C3H8 +02 → CO2 + H20
O Single Replacement
O Decomposition
O Double Replacement
O Combustion

The number of moles of chlorine in a 67.2 liter sample at STP (Standard Temperature and Pressure), is approximately 3 moles.

We need to use the ideal gas law and the molar volume of a gas at STP.

STP conditions are defined as a temperature of 273.15 Kelvin (0 degrees Celsius) and a pressure of 1 atmosphere (1 atm).

The molar volume of a gas at STP is approximately 22.4 liters/mol.

Given:

Volume of the sample = 67.2 liters

We can use the formula:

n = V / Vm

where:

n = number of moles

V = volume of the sample

Vm = molar volume at STP (22.4 liters/mol)

Now, let's calculate the number of moles:

n = 67.2 L / 22.4 L/mol

n ≈ 3 moles

Therefore, there are approximately 3 moles of chlorine in a 67.2 liter sample of chlorine at STP.

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Answer:

Friction

Explanation:

In the research scenario, Dora's father uses engine oil to shield engine pumps from friction and injury. Friction is a force among contact objects that slip or threaten to slide over each other.

Take approximately 12.5 ml of the concentrated stock solution to prepare the diluted solution.

To determine the volume of the concentrated stock solution needed to prepare a diluted solution, we can use the formula:

(Volume of concentrated stock solution) * (Concentration of concentrated stock solution) = (Volume of diluted solution) * (Concentration of diluted solution)

In this case, we know that:
- Concentration of concentrated stock solution = 4.8 M
- Concentration of diluted solution = 0.6 M
- Volume of diluted solution = 100 ml

Let's substitute these values into the formula and solve for the volume of concentrated stock solution:

(4.8 M) * (Volume of concentrated stock solution) = (0.6 M) * (100 ml)

Divide both sides of the equation by 4.8 M:

Volume of concentrated stock solution = (0.6 M * 100 ml) / 4.8 M

Simplify:

Volume of concentrated stock solution = (60 ml) / 4.8

Divide 60 ml by 4.8:

Volume of concentrated stock solution = 12.5 ml

So, you will need to take approximately 12.5 ml of the concentrated stock solution to prepare the diluted solution.

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Answer:

go to google

Explanation:it all wayys works

Answer:

Chlorine (Cl)

The Cl−P−Cl angle for two adjacent Cl atoms in PCl₆⁻ (hexachlorophosphate ion) is approximately 90 degrees.

In the PCl₆⁻ ion, phosphorus (P) is surrounded by six chlorine (Cl) atoms. The geometry of the ion can be described as octahedral, with the P atom at the center and the six Cl atoms at the vertices of an octahedron.

In an octahedral geometry, the bond angles between the central atom (P) and the surrounding atoms (Cl) are generally around 90 degrees. This includes the Cl−P−Cl angles for adjacent Cl atoms in the PCl₆⁻ ion.

Therefore, the Cl−P−Cl angle for two adjacent Cl atoms in PCl₆⁻ is approximately 90 degrees.

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Answer:

A-cycles of the moon

Explanation:

The people of Ancient Greece, Rome and China counted their year based on a 12 moon cycle ( that is, about 354 days). A 13th cycle of the moon is included so that the lunar year remains in step with the seasons of the year.

Today, the Gregorian calendar is mostly used around the world. This calendar was

actually adapted from an earlier lunar version. Ancient civilizations used the phases of the moon to help identify the seasons.

The major difference between the lunar calendar and the solar calendar is the kind of celestial body that is used to determine time.

The approximate normal boiling point of 2-chloroheptane can be determined using a vapor pressure nomograph. Given that the boiling point of 2-chloroheptane is 46 °C at 19 mmHg, we can use the nomograph to estimate the boiling point at normal atmospheric pressure.

1. The vapor pressure nomograph is a graphical representation that relates the boiling point and vapor pressure of a substance at different pressures. To estimate the normal boiling point, we need to determine the vapor pressure at standard atmospheric pressure (760 mmHg) using the given data.

2. On the vapor pressure nomograph, locate the point representing 19 mmHg on the y-axis and draw a horizontal line to intersect with the diagonal line representing the normal boiling point. From this intersection, draw a vertical line down to the x-axis to determine the temperature corresponding to 19 mmHg.

3. By estimating the intersection point, we find that the temperature is approximately 46 °C at 19 mmHg. Since the normal boiling point is defined as the boiling point at atmospheric pressure (760 mmHg), we can approximate the normal boiling point of 2-chloroheptane to be around 46 °C.

4. It's important to note that the accuracy of this approximation depends on the precision and reliability of the vapor pressure nomograph used.

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Answer:

the volume that the gas occupy at 7.47 atm is  0.1564 liters

Explanation:

The computation of the volume that the gas occupy at 7.47 atm is shown below:

As we know that

P1V1 = P2V2

Now

V2 = P1V1 ÷ P2

= 2.05 atm × 0.570 liters ÷ 7.47 atm

= 0.1564 liters

Hence, the volume that the gas occupy at 7.47 atm is  0.1564 liters

So the same would be considered and relevant

The main reservoirs of the carbon cycle are the atmosphere, oceans, land (including vegetation and soils), and fossil fuels. In these reservoirs, carbon exists in both inorganic and organic forms.

The inorganic carbon cycle involves the exchange of carbon dioxide (CO2) between the atmosphere and oceans through processes like photosynthesis and respiration.

Organic carbon, on the other hand, is found in living organisms, dead organic matter, and soil organic matter. It is cycled through processes such as decomposition and consumption by organisms. The interactions between the inorganic and organic carbon cycles occur primarily in the biosphere, where photosynthesis converts inorganic carbon into organic carbon compounds. While inorganic carbon is primarily in the form of CO2, organic carbon is present in complex organic molecules. Both forms of carbon play crucial roles in energy transfer, nutrient cycling, and climate regulation.

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The pressure (in atm) inside the aerosol container obtained is 5.24 atm

101.325 KPa = 1 atm

The pressure inside the aerosol container in atm can be obtained as illustrated below:

101.325 KPa = 1 atm

Therefore,

531 KPa = 531 / 101.325

531 KPa = 5.24 atm

Thus, 531 KPa is equivalent to 5.24 atm

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A 0.0333-liter sample of gold would weigh 0.64326 grams.

This is calculated by multiplying the density of gold by the volume of the sample.

the density of gold = 19.32g/ml

the volume of the sample = 0.0333 L

sample weight = the density of gold × the volume of the sample

which is  19.32g/ml  ×  0.0333 L = 0.64326

In chemistry, density is a measure of the mass of a substance per unit of volume. It is typically represented by the Greek symbol "rho" (ρ) and is typically measured in units of grams per milliliter (g/mL) or grams per cubic centimeter (g/cm^3). A substance's density can be calculated by dividing its mass by its volume.

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.

The pH of the buffer solution containing 0.225 M acetic acid and 0.375 M sodium acetate is approximately 4.96 and after the addition of 10.0 ml of 0.318 M NaOH to the 100.0 ml buffer solution, the pH is approximately 4.90.

To calculate the pH of a buffer solution containing acetic acid (CH3COOH) and sodium acetate (CH3COONa), we need to consider the equilibrium between the weak acid and its conjugate base. The dissociation of acetic acid can be represented by the equation:

CH3COOH ⇌ CH3COO- + H+

The pH of a buffer solution can be calculated using the Henderson-Hasselbalch equation:

pH = pKa + log ([A-]/[HA])

where pKa is the negative logarithm of the acid dissociation constant (Ka), [A-] is the concentration of the conjugate base, and [HA] is the concentration of the weak acid.

In this case, acetic acid is a weak acid with a pKa of 4.74. The given concentrations are 0.225 M for acetic acid ([HA]) and 0.375 M for sodium acetate ([A-]). Plugging these values into the Henderson-Hasselbalch equation, we can calculate the pH of the buffer solution.

pH = 4.74 + log (0.375/0.225)

pH = 4.74 + log (1.67)

pH ≈ 4.74 + 0.221

pH ≈ 4.96

Therefore, the pH of the buffer solution containing 0.225 M acetic acid and 0.375 M sodium acetate is approximately 4.96.

In the second part of the question, we need to determine the pH of the buffer solution after adding 10.0 ml of 0.318 M NaOH to 100.0 ml of the buffer. Since NaOH is a strong base, it will react with the weak acid (acetic acid) in the buffer to form the conjugate base (acetate ion) and water. This reaction consumes the weak acid and shifts the equilibrium towards the conjugate base.

To calculate the new pH, we need to consider the change in concentration of the weak acid and the conjugate base. From the given volumes and concentrations, we can determine the moles of acetic acid and acetate ion:

Moles of acetic acid = 0.225 M × 0.100 L = 0.0225 mol

Moles of acetate ion = 0.375 M × 0.100 L = 0.0375 mol

After the addition of 10.0 ml (0.010 L) of 0.318 M NaOH, we can calculate the new concentrations:

New concentration of acetic acid = (0.0225 mol - 0.010 L × 0.318 mol/L) / (0.100 L + 0.010 L) = 0.195 M

New concentration of acetate ion = (0.0375 mol + 0.010 L × 0.318 mol/L) / (0.100 L + 0.010 L) = 0.285 M

Using the Henderson-Hasselbalch equation with the new concentrations, we can calculate the new pH:

pH = 4.74 + log (0.285/0.195)

pH = 4.74 + log (1.46)

pH ≈ 4.74 + 0.164

pH ≈ 4.90

Therefore, after the addition of 10.0 ml of 0.318 M NaOH to the 100.0 ml buffer solution, the pH is approximately 4.90.

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Explanation:

.200 L  *  7.5 moles / L = 1.5 moles of NaCl

Each mole of NaCl weighs 22.99 + 35.45 =58.44 gm/mole

58.44 gm/mole * 1.5 mole = 87.66 gm

The absence of radioactivity in the first acid-soluble supernatant indicates that the radioisotopes or radioactive substances present in the sample did not dissolve or become soluble in the acidic solution used for the extraction.

There could be several reasons for this lack of radioactivity in the acid-soluble supernatant:

Insolubility: The radioisotopes or radioactive substances in the sample may have low solubility in the acidic solution. This could be due to their chemical nature or specific properties that prevent them from dissolving or forming soluble compounds under acidic conditions.

Chemical Bonding: The radioisotopes or radioactive substances in the sample may form strong chemical bonds with other components present in the sample or the solid matrix. These bonds could be resistant to dissolution in the acidic solution, leading to the absence of radioactivity in the acid-soluble fraction.

Experimental Limitations: It is possible that the extraction process or experimental conditions used were not suitable for extracting the specific radioisotopes or radioactive substances present in the sample. The extraction method employed may not be effective in dissolving or releasing the target radioisotopes from the solid matrix.

To confirm the exact reason for the absence of radioactivity in the acid-soluble fraction, further investigation and analysis would be necessary. Different extraction methods or conditions may need to be explored to determine the solubility or extractability of the specific radioactive substances in the sample.

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Answer:All matter consists of small particles which are in a continual state of motion

Explanation

Answer:

C

Explanation:

Adding another Li will balance the equation

2LiNO3 + CaBr2 → Ca(NO3)2 + 2LiBr

Answer:

11 A

Explanation:

⇒ V = IR

⇒ 110 V = I * 10 Ω

⇒ I = 110/10

⇒ I = 11 A

The current flowing through the frying pan is equal to when 110 Volts are connected to the circuit.

Ohm’s law can be described as the voltage difference across any conductor being directly proportional to the electric current passing through that conductor. Assuming temperature and other conditions remain constant.

Ohm’s law can be applied only if the temperature will be constant. Ohm’s S.I. unit is rho (Ω), and the electric current raises the temperature.

The mathematical expression of voltage difference provided by Ohm's law is:

V = IR

Where V is the voltage difference and R is the resistance and I the electric current flowing.

Given, the voltage difference of the circuit,  V = 110 V

The resistance flowing through the circuit, R = 10 Ω

The electric current flowing through the frying pan can be calculated as:

I = V/R

I = 110/10

I = 11 A

Therefore, the electric current across the circuit is equal to 11 A.

