Calculate the cell potential for the galvanic cell in which the given reaction occurs at 25 °C, given that [Ti2+]=0.00140 M and [Au3+]=0.887 M .
3Ti(s)+2Au3+(aq)↽−−⇀3Ti2+(aq)+2Au(s)

Photosynthesis may help reduce global warming because the carbon dioxide is consumed during the process.

Global warming has to do with an increase in the average global temperature brought about by the increase in the concentration of greenhouse gases in the atmosphere.

The greenhouse gases form a layer that traps reflected solar radiation in the atmosphere. They prevent these radiations from returning back to space and consequently, the temperature of the planet keeps increasing. The more the concentration of these gases in the atmosphere, the more the warming increases.

Carbon dioxide gas represents a major component of greenhouse gases and has been the main culprit in global warming.

During photosynthesis, carbon dioxide is utilized by green plants to make carbohydrates. Thus, photosynthesis remains a major way through which the concentration of carbon dioxide in the atmosphere can be reduced and consequently reduce global warming.

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Answer:

Solution given:

Required reaction is:

2H2+O2➔2H2O

now

10.

oxygen have 16 amu than total mass in the left side of oxygen is:

16×2=32 amu of Oxygen

11.

total mass of Oxygen in product side is;

16×2=32 amu of Oxygen

Answer:

985.2 moles of nitrogen can produce 1970.4 moles of ammonia.

Explanation:

The balanced chemical equation for the production of ammonia from nitrogen is:

N2 + 3H2 → 2NH3

From the balanced equation, we can see that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.

So, to determine how many moles of ammonia can be produced from 985.2 moles of nitrogen, we need to use the mole ratio from the balanced chemical equation as follows:

985.2 moles N2 x (2 moles NH3 / 1 mole N2) = 1970.4 moles NH3

Therefore, 985.2 moles of nitrogen can produce 1970.4 moles of ammonia.

The structure for 2-methyl-3-propalhex-2-yne can be shown in the image attached.

We know that a compound is composed of atoms that can be found in the compound. For the organic compound, we can see that we can be able to obtain the structure of the compound from the structure.

The compound as we can see is  2-methyl-3-propalhex-2-yne. The structure of the compound must be able to include a double bond as we can clearly see from the image that is attached to this answer.

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The number of moles of a solute that 3 liters of a 2-molar solution would contain is 6 moles. Details about number of moles can be found below.

The number of moles of a substance can be calculated using the following formula:

Molarity = no of moles ÷ volume

According to this question, there are 3 liters of a 2-molar solution. The number of moles can be calculated as follows:

no of moles = 3L × 2M

no of moles = 6 moles

Therefore, the number of moles of a solute that 3 liters of a 2-molar solution would contain is 6 moles.

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Answer:

the diaphragm,the rib cage muscles and the abdominal muscles.

Explanation:

From a functional point of view, there are three groups of respiratory muscles: the diaphragm, the rib cage muscles and the abdominal muscles. Each group acts on the chest wall and its compartments, i.e. the lung-apposed rib cage, the diaphragm-apposed rib cage and the abdomen.

Answer:

C)2 mole Cu(NO3)2 / 2 mole Fe

Explanation:

I'm pretty sure.

When iron is combined with copper (1) nitrate, it produces iron (II) nitrate and copper. The following could NOT be a mole ratio in this chemical reaction is:

D) 1 mole Fe(NO₃)₂ / 1 mole Fe

To determine which of the given mole ratios could NOT be part of the chemical reaction between iron and copper(1) nitrate, we need to write the balanced chemical equation for the reaction and then compare it to the given ratios.

The balanced chemical equation for the reaction is:

Fe + Cu(NO₃)₂ → Fe(NO₃)₂ + Cu

A) 1 mole Fe / 2 mole Cu

This mole ratio is consistent with the balanced chemical equation, where 1 mole of Fe reacts with 2 moles of Cu(NO₃)₂ to produce 1 mole of Fe(NO₃)₂ and 1 mole of Cu. So, this ratio could be part of the chemical reaction.

