhydrous is the anhydrous, sodium salt form of sulfuric acid. Sodium ion is the principal cation of the extracellular fluid and plays a large part in the therapy of fluid and electrolyte disturbances.

When aqueous solutions of barium nitrate and sodium sulfate are mixed is barium sulphate, one soluble salt, sodium nitrate, and an insoluble salt, barium sulphate.

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Answer:

0.68 centiseconds

Explanation:

I looked it up

Answer:

The person above is correct 6800 converted to centiseconds is .68

Explanation:

you have to divide x by 10000 to convert it into centiseconds

in this case x=6800

6800÷10000= 0.68

The molarity of the solution is approximately 5.0 M.

To calculate the molarity (M) of a solution, we need to divide the moles of solute by the volume of the solution in liters.

First, we need to convert the mass of NaOH to moles. The molar mass of NaOH is 22.99 g/mol for Na, 16.00 g/mol for O, and 1.01 g/mol for H, giving us a total molar mass of 39.99 g/mol for NaOH.

Moles of NaOH = 120.0 g / 39.99 g/mol

= 3.00 mol

Next, we divide the moles of NaOH by the volume of the solution in liters:

Molarity (M) = moles of solute / volume of solution in liters

M = 3.00 mol / 9.60 L

= 0.3125 M

Rounding to the appropriate number of significant figures, the molarity of the solution is approximately 5.0 M.

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A balanced chemical equation for the combustion of gaseous methanol is:2CH3OH (g) + 3O2 (g) → 2CO2 (g) + 4H2O(g).

Bond energy in C-H bonds is equal to 413 kJ/mol. Bond energy in O-H bonds is equal to 463 kJ/mol.Let us use Hess’s Law for the calculation of enthalpy of reaction.

The enthalpy of combustion of methanol can be given as follows: H = [2 × BE(C=O)] + [4 × BE(O-H)] - [2 × BE(C-H)] - [3 × BE(O=O)]Here, BE stands for bond energy. H = [2 × 799 kJ/mol] + [4 × 463 kJ/mol] - [2 × 413 kJ/mol] - [3 × 498 kJ/mol]H = -726 kJ/mol Thus, the enthalpy of combustion of methanol is -726 kJ/mol.

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The amount of oxygen that would be produced will be 76.38 grams

From the equation of the reaction, the mole ratio of KCIO3 to O2 is 2:3. That is, for every one mole of KCIO3 that decomposes, 1.5 moles of oxygen is produced.

Mole of 195 grams KCIO3 = 195/122.55

                                            = 1.59 moles

Equivalent mole of O2 = 1.59 x 3/2

                                     = 2.39 moles

Mass of 2.39 moles oxygen = 2.39 x 32

                                               = 76.38 grams

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Carbon electrodes are changed frequently in electrolysis as the carbon in the carbon electrodes burns to give out Carbon-di-oxide.

Carbon electrodes are used in electrolysis to facilitate the transfer of electrons between the anode and the cathode. The carbon electrode is usually in the form of a rod or plate and is electrically connected to the anode.

The carbon electrode may also be used to help reduce the overall resistance of the electrolytic cell.

Carbon electrodes are used in electrolysis because they are chemically inert and have a high electrical conductivity.

However, carbon electrodes must be changed frequently because they become corroded and lose their electrical conductivity over time.

This is because carbon burns out in the Carbon electrodes to give out Carbon-di-oxide. That is why the carbon anodes should be changed frequently.

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Answer: \(1.6\times 10^4\)

Explanation:

Scientific notation is defined as the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

For example : 5000 is written as \(5.0\times 10^3\)

In division , the result would contain the same number of significant digits as there in the least precise number , thus the answer would have 2 significant digits.

\(\frac{1.248\times 10^{-2}}{7.8\times 10^{-7}}=1.6\times 10^4\)

Answer:

The chemical properties that make up paper are flammability, non flammability, decomposition, lack of decomposition at high temperatures.

Physical properties of paper sheets are determined by basis weight, thickness, density, two-sidedness, smoothness, permeability, handle, rigidity, roughness, and porosity, which in turn affect sheet properties of softness, hardness, compressibility, dimensional stability, curl, and strength

Explanation:

Answer:

(a) The arrangement of metals in a vertical column in the order of decreasing reactivities is called reactivity series. The reactivity series follows the order:

Answer:

0.00944

Explanation:

Xenon mass number on the periodic table: 131.29

Oxygen mass number: 16.00

Add them to find the molar mass of xenon trioxide: 131.29+3(16) = 179.29g/mol

Convert this to moles

\(1.69g * \frac{mol}{179.29g} = 0.00944mol\)

If a solid crystal of KHP (potassium hydrogen phthalate) is accidentally pipetted and goes unnoticed throughout titrations, the Ksp value (solubility product constant) would be artificially higher than the true value.

In a titration experiment, the concentration of dissolved KHP is determined by titrating it with a strong base, such as NaOH.

If a solid crystal of KHP is accidentally pipetted, it will eventually dissolve, increasing the concentration of KHP in the solution.

This higher concentration will then require more titrant (NaOH) to reach the endpoint of the titration. As a result, the calculated Ksp value will be higher than the actual Ksp value of KHP, because it will be based on an artificially increased concentration.
In summary, the accidental inclusion of a solid KHP crystal during titration will lead to an overestimation of the Ksp value. To obtain accurate results, it is essential to ensure that no solid crystals are present in the solution before beginning the titration process.

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Hello..!

¿What is Ecosistema Lentico?

It is one that presents a closed structure and that its waters are permanently stagnant.

Are:

Answer:B is the right answer

Explanation:

We'll begin by calculating the mass in ounce (oz) of a cube foot (ft³) of gold. This can be obtained as follow:

Density of gold = 19298 oz/ft³

Volume of gold = 1 ft³

Density = mass /volume

19298 = mass / 1

Finally, we shall determine the cost of 19298 oz of gold. This can be obtained as follow:

1 oz = $ 1600

Therefore,

19298 oz = 19298 × 1600

19298 oz = $ 30876800

Therefore, a solid cube foot of gold (i.e 19298 oz) will cost $ 30876800

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The volume of the second vessel is approximately 322.7 mL.

To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:

(P₁ × V₁)/T₁ = (P₂ × V₂)/T₂

where P₁, V₁, and T₁ are the initial pressure, volume, and temperature, respectively, and P₂ and V₂ are the final pressure and volume, respectively.

First, we need to convert the temperatures to Kelvin, which is done by adding 273.15 to the Celsius temperature:

T₁ = 40.0 + 273.15 = 313.15 K

T₂ = 0.0 + 273.15 = 273.15 K

Next, we can plug in the given values and solve for V₂:

(P₁ × V₁)/T₁ = (P₂ × V₂)/T₂

(895 torr × 550.0 mL)/313.15 K = (745 torr × V₂)/273.15 K

Simplifying and solving for V₂, we get:

V₂ = (745 torr × 550.0 mL × 313.15 K) / (895 torr × 273.15 K)

≈ 322.7 mL

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The IUPAC name for the compound H₃C-CH₂-CH-CH₂ is 3-methylbutane.

Let's break down the naming process step by step :

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The reaction is an oxidation-reduction reaction because here Sodium is oxidized from Na to Na⁺ while hydrogen is reduced from H⁺ to H₂⁰.

The reaction below: 3Na(s) + 3H₂O(l)= 3NaOH(aq) + H₂(g)

1. The reaction is an oxidation-reduction reaction because here Sodium is oxidized from Na to Na⁺ while hydrogen is reduced from H⁺ to H₂⁰.

2.  The substances oxidized are Na and reduced. is H⁺.

3. The reducing agent is Na and the oxidizing agent is H₂O.

4.  half ionic equation for the oxidation

  Na => Na⁺ + e⁻

The half ionic equation for the reduction equation.

H₂O + e⁻ => H₂

An oxidation-reduction reaction is any chemical response in which the oxidation number of a molecule, atom, or ion changes by way of gaining or losing an electron. Redox reactions are common and crucial to some of the basic features of lifestyles, such as photosynthesis, respiration, combustion, and corrosion or rusting.

Oxidation is a chemical procedure. it is defined as a method that occurs whilst atoms or agencies of atoms lose electrons. some other manner to define oxidation is when a chemical species gains oxygen or loses hydrogen. whilst these activities occur, oxidation takes area.

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The respective concentrations (m) of K+ and PO43- afforded by dissolving 0.800 mol K3PO4 in water and diluting to 1.63 L are 0.489 M and 0.491 M, respectively.

To determine the concentrations of K+ and PO43- ions in the solution, we need to consider the stoichiometry of the K3PO4 compound. K3PO4 dissociates into three K+ ions and one PO43- ion in solution.

Given:

Amount of K3PO4 dissolved = 0.800 mol

Volume of solution after dilution = 1.63 L

First, we need to find the molar concentration of K3PO4 in the diluted solution:

Concentration of K3PO4 (m) = moles of K3PO4 / volume of solution

Concentration of K3PO4 (m) = 0.800 mol / 1.63 L ≈ 0.491 M

Since there are three K+ ions for every one K3PO4 molecule, the concentration of K+ ions will be three times the concentration of K3PO4:

Concentration of K+ (m) = 3 * Concentration of K3PO4

Concentration of K+ (m) = 3 * 0.491 M ≈ 1.473 M ≈ 0.489 M (rounded to three decimal places)

The concentration of PO43- ions will be the same as the concentration of K3PO4:

Concentration of PO43- (m) = Concentration of K3PO4

Concentration of PO43- (m) = 0.491 M

Therefore, the respective concentrations (m) of K+ and PO43- ions in the solution are approximately 0.489 M and 0.491 M, respectively. The correct answer choice is "0.489 and 0.491."

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Heat is released during a strong reaction between sulfuric acid, alcohol, and water.

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CuSO4 + 2 NaOH = Na2SO4 + Cu(OH)2 is well balanced

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Actually Welcome to the Concept of the Acceleration.

a = V2-V1/t

so the correct answer is, a = ∆v/t

option C.) is correct, a = ∆v/t

Answer:

m = y2-y1 / x2-x1

Explanation: