calculate PH.
1) [H3O+] = 6.7×10−8 M
2) [H3O+] = 2.0×10−7 M
3) [H3O+] = 2.2×10−6 M
4) [H3O+] = 3.4×10−4 M

Answer:

Deposition

Explanation:

Deposition is the phase transition in which gas transforms into solid without passing through the liquid phase. Deposition is a thermodynamic process. The reverse of deposition is sublimation and hence sometimes deposition is called desublimation.

The property of matter that is conserved in chemical reactions and shown by balanced equations is known as the Law of Conservation of Mass. According to this law, mass can neither be created nor destroyed in a chemical reaction; it can only be transformed from one form to another.For instance, when two substances are combined, they react and form a new substance.

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Answer:

. Name a soluble compound that could be added to precipitate all of the iron ions from the solution.

Sodium Hydroxide.

Answer:

Therefore, 2 moles of oxygen will be required to oxidize 2.66 moles of oxygen. 72g of Aluminium will be completely oxidized by 44.8 lit of oxygen at STP.

The noble-gas configurations that the elements would most likely attain in redox reactions are as follows: Lithium (Li) would achieve a helium (He) configuration, Aluminum (Al) and Potassium (K) would attain neon (Ne), Oxygen (O) would attain Ne, Phosphorus (P) would attain argon (Ar), Selenium (Se) could attain either Ar or krypton (Kr), and Strontium (Sr) would attain Kr. These configurations are determined by the tendency of each element to gain or lose electrons in order to achieve a stable electron configuration similar to that of the noble gases.

In redox reactions, elements undergo changes in their electron configurations by either gaining or losing electrons. To determine the noble-gas configuration they would most likely attain, we need to consider their valence electrons and their tendency to gain or lose electrons.

1. Lithium (Li): Lithium has one valence electron and tends to lose it to achieve a stable electron configuration. Therefore, it would most likely attain a helium (He) configuration by losing its valence electron.

2. Aluminum (Al): Aluminum has three valence electrons and tends to lose them to achieve stability. Hence, it would also attain a noble-gas configuration of neon (Ne) by losing all three valence electrons.

3. Oxygen (O): Oxygen has six valence electrons and tends to gain two electrons to achieve stability. It would attain the noble-gas configuration of neon (Ne) by gaining two electrons.

4. Phosphorus (P): Phosphorus has five valence electrons and tends to gain three electrons. Therefore, it would attain the noble-gas configuration of argon (Ar) by gaining three electrons.

5. Potassium (K): Potassium has one valence electron and tends to lose it to achieve stability. Hence, it would attain a noble-gas configuration of argon (Ar) by losing its valence electron.

6. Selenium (Se): Selenium has six valence electrons and can either gain two electrons to achieve a noble-gas configuration of krypton (Kr) or lose six electrons to attain a noble-gas configuration of argon (Ar). Both options are possible depending on the specific reaction conditions.

7. Strontium (Sr): Strontium has two valence electrons and tends to lose them to achieve stability. Therefore, it would attain a noble-gas configuration of krypton (Kr) by losing both valence electrons.

In summary, the noble-gas configurations for the elements are as follows:

Li: He

Al: Ne

O: Ne

P: Ar

K: Ar

Se: Ar or Kr

Sr: Kr

Complete Question : If the following elements were involved in redox reactions, which noble-gas configuration would they most likely attain?

Appropriate elements to their respective bins. ( He OR Ne OR Ar OR Kr ); for { Li, Al, O, P, K, Se, Sr }

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Answer:

Nitrogen, the next nonmetal, has 5 electrons in the valence shell, so it needs to combine with 3 hydrogen atoms to fulfill the octet rule and form a stable compound called ammonia (NH3).

The covalent compound formed from nitrogen and hydrogen is called ammonia with the formula NH₃.  Each hydrogen shares its valence electron with three valence electrons of nitrogen.

Ammonia,  NH₃ is a covalent compound formed by the combination of nitrogen and three hydrogen atoms. Nitrogen is a highly electronegative element with 5 valence electrons.

Nitrogen needs 3 more electrons to achieve octet. Hence valency of nitrogen is 3. During chemical bonding it gains three electrons though sharing or donation from metals.

