Calculate the final volume (in cm3) of a 40 cm long cylindirical copper rod with a cross-sectional area of
1. 2 cm2 when it is
a) stretched with a load of 4. 0×105 Newtons,
(ν= 0. 32, E= 70 GPa, σy = 300 GPa, σTS= 650 GPa, rCu = 120 pm)
b) Compare the absolute volume change during this process.
c) Assume that the stress is applied along [100] direction. Compute the unit cell parameters (a, b,
and c) during the application of the stress.
2) A cylindirical rod of a length of 22. 4 cm and a radius of 1. 2 cm is deformed plastically when it is pressed
with load of 4. 758×108 Newtons. Calculate the final volume of the specimen after the load is released.
(ν= 0. 32, E= 70 GPa, σy = 300 GPa, σTS= 650 GPa. )
Answers
The final volume (in cm3) of a 40 cm long cylindirical copper rod with a cross-sectional area of\(1.2 cm2\) when it is stretched with a load of\(4.0×105\) Newtons can be calculated using the formula;\(V_f = V_i(1+ε)\)
\(where V_i = initial volume V_f = final volume ε = strain\)
For this case, we have;
\(V_i = l × A = 40 × 1.2 = 48 cm3\)
The tensile strain can be calculated using;
\(ε = σ/E\),
\(whereσ = stressE = Young's modulus For this case, we have\);
\(σ = F/Aσ_y < σ < σ_TS\),
hence;\(σ = σ_y = 300 GPaE = 70 GPaε = σ/E = 300/70 = 4.28 × 10-3V_f = V_i(1+ε) = 48(1+4.28 × 10-3)V_f = 48.21 cm3b)\) Compare the absolute volume change during this process.
To find the absolute volume change, we subtract the initial volume from the final volume.
\(Absolute volume change = V_f - V_i\\Absolute volume change = 48.21 - 48\\Absolute volume change = 0.21 cm3c)\) .
To determine the atomic radius of copper, we use the relationship between the atomic radius, r, and the density, ρ;
\(r = ((3M)/(4πρN_A))^1/3\),
where M is the molar mass of copper, ρ is the density of copper, and N_A is Avogadro's number. For copper,
\(M = 63.55 g/mol,\\ ρ = 8.96 g/cm3\) and
\(N_A = 6.02 × 1023 mol-1;\\r = ((3 × 63.55)/(4 × π × 8.96 × 6.02 × 1023))^1/3\\r = 1.28 × 10-8 cm\)
The unit cell parameters are;
\(a = b = c = 2√2 \\r = 2√2 × 1.28 × 10-8 \\= 3.61 × 10-8 cm2)\)
A cylindrical rod of a length of \(22.4 cm\) and a radius of \(1.2 cm\) is deformed plastically when it is pressed with a load of \(4.758×108 Newtons\).
Therefore, the volume after plastic deformation cannot be calculated using strain.
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Related Questions
A car starts at rest and accelerates at a constant rate for 12 seconds to a speed of 30 m/s. a) What is the acceleration
Answers
Answer:
use the equations of motion
What is one reason scientists have developed a system to classify organisms
Answers
Better identification of novel species is made possible by categorization.
Why would scientists create a system of classification for organisms?Living things are categorised by scientists in order to organise and make sense of the astounding diversity of life. We can better comprehend how different living entities are connected to one another by classifying them.To better comprehend the evolutionary relationships among various creatures, scientists classify organisms according to taxonomy. We may learn the fundamentals about a group of creatures and use that information to our advantage when researching the organism later on by classifying animals that are similar in evolutionary terms.Better identification of novel species is made possible by categorization.To learn more about organisms refer to:
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If a rock is thrown upward on the planet Mars with a velocity of 10 m/s, its height in meters t seconds later is given by y=10t−1.86t2. (a) Find the average velocity over the given time intervals: (i) [1,2] (ii) [1,1.5] (iii) [1,1.1] (iv) [1,1.01] (v) [1,1.001] (b) Estimate the instantaneous velocity when t=1.
