C10H22 > C8H18+C2H4 if only ethane can be sold what is the atom econmy of this process

The set up that can be used to separate the mixture is option C.

The process of chromatography can be used in the separation of the components of a mixture (Image C). In this case, it is best used when we have pigments and we want to separate them.

There has to be a stationary phase and a mobile phase in the process. The stationary phase is a adsorbent and the mobile phase is a solvent that is able to carry out the actual separation of the mixture.

Since we have a liquid sample of green food coloring that is known to contain a mixture of two solid pigments, one blue and one yellow, dissolved in an aqueous solution of ethanol, we have to use chromatography.

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Answer:

thunderstorms

Explanation:

Answer:

Power lines produce a magnetic field

Explanation:

Power lines produce a type of magnet called an Electro-magnet which pulls metal magnetic objects towards it and the compass relies on magnetic feilds in order to point north.

A laboratory owned by a company other than the physician's practice is typically referred to as an "independent laboratory" or an "external laboratory." These laboratories are separate entities from the physician's practice and may provide various diagnostic, testing, or research services. They operate independently and may serve multiple healthcare providers or organizations.

Independent laboratories play a crucial role in the healthcare industry by offering specialized testing, advanced technologies, and expertise that may not be available within a physician's practice. They often handle a wide range of laboratory services, including clinical chemistry, microbiology, pathology, genetic testing, and more.

Physicians and healthcare providers may send patient samples or specimens to independent laboratories for analysis and diagnostics. The results obtained from these laboratories can aid in accurate diagnoses, treatment decisions, and monitoring of patient health.

Overall, independent laboratories contribute to the comprehensive healthcare system by providing specialized laboratory services and collaborating with healthcare providers to deliver quality patient care.

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The pOH of the given solution of hydrochloric acid is 3.87.

The given solution of hydrochloric acid has a concentration of 1.34 x 10⁻⁴M.

Now, we are supposed to find the pOH of the given solution.

In order to find the pOH of a given solution, we need to use the following formula:

pOH = -log [OH⁻]

We know that in pure water at 25°C:[OH⁻] = 1.0 x 10⁻⁷ M

Now, in order to find the pOH of a solution, we must first find the concentration of [OH⁻] in the solution.

Let's use the dissociation reaction of HCl to find the [OH-] in the solution:

HCl → H⁺ + Cl-[H⁺] = 1.34 x 10⁻⁴ MOH- + H⁺ → H2₂O

[OH⁻] = 1.0 x 10⁻¹⁴ / [H+]

pOH = -log [OH⁻]

pOH = -log [1.0 x 10⁻¹⁴ / 1.34 x 10⁻⁴]

pOH = -(-3.87)

pOH = 3.87

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The number of atoms in 0.0082g of gold is 2.50 x 10^19 atoms.

What is a molar mass in chemistry?

Molar mass is the mass of one mole of a substance, usually expressed in grams per mole (g/mol). It is a fundamental concept in chemistry that allows us to relate the mass of a substance to the number of atoms or molecules present.

The molar mass of gold (Au) is approximately 197 g/mol. To find the number of atoms in 0.0082 g of gold, we first need to calculate the number of moles of gold present:

moles of gold = mass of gold / molar mass of gold moles of gold = 0.0082 g / 197 g/mol moles of gold = 4.16 x 10^-5 mol

Next, we can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert the number of moles to the number of atoms:

number of atoms = moles of gold x Avogadro's number number of atoms = 4.16 x 10^-5 mol x 6.022 x 10^23 atoms/mol number of atoms = 2.50 x 10^19 atoms

Therefore, there are approximately 2.50 x 10^19 atoms in 0.0082 g of gold.

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The Henderson-Hasselbach equation is used to calculate the pH of a simple conjugate-pair buffer system. For an ammonia/ammonium chloride buffer, the equation would be expressed as pH = 9.25 + log([NH4+]/[NH3]).

This equation takes into account the equilibrium between the weak acid (NH4+) and its conjugate base (NH3) and the dissociation constant (Kb) of the weak base (NH3), which is given as 1.8 x 10-5. By knowing the concentration of the weak acid and its conjugate base, the pH of the buffer solution can be calculated.

