The angular displacement in 10 seconds for the blades of a fan that are rotating at 150 revolutions per minute is 157 radians.
To determine the angular displacement (θ), we can use the formula θ = ω × t, where ω is the angular velocity and t is the time.
First, we need to convert the given 150 revolutions per minute (rpm) to radians per second:
1 revolution = 2π radians
150 rpm × (2π radians/revolution) × (1 minute/60 seconds) = 15.7 radians/second (rounded to one decimal place)
Now, we can calculate the angular displacement:
θ = ω × t = 15.7 radians/second × 10 seconds = 157 radians
So, the angular displacement of the fan blades in 10 seconds is 157 radians.
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It is common for creatures to be able to live in both the spray zone and low-tide zone.
True or False
Hii!!! The correct answer is true. (:
Eksu academic building lot is 150ft by 200ft determine the area of this lot in cm² and m²
To determine the area of a lot, we can multiply the length and width of the lot. The given length and width of the EKSU academic building lot is 150ft and 200ft respectively. so building lot in cm² is 27,847,232 cm² and in m² is 2795.7752 m².
To determine the area of this lot in cm² and m², we need to convert the given measurements from feet to centimeters and meters respectively.
Convert 150ft and 200ft to cm:1 ft = 30.48 cm So, 150ft = 150 x 30.48 = 4572 cm And 200ft = 200 x 30.48 = 6096 cm
Therefore, the area of the lot in
cm² = length x width = 4572 cm x 6096 cm = 27,847,232 cm².Convert 150ft and 200ft to meters:1 ft = 0.3048 mSo, 150ft = 150 x 0.3048 = 45.72 mAnd 200ft = 200 x 0.3048 = 60.96 m
Therefore, the area of the lot in m² = length x width = 45.72 m x 60.96 m = 2795.7752 m² (rounded to four decimal places)
Therefore, the area of the EKSU academic building lot in cm² is 27,847,232 cm² and in m² is 2795.7752 m².
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calculate the binding energy e of the nitrogen nucleus 14 7n (1ev=1.602×10−19j).
The binding energy of the nitrogen nucleus 14^7N is 1.281 MeV.
The binding energy of a nucleus can be calculated using the Einstein's mass-energy equivalence equation, E = m. c ^2, where E is the energy, m is the mass defect, and c is the speed of light.
where:
E is the binding energy in joules
m is the mass of the nucleus in kilograms
c is the speed of light in meters per second
The mass of a nucleus is always less than the sum of the masses of its constituent parts. This is because some of the mass is converted into energy when the nucleus is formed. The binding energy of a nucleus is a measure of how much energy is required to break the nucleus apart.
The mass of the nitrogen nucleus 14^7N is 14.00307 amu. The mass of a proton is 1.00783 amu and the mass of a neutron is 1.0087 amu. There are 7 protons and 7 neutrons in a nitrogen nucleus, so the total mass of the constituent parts is 7 * 1.00783 amu + 7 * 1.0087 amu = 14.07261 amu. The difference between the mass of the nucleus and the mass of its constituent parts is the binding energy. The binding energy of the nitrogen nucleus 14^7N is therefore 14.07261 amu - 14.00307 amu = 0.06954 amu.
The binding energy of the nitrogen nucleus 14^7N in joules is calculated by multiplying the mass of the nucleus in amu by the speed of light squared in meters per second and then converting the result to joules using the conversion factor 1 eV = 1.602 × 10^-19 J. The binding energy of the nitrogen nucleus 14^7N in joules is therefore 0.06954 amu * (3.0 × 10^8 m/s)^2 * (1.602 × 10^-19 J/eV) = 1.281 MeV.
Therefore, the binding energy of the nitrogen nucleus 14^7N is 1.281 MeV.
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how does the input distance of a third-class lever compare to the output distance
Answer:
A first-class lever: fulcrum is between input and output force; second-class lever: output force is between input force and fulcrum; third-class lever: input force is between fulcrum and output force
The natural enzyme reaction in food slowly breaks it down and eventually causes it to spoil. what 2 things halt this enzyme reaction and help preserve the food?
microwaving
cooking at high temperature
storing properly in the refrigerator
blanching and canning
Answer: the answer is storing properly in refrigeration.