Answers
To find the average velocity over the given time intervals, we can use the formula:
Average velocity = (change in position) / (change in time)
(a)
(i) [1,2]:
Change in position = y(2) - y(1) = 10(2) - 1.86(2^2) - (10(1) - 1.86(1^2)) = 20 - 7.44 - 10 + 1.86 = 4.42Change in time = 2 - 1 = 1Average velocity = (4.42) / (1) = 4.42 m/s(ii) [1,1.5]:
Change in position = y(1.5) - y(1) = 10(1.5) - 1.86(1.5^2) - (10(1) - 1.86(1^2)) = 15 - 4.185 - 10 + 1.86 = 2.675Change in time = 1.5 - 1 = 0.5Average velocity = (2.675) / (0.5) = 5.35 m/s(iii) [1,1.1]:
Change in position = y(1.1) - y(1) = 10(1.1) - 1.86(1.1^2) - (10(1) - 1.86(1^2)) = 11 - 2.046 - 10 + 1.86 = 0.814Change in time = 1.1 - 1 = 0.1Average velocity = (0.814) / (0.1) = 8.14 m/s(iv) [1,1.01]:
Change in position = y(1.01) - y(1) = 10(1.01) - 1.86(1.01^2) - (10(1) - 1.86(1^2)) = 10.1 - 1.8686 - 10 + 1.86 = -0.0086Change in time = 1.01 - 1 = 0.01Average velocity = (-0.0086) / (0.01) = -0.86 m/s(v) [1,1.001]:
Change in position = y(1.001) - y(1) = 10(1.001) - 1.86(1.001^2) - (10(1) - 1.86(1^2)) = 10.01 - 1.86006 - 10 + 1.86 = -0.00006Change in time = 1.001 - 1 = 0.001Average velocity = (-0.00006) / (0.001) = -0.06 m/s(b) To estimate the instantaneous velocity when t=1, we can find the derivative of the position function with respect to time and evaluate it at t=1.
y(t) = 10t - 1.86t^2y'(t) = 10 - 3.72tInstantaneous velocity at t=1: y'(1) = 10 - 3.72(1) = 6.28 m/s
About VelocityVelocity is a vector quantity that indicates how fast an object is moving. The magnitude of this vector is called speed and is expressed in meters per second.
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Fill in the blank. When the results of a study can be generalized to other subject populations, the study is said to have _____ validity. A. statistical B. internal C. external D. construct
Answers
When the results of a study can be generalized to other subject populations, the study is said to have external validity. So, option c) is correct.
External validity refers to the extent to which the results of a study can be generalized to other populations, settings, and time periods. In other words, it measures how well the findings of a study can be applied to real-world situations beyond the specific sample used in the study.
It is important to note that external validity is not the same as statistical or internal validity. Statistical validity refers to the accuracy and reliability of the data and statistical analyses, while internal validity refers to the extent to which a study is free from systematic errors or biases.
External validity is crucial in research, as it ensures that the findings of a study are relevant and applicable to a wider range of populations and situations, thus increasing the generalizability and practicality of the study's results.
So, option c) is correct.
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Ill give brainliest! 1. Which item below describes a quick change to
Earth's landscape?
A. a stone becoming smooth
B. dirt moving down a steep hill
C. flat land becoming a canyon
D. a glacier flattening the land below it
Answers
Answer:
hmmmmm
Explanation:
I am gonna say D.
if I am right plz give me a brainliest
Give a reason why radioactive waste is expensive to dispose of safely.
Answers
Answer:
because it takes a lot of recourses and tools to make it no longer radioactive and those recourses and tools are not cheap
Explanation:
Who discovered the comet? describe the type of telescope used? what was the first description of the comet they had found? what were they actually seeing? what did astronomers think they might see prior to the actual impacts? describe what was actually seen by astronomers. For us on earth, what lessons should we learn about this impact?
Answers
In general, comets are often discovered by amateur or professional astronomers using telescopes or other observation equipment. The type of telescope used can vary depending on the observer's preference and the specific requirements of the observation.
When a comet is first discovered, astronomers typically describe its position, brightness, and any visible features such as a tail or coma. They may also use spectroscopy to analyze the composition of the comet's gases and dust.
Astronomers may have various expectations about what they might see when a comet impacts a planet or other object. Prior to the impacts, some astronomers may have predicted a large explosion or other dramatic effects. However, the actual outcome can be difficult to predict and may depend on many factors such as the comet's size, speed, and angle of impact.
As for lessons for us on Earth, the study of comets can help us understand the history and evolution of our solar system. It can also provide insights into the formation of planets and the origins of life on Earth. Additionally, the study of impacts can help us prepare for potential hazards such as asteroid or comet impacts on Earth.
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true or false: the momentum effect is observed where good or bad recent stock performance of particular stocks continue over time.
Answers
The momentum effect is a common occurrence in the market whereby asset values follow a trend for a considerable amount of time.
Both poorly performing stocks and well-performing stocks have a tendency to stick with the current trend. It is a result of momentum investors' propensity to pursue top performers. As a result, when a company is doing well, these investors invest more in it, driving up the price and maintaining the trend. And if a stock is performing poorly, these investors sell it, further down the stock's price. They therefore continue to perform poorly the following period. The momentum effect refers to the propensity of well-performing and poorly-performing equities to carry over their performance into the following period. capital C
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ph
what’s the correct choice?
help!!
Answers
Answer:
I think it's protons as they're positive!!
which statement is true about electron shielding of nuclear charge?
Answers
Electron shielding reduces the effective nuclear charge.
Does electron shielding decrease the effective nuclear charge?Electron shielding refers to the phenomenon where inner electron shells in an atom partially block the attractive force of the positively charged nucleus on the outer electrons. This shielding effect arises from the repulsion between negatively charged electrons. As a result, the outer electrons experience a reduced effective nuclear charge, which is the positive charge felt by an electron due to the nucleus.
The shielding effect can be explained by considering the electron distribution in an atom. Inner electrons occupy regions closer to the nucleus, creating a barrier that diminishes the electrostatic attraction between the outer electrons and the nucleus. This reduction in the effective nuclear charge affects various atomic properties, such as atomic size and ionization energy.
the concept of electron shielding and its impact on atomic properties, including atomic radius and ionization energy. Understanding electron shielding helps in explaining trends and behaviors observed in the periodic table.
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A m = 2.88kg mass starts from rest and slides a distance d down a frictionless θ = 34.7° incline. While sliding, it comes into contact with an unstressed spring of negligible mass, as shown in the figure below. The mass slides an additional 0.185m as it is brought momentarily to rest by compression of the spring (k = 409N/m). Calculate the initial separation d between the mass and the spring.
Answers
The initial separation d between the mass and the spring is 0.14m.
A m = 2.88kg mass starts from rest and slides a distance d down a frictionless θ = 34.7° incline. While sliding, it comes into contact with an unstressed spring of negligible mass. The mass slides an additional 0.185m as it is brought momentarily to rest by compression of the spring (k = 409N/m).
The initial separation d between the mass and the spring can be calculated using the equation:
d = (2*m*g*sin(θ)) / k
Substituting in the given values, we get:
d = (2*2.88kg*9.8m/s2*sin(34.7°)) / 409N/m
d = 0.14m
Therefore, the initial separation d between the mass and the spring is 0.14m.