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Answer:

An equation for a chemical reaction in which the number of atoms for each element in the ... sulfide: 8 Fe + S8 ---> 8 FeS o _____ DECOMPOSITION _____: Definition - A single ... Hydrogen peroxide will produce water and oxygen gas if left in sunlight. (a) ... Sodium oxide reacts with carbon dioxide to form sodium carbonate.

sorry if wrong:(

Explanation:

Answer:

A metal is said to be an active metal when it reacts strongly and quickly with other elements due to the electrons in its structure and its ease of sharing the electrons with other elements. ... A metal's reactivity increases as we go from the top to the bottom of the periodic table.

Explanation:

The force that acts on the body is 53.55 N

According to the Newton law, the force is the product of the mass and the acceleration of a body. This is in accordance the Newton second law of motion. We now have to obtain the force that acts on the body.

Mass of the object =  15.3kg

Acceleration of the object = 3.5.0 m/s2

Force = 15.3kg * 3.50 m/s2

Force = 53.55 N

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Answer:

Autosexuality means people are more attracted to themselves than to others and may prefer masturbation to sex with a partner.

Answer: autosexual people are people who are attracted to themselves rather than other people.

Explanation:

The equipment used in the manufacturing process of olive leaf extraction capsules in a factory using the Soxhlet method is as follows

:1. Soxhlet extractor

2. Rotary evaporator

3. Heating mantle

4. Analytical balance

5. Glassware (flasks, beakers, pipettes, etc.)

6. Filter papers

7. Centrifuge

8. Drying oven

9. Capsule filling machine

10. Capsule polishing machine

The Soxhlet method is a continuous extraction process that is commonly used in the extraction of essential oils and other compounds from plant materials. In this method, the plant material is placed in a thimble that is inserted into a Soxhlet extractor, which is a glass apparatus consisting of a round bottom flask, a condenser, and a siphon tube. The solvent (in this case, ethanol) is heated in the round bottom flask, which causes it to evaporate and condense in the condenser. The condensed solvent then drips into the thimble containing the plant material and dissolves the desired compounds. The solvent then drips back into the round bottom flask, and the process continues until all the desired compounds have been extracted.

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Answer:  the formula mass of calcium phosphate [Ca3(PO4)2] is 310.177 amu, so its molar mass is 310.177 g/mol. This is the mass of calcium phosphate that contains 6.022 × 1023 formula units.

Answer: 310.177

The mass of water produced if the percent yield of the reaction is 72% is 16.2g.

Mass of acetylene = 40.0 grams

Mass of oxygen = 40.0 grams

Percent yield of the reaction = 72%

The balanced chemical equation is : 2 C2H2(g) + 5 O2(g) → 4 CO2(g) + 2 H2O(g)

From the balanced chemical equation, it is clear that 2 moles of acetylene reacts with 5 moles of oxygen to form 2 moles of water.

To find out limiting reagent

Moles of acetylene = Given mass of acetylene / molar mass of acetylene

                                 = 40.0 g / 26 g/mol = 1.54 moles

Moles of oxygen = Given mass of oxygen / molar mass of oxygen

                                = 40.0 g / 32 g/mol = 1.25 moles

The limiting reactant is oxygen because its number of moles is less than acetylene. Oxygen will react with 1.25 moles of acetylene present and form CO2 and H2O.

According to the balanced equation, the stoichiometric ratio of C2H2 to H2O is 2:2, meaning that for every 2 moles of C2H2, 2 moles of H2O are produced.

Since the stoichiometry is 1:1, the moles of water produced will be the same as the moles of acetylene used.

The number of moles of H2O produced 1.25 moles.

The mass of H2O produced = Number of moles of H2O × Molar mass of H2O

Mass of H2O produced = 1.25 × 18 = 22.5 g

Given percent yield = 72%

The actual yield can be calculated as follows;

Percent yield = Actual yield / Theoretical yield × 100

72% = Actual yield / 22.5 g × 100

Actual yield = 22.5 g× 72 / 100 =16.2 g

Thus, the mass of water produced if the percent yield of the reaction is 72% is 16.2g.

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Answer: Communicable diseases, abuse gunshot wounds and forensic medicine

Explanation: