Calculate the heat energy conducted per hour through the side walls of a cylindrical steel
boiler of 1.00 m diameter and 3.0 m long if the internal and external temperatures of the
walls are 140 °C and 40 °C respectively and the thickness of the walls is 6.0 mm. (Thermal
conductivity of steel, k = 42 Wm-4°C-4)

Answer:

10s

Explanation:

Horizontal velocity is the velocity of an object in an horizontal direction

The ball's horizontal velocity is approximately 33.078 ft./s

Reason:

The known parameter are;

The horizontal distance the footballer kicks the ball, d = 43 yards

The time after which the ball lands, Δt = 3.9 seconds

Required:

To find the velocity of the ball

Solution:

\(Velocity = \dfrac{Distance}{Time} = \dfrac{d}{\Delta t}\)

Therefore;

\(Horizontal \ velocity \ of \ the \ ball, \ v_x= \dfrac{43 \ yard}{3.9 \ seconds} \approx 11.026 \ yd/s\)

The ball's horizontal velocity, vₓ ≈ 11.026 yd/s

1 yard = 3 feet

\(11.026 \ yard = 11.026 \ yard \times \dfrac{3 \ feet}{yard} = 22.078 \ feet\)

The ball's horizontal velocity, vₓ ≈ 33.078 ft./s

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Compared with the car, the truck will travel four times as far.

The initial velocity of car and truck, u = 0

The acceleration of both the truck and car = a

The length of time for the acceleration = t

Let the time the truck accelerated be 2t

The distance traveled by car is calculated as;

s = ut + ¹/₂at²

s₁ = 0(t) + ¹/₂at²

s₁ = ¹/₂at²

The distance traveled by truck

s = ut + ¹/₂at²

s₂ = 0(2t) + ¹/₂a (2t)²

s₂ =  ¹/₂a x 4t²

s₂ = 4 (¹/₂at²)

s₂ = 4(s₁)

We can conclude that the Truck distance is four times the car distance.

Therefore, Compared with the car, the truck will travel four times as far.

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Answer:

See the answers below.

Explanation:

We can solve both problems using Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F =m*a

where:

F = force [N] (units of newtons)

m = mass = 1000 [kg]

a = acceleration = 3 [m/s²]

\(F = 1000*3\\F=3000[N]\)

And the weight of any body can be calculated by means of the mass product by gravitational acceleration.

\(W=m*g\\W=1000*9.81\\W=9810 [N]\)

Answer:

D

Explanation:

In a series circuit there is only one path for the current to complete the path....so D

A terminating decimal is a decimal that has a finite amount of decimal places.

For example, 1/4 is equal to 0.25, so it's a terminating decimal.

On the other hand, 1/3 is equal to 0.333..., so it is not a terminating decimal.

Looking at the options, the only one that represents a terminating decimal is option C.

(3/10 = 0.3)

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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The magnitude of the potential difference between the spheres is 1.06 × 105 V. The final charge on the smaller sphere is 11.97 × 10-6 C and on the larger sphere is 9.03 × 10-6 C.

(a) ΔV = VR - Vr
where VR and Vr are the potentials at the surfaces of the larger and smaller spheres, respectively.

We can use the formula for the potential of a point charge to find the potentials at the surfaces of the spheres:
VR = (kQ)/R
Vr = (kq)/r
where k is the Coulomb constant.

Substituting the given values for Q, q, R, and r, we get:
VR = (k × 16 × 10-6 C)/(6.0 × 10-2 m)
Vr = (k × 5.0 × 10-6 C)/(3.4 × 10-2 m)

Therefore, the magnitude of the potential difference between the spheres is:
ΔV = (k × 16 × 10-6 C)/(6.0 × 10-2 m) - (k × 5.0 × 10-6 C)/(3.4 × 10-2 m)
ΔV = (8.89 × 109 N·m2/C2 × 16 × 10-6 C)/(6.0 × 10-2 m) - (8.89 × 109 N·m2/C2 × 5.0 × 10-6 C)/(3.4 × 10-2 m)
ΔV = 2.37 × 105 V - 1.31 × 105 V
ΔV = 1.06 × 105 V

(b) If we connect the spheres with a wire, the charges will redistribute until the potential difference between the spheres is zero. This means that the final charge on the smaller sphere, 11.97 × 10-6 C, will be given by:
qf = (r/R) × (Q + q)

Substituting the given values for Q, q, R, and r, we get:
qf = (3.4 × 10-2 m)/(6.0 × 10-2 m) × (16 × 10-6 C + 5.0 × 10-6 C)
qf = 0.57 × 21 × 10-6 C
qf = 11.97 × 10-6 C

(c) The final charge on the larger sphere, 9.03 × 10-6 C, will be the difference between the initial total charge and the final charge on the smaller sphere:
Qf = (Q + q) - qf

Substituting the values for Q, q, and qf, we get:
Qf = (16 × 10-6 C + 5.0 × 10-6 C) - 11.97 × 10-6 C
Qf = 9.03 × 10-6 C

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Answer:

what

Explanation:

what I dont get it??

Answer:

that makes me confused I don't think of pizza the same again LOL

Answer:

1. The expansion rate of the universe, often measured using the Hubble Constant.

2. The cooling of the cosmic microwave background radiation.

3. The chemical abundances of light elements like helium and deuterium.

4. The abundance of elements heavier than hydrogen and helium created by stellar nucleosynthesis.

5. The redshift of galaxies and other distant objects.

Explanation:

Answer:

Im pretty sure its 7.5

Explanation:

your initial ( starting) velocity was 75. Your final velocity was 0. 75 / 0 = 0 m/s.

BUT you are calculating your acceleration, so it would be 75 - 0 divided by 10 = 7.5

The speed of the two carts after the collision is 10 m/s.

What is momentum?

Momentum is a measure of an object's motion and is defined as the product of an object's mass and velocity. The SI unit of momentum is kilogram-meters per second (kg m/s).

In physics, momentum is an important concept in the study of motion and is related to the forces acting on an object. According to Newton's second law of motion, the momentum of an object changes when a force is applied to the object. The magnitude of the change in momentum is proportional to the size of the force and the time over which it is applied.

In collisions and other interactions between objects, the total momentum of the system is conserved, meaning that the total momentum before the interaction is equal to the total momentum after the interaction.

initial momentum = mA · vA1 + mB · vB1

final momentum = (mA + mB) · vAB2

Where:

mA = mass of cart A = 0.500 kg

vA1 = velocity of cart A before the collision = 100 m/s

mB = mass of cart B = 1.50 kg.

vB1 = velocity of cart B before the collision = - 20 m/s

vAB2 = velocity of the carts that move as a single object = unknown.

(notice that we have considered leftward as negative direction)

Since the momentum of system remains constant:

initial momentum = final momentum

mA · vA1 + mB · vB1 = (mA + mB) · vAB2

Solving for vAB2:

(mA · vA1 + mB · vB1) / (mA + mB) = vAB2

(0.500 kg · 100 m/s - 1.50 kg · 20 m/s) / (0.500 kg + 1.50 kg) = vAB2

vAB2 = 10 m/s

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The specific heat capacity of the alcohol will be 3.72  kJ/kg°C.

The amount of heat required to increase a substance's temperature by one degree Celsius is known as its "specific heat capacity."

Similarly, heat capacity is the relationship between the amount of energy delivered to a substance and the increase in temperature that results.

Given data;

Mass of liquid sample of Alcohol  m₁ = 200-gram

The temperature of alcohol, T₁ =  -6°C.

Mass of liquid sample of water  m₂ = 400-gram

The temperature of the water, T₂=  20°C.

The specific heat capacity of the alcohol, S₁=?

The specific heat capacity of water is, S₂=4.19 kJ/kg.°C

As we know that;

\(\rm Q_{gain}= Q{loss} \\\\ Q_{alcohol} =Q_{water} \\\\\ m_1s_1\triangle T_1 = m_2S_2 \triangle S_2 \\\\ 200 \times 10^{-3} \times S_1 [ (12-(-6) ] = 40 \times 10^{-3} \times 4.19 \times 10^{-3} \times (20-12)\\\\S_1 = 2 \times 4.19 \times 10^3 \times \frac {8}{18} \\\\ S_1 = 3.72 \ kJ /kg ^0 C\)

Hence the specific heat capacity of the alcohol will be 3.72  kJ/kg°C.

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a. the landing ramp should be placed at 276.298 ft horizontally from the launch point.

(b) the angle of the landing ramp is 30°.