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Television Advertising As Sales Manager for Montevideo Productions, Inc., you are planning to review the prices you charge clients for television advertisement development. You currently charge each client an hourly development fee of $2,900. With this pricing structure, the demand, measured by the number of contracts Montevideo signs per month, is 11 contracts. This is down 5 contracts from the figure last year, when your company charged only $2,400. (a) Construct a linear demand equation giving the number of contracts a as a function of the hourly fee p Montevideo charges for development. 960) - (b) On average, Montevideo bills for 40 hours of production time on each contract. Give a formula for the total revenue obtained by charging $p per hour. R(D) - (c) The costs to Montevideo Productions are estimated as follows. Fixed costs: $140,000 per month Variable costs: $70,000 per contract Express Montevideo Productions' monthly cost as a function of the number of contracts. ca) - Express Montevideo Productions monthly cost as a function of the hourly production charge p. Cip) = (d) Express Montevideo Productions' monthly profit as a function of the hourly development fee p. Pp) - Find the price it should charge to maximize the profit (in dollars per hour). ps per hour
Answers
To find the hourly development fee (p) that maximizes the profit, you would need to analyze the profit function and determine the value of p that yields the maximum result.
The linear demand equation giving the number of contracts (a) as a function of the hourly fee (p) charged by Montevideo Productions can be represented as: a = m * p + b
Given that the demand is currently 11 contracts when the fee is $2,900 and it was 5 contracts higher at $2,400, we can find the values of m and b. Using the two data points:
(2900, 11) and (2400, 16)
m = (11 - 16) / (2900 - 2400) = -1/100
b = 16 - (2400 * (-1/100)) = 40
Therefore, the linear demand equation is:
a = (-1/100) * p + 40
(b) The formula for the total revenue (R) obtained by charging $p per hour and billing for 40 hours of production time on each contract is:
R = p * 40 * a
Substituting the demand equation, we get:
R = p * 40 * ((-1/100) * p + 40)
(c) The monthly cost (C) for Montevideo Productions can be expressed as a function of the number of contracts (a) as follows:
C = Fixed costs + (Variable costs per contract * a)
Given: Fixed costs = $140,000 per month
Variable costs per contract = $70,000
So, the monthly cost function is:
C(a) = $140,000 + ($70,000 * a)
(d) The monthly profit (P) for Montevideo Productions can be calculated by subtracting the monthly cost (C) from the total revenue (R):
P(p) = R - C(a)
Finally, to find the hourly development fee (p) that maximizes the profit, you would need to analyze the profit function and determine the value of p that yields the maximum result.
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there is evidence that elephants communicate via infrasound, generating rumbling vocalizations as low as 14 hz that can travel up to 10 km. the intensity level of these sounds can reach 100 db, measured a distance of 5.5 m from the source. determine the intensity level of the infrasound 10 km from the source, assuming the sound energy radiates uniformly in all directions.
Answers
The intensity level of the infrasound 10 km from the source is 62.41 dB.
Describe infrasound.Low-status sound refers to sound waves having a frequency below the threshold of human audibility, also known as infrasound (generally 20 Hz). Hearing increasingly becomes less sensitive as frequency decreases, hence infrasound needs to have a powerful enough sound pressure for people to be able to hear it. Although many parts of the body may be able to detect infrasound vibrations at higher frequencies, the ear is the primary organ for hearing low-frequency sounds.
There are some uses for the term "infrasonics," which examines sound waves below 20 Hz and up to 0.1 Hz (and rarely to 0.001 Hz). Monitoring earthquakes and volcanoes, as well as mapping underground rock and petroleum deposits, are all done in this frequency range.
The intensity level of a sound decreases with the square of the distance from the source. So, the intensity of the infrasound 10 km from the source will be:
100 dB - 20 log (10 km / 5.5 m)
= 100 dB - 20 log (1818.1818)
= 100 dB - 37.59 dB
= 62.41 dB
So, the intensity level of the infrasound 10 km from the source is 62.41 dB.
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Which will most likely be a consequence as fossil fuel reserves are depleted?