B) 1 mole Fe(NO₃)₂ / 2 mole Cu

This mole ratio is also consistent with the balanced chemical equation, where 1 mole of Fe(NO₃)₂ is produced by reacting 2 moles of Cu(NO₃)₂. So, this ratio could be part of the chemical reaction.

C) 2 mole Cu(NO₃)₂ / 2 mole Fe

This mole ratio is consistent with the balanced chemical equation, where 2 moles of Cu(NO₃)₂ react to produce 2 moles of Fe(NO₃)₂. So, this ratio could be part of the chemical reaction.

D) 1 mole Fe(NO₃)₂ / 1 mole Fe

This mole ratio implies that 1 mole of Fe(NO₃)₂ is produced by reacting with 1 mole of Fe, which is not consistent with the balanced chemical equation. The equation shows that 1 mole of Fe reacts with 1 mole of Cu(NO₃)₂ to produce 1 mole of Fe(NO₃)₂ and 1 mole of Cu. Therefore, this ratio could NOT be part of the chemical reaction.

So, the correct answer is:

D) 1 mole Fe(NO₃)₂ / 1 mole Fe

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Answer:

Question

Explanation:

Identification of problem is the first scientific method. This is overtaken by asking questions

To prepare a 0.12 M solution of FeCl₃, the amount of solid FeCl₃ to be dissolved in a given volume of solvent will be 9.72 grams.

Given,

Molarity of FeCl₃ (M)= 0.12 M

The molecular weight (m) of FeCl₃ is  = 162 gm

The volume of the solution (V) to be prepared is =500 ml

The amount of FeCl₃ to be dissolved to make a 0.12 M solution is= x

So,

MV= x ÷ m × 1000

0.12× 500 = x ÷ 162 × 1000

x = 60 × 162 ÷ 1000

x= 9.72 gm

So 9.72 grams of FeCl₃ is dissolved to make 500 ml of 0.12 M solution.

For preparing 0.4 M HCl from 4M HCL:

If we need to make 500 ml of solution with 0.4M of HCL, then we use the formula:

M₁V₁= M₂V₂

0.4 × 500= 4 × x

x= 50 ml

So 50 ml of 4M HCL is taken to make 0.4 M HCL.

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Answer:

4.2 atm

Explanation:

Dalton’s Law of Partial Pressures

PA = XA(PT)

Partial pressure of A = mole factor of gas A x total pressure of all gases

PA = 0.21 atm

XA = 0.050

PT= ?

0.21atm= 0.050(PT)

0.21/0.050 = PT

PT = 4.2 atm

The total pressure of gases must be 4.2 atm for the partial pressure of oxygen to be 0.21 atm.

The partial pressure of a gas can be calculated using Dalton's law of partial pressure equation as follows:

PA = XA(PT)

Where;

Based on the information given in this question;

0.21 atm = 0.050 (PT)

0.21/0.050 = PT

PT = 4.2 atm

Therefore, the total pressure of gases must be 4.2 atm for the partial pressure of oxygen to be 0.21 atm.

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Explanation:

The heart of the doorbell is an electromagnetic so yeah it does.

The statement that best describes the activation energy on the graph below is the vertical difference between 1 and 2 (option B).

Activation energy is the energy required to initiate a reaction. For example, the flame from the fuse of a firecracker provides a small initial amount of energy, after which the explosive reaction proceeds by itself, releasing a considerably larger quantity of energy.

According to this question, a reaction proceeds from 1 to 3. The activation energy needed for the reaction to be initiated is the vertical line that extends to the peak of 2.

Therefore, it can be said that the statement that best describes the activation energy on the graph below is the vertical difference between 1 and 2.

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We can determine the following based on the provided information:

Metal nitrate A is a compound that, when heated, transforms into colourless gas, brown gas B, and a metal oxide with a yellowish brown hue. B. C: Colourless petrol C. B: Brown petrol C. D: Compound D, a yellow precipitate produced by the reaction of potassium iodide with an aqueous solution of compound A.

We may deduce that A is probably lead nitrate (Pb(NO3)2) because lead is frequently used in soldering alloys and the metal contained in A is utilised in an alloy for soldering purposes.