Explanation:
Which of these is an example of printed material? question 4 options: a voicemail an issue of sports illustrated magazine a recording of a speech a text message to a friend
Answer:
(b) an issue of sports illustrated magazine
Explanation:
You want to identify an example of printed material.
Printed materialThe term "printed material" generally refers to text and/or graphics represented in ink on paper. Modern "ink" may be a plastic or carbon material that is fused to the paper by heat.
An issue of Sports Illustrated magazine, choice B, will be an example of printed material.
Other mediaModern communication is often electronic, rendered on a view screen or as audio. Instances of this sort of communication are voicemail, a recording, and a text message.
Among the options given the Sports Illustrated Magazine is an example of printed material. The other options are not considered printed because they are in digital or audio formats.
Explanation:Among the options provided, the Sports Illustrated Magazine is an example of a printed material. Printed materials are those that are typically put into a physical form using any form of printing method, like magazines, books, brochures, and posters. A voicemail, a recording of a speech, and a text message to a friend are not printed materials because they are digital or audio formats, not physical ones.
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The equation below shows a general equation for a reaction, and the amounts of the substance are written underneath.
AB + CD → AC + BD
(15 g) (?) (?) (10 g)
The total mass of the products is 50g. Which best completes the other two amounts?
The amount of CD is 40 g, and the amount of AC is 35 g.
The amount of CD is 35 g, and the amount of AC is 40 g.
The amount of CD and AC would be the same.
The amount of CD and AC is undetermined.
Explanation:
The amount of CD is 35 g, and the amount of AC is 40 g.
Explanation:
AB + CD \rightarrow AC + BDAB+CD→AC+BD
The law of conservation of mass states that in any chemical reaction, the total mass of the reactants must be equal to the total mass of the products.
In this reaction, we know the mass of one reactant (AB, 15 g) and the mass of one product (BD, 10 g). In order to have the same total mass on the left side and on the right side of the equation, the mass of AC must be 5 g more than the mass of CD. We see that the only choice that satisfies this condition is:
The amount of CD is 35 g, and the amount of AC is 40 g.
In fact, if we assume these masses are correct, we have:
- on the reactant side: m(AB)+m(CD)= 15g + 35g = 50g
- on the product side: m(AC)+m(BD)= 40g + 10g = 50g
so, we have the same mass on both sides of the equation, and the law of conservation of mass is satisfied.
Answer:
B is the answer on edge
Explanation:
B: The amount of CD is 35 g, and the amount of AC is 40 g.
of the forces present in the external environment, which is considered to be significantly uncontrollable?
Of the forces present in the external environment, which is considered to be significantly uncontrollable are political forces, competition force. In physics, nuclear energy is uncontrollable.
The economy, politics, competitors, customers, and even the weather are all uncontrollable factors. the energies which are mentioned in the above part are the forces that are involuntary and voluntary both and can be controlled or cannot be controlled by our own means. we cannot tend to change it. the nuclear energy whereas is the energy that generally cannot be controlled and we have to make controls to take a control over it. this is involuntary and generally cannot be controlled. by this primary information, we can firmly conclude that of the forces present in the external environment, which is considered to be significantly uncontrollable are political forces, competition force. In physics, nuclear energy is uncontrollable.
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how potential and kinetic energy changed during the spacecraft launches.
Answer:
Have a blessed day!
Explanation:
The energy to launch the spacecraft came from moving the spacecraft against the magnetic force. The energy used to move a magnet against a magnetic force is stored as potential energy in the magnetic field. This magnetic force can convert potential energy stored in the magnetic field to kinetic energy.
Please give brainliest!
Answer:
Moving the spacecraft against the magnetic force provided the energy needed to launch it. The energy expended to move a magnet against a magnetic force is stored in the magnetic field as potential energy.
Explanation:
i'm strugglingg in science and I need help "Why did Vehicle 2 fall off the cliff in Claire's test of the collision scene, but Vehicle 2 did not fall off the cliff in the film Iceworld Revenge?
Claim 1: The vehicles in Iceworld Revenge had different masses; in Claire’s test, the vehicles had the same mass.