Answers
Convert 1.5 days to s
Convert 5.2 ft to m
Convert 3600 s to hr
Convert 10.2 m to ft
Convert 305 g to kg
Convert 180 pm to m
Convert 73 kg to g
Convert 1,366 s to min
Convert 86,000 m to km
Please answer these and SHOW ALL WORK, please please please show ALL WORK. Need this done right now please help! Thank you so much!
Answers
According to the question, the answer of the given convert will be: 1.5 days = 36 hours, 5.2 ft = 1.58 m, 3600 s = 1 hr,10.2 m = 33.46 ft, 305 g = 0.305 kg, 180 pm = 0.18 m, 73 kg = 73000 g, 1,366 s = 22.77 min, 86,000 m = 86 km.
What is convert?
Convert is a term used to describe the process of changing one type of data into another. This could include changing a file format, changing a text document into a spreadsheet, or converting a physical document into a digital file. It is a useful tool in many industries and is often used to make sure that data is stored in a standard format, making it easy to access and use. Convert is used in a variety of settings, including media, accounting, and business. It is also used to help ensure data security and accuracy.
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A 62kg physics student ran up the stairs in order to get to class on time. The vertical displacement from the ground to the top of the stairs was 5.3 meters and the student ascended the stairs in 4.2 seconds. What was the physics student's power output in watts (W)? (round answer to nearest 10th place) *
4 points
Answers
Answer:
766.7 watts
Explanation:
P=W/T
work= F*d
= F*5.3 m/4.2s
to student is working against gravity
so mgh= 62kg* 5.3m*9.8 m/s2= 3220.28 Nm
so that divided by 4.2 should be 766.7 watts
if my answer helps please mark as brainliest.
Four forces are acting on an object. the earth pulls the box down with a 100 n force of gravity. the floor pushes the box up with a 100 n normal force. a student pushes the box to the right with a force of 50n. friction between the ground and the box oppose the motion of the box with a 30n force to the left. what is the net force on the box?
Answers
The net force on the object on which four forces are acting on is 20 N to the right.
What is net force?The net force acting on an object is the vector sum of all the forces that act upon an object.
Net force gives the resultant force acting on a given object at given period of time.
Mathematically, the net force on an object can be obtained by applying Newton's second law of motion as follows.
F(net) = ma
where;
m is the mass of the object
a is the acceleration of the object
The net vertical force on the object is calculated as follows;
F(upward) = 100 N - 100 N = 0 N
The net horizontal force on the object is calculated as follows;
F(horizontal) = 50 N - 30 N = 20 N
Thus, the net force on the object is acting towards the right of the object.
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there are five general means, or authentication factors, of authenticating a user’s identity, which can be used alone or in combination.
Answers
User identity refers to the unique characteristics, attributes, and information associated with an individual user within a particular context or system. It typically includes both personal and digital elements that help distinguish and identify the user in various interactions, transactions, or online platforms.
Five authentication factors that can be used to authenticate a user's identity. These factors are:
1. Knowledge: This factor refers to something the user knows, such as a password, PIN (Personal Identification Number), or the answer to a security question.
2. Possession: This factor involves something the user possesses, like a physical token, smart card, or mobile device. It can also include software-based tokens or virtual tokens generated by an authentication application.
3. Inherence: This factor relates to something inherent to the user, typically based on biometric characteristics. Examples of biometric factors include fingerprint scans, iris or retinal scans, voice recognition, or facial recognition.
4. Location: This factor takes into account the user's physical location or the network from which they are accessing a system. It can involve IP address geolocation, GPS coordinates, or proximity to a particular network or device.
5. Time: This factor considers the specific time or time-based criteria for authentication. It can involve time-limited passwords or temporary access codes that expire after a certain duration.
These authentication factors can be used individually or in combination, depending on the level of security required and the specific authentication mechanisms implemented by an organization or system. Different systems may have different requirements and may employ different combinations of these factors to verify a user's identity.
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1. While traveling along a highway a driver slows from 24 m/s to 15 m/s in 12 seconds. What is theautomobile's acceleration? (Remember that a negative value indicates a slowing down.)