Identifications:

Lead nitrate, or Pb(NO3)2,

N2O: Nitrogen dioxide

B: Carbon (CO)

D: PbI2, or lead iodide.

Thus, this can be concluded regarding the given scenario.

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Your question seems incomplete, the probable complete question is:

A metal nitrate A on heating gives a yellowish brown coloured metal oxide along with brown gas B and a colourless gas C. An aqueous solution of A on reaction with potassium iodide forms a yellow precipitate of compound D. Identify A, B, C and D. Also, identify the types of reactions taking place. Metal present in A is used in an alloy which is used for soldering purposes.

The partial pressure of \(N_2\)is 165.6 kPa and the partial pressure of \(H_2\)is 434.4 kPa.

To calculate the partial pressures of \(H_2\)and \(N_2\)in the 10dmcube container, we need to use the ideal gas law equation, which states that the pressure of a gas is directly proportional to its number of moles and temperature, and inversely proportional to its volume.

First, we need to calculate the number of moles for each gas. Since we are given the volume of each gas and the volume of the container, we can use the formula:

Number of moles = Volume / Molar volume

The molar volume is the volume occupied by one mole of a gas at a given temperature and pressure. At standard temperature and pressure (STP), the molar volume is 22.4 L/mol.

For \(N_2\), the number of moles is 2 dmcube / 22.4 L/mol = 0.089 mol
For \(H_2\), the number of moles is 5 dmcube / 22.4 L/mol = 0.223 mol

Next, we can calculate the partial pressures of each gas using the formula:

Partial pressure = (Number of moles / Total number of moles) * Total pressure

The total pressure is the sum of the pressures of each gas:

Total pressure = Pressure of N2 + Pressure of \(H_2\)

Given that the pressure of N2 is 100 kPa and the pressure of \(H_2\)is 500 kPa, we have:

Total pressure = 100 kPa + 500 kPa = 600 kPa

Now we can calculate the partial pressure of \(N_2\):

Partial pressure of \(N_2\)= (0.089 mol / (0.089 mol + 0.223 mol)) * 600 kPa = 165.6 kPa

Similarly, we can calculate the partial pressure of \(H_2\):

Partial pressure of H2 = (0.223 mol / (0.089 mol + 0.223 mol)) * 600 kPa = 434.4 kPa

Therefore, the partial pressure of \(N_2\)is 165.6 kPa and the partial pressure of \(H_2\)is 434.4 kPa.

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The combined Gas Law equation is represented by B) P1V1 / T1 = P2V2 / T2.

The combined gas law is the law that combines Charles’s law, Gay-Lussac’s law, and Boyle’s law.

Combined gas law can be mathematically expressed as

k = PV/T

Where,

P = pressure

T = temperature in kelvin

V = volume

K  = constant (units of energy divided by temperature)

When two substances are compared in two different conditions, the law can be stated as,

P1V1/T1 = P2V2/T2

Where,

P1 = initial pressure

V1 = initial volume

T1 = initial temperature

P2 = final pressure

V2= final volume

T2 = final temperature

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Answer:

Acidic solutions are measured to have lower pH values than basic or alkaline solutions.

Explanation:

So basically acids have a lower pH than other liquids like water.

The theoretical yield of \(Pl_{3}\) from the given reaction is 73.2 grams.

What is theoretical yield ?

To calculate the theoretical yield of \(Pl_{3}\), we first need to determine which reactant is limiting. We can do this by calculating the amount of product that would be formed from each reactant, and comparing the values.