Claim 2: The friction of the surface that was used in Iceworld Revenge was different from the friction of the surface in Claire’s test.
State your claim. Use evidence to support your claim, and then explain how the evidence supports your claim."
Answer:the answer is friction and mass.
Explanation:The reason that Vehicle 2 fell off the cliff in Claire's test of the collision scene, but Vehicle 2 did not fall off the cliff in the film Iceworld Revenge is because of the friction and mass. A different friction, called foam, is used in Claire's test. The foam has a really low friction that caused vehicle 2 to fall from the cliff. According to evidence card B which states that, “In Iceworld Revenge, Vehicle 2 moves slowly toward the cliff after the collision, halting only before it goes over the side. In Clasir's test, Vehicle 2 went over the cliff at full speed”.This evidence confirms my arguments that in the film, vehicle 2 did not drive as quickly as in the film scene of Claire . __ ______________________________________________________________________________
In Young's experiment, light from a red laser (wavelength 700 nm) is sent through two
slit. At the same time, monochromatic visible light with another wavelength passes through the same
apparatus. As a result, most of the pattern that appears on the screen is a mixture of two colors; however, the
center of the third bright fringe of the red light appears pure red. What are the possible wavelengths of the
second type of visible light?
In Young's experiment, the pattern that appears on the screen is a result of interference between two sets of waves that are diffracted through two slits.
The location of the bright fringes in the pattern depends on the wavelength of the light used. This means that the path difference between the waves that interfere to produce this fringe is an integer multiple of the red light's wavelength (700 nm).
ΔL = mλ_red = nλ_other
where ΔL is the path difference between the waves, m and n are integers, λ_red is the wavelength of the red light, and λ_other is the wavelength of the second type of visible light.
Solving for λ_other, we get:
λ_other = (m/n) λ_red.
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How did Annamarie know the hirsch’s were not gone for holiday
If Hirsch's car had been gone and their house had been dark, Annamarie might have used the principles of physics. One way she could do this is by using the principles of optics and light.
If Annamarie had access to a telescope or binoculars, she could look through them at Hirsch's house and look for any signs of movement or activity inside. If the Hirsch's were home, she might see movement of people or objects inside the house, or she might see lights turning on and off as they move around. Another way Annamarie could use physics to determine if the Hirsch's were home is by listening for sounds. She could use her knowledge of acoustics to listen to sounds.
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--The complete Question is, Annamarie noticed that the Hirsch's car was still in their driveway and the lights in their house were still on, leading her to conclude that they had not gone on holiday. If the Hirsch's car had been gone and their house had been dark, how might Annamarie have used the principles of physics to determine whether or not they were home? --
Parker completed 4 laps around a 400 m track. He ran for a total of 30 mins. What is the
distance and displacement of his travel?
Answer:
Distance: 1600 m Displacement: 0
Explanation:
The distance is because He ran 400 meters 4 times getting 1600 m
4*400=1600
The displacement is 0 because displacement is the total distnce away from the starting point and since he ran laps around the track in the end he ended up in the same spot as last time.
Nuclear energy is currently used in which three kinds of vehicles?
A. cars, submarines, spacecraft
B. submarines, ships, spacecraft
C. spacecraft, airplanes, cars
D. airplanes, submarines, ships
Answer:
d
Explanation:
Exercise 11.11 Using the known radius of the Earth and that g =9.80m/s at earth surface ,find the average density of the Earth
a train travels 65 miles in 2 hours what is the average speed of the train in miles per hour
Answer:
32.5 miles
Explanation:
65/2=32.5
Hope this helps!
Answer:
32.5
Explanation:
During the rock cycle, cooling magma and lava from igneous rock, heat and pressure cause other rocks to turn into metamorphic rock, and weathered rock on the surface is eventually turned into sedimentary rock. Rocks move through this cycle at different rates, but it can take some rocks several billion years to complete the cycle. Using this information, what is the most likely reason why scientists use models to study the rock cycle?
A. The rock cycle only affects objects that are too small to be observed directly.
B. The rock cycle is only an abstract idea and does not actually occur in nature.
C. The rock cycle no longer occurs on Earth.
D. The rock cycle takes too long to be able to observe it in entirety.
Answer:
D. The rock cycle takes too long to be able to observe it in entirety.
Explanation: is answer
What does a simple pulley do?
A. It makes you have to pull harder on the rope.
B. It increases the force.
O O O O
C. It redirects the force.
D. It makes the load heavier.
Answer:
C. It redirects the force
A ball is projected upwards from a bridge and hits the ground 5 seconds after it was originally projected its initial velocity is 15 m/s and it’s final velocity is 34 m/s calculate the height of the bridge.Max height = 11.48 m
Given:
• Time, t =5 seconds
,• Initial velocity, u = 15 m/s
,• Final velocity, v = 34 m/s
Given that the ball is projected upwards from a bridge, let's find the height of the bridge.
Let's first find the height from the top of the bridge to the maximum height.
To find the height apply the formula:
\(v^2=u^2-2as\)Where:
v is the final velocity = 0 m/s (velocity at max height).
u is the initial velocity = 15 m/s
a is acceleration due to gravity = 9.8 m/s²
s is the height.
\(\begin{gathered} 0^2=15^2-2(9.8)s \\ \\ 0=225-19.6s \\ \\ 19.6s=225 \\ \\ s=\frac{225}{19.6} \\ \\ s=11.48\text{ m} \end{gathered}\)The distance from the bridge to the maximum height is 11.48 m.
Now, let's find the maximum height to the ground.
\(v^2=u^2+2as\)Where:
v is the final velocity = 34 m/s
u is the initial velocity = 0 m/s (velocity at the top).
a is acceleration due to gravity = 9.8 m/s²
s is the maximum height.
Thus, we have:
\(\begin{gathered} 34^2=0^2+2(9.8)s \\ \\ 1156=19.6s \\ \\ s=\frac{1156}{19.6} \\ \\ s=58.9\approx59\text{ m} \end{gathered}\)The maximum height is 59 meters.
To find the height of the bridge, we have:
Height of bridge = Maximum height - Distance from top of bridge to max height.
Height of bridge = 59m - 11.48m = 47.52 m
Therefore, the height of the bridge is 47.52 meters.
• ANSWER:
47.52 meters.
When the sun and moon work together ____________ are formed on Earth.
a
Frankentides
b
Neap Tides
c
Spring Tides
d
Dark Tides
Answer:
C. Spring Tides is the answer.
a container has the mass of 125g when a liquid is added the mass becomes 163g what is the mass of the liquid
A steel railroad track has a length of 34 m
when the temperature is −3◦C.
What is the increase in the length of the
rail on a hot day when the temperature is
30 ◦C? The linear expansion coefficient of
steel is 11 × 10−6(◦C)−1
.
Answer in units of m.
The increase in the length of the rail on a hot day when the temperature is 30 °C is 0.0363 m.
What is length?Length is a measurement of distance or size. It is one of three fundamental measurements (along with width and height) used to describe the size of an object. Length can be measured in a variety of units, such as meters, feet, inches, or centimeters. In mathematics, length is defined as the longest dimension of an object or distance between two points. In physics, length is a fundamental quantity used to measure objects and distances.
The increase in the length of the rail on a hot day when the temperature is 30 °C can be calculated using the formula for linear expansion:
ΔL = L0 * α * ΔT
Where L0 is the original length of the rail (34 m), α is the linear expansion coefficient of steel (11 x 10-6 (°C)-1), and ΔT is the change in temperature (30 °C - (-3 °C) = 33 °C).
Plugging in the values, we get:
ΔL = 34 m * 11 x 10-6 (°C)-1 * 33 °C
ΔL = 0.0363 m
Therefore, the increase in the length of the rail on a hot day when the temperature is 30 °C is 0.0363 m.
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A man walks 2.6 miles east, then turns and walks 6.7 miles north. What is his resultant
vector from start to finish?
Answer:
Yes cause he walks 6.7 miles
The displacement vector of the man is equal to 17.41 miles in the Northeast direction.
What is displacement?The displacement of an object can be defined as the shortest distance between two points. The displacement can be described as a vector quantity because contains both direction and magnitude. The displacement can be positive (+ve), negative, or zero and can change with time.
The distance is the total path traveled and is a scalar quantity as it has only magnitude, and no direction. The distance is always positive (+ve), it can never be equal to zero.
Given, a man moves 2.6 miles along AB in the East and then 6.7 miles North along BC.
The displacement (AC) of the man can be calculated by using Pythagoras' theorem:
AC² = AB² + BC²
AC² = (2.6)² + (6.7)²
AC² = 6.76 +44.89
AC = 17.41 miles
Therefore, the displacement vector of the man is 17.41 miles.
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A pressure of 7x10^5N/m is applied to all surfaces of a copper cube (of sides 25 cm) what is the fractional change in volume of a cube? ( for copper B= 14x10^10N/m)
Answer:
The correct solution is "\(5\times 10^{-4}\) %".
Explanation:
The given values are:
Pressure,
\(\Delta P=7\times 10^5 \ N/m\)
for copper,
\(B=14\times 10^{10} \ N/m\)
As we know,
The Bulk Modulus (B) = \(\frac{\Delta P}{-\frac{\Delta V}{V} }\)
or,
The decrease in volume will be:
= \((\frac{\Delta V}{V})\times 100 \ percent\)
then,
= \(\frac{\Delta P}{B}\times 100 \ percent\)
On putting the values, we get
= \(\frac{7\times 10^5}{14\times 10^{10}}\times 100 \ percent\)
= \(5\times 10^{-4} \ percent\)
Question 4 of 10
Which of the following changes occurs naturally in a system over time?
A. Becoming more organized
B. Becoming more efficient
C. Increasing in energy
OD. Increasing in randomness
Answer: D. Increasing in randomness.
Explanation: The concept related to this change is entropy. Entropy is a measure of the randomness or disorder in a system. According to the second law of thermodynamics, the entropy of an isolated system tends to increase over time. This means that natural processes often lead to an increase in randomness or disorder.
For example, imagine a container of gas molecules. Initially, the molecules may be confined to one side of the container, creating a region of higher concentration. However, over time, the gas molecules will naturally spread out and become more evenly distributed throughout the container. This increase in randomness or disorder corresponds to an increase in entropy.
integers are read from input and stored into a vector until -1 is read. output the negative elements in the vector in reverse order. end each number with a newline.
Loop to print negative elements of the vector in reverse.
Run the loop from the size of the vector to 0, check whether each element is negative, or less than zero then print the element.
for (int i = integerVector.size(); i >=0; i--)
{
if(integerVector[i]<0)
cout<<integerVector[i]<<endl;
}
C++ filled in code for the given program to print negative elements of the vector in reverse order :
#include <iostream>
#include<vector> using namespace std;
int main() { int i; vector<int> integerVector;
int value; cin>>value; while(value!=-1) { integerVector.push_back(value);
cin>>value; } for (int i = integerVector.size(); i >=0; i--) { if(integerVector[i]<0)
cout<<integerVector[i]<<endl; } return 0; }
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A severe thunderstorm dumped 2.4 in. of rain in 30 min on a town of area 28 km2. what volume of water, in acre-feet, fell on the town?
The volume of water fell on the town is 1382 acre foot.
To find the volume of water, the given values are:
Area of the town = 28 km² (square kilometer)
Time = 30 minutes
Height = 2.4 inch
What is the volume of rainfall?The volume of water during a severe thunderstorm can be calculated as,
At first inch should be converted to meter,
1m = 39.37 inch
So, 2.4 inch = 2.4 / 39.37
= 0.0609 m
Then, we have to calculate the volume,
Formula of volume,
Volume V = Height H × Area A
= 0.0609 × 28 × 1000²
= 1705200 m³
Here, the volume should be in acre feet,
The value of, 1 m³ = 0.000810714 acre foot
so, 1705200 m³ = 1382.43 acre foot
Hence, the volume of water during a severe thunderstorm, fell on the town was 1382 acre foot.
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A ball starts from rest and rolls down a hill with uniform acceleration, traveling 200 m during the second 5.0 s of its motion. How fa...
The ball travels a distance of 200 meters during its journey down the hill. The acceleration of the ball rolling down the hill is 16 m/s².