Answers
Given data
*The initial speed of the driver is u = 24 m/s
*The final speed of the driver is v = 15 m/s
*The given time is t = 12 s
The formula for the automobile's acceleration is given as
\(a=\frac{v-u}{t}\)Substitute the values in the above expression as
\(\begin{gathered} a=\frac{15-24}{12} \\ =-0.75m/s^2 \end{gathered}\)While running, how should you throw a ball with respect to you so that you can catch it yourself? a) Slightly forward b) Slightly backward c) Straight up
Answers
C) Straight up
How will you catch the ball ?If the ball is thrown vertically up, only the horizontal component of the runner and the ball will be the same, and in that case only he may catch the ball. To catch the ball, the horizontal component of the force on the ball and the runner should be the same.
The horizontal velocity component (vx) describes the influence of the velocity in displacing the projectile horizontally. The vertical velocity component (vy) describes the influence of the velocity in displacing the projectile vertically.
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In physics, vectors are used to represent displacement, velocity, acceleration, force and other quantities that have a specific ___.
direction
mass
speed
scalar
Answers
Answer:
B and C
Explanation:
The electric field from a sheet of charge is perpendicular to the sheet and has a constant magnitude of Q/(Aeo), where A is the area of the sheet and Q is the charge on the sheet. If the sheet has an area, A=32.93 cm2, and a charge of 20.93 microC, what force, in nanoNewtons, would an electron experience due to this electric field?
Answers
The exercise tells us that the electric field is given by the following equation:
\(\vec{E}=\frac{Q}{A\epsilon_0}\)And it also gives us, A and Q. Thus, our electric field inside the capacitor is:
\(E=\frac{20.93*10^{-6}}{(32.93*10^{-4})*(8.85*10^{-12})}=718181521.8\frac{V}{m}\)As we know, the electric force can be written as:
\(F=q.E\)The charge of an electron is a constant, which is q=1.6*10^(-19) C.
Finally, our force can be written as:
\(F=1.6*10^{-19}*718181521.8=1.149*10^{-19}=0.00001149microN\)Our final answer is 0.00001149 micro Newtons
17. What is the definition of condensation?
Answers
An issue the students encountered is that the marble doesn't land on the launch pad all of the time. To remedy this, they consider constructing a funnel to help direct the marble. How do you suggest the students move forward with their design process in order to find a solution?
A Test funnels of the same size and material with varying sized openings.
B Test funnels of the same shape and size with varying materials.
C Test funnels with identical openings and material with varying size.
D Test all of the above funnels and then construct a funnel with the best design elements from each.
Answers
I suggest that the students move forward with option A.
Test funnels of the same size and material with varying sized openings. This will allow them to determine the optimal size for the opening that will help direct the marble to the launch pad. Once they have determined the optimal size, they can move forward with constructing the funnel with that size opening.
By testing funnels of different sizes, materials, and openings, the students can gather valuable data and insights about how each factor affects the marble's trajectory. This will help them identify the key design elements that contribute to successful landing on the launch pad.
Once the students have tested the various funnels, they can analyze the results and determine which design elements worked best in terms of directing the marble accurately. By combining these successful elements, they can then construct a new funnel that incorporates the best features from each tested funnel. This iterative approach allows them to refine their design and increase the chances of achieving consistent and reliable results.
Therefore, option D provides a comprehensive method for the students to explore different design possibilities, gather data, and ultimately create an improved funnel design.
what is the average velocity of a race car that traveled 88km in 20 min
Answers
Answer:
73.3333meters per second
Explanation:
average velocity= distance ÷ time
=(88×1000)/(20×60)
=73.3333m/s
One half of a balanced chemical equation is shown. 3Mg(OH)2 + 2H3PO4
Answers
Answer:
3 Mg, 2 P, 14 O, 12 H
Explanation:
Details The force on a particle is described by 10x³ - 5 at a point x along the x-axis. Find the work done in moving the particle from the origin to x = 2.