From the balanced chemical equation, we can see that 2 moles of P reacts with 3 moles of \(I_{2}\) to produce 2 moles of \(Pl_{3}\). So, the number of moles of P and \(I_{2}\) present in the reaction can be calculated as:

moles of P = mass of P / molar mass of P

moles of P = 27.0 g / 30.97 g/mol

moles of P = 0.871 mol

moles of \(I_{2}\) = mass of \(I_{2}\) / molar mass of \(I_{2}\)

moles of \(I_{2}\) = 68.0 g / 253.81 g/mol

moles of \(I_{2}\) = 0.268 mol

Now, we can use the stoichiometry of the balanced chemical equation to calculate the number of moles of \(Pl_{3}\) that can be produced from each reactant:

mol of \(Pl_{3}\) produced from P = (0.871 mol P) / (2 mol P per 2 mol \(Pl_{3}\)) * (2 mol \(Pl_{3}\) / 2 mol P)

mol of \(Pl_{3}\) produced from P = 0.871 mol \(Pl_{3}\)

mol of \(Pl_{3}\) produced from \(I_{2}\) = (0.268 mol \(I_{2}\)) / (3 mol \(I_{2}\) per 2 mol \(Pl_{3}\)) * (2 mol \(Pl_{3}\) / 1 mol \(I_{2}\))

mol of \(Pl_{3}\) produced from \(I_{2}\) = 0.178 mol \(Pl_{3}\)

Since the amount of \(Pl_{3}\) produced is limited by the amount of \(I_{2}\), \(I_{2}\) is the limiting reactant. Therefore, the theoretical yield of \(Pl_{3}\) is the amount of \(Pl_{3}\) that would be produced if all of the limiting reactant (\(I_{2}\)) were completely consumed:

mass of \(Pl_{3}\) = moles of \(Pl_{3}\) * molar mass of \(Pl_{3}\)

mass of \(Pl_{3}\) = 0.178 mol * 411.81 g/mol

mass of \(Pl_{3}\) = 73.2 g

Therefore, the theoretical yield of \(Pl_{3}\) from the given reaction is 73.2 grams.

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54.2 g of CaCl2 must be dissolved in 1000 g of water to raise the boiling point to 100.75°C.

To solve this problem, we can use the formula:

ΔTb = Kb × m × i

where ΔTb is the boiling point elevation, Kb is the molal boiling point elevation constant for water, m is the molality of the solution, and i is the van't Hoff factor, which represents the number of particles into which the solute dissociates.

We can rearrange this formula to solve for the molality of the solution:

m = ΔTb / (Kb × i)

We know that ΔTb is 0.75°C (100.75°C - 100°C), Kb is 0.51°C/m, and i for CaCl2 is 3 (since it dissociates into 3 ions in water). Substituting these values, we get:

m = 0.75°C / (0.51°C/m × 3) = 0.490 m

To find the mass of CaCl2 needed to make a 0.490 m solution in 1000 g of water, we can use the formula:

moles of solute = molality × mass of solvent (in kg)

We convert 1000 g of water to 1 kg, and then use the molecular weight of CaCl2 to convert from moles to grams:

moles of CaCl2 = 0.490 m × 1 kg = 0.490 mol

mass of CaCl2 = 0.490 mol × 110.98 g/mol = 54.2 g

Therefore, 54.2 g of CaCl2 must be dissolved in 1000 g of water to raise the boiling point to 100.75°C.

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The type of movement that occurs in the plate movement listed above include the following:

These are gigantic pieces of the Earth's crust and uppermost mantle and are made up of oceanic crust and continental crust.

A convergent boundary as the name implies occurs when lithospheric plates are moving towards one another.

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Answer:

Plant cells contain two organelles that are essential for their functioning. These are the chloroplasts and the vacuoles. The chloroplasts are the organelles responsible for photosynthesis, which involves converting light energy from the sun into chemical energy in the form of glucose. Without chloroplasts, plants would not be able to produce their own food. The vacuoles are large organelles filled with fluid that serve to store nutrients and other materials. Vacuoles also help to maintain the turgor pressure of the cell, which is the pressure that helps to keep the cell rigid and prevents it from collapsing. Without vacuoles, plant cells would not be able to remain rigid and would collapse, leading to the death of the plant.

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To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.

To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.

If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).

However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.

In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.

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Answer:

Gases > liquids > solids.

Explanation:

The statement that best describes the relationship between the particle motion for the states of matter is Gases > liquids > solids.