Hydrogen needs one more electron to be stable. Hence, nitrogen shares its three valence electrons each with three hydrogens and each hydrogen in turn shares its one valence electron with nitrogen forming NH₃.

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Answer:

10.60 grams of silane gas are formed.

Explanation:

From the reaction:

Mg₂Si(s) + 4H₂O(l) → 2Mg(OH)₂(aq) + SiH₄(g)          

We know that the limiting reactant is Mg₂Si, so to find the mass of SiH₄ formed we need to calculate the number of moles of Mg₂Si:

\(\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}}\)

Where:

m: is the mass of Mg₂Si = 25.0 g

M: is the molar mass of Mg₂Si = 76.69 g/mol

\(\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}} = \frac{25.0 g}{76.69 g/mol} = 0.33 moles\)

Now, the stoichiometric relation between Mg₂Si and SiH₄ is 1:1 so:

\( \eta_{Mg_{2}Si} = \eta_{SiH_{4}} = 0.33 moles \)

Finally, the mass of SiH₄ is:

\( m_{SiH_{4}} = \eta_{SiH_{4}}*M_{SiH_{4}} = 0.33 moles*32.12 g/mol = 10.60 g \)

Therefore, 10.60 grams of silane gas are formed.

I hope it helps you!    

The enzymatic cycle has four steps, and they include the following;

1. The reaction between the Enzyme and Substrate

2. The substrate/enzyme complex formation

3. Catalysis

4. Enzyme releases a product

A small molecule will attach to the enzyme's active site and stop the action. The plants adapt by changing amino acid(s) in the enzyme. They adjust the structure and are continuously active; the small molecule cannot limit this enzyme.

The four steps in an enzyme cycle are;

1. The substrate and enzyme are found in one region. There are times when there is more than one substrate molecule and the enzyme changes.

2. The enzyme will then be trapped on the substrate in the special region called the active site. The combination is called substrate/enzyme complex. The active site will be in a shaped special region for the enzyme, which fits around a substrate.

3. Catalysis will happen when the Substrate changes. It can be broken down or combined with other molecules forming something new. It will break and form chemical bonds; afterward, a product/enzyme complex will occur.

4. The enzyme will release a product. When the enzyme is relaxed, it will return to its original shape and be ready to work on the other substrate molecule.

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Answer:

1.62 * 10^-11 J

Explanation:

Nitrogen-14 nucleus has seven neutrons and seven protons. So;

Total mass of protons = 7(1.00728 amu)

Total mass of neutrons = 7(1.00866 amu)

Total mass of nucleons = 7(1.00728 amu) + 7(1.00866 amu)= 14.11158 amu

Mass of Nitrogen-14 nucleus = 14.00307 amu

Mass defect = 14.11158 amu - 14.00307 amu = 0.10851 amu = 1.801852171 * 10^-28 Kg

Binding energy = Δmc^2

Where;

Δm = mass defect

c = speed of light

Binding energy = 1.801852171 * 10^-28 Kg * (3 * 10^8)^2

Binding energy = 1.62 * 10^-11 J

Answer:

0.10851 amu

1.62

-11

Explanation:

Yw

liquid drain cleaner is an alkaline base with a pH of 13.5, while milk is slightly acidic with a pH of 6.6.

Liquid drain cleaner with a pH of 13.5 is classified as a base. Substances with a pH above 7 are considered basic or alkaline, and a pH of 13.5 indicates a highly alkaline solution.

Milk, on the other hand, with a pH of 6.6, is slightly acidic. pH values below 7 are indicative of acidic substances. While milk is generally considered slightly acidic, its acidity is relatively mild and not noticeable to taste.

In summary, liquid drain cleaner is an alkaline base with a pH of 13.5, while milk is slightly acidic with a pH of 6.6.

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the formula below for the application of KVL around i1 is KVL around loop i1: -10V + 5Ω * (I1 - I2) + 10Ω * I1 = 0.

According to Kirchhoff's Voltage Law (KVL), the sum of the voltages around a closed loop in a circuit is equal to zero. In this case, we are applying KVL around loop i1. The equation represents the sum of voltage drops in the loop, where -10V is a voltage source, 5Ω * (I1 - I2) represents the voltage drop across the 5Ω resistor due to the difference in mesh currents I1 and I2, and 10Ω * I1 represents the voltage drop across the 10Ω resistor due to the current I1. The equation is set equal to zero to satisfy KVL.

ii. KVL around loop i2: 10Ω * I2 - 5Ω * (I1 - I2) + 2V = 0

Similar to i, this equation represents the application of KVL around loop i2. The 10Ω * I2 term represents the voltage drop across the 10Ω resistor due to the current I2, the -5Ω * (I1 - I2) term represents the voltage drop across the 5Ω resistor due to the difference in mesh currents I1 and I2, and the 2V term represents a voltage source. The equation is set equal to zero to satisfy KVL.

iii. Determine the current i1: Substitute the obtained values into the equation for i1 and solve for I1 in mA.

iv. Determine the current i2: Substitute the obtained values into the equation for i2 and solve for I2 in mA.

v. Determine Vo: Substitute the obtained values for i1 and i2 into the appropriate equation representing the voltage at Vo, and calculate the value in V.

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High-quality scientific research is characterized by several key criteria. Three examples of such criteria include: rigorous experimental design and methodology, reliable data analysis and interpretation, and clear and transparent reporting of results.

These criteria ensure that research is conducted in a systematic and reliable manner, leading to trustworthy and valid findings.

Rigorous Experimental Design and Methodology: High-quality scientific research requires a well-designed experimental approach. This involves careful planning, proper control groups, randomization, and replication. A rigorous methodology ensures that experiments are conducted under controlled conditions, minimizing bias and confounding variables, and allowing for accurate and reliable data collection.

Reliable Data Analysis and Interpretation: After data collection, high-quality research involves thorough and appropriate analysis of the data. This includes using appropriate statistical methods to evaluate the significance of the results and drawing valid conclusions. Proper data analysis helps researchers identify patterns, trends, and relationships, supporting or refuting their hypotheses in an objective and reliable manner.

Clear and Transparent Reporting of Results: High-quality research demands transparent reporting of the methods, procedures, and findings. This includes providing detailed descriptions of the experimental setup, data collection processes, and statistical analyses used. Clear reporting allows other researchers to replicate the study and verify its results. Additionally, complete reporting ensures that readers can understand the research methodology and draw their own conclusions based on the evidence presented.

By adhering to these criteria, high-quality scientific research maintains integrity, credibility, and reproducibility. It fosters trust among the scientific community and facilitates the advancement of knowledge by building upon reliable foundations.

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Answer:

by using the chromatography you can separate different color

Answer:

electrons

Explanation:

protons and neutrons are found in the nucleus while electrons circle around the nucleus

Therefore, the mass of the solid is 108.0 grams, not 38.852 grams as mentioned in the question. To solve this problem, we can use the concept of mass and volume to find the mass of the solid.

Let's assume the mass of the solid is "m" grams.

Given:

Volume of the solid + volume of the liquid = Total volume

Volume of the solid + 28.0 mL = 76.0 mL

So, the volume of the solid is:

Volume of the solid = Total volume - Volume of the liquid

Volume of the solid = 76.0 mL - 28.0 mL

Volume of the solid = 48.0 mL

We know the density of the solid is 2.25 g/mL. Therefore, we can calculate the mass of the solid using the formula:

Mass = Density × Volume

Mass of the solid = 2.25 g/mL × 48.0 mL

Mass of the solid = 108.0 g

Therefore, rather than the 38.852 grammes specified in the question, the solid's mass is 108.0 grammes.

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Answer:

B. reflection

Explanation:

Rigid transformations are methods involved in changing the dimensions or orientation of a given figure. The methods are; dilation, rotation, translation and reflection.

Reflection is the process in which a given figure is turned or flipped with respect to a point or line of reference.

In the given question,

ΔDEF ≅ ΔD'EF' (Side-Side-Side congruence property)

This implies that ΔDEF was reflected about point E to produce ΔD'EF'. Thus the required rigid transformation is reflection.

