The mass of 6.44 x 10⁻² mol of MnSO₄ is 972.44 x 10⁻² grams.
What is mass?Mass is the quantity of matter in a physical body. Mass can be calculated by multiplying the molar mass by the number of moles of the substance.
Here the moles are given and the molar mass can be calculated. Then put the value in the equation.
The molar mass of MnSO₄ is 151 g/mol
The number of moles is 6.44 x 10⁻²
Putting the value in the equation
moles = mass/molar mass
mass = moles x molar mass
mass = 6.44 x 10⁻² x 151 = 972.44 x 10⁻²
Thus, the mass of 2.88×10²² molecules of Bi (NO₃)₃ is 972.44 x 10⁻² grams.
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What is the volume of 16.0 g of SO2 (g) at STP?
Answer:
Explanation:
At STP 1 mole of an ideal gas = 22.4 L.
Assuming SO2 (sulfur dioxide) acts as an ideal as, we have 16 g SO2 x 1 mol/64 g = 0.25 moles SO2
0.25 moles x 22.4 L/mole = 5.6 liters
I need help please this is so confusing
The genotype probability is :
PP = 25 %
Pp = 50 %
pp = 25 %
Phenotype probability:
Purple color) = 75 %
white color = 25 %
What is the genotype and phenotype probability in a cross of parents with the genotype PP and Pp?The genotype of an offspring is the sum total of all the genes inherited from the parents.
The phenotype is the physical expression of that genotype.
Given that purple color P is dominant over white color, p in flowers, the cross between two heterozygous purple-colored flower plant, Pp will produce the following genotype and phenotype probabilities:
Pp x Pp = PP, Pp, Pp, pp
Genotype ratio will:
PP = 25 %
Pp = 50 %
pp = 25 %
Phenotype ratio:
Purple color (PP, Pp, Pp) = 75 %
white color (pp) = 25 %
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How
molecules of iron (iii) oxide
many
can be produced from 13.5 moles fe?
The number of molecules of iron (iii) oxide F₂O₃ that can be produced from 13.5 moles of Fe is 4.06×10²⁴ molecules
Balanced equation4Fe + 3O₂ —> 2F₂O₃
From the balanced equation above,
4 moles of Fe reacted to produce 2 moles of F₂O₃.
Therefore,
13.5 moles of Fe will react to produce = (13.5 × 2) / 4 = 6.75 moles of F₂O₃
How to determine the number of molecules of F₂O₃ produced
From Avogadro's hypothesis,
1 mole of F₂O₃ = 6.02×10²³ molecules
Therefore,
6.75 moles of F₂O₃ = 6.75 × 6.02×10²³
6.75 moles of F₂O₃ = 4.06×10²⁴ molecules
Thus, 4.06×10²⁴ molecules of F₂O₃ were obtained from the reaction
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calculate the rf value for a spot in a chromatography experiment if the solvent moved 13.1 cm and the spot moved 9.5 cm from the origin.
The rf value for a spot in a chromatography experiment if the solvent moved 13.1 cm and the spot moved 9.5 cm from the origin is 0.73.
What is chromatography ?
Separating ingredients in a mixture using chromatography is a procedure. The mixture is dissolved in the mobile phase, which starts the process off, and then transports it through the stationary phase, which is the final phase.
What is experiment ?
A scientific experiment is a test carried out to ascertain what occurs to a subject under a given set of circumstances.
Therefore, rf value for a spot in a chromatography experiment if the solvent moved 13.1 cm and the spot moved 9.5 cm from the origin is 0.73.
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fire extinguishers that can be used on any type of fire, a, b, or c generally contain a to extinguish the fire. a. water b. carbon dioxide c. nitrogen d. dry chemical powder
Answer:
b? im pretty sure
Explanation:
A sample of chlorine gas occupies a volume of 0.025L at 300 K. At 600K, what will the volume be?
A)808 L
B)50 L
C)0.050 L
D)0.088 L
Answer: The volume at 600 K will be 0.050 L.
Explanation:
Given: \(V_{1}\) = 0.025 L, \(T_{1}\) = 300 K
\(V_{2}\) = ?, \(T_{2}\) = 600 K
Formula used is as follows.
\(\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\)
Substitute the values into above formula as follows.
\(\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{0.025 L}{300 K} = \frac{V_{2}}{600 K}\\V_{2} = 0.050 L\)
Thus, we can conclude that the volume at 600 K will be 0.050 L.
Assess two situations in which it is important to question scientific issues in the media.
Answer:
Claims based on vague statements and statements from non-experts.
Explanation:
An old refrigerator is rated at 500 W how many kilowatt hours of electric energy what does refrigerator use in 30 days assume the refrigerator is running 12 hours per day
The refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.
To calculate the kilowatt-hours (kWh) of electric energy used by the refrigerator in 30 days, we need to multiply the power rating by the total running time.
Given:
Power rating of the refrigerator = 500 W
Running time per day = 12 hours
Number of days = 30
First, we need to convert the power rating from watts to kilowatts:
Power rating = 500 W / 1000 = 0.5 kW
Next, we calculate the total energy used in kilowatt-hours (kWh) over the 30-day period:
Energy used = Power rating × Running time × Number of days
Energy used = 0.5 kW × 12 hours/day × 30 days
Energy used = 180 kWh
Therefore, the refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.
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bile salts are among the lipid class known as __________.
The lipid class known as steroids consists of bile salts.
The steroid lipids are a class of lipids that contain a sterol or steroid backbone. Steroids are lipids that have a fundamental structure of four fused rings with numerous other biological functions. The steroid backbone comprises of three six-membered rings and one five-membered ring fused in a distinct formation known as a cyclopentaneperhydrophenanthrene structure.
Examples of steroid lipids include bile salts, cholesterol, vitamin D, and various hormones such as testosterone and estrogen. Bile salts are synthesized from cholesterol in the liver and metabolized by intestinal bacteria. Bile salts are significant for the absorption of dietary fats and the transport of waste materials out of the liver and into the gut. Bile salts also help in the digestion of fats by emulsifying them and allowing them to be dissolved in the digestive fluids. In addition, they are utilized in the production of steroid hormones by the adrenal gland.
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pls help asap
complete the square too rewrite the following equation. Identify the centers and radius of the circle. You must show l work and calculations too receive full credit.
x2+2x+y2+4y=20
Given the equation `x² + 2x + y² + 4y = 20`, complete the square to rewrite it and identify the centers and radius of the circle. The answer to the question is
Completing the square:
[x^2 + 2x + y^2 + 4y = 20\]\[x^2 + 2x + 1 - 1 + y^2 + 4y + 4 - 4 = 20\]\[(x + 1)^2 + (y + 2)^2 = 25\]
This equation is in the standard form of a circle, that is:
[(x - h)^2 + (y - k)^2 = r^2\]
where `(h, k)` is the center of the circle and `r` is its radius.
The equation of the given circle is \[(x + 1)^2 + (y + 2)^2 = 5^2\].
Therefore, the center of the circle is `(-1, -2)` and its radius is `5`.
We are given the equation x² + 2x + y² + 4y = 20 and we need to complete the square to rewrite the equation and identify the center and radius of the circle. We know that the standard form of a circle is (x - h)² + (y - k)² = r².
To transform the equation into the standard form of the circle, we need to complete the square. We can complete the square by adding and subtracting (1 + 4) on the left-hand side of the equation, which is equal to adding and subtracting 5 (5 is half of the coefficient of y) on the right-hand side of the equation.
This gives us:(x² + 2x + 1) - 1 + (y² + 4y + 4) - 4 = 20 + 5 - 5(x + 1)² + (y + 2)² = 25
This simplifies to:(x + 1)² + (y + 2)² = 5², which is in the standard form of a circle.
Therefore, the center of the circle is (-1, -2) and its radius is 5.
In conclusion, we have found that the equation of the given circle is (x + 1)² + (y + 2)² = 5². We have also found that the center of the circle is (-1, -2) an;
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six line to obtain energy
Answer:
energy, in physics, the capacity for doing work. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another. ... For example, any given body has kinetic energy if it is in motion.
Explanation:
please mark my answer in brainlist
Oxidation States of Manganese Use the half-reaction method to determine the net-ionic redox reaction between the permanganate ion and the bisulfite ion in test tube #5. АР B I U S IX S2 I
the net-ionic redox reaction between permanganate ion and bisulfite ion in test tube #5 is MnO4− + 5HSO3− + 8H+ → MnSO4 + 5SO42− + 4H2O.
Manganese has multiple oxidation states. The most important ones are +2, +4, +6, and +7. In order to determine the net-ionic redox reaction between permanganate ion and bisulfite ion in test tube #5, we first write a balanced equation for the reaction that will occur between these two ions. To balance the equation, we will first write the oxidation states of manganese for both the permanganate and bisulfite ions. Oxidation States of Manganese: Manganese has an oxidation state of +7 in permanganate ion and +4 in MnSO4 (produced by the reaction).
Half Reactions: Next, we need to separate the reaction into two half-reactions: one for oxidation and one for reduction. The half-reaction for oxidation is:
MnO4− → MnSO4 + H2O + e−
The half-reaction for reduction is:
H+ + HSO3− + e− → SO42− + H2O
Combining the two half-reactions, we get:
MnO4− + 8H+ + 5HSO3− → MnSO4 + 5SO42− + 4H2O
Thus, the net-ionic redox reaction between permanganate ion and bisulfite ion in test tube #5 is
MnO4− + 5HSO3− + 8H+ → MnSO4 + 5SO42− + 4H2O.
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What is the value for the activation energy of the reaction using the information in the table?
The activation energy is 101, 800J/mol
What is the activation energy?Activation energy is the minimum amount of energy required to start a chemical reaction by breaking the bonds of the reactant molecules. In other words, it is the energy barrier that must be overcome before a chemical reaction can occur.
Given that;
\(ln(k2/k1) = -Ea/R(1/T2 - 1/T1)\\ln(5 * 10^-4/4.9 * 10^-3) = -Ea/8.314(1/318 - 1/336)\\-2.28 = -2 * 10^-5 Ea\\Ea = 2.28/2 * 10^-5\\Ea = 101, 800J/mol\)
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do the
math!
Wavelength Frequency
Speed
Medium
200 Hz
1500 m/s
The table shows measurements of
some properties of a sound wave in
water and in air.
Water
400 Hz
3.75 m
Water
343 m/s
Air (20°C)
10 m
Calculate Using what you know
about the relationship between
wavelength, frequency, and speed,
fill in the table.
17.15 Hz
343 m/s
Air (20°C)
1a
CHALLENGE What can this table
tell
you about the speed of a wave?
Answer:
everything can be found in the picture
Now that the chemical reaction is balanced, find the stoichiometric ratio of the reactants.
Answer: A
Explanation: A
Two students, Will N. Andable and Ben Pumpiniron, are in the weightlifting room. Will
lifts the 100 lb barbell over his head 10 times in one minute; Ben lifts the 100 lb pound
barbell over his head 10 times in 10 seconds. Which student does the most work? Which
student delivers the most power? Explain your answers.
Both students do the same amount of work since they lifted the barbell over their heads the same number of times.
Ben developed more power because he took less time to do the same amount of work.
What is the formula for calculating mechanical power?The formula for calculating mechanical power is given below as follows:
Power = force * distance/time taken
The power of each of the students is calculated as follows:
Assuming the work done by both students is approximated to the weight of the barbell, the power developed by each student will depend only on the time.
Power developed by Will:
Will lifts the 100 lb barbell over his head 10 times in one minute
Ben lifts the 100 lb pound barbell over his head 10 times in 10 seconds
The time taken by Ben to lift the 100 lb pound barbell over his head 10 times in 10 seconds is less than the time taken by Will to lift the 100 lb pound barbell over his head 10 times in 10 seconds, Hence, Ben developed more power.
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Light travels at a speed of 3.00 x 100 ^10 cm/s. What is the speed of light in kilometers/hour?
Answer:
1.1 x \(10^{9}\) km/h
Explanation:
Here we need to do two conversions- one from centimetres to kilometres and one from seconds to hours.
To get from cm to km- we divide by 100 000 since there are 100 000 cm in a km.
To get from seconds to hours we divide by 3600 since there are 3600 seconds in an hour
\(\frac{3*10^{10}cm/100000 }{1second/3600} =1.1*10^{9} km/h\)
In step 5, of the experiment, a student accidentally added 2.0g of Mg metal instead of Zn, to react with 5.0g of CuSO4 . How will this affect the result of the experiment?
A. The copper (II) sulfate solution would react with the Mg, because Cu is less active than Mg. However, the excess Mg would not react with the 6M HCl because Mg is less active than hydrogen.
B. There will be no effect in the final result, all the copper (II) sulfate will be converted to Cu.
C. The copper (II) sulfate solution would react with the Mg, because Cu is less active than Mg. However, not all the copper (II) sulfate was reacted to form Cu.
D. The copper (II) sulfate solution would not react with the Mg. This is because Cu is more active than Mg.
When a student accidentally adds 2.0g of Mg metal instead of Zn to react with 5.0g of \(CuSO_4\), the copper (II) sulfate solution would react with the Mg, because Cu is less active than Mg. However, not all the copper (II) sulfate reacted to form Cu. Therefore, option C is the correct answer
\(CuSO_4 + Mg \rightarrow Cu + MgSO_4\)
Copper (II) sulfate reacts with magnesium to form copper and magnesium sulfate, and the reaction is exothermic. As a result, the temperature of the solution increases.
When magnesium is added to a copper (II) sulfate solution, the magnesium displaces copper from copper (II) sulfate, forming magnesium sulfate and copper.
The addition of magnesium instead of zinc means that the copper (II) sulfate solution would react with magnesium rather than zinc. Magnesium has a lower reactivity than zinc, which means that it will displace copper from copper (II) sulfate instead of zinc.
However, not all the copper (II) sulfate will be reacted to form copper, since only a portion of the copper (II) sulfate is consumed by the reaction with magnesium.
Therefore correct option is c " the copper (II) sulfate solution would react with the Mg, because Cu is less active than Mg. However, not all the copper (II) sulfate was reacted to form Cu."
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Calculate the number of formula units of silver needed to react with chlorine to produce 84.3 g of silver chloride
To produce 84.3 g of silver chloride, we need 3.53 x 10^23 formula units of silver. The number of formula units of silver needed to react with chlorine to produce 84.3 g of silver chloride, we first need to determine the molar mass of silver chloride.
The molar mass of silver chloride (AgCl) can be calculated by adding the atomic masses of silver (Ag) and chlorine (Cl) together. The atomic mass of silver is 107.87 g/mol, and the atomic mass of chlorine is 35.45 g/mol.
The molar mass of AgCl = 107.87 g/mol + 35.45 g/mol = 143.32 g/mol.
moles = mass/molar mass
So, moles of AgCl = 84.3 g / 143.32 g/mol = 0.588 moles.
Since the balanced chemical equation for the reaction between silver and chlorine to form silver chloride is:
2 Ag + Cl2 → 2 AgCl
We know that 2 moles of Ag react with 1 mole of Cl2 to produce 2 moles of AgCl.
The number of moles of Ag required to produce 0.588 moles of AgCl is: moles of Ag = 2/2 x moles of AgCl = 0.588 moles of Ag . The number of formula units of Ag required can be calculated by multiplying the number of moles of Ag by Avogadro's number (6.022 x 10^23).
Number of formula units of Ag = 0.588 moles x 6.022 x 10^23 = 3.53 x 10^23 formula units of Ag.
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If unshaded and shaded orbitals/lobes represent different phases, which pair of orbitals will combine to create a bonding molecular orbital
In molecular orbital theory, the combination of atomic orbitals of the same phase (either both positive or both negative) leads to the formation of a bonding molecular orbital (MO), while the combination of atomic orbitals of opposite phases (one positive and one negative) leads to the formation of an antibonding molecular orbital.
Molecular orbital theory is a fundamental concept in physics and chemistry that describes the behavior of electrons in molecules. It is based on the idea that electrons in a molecule are not just localized around individual atoms, but can also occupy regions of space between the atoms, forming molecular orbitals. These molecular orbitals arise from the combination of atomic orbitals of the constituent atoms.
According to molecular orbital theory, the electrons in a molecule are distributed among these molecular orbitals in a way that minimizes the overall energy of the molecule. This distribution of electrons determines many of the physical and chemical properties of the molecule, including its shape, reactivity, and electronic structure.
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help here is 50 points
copy and paste words under here ill do it
I give Brainliest!
A stack of atoms on the periodic table is a column. Another name for this is a ________________.
5+64
this is TOTALLY SOOOO hard so help me
^thats what she said
Answer:
69
Explanation:
I thought that I answer is correct
Answer:
The answer is 69
Explanation:
Because if you add one its 66, and so on, hope this helps! but if you add five it will be 69, if you need help with easy equations let me know
Antarctica is a frozen land so cold and I see no changes in Wheeler scientist have discovered fossils
Answer:
The correct answer is - due to the movement of plates it is relocated.
Explanation:
Antarctica is a very cold part of the earth, it is so cold that there is no growth of trees or such vegetation. Even though there are no or less vegetation scientists found fossils of the trees.
It is relocated from the north where the conditions were warmer and easy for tree growth. It is then moved due to plate movements to the south pole. This is the reason behind the fossils scientist found.
Methane, ch 4 , is the gas commonly found in labs to fuel bunsen burners. how many moles of methane are there in a 7.21 gram sample?
There are approximately 0.4495 moles of methane in a 7.21 gram sample. To calculate the number of moles of methane in a given sample, you need to divide the mass of the sample by the molar mass of methane.
The molar mass of methane (CH4) can be calculated by summing up the atomic masses of its constituent elements:
Molar mass of C (carbon) = 12.01 g/mol
Molar mass of H (hydrogen) = 1.008 g/mol
Molar mass of methane (CH4) = (1 × Molar mass of C) + (4 × Molar mass of H)
= (1 × 12.01 g/mol) + (4 × 1.008 g/mol)
= 16.04 g/mol
Now, we can calculate the number of moles of methane using the following formula:
Number of moles = Mass of sample / Molar mass
Plugging in the values:
Number of moles = 7.21 g / 16.04 g/mol
≈ 0.4495 mol (rounded to four decimal places)
Therefore, there are approximately 0.4495 moles of methane in a 7.21 gram sample.
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Which joint in the human body is similar to the chicken wing joint?
The joint in the human body which is similar to the chicken wing joint is referred to as the elbow joint.
What is a Joint?This is referred to as a point where two or more bones meet and are usually lined with cartilages so as to reduce the effect of friction as it causes wear and tear of the skeletal structures which are important for our movement.
The chicken has a structure called wing as its hands which is therefore the reason why it is similar to that of the elbow joint in humans and makes it the correct choice.
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5. Calculate the pСa when 35 mL of 0.009 M Cat2 is titrated with 0.022 M EDTA (as for EDTA at pH=10 is 0.35) in a solution buffered to a constant pH= 10 when the volume of EDTA added is 48 mL. K; CaY-2 = 5.0 x 1010. a. 2.05 b. 1.9 c. 10.8 d. 10.6 11.1
pCa when 35 mL of 0.009 M Cat2 is titrated with 0.022 M EDTA = 8.442. Balanced chemical equation when EDTA is added to the Ca²⁺ solution, the equation is shown below: Ca²⁺+ EDTA⁴⁻ → CaEDTA²⁻. Hence, the correct option is d)10.6
Calculation of pСa when 35 mL of 0.009 M Cat2 is titrated with 0.022 M EDTA (as for EDTA at pH=10 is 0.35) in a solution buffered to a constant pH= 10 when the volume of EDTA added is 48 mL is shown below: Given, Volume of Ca2+ = 35 ml
Concentration of Ca²⁺ = 0.009 M, Volume of EDTA added = 48 ml
Concentration of EDTA = 0.022 M,
pH = 10KCaY-2
= 5.0 x 10¹⁰
To calculate the pCa we have to follow these steps:
First, write down the balanced chemical equation for the reaction that occurs when EDTA is added to the Ca²⁺ solution, the equation is shown below: Ca²⁺+ EDTA⁴⁻ → CaEDTA²⁻
Kf = [CaEDTA²⁻] / ([Ca²⁺] [EDTA⁴⁻])
Initial concentration of Ca²⁺ = 0.009 M
Initial volume of Ca²⁺ = 35 ml, Initial amount of Ca²⁺ = 0.009 × 35
= 0.315 mmol
Final volume of Ca²⁺ = 35 + 48
= 83 ml
Thus, final concentration of Ca²⁺ = 0.315 / 83
= 0.003795 M
In the presence of excess EDTA, the entire amount of Ca²⁺ reacts with EDTA.
Thus,[EDTA⁴⁻] = 0.022 × 48 / 1000
= 0.001056 mol[Ca²⁺]
= 0.003795 mol,
Kf = 5 × 10¹⁰
We have to calculate the [CaEDTA²⁻] at the end point and then convert it into [Ca²⁺] to calculate pCa. Using the equation of equilibrium constant ;Kf = [CaEDTA²⁻] / ([Ca²⁺] [EDTA⁴⁻])
Here,[CaEDTA²⁻] = unknown[Ca²⁺]
= 0[EDTA]
= 0.001056 mol/L
When the end point is reached, all Ca²⁺ is reacted with EDTA to form CaEDTA²⁻.
Thus, moles of EDTA⁴⁻ used = 0.003795 × 83
= 0.315 mmol
Moles of CaEDTA²⁻ formed = 0.315 mmol
Thus, [CaEDTA²⁻] = moles of CaEDTA²⁻ formed / volume
= 0.315 / 83
= 0.003795 M
Now, substituting these values in the equilibrium constant expression;5 × 10¹⁰ = [0.003795] / [(0.001056) (0)]
Thus, [Ca²⁺] = [CaEDTA²⁻]
= 3.607 × 10⁻⁹ M
We know that pCa = -log [Ca²⁺]
Thus, pCa = -log 3.607 × 10⁻⁹
= 8.442 (approx)
Hence, the correct option is d)10.6
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Help!! Need it asap thankyou!
Answer:
ano gagawin dyan? HAAHAHA
Which best describes global CO2 emissions?
O A. The amount of CO2 released by humans has increased over the
last 200 years.
B. There are no fuels that release CO2 when burned.
C. Humans have reduced the amount of CO2 in the atmosphere.
D. Humans have stopped releasing CO2 into the atmosphere.
Which best describes global cO2 emission
Answer:
The amount of CO2 released by humans has increased over the
last 200 years.
Hope it helps!!!
Answer:
A. The amount of CO2 released by humans has increased over the
last 200 years.
Is my answer correct?
Yes the ANSWER is Correct-
On first half life the mass will be 10 gram
On second half life the mass will be 5 gram
On third half life the mass will be 2.5 gram