The correct expression of the Henderson-Hasselbalch equation for an ammonia/ammonium chloride buffer system would be:

pH = 9.25 + log([NH4+]/[NH3])

This equation takes into account the pKa value (9.25) of the conjugate acid (NH4+) and the ratio of the concentrations of the conjugate acid ([NH4+]) and base ([NH3]) in the buffer solution.

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The value of ℰ°cell for the given galvanic cell is 0.179 V (Option C).

To calculate the ℰ°cell, we need to subtract the standard reduction potential of the cathode from that of the anode:

ℰ°cell = ℰ°cathode - ℰ°anode

From the given standard reduction potentials:
MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O, ℰ° = 1.509 V (Reaction 1)
Cr₂O₇²⁻ + 14H⁺ + 6e⁻ → 2 Cr³⁺ + 7H₂O, ℰ° = 1.330 V (Reaction 2)

Since MnO₄⁻ has a higher ℰ° value (1.509 V), it will act as the cathode (reduction occurs). Meanwhile, Cr₂O₇²⁻ has a lower ℰ° value (1.330 V) and will act as the anode (oxidation occurs). (C)

Now, we can find ℰ°cell:

ℰ°cell = 1.509 V (cathode) - 1.330 V (anode)
ℰ°cell = 0.179 V

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Answer:

3 cells

Explanation:

Answer:

ummmm id say god bless you :P

Explanation:

  Option E, BCl3 (boron trichloride), is the nonpolar molecule among the choices given. The other molecules, HCN (hydrogen cyanide), CHCl3 (chloroform), H2O (water), and HClO4 (perchloric acid), are polar due to differences in electronegativity or molecular geometry.

  A molecule is considered nonpolar when the electronegativity difference between the atoms is negligible or when the molecular geometry leads to a symmetric distribution of charge.

  Option A, HCN, is a polar molecule due to the difference in electronegativity between hydrogen and nitrogen.

  Option B, CHCl3, is a polar molecule because of the electronegativity difference between carbon and chlorine.

  Option C, H2O, is a polar molecule due to the bent molecular geometry and the difference in electronegativity between hydrogen and oxygen.

  Option D, HClO4, is a polar molecule due to the difference in electronegativity between hydrogen and chlorine.

  Option E, BCl3, is the nonpolar molecule among the choices. Boron trichloride has a trigonal planar molecular geometry, where the chlorine atoms are symmetrically arranged around the central boron atom. The molecule does not have any significant electronegativity differences, resulting in a nonpolar nature.

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Mole measure the number of elementary entities of a given substance that are present in a given sample. To find mass of 2.25 mol of the element Iron (Fe), we multiply 2.25 mol by (55.84g divided by 1 mol). Therefore option c is correct option.

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance.

Mathematically,

Mole of Fe element=  mass of Fe element÷ Molar mass of Fe element

mass= Mole of Fe element ×Molar mass of Fe element

Substituting the given values in above formula we get

mass= 2.25 mol× 55.84 g/mole

mass= 2.25 mol× 55.84 g/mole

To find mass of 2.25 mol of the element Iron (Fe), we multiply 2.25 mol by (55.84g divided by 1 mol).

Therefore option c is correct option.

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Volatile organic compounds (VOCs) are a group of chemicals that contain carbon and easily evaporate into the air at room temperature. They are commonly found in a variety of products such as paints, cleaning supplies, pesticides, and even personal care products like perfumes and deodorants.

VOCs are known to contribute to poor indoor and outdoor air quality, and can have harmful health effects such as eye, nose, and throat irritation, headaches, and even cancer. In addition to their negative impact on human health, VOCs also contribute to the depletion of the ozone layer and can contribute to climate change. Some common examples of VOCs include dry cleaning fluids, gasoline, and certain types of oils like corn oil.

                                 In the field of landscaping and architecture, VOCs are often found in building materials such as adhesives, sealants, and insulation, as well as in outdoor products like pesticides and fertilizers. To reduce exposure to VOCs, it is recommended to use products with low VOC emissions, increase ventilation in indoor spaces, and dispose of hazardous waste properly.
                                       Among the provided answer choices, the most accurate is that volatile organic compounds (VOCs) evaporate easily under normal atmospheric conditions. These compounds, such as dry cleaning fluids and corn oils, can contribute to ozone layer depletion and have various applications in different industries.

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The density of the unknown solid is approximately 109.864 lb/ft³. To convert the density from grams per cubic centimeter (g/cm³) to pounds per cubic foot (lb/ft³), we need to use appropriate conversion factors.

1 gram is equal to 0.00220462 pounds, and 1 cubic centimeter is equal to 0.0000353147 cubic feet.

First, let's convert the density from g/cm³ to kg/m³. Since 1 kg is equal to 1000 grams and 1 cubic meter is equal to 1,000,000 cubic centimeters, we can use the following conversion:

Density in kg/m³ = Density in g/cm³ × 1000 kg/m³ ÷ 1 g/cm³

Density in kg/m³ = 18.5 g/cm³ × 1000 kg/m³ ÷ 1 g/cm³ = 18500 kg/m³

Now, let's convert the density from kg/m³ to lb/ft³. Since 1 kilogram is equal to 2.20462 pounds and 1 cubic meter is equal to 35.3147 cubic feet, we can use the following conversion:

Density in lb/ft³ = Density in kg/m³ × 2.20462 lb/ft³ ÷ 1 kg/m³ ÷ 35.3147 ft³/m³

Density in lb/ft³ = 18500 kg/m³ × 2.20462 lb/ft³ ÷ 1 kg/m³ ÷ 35.3147 ft³/m³ ≈ 109.864 lb/ft³

Therefore, the density of the unknown solid is approximately 109.864 lb/ft³.

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The equation for the ionization of the weak base pyridine in water is:

C5H5N + H2O ⇌ C5H5NH+ + OH-

Explanation:

Pyridine is a weak base, so it will react with water to create hydroxide (OH-) ions, along with the conjugate acid of pyridine, which is called pyridinium ion (C5H5NH+). The overall equation for the reaction can be written as:C5H5N + H2O ⇌ C5H5NH+ + OH-In this equation, the arrows indicate that the reaction is reversible, meaning that the products can also react to form the reactants. Therefore, the concentration of each species in the reaction mixture will be related by an equilibrium constant (K).

The balanced equation for the ionization of the weak base pyridine in water is C5H5N + H2O ⇌ C5H5NH+ + OH-.

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Answer:

V= 21 cubic cm (( I am not sure about density ))

Explanation:

V= L×W×H

Answer:

a) The predominant Brownstead-Lowry acid- base is perchloric acid

b) A conjugate acid base pair is HClO4 and ClO4^-

c) forward reaction is favored and equilibrium position lies towards the far right

Explanation:

The molecular equation is;

HClO4(aq) + NaH2PO4(aq) -----> H3PO4(aq) + NaClO4(aq)

The net ionic equation of the reaction is;

H^+(aq) + H2PO4^-(aq) ----> H3PO4(aq)

The predominant Brownstead-Lowry acid- base is perchloric acid .

A conjugate acid base pair is HClO4 and ClO4^-

Since the both species; perchloric acid and sodium dihydrogen phosphate are both highly soluble in water yielding ions and also dissociate to a large extent in solution, the forward reaction is favoured leading to the formation of phosphoric acid. Remember that phosphoric acid does not easily dissociate in solution hence the forward reaction is faster than the reverse reaction and the equilibrium position lies towards the far right.

The observed result would be the formation of water, sodium bisulfite, and sodium chloride, which may remain dissolved in the solution.

When equal volumes of 0.1 M aqueous HCl (hydrochloric acid) and 0.01 M aqueous Na2SO3 (sodium sulfite) are mixed, a reaction occurs, resulting in the formation of new substances.

HCl is a strong acid, while Na2SO3 is a salt derived from a weak acid, sulfurous acid. The reaction between them is a neutralization reaction, where the H+ ions from HCl react with the SO3^2- ions from Na2SO3 to form water (H2O) and sodium bisulfite (NaHSO3). NaCl, a common salt, is also formed as a byproduct.

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Among the given materials, alumina (Al2O3) has the lowest conductivity. The order of conductivity, from lowest to highest, is: alumina (Al2O3) < silicon (Si) < silver (Ag).

The conductivity of a material refers to its ability to conduct electric current. In general, metals tend to have higher conductivity compared to non-metals. Among the given options, silver (Ag) is a metal and is known for its high conductivity.

Silicon (Si) is a semiconductor and has moderate conductivity. Alumina (Al2O3), on the other hand, is a non-metal and has significantly lower conductivity compared to silver and silicon. Therefore, alumina (Al2O3) has the lowest conductivity among the given materials.

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Answer:

3220 J of heat released

Explanation:

-qcal = (144.7g total)(4.2 J/g degrees C)(5.3 C)

Answer:

3.2 moles of H2SO4

Explanation:

We need to start with a balanced equation.  Lets assume the sulfuric acid is formed from sulfur dioxide and water.

   SO2 + H2O = H2SO4

This equation is balanced.  (Check it)

It tells us that 1 mole of SO2 will form 1 mole of H2SO4, if the reaction proceeds as planned.  That's a molar ratio of 1 to 1.  They are equal.  What moles we react, we should expect the same number of moles of product.  [And we need 1 mole of water at the same time]

So if we react 3.20 moles of sulfur dioxide, and keep out lab partner back, we'll obtain 3.2 moles of H2SO4.

Answer:

Hydrogen and Oxygen

Explanation:

The chemical equation for water is H20, meaning Hydrogen and 2 oxygen!

The value of kc is the equilibrium constant, which represents the ratio of the concentrations of products to reactants at equilibrium. When a diluted solution is heated, it can affect the value of kc in a number of ways.

Firstly, increasing the temperature can cause the reaction to shift in the direction of the endothermic reaction, which absorbs heat. This can increase the concentration of the products and decrease the concentration of the reactants, thereby increasing the value of kc.

On the other hand, if the reaction is exothermic and releases heat, increasing the temperature can cause the reaction to shift in the direction of the reactants. This can decrease the concentration of the products and increase the concentration of the reactants, thereby decreasing the value of kc.

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Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question

mass = 18.015 g

volume = 15 cm³

We have

\(density = \frac{18.015}{15} \\ = 1.000833333...\)

We have the final answer as

Hope this helps you

Answer:10

Explanation: good job

So there are 13 hydrogen atoms in the molecule of (S)-2-methylbutanoic propanoic anhydride.

To determine how many hydrogen atoms are there in the molecule of (S)-2-methylbutanoic propanoic anhydride, let's first understand the structure of the molecule.

The molecule consists of two parts: 2-methylbutanoic acid and propanoic acid, connected by an anhydride bond. Here's the breakdown of the hydrogen atoms in each part:
1. 2-methylbutanoic acid:
- 3 hydrogens in the methyl group (CH3) at the 2nd carbon
- 6 hydrogens in the remaining 3 carbons of the main chain (2 CH2 groups and 1 CH group)
- 1 hydrogen in the (S)-stereocenter

2. Propanoic acid:
- 3 hydrogens in the methyl group (CH3) at the end of the chain
- 2 hydrogens in the remaining carbon of the main chain (CH2 group)

Now, when the anhydride bond is formed, we lose one hydrogen atom from each carboxylic acid group. So, subtract 2 hydrogens.

To calculate the total number of hydrogen atoms:
(3+6+1) + (3+2) - 2 = 13 hydrogen atoms

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Answer:

2.232 g/L

Explanation:

Assuming 1 mol, volume at STP is 22.4 L so you simply divide 50g by 22.4 L to get density

The density of the given gas is required.

The density of the gas at STP is 2.232 g/L.

M = Molar mass of gas = 50 g/mol

1 mole of any gas at STP occupies 22.4 L.

V = Volume per mole = 22.4 L/mol

Density is given by

\(\rho=\dfrac{M}{V}\\\Rightarrow \rho=\dfrac{50}{22.4}\\\Rightarrow \rho=2.232\ \text{g/L}\)

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