The acceleration of the ball rolling down the hill can be calculated using the formula: Distance = (1/2) × Acceleration × Time². Here, the distance travelled by the ball = 200m. Time is taken by the ball to travel this distance = 5 seconds. As per the given information, the ball rolls down the hill with uniform acceleration, so the acceleration remains constant throughout the journey. Dist = (1/2) x a x t²200 = 0.5a x (5)²200 = 12.5 aSo, acceleration a = 200 / 12.5a = 16 m/s²As per the formula of motion s = ut + (1/2) × a × t², where s is the distance travelled by the object, u is its initial velocity, a is the acceleration of the object, and t is the time taken by the object to travel that distance. Here, the initial velocity of the ball is 0, as it starts from rest. So, s = (1/2) × a × t²s = 0.5 × 16 × 25s = 200 meters.
So, the distance travelled by the ball when it reaches the bottom of the hill is 200 meters. The ball starts from rest and rolls down the hill with uniform acceleration. During the second 5.0 seconds of its motion, it travels a distance of 200 meters. Using the formula for distance, we can find the acceleration of the ball. We get that the acceleration of the ball rolling down the hill is 16 m/s².Using the formula for motion, we can find the distance travelled by the ball when it reaches the bottom of the hill. We get that the distance travelled by the ball is 200 meters. Therefore, the ball travels a total distance of 200 meters during its journey down the hill. The ball travels a distance of 200 meters during its journey down the hill. The acceleration of the ball rolling down the hill is 16 m/s².
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A bicyclist starts from rest and accelerates along a straight path to a speed of 12. 15 m/s in a time of 4. 5 seconds. What is the bicyclist’s acceleration to the nearest tenth of a m/s2?.
A bicyclist starts from rest and accelerates along a straight path to a speed of 12. 15 m/s in a time of 4. 5 seconds. The bicyclist’s acceleration to the nearest tenth of a m/s2 is: C. 2.7 m/\(s^{2}\).
Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.
Mathematically, acceleration is given by the formula;
A=\(\frac{V-U}{t}\)
Substituting the given parameters into the formula, we have;
\(A=\frac{12.5-0}{4.5}\)
\(A=\frac{12.5}{4.5}\)
Acceleration, A = 2.7 \(m/s^{2}\)
Therefore, the cyclist's acceleration to the nearest tenth is 2.7 \(m/s^{2}\)
According to estimates of the power needed to ride, cyclists deliver about 150 W when riding level terrain, but this increases to about 250 W when cycling up hills.
On the flat, the average acceleration is 0.231 m/s2, and the average power output during the acceleration phase—which has an average duration of 26 s—is about 120 W.
Professional cyclists typically travel at 25 to 28 mph while on level ground. On flat ground, the average amateur cyclist moves at a speed of 17–18 mph.
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protons with momentum 50 gev/c are deflected through a collimator slit 2 mm wide by a bending magnet 1.5 m long that produces a field of 1.2 t. how far from the magnet should the slit be placed so that it accepts particles with momenta in the range 49–51 gev/c?
The slit should be placed approximately 2.4 x 10^-11 meters (or 24 picometers) from the magnet to accept particles with momenta in the range of 49-51 GeV/c.To determine the distance from the magnet at which the slit should be placed to accept particles with momenta in the range of 49-51 GeV/c, we can use the principle of magnetic deflection.
The deflection of charged particles in a magnetic field is given by the equation:
Δx = (p / (qB)) * L,
where Δx is the deflection, p is the momentum of the particle, q is the charge of the particle, B is the magnetic field strength, and L is the length of the bending magnet.
In this case, the slit width is 2 mm, so the acceptable deflection range is half of that, which is 1 mm.
We can rearrange the equation to solve for the distance from the magnet (d):
d = (Δx * q * B) / p.
Substituting the given values into the equation:
d = (0.001 m * (1.6 x 10^-19 C) * (1.2 T)) / (50 x 10^9 eV/c * 1.6 x 10^-19 C).
Simplifying the expression:
d = (0.001 m * 1.2 T) / (50 x 10^9 eV/c).
Calculating the result:
d ≈ 2.4 x 10^-11 m.
Therefore, the slit should be placed approximately 2.4 x 10^-11 meters (or 24 picometers) from the magnet to accept particles with momenta in the range of 49-51 GeV/c.
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