Answer:

Is C - Rotation

Explanation:

I have right on my test

The solubility of the potassium nitrate will increase as we increase the temperature because increases the kinetic energy of solute particles. More KNO₃ will dissolve in the solution and makes it unsaturated.

Solubility can be described as the maximum amount of Solute that can dissolve in a known quantity of solvent at a particular temperature. By changing the temperature we can increase the solubility of a solute. Sparingly soluble solids or liquids can be completely liquified by raising the temperature.

Solid solubility depends on the nature of the solute and the solvent. Substances such as sugar, common salt (NaCl), etc dissolve in water while substances such as naphthalene do not dissolve in water.

The solubility of potassium nitrate KNO₃ increases with an increase the temperature but the increasing temperature of NaCl solution does not show much change in the solubility of NaCl.

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30 ml volume of water have to add to 15. 0 ml of 12 m hcl to make it to 6. 0 m solution.

How do you calculate the volume of a solution needed?

Given data

So first we set up the dilution equation: M1*V1=M2*V2

M: Molarity

V: Volume

We can set these equal in a dilution equation because Molarity is Miles per Volume, and by multiplying it by Volume we get Moles on each side. Moles of solute remain equal throughout a dilution since you are just adding water.

Next, we plug in our knowns:

(12.00M HCl)(15.00ml)=(6.00M HCl)(V2)

V2 = 15 X 12 / 6 = 30ML

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Answer:

Sand comes from many locations, sources, and environments. Sand forms when rocks break down from weathering and eroding over thousands and even millions of years. Rocks take time to decompose, especially quartz (silica) and feldspar .

Explanation:

Answer:

a new substance was forming

Explanation:

The electron configuration of Si and Y are as follows;

Si = [Ne] 3s² 3p²

Y = [Kr] 4d¹5s²

Electron configuration of an element describes how electrons are distributed in its atomic orbitals.

Electron configurations of atoms follow a standard notation in which all electron-containing atomic subshells (with the number of electrons they hold written in superscript) are placed in a sequence.

For example, the electron configuration of sodium is 1s²2s²2p⁶3s¹.

The electron configuration of the following elements are given above.

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Answer:

3.00

Explanation:

1) The wavelength of the photon is 6.5 * 10^ -7 m

2) The final level is n =2

3) The number of photons is 1 * 10^ 22

Recall that we must first convert the energy to joules as follows;

1 eV = 1.6 * 10^ -19 J

1.89 eV = 1.89 eV * 1.6 * 10^ -19 J/ 1 eV

= 3.024 * 10^ -19 J

Again;

E = hc/λ

E = energy

h = Plank's constant

c = speed of light

λ = wavelength

3.024 * 10^ -19 J = 6.6 * 10^ -34 * 3 * 10^ 8/λ

λ = 6.6 * 10^ -34 * 3 * 10^ 8/3.024 * 10^ -19 J

= 6.5 * 10^ -7 m

2)

Now we have;

E = -RH (1/\(n_{2} ^{2}\) - 1/\(n_{1} ^{2}\))

RH = Rydberg constant

Initial level = 2

Final level = x

Energy =  1.89 eV or 3.024 * 10^ -19 J

3.024 * 10^ -19  = - 2.18 * 10^ -18 (1/x^2 - 1/4)

3.024 * 10^ -19 /2.18 * 10^ -18 = 1/4 - 1/x^2

0.139 = 1/4 - 1/x^2

0.139 = 0.25 - 1/x^2

0.139 -  0.25  = - 1/x^2

-0.111 = - 1/x^2

0.111 = 1/x^2

x^2 = 9

x = 3

3) Let us find the energy from;

E = 6.6 * 10^ -34 * 3 * 10^ 8/400 * 10^-9

E = 0.0495 * 10^- 17 J

E = 4.95 * 10^ -19 J

Then;

5,000 J = n4.95 * 10^ -19 J

n = 5,000 J/4.95 * 10^ -19 J

= 1 * 10^ 22

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Answer:

All except "How much money is in the bank?"

Explanation:

"What does the material consist of?"- this would be included because different materials are made of different elements.

"How does this material behave when it is heated?"- this can mean will it melt (the matter's state)? Explode (the chemical properties)? Which are all a part of chemistry!