In a solid, the particles are packed tightly together and they vibrate in place. In a liquid, the particles are still close together, but they can move around each other. In a gas, the particles are far apart and they move around very quickly.

The faster the particles move, the more energy they have. So, gases have the most energy, liquids have less energy, and solids have the least energy.

Answer:

A, drawing a conclusion

Explanation:

The pH at the equivalence point for the titration of 0.25 M HCOOH versus 0.25 M NaOH is 8.5.

Let's consider the following neutralization reaction.

HCOOH + NaOH ⇒ HCOONa + H₂O

At the equivalence point, 0.25 M HCOOH completely reacted with 0.25 M NaOH to form 0.25 M HCOONa.

HCOONa undergoes hydrolysis. The net ionic equation is:

HCOO⁻(aq) + H₂O(l) ⇄ HCOOH(aq) + OH⁻(aq)

Given the concentration of HCOO⁻ is 0.25 M (Cb) and the basic dissociation constant of HCOO⁻ is 4.8 × 10⁻¹¹ (Kb), we can calculate the concentration of OH⁻ using the following expression.

\([OH^{-} ] = \sqrt{Kb \times Cb } = \sqrt{(4.8 \times 10^{-11} ) \times 0.25 } = 3.5 \times 10^{-6} M\)

The pOH of the solution is:

\(pOH = -log [OH^{-} ] = -log (3.5 \times 10^{-6} ) = 5.5\)

The pH of the solution is:

\(pH = 14 -pOH = 14 -5.5 = 8.5\)

The pH at the equivalence point for the titration of 0.25 M HCOOH versus 0.25 M NaOH is 8.5.

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Answer:

0.606 g of KNO₃.

Explanation:

We'll begin by converting 300 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

300 mL = 300 mL × 1 L / 1000 mL

300 mL = 0.3 L

Next, we shall determine the number of mole of KNO₃ in the solution. This can be obtained as follow:

Volume = 0.3 L

Molarity of KNO₃ = 0.020 M

Mole of KNO₃ =?

Mole = Molarity x Volume

Mole of KNO₃ = 0.020 × 0.3

Mole of KNO₃ = 0.006 mole.

Finally, we shall determine the mass of 0.006 mole of KNO₃. This can be obtained as follow:

Mole of KNO₃ = 0.006 mole.

Molar mass of KNO₃ = 39 + 14 + (16×3)

= 39 + 14 + 48

= 101 g/mol

Mass of KNO₃ =?

Mass = mole × molar mass

Mass of KNO₃ = 0.006 × 101

Mass of KNO₃ = 0.606 g

Thus, 0.606 g of KNO₃ is needed to prepare the solution.

The birth weight of cats at the 90th percentile would be approximately 3.7 ounces. b. The birth weight of cats at the 10th percentile would be approximately 2.3 ounces.

There are three main methods of calculating weight:

1. Balance Beam Scale: A balance beam scale is an example of a mechanical weighing system. It uses a set of calibrated weights to measure the weight of an object.

2. Digital Scale: A digital scale uses an electronic or digital readout to display the weight of an object.

3. Calipers: Calipers are devices used to measure the distance between two points, such as thickness or diameter. They come in various sizes and shapes, depending on the type of measurement the user wants to take.

Birth weight is the weight of a baby at the time of birth. It is usually measured soon after delivery, with a special baby scale, though sometimes the baby's weight is estimated. The normal range of birth weight is anywhere between 5 lbs 8 oz and 10 lbs, though preterm or premature babies may be significantly lighter. A baby's birth weight is important because it can provide a clue to the baby's overall health. High birth weights may indicate an underlying medical condition, and low birth weights can be a sign of premature or difficult delivery and health risks associated with such a delivery.

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Answer:

c

Explanation:

Science is best described as a way of building knowledge about the world around us through observation and experimentation.

Explanation

Given

number of moles of Al = 4.80 mol

Required: Moles of O2

Solution

Use the stoichiometry to calculate the moles of O2

The molar ratio of Al to O2 is 4:3

Therefore moles of O2 = 4.80 x (3/4) = 3.6 mol

Answer

moles of O2 = 3.6 mol