(a)

Launch speed = 55.0 mph * (1.467 ft/s)

= 80.685 ft/s

Horizontal distance = Launch speed * Time of flight

Vertical velocity = Launch speed * sin(30.0°)

Time to reach maximum height = Vertical velocity / g

Vertical distance = (1/2) *g * t²

and Time = √(2 * Vertical distance / g)

Total time of flight = 2 * Time to reach maximum height + Time for descent

Horizontal distance = Launch speed * Total time of flight

The Vertical velocity = 80.685 ft/s * sin(30.0°)

= 40.3425 ft/s

Time to reach maximum height = 40.3425 ft/s / 32.2 ft/s²

Time to reach maximum height  = 1.253 s

Time of descent = √(2 * 25.0 ft / 32.2 ft/s²)

Time of descent  = 0.913 s

Total time of flight = 2 * 1.253 s + 0.913 s

Total time of flight = 3.419 s

In conclusion, the horizontal distance = 80.685 ft/s * 3.419 s

horizontal distance = 276.298 ft

b.

the angle of the landing ramp is  30.0 be the same as the launch angle.

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a) To determine if the car will hit the object before coming to a stop, we need to calculate the distance required to stop the car, assuming maximum braking deceleration. We can use the following formula:

d = (v^2) / (2a)

where:

d = distance required to stop

v = initial velocity

a = acceleration/deceleration

In this case, v = 100 km/h = 27.78 m/s (converted from km/h to m/s)

a = -7 m/s^2 (negative sign indicates deceleration)

We know that the car's headlights extend out to a range of 30 m, so if the distance required to stop the car is greater than 30 m, the car will hit the object before coming to a stop.

Plugging in the values to the formula, we get:

d = (27.78^2) / (2 x -7) = 108.61 m

Since 108.61 m is greater than 30 m, the car will hit the object before coming to a stop.

b) To calculate the time required to stop, we can use the following formula:

t = v / a

where:

t = time required to stop

v = initial velocity

a = acceleration/deceleration

Plugging in the values, we get:

t = 27.78 / 7 = 3.97 s

Therefore, it will take 3.97 seconds to stop the car.

Answer:

Ejejen2iwj2iwn3bsbwisb3ibsisnisisje

To solve this we are going to use the angular momentum, to calculate de distance of the red spot. The momentum is not going to change, so the initial total momentum has to be the same as the final total momentum

Both momentums are the same, so now we can equal both expressions

Answer:

False

Explanation:

A land breeze is when air flows from land to water. The question above is describing a sea breeze, which is when cool ocean air blows toward land.

If the net work done on a particle is zero, the particle will move with a constant speed.

The principle of work and kinetic energy, often known as the work-energy theorem, states that the change in kinetic energy of a particle is equal to the sum of the entire work done by all of the forces acting on it.

So,

W = ΔKE

Thus, we can say that the kinetic energy of the particle will not change if the net work done on it is equal to zero.

As a result, the state of motion of the particle will not change, and thus the speed of the particle will also remain constant.

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Answer:

Explanation:

if he is moving at a constant velocity, the work changes the potential energy

W = PE = mgh = 80(9.8)(5) = 3,920 J

Power is the rate of doing work

P = W/t = 3920/10 = 392 W(atts)

Explanation:

Environmental science is the pursuit of knowledge about the workings of the environment and our interactions with it. Environmentalism is a social movement dedicated to protecting the natural world. Nature makes resources at similar speeds

The amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

The total capacitance of the circuit is calculated as follows;

Capacitors in series;

1/Ct = 1/8 + 1/7.5

1/Ct = 0.25833

Ct = 3.87 mF

Capacitors is parallel;

Ct = 3.87 mF + 12 mF + 15 mF

Ct = 30.87 mF

Ct = 0.03087 F

Q = CV

Q = 0.03087 x 12

Q = 0.37 C

Thus, the amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

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The forces F3 and F6 form a couple since they are parallel, act in the same directions, and have the same magnitude (both are 3N), but they do not have the same point of application.

A couple is a pair of equal but disjointed forces that act in opposite directions and along parallel lines of force.

The rigid body rotates about its center of mass as a result of the forces acting on it at various places.

We can observe that the forces F3 and F6 in the provided set of forces are parallel, have the same magnitude of 3N, and act in opposite directions.

However, because they are applied to various locations on the rigid body, the body will rotate as a result. The stiff body tends to rotate around its center of mass because of this phenomenon, which is known as a couple.

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The acceleration of the dragster is 2.01 * 10^5 m/s^2

The term acceleration refers to the change in velocity with time. Hence the formula for acceleration is given as;

a = v - u/t

a = acceleration

v = final velocity

u = initial velocity

t = time taken

Now;

v = 100 miles or 160934 meters

u = 0 miles or 0 meters

t = 0.8 seconds

a =  160934 - 0/ 0.8

a = 2.01 * 10^5 m/s^2

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Answer:

Explanation:

 Given data

mass m= 2 kg

radius r= 0.5 m

angular velocity ω= 12 rad/s

distance d= 0.75 m

we know that

\(Force= mass * acceleration\\\ acceleration= w^2r\\\\ Force= m*w^2r\\\\Force =2*12^2*0.5= 144 N\)

we know that torque = F*d= 144*0.75= 108 Nm

The audience for the 9th grade physics MCAS is students in the 9th grade who are taking the Massachusetts Comprehensive Assessment System (MCAS) physics exam.

The exam is designed to assess students' knowledge and skills in physics, and it is used to make decisions about students' placement in courses, graduation requirements, and eligibility for college and career programs.

The 9th grade physics MCAS is a multiple-choice exam that consists of 50 questions. The questions are based on the Massachusetts Curriculum Framework for Science, which outlines the standards that students are expected to meet in physics.

Students who take the 9th grade physics MCAS must score at least proficient in order to meet the state's graduation requirements. Students who score below proficient may be required to take additional courses or remediation.

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The frequency at which the capacitive reactance is 375 ω and the Capacitance of 3.25 μF is 131 s⁻¹.

Capacitance is the ability or capacity of the substance to collect and store electrical energy and the unit of capacitance is Farad (F). Capacitive reactance is the term that measures the opposition to current flow in the AC circuits and the unit of capacitive reactance is the ohm(Ω).

From the given,

The capacitive reactance (Xc) = 375ω

capacitance (C) = 3.25μF

capacitive reactance Xc = 1/(2π×f×C)

Frequency (f) = 1/(2π×Xc×C)

                     = 1/(2×3.14×375×3.25×10⁻⁶)

                     = 131 s⁻¹.

Thus, the frequency of the capacitive reactance is 131 s⁻¹.

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The electric field 0.40 m away from a source charge of 3.00 x 10^-5 C is 1.69 x 10^6 N/C, directed away from the source charge.

The electric field created by a point charge at a distance r from the charge is given by the equation:

E = kQ/r^2

where

E is the electric field in N/C,

k is Coulomb's constant (9.0 x 10^9 N m^2/C^2),

Q is the source charge in Coulombs, and

r is the distance from the source charge in meters.

Substituting the given values into the equation, we get:

E = (9.0 x 10^9 ) x (3.0 x 10^-5) / (0.40)^2

E = 1.69 x 10^6 N/C

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Air can do work when it exerts a force on an object and causes it to undergo displacement. The ability of air to do work is evident in various phenomena, such as wind pushing sails, fans moving objects, and air pressure powering pneumatic systems.

Air can do work through its ability to exert a force over a distance. Work is defined as the transfer of energy that occurs when a force is applied to an object and it undergoes displacement in the direction of the force. When air is in motion, it possesses kinetic energy and can exert a force on objects in its path, thus performing work.

To understand how air can do work, we can consider the example of a moving fan. When a fan is turned on, the blades start to rotate, creating a flow of air. As the air moves, it carries kinetic energy. When the moving air encounters an object, such as a piece of paper, the air molecules collide with the paper's surface and exert a force on it. This force causes the paper to move and displaces it from its initial position.

The work done by the air can be calculated using the equation:

Work = Force * Distance * cos(θ)

Where Force is the magnitude of the force exerted by the air, Distance is the displacement of the object, and θ is the angle between the direction of the force and the displacement.

In the case of air doing work on an object, the force exerted by the air is perpendicular to the direction of motion, resulting in θ = 90 degrees. Since cos(90) = 0, the equation simplifies to:

Work = Force * Distance * 0

Therefore, the work done by the air on the object is zero when the force exerted by the air is perpendicular to the displacement.

However, if the force exerted by the air is not perpendicular to the displacement, such as when blowing air at an angle to move an object, then work is performed. The air exerts a force on the object and causes it to move in the direction of the force, resulting in the transfer of energy.

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Answer:

velocity is the answer of this question.

Answer:

Velocity is the right answer ok