"Why does sugar dissolve in water?"- water is a magnificent solvent! As you may know, polar-polar and nonpolar-nonpolar will "melt together." As the two molecules exchange energy, it causes the sugar to melt.

Keep up the learning!

Chemistry deals with the composition, behavior, and reactions of substances. Therefore, questions about a material's composition, how it reacts to heat, and why sugar dissolves in water are all relevant. A question about the amount of money in a bank, however, is not related to chemistry.

The subject of chemistry deals with several types of questions, mainly related to the composition, properties, and reactions of substances. This encompasses questions like 'What does this material consist of?', which refers to the atomic or molecular composition of a substance, as well as 'How does this material behave when it is heated?' representing discussions on how substances change under different conditions such as temperature changes. Furthermore, 'Why does sugar dissolve in water?' is a quintessential chemistry question investigating solvation processes, particularly in the context of polar and nonpolar substances.

However, the question 'How much money is in the bank?' does not fall under chemistry's purview as it pertains to financial matters, not the scientific study of matter and its interactions.

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One of the basic building blocks of matter, which cannot be broken down by chemical means is an element.

The first chemical element is hydrogen (atomic number is 1) and the last is oganesson (atomic number is 118).

Elements are scheduled in Periodic table, ordered by their atomic number.

Other example, krypton is a chemical element with symbol Kr and atomic number 36.

Krypton has 36 electron and 36. It is noble gas (group 18).

Noble gases are in group 18: helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe) and radon (Rn). They have very low chemical reactivity.

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The value of ΔH for the reaction CO(g) + H₂(g) + O₂(g) → CO₂(g) + H₂O(g) is -1272 kJ.

To calculate the enthalpy change (ΔH) for the given reaction, we can use Hess's law, which states that the overall enthalpy change of a reaction is equal to the sum of the enthalpy changes of the individual reactions involved.

Given the enthalpy changes:

1. 2 C(s) + O₂(g) → 2 CO(g)... ∆H = -222 kJ

2. C(s) + O₂(g) → CO₂(g)... ∆H = -394 kJ

3. 2 H₂(g) + O₂(g) → 2 H₂O(g)... ∆H = -484 kJ

We need to manipulate these reactions to obtain the desired reaction:

1. Reverse reaction 2: CO₂(g) → C(s) + O₂(g)... ∆H = +394 kJ

2. Multiply reaction 2 by 2 to balance carbon atoms: 2 CO₂(g) → 2 C(s) + 2 O₂(g)... ∆H = -788 kJ

3. Leave reaction 3 unchanged: 2 H₂(g) + O₂(g) → 2 H₂O(g)... ∆H = -484 kJ

By adding reactions 2 and 3, we obtain the desired reaction:

CO(g) + H₂(g) + O₂(g) → CO₂(g) + H₂O(g)... ∆H = -788 kJ + (-484 kJ) = -1272 kJ

Therefore, the value of ΔH for the given reaction is -1272 kJ.

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Generally, a literature review should aim to provide a comprehensive and up-to-date overview of the existing research and scholarly literature relevant to the research question or topic. This means that the number of studies or literatures included in a literature review will depend on factors such as the breadth and depth of the research question, the availability and relevance of existing research, and the scope of the research project.

It is important to ensure that the literature review is well-organized, critically analyzed, and clearly presented, regardless of the number of studies or literatures included. The focus should be on selecting high-quality and relevant sources, rather than simply aiming for a specific number of sources. A literature review should provide a thorough synthesis and analysis of the existing literature, and should demonstrate a clear understanding of the key debates, trends, and findings in the field.

The balanced equation for the reaction is: Cl2O7(s) + H2O(l) → 2HClO4(aq)

In this given reaction, solid Cl2O7 reacts with liquid water (H2O) to produce aqueous HClO4. HClO4 is a strong acid, meaning it completely dissociates into its ions in water, so it is a very strong electrolyte. Therefore, the product is a strong electrolyte.

The balanced equation shows that one molecule of Cl2O7 reacts with one molecule of H2O to produce two molecules of HClO4. The equation is balanced because there are equal numbers of atoms of each element on both the reactant and product sides of the equation.

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