Answers
Answer:
To find the work done in moving the particle from the origin to x = 2, we need to integrate the force over the given interval.
The work done (W) is calculated by integrating the force function with respect to displacement (dx) from the initial position (0) to the final position (2):
W = ∫(0 to 2) (10x³ - 5) dx
Integrating the force function, we get:
W = ∫(0 to 2) (10x³ - 5) dx = [2.5x⁴ - 5x] evaluated from 0 to 2
Now, substituting the upper limit (2) and lower limit (0) into the equation:
W = [2.5(2)⁴ - 5(2)] - [2.5(0)⁴ - 5(0)]
= [2.5(16) - 10] - [0 - 0]
= 40 - 10
= 30
Therefore, the work done in moving the particle from the origin to x = 2 is 30 units of work.
Explanation:
how can we calculate the e.m.f of the battery?.
Answers
Explanation:
The emf is equal to the work done on the charge per unit charge (ϵ=dWdq) when there is no current flowing. Since the unit for work is the joule and the unit for charge is the coulomb, the unit for emf is the volt (1V=1J/C).
Answer:
The EMF or electromotive force is the energy supplied by a battery or a cell per coulomb (Q) of charge passing through it. The magnitude of emf is equal to V (potential difference) across the cell terminals when there is no current flowing through the circuit. (byjus)
Explanation:
por qué existen diferentes tipos de estrellas
Answers
La masa de una estrella es uno de los factores principales que determina su tipo. Las estrellas pueden variar desde enanas rojas de masa baja hasta supergigantes de masa alta. La masa influye en la temperatura y la presión interna de la estrella, lo que a su vez afecta su brillo, color y ciclo de vida.
La temperatura de una estrella también es un factor importante en su clasificación. Las estrellas más calientes suelen ser de color azul o blanco, mientras que las más frías son de color rojo. La temperatura está relacionada con la cantidad de energía que una estrella emite y su espectro de radiación.
Además, la composición química de una estrella puede variar, lo que afecta su luminosidad y otros aspectos. Las estrellas están compuestas principalmente de hidrógeno y helio, pero también contienen trazas de otros elementos. La presencia de diferentes elementos influye en la reacción nuclear que ocurre en el núcleo de la estrella y, por lo tanto, en su brillo y evolución.
Las diferencias en masa, temperatura y composición química dan lugar a una amplia variedad de tipos de estrellas, como enanas rojas, estrellas de secuencia principal (como el Sol), gigantes rojas, supergigantes y estrellas de neutrones. Cada tipo de estrella tiene su propia vida y evolución, y contribuye a la diversidad y belleza del universo observado.
fill in the blank. on mercury and the moon, we notice that larger craters __________ smaller crater
Answers
On Mercury and the Moon, we notice that larger craters dwarf smaller craters.
What is the relationship between the size of craters and their impact on Mercury and the Moon?On both Mercury and the Moon, the surfaces are covered with impact craters, which are formed when asteroids or comets collide with these bodies. While craters come in various sizes, we can observe that larger craters tend to dominate and overshadow smaller ones. This indicates that there have been significant impacts throughout the history of Mercury and the Moon, resulting in the formation of these larger craters.
The size difference between larger and smaller craters is particularly evident on Mercury, as it lacks an atmosphere to erode or weather the craters. Therefore, the larger craters on Mercury remain well-preserved and are easily distinguishable. On the Moon, although there is no atmosphere to the same extent as Earth's, some erosion and weathering processes occur due to micrometeorite impacts, the solar wind, and occasional volcanic activity. Nonetheless, the larger craters still retain their dominance over the smaller ones.
Understanding the relationship between the sizes of craters on Mercury and the Moon provides valuable insights into their geological history and the frequency and magnitude of impacts these bodies have experienced over time. The presence of larger craters suggests that more substantial objects have collided with these celestial bodies, potentially causing significant disturbances and shaping their surfaces.
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